Mathematics College

Amortization for 2021, $3.Record on adjusting entry

Answers

Answer 1

The adjusting entry for the Software of Northland Physical Therapy is as follows:

Adjusting Journal Entry:

December 31, 2018:

Debit Amortization Expense $3

Credit Accumulated Amortization $3

To record the amortization expense for the year.

What is an Adjusting Entry:

An adjusting entry for Amortization records the amortization expense for the period, which is debited. It also credits the Accumulated Amortization, increasing the amount of the amortization expense.

For instance, the Amortization Expense for Northland Physical Therapy's Software is recorded as above.

Learn more about adjusting entries at https://brainly.com/question/13035559

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Related Questions

2. (07.01)
In a city school, 70% of students have math class, 65% have science class, and 45% have math
and science class this semester. What is the probability (rounded to the nearest whole percent)
that a randomly selected student will have science class this semester, given that the student is in
math class? (1 point)
Hint: P(AB)
P(ANB)
P(B)
O 93%
20%
69%

Answers

Answer:

[tex]P(\text{Science}|\text{Math})\approx64\%[/tex]

Step-by-step explanation:

[tex]\displaystyle P(\text{Science}|\text{Math})=\frac{P(\text{Science and Math})}{P(\text{Math})}\\\\P(\text{Science}|\text{Math})=\frac{0.45}{0.70}\\ \\P(\text{Science}|\text{Math})\approx0.643\approx64\%[/tex]

None of the answer choices have this solution apparently, so either you left out some option, mistyped them, or it wasn't there to begin with

can someone please help me with this math problem please please

Answers

Answer:

Step-by-step explanation:

Step 1

Solve 3x-y=-63x−y=−6 for yy.

y=6+3xy=6+3x

Step 2

Substitute 6+3x6+3x for yy in the second and third equation.

2\left(6+3x\right)-5z=-52(6+3x)−5z=−5 x-\left(6+3x\right)-2z=-4x−(6+3x)−2z=−4

Step 3

Solve these equations for xx and zz respectively.

x=-\frac{17}{6}+\frac{5}{6}zx=−

z z=-1-xz=−1−x

Step 4

Substitute -\frac{17}{6}+\frac{5}{6}z−

z for xx in the equation z=-1-xz=−1−x.

z=-1-\left(-\frac{17}{6}+\frac{5}{6}z\right)z=−1−(−

Step 5

Solve z=-1-\left(-\frac{17}{6}+\frac{5}{6}z\right)z=−1−(−

z) for zz.

z=1z=1

Step 6

Substitute 11 for zz in the equation x=-\frac{17}{6}+\frac{5}{6}zx=−

x=-\frac{17}{6}+\frac{5}{6}\times 1x=−

×1

Step 7

Calculate xx from x=-\frac{17}{6}+\frac{5}{6}\times 1x=−

×1.

x=-2x=−2

Step 8

Substitute -2−2 for xx in the equation y=6+3xy=6+3x.

y=6+3\left(-2\right)y=6+3(−2)

Step 9

Calculate yy from y=6+3\left(-2\right)y=6+3(−2).

y=0y=0

Step 10

The system is now solved.

x=-2x=−2 y=0y=0 z=1z=1

Solution

x=-2x=−2

y=0y=0

z=1z=1

Lillian and Mackenzie clean rooms at a hotel. Today, they cleaned the same number of rooms, but Mackenzie worked fewer hours. Tomorrow, their shifts are the same length. Who will likely clean more rooms?

Answers

Answer:Mackenzie

Step-by-step explanation:

Answer:

Step-by-step explanation:

Mackenzie

rewrite! Write an new and equivalent equation that is easier to solve

Answers

[tex]{\huge{\fcolorbox{yellow}{red}{\orange{\boxed{\boxed{\boxed{\boxed{\underbrace{\overbrace{\mathfrak{\pink{\fcolorbox{green}{blue}{Answer}}}}}}}}}}}}}[/tex]

[tex] \sf 7( \sqrt{m + 1} - 3) = 21[/tex]

we will multiply 7 with bracket

[tex] \sf 7 \sqrt{m + 1} - 21 = 21[/tex]

Now we will take (-21) on LHS to RHS

[tex] \sf 7 \sqrt{m + 1} = 21 + 21 \\ \\ \sf7 \sqrt{m + 1 } = 42 \\ \\ \sf \sqrt{m + 1} = \frac{42}{7} \\ \\ \sf \sqrt{m + 1} = 6[/tex]

Now we will do squaring both sides

[tex] \sf {( \sqrt{m + 1}) }^{2} = {(6)}^{2} \\ \\ \sf \red {m + 1 = 36}[/tex]

[tex]\sf{ 7( \sqrt{m+1} - 3)=21}[/tex]