What kind of force could cause this ball to not be at rest anymore, or cause it to move?

Answers

Answer 1

Answer:

friction

Explanation

Answer 2

Answer:

Friction

Explanation:

What force prevents an object at rest?

Sliding Friction While static friction keeps an object at rest, sliding friction slows down an object that slides. If you push an object across a room, you notice the sliding friction between the bottom of the object and the floor. You have to keep pushing to overcome the force of sliding friction.


Related Questions

An object is at rest. There are several forces acting on the object, but the net force is zero. If all the
forces acting on the object were to suddenly double in size, would the object start moving? Why or why not?

Answers

It would not. Imagine four forces equal in magnitude but opposite in direction (e.g. north, east, south, and west). If these forces were to double in magnitude they would still have the same magnitude, meaning the net force is still equal to zero.

Answer:

no

Explanation:

because the heaver an object the harder it is to move s the force will not be able to move it

Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. You have determined that the football would travel 15.1 m before landing.

How would this value change if the football was kicked at an angle of 35.0°?Complete all equations without rounding and then round to the nearest tenth at the end.

From edge

Answers

Answer:

like 23 or something

Explanation:

In the diagram below if bulb 2 blew out what would happen to the VOLTAGE? (it’s not decreases that’s why it’s highlighted)

Answers

Answer:

apagado, así que lo más destacado es el problema, oh, está bien, esa es la respuesta, cariño.

A bus slams on its breaks and goes from 30km/hr to 15km/hr in 4 seconds. What is its acceleration?

Answers

Answer:

− 2.08

Explanation:

Note the equation v = v0 + at, where v is the final velocity in meters per second, v0 is the initial velocity in meters per second, a is the acceleration, and t is the time in seconds.

Fist convert the velocities so 30km/hr=8.333m/s and 15km/hr=4.167m/s

Plugging this into the equation, we get
4.167 = 8.333 + a(4)
=> -4.167 = a(4)
=> a = -1.042 m/s^2


1. An object would have a different mass on Earth as it would have on the moon.
a. True
b. False

Answers

Answer:

a.true

Explanation:

because the gravitational strength of earth and moon is different

What is the half-life for the radioactive decay of particle that
starts with 400.00 g and ends up with 12.50 g if the total time
was 50 minutes for the decay to occur?

Answers

Answer:

ytyug

Explanation:

which chamber approves presidential nomination

Answers

Answer: The Senate provides advice and consent on presidential nominations.

Please help me on this 1 assignment im giving 25 points GOOD LUCK!

Answers

Answer:

Explanation:

im sorry if this doesn't help but i think  its A

an electric charge (Q=-230nc) located at origin generate an electric field at point P located at (2 , 6)m(meter) find the electric filed at P *

Answers

See attached file:
We are given the electric field equation so we input all the values we are given, eventually getting E = 51.75 N/C

What would a force diagram for something WHILE it is being thrown DOWNWARDS look like?

Ty

Answers

Answer:

it look the same just to tell you

A 50-n force is applied to a 10-kg chair, but the chair does not change its motion. What could explain this?.

Answers

Explanation:

it will not change it's motion because it's force is less than the force applied

A man is sitting on a chair with wheels. He grabs a 2.1 kg book from the desk and throws
the book at a speed of 7.2 m/s. His chair moves backward. The man has a mass of 70 kg and
the chair has a mass of 9.2 kg. What is the speed of the man and the chair after the book is
thrown?

Answers

The speed of the man and the chair after the book is thrown is 0.2 m/s.

The given parameters:

mass of the book, m₁ = 2.1 kgspeed of the book, u₁ = 7.2 m/smass of the man, M = 70 kgmass of the book, m = 9.2 kg

The total mass of the man and the book is calculated as follows;

m₂ = 70 kg + 9.2 kg

m₂ = 79.2 kg

The speed of the man and the chair after the book is thrown is determined by applying the principle of conservation of linear momentum;

[tex]m_1 u_1 = m_2u_2\\\\u_2 = \frac{m_1u_1}{m_2} \\\\u_2 = \frac{2.1 \times 7.2}{79.2} \\\\u_2 = 0.2 \ m/s[/tex]

Thus, the speed of the man and the chair after the book is thrown is 0.2 m/s.

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a race car traveling at 44m/s slows at a constant rate to a velocity of 22m/s over 11 seconds , how far does it move during this time

find distance and acceleration

PLEASEEEE HELP I HAVE A PHYSICS EXAM TOMORROW AND IM STRUGGLING

Answers

Answer:

add 44m/s and 22m/s then multiply it by 11

Explanation:

A race car traveling at 44m/s slows at a constant rate to a velocity of 22m/s over 11 seconds, Acceleration is -2 m/s² (deceleration), and distance is 242 meters.

To solve this problem, it is given:

Initial velocity ([tex]\(v_i\)[/tex] ) = 44 m/s

Final velocity ([tex]\(v_f[/tex] ) = 22 m/s

Time ([tex]\(t\)[/tex] ) = 11 s

We have two tasks: finding the acceleration (a) and then using it to calculate the distance (d).

1. Calculate Acceleration (a):

[tex]\[a = \frac{v_f - v_i}{t} \\\\= \frac{22 \, \text{m/s} - 44 \, \text{m/s}}{11 \, \text{s}} \\\\= -2 \, \text{m/s}^2\][/tex]

The negative sign indicates deceleration (slowing down).

2. Calculate Distance (d):

Using the kinematic equation:

[tex]\[d = v_i \cdot t + \frac{1}{2} \cdot a \cdot t^2\][/tex]

Plugging in the values:

[tex]\[d = (44 \, \text{m/s}) \cdot (11 \, \text{s}) + \frac{1}{2} \cdot (-2 \, \text{m/s}^2) \cdot (11 \, \text{s})^2\][/tex]

Calculating the first part:

[tex]\[d = 484 \, \text{m} - 121 \, \text{m} \\\\= 363 \, \text{m}\][/tex]

Calculating the second part:

[tex]\[d = 363 \, \text{m} + \frac{1}{2} \cdot (-2 \, \text{m/s}^2) \cdot (121 \, \text{s}^2) \\\\= 363 \, \text{m} - 121 \, \text{m} \\\\= 242 \, \text{m}\][/tex]

The total distance the race car moves during this time is 242 meters.

Thus, acceleration is -2 m/s² (deceleration), and distance is 242 meters.

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Two forces are applied to a 50-kg box. One is 60.0
N to the south and the other is 80.0 N to the east.
These are the only forces acting on the box. The
magnitude of the acceleration of the box is:
1. 20m/s^2
2. 1.5 m/s^2
3. 5.2 m/s^2
4. 0.50m/s^2
5. 10m/s^2

Answers

The magnitude of the acceleration of the box is 2 m/s².

The given parameters;

mass of the box, m = 50 kgfirst force, F₁ = 60 N southsecond force, F₂ = 80 east

The resultant of the two given forces is calculated as follows;

[tex]F= \sqrt{F_1 ^2 + F_2 ^2} \\\\F = \sqrt{60^2 + 80^2} \\\\F = 100 \ N[/tex]

The magnitude of the acceleration of the box is calculated as follows;

[tex]F = ma\\\\a = \frac{F}{m} \\\\a = \frac{100}{50} \\\\a = 2 \ m/s^2[/tex]

Thus, the magnitude of the acceleration of the box is 2 m/s².

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How to find direction of magnetic field.

Answers

unlock your third eye and youll be able to see it

what kind of frog species is this

Answers

Answer: i think its a bullfrog forgive me if im wrong i dont exactly know

Explanation:

Answer:

that is an African bullfrog

What types of energy do you acquire when you eat a bowl of hot vegetable soup?

Answers

Answer:

you need kinetic energy because it is the energy that is used when In motion

The type of energy that one acquire when you eat a bowl of hot vegetable soup is chemical energy.

What is chemical energy?

Chemical power the bonds of chemical molecules contain energy. Exothermic reactions are those in which chemical energy is released during the reaction, frequently in the form of heat.

Some of the heat energy needed for a reaction to continue can be stored as chemical energy in newly created bonds.

Food particles go through a chemical reaction that releases chemical energy when we eat it. The body then uses this energy to carry out its regular tasks.

As a result, when you eat a cup of vegetable soup, you also consume the chemical energy it contains.

Thus, the answer is chemical energy.

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How to find angular velocity of an object traveling at a constant speed.

Answers

I only know the formula which is ω = 2πf

How are earthquakes at continental plate boundaries different from earthquakes at mid-ocean ridges?

Answers

Differences between earthquakes at continental plate boundaries and earthquakes at mid-ocean ridges discussed in the answer.

What is earthquakes at continental plate boundaries and earthquakes at mid-ocean ridges?

When plates travel in the same direction and collide, this happens. The thinner, denser, and more flexible oceanic plate dips beneath the thicker, more rigid continental plate when a continental plate meets an oceanic plate. It's known as subduction.

Deep ocean trenches, like the one that runs down South America's west coast, are created by subduction. The continent's undercut rocks start to melt. On occasion, a chain of volcanoes forms as the molten rock rises to the surface and passes through the continent. Nearly 80% of earthquakes happen along convergent borders, when plates are being forced together.

Shallow earthquakes, often less than 30 km deep, occur in small bands adjacent to plate borders along mid-ocean ridges and transform edges. There are earthquakes in subduction zones at various depths, some of which are more than 700 km deep. Because they occur everywhere throughout the subducting slab that stretches beneath the opposing plate, earthquake bands are wider along subduction zones. Wide areas of distributed earthquakes may be associated with collision zones between continents, such as those between the Eurasian plate and the plates to the south of the African, Arabian, and Indian tectonic arcs.

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A falling object with a weight of 15N is moving downwards towards earth at a steady speed. What is the size of the drag force on this object?

Answers

Answer:

15 N :D

Explanation:

The size of the drag force on this object falling at a constant speed is determined as 15 N.

Drag force on the object

The drag force on the object is determined by calculating the net force on the object;

F(net) = W - D

where;

W is weight of the objectD is the drag force of air

ma = W - D

at constant speed, acceleration, a = 0

0 = W - D

W  = D

15 N = D

Thus, the size of the drag force on this object falling at a constant speed is determined as 15 N.

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1
A pencil weighing 1N is sitting on a desk.
Write down all the forces on the desk.
a.
b.
Draw a free body diagram of the desk.
c.
Add up the forces in the x-direction (horizontal) and the y-direction (vertical)

Answers

The force diagram on the desk consists of normal reaction and weight of the pencil.

The net force on the desk in vertical direction is 1 N.

The net force on the desk in horizontal direction is 0.

The given parameters;

weight of the pencil, W = 1 N

The force diagram of the desk is sketched as follows;

                                             ↑ N

                                             ⊕

                                              ↓ W

Where;

N is the normal reaction on the deskW is the weight of the ball

The net force on the desk in vertical direction = 1 N

The net force on the desk in horizontal direction = 0

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PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!


Zhiyu wants to start an exercise program. He knows that he should talk to his doctor, but he cannot get an appointment for several weeks. He does not have any health conditions. What is the BEST advice for Zhiyu?
A.
All exercise needs to be medically supervised, so he must wait.
B.
There is always a risk of injury, so he needs professional advice before he starts.
C.
He can start slowly with low impact activity like walking or light weightlifting.
D.
He should do whatever he feels like; his body will let him know if he overdoes it.


PLEASE NO LINKS OR I WILL REPORT YOU

Answers

Answer:

c

Explanation:

the relationship between global warming and greenhouse gases is the _______.

Answers

how both affect the ozone layer and affect temperature in a grobal way

A force of 6.0 N acts on a 4.0 Kg object for 10.0s. What is the object's change in momentum?

Answers

Answer:

60 Ns

Explanation:

change in momentum = Fxt

6*10

60 Ns

A force of 6.0 N acts on a 4.0 Kg object for 10.0 s. The object's change in momentum is 60 kg-m/sec.

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

change in momentum = force . time

change in momentum = 6 . 10 = 60

A force of 6.0 N acts on a 4.0 Kg object for 10.0 s. The object's change in momentum is 60 kg-m/sec.

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a water skier has a mass of 80 kg and accelerates at 2 m/s2. What is the net force(F) acting on him?

Answers

Answer:

160 N

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

mass = 80 kg

acceleration = 2 m/s²

We have

force = 80 × 2 = 160

We have the final answer as

160 N

Hope this helps you

help plz

Stop and go traffic means a lot of opportunities for acceleration. This assignment looks at a typical experience of a car in typical rush hour traffic. Calculate the different accelerations from the graph, interpret what your answers mean and show you really understand acceleration.

A car traveled through rush hour traffic in a city. There was a lot of starting and stopping. The graph below shows the motion of the car for a 16 second interval of time.
Explain what is going on between point B and C in terms of velocity and acceleration.

Velocity:

Acceleration:

Answers

-In terms of velocity it remains constant at 7 m/s for 4 hours (time between b and c)

- in terms of acceleration, there is no acceleration. When something has constant velocity there is 0 acceleration

What is gibbs free energy.

Answers

Answer:

It’s a

Explanation:

You discover a planet orbiting a distant star that has about the same mass as the sun, with an orbital period of 53 days. What is the planet’s orbital distance?.

Answers

Answer:

G M1 m1 / R1^2 = G M2 m2 / R2^2          gravitational equation

We can try Kepler's harmonic law

P2^2 = K R2^3

P1^2 = K R1^3     for earth

(P2 / P1)^2 = (R2 / R1)^3       dividing equations

R2^3 = (P2 / P1)^2 * R1^3

R2^3 = (53 / 365)^2 * R1^3

R2^3 = .145 R1^3

R2 = .526 R1

If one uses 93E6 miles as distance of sun from earth then

R2 = 49E6 miles

true or false

as mass increases the gravitational force decreases​

Answers

The answer to this question is true I believe
The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them. This means that the force of gravity increases with mass, but decreases with increasing distance between objects.

what third force must be added to the two forces 30 Newton at 30 degree and 80 Newton at 135 degree the resolution for equal to zero​

Answers

Answer:

Resolve the vectors:

F1 = 30 cos 30 i + 30 sin 30 j = 26 i + 15 j

F2 = 80 cos 135 i + 80 sin 135 j = -56.6 i + 56,6 j

F1 + F2 = (26 - 56.6) i + (15 + 56.6) j = -30.6 i + 71.6 j

The offsetting force would be

F3 = 30.6 i - 71.6 j

The magnitude of this vector is (30.6^2 + 71.6^2)^1/2 = 77.9

cos theta 3 = 30.6 / 77.9 = 66.9 deg

Check:

77.9 * sin 66.9 = 71.6  agreeing in magnitude with F3

Now we need the quadrant of the offsetting vector

sin theta 3 = -         cos theta 3 = +

This occurs in the fourth quadrant and theta 3 = 360 - 66.9 = 293.1 deg

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