is this correct and why​

Explanation:

u7ruey737€*hr7j37j27jw7uw7bwydbe7887yeyhduheyheyy755÷÷+5÷÷8€737€=67577

Answer:

16.67 m/s

Explanation:

Let that velocity be v.

Using conservation of momentum:

Initial momentum = final momentum

momentum of car1 = momentum of cars

mass1 x velocity1 = (m1 + m2)v

1500*30 = (1500 + 1200)v

45000/2700 = v

16.67 m/s = v

If you drag a bag across floor, you are experiencing a friction force

if you throw a paper or feather up, it floats side ways slowly. It is called air Resistance.

if you push or pull a Door, it is Normal force.

I hope this helped!

have an amazing Day!!

Answer:

I(sphere) = 2/5 M R^2

I(rod) = 1/3 M L^2

I(cylinder) = 1/2 M R^2

From the information given I would assume that

the cylinder is the correct answer.

Answer:

b.lead

Explanation:

Answer:

B)Lead

Explanation:

I did the usatestprep

Answer:

when water hits a metal surface it alongside oxygen have a chemical reaction making Hydrogenated Iron Oxide

Explanation:

what i remember from 7th grade

Answer:

5 m/s

Explanation:

Answer:

The correct solution is:

(a) [tex]1.375\times 10^{-2} \ J[/tex]

(b) [tex]4.43\times 10^{-3} \ C[/tex]

(c) [tex]1.42\times 10^{-3} \ F[/tex]

(d) [tex]178.57 \ \Omega[/tex]

Explanation:

The given values are:

Effective duration of the flash,

ζ = 0.25 s

Average power,

[tex]P_{avg}=55 \ mW[/tex]

       [tex]=55\times 10^{-3} \ W[/tex]

Average voltage,

[tex]V_{avg}=3.1 \ V[/tex]

Now,

(a)

⇒ [tex]E=P_{avg}\times \zeta[/tex]

On substituting the values, we get

⇒     [tex]=55\times 10^{-3}\times 0.25[/tex]

⇒     [tex]=1.375\times 10^{-2} \ J[/tex]

(b)

⇒ [tex]E=Q\times V_{avg}[/tex]

then,

⇒ [tex]Q=\frac{E}{V_{avg}}[/tex]

On substituting the values, we get

⇒     [tex]=\frac{1.375\times 10^{-2}}{3.1}[/tex]

⇒     [tex]=4.43\times 10^{-3} \ C[/tex]

(c)

⇒ [tex]C=\frac{Q}{V}[/tex]

⇒     [tex]=\frac{4.43\times 10^{-3}}{3.1}[/tex]

⇒     [tex]=1.42\times 10^{-3} \ F[/tex]

(d)

As we know,

⇒ [tex]R=\frac{1}{4C}[/tex]

⇒     [tex]=\frac{1}{4\times 1.42\times 10^{-3}}[/tex]

⇒     [tex]=\frac{1000}{5.6}[/tex]

⇒     [tex]=178.57 \ \Omega[/tex]

Answer:

c

Explanation:

It contains both kinetic and potential energy.

Answer:

speed and velocity or direction.

Answer:

3333.3 ohm

Explanation:

V=IR so R =V/I (in Ampere) so convert 3.6 mA to 3.6*10^-3 A

so R =12/3.6*10^-3 =3333.3

Answer:

a,b)   #_ {electron} = 1.64 10¹⁹ electrons, c)  R = 19.54  Ω, d)   V = 10.3 V

Explanation:

a and b) The current is defined as the number of electrons that pass per unit of time

let's look for the load

            Q = I t

            Q = 0.526  5

            Q = 2.63 C

Let's use a direct rule of three proportions. If an electron has a charge of 1.6 10⁻¹⁹ C, how many electrons does 2.63 C have?

           #_ {electron} = 2.63 C (1 electron / 1.6 10⁻¹⁹)

           #_ {electron} = 1.64 10¹⁹ electrons

c) the resistance of a wire is given by

          R = ρ l / A

where the resistivity of tungsten is 5.6 10⁻⁸ Ω

the area of ​​the wire is

           A = π r2 = π d²/4

we substitute

            R = [tex]\rho \ l \ \frac{4}{\pi d^2}[/tex]

let's calculate

           R = 5.6 10⁻⁸  0.580 [tex]\frac{4}{ \pi (0.046 \ 10^{-3})^2 }[/tex]

           R = 19.54  Ω

d) let's use ohm's law

           V = i R

            V = 0.526 19.54

            V = 10.3 V

Answer:

Impulse = [tex]206.28 * 10 = 2062.8[/tex] g.m/s

Explanation:

Impulse is equal to the product of force and time

Here

Density of car =  [tex]0.54[/tex]  g/mL

Volume of car [tex]= 38.2[/tex] mL

Mass of the car is equal to the product of density and volume of car

Mass of the car [tex]= 0.54 * 38.2[/tex] [tex]= 20.628[/tex] grams

Acceleration of the car is [tex]10[/tex] m/s^2

Force is equal to product of mass and acceleration

F = [tex]20.628 * 10 = 206.28[/tex] g .m/s^2

Impulse = F * t

Impulse = [tex]206.28 * 10 = 2062.8[/tex] g.m/s

Explanation:

Drinking water requirement in town 2.0 m^3/s of water per second

nitrate in local well  nitrate per 15 [tex]\mathrm{m}^{3}[/tex] of water

nitrate in distant reservoir [tex]=5 \mathrm{~g} / \mathrm{m}^{3}[/tex]

Let the flow rate of well

flow rate of reservoir [tex]=y m^{3} / s[/tex]

Drinking water requirement is [tex]45 \mathrm{ppm}[/tex] or [tex]45 \mathrm{~g} / \mathrm{m}^{3}[/tex]

therefore, the total flow of drinking water

Answer:

Explanation:

this is the answer

Answer:

1.true

2true

3.false

Explanation:

espero que te ayude

Answer: I think the answer is b

Explanation:

Answer:

C

Explanation:

trust me

D. Fixed position ,mean position , Equilibrium position.

Wave motion is the transfer of energy and momentum from one point of the medium to another point of the medium without actual transport of matter between two points.

The particles of the medium vibrate about their equilibrium position in a direction parallel to the direction of propagation of the wave is called a longitudinal waves.

Characteristics of Wave Motion

In wave motion, the disturbance travels through the medium due to repeated periodic oscillations of the particles of the medium about their mean position (or) Equilibrium position.

Energy and momentum are transferred from one point to another without any actual transfer of the particles of the medium.

There is a regular phase difference between the particles of the medium because each particle receives disturbance little later than its preceding particle.

Therefore,

In a wave, each particle of the medium vibrates, or oscillates, around a fixed position.

Learn more about wave motion here:

https://brainly.com/question/12512349

#SPJ2

Explanation:

resistance of wire can be determined by this equation

R = Rho . L / A

L = the length of wire

A = the Area, A = πr²

Rho = density of resictance

we can do some rational

R1/R2 = ( Rho L1/A1) / (Rho L2/A2)

L2 is the condition when the length is doubled and

L2 = 2 x L

A2 is the condition when the diameter is doubled

A2 = 4A1

R/R2 = (L1/A1)/(L2/A2)

R/R2 = (L/A) / (2L/4A)

R/R2 = 1 / ½

R2 = ½ R.

then we use formula of Voltage

V = I R

1st condition

V = 0.3 R

2nd condition ( V is constant)

V = I2 R2

0.3 R = I2 x ½R

i2 = 0.3/ ½

i2 = 0.6 Ampere

Answer: Convection

Explanation:

Convection can be defined as the transfer of heat energy from a fluid as hotter materials in the fluid rise up and cooler ones sink down. This results as the hot materials have low density as compared to those which are cold. In the decorative lamp the globs break out as the evaporated form of liquid rises up due to low density and the remaining cold fluid remains at the bottom as a result of convection.

Answer:

d. an object immersed in a fluid is buoyed up by a force equal to the weight of the displaced fluid.

Answer:

I don't know.

Answer:

mountain range:)

Explanation:

Answer:

8512 N

Explanation:

From the work energy theorem we know that: The net work done on a particle equals the change in the particles kinetic energy:

[tex]W=\Delta K=K_{f}-K_{i} \\ \\qquad \begin{array}{r} W=F \cdot d, \Delta K=\frac{1}{2} m v_{f}^{2}-\frac{1}{2} m v_{i}^{2} \\ F \cdot d=\frac{1}{2} m v_{f}^{2}-\frac{1}{2} m v_{i}^{2}[/tex]

Where:

-W is the work done by the force.

- F is the force actin on the.

- d is the distance travelled.

- m is the mass of the car.

- [tex]v_{f}, v_{i}[/tex] are the final and the initial velocity of the car

[tex]K_{f}, K_{i}[/tex] are the final and the kinetic energy of the car.

Givens: [tex]m=830 \mathrm{~kg}, v_{i}=2 \mathrm{~m} / \mathrm{s}, v_{f}=0 \mathrm{~km} / \mathrm{h}, d=0.195 \mathrm{~m}[/tex]

Plugging known information to get:

[tex]F \cdot d &=\frac{1}{2} m v_{f}^{2}-\frac{1}{2} m v_{i}^{2} \\ F &=\frac{\frac{1}{2} m v_{f}^{2}-\frac{1}{2} m v_{i}^{2}}{d} \\ &=\frac{0-\frac{1}{2} \times 830 \times 2^{2}}{0.195} \\ &=8.512 \times 10^{3} \\ F &=8.512 \times 10^{3} \mathrm{~N}[/tex]

Answer: [tex]7.95^{\circ}C[/tex]

Explanation:

Given

Mass of water is [tex]m_1=1\ kg[/tex]

mass of ice is [tex]m_2=0.1\ kg[/tex]

Latent heat of fusion [tex]L=3.33\times 10^5\ kJ/kg[/tex]

The heat capacity of water is [tex]c_{w}=4186\ J/kg^{\circ}C[/tex]

Suppose water is at  [tex]T^{\circ} C[/tex]  and it reaches to [tex]0^{\circ}C[/tex] to melt the ice

the heat released by water must be equivalent to heat absorbed by the ice

[tex]\therefore \quad m_1c_w(T-0)=m_2\times L\\\Rightarrow 1\times 4186\times T=0.1\times 3.33\times 10^5\\\Rightarrow T=7.95^{\circ}C[/tex]