Please help me complete this, it’s my last chance

Answer:

O2 is the limiting reactant.

Explanation:

Hello there!

In this case, according to the given information about this reaction, one could identify the limiting reactant by performing a mole ratio of H2S to SO2 and O2 to SO2:

[tex]14.3molH_2S*\frac{2molSO_2}{2molH_2S}=14.3molSO_2 \\\\17.1molO_2*\frac{2molSO_2}{3molO_2}=11.4molSO_2[/tex]

Thus, since 17.1 moles of O2 yields fewer moles than 14.3 moles of H2S, we infer the former is the limiting reactant.

Regards!

Answer: 26 moles of [tex]PH_3[/tex] are required for the reaction.

Explanation:

We are given:

Moles of [tex]P_4O_{10}[/tex] = 6.5 moles

The given chemical reaction follows:

[tex]4PH_3(g)+8O_2(g)\rightarrow P_4O_{10}(s)+6H_2O(g)[/tex]

By the stoichiometry of the reaction:

If 1 mole of [tex]P_4O_{10}[/tex] is produced by 4 moles of [tex]PH_3[/tex]

So, 6.5 moles of [tex]P_4O_{10}[/tex] will be produced by = [tex]\frac{4}{1}\times 6.5=26mol[/tex] of [tex]PH_3[/tex]

Hence, 26 moles of [tex]PH_3[/tex] are required for the reaction.

Answer:

See explanation

Explanation:

Specific activity of an enzyme is defined as a measure of the rate of reaction between enzyme and substrate.

In the study of enzyme kinetics, specific activity is particularly regarded to be the amount of substrate converted by the enzyme per milligram of protein per unit of time. It is thus a reliable measure of enzyme activity per milligram of total protein.

On the other hand, the turnover number is defined as a measure of the number of conversions achieved by a substrate molecule in one second at a particular active site depending on the specific enzyme concentration.

Since specific activityof the enzyme is the ratio of the enzyme activity to enzyme concentration, then specific activity can be used as a measurement of enzyme purity.

Answer:

Solubility indicates the maximum amount of a substance that can be dissolved in a solvent at a given temperature. Such a solution is called saturated. Divide the mass of the compound by the mass of the solvent and then multiply by 100 g to calculate the solubility in g/100g .

Solubility of solute:

To calculate the solubility in g/100g:

Solubility of NaNO₃=[tex]\frac{21.9g*100g}{25 g} =87.6[/tex]

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Answer: hello your question has some missing data attached below is the complete question.

answer:

attached below

Explanation:

Attached below is the mechanism for proton transfer

a) HBr

H₃O + Br⁻

b) attached below

c) attached below

Answer:

to remove any remaining 2,4-dinitrophenylhydrazone

Explanation:

Usually, when an organic compound is synthesised, traces of impurities such as excess reagents or solvent remain in the product.

It is therefore imperative that these contaminants are removed so that the product can attain a very high degree of purity.

Hence, during the synthesis of 2,4-dinitrophenylhydrazone derivative, 10 mL of 2 M hydrochloric acid is titrated against the crude product so that any remaining 2,4-dinitrophenylhydrazone is removed.

Answer:

Answer: There are 1.53 moles present in   molecules of water in a beaker.

Explanation:

According to the mole concept, there are  molecules present in 1 mole of a substance.

So, number of moles present in  molecules are calculated as follows.

Thus, we can conclude that there are 1.53 moles present in   molecules of water in a beaker.

Explanation:

Answer:

[tex]T_F=77.4\°C[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible to set up the following energy equation for both objects 1 and 2:

[tex]Q_1=-Q_2[/tex]

In terms of mass, specific heat and temperature change is:

[tex]m_1C_1(T_F-T_1)=-m_2C_2(T_F-T_2)[/tex]

Now, solve for the final temperature, as follows:

[tex]T_F=\frac{m_1C_1T_1+m_2C_2T_2}{m_1C_1+m_2C_2}[/tex]

Then, plug in the masses, specific heat and temperatures to obtain:

[tex]T_F=\frac{760g*0.87\frac{J}{g\°C} *52.2\°C+70.7g*3.071\frac{J}{g\°C}*154\°C}{760g*0.87\frac{J}{g\°C} +70.7g*3.071\frac{J}{g\°C}} \\\\T_F=77.4\°C[/tex]

Yet, the values do not seem to have been given correctly in the problem, so it'll be convenient for you to recheck them.

Regards!

Answer:

Percentage yield = 36.75%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

C + O₂ —> CO₂

Next, we shall determine the mass of C that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:

Molar mass of C = 12 g/mol

Mass of C from the balanced equation = 1 × 12 = 13 g

Molar mass of CO₂ = 12 + (2×16)

= 12 + 32

= 44 g/mol

Mass of CO₂ from the balanced equation = 1 × 44 = 44 g

SUMMARY:

From the balanced equation above,

12 g of C reacted to produce 44 g of CO₂.

Next, we shall determine the theoretical yield of CO₂. This can be obtained as follow:

From the balanced equation above,

12 g of C reacted to produce 44 g of CO₂.

Therefore, 9.50 g of C will react to produce = (9.50 × 44) / 12 = 34.83 g of CO₂.

Thus, the theoretical yield of CO₂ is 34.83 g.

Finally, we shall determine the percentage yield of the reaction. This can be obtained as follow:

Actual yield of CO₂ = 12.8

Theoretical yield of CO₂ = 34.83 g

Percentage yield =?

Percentage yield = Actual yield / Theoretical yield × 100

Percentage yield = 12.8 / 34.83 × 100

Percentage yield = 1280 / 34.83

Percentage yield = 36.75%

Explanation:

The atomic number is equal to the number of protons in an atom's nucleus. Hydrogen's atomic number is 1 because all hydrogen atoms contain exactly one proton.

Answer:

[tex]m_{KMnO_4}=90.9gKMnO_4[/tex]

Explanation:

Hello there!

In this case, according to the given chemical equation for the reaction for the production of potassium permanganate, we can see a 2:2 mole ratio of this product to the starting manganese (II) oxide, which means, we can calculate the theoretical yield of the former via stoichiometry:

[tex]m_{KMnO_4}=50.0gMnO_2*\frac{1molMnO_2}{86.94gMnO_2}*\frac{2molKMnO_4}{2molMnO_2} *\frac{158.034gKMnO_4}{1molKMnO_4} \\\\m_{KMnO_4}=90.9gKMnO_4[/tex]

Regards!

Answer:

the characteristics of primary standard substances are:

1.High purity.

2.Stability (low reactivity)

3.Low hygroscopicity

4.High equivalent weight

5.Non-toxicity.

Ready and cheap availability.

Answer:

aa

Explanation:

There is a lowercase a on both sides.

Answer:

12,096 mg of antibiotics

Explanation:

cuz honeyyy:

160lb=72 kg

6mg twice a day so daily 12mg

12mg per kg so 12×72 =864

for 14 days is :864×14=12,096

Answer:

When red cabbage is treated with an acid or a base, it produces anthocyanin, a water-soluble pigment that changes color. In acidic situations with a pH less than 7, the pigment turns red, whereas in alkaline (basic) situations with a pH more than 7, the pigment turns bluish-green.

Explanation:

Answer:

A mixture of 3 moles of N2, 5 moles of CO2, and 10moles of Cl2 exert a total pressure of 1120 mmHg. What is the partial pressure of CO2?

Explanation:

According to Dalton's law of partial pressures:

The partial pressure of a gas can be determined by using the formula:

[tex]the partial pressure of a gas = mole fraction of the gas * total pressure[/tex]

Partial pressure of CO2:

[tex]partial pressure of CO2= total pressure * mole fraction of CO2\\\\Mole fraction of CO2=\frac{number of moles of CO2}{total number of moles of all the gases} \\mole fraction of CO2=\frac{5mol}{3mol+5mol+10mol} = 5/18\\Partial pressure of CO2=\frac{5}{18} * 1120mmHg\\ =311.1mmHg[/tex]

Hence, the partial pressure of CO2 is 311.1mmHg.

Answer:

a  lipped cylindrical glass container for laboratory use

Explanation:

Answer:

[tex]n_{Mg}=3.50molMg\\\\ n_{Cl}=7.00molCl\\\\n_O=28.0molO[/tex]

Explanation:

Hello there!

In this case, according to the given information it turns out possible for us to realize that one mole of the given compound, Mg(ClO₄)₂, has one mole of Mg, two moles of Cl and eight moles of O; thus, we proceed as follows:

[tex]n_{Mg}=3.50molMg(ClO_4)_2*\frac{1molMg}{1molMg(ClO_4)_2}=3.50molMg\\\\ n_{Cl}=3.50molMg(ClO_4)_2*\frac{2molCl}{1molMg(ClO_4)_2}=7.00molCl\\\\n_O=3.50molMg(ClO_4)_2*\frac{8molO}{1molMg(ClO_4)_2}=28.0molO[/tex]

Best regards!

Answer:

[tex]Key=2.5x10^{-9}[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to calculate the equilibrium constant value for the reverse reaction:

[tex]2CO_2(g) \rightleftharpoons 2CO(g) + O_2(g)[/tex]

By knowing that the equilibrium expression is actually:

[tex]Key =\frac{[CO]^2[O_2]}{[CO_2]^2} =\frac{1}{Keg}[/tex]

Thus, we plug in and solve for the inverse of Keq to obtain Key as follows:

[tex]Key =\frac{1}{4.0x10^{-10}}\\\\Key=2.5x10^{-9}[/tex]

Regards!

Answer:

B

Explanation:

C and D is correct

To be clear that electrochemical is science that study the exchange conversion of chemical energy and electric energy through redox reaction

As c is salt bridge

And d is electrochemical define

A is correct as the electricity transfer in electric wire not in solution so its B) un correct

The statement which is not true about the electrochemical cell is option B, the metals that form the electrodes cannot be identical.

In an electrochemical cell, two different metals or metal ions are typically used as the electrodes. These electrodes are placed in separate compartments, which contain the reaction solutions and are connected by a salt bridge or porous membrane.

During the cell's operation, electrons flow through an external wire or circuit, from the anode (where oxidation occurs) to the cathode (where reduction occurs), and nonparticipating ions flow through the salt bridge or porous membrane to maintain charge neutrality.

An oxidation-reduction reaction must occur to generate an electrical potential difference between the two electrodes, driving the flow of electrons through the external circuit. Therefore, options A, C, and D are true for an electrochemical cell. Hence, B is incorrect.

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Answer:

The correct answer is - d. hydrogen bonding.

Explanation:

Water has strong hydrogen bonds between its molecules that require a very high amount of energy in order to break. Water molecules are joined together or bound with a strong intermolecular force called hydrogen bonds.

These bonds require more kinetic energy which means more temperature or heat in order to break the bonds and turn into steam and this is the reason it has a high boiling point.

Answer:

[tex]1 {s}^{2} 2 {s}^{2} 2 {p}^{4} [/tex]

OR

[tex]2 : 6[/tex]

Answer:

If we look at the ground state (electrons in the energetically lowest available orbital) of oxygen, the electron configuration is [tex]1s^{2} 2s^{2} 2p^{4}[/tex] . If the element were to become excited, the electron could occupy an infinite number of orbitals. However, in most texts, the example will be the next available one. So for oxygen, it might look like this:  [tex]1s^{2} 2s^{2} 2p^{3}3s^{1}[/tex]  - where the valence electron now occupies the 3s orbital in an excited (i.e. not ground) state.

So, the electron configuration of oxygen in its excited state​ is [tex]1s^{2} 2s^{2} 2p^{3}3s^{1}[/tex].

Answer: The bond present in given compounds is as follows-

Explanation:

An ionic bond is always formed between a metal and a non-metal atom.

For example, MgF has metal magnesium and non-metal fluorine. So, an ionic bond is there in the compound MgF.

When sharing of electrons occur between atoms of different electronegativity then the bond formed is called a polar covalent bond.

For example, C-O has a polar covalent bond.

For example, Cl-Cl is a non-polar covalent bond.

Answer:

pa helpppp

Explanation:

pleseee need answerrrr

The correct relations for exothermic and endothermic reactions from the given relations is  H Products > H Reactants in exothermic reactions. Hence, Option (D) is Correct.

In thermochemistry, an exothermic reaction is a "reaction for which the overall standard enthalpy change ΔH⚬ is negative." Exothermic reactions usually release heat.

Therefore, The correct relations for exothermic and endothermic reactions from the given relations is  H Products > H Reactants in exothermic reactions. Hence, Option (D) is Correct.

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Answer:

0.123 mol

Explanation:

Step 1: Convert 250 °C to Kelvin

We will use the following expression.

K = °C + 273

K = 250 + 273 = 523 K

Step 2: Calculate the number of moles of gas (n)

A gas occupies a container with volume (V) 3.2 L at a temperature (T) of 523 K and pressure (P) of 1.65 atm. We can calculate the number of moles of the gas using the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.65 atm × 3.2 L / (0.0821 atm.L/mol.K) × 523 K = 0.123 mol

Answer:

C. 2.70 g/mL

Explanation:

Density is the ratio between the mass of a substance and the volume it occupies. Based on Archimedes' volume, the displaced volume of the aluminium is the volume it occupies. To solve this question we must find the difference in volume between initial volume of water = 30mL and final volume of water + aluminium = 39.26mL. This difference is the volume of the aluminium. With its mass we can find density:

39.26mL - 30mL = 9.26mL

Density = 25.00g / 9.26mL =

2.70g/mL

Right answer is:

Answer:

3.59x10⁻⁴ mol

Explanation:

Assuming ideal behaviour we can solve this problem by using the PV=nRT formula, where:

We input the data given by the problem:

And solve for n: