In MIPS assembly language, the user is prompted to enter three integers, and the program then prints out the average of the three numbers. This problem can be solved by dividing the sum of the three numbers by three. No user input validation is required in this program.
MIPS assembly language is a low-level programming language that is used to write computer programs. It is often used in embedded systems and other types of hardware that require efficient, low-level programming. In this program, we will use the following instructions to read in the user's input and compute the average of the three numbers:
read the first integer (syscall 5)read the second integer (syscall 5)read the third integer (syscall 5)add the three numbers together (add $t0, $t1, $t2)divide the sum by 3 (div $t0, $t3)store the quotient in $v0 (mflo $v0)print the average (syscall 1)In conclusion, we have written a MIPS assembly language program that prompts the user to input three integers and then prints out the average of the three numbers. This program can be used in a variety of applications, such as calculating the average score on an exam or the average temperature in a room. By dividing the sum of the three numbers by three, we can quickly and efficiently compute the average.
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Which of the following statement will result in runtime error? a. 9/0 b. 8 +-8 c. 1% 9 *7 d. (3**2)**3
option a. 9/0 will result in a runtime error.
Dividing a number by zero is undefined in mathematics and programming. In Python, dividing by zero will raise a runtime error called "ZeroDivisionError". This error occurs because division by zero is not a valid operation and violates the mathematical principles.
To avoid this error, you should ensure that you never divide any number by zero in your code. If you need to perform calculations that involve division, make sure to handle potential zero denominators with appropriate checks or conditions to prevent the runtime error.
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(0)
write a c++ program to read any month number in integer and disaplay the number of days for this month
In this program, the user is prompted to enter a month number between 1 and 12. The program then checks if the input is within the valid range. If it is, a switch statement is used to assign the appropriate number of days for that month. For February (month 2), 28 days are assigned.
Certainly! Here's a C++ program that reads a month number as input from the user and displays the number of days for that month:
cpp
Copy code
#include <iostream>
using namespace std;
int main() {
int month;
cout << "Enter the month number (1-12): ";
cin >> month;
// Check if the month is valid
if (month >= 1 && month <= 12) {
int days;
// Assign the number of days based on the month
switch (month) {
case 2:
days = 28;
break;
case 4:
case 6:
case 9:
case 11:
days = 30;
break;
default:
days = 31;
break;
}
cout << "Number of days in month " << month << ": " << days << endl;
}
else {
cout << "Invalid month number!" << endl;
}
return 0;
}
For April, June, September, and November (months 4, 6, 9, and 11 respectively), 30 days are assigned. For all other months, 31 days are assigned. Finally, the program displays the number of days for the entered month. If the input is invalid, an appropriate error message is displayed.
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Write C++ code to implement a carry-save adder
In the main function, an example usage is demonstrated. Two binary numbers a and b are defined as vectors, and the carrySaveAdder function is called with these vectors. The resulting sum is then displayed on the console.
Sure! Here's an example of C++ code that implements a carry-save adder:
```cpp
#include <iostream>
#include <vector>
std::vector<int> carrySaveAdder(const std::vector<int>& a, const std::vector<int>& b)
{
std::vector<int> sum(a.size(), 0);
int carry = 0;
for (int i = 0; i < a.size(); i++)
{
sum[i] = a[i] ^ b[i] ^ carry;
carry = (a[i] & b[i]) | (a[i] & carry) | (b[i] & carry);
}
sum.push_back(carry); // Append the final carry to the sum vector
return sum;
}
int main()
{
// Example usage
std::vector<int> a = {1, 0, 1, 0}; // Binary representation of number A
std::vector<int> b = {1, 1, 0, 1}; // Binary representation of number B
std::vector<int> sum = carrySaveAdder(a, b);
// Display the result
std::cout << "Sum: ";
for (int i = sum.size() - 1; i >= 0; i--)
{
std::cout << sum[i];
}
std::cout << std::endl;
return 0;
}
```
In this code, the `carrySaveAdder` function takes two vectors `a` and `b`, representing the binary representation of two numbers. It performs the carry-save addition operation and returns the sum as a vector. The carry-save adder logic is implemented using XOR and AND operations to compute the sum and carry bits.
In the `main` function, an example usage is demonstrated. Two binary numbers `a` and `b` are defined as vectors, and the `carrySaveAdder` function is called with these vectors. The resulting sum is then displayed on the console.
Note: This code assumes that the binary numbers `a` and `b` have the same size. Make sure to adjust the code if you want to handle different-sized inputs.
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Consider the following B+ tree (no duplicates). Start with the original tree index for each question part. Apply the action(s) asked and SHOW the resulting tree. In the case of a split, "push right" the extra value (3 values split1 into 1 and 2, with the 2 values placed in the right node). Node P1 is the root of the tree.
1. Insert 42* into the original tree. Indicate changes in a different color.
How many I/O reads are performed and on which pages:
How many I/O writes are performed and on which pages (include the reason):
2. Insert 47*, 43* into the original tree. Show the state of the final tree. Indicate changes in a different color.
How many I/O reads are performed and on which pages:
How many I/O writes are performed and on which pages (include the reason):
3. Delete 12* from the original tree. Indicate changes in a different color.
How many I/O reads are performed and on which pages:
How many I/O writes are performed and on which pages (include the reason):
4. Delete 30* from the original tree. Indicate changes in a different color.
How many I/O reads are performed and on which pages:
How many I/O writes are performed and on which pages (include the reason):
5. Delete 39* from the original tree. Indicate changes in a different color.
How many I/O reads are performed and on which pages:
How many I/O writes are performed and on which pages (include the reason):
6. Delete 31* from the original tree. Indicate changes in a different color.
How many I/O reads are performed and on which pages:
How many I/O writes are performed and on which pages (include the reason):
7. Which pages (node and leaf) are read, in order of access, when searching for key values between 15 and 60 inclusive (15 ≤ x ≤ 60)?
The number of I/O reads and writes in a B+ tree varies based on the specific structure and the operations being performed. The tree is balanced through node splitting and merging, ensuring efficient access and retrieval of data in disk-based systems.
When inserting 42* into the original tree, the exact number of I/O reads and writes would depend on the structure and size of the tree. However, the general process for inserting a value into a B+ tree involves traversing the tree from the root to the appropriate leaf node, splitting nodes if necessary, and then inserting the value into the appropriate position in the leaf node. This process typically requires reading a few nodes from disk into memory and writing the modified nodes back to disk.
Similarly, when inserting 47* and 43* into the original tree, the number of I/O reads and writes would depend on the specific structure of the tree. The process involves traversing the tree, potentially splitting nodes and reorganizing the tree structure to accommodate the new values.
When deleting a value, the process also involves traversing the tree to find the appropriate leaf node and removing the value from it. Depending on the specific case, the deletion might require redistributing keys among nodes or merging nodes to maintain the balance and integrity of the tree.
The same applies to deleting values 30*, 39*, and 31* from the original tree. The exact number of I/O reads and writes would depend on the specific structure of the tree and the location of the values being deleted.
To search for key values between 15 and 60 inclusive, you would start from the root node and traverse the tree, following the appropriate pointers based on the ranges of keys. This search process would involve reading the necessary nodes from disk into memory until you find the leaf nodes containing the desired values.
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Write a C function named timel() that accepts integer number of seconds and the address of three variables named hours, min, and sec. The function is to convert the passed number of seconds into an equivalent number of hours, minutes, and seconds and directly alter the value of respective variables using their passed addresses. The function should use the following prototype: void timel(int total_sec, int* hours, int* min, int *sec);
Here's an implementation of the timel() function in C that converts the given number of seconds into hours, minutes, and seconds:
void timel(int total_sec, int* hours, int* min, int* sec) {
*hours = total_sec / 3600; // Calculate the number of hours
total_sec %= 3600; // Update the remaining seconds
*min = total_sec / 60; // Calculate the number of minutes
*sec = total_sec % 60; // Calculate the remaining seconds
}
In this function, we divide the total number of seconds by 3600 to calculate the number of hours. Then, we update the remaining seconds by taking the modulus of 3600. Next, we divide the updated total seconds by 60 to calculate the number of minutes. Finally, we calculate the remaining seconds by taking the modulus of 60.
To use this function, you can declare variables for hours, minutes, and seconds, and pass their addresses to the timel() function. Here's an example usage:
int main() {
int total_sec = 4523;
int hours, min, sec;
timel(total_sec, &hours, &min, &sec);
printf("Hours: %d, Minutes: %d, Seconds: %d\n", hours, min, sec);
return 0;
}
Output:
yaml
Copy code
Hours: 1, Minutes: 15, Seconds: 23
In this example, the timel() function is called with total_sec set to 4523, and the values of hours, min, and sec are updated accordingly. Then, we print the converted values of hours, minutes, and seconds.
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Please answer fast
Briefly explain about app development approaches.
The choice of app development approach depends on factors such as the target platform, development resources, desired functionality, and user experience goals.
Native app development involves creating applications specifically for a particular platform, such as iOS or Android, using the platform's native programming languages and tools. This approach allows for full utilization of the platform's capabilities, providing a seamless user experience but requiring separate development efforts for each platform.
On the other hand, cross-platform app development involves building applications that can run on multiple platforms using frameworks and tools that enable code sharing. This approach streamlines development efforts by writing code once and deploying it on various platforms. However, cross-platform apps may have limitations in accessing certain platform-specific features or performance optimization.
Other app development approaches include hybrid app development, which combines native and web technologies, and progressive web app development, which involves creating web applications that can be accessed and installed like native apps. These approaches offer their own advantages and trade-offs, depending on the project requirements and constraints.
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Construct a UML class diagram showing the structure of a professional society, wherein members pay an annual fee. Your class diagram should incorporate the following 6 classes: member, student Member, standard Member, senior Member, society, and governing Committee, which should be connected with appropriate relationships, and be populated with appropriate instance variables and methods to enable the names, addresses and fees of members to be stored, along with the management committee members, and the name and HQ address of the society. The governing committee will comprise a number of senior members.
Answer:
Explanation:
Here is a UML class diagram representing the structure of a professional society:
```
____________________
| Member |
|------------------|
| - name: String |
| - address: String |
| - fee: double |
|------------------|
| + Member(name: String, address: String, fee: double) |
| + getName(): String |
| + getAddress(): String |
| + getFee(): double |
____________________
^
|
________|________
| StudentMember |
|----------------|
|----------------|
____________________
^
|
________|________
| StandardMember |
|----------------|
|----------------|
____________________
^
|
________|________
| SeniorMember |
|----------------|
|----------------|
____________________
^
|
________|________
| Society |
|----------------|
| - name: String |
| - hqAddress: String |
| - members: List<Member> |
| - committee: List<SeniorMember> |
|----------------|
| + Society(name: String, hqAddress: String) |
| + getName(): String |
| + getHQAddress(): String |
| + addMember(member: Member): void |
| + removeMember(member: Member): void |
| + getMembers(): List<Member> |
| + addCommitteeMember(member: SeniorMember): void |
| + removeCommitteeMember(member: SeniorMember): void |
| + getCommitteeMembers(): List<SeniorMember> |
____________________
^
|
________|________
|GoverningCommittee |
|----------------|
|----------------|
____________________
```
In this diagram, the "Member" class represents the basic attributes and methods of a member, such as name, address, and fee. The "StudentMember," "StandardMember," and "SeniorMember" classes are subclasses of "Member" and represent different types of members with specific characteristics.
The "Society" class represents the professional society and has attributes for the society's name, headquarters address, a list of members, and a list of committee members. It also has methods for adding/removing members, adding/removing committee members, and retrieving the lists of members and committee members.
The "GoverningCommittee" class represents the committee responsible for managing the society. It is connected to the "SeniorMember" class, indicating that committee members are senior members of the society.
Overall, this class diagram captures the relationships and attributes necessary to model a professional society with different types of members and a governing committee.
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Single Choice (3.Oscore) 22.For the following storage classes, which can applied to global variables? A register, auto B auto, static C static, extern D auto, extern
The correct answer is C. static, extern. In C programming, the storage classes dictate the lifetime, scope, and initialization of variables.
Out of the given options, the storage classes that can be applied to global variables are: B. auto: The auto storage class is the default for local variables, and it is not typically used for global variables. It is automatically assigned to variables within a function, and it is not suitable for global scope. C. static: The static storage class can be applied to global variables. It provides internal linkage, meaning the variable is accessible only within the file it is defined in. It has a lifetime throughout the entire execution of the program.
D. auto, extern: This combination is not applicable to global variables. The auto storage class is not used for global variables, and the extern storage class is typically used to declare global variables without defining them. Therefore, the correct answer is C. static, extern.
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Discrete math
Suppose vehicle arrive at a signalised road intersection at an average rate of 360 per hour and the cycle of the traffic lights is 40 seconds . In what percentage of cycle will the number of vehicles arriving be :
a. exactly 5
b. less than 5
c. What is the expectation value of arriving vehicles?
d. What is the probability that more than 5 cars will arrive ?
a) Exactly 0.084% of the cycle will have 5 vehicles arriving.
b) So less than 0.24% of the cycle will have less than 5 vehicles arriving
c) On average, we can expect 4 vehicles to arrive during each cycle of the traffic lights.
d) There is a 54.012% chance that more than 5 vehicles will arrive during a cycle of the traffic lights.
Let lambda be the arrival rate of vehicles per second, then lambda = 360/3600 = 0.1 (since there are 3600 seconds in an hour).
a. To find the percentage of cycle where exactly 5 vehicles arrive, we can use the Poisson distribution. The probability of exactly 5 arrivals in a 40-second cycle is given by P(X=5) = (e^(-lambda) * lambda^5) / 5! = (e^(-0.1) * 0.1^5) / 120 ≈ 0.00084 or 0.084%. Therefore, exactly 0.084% of the cycle will have 5 vehicles arriving.
b. To find the percentage of cycle where less than 5 vehicles arrive, we need to calculate the cumulative distribution function for X, which is given by F(x) = ∑(k=0 to x) [(e^(-lambda) * lambda^k) / k!]. For x=4, F(4) = ∑(k=0 to 4) [(e^(-0.1) * 0.1^k) / k!] ≈ 0.0024 or 0.24%, so less than 0.24% of the cycle will have less than 5 vehicles arriving.
c. The expectation value or mean number of arriving vehicles E(X) can be calculated using the formula E(X) = lambda * t, where t is the time period. Since the time period is equal to the length of one cycle, which is 40 seconds, we get E(X) = 0.1 * 40 = 4. Therefore, on average, we can expect 4 vehicles to arrive during each cycle of the traffic lights.
d. To find the probability that more than 5 cars will arrive, we can use the complement rule and subtract the probability of 5 or fewer arrivals from 1: P(X > 5) = 1 - P(X ≤ 5) = 1 - F(5) = 1 - ∑(k=0 to 5) [(e^(-0.1) * 0.1^k) / k!] ≈ 0.54012 or 54.012%. Therefore, there is a 54.012% chance that more than 5 vehicles will arrive during a cycle of the traffic lights.
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Explain 2 different techniques attackers might use to hide their identity/address while attacking systems. How can those techniques be (a) detected, (b) stopped, and (c) defeated (e.g, discovering the attackers’ real identity/address)?
Attackers can hide their identity/address through techniques like IP spoofing and proxy servers.
These can be detected through network analysis, prevention methods include filtering and authentication, and defeating them may involve forensic analysis and collaboration with ISPs or law enforcement.
1. IP Spoofing: Attackers can use IP spoofing to hide their true IP address and make it appear as if the attack is originating from a different IP address. They forge the source IP address in the packets they send, making it difficult to trace the attack back to its actual source.
(a) Detection: IP spoofing can be detected through various techniques such as analyzing network traffic patterns, monitoring for inconsistencies in packet headers, and employing intrusion detection systems (IDS) that can detect spoofed IP addresses.
(b) Prevention: To prevent IP spoofing attacks, network administrators can implement ingress and egress filtering at network borders to verify the legitimacy of the source IP addresses. Additionally, implementing strong authentication mechanisms can help prevent unauthorized access to systems.
(c) Defeat: To defeat IP spoofing attacks and discover the attackers' real identity/address, forensic analysis can be performed on network logs, examining packet headers, and collaborating with internet service providers (ISPs) to trace the origin of the spoofed packets.
2. Proxy Servers: Attackers can use proxy servers to hide their identity and route their attacks through intermediate servers. By leveraging anonymous proxy servers or networks such as Tor, attackers can obfuscate their true IP address and make it challenging to identify their location.
(a) Detection: Detecting attackers using proxy servers requires monitoring network traffic for suspicious patterns, analyzing the source and destination IP addresses, and employing techniques like traffic analysis and correlation to identify anomalies.
(b) Prevention: Network administrators can implement measures such as access control lists (ACLs) and firewalls to block known proxy servers and anonymization networks. Intrusion prevention systems (IPS) and behavioral analysis techniques can also help identify malicious activities associated with proxy server usage.
(c) Defeat: Defeating attackers using proxy servers requires comprehensive investigation and analysis. This can involve cooperation with law enforcement agencies, collaboration with proxy service providers to identify the real IP addresses behind the proxies, and utilizing advanced forensic techniques to gather evidence and trace the attacks back to their source.
It's important to note that the effectiveness of detection, prevention, and defeat techniques can vary depending on the sophistication of the attackers and the specific circumstances of the attack.
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3. Disjoint Sets : Disjoint sets are constructed from elements 0, 1, 2, 3, .9, using the union-by-size policy. Draw diagrams similar to those in Figs 8.10 to 8.13 to illustrate how the disjoint sets are constructed step by step by processing each of the union operations below. union (3,5), union (7,4) union (6,9), union (1,0), union (9,8) union (2,7), union (1,5), union (2,7), union (8,1), union (5,9), union (4,7).
Here are the diagrams illustrating how the disjoint sets are constructed step by step for each of the union operations:
union(3, 5)
Initial set: {0}, {1}, {2}, {3}, {4}, {5}, {6}, {7}, {8}, {9}
3 5
\ /
\ /
0
union(7, 4)
3 5 7
\ / => / \
\ / 4 0
0
union(6, 9)
3 5 7 6
\ / => / \ / \
\ / 4 0 9 8
0
union(1, 0)
3 5 7 6
\ / => / \ / \
\ / 4 1 9 8
0 |
2
union(9, 8)
3 5 7 6
\ / => / \ / \
\ / 4 1 9 0
2 | / \
8 3 5
union(2, 7)
3 5 7 6
\ / => / \ / \
\ / 4 1 9 0
2 / / | / \
8 3 5 2 7
union(1, 5)
3 1 7 6
\ / => / \ / \
\ / 4 0 9 5
2 / / | |\ |
8 3 5 | 1
2 4
union(2, 7)
3 1 7 6
\ / => / \ / \
\ / 4 0 9 5
2 / / |\ /| |
8 3 5 2 1 7
| |/_\|_/
4 8 3
union(8, 1)
3 8 7 6
\ / => / \ / \
\ / 4 0 9 5
2 / / |\ /| |
3 5 1 2 8 7
| |/_\|_/
4 6 9
union(5, 9)
3 8 7 6
\ / => / \ / \
\ / 4 0 5 9
2 / / |\ /|\ |
3 9 1 2 8 7
| |/_\|
4 6 5
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What is the result of the following:
int f = 7;
double answer;
answer = (double) f / 3;
f /= 3;
System.out.println ("answer is: " + answer);
System.out.println ("f is: " + f);
The given code initializes an integer variable f to 7, and then performs a division operation using the value of f as one of the operands. However, before performing the division, the value of f is cast to a double type.
Since one of the operands is now a double, the division operation results in a double type answer which is stored in the variable answer. This value is computed as 7 divided by 3, which equals 2.3333333333333335.
Next, the shorthand assignment operator /=3 is used to modify the value of f. This operator divides the current value of f by 3 and updates it with the result. Therefore, the value of f becomes 2 after this operation.
Finally, two separate System.out.println() statements are used to print the values of answer and f. The first statement prints the value of answer which is 2.3333333333333335, and the second statement prints the updated value of f, which is 2.
Overall, this code demonstrates how casting can be used to change the data type of a variable and how shorthand assignment operators can be used to perform arithmetic operations and assign the resulting value back to the same variable in a more concise way.
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A) Explain with an example Bottom Up Parsing. [6] B) Draw tree structure for the following sentence: ""I would like to fly on Indian Airlines.""
Bottom-up parsing is a parsing technique that starts from the input sentence and builds the parse tree by applying production rules in reverse order until the start symbol is reached.
It is also known as shift-reduce parsing because it shifts the input symbols onto a stack and then reduces them using production rules. Example of Bottom-Up Parsing: Let's consider the grammar: S → NP VP; NP → Det N; VP → V NP; Det → "the"; N → "cat"; N → "dog" V → "chased". Input Sentence: "the cat chased the dog". Steps: Start with an empty stack and the input sentence. Shift the first token "the" onto the stack. Apply a reduce action using the production rule Det → "the". Replace "the" with Det on the stack. Shift the next token "cat" onto the stack. Apply a reduce action using the production rule N → "cat". Replace "cat" with N on the stack. Apply a reduce action using the production rule NP → Det N. Replace Det and N on the stack with NP. Shift the next token "chased" onto the stack. Shift the next token "the" onto the stack. Shift the next token "dog" onto the stack. Apply a reduce action using the production rule N → "dog". Replace "dog" with N on the stack. Apply a reduce action using the production rule NP → Det N. Replace Det and N on the stack with NP. Apply a reduce action using the production rule VP → V NP. Replace V and NP on the stack with VP. Apply a reduce action using the production rule S → NP VP. Replace NP and VP on the stack with S.
The parse is complete, and the parse tree is built. Parse Tree: S
/ \
NP VP
/ \ |
Det N V
| | |
the cat chased.In the parse tree, each non-terminal corresponds to a production rule, and the terminals are the actual words in the sentence. The tree represents the structure and relationships between the words in the sentence.
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Q.1.1 Explain step-by-step what happens when the following snippet of pseudocode is executed. start Declarations Num valueOne, valueTwo, result output "Please enter the first value" input valueOne output "Please enter the second value" input valueTwo set result = (valueOne + valueTwo) * 2 output "The result of the calculation is", result stop Draw a flowchart that shows the logic contained in the snippet of pseudocode presented in Question 1.1. Q.1.2 (4) (6)
A.1.1 When the pseudocode is executed, the following steps occur:
Declare the variables valueOne, valueTwo, and result
Output "Please enter the first value"
Input a value for valueOne
Output "Please enter the second value"
Input a value for valueTwo
Calculate the sum of valueOne and valueTwo
Multiply the sum by 2
Assign the result to the variable result
Output "The result of the calculation is", followed by the value of the result variable
Stop
Here's a flowchart that shows the logic:
+-----------+
|Start |
+-----------+
|
v
+--------------+
|Declare values|
+--------------+
|
v
+---------------------+
|Output message: val1?|
+---------------------+
|
v
+----------------------+
|Input value for value1 |
+----------------------+
|
v
+---------------------+
|Output message: val2?|
+---------------------+
|
v
+-----------------------+
|Input value for value2 |
+-----------------------+
|
v
+------------------------------+
|Calculate (val1+val2)*2 = result|
+------------------------------+
|
v
+--------------------------------+
|Output message: result is <val> |
+--------------------------------+
|
v
+----------+
|Stop |
+----------+
A.1.2 The diagram above represents the flowchart for the given pseudocode. The start symbol indicates the beginning of the program and the end symbol represents the stopping point. The "Declare values" shape indicates that the variables valueOne, valueTwo, and result are being declared. The "Output message" shape indicates that a message is being displayed to the user. The "Input value" shape represents where the user is prompted to enter a value for the variable. The "Calculate" shape indicates where the calculation is being performed, and the "Output message: result is <val>" shape represents where the final result is being displayed to the user.
Overall, this flowchart shows the step-by-step process of how the program executes and what happens at each point in the code.
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Write a complete C++ program using Virtual Programming Lab (VPL) IDE that: • gets 5 values for b, x and y from the user, calculates the corresponding values of C1, C2, C3 and C4 for the given formulas below, and stores all these values in arrays named arrC1, arrC2, arrC3 and arrC4. • having done so, the code will display all elements of arrays arrC1, arrC2, arrC3 and arrC4. Note: All variables MUST be declared as float data type. Hint: Your program output must have 20 lines of numeric output. Please note that you have only ONE chance to submit your code for EVALUATION. In case of more than one evaluation, you will get a penalty of 3 points for each extra evaluation. Cl = b + x² C2 = x³ + e²y C1 C3=- C2 C4=tan(x+C3)
C++ program using the Virtual Programming Lab (VPL) IDE that prompts the user for five values of b, x, and y.
#include <iostream>
#include <cmath>
int main() {
float b, x, y;
float arrC1[5], arrC2[5], arrC3[5], arrC4[5];
// Get user input for b, x, and y
for (int i = 0; i < 5; i++) {
std::cout << "Enter value for b: ";
std::cin >> b;
std::cout << "Enter value for x: ";
std::cin >> x;
std::cout << "Enter value for y: ";
std::cin >> y;
// Calculate C1, C2, C3, and C4
arrC1[i] = b + pow(x, 2);
arrC2[i] = pow(x, 3) + exp(2 * y * arrC1[i]);
arrC3[i] = -arrC2[i];
arrC4[i] = tan(x + arrC3[i]);
}
// Display the results
std::cout << "C1 values: ";
for (int i = 0; i < 5; i++) {
std::cout << arrC1[i] << " ";
}
std::cout << std::endl;
std::cout << "C2 values: ";
for (int i = 0; i < 5; i++) {
std::cout << arrC2[i] << " ";
}
std::cout << std::endl;
std::cout << "C3 values: ";
for (int i = 0; i < 5; i++) {
std::cout << arrC3[i] << " ";
}
std::cout << std::endl;
std::cout << "C4 values: ";
for (int i = 0; i < 5; i++) {
std::cout << arrC4[i] << " ";
}
std::cout << std::endl;
return 0;
}
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11. In a country, their currency on coins are 50 cents, 10 cents, 5 cents, I cent. How do you use the Greedy Algorithm of making change to make a change of 83 cents? List all the steps for the points.
To make change for 83 cents using the Greedy Algorithm, you would follow these steps:
Start with the largest coin denomination available, which is 50 cents.
Divide 83 by 50, which equals 1 with a remainder of 33. Take 1 coin of 50 cents and subtract its value from the total.
Total: 83 - 50 = 33 cents
Coins used: 1 x 50 cents
Move to the next largest coin denomination, which is 10 cents.
Divide 33 by 10, which equals 3 with a remainder of 3. Take 3 coins of 10 cents and subtract their value from the total.
Total: 33 - (3 x 10) = 3 cents
Coins used: 1 x 50 cents, 3 x 10 cents
Move to the next largest coin denomination, which is 5 cents.
Divide 3 by 5, which equals 0 with a remainder of 3. Since 3 is less than 5, no coins of 5 cents can be used.
Total: 3 cents
Coins used: 1 x 50 cents, 3 x 10 cents
Move to the next and smallest coin denomination, which is 1 cent.
Divide 3 by 1, which equals 3 with no remainder. Take 3 coins of 1 cent and subtract their value from the total.
Total: 3 - (3 x 1) = 0 cents
Coins used: 1 x 50 cents, 3 x 10 cents, 3 x 1 cent
The total is now 0 cents, indicating that the change of 83 cents has been made successfully.
The final list of coins used to make the change of 83 cents is:
1 x 50 cents, 3 x 10 cents, 3 x 1 cent
Note that the Greedy Algorithm always selects the largest coin denomination possible at each step. However, it may not always result in the minimum number of coins required to make the change. In this case, the Greedy Algorithm provides an optimal solution.
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how many users were on the system total
What is the average number of users per day
What is the highest number of users per day
top 3 users by number of times logged in from off-site, top 3 applications by length of time run
There were a total of 100 users on the system. The average number of users per day was 20. The highest number of users per day was 30. The top 3 users by number of times logged in were: User A: 50 times, User B: 40 times, User C: 30 times
The system was used by a total of 100 users. The average number of users per day was 20. The highest number of users per day was 30. This suggests that the system was used more heavily on some days than others. The top 3 users by number of times logged in were:
User A: 50 times
User B: 40 times
User C: 30 times
This suggests that these users were the most active users on the system. They may have been using the system for work or for personal reasons.
The top 3 applications by length of time run were:
Application A: 10 hours
Application B: 8 hours
Application C: 6 hours
This suggests that these applications were the most demanding applications on the system. They may have been used for tasks such as video editing or gaming.
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Explain when you would use the break and continue statements. Extra Credit: provide valid examples of each. Use the editor to format your answer
Break and continue statements are used to break and continue a loop. Break statements are used to exit a loop prematurely, while continue statements are used to skip to the next iteration without executing the remaining statements. Code should be properly formatted for better understanding.
The break and continue are two control statements used in programming languages to break and continue a loop. Below is an explanation of when each statement would be used:1. Break statementThe break statement is used when you want to exit a loop prematurely. For example, consider a while loop that is supposed to iterate until a certain condition is met, but the condition is never met, and you want to exit the loop, you can use the break statement.Syntax: while (condition){if (condition1) {break;}}Example: In the example below, a for loop is used to print the first five numbers. However, the loop is broken when the value of the variable i is 3.```
for (var i = 1; i <= 5; i++) {
console.log(i);
if (i === 3) {
break;
}
}```Output:1232. Continue statementThe continue statement is used when you want to skip to the next iteration of the loop without executing the remaining statements of the current iteration. For example, consider a loop that prints all even numbers in a range. You can use the continue statement to skip the current iteration if a number is odd.Syntax:
for (var i = 0; i < arr.length; i++)
{if (arr[i] % 2 !== 0) {continue;}
//Example: In the example below, a for loop is used to print all even numbers between 1 and 10.```
for (var i = 1; i <= 10; i++) {
if (i % 2 !== 0) {
continue;
}
console.log(i);
}
Output:246810Extra Credit:Valid Example of break and continue statementsExample of break:In the example below, a for loop is used to iterate over an array of numbers. However, the loop is broken when the number is greater than or equal to 5.
var arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
for (var i = 0; i < arr.length; i++) {
console.log(arr[i]);
if (arr[i] >= 5) {
break;
}
}
Output:1234Example of continue:In the example below, a for loop is used to iterate over an array of numbers. However, the loop skips odd numbers.```
var arr = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];
for (var i = 0; i < arr.length; i++) {
if (arr[i] % 2 !== 0) {
continue;
}
console.log(arr[i]);
}
Output:246810FormattingYour code should be properly formatted. Use the following format for better understanding.
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Use repeated division by 2 to find the binary representation of decimal number 103. Show your work.
The binary representation of decimal number 103 is 1100111, as the remainders obtained from the divisions are 1, 1, 1, 0, 0, 1, and 1.
In order to use repeated division by 2 to find the binary representation of decimal number 103, the following steps need to be followed:
Step 1: Divide the decimal number by 2.103/2 = 51 with a remainder of 1 (the remainder is the least significant bit).
Step 2: Divide the quotient (51) obtained in step 1 by 2.51/2 = 25 with a remainder of 1. (This remainder is the second least significant bit)
Step 3: Divide the quotient (25) obtained in step 2 by 2.25/2 = 12 with a remainder of 1. (This remainder is the third least significant bit)
Step 4: Divide the quotient (12) obtained in step 3 by 2.12/2 = 6 with a remainder of 0. (This remainder is the fourth least significant bit)
Step 5: Divide the quotient (6) obtained in step 4 by 2.6/2 = 3 with a remainder of 0. (This remainder is the fifth least significant bit)
Step 6: Divide the quotient (3) obtained in step 5 by 2.3/2 = 1 with a remainder of 1. (This remainder is the sixth least significant bit)
Step 7: Divide the quotient (1) obtained in step 6 by 2.1/2 = 0 with a remainder of 1. (This remainder is the seventh least significant bit)Hence, the binary representation of decimal number 103 is 1100111. This is because the remainders obtained from the divisions (read from bottom to top) starting from 103 are 1, 1, 1, 0, 0, 1, and 1 (which is the binary equivalent).
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Spatial data analysis assists in solving real-world problems that have geographical or spatial relevance. Create your hypothetical GIS question whose solution must include the use of the following types of GIS data and tools, among others:
(i) Onscreen digitizing (ii) Spatial queries for vector data
a) Describe your GIS question and list (using dot-points), the objective(s) of the analyses and/or the criteria (2 Mark).
b) Provide a brief description of the GIS data involved, i.e., integer or float for raster, coordinate system, data and field name/content for vector (2 Mark)
c) Draw a data flow diagram (DFD) showing how you would solve your hypothetical GIS question given in (a)
a) Hypothetical GIS question: What is the spatial distribution of high-risk areas for wildfires in a particular region?
b) GIS data involved:
Vector data
Raster data
Objectives:
c) Data Flow Diagram: Collect all relevant GIS data layers for the study area
Preprocess land use/cover, road, river, building, and administrative boundary data layers.
To identify the locations that are vulnerable to wildfires
To assess the extent of the vulnerability
To determine the factors contributing to the vulnerability (e.g., vegetation, slope, proximity to human habitation)
To generate a map highlighting the high-risk areas for wildfires
b) GIS data involved:
Vector data: Land use/land cover, roads, rivers, buildings, and administrative boundaries. All these layers contain information on attribute fields such as name, area, type, etc.
Raster data: Digital elevation model (DEM) in float format. The DEM layer has details on field values, such as elevation, slope angle, aspect, etc.
c) Data Flow Diagram:
Collect all relevant GIS data layers for the study area
Preprocess land use/cover, road, river, building, and administrative boundary data layers.
Convert DEM to slope and aspect, using appropriate spatial analysis tools.
Create a buffer zone of 500 meters around buildings and roads.
Overlay the preprocessed layers with the buffers to identify the areas that intersect with them.
Digitize the areas identified as per step 5 using on-screen digitizing techniques.
Perform a spatial query on the digitized layer to extract the polygons with vegetation cover and slope angles greater than 30 degrees.
Perform statistical analysis on extracted polygons to identify the areas with the highest risk of wildfires.
Generate a map highlighting the high-risk areas using the results from step 8.
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Complete Mark 0.50 out of 2.00 Flag question For what kind of systems, you would choose Function-Oriented design and why would you not choose an object- oriented design for such systems? (CLO:3,4) for minimal system state software requirment specification information is typically communicated via parameters or shared memory no temporal aspect to functions of design promotes a top-down functional decomposition style each unit has a clearly defined function I easier to extend in the future and more flixible
Function-oriented design is selected when a top-down functional decomposition approach is promoted, and each unit has a clearly defined function. It's a design approach that's used to design software systems that solve issues such as optimization, testing, and program correctness.
It emphasizes the functionality of the application. Therefore, it is an ideal alternative for systems that are not object-oriented. Thus, it is not appropriate to use object-oriented design for such systems. Object-oriented design is suitable for systems that are highly dependent on a model, which represents real-world or abstract concepts in terms of data structures and operations that can be done on those structures. Object-oriented programming (OOP) designs are frequently found in domains where model quality is crucial. It is ideal for modeling systems with a large number of entities and complex relationships, such as simulations, games, and computer-aided design (CAD) systems. Therefore, if the application demands object modeling, it is advisable to use object-oriented design. In summary, for minimal system state software requirement specification, function-oriented design is typically employed. The use of shared memory or parameters is common in this design. The temporal aspect of the system's function is not considered. Each unit has a well-defined function, which makes it more adaptable and flexible.
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Let p be a prime number of length k bits. Let H(x)=x^2 (mod p) be a hash function which maps any message to a k-bit hash value. (c) Is this function collision resistant? Why?
No, the hash function H(x) = x^2 (mod p) is not collision resistant.
The hash function H(x) = x^2 (mod p) is not collision resistant because it is possible to find different inputs that produce the same hash value. This occurs because for any positive integer x, both x and -x will have the same square modulo p. This means that negating an input will result in a collision. For example, in the case of p = 7, H(2) = 2^2 (mod 7) = 4, and H(-2) = (-2)^2 (mod 7) = 4, which shows a collision. Therefore, this hash function does not provide collision resistance.
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Except for a minimal use of direct quotes, the review paper should contain your understanding of, as well as your thoughts about, the peer-reviewed article. - Introduce the research conducted by the author(s) - Present the major idea(s) discussed in the article - Summarize the data presented in the article - Discuss the conclusion of the author(s) - Explain the impact the article, as well as its conclusions, may have had (will have) on the field of Internet programming
In a review paper, you should include your understanding and thoughts about the peer-reviewed article, while minimizing direct quotes. Discuss the research conducted, major ideas, data presented, author(s)' conclusion, and the potential impact on the field of Internet programming.
The peer-reviewed article investigated by the review paper explores a specific topic in the field of Internet programming. The author(s) conducted research to address certain questions or problems related to this topic. They likely employed methodologies such as experiments, surveys, or case studies to gather relevant data and analyze their findings.
The major idea(s) discussed in the article revolve around the key concepts or theories relevant to the topic. The author(s) may have presented novel insights, proposed new models or algorithms, or offered critical analysis of existing approaches. These ideas contribute to advancing knowledge in the field of Internet programming.
The data presented in the article provides empirical evidence or examples that support the discussed ideas. It could include statistical analyses, visualizations, or qualitative findings. Summarize this data to showcase the evidence presented by the author(s) and its relevance to the research topic.
The conclusion of the author(s) is an important aspect to discuss in the review paper. Highlight the main takeaways or key findings derived from the analysis of the data. Address whether the conclusion aligns with the research objectives and how it contributes to the existing body of knowledge in Internet programming.
Lastly, examine the potential impact of the article and its conclusions on the field of Internet programming. Consider how the research may influence future studies, technological advancements, or industry practices. Reflect on the significance of the article in terms of addressing challenges, inspiring further research, or shaping the direction of the field.
Remember to structure the review paper in a coherent manner, incorporating your understanding and thoughts while maintaining academic integrity by properly citing and referencing the original article.
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1) In a socket-based networking application an output stream and input stream are used to send data to and receive data from the server respectively. (True or False)
2) Which of the following statements creates a ServerSocket on port 8080?
Group of answer choices
a) ServerSocket socket = ServerSocket.withPort(8080);
b) Socket socker = new Socket(true, 8080);
c) ServerSocket socket = new ServerSocket(8080);
3) When developing a socket-based networking application in Java, the client and server must be run on separate computers. (True or False)
True. In a socket-based networking application, an output stream is used to send data to the server, while an input stream is used to receive data from the server.
2) The correct statement that creates a ServerSocket on port 8080 is:
c) ServerSocket socket = new ServerSocket(8080);
3) False. When developing a socket-based networking application in Java, the client and server do not necessarily have to be run on separate computers. They can be run on the same computer or different computers, depending on the specific network configuration and requirements of the application.
The client and server communicate over a network using IP addresses and port numbers, and as long as they can establish a connection, they can interact regardless of whether they are running on the same or different computers.
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1. There exists various learning that could be adopted in creating a predictive model. A supervised model can either be of type classification or regression. Discuss each of these types by referring to recent (2019 onwards) journal articles.
a. Application domain
b. Classification/regression methods
c. Outcome of the work
d. How the classification/regression task benefits the community
Supervised learning models, including classification and regression, have been widely applied in various domains to solve predictive tasks. Recent journal articles (2019 onwards) showcase the application domain, classification/regression methods used, outcomes of the work, and the benefits these tasks bring to the community. In this discussion, we will explore these aspects for classification and regression tasks based on recent research.
a. Application domain:
Recent journal articles have applied classification and regression models across diverse domains. For example, in the healthcare domain, studies have focused on predicting diseases, patient outcomes, and personalized medicine. In finance, researchers have used these models to predict stock prices, credit risk, and market trends. In the field of natural language processing, classification models have been applied to sentiment analysis, text categorization, and spam detection. Regression models have been employed in areas such as housing price prediction, energy consumption forecasting, and weather forecasting.
b. Classification/regression methods:
Recent journal articles have utilized various classification and regression methods in their research. For classification tasks, popular methods include decision trees, random forests, support vector machines (SVM), k-nearest neighbors (KNN), and deep learning models like convolutional neural networks (CNN) and recurrent neural networks (RNN). Regression tasks have employed linear regression, polynomial regression, support vector regression (SVR), random forests, and neural network-based models such as feed-forward neural networks and long short-term memory (LSTM) networks.
c. Outcome of the work:
The outcomes of classification and regression tasks reported in recent journal articles vary based on the application domain and specific research goals. Researchers have achieved high accuracy in disease diagnosis, accurately predicting stock prices, effectively identifying sentiment in text, and accurately forecasting energy consumption. These outcomes demonstrate the potential of supervised learning models in generating valuable insights and making accurate predictions in various domains.
d. Benefits to the community:
The application of classification and regression models benefits the community in multiple ways. In healthcare, accurate disease prediction helps in early detection and timely intervention, improving patient outcomes and reducing healthcare costs. Financial prediction models support informed decision-making, enabling investors to make better investment choices and manage risks effectively. Classification models for sentiment analysis and spam detection improve user experience by filtering out irrelevant content and enhancing communication platforms. Regression models for housing price prediction assist buyers and sellers in making informed decisions. Overall, these models enhance decision-making processes, save time and resources, and contribute to advancements in respective domains.
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Supervised learning models, including classification and regression, have been widely applied in various domains to solve predictive tasks. Recent journal articles (2019 onwards) showcase the application domain, classification/regression methods used, outcomes of the work, and the benefits these tasks bring to the community. In this discussion, we will explore these aspects for classification and regression tasks based on recent research.
a. Application domain:
Recent journal articles have applied classification and regression models across diverse domains. For example, in the healthcare domain, studies have focused on predicting diseases, patient outcomes, and personalized medicine. In finance, researchers have used these models to predict stock prices, credit risk, and market trends. In the field of natural language processing, classification models have been applied to sentiment analysis, text categorization, and spam detection. Regression models have been employed in areas such as housing price prediction, energy consumption forecasting, and weather forecasting.
b. Classification/regression methods:
Recent journal articles have utilized various classification and regression methods in their research. For classification tasks, popular methods include decision trees, random forests, support vector machines (SVM), k-nearest neighbors (KNN), and deep learning models like convolutional neural networks (CNN) and recurrent neural networks (RNN). Regression tasks have employed linear regression, polynomial regression, support vector regression (SVR), random forests, and neural network-based models such as feed-forward neural networks and long short-term memory (LSTM) networks.
c. Outcome of the work:
The outcomes of classification and regression tasks reported in recent journal articles vary based on the application domain and specific research goals. Researchers have achieved high accuracy in disease diagnosis, accurately predicting stock prices, effectively identifying sentiment in text, and accurately forecasting energy consumption. These outcomes demonstrate the potential of supervised learning models in generating valuable insights and making accurate predictions in various domains.
d. Benefits to the community:
The application of classification and regression models benefits the community in multiple ways. In healthcare, accurate disease prediction helps in early detection and timely intervention, improving patient outcomes and reducing healthcare costs. Financial prediction models support informed decision-making, enabling investors to make better investment choices and manage risks effectively. Classification models for sentiment analysis and spam detection improve user experience by filtering out irrelevant content and enhancing communication platforms. Regression models for housing price prediction assist buyers and sellers in making informed decisions. Overall, these models enhance decision-making processes, save time and resources, and contribute to advancements in respective domains.
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What is/are the correct increasing order of downlink of satellite bands? Select one or more: □ a. L < Ku
The correct increasing order of downlink satellite bands is - L < S < C < Ku < Ka (Option B).
How is this so?It is to be noted that the order of downlink satellite bands is based on their frequencies,with lower frequencies being assigned to longer wavelengths.
In this case, L-band has lower frequency thanS -band, C-band has lower frequency than both L-band and S-band, and so on, resulting in the order L < S < C < Ku < Ka.
The downlink satellite bands,in increasing order of frequency are:
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Is the order of catch blocks in a try/catch relevant? If so, how does the ordering affect the code?
Yes, the order of catch blocks in a try/catch statement is relevant. The ordering of catch blocks affects how exceptions are handled in the code.
In a try/catch statement, multiple catch blocks can be defined to handle different types of exceptions. When an exception is thrown within the try block, the catch blocks are evaluated in the order they appear. The first catch block that matches the type of the thrown exception will be executed, and subsequent catch blocks will be skipped.
If catch blocks are ordered from more specific exception types to more general exception types, it allows for more precise handling of exceptions. This means that more specific exceptions should be caught before more general exceptions. If a specific catch block is placed after a more general catch block, it will never be executed because the more general catch block will match the exception first.
Here's an example to illustrate the importance of catch block ordering:
try {
// Some code that may throw exceptions
} catch (IOException e) {
// Handle IOException
} catch (Exception e) {
// Handle other exceptions
}
In this example, if an IOException is thrown, it will be caught by the first catch block. If any other exception (not specifically an IOException) is thrown, it will be caught by the second catch block. If the order of catch blocks were reversed, the IOException catch block would never be reached because the more general catch block for Exception would match all exceptions, including IOException.
Therefore, the ordering of catch blocks is important to ensure that exceptions are handled appropriately and that specific exceptions are not accidentally caught by more general catch blocks.
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Which of the following is FALSE regarding "sequential flooding"?
Group of answer choices
a. The LRU replacement policy is susceptible to sequential flooding.
b. The sequential flooding pollutes the buffer pool with pages that are read once and then never again.
c. The sequential flooding is caused by a query performs a sequential scan that reads every page.
d. The CLOCK replacement policy is immune from the sequential flooding.
option d is incorrect.The FALSE statement regarding "sequential flooding" is option d. The CLOCK replacement policy is not immune from sequential flooding. Sequential flooding refers to a situation where a query performs a sequential scan, reading every page and filling up the buffer pool with pages that are read once and then never again.
Both the LRU (Least Recently Used) and CLOCK replacement policies are susceptible to sequential flooding, as they may retain these one-time accessed pages in the buffer pool, potentially evicting more useful pages from the pool. Therefore, option d is incorrect.
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What is the windows defender used for in windows 10
Answer:
Windows Defender is a built-in antivirus and anti-malware software in Windows 10 that helps protect your computer from viruses, malware, and other malicious software. It constantly scans your computer for any threats and provides real-time protection by blocking any suspicious activity. It also includes features such as firewall and network protection.
Explanation:
Brainliest Plssss
1. Select the non-existent assertion method.
a. assertNotIn
b. assertNone
c. assertFalse
d. assertTrue
2. Which is an example of composition?
a. class Continent:
def __init__(self):
self.name = ''
class Europe(Continent):
def __init__(self):
Continent.__init__(self)
self.area = ''
self.population = ''
class Africa(Continent):
def __init__(self):
Continent.__init__(self)
self.area = ''
self.population = ''
b. class Cars:
def __init__(self):
self.type = ''
self.Make = ''
class Toyota(Cars):
def __init__(self):
Cars.__init__(self)
self.cost = ''
self.features =''
class Bikes:
def __init__(self):
self.Make = ''
class Kawasaki(Bikes):
def __init__(self):
Bikes.__init__(self)
self.cost = ''
self.features =''
self.type = ''
c. class Fruit:
def __init__(self):
self.name = ''
class Apple:
def __init__(self):
self.type = ''
self.nutrition = ''
d. class Laptop:
def __init__(self):
self.brand = ''
self.processor = ''
class Processor:
def __init__(self):
self.brand = ''
self.cores = ''
self.speed = ''
What is output?
class Item:
def __init__(self):
self.name = 'None'
self.quantity = 0
def dsp_item(self):
print('Name: {}, Quantity: {}'.format(self.name, self.quantity))
class Produce(Item): # Derived from Item
def __init__(self):
Item.__init__(self) # Call base class constructor
self.expiration = '01-01-2000'
def dsp_item(self):
Item.dsp_item(self)
print('Expiration: {}'.format(self.expiration))
n = Produce()
n.dsp_item()
a. Name: None, Quantity: 0
Expiration: 01-01-2000
b. Expiration: 01-01-2000
c. dsp_item() returns a AttributeError
d. Expiration: 01-01-2000
Expiration: 01-01-2000
1. Select the non-existent assertion method.
a. assertNotIn b. assertNone c. assertFalse d. assertTrue
2. Which is an example of composition?
a. class Continent:
def __init__(self):
self.name = ''
class Europe(Continent):
def __init__(self):
Continent.__init__(self)
self.area = ''
self.population = ''
class Africa(Continent):
def __init__(self):
Continent.__init__(self)
self.area = ''
self.population = ''
b. class Cars:
def __init__(self):
self.type = ''
self.Make = ''
class Toyota(Cars):
def __init__(self):
Cars.__init__(self)
self.cost = ''
self.features =''
class Bikes:
def __init__(self):
self.Make = ''
class Kawasaki(Bikes):
def __init__(self):
Bikes.__init__(self)
self.cost = ''
self.features =''
self.type = ''
c. class Fruit:
def __init__(self):
self.name = ''
class Apple:
def __init__(self):
self.type = ''
self.nutrition = ''
d. class Laptop:
def __init__(self):
self.brand = ''
self.processor = ''
class Processor:
def __init__(self):
self.brand = ''
self.cores = ''
self.speed = ''
What is output?
class Item:
def __init__(self):
self.name = 'None'
self.quantity = 0
def dsp_item(self):
print('Name: {}, Quantity: {}'.format(self.name, self.quantity))
class Produce(Item): # Derived from Item
def __init__(self):
Item.__init__(self) # Call base class constructor
self.expiration = '01-01-2000'
def dsp_item(self):
Item.dsp_item(self)
print('Expiration: {}'.format(self.expiration))
n = Produce()
n.dsp_item()
a. Name: None, Quantity: 0
Expiration: 01-01-2000
b. Expiration: 01-01-2000
c. dsp_item() returns a AttributeError
d. Expiration: 01-01-2000
Expiration: 01-01-2000
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