Water is formed when two hydrogen atoms bond to an oxegyn atom. When a substance is made of two or more atoms like this we call it

Answers

Answer 1

When two hydrogens and an oxygen share electrons via covalent bonds, a water molecule is formed. An example of a simple chemical reaction is the breaking down of hydrogen peroxide molecules, each of which consists of two hydrogen atoms bonded to two oxygen atoms (H2O2).

Related Questions

A coil has an inductance of 6.00 mH, and the current in it changes from 0.200 A to 1.50 A in a time interval of 0.300 s. Find the magnitude of the average induced emf in the coil during this time interval.

Answers

Answer:

0.026 V

Explanation:

Given that,

Inductance of the coil, L = 6 mH

The current changes from 0.2 A to 1.5 A in a time interval of 0.3 s

We need to find the magnitude of the average induced emf in the coil during this time interval. The formula for the induced emf is given by :

[tex]\epsilon=L\dfrac{dI}{dt}\\\\=6\times 10^{-3}\times \dfrac{1.5-0.2}{0.3}\\\\=0.026\ V[/tex]

So, the magnitude of induced emf is 0.026 volts.

Steven tries to sneak a look into the freezer to see what kind of ice cream cake he will be eating for his birthday tomorrow. Which of the following best describes what is happening when Steven opens the freezer door right before his dad catches him?
A-Heat energy flows from the kitchen to the freezer
B-Heat energy flows from the freezer to the kitchen
C- Cold energy flows from the kitchen into the freezer
D- Cold energy flows from the freezer into the kitchen​

Answers

I believe it’s B because all the air from inside is cold and heat rushes into that so I think

A uniform solid cylindrical log begins rolling without slipping down a ramp that rises 28.0° above the horizontal. After it has rolled 4.20 m along the ramp, what is the magnitude of the linear acceleration of its center of mass?

Answers

Answer:

3.07 m/s

Explanation:

The magnitude of the linear acceleration will be "3.07 m/s²".

Given:

Angle, [tex]\Theta = 28^{\circ}[/tex]Length = 2.40 m

The acceleration of its center of mass will be:

= [tex]\frac{2}{3}g Sin \Theta[/tex]

By putting the above given values, we get

= [tex]\frac{2}{3}\times 9.8 Sin 28^{\circ}[/tex]

= [tex]\frac{2}{3}\times 9.8\times 0.46[/tex]

= [tex]\frac{9.0167}{3}[/tex]

= [tex]3.07 \ m/s^2[/tex]

Thus the solution above is appropriate.

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For the common-emitter, common-base and emitter-follower amplifier designs,what is the primary benefit of each amplifier?

Answers

Answer:

Explanation:

A common emitter amplifier works by inverting. It does have low input impedance. Despite its low input impedance, it poses an otherwise high output impedance.

The common base circuit performs optimally when it acts as a current buffer. It has the ability to take an input current at a low input impedance, and transmit almost the same current to an impedance with a higher output

The primary benefit of emitter follower amplifier is that the transistor is able to provide current and power gain. Although this transistor takes in little current from the input. It still provides an impedance with a low output to a circuit by exercising the output of the follower. This then translates to that the output under load not dropping.

A. If an electron of 16 eV had a head-on collision with a Cs atom at rest, what would be the kinetic energy in eV) of the recoiling Cs atom? Assume an elastic collision. (Take the atom to be the most abundant isotope of the element. B. In a Frank-Hertz experiment, the first excited state of Hg is obtained at an accelerating voltage measured to be 4.87 V. Based on this measured value, determine the wavelength of the ultraviolet radiation you expect to be emitted.

Answers

Answer:

A) 1.96 * 10^-8 J

B) 2.55 * 10^-7 m

Explanation:

A) calculate the kinetic energy in eV of the recoiling Cs atom

we have to apply the principle of energy conservation and momentum

Initial kinetic energy of electron = 16 eV = 16 * (1.6 * 10^-19 ) J

Initial kinetic energy of atom = 0

therefore the final kinetic energy after collision ( E )

= [ 16 * ( 1.6 * 10^-19 ) ] + 0

= 1.96 * 10^-8 J

B) Determine the wavelength of the ultraviolet radiation

accelerating Voltage = 4.87 V

K.E = eV = 1.6 * 10^-19 * 4.87

next we will apply Planck's relationship

[tex]\frac{hc}{w} = KE[/tex]  ---------  ( 1 )

w = wavelength

h = 6.64 * 10^-34 J-S ( Planck's constant )

c = 3 * 10 ^8 m/sec  ( speed of light )

KE = 1.6 * 10^-19 * 4.87

substitute given values into equation 1 above

w ( wavelength ) =  2.55 * 10^-7 m

What tectonic event in the western U.S. caused magmatism and deformation to move farther into the continent during the late Mesozoic and early Cenozoic Laramide Orogeny?

a. the continent overran a hot spot
b. the continent overran the East Pacific Rise
c. continental extension stretched the continent to twice its original width
d. an oceanic plate subducted at a low angle beneath the continent

Answers

Answer:

d. an oceanic plate subducted at a low angle beneath the continent

Explanation:

The tectonic event in the western U.S. caused magmatism and deformation to move farther into the continent during the late Mesozoic and early Cenozoic Laramide Orogeny is as a result of an oceanic plate being subducted at a low angle beneath the continent.

Due to the oceanic plate being at a low angle underneath the continent it favoured the release of molten magma.

Which material will heat up the most quickly if placed near a heat source

Answers

Answer:

metal

Explanation:

metal heats up the fastest when near a hot source

A 42.6kg lamp is hanging from wires as shown in figure.The ring has negligible mass. Find tensionsT1, T2,T3 if the object is in equilibrium.

Answers

Answer:

T1 = 417.48N

T2 = 361.54N

T3 = 208.74N

Explanation:

Using the sin rule to fine the tension in the strings;

Given

amass = 42.6kg

Weight = 42.6 * 9.8 = 417.48N

The third angle will be 180-(60+30)= 90 degrees

Using the sine rule

W/Sin 90 = T3/sin 30 = T2/sin 60

Get T3;

W/Sin 90 = T3/sin 30

417.48/1 = T3/sin30

T3 = 417.48sin30

T3 = 417.48(0.5)

T3 = 208.74N

Also;

W/sin90 = T2/sin 60

417.48/1 = T2/sin60

T2 = 417.48sin60

T2 = 417.48(0.8660)

T2 = 361.54N

The Tension T1 = Weight of the object = 417.48N

Consider a one-dimensional crystal (similar to a carbon nanowire) with length 10 um and lattice spacing 0.1 nm.

RequireD:
a. What is the Fermi level assuming one electron per atom?
b. What is the density of states as a function of electron energy?

Answers

Answer:

a)  Fermi level = 600 electron-volts

b) [tex]\frac{2.04 * 10^{13} }{\sqrt{E} }[/tex]

Explanation:

Given data:

length of one-dimensional crystal = 10 um

Lattice spacing = 0.1 nm

A) Determine the Fermi level assuming one electron per atom

Total length = 10 um

Interatomic separation of a = 0.1 nm

in this case the Atom has one electron therefore the number of electrons = 10^5  and the number of states Ns = gsN = 2 * 10^5  ( attached below is some part of the solution )

hence : Fermi level = 600 electron-volts

B) Determine the density of states as a function of electron energy

attached below is the detailed solution

PLEASE HELP!!


1.The Law of Conservation of Energy states that?

A. matter cannot be created or destroyed, only stored and transferred.

B. momentum cannot be created or destroyed, only stored and transferred.

C. energy cannot be created or destroyed, only stored and transferred.


2.The total amount of kinetic and potential energy in a system that remains constant is the system's


A .mechanical energy

B. elastic energy

C. chemical energy

D. gravitational energy


3, At the top of a giant hill sits a roller coaster cart, all the energy of the cart is stored as


A. kinetic energy

B. chemical energy

C. elastic energy

D. gravitational potential energy



4. At the bottom of the hill (ground level), the roller coaster cart in the previous problem, all the energy of the cart is stored as


A. kinetic energy

B. chemical energy

C. elastic energy

D. gravitational potential energy





When a pendulum swings when will the potential energy be at a maximum?

A
B
C
D

6. If total mechanical energy = kinetic energy + potential energy, TME = KE + PE, and a roller coaster has 500 J of total mechanical energy. At the very beginning of the track the roller coaster has 500 J of potential energy, how much kinetic energy is there at the beginning of the track?



A 25 kg child is sitting at the top of a 4 m tall slide, what is his potential energy?




It the same child has a velocity of 2 m/s half-way down the slide, what is his kinetic energy?



If the TME energy for the same child on the slide is 100 J, how much potential energy does the child have half-way down the slide?

Answers

Answer:

A

A

D

D

when the pendulum is at the lefend and right end.

0 because kinetic energy is only formed when a moving object is moving.

dont know the others sorry

Explanation:

i got about half way for you hope it correct

give me nothing if you got some wrong!

or just give me a message saying that i didn't help

Two light bulbs have resistances of 400Ω and 800Ω. The two light bulbs are now connected in parallel across the 120-V line. A. Find the current through each bulb.B. Find the power dissipated in each bulb. C. Find the total power dissipated in both bulbs.

Answers

Answer:

a.) O.3A and 0.15A

b.) P1 = 36W, P2 = 18W

c.) 54W

Explanation:

Constant resistance R1 = 400 ohms, R2 = 800 ohms

a.)

The current through each bulb

While in parallel.

I = 120/800/3

= 0.45A

For 400= 800/400+800

= 800/1200 x 0.45

= 0.3A

I-800 = 400 /400+800

= 400/1200*0.45

= 0.15A

B.)

The power dissipated in each bulb

P409 = I²400r

= 0.3A²x400 ohms

= 36 W

P800 = I²800R

= 0.15A²*800 ohms

= 18W

C.)

The total power dissipated

= 36W + 18 W

= 54W

A 20-kg child is coasting at 3.3 m/s over flat ground in a 4.0-kg wagon. The child drops a 1.0-kg ball out the back of the wagon. What is the final speed of the child and wagon?

Answers

Answer:

The final velocity is [tex]u_f = 3.44 \ m/s[/tex]

Explanation:

From the question we are told that

    The mass of the child is  [tex]m_1 = 20 \ kg[/tex]

    The initial  speed  of the child is  [tex]u_1 = 3.3 \ m/s[/tex]

    The mass of the wagon is  [tex]m_w = 4.0 \ kg[/tex]

    The  initial  speed of the wagon is [tex]u_w = 3.3 \ m/s[/tex]

    The mass of the ball is  [tex]m_2 = 1.0 \ kg[/tex]

    The initial speed off the ball  is  [tex]u_2 = 3.3 \ m/s[/tex]

Generally the initial  speed of the system (i.e the child , wagon ,  ball) is  

          [tex]u_1 = u_w = u_2 = u =3.3 \ m/s[/tex]

Generally from the law of linear momentum conservation

    [tex]p_i = p_f[/tex]

Here [tex]p_i[/tex]  is the momentum of the system before the ball is dropped which is mathematically represented  as

      [tex]p_i = ( m_1 + m_2 + m_3 ) * u[/tex]

=>   [tex]p_i = ( 20 + 4 + 1 ) * 3.3[/tex]

=>   [tex]p_i = 82.5 \ kg \cdot m/s[/tex]

and  

       [tex]p_f[/tex]  is the momentum of the system after the ball is dropped which is mathematically represented  as  

       [tex]p_f = ( m_1 + m_w ) * u_f[/tex]

=>   [tex]p_i = ( 20 + 4 ) * u_f[/tex]

So

     [tex]82.5 = 24 * u_f[/tex]

=>   [tex]u_f = 3.44 \ m/s[/tex]

   

A child wants to throw a rock upward to try to strike a plump apple up in a
tree. If the fastest the child can throw the rock is 7 m/s, what is the highest
the apple can be in order for the child to be able to strike the apple?

Answers

Answer:

7m because that is the height that the child can throw.

Red light of wavelength 633 nm from a helium-neon laser passes through a slit 0.400mm wide. The diffraction pattern is observed on a screen 3.35 m away. Define the width of a bright fringe as the distance between the minima on either side.

(a) What is the width of the central bright fringe?

(b) What is the width of the first bright fringe on either side of the central one?

Answers

Answer:

a)[tex]y_{first}=5.3mm[/tex]

b)[tex]y_{second}=10.6-5.3 =5.3 mm[/tex]  

Explanation:

a)

The width of the central bright in this diffraction pattern is given by:

[tex]y=\frac{m\lambda D}{a}[/tex] when m is a natural number.

here:

m is 1 (to find the central bright fringe)                 D is the distance from the slit to the screen a is the slit wide λ is the wavelength

So we have:

[tex]y_{first}=\frac{633*10^{9}*3.35}{0.0004}[/tex]

[tex]y_{first}=5.3mm[/tex]

b)

Now, if we do m=2 we can find the distance to the second minima.

[tex]y_{2}=\frac{2*633*10^{9}*3.35}{0.0004}[/tex]

[tex]y_{2}=10.6 mm[/tex]

Now we need to subtract these distance, to get the width of the first bright fringe :

[tex]y_{second}=10.6-5.3 =5.3 mm[/tex]    

I hope it heps you!

     

In a liquid metal fast breeder reactor, no neutron moderation is desired and sodium is used as a coolant to minimize fission-neutron thermalization. How many elastic scatters with sodium, on the average, would it take for 2-MeV neutrons to reach an average thermal energy of 0.025 eV?

Answers

Answer:

219 scatterings

Explanation:

Given that:

The Coolant used In the liquid metal fast breed reactor = Sodium

The atomic weight (A) of sodium = 23

The initial energy [tex]E_{i}[/tex] = 2 - MeV

The final energy [tex]E_{f}[/tex] = 0.025 eV  (thermal energy)

The number of elastic neutron scatterings (n) needed to reach the given average thermal energy can be computed as:

[tex]n = \dfrac{log \bigg(\dfrac{E_f}{E_i} \bigg)}{log \bigg [ \dfrac{A^2+1}{(A+1)^2} \bigg]}[/tex]

[tex]n = \dfrac{log \bigg(\dfrac{0.025}{2 \times 10^6} \bigg)}{log \bigg [ \dfrac{23^2+1}{(23+1)^2} \bigg]}[/tex]

[tex]n = \dfrac{log \bigg(1.25\times 10^{-8} \bigg)}{log \bigg [ 0.92014\bigg]}[/tex]

[tex]n = 218.643[/tex]

n ≅ 219 scatterings

In a mercury barometer at atmospheric pressure, the height of the column of mercury in a glass tube is 760 mm. If another mercury barometer is used that has a tube of larger diameter, how high will the column of mercury be in this case?

a. greater than 760 mm
b. Less than 760 mm
c. equal to 760 mm

Answers

Answer:

c. equal to 760 mm

Explanation:

We are told that another mercury barometer is used that has a tube of larger diameter. This means a larger area and the weight of the liquid in the tube will have increased since volume = area × height. Also, due to the larger area, the net upward force on the mercury will have also increased by the same amount because force = area × pressure. Therefore, as long as the pressure remains the same, the height of the mercury will also remain the same.

Thus the height of the mercury = 760 mm

A centrifuge accelerates uniformly from rest to 15000 rpm in 330 s . Through how many revolutions did it turn in this time?

Answers

Answer:

The number of revolutions turned by the centrifuge is 8250 revolutions.

Explanation:

Given;

number of revolution per minutes, ω = 15000 rpm

time of  motion, t = 330 s = 5.5 minutes

The number of revolutions turned by the centrifuge is given by;

[tex]N = \frac{1500 \ Rev}{minutes} *5.5 \ minutes\\\\N = 8250 \ revolutions[/tex]

Therefore, the number of revolutions turned by the centrifuge is 8250 revolutions.

how does the law of conservation energy relate to the system shown in thos model

Answers

Answer:

there is no model shown

Explanation:

Therefore it can be thousands of different answers

An athlete whirls a 6.41 kg hammer tied to the end of a 1.3 m chain in a simple horizontal circle where you should ignore any vertical deviations. The hammer moves at the rate of 1.64 rev/s. What is the centripetal acceleration of the hammer

Answers

The chain makes a circle of radius 1.3 m as it spins, so that 1 revolution of the hammer amounts to it moving a linear distance of 2π (1.3 m) = 2.6π m. Then the hammer's linear speed is

(1.64 rev/s) • (2.6π m/rev) = 4.264π m/s

and so the centripetal acceleration has magnitude

a = v²/r = (4.264π m/s)² / (1.3 m)

a ≈ 140 m/s²

Is clinical depression associated with eating disorders yes or no

Answers

yes it can clinical depression and eating disorders usually go one on one with each other each type of disorder goes one on one with each other

Yes, a symptom of depression is a loss of appetite, and eating disorders are often developed as a result of an unhealthy coping mechanism with life; therefore, people with depression can get eating disorders and vice versa. They go hand in hand.

For the winter, a duck flies 10.0 m/s due south against a gust of wind with a velocity of 2.5 m/s. What is the resultant velocity of the duck?

a. 12.5 m/s south
b. 12.5 m/s north
c. 7.5 m/s south
d. 7.5 m/s north
e. 10.3 m/s south

Answers

Answer:

c. 7.5 m/s south

Explanation:

Given the following data;

Velocity of duck = 10m/s due South

Velocity of wind = 2.5m/s

To find the resultant velocity;

Since we know that the duck is flying against a gust of wind, we would have to subtract the velocity of the gust of wind from that of the duck.

This ultimately implies that, the gust of wind (headwind) would decrease the resulting velocity of the duck because it approaches the duck from the front.

Resultant velocity, /V/ = 10 - 2.5

Resultant velocity, /V/ = 7.5m/s South.

Therefore, the resultant velocity of the duck is 7.5m/s south.

As friction with our atmosphere causes a satellite to spiral inward, closer to Earth, its orbital speed increases. Why?

Answers

Answer:

Explanation:

When we go back and look at Kepler's third law. Kepler's third law states that "the square of the period is proportional to the cube of the semi-major axis of the orbit". P²µa³

where a is the semi-major axis of orbit,

P is the period of orbit

The orbit in question is the distance from the center of Earth. If the satellite spirals in as a result of air friction, then it decreases and, so does P.

Note that P = 2πa / V or Vµ1 / a0.5 .

From the formula, we can see that a decrease in the value of a, will lead to an Increase in the value of V.

5. Salt is often spread on roads during winter to prevent ice from forming. Do you think sugar would
work as well? Explain your answer.

Answers

Answer:

No because sugar is more sweet and it would not have the benefits of salt. Think of it like how people used to put salt on meat to preserve it. Would they put sugar on? No they would not because salt is a combination of things that sugar does not have.

Explanation

How fast would a(n) 85 kg man need to run in order to have the same kinetic energy as an 8.0 g bullet fired at 410 m/s?

Answers

Answer:

V = 3.97 m/s

Explanation:

Mass of a man, M = 85 kg

Mass of a bullet, m = 8 g = 0.008 kg

Speed of bullet, v = 410 m/s

We need to find the speed of a man in order to have the same kinetic energy as that of the bullet. Let the kinetic energy of the bullet is k. So,

[tex]k=\dfrac{1}{2}mv^2\\\\k=\dfrac{1}{2}\times 0.008\times 410^2\\\\k=672.4\ J[/tex]

Since, k = K (K is the kinetic energy of the man and Let V is the speed)

[tex]K=\dfrac{1}{2}MV^2\\\\V=\sqrt{\dfrac{2K}{M}} \\\\V=\sqrt{\dfrac{2\times 672.4}{85}} \\\\V=3.97\ m/s[/tex]

So, the speed of the man is 3.97 m/s.

We have that for the Question "How fast would a(n) 85 kg man need to run in order to have the same kinetic energy as an 8.0 g bullet fired at 410 m/s?" it can be said that the speed is

v=4.0m/s

From the question we are told

How fast would a(n) 85 kg man need to run in order to have the same kinetic energy as an 8.0 g bullet fired at 410 m/s?

Generally the equation for the kinetic energy  is mathematically given as

[tex]K.E=1/2*m*v^2\\\\Therefore\\\\K.E=1/2*0.008*(420)^2\\\\K.E=672.4J\\\\[/tex]

Therefore

[tex]v^2=\frac{672.4*2}{85}\\\\v^2=15.821[/tex]

v=4.0m/s

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An object in motion, will tend to remain in motion until acted upon my an external, unbalanced force is defined to be

Answers

Answer:

The first law states that a body at rest will stay at rest until a net external force acts upon it and that a body in motion will remain in motion at a constant velocity until acted on by a net external force. Inertia is the tendency of a body in motion to remain in motion.

Explanation:

What is the acceleration due to gravity on a planet with a mass of 4.76x10^23 kg and a radius of 2,635,000 meters? Report your answer to three digits and include the units. (Ex: 7.15 m/s/s).​

Answers

Answer:

g=4.5727 m/s^2

Explanation:

[tex]We\ know\ that\ , \\F=G\frac{Mm}{d^2} \\As\ F=ma\ and\ a=g\ (g\ is\ the\ acceleration\ caused\ due\ to\ gravity),\\mg=G\frac{Mm}{d^2}\\Canceling\ m\ on\ both\ sides\ we\ get,\\g=G\frac{M}{d^2}\\[/tex]

[tex]We\ are\ given\ that\ ,\\Mass\ of\ the\ planet\ (M) = 4.76*10^{23} kg\\Distance(d) = 2,635,000 m\\G(Universal\ Gravitation\ Constant) = 6.67*10^{-11}\\Hence,\\g=6.67*10^{-11} (\frac{4.76*10^{23}}{2,635,000^2} )\\g= 4.5727 m/s^2[/tex]

A drop of water dripping from the faucet in your kitchen is electrically neutral. A charged plastic hair comb can attract the drips and drops by the process of __________________.

Answers

Answer:

Polarizatión

Explanation:

Polarization is that property of waves that particular to transverse waves. Ir specifies the geometrical orientation of the oscillations. In transverse waves, the direction of the oscillation is often at perpendicular with respect to the direction of motion of the wave itself.

Again, it can be called the property of electromagnetic radiations to which the direction and magnitude of the vibrating electric field are related in a particular way.

most elements in nature exist as mixture of two or more isotopes
t or f

Answers

Answer:

Atomic mass is a value that depends on the distribution of an element's isotopes in nature and the masses of those isotopes. Circle the letter of each sentence that is true about a carbon-12 atom. ... Most elements exist as a mixture of two or more isotopes.

So the answer is true.

Thank you and please rate me as brainliest as it will help me to level up

Developing a question for appointments

Answers

Explanation:

how can I help you that?

Suppose a rocket is traveling through space and moving at a speed close to the speed of light. Three minutes pass on the rocket as recorded by an observer on Earth.

How many minutes pass on Earth?

less than three minutes because of time dilation
more than three minutes because of time dilation
three minutes because time is absolute
less than or greater than three minutes depending on the speed

Answers

Answer:

B

Explanation:

on edge2020

Three minutes pass on the rocket as recorded by an observer on Earth will be more than three minutes because of time dilation. The correct option is B.

What is time dilation?

It is a phenomenon a slowing of time according to the theory of relativity when a system is in motion relative to an outside observer and that becomes apparent when the speed of the system approaches that of light is known as time dilatation.

The time dilation results in Three minutes passing on the rocket as recorded by an observer on earth will be more than three minutes.

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