Tyler has 500 counters in a bag.
He gives
15 of the counters to Sam
52 of the counters to Peter
43 of the counters to Lakhdar

What fraction of the 500 counters is left in Tyler's bag?
Give your fraction in its simplest form.

Answer:

22

Step-by-step explanation:

Answer:

9/25

0.36

Step-by-step explanation:

Part 1:

You divide 36 by 100 to find the fraction:

36/100

Then, simplify:

36/100 = 9/25

.................................................................................

Part 2:

To find the decimal of a percentage, divide the percent by 100. When dividing by 100, you get the answer by moving the decimal point two spaces to the left.

36% = 0.36

Answer:

-15x - 3

I hope this helps :)

The change in the price level from the first to the second month is 106.4

Price index: Price index, measure of relative price changes, consisting of a series of numbers arranged so that a comparison between the values for any two periods or places will show the average change in prices between periods or the average difference in prices between places.

A college student purchases 4 movie tickets for $7 each, 2 CDs for $13 each, and 20 gallons of gasoline at $2 a gallon during the base period.

Gas will cost $2.25 per gallon in the upcoming month, CDs will cost $12.50 each, and cinema tickets will cost $7.50

The price index

=(price in current year/price in last year) x 100

=100/94 x 100

=106.38 or 106.4

The change in the price level from the first to the second month is 106.4

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Equivalent ratios are the ratios that are the same when we compare them. Three equivalent ratios are 1/2, 4/8, 3/6 in digits from 1 to 9.

A ratio is an ordered pair of numbers a and b, written a / b where b does not equal 0. A proportion is an equation in which two ratios are set equal to each other

Equivalent ratios are the ratios that are the same when we compare them.

The digits from 1 to 9 include 1,2,3,4,5,6,7,8,9.

Ratios are nothing but fractions.

Let 1/2 (one by two) is the first ratio.

Now 3/6 (three by six) is the second ratio

4/8 (four by eight) is the third ratio.

If we calculate the value of 1/2 = 0.5

The value of  3/6=1/2=0.5

The value of 4/8= 1/2=0.5

we get the same answer for all the ratios 1/2, 4/8 and 3/6 that is 0.5

That is 0.5 or 1/2.

Hence the three equivalent ratios are 1/2, 4/8, 3/6.

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Answer:

C

Step-by-step explanation:

[tex]\frac{8}{12} \times 100 \approx 67[/tex]

Answer:

I think it's 171.5 in^3 but not sure :)

Step-by-step explanation:

Step-by-step explanation:

the area of the parallelogram is

baseline × height.

we know the baseline (15 cm), because as parallelogram it must have 2 pays off equal sides. so, the bottom side must be 15 cm too.

15×height = 390

height = 390/15 = 26 cm

now, the height of the triangle on the right is the same height.

and the baseline of this triangle is 25 - 15 = 10 cm.

the area of a triangle is

baseline × height / 2

so, in our case

10 × 26 / 2 = 10×13 = 130 cm²

therefore the area of the trapezium is the area of the parallelogram plus the area of the triangle :

390 + 130 = 520 cm²

Answer:

x < 7/3

Step-by-step explanation:

[tex] - 5 < 9 - 6x[/tex]

[tex] - 14 < - 6x[/tex]

[tex] \frac{7}{3} > x[/tex]

[tex]x < \frac{7}{3} [/tex]

Answer:

A answer is A brainly helps you

The total weight is 57kg

The perimeter = 2×(8+6)

= 2(14) = 28m

The diagonal = √8²+6²

= √64+36

100 = 10m

The total length of the frame =

28+10 = 38 m

Therefore the total Weight =

38× 1.5 kg = 57 kg

What is the formula for weight?

The force of gravity acting on an item is known as its weight, and it can be determined using the formula w = mg, which equals the mass times the acceleration of gravity.

You must multiply the sectional area, length, and density collectively to determine the weight of your metal. The product must then be divided by 1,000 in order to convert the weight to kilograms. There are several online metal weight calculators that you may use to figure out the weight of your metal product.

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The classification of the numbers as counterexamples of the conjecture is given as follows:

The next number in the sequence is of 256.

The conjecture is defined as follows:

"Any number divisible by 2 is also divisible by 4"

Hence the counterexamples are the numbers that are divisible by 2 but not by 4, then they are classified as follows:

Each number in the sequence is given by the multiplication of the two previous terms, as:

Then the next number is calculated as follows:

32 x 8 = 256.

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[tex] \frac{v}{8} - 4 = - 12 \\ \frac{v}{8} = - 12 + 4 \\ \frac{v}{8} = - 8[/tex]

Now I will use CROSS MULTIPLICATION

[tex]v = 8( - 8) \\ v = -6 4[/tex]

ATTACHED IS THE SOLUTION

Answer: v/8 - 4 = (-12)

-12 + 4 = (-8)

what divided by 8 is 8?

8/8 = 1 so 8 x 8 = 64

this means v = -64

64/8 - 4 = -12

- 64/8 is -8 and that minus 4 is -12

The original price of the jacket before sale amount is $45.

Original price of the jacket will be calculated by forming the expression relating mentioned price. Let us assume the original price of the jacket to be x.

Writing the equation representing original price, percentage and price after sale

80%×x = 36

Converting percentage to fraction

80/100×x = 36

Shifting the fraction to Right Hand Side of the equation

x = 36×100/80

Cancelling zero as it is common in numerator and denominator and performing division

x = 45

Therefore, according to the sale price, the original price of jacket is $45.

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Given: A table that shows the result of a survey from 35 randomly selected students at Courtney's school.

Required: To determine the number of votes Rockzilla is expected to receive from a population of 115 students at Courtney's school.

This is achieved thus:

First, we determine the probability of Rockzilla's votes as follows:

Next, we determine the number of votes Rockzilla is expected to receive as follows:

Hence, the answer is:

[tex]|x-4|[/tex] is non-negative, and vanishes when [tex]x=4[/tex].

For all [tex]x\in[-2,1][/tex], we have [tex]x<4[/tex], so by definition of absolute value,

[tex]g(x) = |x-4| + 8 = -(x-4)+8 = -x+4[/tex]

which is strictly decreasing on [-2, 1] since [tex]g'(x)=-1<0[/tex]. Then the minimum value of [tex]g[/tex] on [-2, 1] occurs at the endpoint [tex]x=1[/tex], so that

[tex]\min\left\{g(x) \mid -2\le x\le1\right\} = g(1) = |1-4| + 8 = \boxed{11}[/tex]

Answer:

20% off is better and it is the only offer which is under the budget.

20% off of the $1,500 dining set is $300, and the dining set price will be 1500 - 300 = $1200.

And by applying the $150 coupon, the dining set price will be $1500 - $150 = $1350.

Therefore 20% off is better and it is the only offer which is under the budget.

Step-by-step explanation:

Answer:

D. 9x² - 12x - 1

Explanation:

To find f(g(x)), we need to replace x by g(x) as follows:

f(x) = x² - 5

f(g(x)) = (g(x))² - 5

Then, g(x) is equal to -3x + 2, so replacing g(x) by (-3x + 2), we get:

f(g(x)) = (g(x))² - 5

f(g(x)) = (-3x + 2)² - 5

f(g(x)) = (-3x)² + 2(-3x)(2) + 2² - 5

f(g(x)) = 9x² - 12x + 4 - 5

f(g(x)) = 9x² - 12x - 1

Therefore, the answer is D. 9x² - 12x - 1

Answer:

Sometimes, Never, and Always.

(Sounds like a good movie title).

Step-by-step explanation:

See attached image.

The equality of the respective angles and the proportionality of the corresponding sides determine if two triangles are comparable.

Triangle A: 53, 71, Triangle B: 53, 71; Similar

Triangle C: 90, 37, Triangle D: 90, 53; Similar

Triangle E: 63, 45 Triangle F:14, 71; Not similar

Triangle G, 121, Triangles H: 70, Not similar

If two of one triangle's angles are congruent with two of the

angles of a different triangle, then the two triangles are comparable.

Similarity hypothesis, angle, and AA

Given that: The interior product of the AA similarity hypothesis

The angle sum property of a triangle states that the angles of a triangle are 180°,

Consequently, the third angle is also congruent when two angles are

congruent

53, 71 in Triangle A and 53, 71 in Triangle B; similar

Based on the AA similarity postulate, the triangles are similar.

Triangles C (90, 37) and D (90, 53) have similar angles.

Supplied that the given angles are identical to each of their complimentary angles, the triangle is similar.

Triangle F: 14, 71 Triangle E: 63, 45; not comparable

There are no parallel triangles.

Triangles H: 70, not identical to Triangle G's 121,

The details are insufficient.

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An expression is a collection of variables and constants that are bound by some mathematical operation the value for w for the given expression w -5.36=10+w/6 is 18.432.

A mixture of variables, numbers, addition, subtraction, multiplication, and division are called expressions.

A statement expressing the equality of two mathematical expressions is known as an equation.

As per the given expression,

w - 5.36 = 10 + w/6

Subtract w/6 both sides,

w - w/6 - 5.36 = 10 + w/6 - w/6

5w/6 = 10 + 5.36

w = 18.432

Hence "The value for w for the given expression w -5.36=10+w/6 is 18.432".

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Answer:  36 copies per minute

Step-by-step explanation:

126 copies in 3.5 minutes

We want x number of copies per 1 minute

[tex]\frac{126copies}{3.5minutes} = \frac{xcopies}{1minute}[/tex]

Cross multiply and we get

126 = 3.5x

Solve for x.

x = 126/3.5

x = 36

36 copies per minute

The total amount of money collected if Anya and Lauren sold their mangoes at $15 is $10,350

= 575 mangoes

Total number of mangoes = Number of mangoes Anya has + Number of mangoes Lauren has

= 115 + 575

= 690 mangoes

Amount each mangoes was sold = $15

Total amount of money collected = Total number of mangoes × Amount each mangoes was sold

= 690 × 15

= $10,350

So therefore, Anya and Lauren sold their total mangoes for $10,350

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Given the equation of a parabola:

• You can rewrite it in Standard Form by following these steps:

1. Add the y-term to both sides of the equation:

2. Subtract the Constant Term from both sides of the equation:

3. Divide both sides of the equation by 5 (the leading coefficient)

4. The coefficient of the x-term is:

Then, you need to add this value to both sides:

Therefore.

5. Rewrite the equation as follows:

• Having the equation written in Standard Form:

You can identify that:

Solving for "p", you get:

• You can identify that:

Therefore, the Vertex is:

• By definition, the Focus of a parabola that opens upward is given by:

Then, in this case, this is:

• By definition, the Directrix for a parabola that opens upward is given by:

Then, in this case, you get:

Hence, the answers are:

• Standard Form:

• Value for "p":

• Vertex:

• Focus:

• Directrix:

Answer:

[tex]1) \:\:\: \dfrac{14x}{y}[/tex]

[tex]2) \:\:\:\dfrac{16x^2}{9y^2}[/tex]

[tex]3)\:\:\:10[/tex]

[tex]4)\:\:\:\dfrac{x-2}{x+4}[/tex]

Step-by-step explanation:

I will provide detailed explanation for the first problem and quicker steps to solve the others. You should be able to figure them out

Dividing a number(integer or fraction) by a fraction is equivalent to multiplying that number by the reciprocal of the divisor fraction

So if you have an expression
[tex]\dfrac{a}{b} \div \dfrac{c}{d}\\\\\implies \dfrac{a}{b} \times \dfrac{d}{c}[/tex]

Question 1

[tex]\dfrac{14x^5}{5y^2}\:\div \dfrac{2x^4}{10y}\\\\= \dfrac{14x^5}{5y^2} \times \dfrac{10y}{2x^4}\\\\[/tex]

[tex]=\dfrac{14x^5\cdot \:10y}{10y^2x^4}[/tex]

10 in the numerator and 10 in the denominator cancel:

[tex]=\dfrac{14x^5y}{y^2x^4}[/tex]

[tex]\dfrac{x^5}{x^4} = x^{5-4} = x \;\;\;\;\;\;\text{Since }\dfrac{x^a}{x^b}=x^{a-b}}[/tex]

Likewise

[tex]\dfrac{y}{y^2} = y^{1-2} = y ^{-1} = \dfrac{1}{y}[/tex]

Therefore
[tex]=\dfrac{14x^5\cdot \:10y}{10y^2x^4} = 14 \dfrac{x}{y} = \dfrac{14x}{y}[/tex]
Answer: Question 1

Question 2

[tex]\left(\dfrac{x}{y}\right)\left(\dfrac{4y}{3x}\right)\:\div \dfrac{6y^2}{8x^2}[/tex]

[tex]\dfrac{x}{y} \cdot \dfrac{4y}{3x} = \dfrac{4}{3}[/tex]

[tex]\dfrac{6y^2}{8x^2} = \dfrac{4y^2}{3x^2}[/tex]'

[tex]\left(\dfrac{x}{y}\right)\left(\dfrac{4y}{3x}\right)\:\div \dfrac{6y^2}{8x^2} \\\\= \dfrac{4}{3} \times \dfrac{3x^2}{4y^2}\\\\= \dfrac{16x^2}{9y^2}[/tex]

Question 3

[tex]\dfrac{\left(5\left(y+6\right)\right)}{2\left(xy-3\right)}\:\div \dfrac{\left(y\:+\:6\right)}{4\left(xy\:-\:3\right)}\\\\\\\dfrac{5(y + 6)}{2(xy-3)} \times \dfrac{4(xy-3)}{y+ 6}\\\\[/tex]

The y + 6 terms cancel out from numerator and denominator as do the xy - 3terms

[tex]= \dfrac{5}{2} \times \dfrac{4}{1}\\\\= \dfrac{20}{2} \\\\= 10[/tex]

Question 4

[tex]\dfrac{x^2-4}{x^2+5x+4}\:\div \dfrac{x+2}{x+1}\\\\=\dfrac{x^2-4}{x^2+5x+4}\:\times \dfrac{x+1}{x+2}[/tex]

[tex]x^2-4 = (x + 2)(x-2) \;\;\;\; \text{Since $a^2-b^2 = (a +b)(a-b)$}[/tex]

[tex]x^2 + 5x + 4\;\;\; \text{can be factored as: }\\\\(x + 1)(x + 4)[/tex]

Therefore
[tex]\dfrac{x^2-4}{x^2+5x+4}\:\div \dfrac{x+2}{x+1}\\\\\\=\dfrac{x^2-4}{x^2+5x+4}\:\times \dfrac{x+1}{x+2}\\\\\\= \dfrac{(x+2)(x-2)}{(x+1)(x+4)} \times \dfrac{x+1}{x+2}\\\\\\\\[/tex]

The x+2 terms cancel out as do the x + 1 terms giving the result
[tex]\dfrac{x-2}{x+4}[/tex]

Answer:

[tex]\textsf{1. \quad $\dfrac{14x}{y}$}[/tex]

[tex]\textsf{2. \quad $\dfrac{16x^3}{9y^2}$}[/tex]

[tex]\textsf{3. \quad $10$}[/tex]

[tex]\textsf{4. \quad $\dfrac{x-2}{x+4}$}[/tex]

Step-by-step explanation:

When dividing two fractions, multiply the first fraction by the reciprocal of the second fraction.  

The reciprocal of a fraction is its inverse (swap the numerator and denominator).

[tex]\boxed{\begin{minipage}{3 cm}\underline{Exponent Rules}\\\\$\dfrac{a^b}{a^c}=a^{b-c}$\\\\$a^{-n}=\dfrac{1}{a^n}$\\\end{minipage}}[/tex]

[tex]\begin{aligned}\dfrac{14x^5}{5y^2} \div \dfrac{2x^4}{10y} & = \dfrac{14x^5}{5y^2} \times \dfrac{10y}{2x^4}\\\\& = \dfrac{14x^5 \times 10y}{5y^2\times 2x^4}\\\\& = \dfrac{140x^5y}{10x^4y^2}\\\\& = \dfrac{14x^5y}{x^4y^2}\\\\& = 14x^{5-4}y^{1-2}\\\\& = 14x^1y^{-1}\\\\& = \dfrac{14x}{y}\end{aligned}[/tex]

------------------------------------------------------------------------------------------

[tex]\begin{aligned}\left(\dfrac{x}{y} \right)\left(\dfrac{4y}{3x} \right) \div \dfrac{6y^2}{8x^3}&=\dfrac{4xy}{3xy} \div \dfrac{6y^2}{8x^3}\\\\&=\dfrac{4}{3} \div \dfrac{6y^2}{8x^3}\\\\&=\dfrac{4}{3} \times \dfrac{8x^3}{6y^2}\\\\&=\dfrac{4 \times 8x^3}{3 \times 6y^2}\\\\&=\dfrac{32x^3}{18y^2}\\\\&=\dfrac{16x^3}{9y^2}\end{aligned}[/tex]

------------------------------------------------------------------------------------------

[tex]\begin{aligned}\left[\dfrac{5(y+6)}{2(xy-3)} \right] \div \left(\dfrac{y+6}{4(xy-3)}\right) & = \left[\dfrac{5(y+6)}{2(xy-3)} \right] \times \left(\dfrac{4(xy-3)}{y+6}\right)\\\\& = \dfrac{5(y+6) \times 4(xy-3)}{2(xy-3) \times (y+6)}\\\\& = \dfrac{20(y+6)(xy-3)}{2(xy-3)(y+6)}\\\\& = \dfrac{20}{2}\\\\&=10\end{aligned}[/tex]

------------------------------------------------------------------------------------------

Factor the numerator and denominator of the first fraction.

Apply the Difference of Two Squares to the numerator:

[tex]\implies x^2-4=x^2-2^2=(x-2)(x+2)[/tex]

Factor the denominator:

[tex]\begin{aligned}\implies x^2+5x+4 & =x^2+x+4x+4\\ & =x(x+1)+4(x+1)\\ & =(x+1)(x+4)\end{aligned}[/tex]

Therefore:

[tex]\begin{aligned}\left(\dfrac{x^2-4}{x^2+5x+4}\right) \div \left( \dfrac{x+2}{x+1} \right) & = \left(\dfrac{x^2-4}{x^2+5x+4}\right) \times \left( \dfrac{x+1}{x+2} \right)\\\\& = \left( \dfrac{(x-2)(x+2)}{(x+1)(x+4)} \right) \times \left( \dfrac{x+1}{x+2} \right)\\\\& = \dfrac{(x-2)(x+2)(x+1)}{(x+1)(x+4)(x+2)}\\\\& = \dfrac{x-2}{x+4}\\\\\end{aligned}[/tex]

Using algebra, we know that the total number of bees in her hive is 540.

So,

Then,

(A) Work out an estimate for the total number of bees in her hive

The estimated total no. of bees will be 540 bees.

Therefore, using algebra, we know that the total number of bees in her hive is 540.

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Answer:

The answer is 5(30+2)!

Answer:

#7 m∠4 = 30°  

#8. m∠5 = 150

#22. A'(-6, -3), B'(-3, 4), C'(3, 5)
*** You may just want to put the coordinate points: (-6, -3), (-3, 4), (3, 5) without the A', B', C'. ***

#23. A'(6, -3), B'(3, 4), C'(-3, 5)

Step-by-step explanation:

#7 Angles 30° and ∠4 are corresponding angles and hence equal

#8 ∠4 and ∠5 are supplementary linear angles and add up to 180° So m∠5 = 180 - m∠4 = 180 - 30 = 150°

#22 Reflection about the x-axis means the x-coordinates do not change but the new y-coordinate is the negative of the original y coordinate

In other words, a point(x, y) in the pre-image becomes (x, -y) in the image

#23 With a 180° rotation both x and y axes change signs. (x, y) becomes (-x, -y)

The foci of the given ellipse are (D) (0, 5) and (0, -5).

So, the foci of the ellipse are:

(Refer to the graph attached below)

Therefore, the foci of the given ellipse are (D) (0, 5) and (0, -5).

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The correct question is shown below:

Which are the foci of the ellipse represented by 25x² + 16y² = 400?

A. (-3,0) and (3, 0)

B. (-5, 0) and (5, 0)

C. (0, 3) and (0, -3)

D. (0, 5) and (0, -5)