Which of the following are SI units? Select all that apply.gLs

Let's see that the formula to find the volume using density and mass is:

In this case, the problem is asking about the volume in mL but remember that mL is the same that cm^3, so using the formula we're going to obtain:

The volume of 5.52 g of acetone is 7.02 mL.

Atomic mass of zinc is 65. Simply dip one strip into the water for 3 seconds, remove it and shake once to remove excess water, wait 20 seconds for the color to develop, and compare it to the closest color match to determine your zinc concentration.

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The Lewis dot model of a molecule is shown as -

On the basis of this model, the statement which is true is Carbon has a total of four bonded pairs of electrons around it.

Formaldehyde, HCHO has two hydrogen atoms, one carbon atom and one oxygen atom. Oxygen and carbon has double bond between them. Carbon atom is located at the center in the lewis dot structure. Valence electrons in the outer shell of carbon is four. Four electrons of carbon are bonded as it is bonded with two hydrogen atoms and one oxygen atom and oxygen and carbon atom has double bond between them.  

Therefore, Carbon has total of four bonded pairs of electrons around it. Hence, this statement is true.

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The volume of NaOH required is 80ml.

Sulfuric acid is a dibasic acid and NaOH is monoacidic base.

M1V1 = M2V2

where, M1 = initial concentration,

V1 = initial volume,

M2 = concentration after mixing

V2 = total final volume.

This formula is used for calculating the final volume or molarity after mixing two solutions.

Given the question,

M1 = 0.505M

V1 =?

M2 = 0.505M

V2 = 40 ml

M1V1 = 2×M2V2

0.505 × V2 = 2 × 0.505 × 40

V2 = 2×0.505×40

            0.505

V2 = 80ml

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The molar change in enthalpy of reaction is 99.6 kJ/mol.

the formula for the specific heat capacity expressed as :

Q = mcΔT

where,

m , mass = 104.153 g

c, specific heat = 4.184 J/g °C

dt, change in temperature = 22.9  °C

Q = 104.153 × 4.184 × 22.9

Q = 9969.7 J = 9.96 kJ

now, the molar change in enthalpy is give by:

Q = ΔH / n

n is no. of moles

morality of HCl = 2.2 M

v = 50 mL = 0.05 L

n = 0.05 × 2.2

   =  0.11 moles

no. of moles of NaOH = mass / molar mass

                                    = 4.039 / 40

                                    = 0.100

NaOH is limiting reactant.

using the formula we get:

Q = ΔH / n

ΔH = Q / n

ΔH  =  9.96 kJ/ 0.10

ΔH, change in enthalpy  = 99.6 kJ/mol

Thus, combine 50.0 mL H₂O, 50.0 mL of 2.2 M HCl(aq), and 4.039 g NaOH(s) (molar mass of NaOH = 40.00 g/mol) in a Styrofoam calorimeter, recording a maximum solution temperature change of 22.9 °C and a final solution mass of 104.153 g (c solution = 4.184 J/g°C).  the molar change in enthalpy of reaction is 99.6 kJ/mol.

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The percentage of mass of 0.101g in 2.093g of vinegar comes out to be 4.8%. Mass percentage does not have any unit as numerator and denominator contains the same unit.

Mass percentage represents the the percentage of each element that is making a particular compound.

mass of vinegar solution =density of vinegar solution× volume of  vinegar solution

                                          =0.996 g/mL×2.00 mL

                                           =1.992g

Percentage of mass=(mass of acetic acid ÷ total mass of solution) x 100%

                                  =[0.101÷(0.101+1.992)]×100

                                 =0.048×100

                                  =4.8%

Thus the mass percentage of acetic acid is 4.8%

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The mass of the piece of porcelain is 27.3 oz.

1st) It is necessary to calculate the mass of the porcelain with the density formula:

2nd) Now it is necessary to convert the gram unit to oz. Here we need to use the relation that 1 g is equal to 0.035 oz:

So, the mass of the piece of porcelain is 27.3 oz.

When 0.900mol of octane is burned in air it reacts with oxygen Oxygen gas to produce carbon dioxide gas and water vapor, then 7.20mole of carbon dioxide is produced.

Combustion reaction is a reaction in which a substance, basically hydrocarbons burns in presence of oxygen to produce carbon dioxide and water.

The balanced reaction is

[tex]2C_{8} H_{18}+25O_{2} \rightarrow16CO_{2} +18H_{2}O[/tex]

The mole ratio of octane to carbon dioxide is 2:16 that is 1:8

2 mole of octane produce =16 mole of carbon dioxide

1 mole of octane produce = 8 mole of carbon dioxide

0.900mol of octane produce= 8× 0.900

                                                = 7.20mole

Thus the mole of carbon dioxide produced is 7.20mole.

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A risk-benefit analysis compares the risks and benefits of a situation and determines whether the advantages outweigh the disadvantages. 

Strengths

Risk-benefit analysis calculates the amount of time will be worth it to the production of technology and whether the technology will have a healthy impact on the industry or not.

Weaknesses

Risk-benefit analysis cannon determine product implementation and the outcomes of real life experiences of individual customers. It has some drawbacks like benefits of customer is take under consideration but pollution in nature is not calculated.

Implication

Risk-benefit analysis is implied in almost all technical industry as it the decision maker of any developing team to work on a particular project or not. Some examples are automobile industry and smartphone industry.

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We are asked to find the temperature of hydrogen gas (H2) given certain pressure and temperature conditions. Since the pressure to which the gas will be subjected is low we can apply the ideal gas law which is represented by the following equation:

Where,

P= Pressure = 140kPa = 1.38169 atm

V= Volumen = 224 L

R= Ideal gas constant = 0.08206 (atm L)/(mol K)

n= Number of moles

T= Temperature in K

Now we are going to find the number of moles of the gas, n. We will use the molar mass of the hydrogen gas (2.01594g/mol). So, we have:

Now, we will clear the temperature T from the first equation:

We replace the known values:

So, the temperature of hydrogen gas will be 376.40K

pH of the acid can be calculated from the first and second ionization constants of the acid. The pH of 0.294 M of Phthalic acid is 0.53.

pH of a solution is the measure of its H+ ion concentration.It measures the acidity or basicity of the solution. Mathematically it is the negative logarithm of hydrogen ion concentration.

pH = -log [H+]

Give that the first ionization constant of the acid is 1.12 × 10 ⁻³ and second ionization constant is 3.90 × 10⁻⁶. The diprotic acid can be represented as H2A and after its first ionization it produce HA- and H+ On the second ionization the base A- and H+ ion is produced.

The second ionization constant a₂  is written as follows:

a₂ =  [A-] [H+] / [HA - [A]] = 3.90 × 10⁻⁶

From this simply we can get [A] = 3.90 × 10⁻⁶

Thus [H+] = H₂A - [A]

The concentration of the diprotic acid H₂A is given 0.294 M.

Thus [H+] = 0.294 - 3.90 × 10⁻⁶  

                = 0.2933 M

Now, the pH is calculated as follows:

pH = -log (0.2933)

    = 0.53.

Therefore, the pH of 0.294 M of Phthalic acid is 0.53.

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Uranium-238 is an unstable nuclide that emits an alpha particle, three neutrons, and

gamma particles and produces a daughter nuclide Thorium.

The atomic mass of alpha particle is 4g and atomic number 2. Since an alpha particle emits, so there is reduction in the atomic mass 4 and atomic number 2.

The atomic number of neutron is 0 and the atomic mass of neutron is 1. When three neutrons emit the atomic mass reduces to 3 while atomic number remains same.

Gamma particles have no mass and charge. So, atomic number and atomic mass remains same.

Total reduction in atomic mass : 238 - 4 - 3 = 231.

Total reduction in atomic number = 92- 2 = 90

Therefore, the daughter nuclide is Thorium.

Thus, we concluded that the Uranium-238 is an unstable nuclide that emits an alpha particle, three neutrons, and gamma particles and produces a daughter nuclide Thorium.

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Answer

Explanation

Given:

2Al + 3Cl₂ 2AlCl₃

Molar mass of AlCl3 => 133 g/mol

Moles of Cl₂ = 25.0 mol

What to find:

The grams of aluminum chloride that can be produced.

Step-by-step solution:

Step 1: Determine the mole of AlCl₃ produced.

From the given chemical equation for the reaction,

3 mol Cl₂ produce 2 mol AlCl₃

So 25.0 mol Cl₂ will produce

16.67 moles of AlCl₃ produced.

Step 2: Calculated the grams of AlCl₃ produced.

Using the mole formula

Answer: 0.132 moles of Na2SO4

Explanation:

Multiply the grams of Na2SO4 by the 1/molar mass of Na2SO4, which is the sum of all the elements 2(Na)+S+4(O)= 142.04.

Here are all names of compounds in aqeous solution.

What is aqeous solution?

An aqeous solution is one in which the solvent is liquid water .

In this solution water act as a solvent.

Sol-

HBr- Hydrogen bromide

1-HBrO- hydrobromic acid

2-HCL-hydrochloric acid

3-H2O3- hydrogen peroxide

4- HC2H3O2- glacial acetic acid

5-H2SO4-sulfuric acid

6- H3ASO3- Arsenous acid

7- HNO2- Nitrous acid

8- HC104- Perchloric acid

9-H2C2O4- oxalic acid

10- H3pO4- phosporic acid

11-H2CrO4- chromic acid

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Answer:

Explanation:

Here, we want to know the volume of chlorine gas necessary to complete the reaction

We can start by writing a balanced equation of reaction as follows:

From the balanced equation, we can see that 1 mole of chlorine gas requires 2 moles of sodium metal

Now, let us get the number of moles of sodium metal that actually reacted

We have that as the mass of sodium metal divided by the atomic mass

The atomic mass of sodium metal is 23 amu

Thus, we have the number of moles as:

Since the mole ratio is 2 to 1, half of this number of moles is needed by the chlorine gas

Mathematically, 1 mole of a gas occupies a volume of 22.4 L at STP

the volume occupied by the calculated number of moles will be:

The molar mass of unknown gas is 211.59 g/mol.

Since both the gases are present in identical experimental condition, using Grahams law of effusion:

      [tex]\frac{time req for unknown gas}{time of oxygen}[/tex] = [tex]\sqrt{\frac{Molar mass of unknown gas}{molar mass of Oxygen} }[/tex]

  Given:

Time of unknown gas = 72 sec

Time of Oxygen = 28 sec

we know the molar mass of oxygen = 32 g/mol

Now substituting:

    [tex]\frac{72 sec}{28 sec} = \sqrt{\frac{M.M of unknown}{32g/mol} }[/tex]

M.M of unknown = (72 / 28)² × 32 g/mol

                            = 211.59 g/mol

So the molar mass of unknown gas is 211.59 g/mol

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With a balanced reaction, we can determine the moles of products. The balanced equation will be:

FeCl3 + 3NH4OH → Fe(OH)3 + 3NH4Cl

They says that NH4OH is in excess, so, the limiting reactant will be FeCl3 and we will do all the calculations with this reactant.

We have to calculate the moles of FeCl3, we will use the molar mass:

Now, to calculate the moles of the products we must take into account the product/reactive ratios, for this we are guided by the coefficients that accompany the molecules.

Ratio Fe(OH)3 to FeCl3 = 1/1

Ratio NH4Cl to FeCl3 = 3/1

Moles of each product

Moles of Fe(OH)3

Moles of NH4Cl

The grams of each product we will find by multiplying the moles by the molar mass. So we have.

g of Fe(OH)3

g of NH4Cl

Hello.  This is Mr. Biederman, your science teacher at Insight School of Michigan.  You are obviously one of my students.  Posting content here is against school policy.  Just ask me directly for help.  I am always happy to help with anything!

-ZnO is the compound illustrated by the law of constant composition.

According to the rule of constant proportion, the elements are always present in certain amounts to one another by mass in chemical compounds. For instance, regardless of how or where water is obtained, it always contains H2O, hydrogen, and oxygen in a mass ratio of 1:8, according to an example.

for sample A

mass Zn = 8.11g

mass of O =10-8.11=1.89g

Zn= 8.11/65 = 0.1

O= 1.89/16 =0.1

ratio is 1:1

compound = ZnO

for sample b

Zn= 10.70g

O= 13.2-10.7=2.5g

Zn= 10.70/65 =1

O= 2.5/16 =0.16=1

ratio = 1:1

compound= -ZnO

Therefore, it is shown that the figures illustrate the law of constant composition.

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In order to separate the mixture of toluic acid, p-bromo-aniline, and anthracene, the difference in their physical properties such as solubility in organic or inorganic solvents is utilized.

The flow chart for the separation method is found in the attachment.

Mixtures are substances that consist of two or more substances that are physically combined together.

The physical properties of the components of the mixture are employed in the separation of the constituents of the mixture

In separating the given mixture, it is first dissolved in dichloromethane, and then dilute NaOH is added to separate the toluic acid in the aqueous phase. The toluic acid is then precipitated by adding HCl.

Dilute HCl is then added to the organic phase to separate p-bromo-aniline into an aqueous phase and then precipitated by adding 10% NaOH.

Anthracene is left in the organic phase.

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We can care for the pH meter electrode by;

1) Making sure that the electrode remains moist

2) The electrode should be stored in a 4M solution of KCl

3) Electrodes should not come in contact with deionized water.

The term pH has to do with the negative logarithm of the hydrogen ion concentration. Now we know that the pH of a solution tells us the amount of the hydrogen ions or the hydroxyl ions that is present in the solution. The pH mete is the instrument that we could use to be able to measure the pH of the solution.

The pH scale runs between 0 - 14. The points on the scale that have been labeled from 0 - 6 tells us that the solution is an acidic solution and contains more hydrogen ions.  If the solution has a pH of 7, then it is neutral and contains equal concentration of hydrogen and hydroxyl ions. A solution of pH 8 - 14 is basic and contains more hydroxyl than hydrogen ions.

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The half-life of N₂O₅ at 70°C then it is 50s or 0.8min

Half life is the the interval of time required for one half of the atomic nuclei of a radioactive sample to decay

The first-order rate constant for the decomposition of N₂O₅ and reaction is

2N₂O₅(g) → 4NO₂(g)+O₂(g)

The half life is the time at which the concentration of  N₂O₅ is the half initial concentration that is [ N₂O₅ ] = 1/2 [ N₂O₅ ]₀

Using this same equation then

ln ([N₂O₅]) = -2kt + ln ([N₂O₅]₀)

We replace [ N₂O₅ ] by 1/2[ N₂O₅ ]₀ and solve for t

ln (1/2 [N₂O₅]₀) = -2kt + ln ([N₂O₅]₀) applying logarithmic property

ln 1/2 + ln([N₂O₅]₀) = -2kt + ln ([N₂O₅]₀)  solving for t and applying logarithmic property (ln 1/2 = ln 1 - ln 2 = 0 - ln 2 = - ln 2)

t = ln 2/2k

t = 50s or 0.8min

The half-life of N₂O₅ at 70°C then it is 50s or 0.8min

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Answer:

It would generate a electro lithium nucleous

Answer:

b.Carbon has a total of four bonded pairs of electrons around it.

ANSWER

Moles of water is 3.50 moles

EXPLANATION

Given that:

The mole of hydrogen gas is 3.50 moles

Firstly, write a balanced equation for the reaction

In the reaction, 2 moles of hydrogen will give you 2 moles of H2O

Since the number of moles of hydrogen given id 3.5 moles, then the number of moles of water.

• We are given that Lidocaine is available as 0.5%(w/v) , 0.5%(w/v) represents the amount of Lidocaine in grams per 100mL. so, 0.5% is the same as 0.5g of Lidocaine in 100ml.

• Since our solution has a volume of 6.0mL:

mass of Lidocaine = 6mL * (0.5g /100mL)

= 0.03g of Lidocaine in 6.0mLsolution.

This means that, in 6.0ml of this injection solution, we have 0.03g of Lidocaine .

The heat energy that is required to melt all the ice at temperature of 0° C is 7.28x10^5 cal.

What is heat energy?

Heat energy is created by the movement of tiny atoms, molecules, or ions in solids, liquids, and gases. It is possible to transfer heat energy from one thing to another. Heat is a flow or transfer that happens when two objects have different temperatures from one another.

We know that the initial temperature of the ice (T) is 0° C

Latent heat of ice is given in the question as 80.0 cal/g

The mass of ice given in question is 9.10 kg

So, the heat required to change the phase of the ice is given as:

[tex]Q=mL[/tex]

[tex]Q =(9.10 \times 10^3)(80)[/tex]

[tex]Q = 728 \times 10^3[/tex]

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Temperature is a measure of how hot a substance or radiation is expressed numerically.

There are three different types of temperature scales:

those that depend only on macroscopic properties and thermodynamic principles, like Kelvin's original definition;

those that depend on practical empirical properties of particles rather than theoretical principles;

and those that are defined by the average translational kinetic energy per freely moving microscopic particle, like an atom, molecule, or electron, in a body, like the SI scale.

How much heat is gained or lost by a sample can be calculated using the equation q = mcΔT, where m is the mass of the sample, c is the specific heat, and T is the temperature change (q).

Therefore,

q = m*c*ΔT

102.3 = 335 * 4.184 * ΔT

ΔT = 0.073 °c

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Answer:

flammability, toxicity etc..

Explanation:

are chemical changes