A ________ is a condition or capability needed by a user to solve a problem or achieve an objective that satisfies a standard or specification or any other formally documented need.

Answer:

The corresponding absolute pressure of the boiler is 24.696 pounds per square inch.

Explanation:

From Fluid Mechanics, we remember that absolute pressure ([tex]p_{abs}[/tex]), measured in pounds per square inch, is the sum of the atmospheric pressure and the working pressure (gauge pressure). That is:

[tex]p_{abs} = p_{atm}+p_{g}[/tex] (1)

Where:

[tex]p_{atm}[/tex] - Atmospheric pressure, measured in pounds per square inch.

[tex]p_{g}[/tex] - Working pressured of the boiler (gauge pressure), measured in pounds per square inch.

If we suppose that [tex]p_{atm} = 14.696\,psi[/tex] and [tex]p_{g} = 10\,psi[/tex], then the absolute pressure is:

[tex]p_{abs} = 14.696\,psi+10\,psi[/tex]

[tex]p_{abs} = 24.696\,psi[/tex]

The corresponding absolute pressure of the boiler is 24.696 pounds per square inch.

Answer:

d = 1.9 in

Explanation:

Since, the tension force is greater than the shear force. Hence, the area of cross-section shall be limited by the tension:

Tension = Force/Area

Area = Force/Tension

Area = 89 kips/31 ksi

Area = 2.87 in²

but,

Area = πd²/4

2.87 in² = πd²/4

(2.87 in²)(4)/π = d²

d = √(3.65 in²)

d = 1.9 in

Solution :

Given :

Dry bulb temperature, T = 30 degree C

Absolute pressure, P = 102 kPa

Partial pressure of water vapor, [tex]$P_v$[/tex] = 1.5 kPa

a). Relative humidity is given by

[tex]$\phi = \frac{P_v}{P_{sat}}$[/tex]

At T = 30 degree C, from the steam table, we have saturation temperature as 4.2469 kPa.

[tex]$\phi = \frac{1.5}{4.2469}$[/tex]

  = 0.35319

  = 35.31 %

b). Humidity ratio,  

[tex]$w= 0.622 \times \frac{P_v}{P-P_v}$[/tex]

[tex]$w= 0.622 \times \frac{1.5}{102-1.5}$[/tex]

w = 0.009283 kg per kg of dry air

c). Dew point temperature is the saturation temperature at vapor pressure of air (can be found from steam table)

At [tex]$P_v$[/tex] = 1.5 kPa, saturation temperature = 1.02 degree C

∴ Dew point temperature = 13.02 °C

d). Humidity ratio can be be defined as the ratio of mass of water vapor to the mass of dry air.

i.e. [tex]$w=\frac{m_v}{m_a}$[/tex]

[tex]$0.009283 =\frac{10}{m_a}$[/tex]

∴ [tex]m_{a}[/tex] = 1077.170 kg of dry air

Answer: 5   6    7

Explanation:

you can run this in python and get this result

The output for the given program is: 5   6    7

This refers to the high-level language that was created and is used for data structures due to its OOP (object-oriented programming).

Hence, this python code asks for an array of numbers in the range of 3 and when that is found, it should make a display of the number and increment it.

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Answer:

Fracture.

Explanation:

Fracture describes how a mineral looks when it breaks apart in an irregular way.

Answer:

Fracture.

Explanation:Fracture describes how a mineral looks when it breaks apart in an irregular way.

Answer:

[tex]1.67\times 10^{9}\ \text{cm}^{-3}\text{s}^{-1}[/tex]

[tex]3.33\times 10^{19}\ \text{cm}^{-3}\text{s}^{-1}[/tex]

[tex]3.33\times 10^{19}\ \text{cm}^{-3}\text{s}^{-1}[/tex]

Explanation:

[tex]p_0[/tex] = Hole concentration = [tex]2\times 10^{16}\ \text{cm}^{-3}[/tex]

[tex]n_i[/tex] = Intrinsic concentration = [tex]10^{10}\ \text{cm}^{-3}[/tex]

[tex]\tau_{n0}[/tex] = Minority carrier life time = [tex]3\times 10^{-6}\ \text{s}[/tex]

[tex]\delta n[/tex] = Excess concentration of electrons = [tex]10^{13}\ \text{cm}^{-3}[/tex]

Majority carrier electron concentration is given by

[tex]n_0=\dfrac{n_i^2}{p_0}\\\Rightarrow n_0=\dfrac{(10^{10})^2}{2\times 10^{16}}\\\Rightarrow n_0=5000\ \text{cm}^{-3}[/tex]

Recombination rate is given by

[tex]R_{n0}=\dfrac{n_0}{\tau_{n0}}\\\Rightarrow R_{n0}=\dfrac{5000}{3\times 10^{-6}}\\\Rightarrow R_{n0}=1.67\times 10^{9}\ \text{cm}^{-3}\text{s}^{-1}[/tex]

The recombination rate is [tex]1.67\times 10^{9}\ \text{cm}^{-3}\text{s}^{-1}[/tex]

Recombination rate is given by

[tex]R_n=\dfrac{\delta_n}{\tau_{n0}}\\\Rightarrow R_n=\dfrac{10^{13}}{3\times 10^{-7}}\\\Rightarrow R_n=3.33\times 10^{19}\ \text{cm}^{-3}\text{s}^{-1}[/tex]

The recombination rate is [tex]3.33\times 10^{19}\ \text{cm}^{-3}\text{s}^{-1}[/tex]

Change in the recombination rate is

[tex]\Delta R_n=3.33\times 10^{19}-1.67\times 10^{9}\\\Rightarrow \Delta R_n=3.33\times 10^{19}\ \text{cm}^{-3}\text{s}^{-1}[/tex]

The change in the recombination rate is [tex]3.33\times 10^{19}\ \text{cm}^{-3}\text{s}^{-1}[/tex]

Answer:

1) Public key of the receiver is (e, n) is (5, 21)  and Private key of the receiver (d, n)   is (5 , 21) ,

2) the encryption of a message whose integer equivalent is 12 is 3

3) Decryption of the message ⇒ P = C^d mod n  

⇒ P = 3⁵ mod 21

⇒ P = 243 mod 21

⇒ 12

Explanation:

Given that,

p = 3

q = 7

e = 5

1)

Now, n = pq = 3 × 7 = 21

Ø(n) = (p-1) × (q-1)  = 2 × 6 = 12

Public key of the receiver is (e, n) is (5, 21)

and private key of the receiver is (d, n)

we have to find 'd' by using the expression

ed = 1 + kmodØ(n)

d = 1 + kmodØ(n) / e

now to get 'd' , we need to choose the least positive integer 'k', by substituting different values of ‘k’ from 0,

so for k =0 , d = (1+0) / 5 = 0.2 not an integer.

for k =1 , d = (1+12) / 5 = 13/5 = 2.6 not an integer.

for k =2 , d = (1+24) / 5 = 5 , now 5 is an integer

So k = 2 and d = 5

Private key of the receiver (d, n)   is (5 , 21)

2)

Now the encryption of a message whose integer equivalent is 12?

Encryption of the message ⇒ C = P^e mod n

⇒ C = 12⁵ mod 21

⇒ 248832 mod 21

⇒ 3

3)

Also the decryption gives back the message 12.

Decryption of the message ⇒ P = C^d mod n

⇒ P = 3⁵ mod 21

⇒ P = 243 mod 21

⇒ 12

Answer:

Cost per cubic yard to place concrete using each of the following alternatives:

Alternative a = $14.04

Alternative b = $14.71

Explanation:

a) Data and Calculations:

Work of concrete in footings = 140 cubic yards

a. Price of using crane and bucket = $225 per hour

Number of hours required for this setup = 7 hours

Transportation of the crane = $390

Therefore, total cost under this alternative = $1,965 (($225*7) + $390)

Cost per cubic yard = $14.04 ($1,965/140)

b. Price of using a concrete pump = $295 per hour

Number of hours required for this setup = 6 hours

Transportation of the pump = $290

Therefore, total cost under this alternative = $2,060 (($295*6) + $290)

Cost per cubic yard = $14.71 ($2,060/140)

Answer:

hello some part of your question is missing below is the complete question

answer :

A) 162750 Ib.ft

B) - 64950 Ib.ft

Explanation:

Applying Muller-Breslau's law

we will make assumptions which include assuming an imaginary hinge at G

therefore the height of I.LD for B.M at G = ( 12 * 8 ) / 20 = 4.8

height of I.L.D at C = 2.4 ( calculated )

height of I.L.D at F = 1.5 ( calculated )

A) Determine Maximum positive moment produced at G

[tex]M ^+[/tex] = [ (1/2 * 20 * 4.8 ) ( 600 + 300 ) ] + [ ( 25 * 4.8 * 10^3 ) ] - [ ( 1/2 *2.4*20 ) * 300 ] + [ (1/2 * 1.5 * 10 ) ( 600 + 300 ) ]

      = 162750 Ib.ft

B)   Determine the maximum negative moment produced at G

[tex]M ^-[/tex] = [ ( 1/2 * 20 * 4.8 ) * 300 ] - [ ( 1/2 * 2.4 * 20 ) ( 600 + 300 ) ] - [ (2.5 * 10^3 * 2.4 ) ] + [ ( 1/2 * 1.5 * 10) * 300 ]

     = - 64950 Ib.ft

Solution :

Given :

Height at which the metal is poured, h = 10 in

Diameter of the runner , d = 0.4 in

Assume viscosity, μ = 0.004 Pa-s

Now considering Bernoulli's equation to find velocity,

As there is no loss in energy, Δ Pressure energy ≅ 0

So,

[tex]$\frac{v^2_1}{2g}+z_1=\frac{v^2_2}{2g}+z_2$[/tex]

Here 1 and 2 represents top and bottom section of the sprue.

[tex]$\frac{v^2_1}{2g}+z_1=\frac{v^2_2}{2g}+z_2 \ \ \ (v_1=0)$[/tex]

[tex]$v_2=\sqrt{2g \Delta z}$[/tex]

Now substituting [tex]$32.20 \ ft/s^2 = 386.4 \ in/s^2$[/tex] for g and 10 in for Δz in velocity equation,

[tex]$v_2=\sqrt{2 \times 386.4 \times 10}$[/tex]

[tex]$v_2= 87.91 \ in\s = 7.32 \ ft/s$[/tex]

Calculating the area of the basin

[tex]$A=\frac{\pi}{4}d^2$[/tex]

Substitute .04 in  for d in the above equation

[tex]$A =\frac{\pi}{4} \times (0.4)^2$[/tex]

[tex]$A= 0.1256 \ in^2$[/tex]

Calculating the flow rate

Q = 0.1256 x 87.91

[tex]$ Q= 11 .04 \ in^3/s $[/tex]

Hence the viscosity is [tex]$v_2 = 87.91 \ in/s$[/tex] and the flow rate is [tex]$Q=11.04 \ in^3/s$[/tex]

Calculating the Reynolds number of the flow,

[tex]$Re = \frac{\rho v d}{\mu}$[/tex]

[tex]$Re = \frac{0.097544 \times 87.91 \times 0.40}{5.8 \times 10^{-7}}$[/tex]

[tex]$Re=5.9 \times 10^6$[/tex]

Therefore, the flow is turbulent.

Now considering the solidification time,

[tex]$t=c \times \left(\frac{V}{A}\right)^2$[/tex]

[tex]$t=c \times \left(\frac{\frac{\pi}{4}d^2h}{2\left(\frac{\pi}{4}d^2\right)+ \pi dh}\right)^2$[/tex]

[tex]$t=c\left(\frac{dh}{2d+4h}\right)^2$[/tex]

Substituting 1.5 for d and 3 for h and 3 min for t to calculate the value of c is

[tex]$3=c\left(\frac{1.5 \times 3}{2 \times 1.5 + 4 \times 3} \right)^2$[/tex]

c = 33.33

For case when height is double i.e. h = 6 in

[tex]$t_h = 33.33 \times \left(\frac{1.5 \times 6}{2 \times 1.5 + 4 \times 6} \right)^2$[/tex]

[tex]$t_h= 3.70 \ min$[/tex]

For case when the diameter is doubled i.e. 3 in for d and 3 in  for h,

[tex]$t_d = 33.33 \times \left(\frac{3 \times 3}{2 \times 3 + 4 \times 3} \right)^2$[/tex]

[tex]$t_d= 8.3325 \ min$[/tex]

Answer:A

Explanation:

B - it never talked about a steep path or not.

C- it never stated the speed.

d- more experienced driver makes a little bit of sence since she is new but she is new at the farm not driving.  

thats my guess.

Answer:

 b is the answer

Explanation:

Answer:

Engineers spend up to 25 percent of their design process formulating and analyzing

the team that will work on the project.

Explanation:

During the design engineering stage of a project, the team is a very important decision item because determining the required team also determines the cost and the technical skill requirements of the project.  The cost depends, to a large extent, on the technical skills of those that will work on the project.  When the technical skill requirements are not met, the project will be massively jeopardized.

Answer:

the team that will work on the project.

Explanation:

Answer:

I think the answer is drop ceilings

Explanation:

Answer:

immediately

Explanation:

Answer:

c

Explanation:

Answer: False

Explanation:

Answer:

we have zero degree of freedom (F = 0) at the first phase region and one degree of freedom (F = 1) at the second phase region

Explanation:

given the diagram;

C = 2 { Ti and Ni}, N = 1 {Pr is constant}, P = 3 { L and B}

For degree of freedom,

Gibbs phase rule is applied for invariant point (ex.A)

P + F = C + N

3 + F = 2 + 1

F = 3 - 3

F = 0

For the second phase region ( ex.B)

C = 2, N = 1, P = 2

P + F = C + N

2 + F = 2 + 1

F = 3 - 2

F = 1

Therefore we have zero degrees of freedom (F = 0) at the first phase region and one degrees of freedom (F = 1) at the second phase region

Answer:

Following are the solution to this question:

Explanation:

In point a:

This takes me six weeks for both the took ideas that I was searching for but it continued for 3 years (12 weeks) as it's an intern.  

In point b:

Finding job:

[tex]\to f = \frac{1}{6} = 0.166[/tex] jobs weekly  

Separation of jobs:

[tex]\to \frac{ 1}{12}=0.083[/tex] employment per week.  

In point c:

Its natural rate of unemployment is:  [tex]\frac{U}{L} = s+(s \times f)[/tex].  

The normal level of employment for that community I represent, once we add up from that preceding section, is as follows:

[tex]\to \frac{U}{L} = 0.083+ (0.083\times 0.166) = 0.096[/tex]

If on average, it requires six weeks to find another job or the work lasted 12 weeks, the group's unemployment level is [tex]0.096 \ \%[/tex].

Answer:

a) 13 mins

b) 18 mins

Explanation:

solidification time = 10 minutes

height-to-diameter ratio = 1

applying the expression for calculating solidification time

t = B  [tex](\frac{V}{A} ) ^n[/tex]  --------- ( 1 )

n = 1.5

B = ?

t = 10 minutes

V = [tex]\frac{\pi d^2}{4} H[/tex]

A = [tex]\frac{\pi d^2}{2} + \pi dH[/tex]

back to equation 1

making B subject of the formula ; B = [tex]\frac{147}{d^{1.5} }[/tex]

a) Determine the solidification time if the cylinder height is doubled

t = B  [tex](\frac{V}{A} ) ^n[/tex]

substitute :  B = [tex]\frac{147}{d^{1.5} }[/tex]  , H = 2D  , V = [tex]\frac{\pi d^2}{4} H[/tex] , A = [tex]\frac{\pi d^2}{2} + \pi dH[/tex] , n = 1.5

therefore ; t ( solidification time when height is doubled ) ≈ 13 mins

b) Determine the time if the diameter is doubled

t = B  [tex](\frac{V}{A} ) ^n[/tex]

substitute ; B = [tex]\frac{147}{h^{1.5} }[/tex] , D = 2H , n = 1.5 , V = [tex]\frac{\pi d^2}{4} H[/tex], A = [tex]\frac{\pi d^2}{2} + \pi dH[/tex]

therefore ; t ( solidification time when diameter is doubled ) ≈ 18 mins

Answer:

B

Explanation:

Answer:

mmmmmm

Explanation:

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Answer: Partial pressures are 0.6 MPa for nitrogen gas and 0.4 MPa for carbon dioxide.

Explanation: Dalton's Law of Partial Pressure states when there is a mixture of gases the total pressure is the sum of the pressure of each individual gas:

[tex]P_{total} = P_{1}+P_{2}+...[/tex]

The proportion of each individual gas in the total pressure is expressed in terms of mole fraction:

[tex]X_{i}[/tex] = moles of a gas / total number moles of gas

The rigid tank has total pressure of 1MPa.

molar mass = 14g/mol

mass in the tank = 2000g

number of moles in the tank: [tex]n=\frac{2000}{14}[/tex] = 142.85mols

molar mass = 44g/mol

mass in the tank = 4000g

number of moles in the tank: [tex]n=\frac{4000}{44}[/tex] = 90.91mols

Total number of moles: 142.85 + 90.91 = 233.76 mols

To calculate partial pressure:

[tex]P_{i}=P_{total}.X_{i}[/tex]

For Nitrogen gas:

[tex]P_{N_{2}}=1.\frac{142.85}{233.76}[/tex]

[tex]P_{N_{2}}[/tex] = 0.6

For Carbon Dioxide:

[tex]P_{total}=P_{N_{2}}+P_{CO_{2}}[/tex]

[tex]P_{CO_{2}} = P_{total}-P_{N_{2}}[/tex]

[tex]P_{CO_{2}}=1-0.6[/tex]

[tex]P_{CO_{2}}=[/tex] 0.4

Partial pressures for N₂ and CO₂ in a rigid tank are 0.6MPa and 0.4MPa, respectively.

Answer:

a) 294.34 days

b) Δh = 25.361 cm

Explanation:

Given data:

Thickness of clay layer = 18 ft

initial pressure = 0.75 ton/ft^2

final pressure = 1.5 ton/ft^2

Δp = 0.75 ton/ft^2

eo = 1.12

e1 = 0.98

k = 4.3 * 10^-7 cm/sec

A ) determine how long it will take to reach 70% consolidation

attached below is the detailed solution

T( time in days ) = 294.34 days

B) determine settlement at 70%

attached below is the detailed solution

Δh = 25.361 cm

Answer:

5 multiply by 10 S/M

Based on the calculations, the incident wave would be down to 1 mV/m at a depth of 287.82 meters.

Since the medium is a wet soil, it is characterized by the following:

Next, we would determine loss tangent, so as to know if the wet soil is a low-loss medium:

For a low-loss medium; ε''/ε' = σ/ωε < 0.01.

[tex]\frac{\sigma}{\omega \epsilon} = \frac{5 \times 10^{-4} \;\times\; 36 \pi}{2\pi \;\times \;3 \times 10^9\; \times\; 10^{-9} \times \;9} \\\\\frac{\sigma}{\omega \epsilon} =3.32 \times 10^{-4}[/tex]

Therefore, the wet soil medium is a low-loss dielectric and its absorption (attenuation) coefficient is calculated by using this formula:

Note:

[tex]\alpha = \frac{\sigma}{2}\sqrt{\frac{\mu}{\epsilon}} \\\\\alpha = \frac{\sigma}{2} \times \frac{120\pi}{\sqrt{\epsilon_r} } \\\\\alpha =\frac{5 \times 10^{-4} \times 120\pi}{2 \times \sqrt{9} } \\\\[/tex]

α = 0.032 Np/m.

Now, we calculate the depth:

[tex]E(z) = E_oe^{-\alpha z} = 10e^{-\alpha z}\\\\10^{-3}=10e^{-0.032 z}\\\\ln(10^{-4})=-0.032 z\\\\-9.21 \times 10^9=-0.032z\\\\z=\frac{-92.1 0}{-0.032}[/tex]

z = 287.82 meters.

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Answer:

True

Explanation:

Answer: The movement of tectonic plates

Explanation:

Tectonic plates are the part of the earth's crust that both the ocean and land rest on. These plates are constantly moving as a result of currents in the mantle.

These movements cause stress on the surface which has the effect of fracturing rocks and thereby creating/ forming faults in the earth's crust. Sometimes faults form when these plates move away from each other and sometimes they are formed when they push into each other.

Answer:

Following are the solution to this question:

Explanation:

In question 1:

It Cmdlet gets the representatives of items, its features including their methods. Now use a variable (InputObject) and pipe the object to Even getting Member for both the purpose of specifying the object. It static variable utilizes their class members, not the case, to gather information regarding static members. Just use the (MemberType) parameter and receive only some forms of participants, such example NoteProperties.

In question 2:

Its Purchase cmdlet allows us to import components through our process. It can import components via remote sessions through the local client beginning with Window PowerShell 3.0.

In question 3:

The Syntax query to have all cmdlets lists it in the cmdlet title alphabetical order, but instead shows them in noun clauses.

Command:

[tex]\text{Type Cmdlet } | \text{Sort-Object -Property Noun} | \text{Format-Table -GroupBy Noun}[/tex]

In question 4:

Syntax:

[tex]\text{Get node} | \text{format list} | \text{Selection process, device forms, route group title all}[/tex]

[tex]| \text{Layout Table} | \text{Selection process}[/tex]

[tex]\$ s[/tex] = New-PSSession -ComputerName Server

Get-Module -PSSession [tex]\$ s[/tex] -ListAvailable

Answer:

zero off your workpiece so you can work from a datum, usually the centre of your work on a lathe. change your tool to a drill and drill a hole to a size smaller than your thread diameter, change out your tool for a threaded tap and away you go.

I'm not sure which part they want but I'd say ensure your tool is set to the right height, you have the tool lines up where you want to cut and that you have calculated the speed you need to cut at safety. Drill a hole before you tap though.

If you have a CNC lathe you just set the programme to do the processes and tool change for you.

The first step to cutting internal threads on an engine lathe is to make calculations so that the thread will have proper dimensions.

The technique of thread cutting on the lathe results in a helical ridge with a consistent section on the workpiece.

To work from a datum, often the center of your work on a lathe, zero off your workpiece. Use a drill to create a hole that is less in diameter than the thread, then switch to a threaded tap and carry on.

One would advise making sure your tool is adjusted to the appropriate height, that it is lined up where you want to cut, and that you have determined the speed you must cut in order to be safe. Before you tap, drill a hole.

With a CNC lathe, you can simply program the machine to perform the processes and tool changes for you.

Therefore,  to do this, make a series of cuts with a threading toolkit that matches the needed thread form.

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Answer:

NG=64 teeth

dG=384mm

dP=96mm

C=240mm

Explanation:

step one:

given data

module m=6mm

velocity ratio VR=4

number of teeth of pinion Np=16

Step two:

Required

1. Number of teeth on the driven gear

[tex]N_G=N_P*V_R\\\\N_G=16*4\\\\N_G=64[/tex]

The driven gear has 64 teeth

2.  The pitch diameters

The driven gear diameter

[tex]d_G=N_G*m\\\\d_G=64*6\\\\d_G=384[/tex]

The driven gear diameter is 384mm

The pinion diameter

[tex]d_P=N_P*m\\\\d_P=16*6\\\\d_P=96[/tex]

Pinion diameter is 96mm

3. Theoretical center-to-center distance

[tex]C=\frac{d_G+d_P}{2} \\\\C=\frac{384+96}{2} \\\\C=\frac{480}{2}\\\\C=240[/tex]

The theoretical center-to-center distance is 240mm

The results are listed below:

First, we proceed to find the number of teeth of each gear ([tex]N_{D}, N_{P}[/tex]) based on the fact that gear only fit when they have the same module ([tex]m[/tex]). The velocity ratio ([tex]r_{v}[/tex]) is defined by the following relationship:

[tex]r_{v} = \frac{N_{D}}{N_{P}}[/tex] (1)

If we know that [tex]r_{v} = 4[/tex] and [tex]N_{P} = 16[/tex], then the number of teeth of the driven gear is:

[tex]N_{D} = r_{v}\cdot N_{P}[/tex]

[tex]N_{D} = 4\cdot (16)[/tex]

[tex]N_{D} = 64[/tex]

The driven gear has 64 teeth.

The pitch diameter ([tex]D[/tex]) is obtained by multiplying the number of teeth ([tex]N[/tex]) by module ([tex]m[/tex]), in milimeters.

Pinion

[tex]D_{P} = m\cdot N_{P}[/tex] (2)

([tex]m = 6\,mm[/tex], [tex]N_{P} = 16[/tex])

[tex]D_{P} = (6\,mm)\cdot (16)[/tex]

[tex]D_{P} = 96\,mm[/tex]

Driven gear

[tex]D_{D} = m\cdot N_{D}[/tex] (3)

([tex]m = 6\,mm[/tex], [tex]N_{D} = 64[/tex])

[tex]D_{D} = (6\,mm)\cdot (64)[/tex]

[tex]D_{D} = 384\,mm[/tex]

The pinion has a diameter of 96 millimeters and the driven gear has a diameter of 384 millimeters.

Lastly, the theoretical center-to-center distance is calculated by the following formula:

[tex]d = \frac{1}{2}\cdot (D_{P}+D_{D})[/tex]  (4)

([tex]D_{P} = 96\,mm[/tex], [tex]D_{D} = 384\,mm[/tex])

[tex]d = \frac{1}{2}\cdot (96\,mm + 384\,mm)[/tex]

[tex]d = 240\,mm[/tex]

The theoretical center-to-center distance is 240 millimeters.

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Answer:

9.2 hp

Explanation:

Service factor is the ratio of the gearbox rated horsepower (or torque) to the application's required horsepower (or torque)

SF = Pₒ / Pᵢ

Pᵢ = Pₒ × SF

Pᵢ = 8 hp × 1.15

Pᵢ = 9.2 hp