The average angular acceleration of a Blu-ray disc is 0.089 rad/s².
Angular acceleration refers to the time price of exchange of angular speed. As there are types of angular velocity, namely spin angular velocity and orbital angular velocity, Angular speed is the rate of change of angular displacement and angular acceleration is the rate of trade of angular pace.
Angular Acceleration is described as the time rate of change of angular velocity. it is usually expressed in radians in keeping with second in line with second. as a result, α = d ω d t. Angular acceleration is also known as rotational acceleration.
t = time duration = 6 h = 6 x 3600 sec
α = angular acceleration = (Wmax - Wmin )/t = (315 - 121)/(6 x 3600 ) = 0.089 rad/s²
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The location of magnetic north changes over time in its relation to true north. This angular difference between magnetic north and true north is called.
The angular difference between true north and magnetic north is called declination.
What is declination?
Declination is the said to be the angle between magnetic north and geographic north in the horizontal plane that changes with time and geographic location. The true north or geographic north is a fixed point on the globe that points towards the north pole directly while the magnetic north unlike the true north changes over time, and it is the direction a compact needle points to as it aligns with the earth's magnetic field.
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A swimmer needs to cross a river as quickly as possible. The swimmer’s speed in still water is 1.35 m/s.
(a) If the river’s current speed is 0.60 m/s and the river is 106.68 m wide, how long will it take the swimmer to cross the river if he swims so that his body is angled slightly upstream while crossing, and he ends up on the far bank directly across from where he started?
(b) If he points his body directly across the river and is therefore carried downstream, how long will it take to get across the river and how far downstream from his starting point will he end up?
A swimmer needs to cross a river as quickly as possible. The swimmer’s speed in still water is 1.35 m/s.
(a) If the river’s current speed is 0.60 m/s and the river is 106.68 m wide, it will take the time swimmer to cross the river is (t) = 72.57 S, if he swims so that his body is angled slightly upstream while crossing, and he ends up on the far bank directly across from where he started.
(b) If he points his body directly across the river and is therefore carried downstream, it will take time to get across the river is (t)=72.57 S, and the distance downstream from his starting point will he end up is (S) = 43.542m.
What is velocity?Velocity means that the covered distance in a given time. In other words mathematically distance divided by time called velocity. It can be measured in m/s and cm/s.
How can we calculate the time and distance?(a)To calculate the time for the first case we are using the formula, S=vt.
The swimmer’s speed in still water is 1.35 m/s.=v₁=1.35j m/s.
the river’s current speed is 0.60 m/s.=v₂=0.60i m/s.
Now, let us apply the rule of relative velocity:
v=v₁+v₂=1.35j+0.60i
Or, |v|=√(1.35)²+(0.60)²
Or, |v|=1.47 m/s
Now we know the velocity of the water, v=1.47 m/s.
The wide of the river, S=106.68 m
Now we have to calculate the time to travel of the swimmer= t s
Now we put the values in above equation,
S=vt
Or, t=S/v
Or, t= 106.68/1.47
Or, t=72.57 s.
From the above calculation we can say that, If the river’s current speed is 0.60 m/s and the river is 106.68 m wide, it will take the time swimmer to cross the river is (t)=72.57 S
(b) If he points his body directly across the river and is therefore carried downstream, The time taken by the swimmer is the same as the first case.
So the time would be (t)=72.57 S.
The distance downstream from his starting point will he end up,
S = vt
Or, S= 0.6*72.57
Or, S=43.542
So according to the solution, If he points his body directly across the river and is therefore carried downstream, it will take to get across the river is (t)=72.57 S, and the distance downstream from his starting point will he end up is (S)=43.542m.
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1. How does the transfer of momentum change when the velocity of the marble change?
2. How does the transfer of momentum change when the mass (number of marbles) changes?
3. How could you calculate the momentum of a single marble?
4. If two marbles together are moving at the same speed as a single marble which will have greater momentum and why?
5. Can momentum be shown as a vector? Explain why or why not?
The transfer of momentum increases when the velocity of the marble increases and vice versa.
The transfer of momentum increases when the mass (number of marbles) increases and vice versa.
The momentum of a single marble can be calculated from the product of its mass and velocity.
If two marbles together are moving at the same speed as a single marble, the two marbles will have greater momentum because of their greater mass.
Momentum can be shown as a vector because the direction of the momentum of a body is specified.
What is the momentum of a body?The momentum of a body is the product of the mass and the velocity of the body.
Mathematically;
Momentum = mass * velocitySince the velocity of an object is a vector, the momentum of a body is also a vector.
The momentum of a body is directly proportional to its mass and velocity.
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Carlos does a chin-up in gym class and raises himself 0.8 m. If Carlos has a mass of 62 kg how much work does he accomplish?
Answer:486.1 J
Explanation:
25 Which wavefront is travelling at a speed closest to that of a sound wave through a solid? A one that moves 10m in 0.01 s B one that moves 50m in 0.5s C one that moves 1000 m in 100 s D one that moves 2000 m in 2000 s
The wavefront B is travelling at the speed(5000m/s) closest to that of a sound wave(6000m/s) travelling through solid.
The velocity of the sound waves in solids is nearly 6000 meters per second.
Let us check the velocity for all the three wave fronts,,
Wavefront A,
We know,
speed = distance/time taken
Distance travelled by the wavefront A is 10m,
Time taken by the wavefront A to travel the distance is 0.01 seconds,
Putting all the values,
Speed = 10/0.01
Speed = 1000m/s.
Speed of wavefront A is 1000m/s.
Wavefront B,
Again we know,
speed = distance/time taken
Distance travelled by the wavefront Bis 50m,
Time taken by the wavefront B to travel the distance is 0.01 seconds,
Putting all the values,
Speed = 50/0.01
Speed = 5000m/s.
Speed of wavefront B is 5000m/s.
Wavefront C,
We know,
speed = distance/time taken
Distance travelled by the wavefront C is 1000m,
Time taken by the wavefront C to travel the distance is 100 seconds,
Putting all the values,
Speed = 1000/100
Speed = 10m/s.
Speed of wavefront C is 10m/s.
Wavefront D,
Again using the formula,
speed = distance/time taken
Distance travelled by the wavefront is 2000m,
Time taken by the wavefront to travel the distance is 2000 seconds,
Putting all the values,
Speed = 2000/2000
Speed = 1m/s.
Speed of wavefront D is 1m/s.
As we can see, The speed of wavefront B is closest to the speed of sound waves in solids.
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A tennis player makes a return at a speed of 15m/s and at height of 3m to land in the court at a horizontal distanceof 12m from her. what are the possible angles of projection of the ball
With the use of range formula, also, in multiple of 180 degree, 59 and 239 degrees are the angles of projection.
What is a Projectile ?A projectile in kinematic under physics can be defined as any object that is projected or thrown to take a trajectory path.
Given that a tennis player makes a return at a speed of 15 m/s and at height of 3m to land in the court at a horizontal distance of 12 m from her.
Let us assume that the ball fall at height 3m. U = 0. Let us find the time
h = ut + 1/2gt²
3 = 0 + 1/2 × 9.8 × t²
3 = 4.9t²
t² = 3/4.9
t² = 0.612
t = √0.612
t = 0.782 s
Total time T = 2t
T = 2 × 0.782
T = 1.564 s
The possible angles of projection of the ball can be calculated by using the range formula
R = UcosФT
12 = 15cosФ × 1.564
12 = 23.46cosФ
cosФ = 12 / 23.46
cosФ = 0.512
Ф = [tex]Cos^{-1}[/tex] (0.512)
Ф = 59. 2 degree
Ф = 59°
Therefore, the possible angles of projection of the ball are 59° and 239°
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A student drops a rock from a bridge to the
water 14.4 m below.
With what speed does the rock strike
the water? The acceleration of gravity is
9.8 m/s².
Answer in units of m/s.
Answer:
Explanation:
at first the rock is at rest so initial velocity is zero
after accelerating it reaches a final velocity
we are supposed to find that final velocity
[tex]v^{2} = u^{2} +2ax[/tex]
v= final velocity
u= initial velocity
x= distance
a= acceleration
[tex]v^{2} = 0^{2} + 2(9.8)(14.4)[/tex]
[tex]v^{2} = 282.24[/tex]
[tex]v= \sqrt{282.24}[/tex]
[tex]v= 16.8 m/s[/tex]
among the different forms of electromagnetic radiation emitted by the sun, which form is absorbed by plants for photosynthesis? microwaves ultraviolet visible light gamma rays infrared
Visible light , The process by which plants convert carbon dioxide, water, and sunshine into oxygen and sugar-based energy is known as photosynthesis.
What is photosynthesis?Photosynthesis is a mechanism used by plants and other living organisms to convert light energy into chemical energy that can then be released through cellular respiration to power the organism's activities.Photosynthesis is the process through which plants turn carbon dioxide, water, and sunlight into oxygen and sugar-based energy.The process through which green plants use sunlight to create their own nourishment is known as photosynthesis. Life on Earth depends on photosynthesis. There would be no green vegetation if it did not exist, and there would be no creatures if it did not exist.Photosynthesis is primarily used to convert solar energy into chemical energy, which is then stored for use at a later time. The majority of the life systems on the planet are powered.To learn more about photosynthesis, refer to:
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What is the frequency of light when the energy of a single photon is 1. 48 × 10-15 j?.
The frequency of light is 3.88x10^23Hz
E = 1.55 x J/ mol
E = hv
v = (1.55 x /1mol x 1mol/6.023 x )/6.626 x 10^34
velocity = 3.88x10^23 s-1
since 1 Hz = 1/ s = 1
velocity =3.88x10^23 Hz
The portion of the electromagnetic spectrum contains the electromagnetic radiation that the human eye perceives as light or visible light. Visible light typically possesses wavelengths between 400 and 700 nanometers (nm) or frequencies between 750 and 420 terahertz, which are halfway between infrared and ultraviolet (with longer wavelengths) (with shorter wavelengths).
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Sample question: What is the frequency of light when the energy for a mole of photons is 1. 55 × 1013 j?.
a car of mass 1850 kg is traveling at 22.5 m/s in a straight line. a truck of mass 3170 moving in the opposite direction collides with the car and the 2 vehicles stop immediately without sliding. the speed of the truck was
13.13 m/s is the velocity of the truck was when a truck of mass 3170 moving in the opposite direction collides with the car and the 2 vehicles stop immediately without sliding.
Momentum of car= 1850(22.5)=41625 kg m/s
Momentum of car = momentum of truck
Let the speed of truck = v m/s
Momentum of truck= v(3170)=3170 v kgm/s
3170v = 41625
v = 13.13 m/s
Speed of truck = 13.13 m/s
The pace at which a moving object changes position as seen from a certain point of view and as measured by a particular time standard is known as its velocity.
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Which is an example of an inclined plane?
ramp
zipper
knife
jar lid
States that if no external forces act on a group of objects, their total momentum does not change
Answer: this is true
Explanation:
if the object is moving and there is nothing stooping it, it will keep moving
If an astronaut weighs 148 N on the Moon and 893 N on Earth,
then what is his mass on Earth?
Answer:
So, at moon g’=1.62 m/s^2
Therefore, mg’=99N (as given , where m is the mass )
so, m=99/1.62 =61.11 kg
hence, weight on earth will be mg( where g is the acceleration due to gravity at earth, 9.8m/s^2)
61.11*9.8=598.878 N will be the weight on earth
Explanation:
hope it helps
an airplane that is flying level needs to accelerate from a speed of 200 m/s to a speed of 240 m/s while it flies a distance of 1200 m. what must the constant acceleration of the plane be?
The constant acceleration of the plane is 7.33 m/[tex]s^{2}[/tex].
Use this formula of acceleration, [tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2as
[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2as,
a = [tex]v^{2}[/tex] - [tex]u^{2}[/tex] / 2s
v = velocity
s = distance
a = acceleration
Put the values in this formula, a = [tex]v^{2}[/tex] = [tex]u^{2}[/tex] / 2s
a = (240× 240) - (200 × 200)/ 2 × 1200
a = 7.33 m/[tex]s^{2}[/tex]
Hence, the constant acceleration of the plane is 7.33 m/[tex]s^{2}[/tex].
Acceleration is the rate of change of velocity per unit time. It is vector quantity and its S.I. unit is m/[tex]s^{2}[/tex].
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a wave has an amplitude of 2 cm (y-direction) and a frequency of 12 hz, and the distance (x-direction) from a crest to the nearest trough is measured to be 5 cm. determine the velocity of the wave.
120 centimeters per second, is the wave speed or wave velocity.
How fast do waves travel?Wave velocity is the amount of distance a wave travels in one unit of time. The rate at which a particle disturbance like a crest or trough or compression or rarefaction spreads in a medium is known as the particle's propagation speed.
Given,
Amplitude (A) = 2cm,
Frequency (f) = 12hz,
Time period [tex]T=\frac{1}{f} =\frac{1}{12} s[/tex]
The horizontal distance between the closest peak or trough, respectively, is referred to as the wavelength. A crest's distance from the closest tough was specified. The distance between a crest and the closest crest is therefore two times that distance.
This is the wave length :
λ=(2)(5)
=10cm
The wave velocity or wave speed is given by:
v = λf
v=(10)(12)
=120 cm/s
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A steam turbine has an efficiency of 40.0%. A steam engine has an efficiency of
25.0%. Suppose both devices are provided with 1000 J of thermal energy. How much
more useful work will the steam turbine do? Show your work.
Answer:
150J (joules)
Explanation:
25% efficiency of 1000J = 250J
40% efficiency of 1000J= 400J
400-250=150
2. A feather is dropped on the moon from a height of 1.40 meters. The acceleration of gravity on the moon is 1.67 m/s2. Determine the time for the feather to fall to the surface of the moon.
The total time taken by the feather to fall to the surface of moon will be 1.29 seconds.
Given is a feather dropped on the moon from a height of 1.40 meters. The acceleration of gravity on the moon is 1.67 m/s².
State second equation of motion.The second equation of motion is -
S = ut + 1/2 at²
We can write -
[S] = 1.4 m
[a] = 1.67 m/s²
[u] = 0 m/s
Using the second equation of motion -
S = ut + 1/2 at²
S = 1/2 at²
1.4 = 1/2 x 1.67 x t²
1.4 = 0.835 x t²
t = 1.29 seconds
Therefore, the total time taken by the feather to fall to the surface of moon will be 1.29 seconds.
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1. what happens when electromagnetic radiation encounters a metal object? discuss two ways that can be used to reduce interference from electrical noise.
A full circuit is required for the flow of electrical current, and all electrical energy transmissions need the formation of a circuit with two wires—one going to the recipient and the other going back to the sender.
The construction of a circuit with two wires—one going to the recipient and the other back to the sender—is necessary for all electrical energy transmissions in order for current to flow. Due to the fact that all wireless signals are essentially delivered as electromagnetic signals rather than electrical signals, electromagnetic interference, often known as EMI, is a common problem in wireless communications.
This suggests that any interference with an electromagnetic signal (wave) may cause it to be amplified, destroyed, or lost (assuming constructive interference).
The interference brought on by electromagnetic disturbance is known as electromagnetic interference. Radio frequency interference is another name for it. We refer to interference that occurs in the radio frequency spectrum as radio frequency interference.
These days, wireless communication is expanding at an unprecedented rate. Over a large concentration, a small spectrum is available. Because of this, there is a greater likelihood of mutual interference. The performance of the device and the channel can both be impacted by a slight electromagnetic disturbance. It is crucial to keep interference at a minimal for better wireless performance.
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a hockey puck with a mass of 0.11 kg is at rest on the horizontal frictionless surface of the rink. a player applies a horizontal force of 1 n to the puck. find the speed and the traveled distance 5 s later.
The solution to this ques is available in the image.
Given,
Force= 1N
Mass= 0.11kg
Time= 5sec
Force= mass X accelaration
Accelaration= velocity/ time
Speed=distance/ time
Hence, the speed is 45 m/s and the distance is 225 m.
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On the kickoff, the football was in the air for 4 seconds before hitting the ground 53 meters away. How fast did the ball leave the foot of the kicker?
Answer:
Vx = 53 m / 4 sec = 13.25 m/s horizontal speed
Vy = 2 sec* 9.80 m/sec^2 = 19.6 m/s vertical speed
V = (13.25^2 + 19.6^2)^1/2 = 23.7 m/s
Check:
Range = V^2 sin 2θ / g
tan θ = 19.6 / 13.25 = 1.48 θ = 55.9 deg
R = 23.7^2 sin 112 deg / 9.8 = 53.1 m
2 and 23/75 as a percentage
2 and 23/75 as a percentage is 2.30666666666. Hope this helps! :)
A cyclist is going downhill and begins its movement with 12.5 m/s. 30 seconds later he reaches 25 m/s and maintains that velocity for the next 60 seconds. Then he sees the finishing line and brakes until he reaches a complete stop 15 seconds later
Find the value for Acceleration for the stages where it is involved and find the total distance traveled.
1. The acceleration of the cyclist is 0.42 m/s²
2. The total distance travelled by the cyclist is 2437.5 m
1. How to determine the acceleration
We can obtain the acceleration of theration of the cyclist as follow:
Initial velocity (u) = 12.5 m/sTime (t) = 30 secondsFinal velocity (v) = 25 m/sAcceleration (a) =?a = (v – u) / t
a = (25 – 12.5) / 30
a = 12.5 / 30
a = 0.42 m/s²
Thus, the acceleration is 0.42 m/s²
2. How to determine the total distance
We'll begin by obtaining the distance travelled in the first 30 s. This can be obtained as follow:
Initial velocity (u) = 12.5 m/sTime (t) = 30 secondsFinal velocity (v) = 25 m/sDistance (s) = ?s = (u + v)t / 2
s = [(12.5 + 25) × 30] / 2
s = [37.5 × 30] / 2
s = 1125 / 2
s = 562.5 m
Next, we shall determine the distance in the next 60 second.
Velocity (v) = 25 m/sTime (t) = 60 secondsDistance (s) =?s = vt
s = 25 × 60
s = 1500 m
Next, we shall determine the distance in the last 15 seconds.
Initial velocity (u) = 25 m/sTime (t) = 15 secondsFinal velocity (v) = 0 m/sDistance (s) = ?s = (u + v)t / 2
s = [(25 + 0) × 15] / 2
s = [25 × 30] / 2
s = 750 / 2
s = 375 m
Finally, we shall determine the total distance travelled.
Distance in the first 30 s = 562.5 mDistance in the next 60 s = 1500 mDistance in the last 15 s = 375 mTotal distance = ?Total distance = 562.5 + 1500 + 375
Total distance = 2437.5 m
Thus, the total distance travelled is 2437.5 m
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A ball is booted from the ground at an angle of 0 = 44 degrees with respect to the horizontal. The ball is in the air for a time im = 2.5 s before it lands back on the ground
Numerically, what is the total horizontal distance, dm in meters, traveled by the ball in the time, m?
Projectile motion is exemplified by actions like throwing a ball straight up, a ball and giving it speed at an angle to the horizontal, or simply dropping something and letting it fall freely. Gravity is the only force acting on the object during projectile velocity.
Horizontal distance traveled by the ball is 29.86 m
What is projectile motion?A projectile is an object that is launched into the air and moves in that direction. The only force an object experiences after the initial force that launches it is gravity. The trajectory of the object is referred to as the projectile's path.The three different types of projectile motion are as follows: horizontal projectile motion. projectile motion that is oblique. motion of a projectile on an incline.Projectile motion is exemplified by actions like throwing a ball straight up, kicking a ball and giving it speed at an angle to the horizontal, or simply dropping something and letting it fall freely. Gravity is the only force acting on the object during projectile velocity.Launch angle x = 44 °
time period of flight = 2.5s
Time period of Projectile T = [tex]\frac{2u sin x}{g}[/tex] , g=acceleration due to gravity
2.5 = [tex]\frac{2 X u sin 44}{9.2}[/tex]
Where u=initial velocity = 16.66 m/s
Range of Projectile is given by
R = [tex]\frac{u^{2} sin 2x }{g}[/tex]
R= [tex]\frac{16.66^{2} sin 2x44}{9.2}[/tex]
R = 29.86 m
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Urgent!!!!
Batman is chasing the joker. If, while gliding down towards him at 75 m/s, it takes him 30 seconds to catch him, how far away was the joker? And how many kilometers is that?
Answer:
it's 2250meters and 2.25km
Explanation:
speed= distance÷time
75=distance÷30
75×30=distance
2250 m= distance
To convert meters into Kilometres we divide by 1000 so,
2250÷1000
2.25 Km
if the satellite has a mass of 3500 kg , a radius of 4.4 m , and the rockets each add a mass of 220 kg , what is the required steady force of each rocket if the satellite is to reach 32 rpm in 5.0 min , starting from rest?
0.145 Newton is the required steady force of each rocket if the satellite is to reach 32 rpm in 5.0 min , starting from rest
mass of satellite ( M ) = 3500 kg
radius of satellite ( r ) = 4.4 m
mass added by each rocket ( m ) = 220 kg
Angular speed of satellite = 32 rpm
Time = 5 mins
moment of inertia
[tex]I=1/2Mr^2+4mr^2[/tex]
M = 3500 kg m = 220 kg, r =4.4 m
I=33880+17036
Insert values into equation ( 1 )
I =20416 kg-m^2
angular acceleration
∝ = ω / t
= ( 2π×32 ) / 3600×5
= 0.0112 rad/s²
steady force required by each rocket
Τ = I × ∝ ( 1 )
T = 4rF
Equation ( 1 ) becomes
4rF = I × ∝
Force = I×∝ / 4r
= ( 228×0.0112 ) / 4×4.4
=2.56/17.6
= 0.145 N .
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2.using what you know about electricity, hypothesize about how parallel resistors would affect current flow. what would you expect the effective resistance of two equal resistors in parallel to be, compared to the resistance of one alone?
The effective resistance of two equal resistors connected in series is twice that of a single resistor, reducing the amount of current flowing in the circuit.
The effective resistance of two resistors connected in series is the sum of their individual resistances. Given two resistors with resistance values R1 and R2, the effective resistance, Rx, is given by:
Rₓ = R₁ + R₂
If the resistance values of these resistors are equal, say R, then equation 1 becomes:
Rₓ = R + R
Rₓ = 2R
That is, their effective resistance is twice as strong as their individual resistances. In other words, when two equal resistors are connected in series, their effective resistance is twice the resistance of each resistor.
Ohm's law states that voltage (V) is the product of current (I) and resistance (R) i.e.
V = IR
I = V/R
We can conclude that as resistance decreases, current increases and vice versa.
As a result, connecting the two equal resistors described above in series reduces the amount of current flowing compared to having just a single resistor.
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A submarine begins a descent from the surface downward at an angle of 40.5 degrees with the water and continues along a straight-line path for a total distance of 397.0 meters before leveling off its path. How far (in meters) is the submarine below the surface of the water?
The submarine is 288.04 meters below the surface of the water.
As we can see,
The submarine is making an angle of 40.5° with the water surface and moving down till a displacement L of 397 meters.
The displacement L moved by the submarine will have two components because displacement is a vector quantity.
One along water surface Lcos(40.5°) and one along the line perpendicular to water surface Lsin(40.5°).
The depth D of the submarine below the water surface is along the line perpendicular to the water surface.
Here,
D = Lsin(40.5°)
Value of cos 40.5°is 0.76.
So,
D = 397×0.76
D = 288.04 meters.
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air is contained in a rigid tank with a volume of 2 m3, initially at 10 bar and 300 k. heat is transferred to the tank until its temperature reaches 400 k. during this process a pressure-relief valve allows air to escape and maintain the pressure constant at 10 bar. neglecting kinetic and potential energy variation e↵ects, and using ideal gas equations with constant specific heat at 300 k, determine, (a) the mass of air that escapes the tank (in kg), and (b) the amount of heat transferred to the tank.
Mass of air that escapes the tank is M =2.8075 kg and the amount of heat transferred to the tank is Q = 1008.942 kj
In physics, mass is a numerical representation of inertia, which is a basic characteristic of all matter. The resistance a body of matter offers to a change in its speed or location as a result of the application of a force is what it is in essence. The change a force applies produces a change that is smaller the more mass a body has. The kilogramme, which is defined in terms of Planck's constant as equal to 6.62607015 1034 joule second, is the unit of mass in the International System of Units (SI). One kilogramme times one square metre per second squared is equivalent to one joule. Accurate measurements of Planck's constant are used to determine the kilogramme since the second and the metre are already defined in terms of other physical constants.When a body breaks up into fragments, the mass also breaks up into bits, thus the total mass of all the pieces equals the original mass.
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a paramecium swimming through a fluid is moving at approximately a constant velocity as a result of wiggling its cilia. what can you say about the net force that is being exerted on it while it is doing this?
In the case of a paramecium moving at a constant speed, there is no net force acting on it.
The paramecium's cilia exerts a force on water that is equal to the force that the water exerts on the paramecium's cilia, according to Newton's third law.
The strength of the viscous force the water is exerting on the paramecium will be equal to the strength of the force the paramecium's cilia are exerting on the water.
How does Paramecium use cilia?
Cilia, or tiny strands like hair, cover the whole surface of parasites like cilia, which beat rhythmically to move them and guide bacteria and other food particles into their mouths.
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The most energetic region of the electromagnetic spectrum is the microwave region. True or false?.
False. The most energetic region of the electromagnetic spectrum is NOT the microwave region. It is the Gamma rays.
What are Gamma rays?
The electromagnetic radiation with the shortest wavelength and maximum energy is known as a gamma ray. The wavelengths of gamma radiation are often less than a few tenths of an angstrom (1010 meter), yet the energy of gamma photons exceed tens of thousands of electron volts.
Gamma rays are created when radioactive atomic nuclei break apart and when certain subatomic particles decay. Pair annihilation, in which two photons are formed along with the disappearance of an electron and its antiparticle, a positron, also results in the production of gamma rays. Additionally, they can be produced when some unstable subatomic particles, such the neutral pion, decay.
Therefore, The most energetic region of the electromagnetic spectrum are gamma rays.
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