Given the function of the rate of change of the population:
[tex]P(t)=200e^{0.02t}[/tex]The integral of this function will be the value of the population growth of the town from 1990 to 2010. This is because P(t) is the rate of change of population, its integral will be the antiderivative, that is the population of the town.
To calculate the change in population we have to find the integral from 5 to 10 of P(t):
[tex]\begin{gathered} \int_5^{10}200e^{0.02t}dt \\ 200\int_5^{10}e^{0.02t}dt \\ 200\cdot\frac{e^{0.02t}}{0.02} \\ 10000e^{0.02t} \\ (10000e^{0.02(10)})-(10000e^{0.02(5)}) \\ 1162.3 \end{gathered}[/tex]The change in population can not be a decimal number, so we can round it to 1162.
To calculate the population in 2020 we have to find the integral from 0 to 30 of P(t) and then add it to 10000 which was the initial population (we already know the integral so we're just going to evaluate it):
[tex]\begin{gathered} 10000e^{0.02(30)}-10000e^{0.02(0)} \\ 8221.2 \\ 10000+8221.2=18221.2 \end{gathered}[/tex]It means that the population in 2020 is 18221 (Remember that we round it because it is not possible to have a decimal value for the population of the town).
How many inches are in 4 feet 6 inches?
6 inches
54 inches
46 inches
48 inches
Answer:
54 inches
Step-by-step explanation:
There are 12 inches in 1 foot
12in = 1ft
There are 4 feet and 6 inches
If you break it down its 4×12
4 × 12 = 48
Add 6 inches
48 + 6 = 54
Therefore the answer would be 54 inches
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$150,000 is still owed on a home loan. The loan has an interest rate of 4.5% compounded monthly and calls for monthly payments. The current payment is $1,100 per month. How long will it take to pay the loan off? R
Based on the monthly payment of $1,100, it will take 16 years to liquidate the loan.
How is the number of periods determined?The number of periods is a function of the total payments that will be paid, given the compounding of the interest at 4.5% and the monthly payment of $1,100.
Using an online finance calculator, the total number of years is determined as follows:
I/Y (Interest per year) = 4.5%
PV (Present Value) = $150,000
PMT (Periodic Payment) = $-1,100
FV (Future Value) = $0
Results:
N (# of periods) = 191.328 months
= 16 years (191.328/12)
Sum of all periodic payments = $-210,460.39 (191.328 x $1,100)
Total Interest = $60,460.39
Thus, before the loan is paid off, it will take 16 years or 191 monthly payments.
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Answer:
it would be 600
Write and graph a direct variation equation that passes through the given point.(2, 5)Write the direct variation equation.y=
For direct variation, an increase or decrease in one variable leads to a proportional increase or decrease in the other variable
Given that y varies directly with x, we would introduce a constant of proportionality, k
The expresion becomes
y = kx
For x = 2 and y = 5,
5 = 2k
k = 5/2 = 2.5
The direct variation equation is
y = 2.5x
which best describes the relationship between the two lines described below?
If two lines are perpendicular, then the product of their slopes is equal to -1.
If two lines are parallel, then their slopes are equal.
Write the equation of the lines P and Q in slope-intercept form by isolating y. Compare their slopes to see if they are either parallel or pependicular, or none.
The equation of a line with slope m and y-intercept b in slope-intercept form, is:
[tex]y=mx+b[/tex]Line P:
[tex]\begin{gathered} 6x+3y=12 \\ \Rightarrow3y=-6x+12 \\ \Rightarrow y=\frac{-6x+12}{3} \\ \therefore y=-2x+4 \end{gathered}[/tex]Then, the slope of the line P is -2.
Line Q:
[tex]\begin{gathered} -4x=2y-2 \\ \Rightarrow2y=-4x+2 \\ \Rightarrow y=\frac{-4x+2}{2} \\ \Rightarrow y=-2x+1 \end{gathered}[/tex]Then, the slope of the line Q is -2.
Since both lines have the same slope, then they are parallel.
What is an equation of the line that passes through the point (8,0)(8,0) and is parallel to the line x-4y=20x−4y=20?
The equation of the line that passes through the point (8, 0) is parallel to the line x - 4y = 20 is 1/4x - y = 2
Given,
The equation of the line: x - 4y = 20
The points which the line passes through, (x₁, y₁) = (8, 0)
We have to find the equation of the line parallel to the given line.
The formula for the slope intercept form:
(y - y₁) = m(x - x₁)
m is the slope of the line.
Lets find the slope of the line given.
x - 4y = 20
x = 20 + 4y
x - 20 = 4y
y = (x - 20) / 4
y = 1/4x - 5
Here, slope of the line is 1/4
Now, substitute the slope of the line and (x₁, y₁) in the slope intercept formula to get the equation of line parallel to the given line
(y - y₁) = m(x - x₁)
(y - 0) = 1/4(x - 8)
y = 1/4x - 8/4
y = 1/4x - 2
1/4x - y = 2
Therefore,
The equation of the line that passes through the point (8, 0) is parallel to the line x - 4y = 20 is 1/4x - y = 2
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Hi someone please help me and thanks have a great day.Hi someone please help me and thanks have a great day. Hi someone please help me and thanks have a great day.
Given data:
The given figure is shown.
For figure A, the expression for sin(A) is,
[tex]\begin{gathered} \sin A=\frac{7}{18} \\ A=\sin ^{-1}(\frac{7}{18}) \\ =22.885^{\circ} \\ \approx23^{\circ} \end{gathered}[/tex]Thus, the value of angle A is 23 degrees.
(b)
The vaue of tan(A) is,
[tex]\begin{gathered} \tan (A)=\frac{14}{12} \\ A=\tan ^{-1}(\frac{7}{6}) \\ =49.398^{\circ} \\ \approx49^{\circ} \end{gathered}[/tex]Thus, the value of A is 49 degrees.
(c)
The value of cos(A) is,
[tex]\begin{gathered} \cos (A)=\frac{6}{10} \\ A=\cos ^{-1}(0.6) \\ \approx53^{\circ} \end{gathered}[/tex]Thus, the value of A is 53 degrees.
(d)
The value of tan(A) is,
[tex]\begin{gathered} \tan A=\frac{20}{28} \\ \tan A=\frac{5}{7} \\ A=\tan ^{-1}(\frac{5}{7}) \\ =35.53^{\circ} \\ \approx35^{\circ} \end{gathered}[/tex]Thus, the measurement of angle A is 35 degrees.
Graph the line with slope
-2/3
passing through the point (2, -3).
The solution is written down, and the graph is drawb below
in point a the diameter is 12 C D equals 8 and MCD equals 90 find a measure round to the nearest hundred
Given that BE is diameter and CD is perpendicular, we can deduct that arcs CE and DE are equal.
[tex]\begin{gathered} arc(CD)=arc(CE)+arc(DE) \\ 90=2\cdot arc(CE) \\ \text{arc(CE)}=45=arc(DE) \end{gathered}[/tex]Therefore, arc DE is 45°.
What is the product of -2 1/2 and -3 1/3?
A mixed fraction exists one that is represented by both its quotient and remainder.
Product of -2 1/2 and -3 1/3 is [tex]8\frac{1}{3}[/tex].
Product of 1 1/3 and -3 1/2 is [tex]-5\frac{5}{6}[/tex] .
How do you multiply fractions and mixed numbers in simplest form?A mixed fraction is one that is represented by both its quotient and remainder. A mixed fraction exists, for example, 2 1/3, where 2 is the quotient and 1 is the remainder. An amalgam of a whole number and a legal fraction is a mixed fraction.
Step 1: Create an incorrect fraction from the jumbled number.Step 2: Separately multiply the denominators and numerators of the two fractions. Step 3: Simplify by removing the common elements to obtain the most basic version of the outcome. Step 4: Change the result back to a mixed number if it is an incorrect fraction.Product of -2 1/2 and -3 1/3 is [tex]8\frac{1}{3}[/tex].
Product of 1 1/3 and -3 1/2 is [tex]-5\frac{5}{6}[/tex] .
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#12 Suppose Bob is a 9th grade student. Bob's Mom plans to buy him a VA529 education bondof $50,000 education bond for his college education. If the discount rate is 6%, compounded semi-annually, what price should Bob's Mom pay now (current price)? (Hint: there are 4 years from 9thgrade to college.)
For solving this exercise, we will use the formula of the Present or Current value, as follows:
[tex]PV\text{ = FV }\ast\text{ }\lbrack\frac{1}{\square}(1+i)^n\rbrack[/tex]Where:
PV = Present or Current Value
FV = Future Value
i = Interest or discount rate
n = Periods of time
Replacing with the values we know:
[tex]PV\text{ = 50,000 }\ast\text{ }\lbrack\text{ 1 }\frac{\square}{\square}\text{ }(1+0.03)^8\rbrack[/tex]PV = 50,000 * 0.7894
PV = 39,470
Bob's Mom
A chef at a restaurant uses 19 pounds of butter each day. About how many grams of butter does the chef use each day? Use the conversion factors
28.4 grams
1 ounce
16 ounces
1 pound
and
Using the conversion factors, 454 grams of butter is used by the chef each day.
What are conversion factors?A conversion factor is a number that is used to multiply or divide one set of units into another. If a conversion is required, it must be done using the correct conversion factor to get an equal value. For instance, 12 inches equals one foot when converting between inches and feet.So, grams of butter used each day:
19 pounds = 8618.26 gramsThen,
1 pound = 8618.26/191 pounds = 453.592 gramsRounding off: 454 gramsTherefore, using the conversion factors, 454 grams of butter is used by the chef each day.
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The correct question is given below:
A chef at a restaurant uses 19 pounds of butter each day. About how many grams of butter does the chef use each day? Use the conversion factors
What is the slope of the line whose equation is y-4=(x-2)?6543qu6543+2w9(0,-1)(2,4)2 3 4 5 6 x
The point-slope form of the equation of a line is given to be:
[tex]y-y_1=m(x-x_1)[/tex]where
[tex]\begin{gathered} m=slope \\ (x_1,y_1)=point\text{ }on\text{ }the\text{ }line \end{gathered}[/tex]The equation of the line is given to be:
[tex]y-4=\frac{5}{2}(x-2)[/tex]This means that the slope is 5/2.
Find the midpoint of the segment with endpoints of (-1, 7) and (3,-3) andenter its coordinates as an ordered pair. If necessary, express coordinates asfractions, using the slash mark (/) for the fraction bar.
We are given the points (-1,7) and (3,-3) and we want to calculate the midpoint of the segment that joins this points. REcall that given points (a,b) and (c,d), the midpoint of the segment that joins the points is calculated by averaging each coordinate (that is,adding the coordinates and then dividing them by 2). So the midpoint would be
[tex](\frac{a+c}{2},\frac{b+d}{2})[/tex]In July 1 2020 culver inc invested $635250 in a mine estimated to have 847000 tons of ore of uniform grade during the last 6 months of 2020 146000 tons of ore were mined calculate depletion cost per unit
Given:
culver inc invested $635250 in a mine estimated to have 847000 tons of ore of uniform grade
So, the estimated cost per unit =
[tex]\frac{635250}{847000}=0.75[/tex]This means the cost = $0.75 per ton
Directions: Find the slope of the line that passes through the given point.
15.) (-8,-11) and (17,4)
16.) (10,-15) and (13,-17)
17.) (-6,-7) and (5,-7)
The population of a town over the past 10 years can be represented with the equationy = 2450(1.07)? What is the rate of change?A) 1.07%B 2450C 7%D.0796
Let's begin by identifying key information given to us:
The population is represented by the equation:
[tex]y=2450\mleft(1.07\mright)[/tex]We will compare the equation for the population with the general exponential growth equation, we have:
[tex]\begin{gathered} f(x)=a(1+r)^x \\ where\colon \\ f(x)=exponential\text{ }growth\text{ }function \\ a=initial\text{ }amount \\ r=growth\text{ }rate \\ x=number\text{ }of\text{ }time\text{ }intervals \end{gathered}[/tex]Comparing, we have:
[tex]\begin{gathered} f(x)\Rightarrow y \\ a=2450 \\ (1+r)=1.07\Rightarrow r=1.07-1=0.07 \\ \Rightarrow r=0.07=7\text{\%} \\ \\ \\ \end{gathered}[/tex]Therefore, the rate of change is 7%. Hence, C is the answer
14) Solve the following quadratic equations by using the quadratic formula a) 3x2 - 7x + 4 = 0 b) 5x2 + 3x = 9
Quadratic formula
[tex]x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]Where a is the coefficient of the first term, b the coefficient of the second term and c the coefficient of third term
a)
[tex]3x^2-7x+4=0[/tex]replacing on the quadratic formula
[tex]x=\frac{-(-7)\pm\sqrt[]{(-7)^2-4(3)(4)}}{2(3)}[/tex]simplify
[tex]\begin{gathered} x=\frac{7\pm\sqrt[]{49-48}}{6} \\ \\ x=\frac{7\pm\sqrt[]{1}}{6} \\ \\ x=\frac{7\pm1}{6} \end{gathered}[/tex]x has two solutions
[tex]\begin{gathered} x_1=\frac{7+1}{6}=\frac{4}{3} \\ \\ x_2=\frac{7-1}{6}=1 \end{gathered}[/tex]b)
[tex]5x^2+3x=9[/tex]rewrite on general form
[tex]5x^2+3x-9=0[/tex]raplace on quadratic formula
[tex]x=\frac{-(3)\pm\sqrt[]{(3)^2-4(5)(-9)}}{2(5)}[/tex]simplify
[tex]\begin{gathered} x=\frac{-3\pm\sqrt[]{9+180}}{10} \\ \\ x=\frac{-3\pm\sqrt[]{189}}{10} \end{gathered}[/tex]x has two solutions
[tex]\begin{gathered} x_1=\frac{-3+\sqrt[]{189}}{10}\approx1.075 \\ \\ x_2=\frac{-3-\sqrt[]{189}}{10}\approx-1.67 \end{gathered}[/tex]I'm re-posting because I need to turn this in soon! Please help! Thanks :)
The slope of g(x) is -3 and the g(x) is reflected across the x-axis
The table of values is
x f(x) = x g(x) = -3x
0 0 0
1 1 -3
2 2 -6
How to complete the blanks in the question?From the question, we have the definition of the functions to be
f(x) = x and g(x) = -3x
Also, we have the following x values from the blank table of values
x = 0, 1 and 2
Next, we calculate f(x) and g(x) at these x values
For the function f(x), the values are
f(0) = 0, f(1) = 1 and f(2) = 2
For the function g(x), the values are
g(0) = 0, g(1) = -3 and g(2) = -6
The next step is to calculate the slope and the transformation
Recall that
f(x) = x and g(x) = -3x
Generally, the form of a linear equation is
y = mx
Where m is the slope
This means that the slope of g(x) is -3
Lastly, the negative sign in g(x) = -3x implies that the graph is reflected across the x-axis or the y-axis
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[tex]P(0)=0.023(0)^3-0.289(0)^2+3.068(0)+55.170=55.17[/tex]
One year ago, Anne could run a mile in m minutes. Since then, her time hasdecreased by 16%. Write two different expressions that represent the number ofminutes it now takes Anne to run a mile, and show or explain why the expressionsare equivalent.
We know that
• Anne could run a mile in ,m, minutes.
,• Now, time has decreased by 16%.
The following expressions represent the number of minutes She uses to run a mile now.
[tex]\frac{16}{100}\cdot m[/tex]This expression represents 16% of m in fraction form.
[tex]0.16\cdot m[/tex]This expressed represents 16% of m in decimal form.
Both expressions are equivalent because they refer to the same percentage 16%. That is 0.16 and 16/100 are equivalent to 16%
Write 8.94 in fractional notation. don't simplify
We have to write 8.94 in fractional notation without simplification.
For decimal values, we can convert them to fractions taking into account the number of decimals they have.
In this case, 8.94 has two decimals. Then, we can multiply it by a fraction 100/100, as 100 has two zeros.
Then, we will get:
[tex]8.94\cdot\frac{100}{100}=\frac{8.94\cdot100}{100}=\frac{894}{100}[/tex]This works beacuse we multiply the number 8.94 by a number that will make it become an integer (without decimals). To keep the value of the fraction equal to the decimal number, we have to divide by the same factor (in this case, 100).
This fraction can be simplified.
Answer: the fractional notation, without simplification, of 8.94 is 894/100.
3 1/3(y+1 1/8)=6 11/12
Answer:
(3 1/3)·(y + (1 1/8)) = 6 11/12
(9/3 + 1/3)·(y + (8/8 + 1/8)) = 72/12 + 11/12
10/3·(y + 9/8) = 83/12
y + 9/8 = 83/12·3/10
y + 9/8 = 83/4·1/10
y + 9/8 = 83/40
y = 83/40 - 9/8
y = 83/40 - 45/40
y = 38/40
y = 19/20
to find 24 times 17 i multiply 20 times 17 and add it to 4 times 17
Step-by-step explanation:
to find 24 times 17 i multiply 20 times 17 and add it to 4 times 17?
Yes, that is one way of doing it:
Your method:
20 × 17 = 340
4 × 17 = 68
340 + 68 = 408
The typical way of solving is:
24 × 17 = 408
Both return the correct answer.
Answer:
24 times 17 = 408
But if you multiply:
20 times 17 = 340 Then add that to:
4 times 17 = 68
340 + 68 = 408
You would get the same answer so this is correct!
Step-by-step explanation:
Hope it helps! =D
Hello! I can’t seem to remember to do this answer
Given the following inequality:
[tex]2x\leq10[/tex]We will solve the inequality as follows:
Divide both sides by 2
[tex]\begin{gathered} \frac{2x}{2}\leq\frac{10}{2} \\ \\ x\leq5 \end{gathered}[/tex]So, the solution to the inequality x = (-∞, 5]
So, x = 5 is a solution to the inequality
So, the answer will be yes; x = 5 is a solution.
How can you use the Power of a Quotient, Quotient of Powers, Zero Exponent Laws Identity Exponent and to evaluate numerical expressions with whole-number exponents?
Though working with laws of exponents, when part of the exponential equations with the same base, the exponent need to be subtracted.
Since the Quotient of Powers rules is utilized to decrease the number of terms when parts like terms with exponents. In arrange to urge the solution, fair remove the exponents whereas dividing the terms with the same base is appropriate for exponents with the same bases. when powers are multiplied, for two whole numbers of the same bases the exponents are added, while when powers are divided for two whole numbers of the same bases, exponents are subtracted. When any number is raised to the power of zero it comes about in 1 is the zero exponent rule.
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Simplify the following expressions by using the properties of exponents. Assume none of the denominators is zero.
a^3 (2a^2 + 4bc^4)^ 0
The simplified form of the expression is a³ which is calculated by using the properties of exponents.
Exponentiation is a mathematical operation that involves the base number (b) and the exponent (or power) number (n), and is represented as bⁿ. Its pronunciation is "b (raised) to the (power of) n." Exponentiation corresponds to repeated base multiplication where n is a positive integer; so, bⁿ is the result of multiplying n bases.
Typically, a superscript to the right of the base indicates the exponent. Then, bⁿ is referred to as "b raised to the nth power," "b (raised) to the power of n," "the nth power of b," "b to the nth power," or, most succinctly, "b to the nth."
The given expression is a³(2a² + 4bc⁴)⁰.
From the properties of exponents we know that:
a⁰ = 1
Therefore the value of the part of the expression (2a² + 4bc⁴)⁰ is 1
Therefore the total value of the exponential expression is a³
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An artist wants to earn a revenue of $2700 by selling paintings for $30 each and sculptures for $45 each
The most appropriate choice for equation of line in slope intercept form x intercept = 90
y intercept = 60
Domain = {0, 3, 6, 9, ....., 90}
Range = {0 , 2, 4,...., 88}
What is equation of line in slope intercept form?
Equation of line in slope intercept form is written as y = mx + c, where m is the slope of the line and c is the y intercept of the line.
The distance from origin to the point where the line cuts the x axis is the x intercept and the distance of origin to the point where the line cuts the y axis is the y intercept.
Here,
Selling price of one painting = $30
Selling price of x paintings = $30x
Selling price of y sculptures = $45
Selling price of y sculptures = $45y
Total revenue = $(30x + 45y)
By the problem,
30x + 45y = 2700
a)
For x intercept, y = 0
30x = 2700
x = [tex]\frac{2700}{30}[/tex]
x = 90
x intercept is $90
For y intercept, x = 0
45 y = 2700
y = [tex]\frac{2700}{45}[/tex]
y = 60
y intercept is 60
b)
In 30x + 45y = 2700
Since x represents the number of paintings sold and y represents the number of sculptures sold, then x and y has to be integers.
If x = 0 , y = [tex]\frac{2700}{45}[/tex] = 60
If x = 3, y = [tex]\frac{2700 -90}{45} = 58[/tex]
If x = 6, y = [tex]\frac{2700 -180}{45} = 56[/tex]
If x = 9, y = [tex]\frac{2700 -270}{45} = 54[/tex]
_______________________________
If x = 90 , y = [tex]\frac{2700 -2700}{45} = 0[/tex]
Domain is the values of x
Domain = {0, 3, 6, 9, ....., 90}
Range is the values of y
Range = {0 , 2, 4,...., 88}
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Complete Question
The diagram with the questions have been attached below
What’s the correct answer answer asap i need help can somebody answer this question?
il give you brainlist
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The elephants at the zoo eat 3 1/6 buckets of bananas each day. The zookeeper bought 6 1/3 buckets of bananas. How many days will the bananas last?
Write your answer as a fraction or as a whole or mixed number.
The bananas will last 2 days at the zoo (found by division).
According to the question,
We have the following information:
The elephants at the zoo eat [tex]3\frac{1}{6}[/tex] buckets of bananas each day. The zookeeper bought [tex]6\frac{1}{3}[/tex] buckets of bananas.
Now, first we will find the number of days taken in eating 1 bucket of bananas.
[tex]3\frac{1}{6}[/tex] buckets = 1 day
Now, we will convert this mixed fraction into simple fraction.
19/6 buckets = 1 day
1 bucket = 1/(19/6) days
1 bucket = 6/19 days
Now, we have the total number of buckets as [tex]6\frac{1}{3}[/tex].
Now, after converting this mixed fraction, we have:
19/3 buckets
1 bucket = 6/19 days
19/3 buckets = (6/19)*(19/3)
19/3 buckets = 2 days
2 is a whole number.
Hence, the given buckets of bananas will last 2 days.
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