If 7 men 5 women have applied for job and 3 applicants are randomly selected from the probability that 2 are men how many WOmen?
.

Answers

Answer 1

The probability of selecting 2 men and a woman is  [tex]\frac{21}{44}[/tex]

The sample space is made up of 7 men and 5 women. So we have a total of 12 people.

If 3 applicants are randomly selected without replacement, there will be three mutually exclusive possibilities;

[tex]MMW=\text{Event that a Man, then Man, then Woman is selected}\\MWM=\text{Event that a Man, then Woman, then Man is selected}\\WMM=\text{Event that a Woman, then Man, then Man is selected}\\[/tex]

The final probability will have the form

[tex]P(\text{2 men and 1 woman})=P(MMW)+P(MWM)+P(WMM)[/tex]

because the possibilities are mutually exclusive.

Computing the Probability of each possibility

Each mutually exclusive possibility is made up of dependent events. This is because when selection is done without replacement, it affects the size of the sample space.

The Probability of selecting a Man, then a Man, then a Woman is

        [tex]P(MMW)=\dfrac{7}{12}\times\dfrac{6}{11}\times\dfrac{5}{10}\\\\=\dfrac{7}{44}[/tex]

The Probability of selecting a Man, then a Woman, then a Man is

        [tex]P(MWM)=\dfrac{7}{12}\times\dfrac{5}{11}\times\dfrac{6}{10}\\\\=\dfrac{7}{44}[/tex]

The Probability of selecting a Woman, then a Man, then a Man is

        [tex]P(MWM)=\dfrac{5}{12}\times\dfrac{7}{11}\times\dfrac{6}{10}\\\\=\dfrac{7}{44}[/tex]

Calculate the Probability of getting two men and a woman

The final probability is

[tex]P(\text{2 men and 1 woman})=P(MMW)+P(MWM)+P(WMM)\\\\=\dfrac{7}{44}+\dfrac{7}{44}+\dfrac{7}{44}\\\\=\dfrac{21}{44}[/tex]

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Answer:

Bailouts and debt defaults can also help a government solve a debt problem, but these approaches have notable drawbacks as well.

Issuing Debt With Bonds.

Interest Rate Manipulation.

Instituting Spending Cuts.

Raising Taxes.

Lowering Debt Successes.

National Debt Bailout.

Controversy with Every Method.

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Ten numbered balls are placed in a box. The balls numbered 1–4 are blue and those numbered 5–10 are red. What is the probability that a ball drawn at random from the box is blue?

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Answer: If 5- 10 is red and 1-4 of them are blue I would say that 7 of them are red and 3 are blue because the probility of it having more than3 would be rare an out of ordinary Hope this helps if not please tell me what the answer options are.

Explanation:

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Explanation:

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Answers

Answer:

18 is the sum of the two integers.

Explanation:

65 is divisible by 4 numbers: 1, 5, 13, and 65.

Meaning 65 x 1 = 65 and 13 x 5 = 65.

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18 is the sum of the two integers.

Please like if this helped :)

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16. A chalk box is 5/6 th full of its capacity. 5 chalks were taken out by a teacher and 2
chalks were put inside it by a student. If it is 4/5th full now, how many chalks the box
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(a) 90
(b) 80
(c) 72
(d) can't be determined

Answers

Answer:

Well honestly this is a easy one, to figure out the answer to this we first need to pay close attention, it says at the start 5/6 of it is filled which means 90% of it is filled, then it says 5 chalks were taken out by the teacher which would leave the box with 0, and lastly it says that 4 out of 5 of it was put back inside but it had 5 out of 6 but now 4 out of 5 which would mean that it would be 65.67% and then since that is not one of the options you would have to estimate and use number math to figure out what that could be and it would be 72, so 72% of it is filled, Hope this helps :D

Explanation:

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Answers

Answer:

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Explanation:

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Answers

Answer:

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