1 1/6 as an improper fraction

Answer:$27,57

1)find out how much wallets cost in the first month:

24,50 -100%

х      - 125%

х= 24,50*125/100 ≈ 30,63

2)we will find out how much the wallets cost after the price is reduced by 10%:

30,63 - 100%

х         -90%

х=30,63*90/100 ≈ 27,57

Step-by-step explanation:

Answer:

7°

Step-by-step explanation:

you get the minimum +the maximum ÷ 2

so : (0+14)÷2 =7°

Answer:96km in 1 hour requires a speed of 96km/h; 96km in 2 hours requires a speed of 96/2=48km/h.

You can travel at any speed between 48km/h and 96km/h to arrive in between 1 and 2 hours.

There is no sufficient info to solve the problem and answer the question.

Also,  this fragment   "Two bikers started at the same,"   is a nonsense,  not allowable in  Math.

Find the antiderivative of the velocity function.

1 rotation = 2pi radians = 2*3.14 radians = 6.28 radians

1 rotation per 8 seconds is the angular velocity  2pi%2F8 radians per second = 6.28%2F8 = 0.785 radians per second

hope this is helpful

Answer:

48.3

Step-by-step explanation:

since b = 9 and c = 4

9 x 4 = 36 and 36 + 12.3 = 48.3

Given:

p and q are the two distinct solutions to the equation

[tex](x-3)(x+3)=21x-63[/tex]

To find:

The value of p-q if p>q.

Solution:

We have,

[tex](x-3)(x+3)=21x-63[/tex]

[tex](x-3)(x+3)=21(x-3)[/tex]

[tex](x-3)(x+3)-21(x-3)=0[/tex]

[tex](x-3)(x+3-21)=0[/tex]

[tex](x-3)(x-18)=0[/tex]

Using zero product property, we get

[tex]x-3=0\text{ and }x-18=0[/tex]

[tex]x=3\text{ and }x=18[/tex]

Here, 18>3, so p=18 and q=3.

Now,

[tex]p-q=18-3[/tex]

[tex]p-q=12[/tex]

Therefore, the value of p-q is 12.

Answer:

The answer is 5, the "Expert Verified" is wrong :)

Step-by-step explanation:

First we try factoring the left side to simplify it. Now we can multiply both sides by (x+5)and solve.

Answer:

A

Step-by-step explanation:

Answer:

-7=k

Step-by-step explanation:

5k-3k-2=-16

2k-2=-16

2k=-14

k=-7

Given:

[tex]f^{-1}(f(x))=f(f^{-1}(x))=?[/tex]

To find:

The missing value.

Solution:

We have,

[tex]f^{-1}(f(x))=f(f^{-1}(x))=?[/tex]       ...(i)

We know that, if [tex]f(x)[/tex] is a function and [tex]f^{-1}(x)[/tex] is its inverse function, then

[tex]f^{-1}(f(x))=f(f^{-1}(x))=x[/tex]          ...(ii)

From (i) and (ii), we get

Missing value = [tex]x[/tex]

Therefore, the missing value is [tex]x[/tex], i.e., [tex]f^{-1}(f(x))=f(f^{-1}(x))=x[/tex].

Answer:

A= l×l

= 13×13

A= 169

P= 4l

= 4×13

= 52

so the answer is C

Answer:

B is the answer.

Step-by-step explanation:

Answer:

The second one

Step-by-step explanation:

-2 and 1/4 is the same as -9/4 bec -9/4 is just in the improper form.

(can i get brainliest now)

Answer:

-2x+-8-3x-8

Step-by-step explanation:

-2 times x =-2x  

-2 times 4=-8

Answer:

x

Step-by-step explanation:

-2 (x + 4) – (3x – 8)

-2x-8-3x+8

x+0

x

Answer:

B) x = -5

Step-by-step explanation:

The zero of a graph is the inputted value in which the output is 0. Therefore, we must find the x-value that makes the y-value be 0. In the graph, we see that y = 0 at (-5, 0). The x-value of the coordinate (-5, 0) is -5. Therefore, the zero of the function in the graph is x = -5.

I hope this helps! :)

Answer:

f(3) = 4

Step-by-step explanation:

The absolute value, |X|, is defined as the magnitude of a number without regard to its sign. For example, absolute value of 1 is 1 and absolute value of -1 is 1.

Thus, based on the function:

f(x)=|x−5|+2

f(3) = |3−5|+2

f(3) = |-2|+2

-Absolute value of -2 = 2-

f(3) = 2+2

Answer:

$0.97

Step-by-step explanation:

Let the cost of a single apple is x and that of single mango is y.

ATQ,

3x+6y=9.15 ....(1)

8x+4y=11.92 ...(2)

Multiply equation (1) by 8 and equation (2) by 3

24x+48y=73.2 ...(3)

24x+12y=35.76  ...(4)

Subtract equation (2) from (1) :

24x+12y-(24x+48y) = 35.76  - 73.2

12y-48y = -37.44

-36y = -37.44

y = $1.04

Put the value of y in equation (1)

3x+6y=9.15

3x+6(1.04) = 9.15

3x = 9.15-6(1.04)

3x = 2.91

x = $0.97

Hence, the cost of single apple is $0.97.

Given:

Equation of line is [tex]y-25=2(x-10)[/tex].

A line is perpendicular to the given line and passes through (-3,7).

To find:

The point slope form of the perpendicular line.

Solution:

Point slope form of a line is

[tex]y-y_1=m(x-x_1)[/tex]          ...(i)

where, [tex](x_1,y_1)[/tex] is the point from which the line is passing through and m is slope.

We have,

[tex]y-25=2(x-10)[/tex]       ...(ii)

From (i) and (ii), we get

[tex]m_1=2[/tex]

Product of slopes of two perpendicular lines is -1.

[tex]m_1\times m_2=-1[/tex]

[tex]2\times m_2=-1[/tex]

[tex]m_2=-\dfrac{1}{2}[/tex]

So, slope of perpendicular line is [tex]-\dfrac{1}{2}[/tex].

Point slope form of the perpendicular line is

[tex]y-(7)=-\dfrac{1}{2}(x-(-3))[/tex]

[tex]y-7=-\dfrac{1}{2}(x+3)[/tex]

Therefore, the correct option is C.

Answer:

20 + 14 = 34, there there are only 29 students, so 34 - 29 or 5 have both a dog and a cat

15 have only a dog

5 have a dog and a cat

9 have only a cat

Step-by-step explanation:

The probability that a student has a cat given that they do not have a dog  is 3/5

Probability denotes the possibility of the outcome of any random event. The meaning of this term is to check the extent to which any event is likely to happen.

According to the question,

The number of student who do not have a dog is

25 - ( 8 + 2 ) = 15

9 have a cat { do not have a dog is a prerequisite }

So the probability that a student has a cat given that they do not have a dog = 9/15

       = 3/5

To learn more about probability from here

https://brainly.in/question/3144050

#SPJ2

Answer:

F = 9 over 5C + 32

Step-by-step explanation:

Let's consider the following equation that shows the relationship between the temperature in degrees Celsius, C, and degrees Fahrenheit, F.

C = 5 over 9(F − 32)

C = 5/9 (F − 32)

To solve for F, first, we will multiply both sides by 9/5.

C × 9/5 = 5/9 (F − 32) × 9/5

9/5 C = F − 32

Now, we add 32 to both sides.

9/5 C + 32 = F − 32 + 32

9/5 C + 32 = F

F = 9 over 5C + 32

Answer:

F = 9 over 5C + 32

Step-by-step explanation:

Answer:

[tex]Distance = 39.2[/tex]

Step-by-step explanation:

Given

[tex]Distance = 6ft;\\ Time = 15seconds[/tex]

Required

Determine the distance covered in 98 seconds

To solve this, the following assumption must be made:

So, first we calculate the speed

[tex]Speed = \frac{Distance}{Time}[/tex]

Substitute 6 for Distance and 15 for Time

[tex]Speed = \frac{6}{15}[/tex]

[tex]Speed = 0.40[/tex]

Next, is to calculate the required distance

[tex]Speed = \frac{Distance}{Time}[/tex]

In this case:

[tex]Speed = 0.40[/tex] because it is constant and

[tex]Time = 98[/tex]

The expression becomes:

[tex]0.40 = \frac{Distance}{98}[/tex]

Make Distance the subject:

[tex]Distance = 0.40 * 98[/tex]

[tex]Distance = 39.2[/tex]

The peacock will walk 39.2 feet in 98 seconds

Answer:

18n+9 i think

Step-by-step explanation:

Step-by-step explanation:

what is this answer

(3x + 40) + (5x - 52) = 180°

8x - 12 = 180°

8x = 180 + 12

8x = 192

8x = 24

x = 3

==================================================

Work Shown:

[tex]\displaystyle \lim_{x \to 3} \frac{f^2(x)-4}{f^2(x)-f(x)-2}\\\\\\\displaystyle \lim_{x \to 3} \frac{(f(x)-2)(f(x)+2)}{(f(x)-2)(f(x)+1)}\\\\\\\displaystyle \lim_{x \to 3} \frac{f(x)+2}{f(x)+1}\\\\\\\displaystyle \frac{f(3)+2}{f(3)+1}\\\\\\\displaystyle \frac{2+2}{2+1}\\\\\\\displaystyle \frac{4}{3}\\\\\\[/tex]

Notes:

In step 2, I used the difference of squares rule to factor the numerator. The denominator can be factored through trial and error. The key here is the f(x)-2 terms that show up in each. Those factors cancel in step 3.

Afterward, we apply the substitution rule, [tex]\displaystyle \lim_{x \to a} f(x) = f(a)[/tex], so basically I plugged in x = 3. Then evaluated f(3) = 2 due to the point (3,2).

Answer:

c

Step-by-step explanation:

it would have some exponent but its the only one that is constant

Answer:

6.oz I will ply to get a

Step-by-step explanation:

ok is the only

Answer:

Step-by-step explanation:

9(67)=9(70-3)=

Answer:

x = 1 and y = 3

Step-by-step explanation:

To use substitution, you want to substitute something for another variable. So lets take the first equation and solve for y

2x - y = -1

2x = y - 1

2x + 1 = y

Now we can substitute 2x + 1 for y in the other equation

3x + 2x + 1 = 6

5x = 5

x = 1

now that we have x, we can get y

2(1) - y = -1

2 - y = -1

2 = y - 1

3 = y

So x = 1 and y = 3

Step-by-step explanation:

18,200

-12,350

5,850 (A) 5,850

Answer:

no u

Step-by-step explanation: no no no no no no no no no

Answer:

Her raise per hour is $3.

Step-by-step explanation:

Quadratic Equation

The standard representation of a quadratic equation is:

[tex]ax^2+bx+c=0[/tex]

where a,b, and c are constants.

It can be solved by using the quadratic formula:

[tex]\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

Jill asks for an increase in the hourly wage she receives. Since she works in a Maths Center, the increase comes as a maths equation.

She must solve the equation:

[tex]x^2-6x+9=0[/tex]

The solution to the equation is the increase in her hourly wage.

Comparing with the general form, we have a=1, b=-6, c=9. Thus, the solutions are:

[tex]\displaystyle x=\frac{-(-6)\pm \sqrt{(-6)^2-4(1)(9)}}{2(1)}[/tex]

[tex]\displaystyle x=\frac{6\pm \sqrt{36-36}}{2}[/tex]

[tex]\displaystyle x=\frac{6\pm \sqrt{0}}{2}[/tex]

Since the square root is 0, there is only one solution:

[tex]\displaystyle x=\frac{6}{2}=3[/tex]

x = 3

Thus, her raise per hour is $3.

9514 1404 393

Answer:

  a) see the attached spreadsheet (table)

  b) Calculate, for a 10-year horizon; Computate for a longer horizon.

  c) Year 13; no

Step-by-step explanation:

a) The attached table shows net income projections for the two companies. Calculate's increases by 0.5 million each year; Computate's increases by 15% each year. The result is rounded to the nearest dollar.

__

b) After year 4, Computate's net income is increasing by more than 0.5 million per year, so its growth is faster and getting faster yet. However, in the first 10 years, Calculate's net income remains higher than that of Computate. If we presume that some percentage of net income is returned to investors, then Calculate may provide a better return on investment.

The scenario given here is only interested in the first 10 years. However, beyond that time frame (see part C), we find that Computate's income growth far exceeds that of Calculate.

__

c) Extending the table through year 13, we see that Computate's net income exceeds Calculate's in that year. It continues to remain higher as long as the model remains valid.