The mass of the seashell suspended by the two strands of spider silk is 0.28 kg.
The given parameters:
Tension on each strand of silk, T = 1.42 NAngle of inclination of each strand, θ = 75⁰The mass of the seashell at equilibrium is calculated by applying Newton's second law of motion;
[tex]\Sigma F = 0\\\\T_1 sin(\theta) + T_2 sin(\theta) - W = 0[/tex]
where;
W is the weight of the seashellThe weight of the seashell is calculated as;
[tex]1.42 \times sin(75) \ + \ 1.42 \times sin(75) \ - W = 0\\\\2.743 - W = 0\\\\W = 2.743 \ N[/tex]
The mass of the seashell is calculated as follows;
[tex]W = mg\\\\m = \frac{W}{g} \\\\m = \frac{2.743}{9.8} \\\\m = 0.28 \ kg[/tex]
Thus, the mass of the seashell suspended by the two strands of spider silk is 0.28 kg.
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What determines the amount of gravitational force between
objects?
Answer:
The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them. This means that the force of gravity increases with mass, but decreases with increasing distance between objects.
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A 1.5 kg ball has a velocity of 12 m/s just before it strikes the floor. Find the impulse on the ball if the ball bounces up with a velocity of 10 m/s.
Hi there!
Recall:
Impulse = Change in momentum
I = Δp = mΔv = m(vf - vi)
Let the direction TOWARDS the floor be POSITIVE, and AWAY be NEGATIVE.
Plug in the givan values:
Δp = 1.5(-10 - 12) = -33 Ns
**OR, the magnitude: |-33| = 33 Ns
The body weighs 15N. What is the mass of that body?
What is an object's mass if it accelerates at 5 m/s2 when a force of 0.5 N is applied?
Answer:
0.1kg
Explanation:
mass = force / acceleration
0.5 / 5
0.1kg
Select the correct answers from the list.(1 point) A black hole begins to form as an aging star abruptly collapses when it ceases__________ . This occurs after the star has consumed its component elements in this order___________.
A black hole forms as a star collapses when it ceases emitting radiation from fusion reactions. This occurs after the star has consumed hydrogen, helium, then through iron.
Star evolution refers to the process by which stars evolve (change) over time.
A black hole can be defined as a collapsed star where the gravitational field in its nucleus becomes greater than particles cannot escape from it.
In consequence, black holes are cosmic bodies in which gravity is so powerful that nothing (i.e., particles, radiation, light, etc.) can escape from them.
Nuclear fusion refers to the energy reactions produced by the fusion of hydrogen at the core of a star, thereby becoming helium.
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These diagrams represent two types of tectonic plate boundaries
Convergent boundaries are caused by the collision of two plates and can originate volcanoes. Transforming boundaries produce fractures by displacement. The correct option is D. Type A boundaries have fewer volcanoes.
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The crust -the outermost layer of the earth- is divided into many plates that move over the mantle.
These plates are limited by three types of ridges or borders that differ in the movement they produce.
Boundaries types:
I. Divergent:
This boundary occurs when two plates separate and molten material rises from the mantle creating a new crust. The hot material creates a new seabed between the separating plates, expanding the sea bottom.II. Convergent.
Collision area between two plates. Two oceanic plates might collide, or one oceanic plate with a continental one. In this last case, the oceanic crust sinks under the continental plate, and magma rises to the surface by crevices. The thicker and older plate subduces under the other plate. Collisions create volcanic arches and continental arches.
III. Transforming.
The plates slide laterally with each other, and they are usually called faults. It is associated, in general, with the oceanic ridge, although it might also occur in the continental plate. No rocky material is either destroyed or formed. When the plates move and produce a displacement of one transforming limits from side to side, earthquakes occur. The movement breaks the crust and originates pronounced fractures.
In the attached images, we can see
image A representing transforming boundaries, image B representing Convergent boundaries.Image B is the one that can originate volcanoes because transforming boundaries only produce fractures.
So the correct option would be D.
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Answer:
d
Explanation:
A 0.40 kg bead slides on a straight frictionless wire with a velocity of 3.50 cm/s to the right. The
bead collides elastically with a larger 0.60 kg bead initially at rest. After the collision the smaller
bead moves to the left with a velocity of 0.70 cm/s. Find the distance the larger bead moves along
the wire in the first 5.0 s following the collision?||
Answer:
Total momentum before collision
P1 =.4 * 3.5 = 1.4 ignoring units here
Total momentum after collision
P2 = .6 * V - .4 * .7 = .6 V - .28
.6 V = 1.4 + .28 momentum before = momentum after
V = 2.8 cm/sec
In 5 sec V moves 2.8 cm/sec * 5 sec = 14 cm
the motion of a particle along a straight line is represented by the position versus time graph above. at which of the labeled points on the graph is the magnitude of the acceleration of the particle greatest?
Point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.
On the graph, A is the point where magnitude of the acceleration of the particle is greatest as compared to other positions on the graph because the height of point A is the largest as compared to other points of the graph.
The graph shows at which point acceleration of an object is higher and lower so we can conclude that point A has the largest magnitude of acceleration as compared to other points on the position verses time graph.
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Explain briefly about viscous force
The viscous force refers to the resistance of a fluid to flow. It is measured in Newton-second per square meter.
The viscous force can be defined as the resistance that a fluid has to flow in a given space. Viscous force is proportional to the fluid velocity, while this constant is called viscosity.The viscous force can be measured in Newton-second per square meter (abbreviated as N s/m2).Learn more about viscous force here:
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What the number ??? Help Please
Answer:
first number is 113 and the second number is 15
If mason runs a 5 k race at an average speed of 300 m/min how long will it take him to finish
[tex]\\ \sf\Rrightarrow Speed=\dfrac{Distance}{Time}[/tex]
[tex]\\ \sf\Rrightarrow Time=\dfrac{Distance}{Speed}[/tex]
[tex]\\ \sf\Rrightarrow Time=\dfrac{5000}{300}[/tex]
[tex]\\ \sf\Rrightarrow Time=16.6min[/tex]
what was stored when you bent the ruler in your left hand?
Answer:
potential energy
the name comes from the fact that the ruler has "potential" to act
Explanation:
Explanation:
The deformation of the ruler creates a force in the opposite direction, known as a restoring force.
I'm not sure if it's correct...
Chapter Name :- Vector
Question :-
A car is moving at Vc speed. Rain is falling vertically at a speed of 10 m / s. What is the value of Vc in this case,if the front glass of the car will get wet?
Answer :- Vc ≥ 10
I need Explanation! Please Don’t do copy from net! If you don’t know then no need to answer!
The value of the speed of the car, for the front glass of the car to get wet, [tex]V_c \geq 10 \ m/s[/tex].
The given parameters:
Speed of the car, = VcSpeed of the rain, = 10 m/sThe relative velocity of the car with respect to the falling rain is calculated as;
[tex]V_{C/R} = V_C- V_R[/tex]
If the speed of the car equals the speed of the rain, the rain will fall behind the car.If the speed of the rain is greater than speed of the car, the rain will fall far in front of the car.If the speed of the car is greater than speed of the rain, the rain will fall on the car.Thus, for the front glass of the car to get wet, [tex]V_c \geq 10 \ m/s[/tex].
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a race car is traveling at a speed of 80.0m/s on a circular race track of radius 450m what is the centripetal acceleration
Answer:
The answer of this question is =1.258*10-4
how many bears are witching the category of the
How did Ptolemy adapt the geocentric model so he could account for the motion of the planets?
ANSWER ASAP
Answer:
The most important solution to this problem was proposed by Claudius Ptolemy in the 3rd century AD. He argued that planets move on two sets of circles, a deferent and an epicycle. This explained retrograde motion while keeping the planets in their circular orbits around the Earth.
Explanation:
Please help my physics teacher cannot teach pls hurry pls help uwu
Hi there!
To find how much the spring stretches with the mass attached, we must find the spring's equilibrium point.
The equilibrium point satisfies the following:
[tex]\large\boxed{\Sigma F = 0}[/tex]
The two forces acting in this situation are the weight of the mass and the spring force.
The spring force (restoring force) is in the opposite direction of the weight, so:
[tex]\Sigma F = 0 = Mg- k\Delta x[/tex]
Mg = weight
k = Spring Constant (N/m)
Δx = distance to equilibrium point (m)
Now, we can set the two equal to each other:
[tex]Mg = k\Delta x\\\\544 = 1146\Delta x\\\\\boxed{\Delta x= .475 m}[/tex]
If someone can help that would be cool
Answer:
1.5 cm
Explanation:
The ratio of areas is the square of the ratio of diameters, so cylinder A has (1/2)^2 = 1/4 the area of cylinder B.
The volume of the cylinder is jointly proportional to its area and its height. So, for a fixed volume, the height is inversely proportional to the area.
Cylinder B has 4 times the area of cylinder A, so any volume moved from cylinder A to B will require only 1/4 of the change in height that is required in cylinder A.
The red piston in cylinder B rises 1.5 cm.
A vector consists both?
Answer:
magnitude and a direction
Explanation:
A weightlifter lifts a 350 N set of weights over his head a vertical distance of 2.5 meters above the floor. Calculate the work the athlete does on the weights, assuming he lifts them at a constant speed.
A. 525 J
B. 750 J
C. 1005 J
D. 700 N•m
E. 875 J
From one point on the ground, the
angle of elevation of the peak of a
mountain is 10.38°, and from a
point 15,860 ft closer to the
mountain, the angle of elevation is
14.67º. Both points are due south of
the mountain. Find the height of the
mountain.
10.38°
一企一
14.67°
15,860 ft
Trigonometry allows to find the result for the question about the height of the mountain is:
The height mountain is: y = 9674.4 ftTrigonometry allows finding relationships between the angles of a right triangle.
[tex]tan \theta = \frac{y}{x}[/tex]
Where θ is the angle, y the opposite leg (height) and x the adjacent leg (horizontal distance).
In the attachment we can see a diagram of the system. They indicate that for x distance the angle is 14.67º
tan 14.67 = [tex]\frac{y}{x}[/tex]
At the other point the angle is 10.38º.
tan 10.38 = [tex]\frac{y}{x+15860}[/tex]
We look for the horizontal distance (x) with these equations.
x tan 14.67 = (x + 15860) tan 10.38
x tan 14.67 / tan 10.38 = x + 15860
x 1,429 = x + 15860
x 0.429 = 15860
x = [tex]\frac{15680}{0.429}[/tex]
x = 36955.3 ft
We calculate for the height.
y = x tan 14.67
y = 36955.3 tan 14.67
y = 9674.4 ft
In conclusion using trigonometry we can find the result for the height of the mountain is:
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1. The law of reflection states that the angle of _______ is equal to the angle ofreflection
•refraction
•incidence
Answer:
refraction
Explanation:
but this is easy so why
How can you use a simple model to describe a wave and its features?
Answer:
Explanation:
Use mathematical representations to describe a simple model for waves that includes how the amplitude of a wave is related to the energy in a wave. Patterns can be used to identify cause and effect relationships.
Calculate the weight of the object of mass
20kg. (g= 10 m/s^2)
Answer:
mass= 20kg
g=10m/s2
weight is F=mg
F=20×10
F=200N
How much work is done if a boat has a force 60N and travels 600 meters
Formula
substitute
answer
Answer:
36,000 J
Explanation:
Work is equal to Force times Distance:
W = Fd
W = 60N*600m
36,000 = 60N*600m
why is it less air pressure up in the sky and why does it affect our ears
Answer:
When you in a airplane you are in high altitude and thats where air density drops. Thats where ear pops come from.
Explanation:
PLEASE HELP!!
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(answer choices: applied force, normal force, friction, electrical force, magnetic force and gravitational force)
(question in picture)
Answer:
3
Explanation:
because they are pushing a body
Two billiard balls having the same mass and speed roll directly toward each other. What is their combined momentum after they meet
Their combined momentum after they meet is 0.
What is law of conservation of momentum?According to the law of conservation of momentum, absent an external force, the combined momentum of two or more bodies operating upon one another in an isolated system remains constant. As a result, momentum cannot be gained or lost.
Let the mass of each billiard balls = m.
If the initial velocity of first ball is u; according to the question, the initial velocity of the second ball be -u.
Hence, initial momentum of the first ball is: P₁ = mu
initial momentum of the second ball is: P₂ = -mu
Hence, total initial momentum of the two balls = P₁ + P₂ = mu + ( -mu) = 0.
So, according to law of conservation of momentum:
Their combined momentum after they meet is = 0.
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The combined momentum of the two billiard balls after they meet is zero.
When two pool balls of the same size and speed roll directly at each other and collide, their momentum will increase.
Let us denote the speed of the first ball as [tex]\rm p_1[/tex] and the speed of the second ball as [tex]\rm p_2[/tex]. The momentum of the balls are equal in magnitude but opposite in direction because they have the same mass and velocity.
[tex]\rm p_1= -p_2[/tex]
When the balls collide, their momentum increases:
Total momentum after the collision= [tex]\rm p_1+ p_2[/tex]
Substituting the relationship
[tex]\rm p_1= -p_2[/tex]
Total momentum after the collision
[tex]\rm p_1- p_1= 0[/tex]
Therefore, the combined momentum of the two billiard balls after they meet is zero.
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A pail of water of mass 2000 gm is rotated in a vertical circle of radius 1.00 m. What is the pail’s minimum speed at the top of the circle if no water is to spill out and the tension exerted by the string is 25 N?
The pail’s minimum speed at the top of the vertical circle is 4.72 m/s.
The given parameters:
Mass of the water, m = 2000 g = 2 kgRadius of the circle, r = 1 mTension on the string, T = 25 NThe net force on the pail of water at the top of the vertical circle is calculated as follows;
[tex]T = ma - mg\\\\T = \frac{mv^2}{r} - mg\\\\T + mg = \frac{mv^2}{r} \\\\mv^2 = r(T + mg)\\\\v^2 = \frac{r(T + mg)}{m} \\\\v= \sqrt{\frac{r(T + mg)}{m}} \\\\v = \sqrt{\frac{1 (25\ + \ 2 \times 9.8)}{2}} \\\\v = 4.72 \ m/s[/tex]
Thus, the pail’s minimum speed at the top of the vertical circle is 4.72 m/s.
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The pail’s minimum speed at the top of the circle if no water is to spill out is; v = 4.722 m/s
We are given;
Mass of the pail of water; m = 2000 g = 2kg
Radius of the circle; r = 1 m
Tension exerted by string; T = 25 N
To calculate the net force on the pail of water at the top of the vertical circle, let us take equilibrium of forces to give;
W - T = ma
Where;
W is weight = mg
T is tension on the string
Now, in circular motion, we know that;
Acceleration is; a = v²/r
Thus;
mg - T = m(v²/r)
Making v the subject of the formula gives us;
v = √[(r(T + mg)/m)
Plugging in the relevant values gives;
v = √[(1(25 + (2 * 9.8))/2)
v = 4.722 m/s
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A young diver is practicing his skills before an important team competition. Use the diagram below in order to analyze the energies of the diver and complete the statements below.
Where m = mass (kg), g = 9.8 m/s2, v = velocity (m/s), h = height (m), KE = kinetic energy (J), and GPE = gravitational potential energy (J).
Use the equations above to answer the following questions.
A diver with a mass of 90 kg is at a height of 10 m, and he has not jumped off of the board yet (v = 0 m/s). When the diver reaches a height of 5 m (Point C), his gravitational potential energy is
A. 1350 J
B. 8820 J
C. 4410 J
D. 0 J
and his velocity is
E. 4.5 m/s
F. 0 m/s
G. 3.2 m/s
H. 9.9 m/s
Please help will mark brainliest
Answers:
The gravitational potential energy of the diver when he reaches point C is 4410 J.
The velocity of the diver is 9.9 m/s.
Hope you could get an idea from here.
Doubt clarification - use comment section.
[tex]\\ \sf\longmapsto PE=mgh[/tex]
[tex]\\ \sf\longmapsto PE=90(5)(9.8)[/tex]
[tex]\\ \sf\longmapsto PE=4410J[/tex]
Now
It's converted to kinetic energy while reaching ground.
[tex]\\ \sf\longmapsto K.E=4410[/tex]
[tex]\\ \sf\longmapsto \dfrac{1}{2}mv^2=4410[/tex]
[tex]\\ \sf\longmapsto 90v^2=8820[/tex]
[tex]\\ \sf\longmapsto v^2=98[/tex]
[tex]\\ \sf\longmapsto v=9.9m/s[/tex]