During revision, you should _____.A set your first draft aside for awhileB work from typed or printed textC write down additional thoughtsD All of the above

Answers

Answer 1

You should jot down any new ideas you have while you revise.

Revision is the process of rearrangement, addition, or deletion of paragraphs, sentences, or words in writing. Writers are free to edit their work both during and after the writing process. Many of the techniques associated with editing are used in revision, but it can also require more significant changes to the goal, target audience, and content.

To ensure proper memorization, revise by reading or writing the material again. A must-do before each exam is revision. Additionally, it allows you to check for errors and reorganize your work.

During revision, you should write down additional thoughts.

The correct option is (c).

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Related Questions

In a square box problem, the:Top number is the product of those left and rightBottom number is the sum of those at left and rightComplete this square box problem

Answers

Answer

Draw the box to complete the table.

Next,

To get the top, multiply both the left and the right = 11 x (-3)

= -33

To get the top, add both the left and the right = 11 + (-3) = 11 - 3 = 8

For j(x) = 3x − 1, find j of the quantity x plus h end quantity minus j of x all over h period a 3 to the power of the quantity x minus 1 end quantity times the quantity 3 to the power of h end quantity all over h b 3 to the power of the quantity x minus 1 end quantity times the quantity 3 to the power of h minus 1 end quantity all over h c 3 to the power of the quantity x minus 1 end quantity times the quantity 3 to the power of h plus 1 end quantity all over h d the quantity x minus 1 end quantity times the quantity 3 to the power of h plus 1 end quantity all over h

Answers

The resulting value of the function [j(x+h)-j(x)/h] is 3⁽ˣ⁻¹⁾ ([tex]3^{h}[/tex]-1)/h

What is an exponential function?

An exponential function is defined as a function whose value is a constant raised to the power of an argument is called an exponential function.

It is a relation of the form y = aˣ  in mathematics, where x is the independent variable

Given the function expressed as;

j(x) = 3⁽ˣ⁻¹⁾

Required value of the function  [j(x+h)-j(x)]/h

We have to determine the function j(x+h) and j(x)

j(x+h) = [tex]3^{(x+h) -1}[/tex]

Substitute the values,

[j(x+h)-j(x)]/h = [  [tex]3^{(x+h) -1}[/tex]  -  3⁽ˣ⁻¹⁾ ]/h

⇒ [  [tex]3^{(x-1) +h}[/tex]  -  3⁽ˣ⁻¹⁾ ]/h

⇒ [  [tex]3^{(x-1)} \times3^{h}[/tex]  -  3⁽ˣ⁻¹⁾ ]/h

⇒ 3⁽ˣ⁻¹⁾ ([tex]3^{h}[/tex]-1)/h

Hence, the equivalent value of the function is 3⁽ˣ⁻¹⁾ ([tex]3^{h}[/tex]-1)/h

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As part of a charity drive, 50 fourth grade students each donated an equal number of dimes and 30 third grade students each donated the same number of nickels. Let d represent the number of dimes and n represent the number of nickels. Determine which of the expressions shows the total amount (in cents) donated by the 3rd and 4th grade students. A.) 10(50d)+5(30n)B.) 80cC.) 10d+5nD.) 50d+30n

Answers

[tex]\begin{gathered} By\text{ fourth grade is }\Rightarrow50d \\ By\text{ third grade is}\Rightarrow30n \\ So,\text{ the expression is,} \\ 50d+30n \\ \text{Thus, the option D is correct.} \end{gathered}[/tex]



(-8.8)(-9) =
(0.5)(-0.5)=
(-0.2)(-5)

Answers

Answer:

(-8.8)(-9)= 79.2

(0.5)(-0.5)= -0.25

(-0.2)(-5)= 1

^^^^^^^^^^^^^^^^^^^^^^

Which of the following statements best describe the branches of the hyperbola?Select one:a.It is not possible to determine how the branches of the hyperbola open.b.The branches of the hyperbola are positioned at a 30⁰ angle.c.The branches of the hyperbola open up and down.d.The branches of the hyperbola open side to side.

Answers

Answer:

Explanation:

The first step is to plot the graph of the parabola. It is shown below

Looking at the graph, the branches open up and down. Thus, the correct option is

c. The branches of the hyperbola open up and down.



i just want the answers, i dont want an explanation.

Answers

Given:

Required: Evaluation

Explanation:

Use BODMAS rule to evaluate all

71.

[tex]\begin{gathered} 16+4(-3)-7=16-12-7 \\ =-3 \end{gathered}[/tex]

72.

[tex]\begin{gathered} (-24)\div(4)+16(2)=-6+32 \\ =26 \end{gathered}[/tex]

73.

[tex]\begin{gathered} -5-8+6(-3)=-13-18 \\ =-31 \end{gathered}[/tex]

74.

[tex]\begin{gathered} 30-6\div3+4=30-2+4 \\ =32 \end{gathered}[/tex]

75.

[tex]\begin{gathered} 21-45+8\div2=21-45+4 \\ =25-45=-20 \end{gathered}[/tex]

Final Answer:

71 - E

72 - AE

73 - A

74 - BE

75 - B

2. A new car dealership invites 500 people to a promotional event. Only 330 people attend the event. What percentage of the people attend the event?

Answers

since

[tex]550X=330[/tex]

then

[tex]X=\frac{330}{500}=0.66[/tex]

then it is the 100x0.66= 66%

Thursday

Each 4th grade class at Garza Elementary collected plastic water bottles to recycle.
Each number on the stem and leaf plot represents how many bottles each class
brought in. Record each answer in the blank box next to each question.
Help fill the table please.

1. how many fourth grade classes brought in between 90 and 100 bottles

2. How many classes brought in more than 100 water bottles

3. how many classes brought in less than 99 water bottles

4. How many fourth grade glasses are represented on the stem and leaf plot

Answers

The number of students that collected between 90 and 100 bottles is 3.

The number of students that collected more than 100 bottles are 7.

The number of students that collected less than 90 students are 2

The total number of classes represented is 10.

Here is the completed frequency table

Number of bottles collected  Classes

90 - 100                                         3

101 - 110                                          6

111 - 120                                          1

What is a stem and leaf plot?

A stem-and-leaf plot is a table that splits a number into a stem and leaf.   The stem is the first number in the digit while the leaf is the last number. For example the stem in 45 is 4 and the leaf is 5.  

An advantage of the stem-and-leaf plot is that it provides an easy way to present and interpret a dataset. A disadvantage of the stem-and-leaf plot is that it cannot be used for a large dataset.

Bottles collected that are between 90 and 100 are 94, 98, 99

Bottles that are greater than 100 are 105, 107, 107, 113, 114, 119, 120

Bottles that are less than 99 are 94, 98

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The average amount of time spent grocery shopping is 45 minutes with a standard deviation of 12 minutes. Using the Empirical Rule, what percent should spend less than 33 minutes?

Answers

You have:

mean = 45

standard deviation = 12

Use the following formula:

Find the standard form for the equation of a circle ( x − h )^2 + ( y − k )^2 = r^2 with a diameter that has endpoints ( − 4 , − 8 ) and ( 6 , − 4 ) .h=k=r=

Answers

Answer:

[tex](x-1)^2+(y+6)^2=29[/tex][tex]\begin{gathered} h=1 \\ k=-6 \\ r=\sqrt{29} \end{gathered}[/tex]

Explanation:

Given:

Endpoints of the diameter of a circle as (-4, -8) and (6, -4)

To find:

Equation of a circle in standard form

The equation of a circle in standard form is generally given as;

[tex](x-h)^2+(y-k)^2=r^2[/tex]

where (h, k) is the coordinate of the center of the circle and r is the radius of the circle.

We'll go ahead and determine the coordinates of the midpoint of the endpoints of the diameter which will be the coordinates of the center of the circle as seen below wi;

[tex]h=\frac{x_1+x_2}{2}=\frac{-4+6}{2}=\frac{2}{2}=1[/tex][tex]k=\frac{-8+(-4)}{2}=\frac{-12}{2}=-6[/tex]

So the center of the circle has coordinates (1, -6)

Since h = 1, and k = -6 and we have that x1 = -4 and y1 = -8, we can go ahead and solve for r as seen below;

[tex]\begin{gathered} (-4-1)^2+(-8-(-6))^2=r^2 \\ (-5)^2+(-2)^2=r^2 \\ 25+4=r^2 \\ 29=r^2 \\ \therefore r=\sqrt{29} \end{gathered}[/tex]

We can now write the equation of the circle in standard form as;

[tex]\begin{gathered} (x-1)^2+(y-(-6))^2=29 \\ (x-1)^2+(y+6))^2=29 \end{gathered}[/tex]

A trendline is given to depict the enrollment at a local college where x is the year and y represents enrollment. y=178.09x−353194Use the trendline to estimate the enrollment for 2009. Round to the nearest whole number.

Answers

To determine the enrollment in 2009 we need to plug x=2009 in the equation given to determine the value of y:

[tex]\begin{gathered} y=178.09(2009)-353194 \\ y=357782.81-353194 \\ y=4588.81 \end{gathered}[/tex]

Therefore, in the year 2009, there were 4589 students enrolled

how many cubic blocks with a side length of 1/6 cm are needed to fill the volume of this prism?The answer choices are 4,8,9,32.

Answers

Given the figure, we can deduce the following information:

Height=1/2 cm

Length=1/2 cm

Width= 1/6 cm

To determine the number of cubic blocks with a side length of 1/6 cm needed to fill the volume of the given prism, we first note that a cube has equal sides. So, the dimensions of the cube must be:

Height= 1/6 cm

Length=1/6 cm

Width=1/6 cm

Next, we get the volume of the cube by using the formula:

[tex]\begin{gathered} Volume\text{ of the cube}=(Height)(Length)(Width) \\ =(\frac{1}{6})(\frac{1}{6})(\frac{1}{6}) \\ Simplify \\ =\frac{1}{216}\text{ }cm^3\text{ } \end{gathered}[/tex]

Then, we get the volume of the given prism using the same formula:

[tex]\begin{gathered} Volume\text{ of the given prism}=(He\imaginaryI ght)(Length)(W\imaginaryI dth) \\ =(\frac{1}{2})(\frac{1}{2})(\frac{1}{6}) \\ =\frac{1}{24}\text{ }cm^3\text{ } \end{gathered}[/tex]

Now, we find the number cubic blocks by using the formula:

[tex]\begin{gathered} Number\text{ }of\text{ cubic blocks}=\frac{Volume\text{ of the given prism}}{Volume\text{ of the cube}} \\ =\frac{\frac{1}{24}}{\frac{1}{216}} \\ Simplify \\ =9 \end{gathered}[/tex]

Therefore, the answer is 9.

answers pleaseeee
im struggling

Answers

The answer is 3/4 and -2

Answer:

y=3/4x-2

Step-by-step explanation:

slope=3/4x

y-intercept=-2

A manufacturer of ski clothing makes ski pants and ski jackets. The profit on a pair of ski pants is $3 and on a jacket is $2. Both pants and jackets require the work of sewing operators and cutters. There are 60 minutes of sewing operator time and 48 minutes of cutter time available. It takes 8 minutes to sew one pair of ski pants and 4 minutes to sew one jacket. Cutters take 4 minutes on pants and 8 minutes on a jacket. The manufacturer wants to make a minimum of 4 ski pants and 2 ski jackets, Let x represent the number of ski pants. Let y represent the number of ski jackets.

Answers

For the sewing operator:

[tex]8x\text{ + 4y }\leq\text{ 60}[/tex]

For cutter:

[tex]4x\text{ + 8y }\leq48[/tex]

The two above equation is solve to obtain the graph

The solution of the graph is where the two lines meet

The coordinate is (10, 4), at the this point the maximum profit is made

So 10 ski pants and 4 ski jackets is made to get maximum profit

The profit made is given by

P = 3x + 2y

x =10 , y = 4

P = 3(10) + 2(4)

P = 30 + 8 = $38

it takes 126 cubes that have edge lengths of 1/3feet to completely fill this plastic bin what is the area of the base of bin

Answers

Answer: 1) Each of the 126 cubes has a volume = (1/3)3 = 1/3 × 1/3 × 1/3 = 1/27 cubic feet.

2) It takes 126 cubes to fill the bin, so the bin has a volume of 126 × 1/27 = 126/27 cubic feet. (Don't do this division yet - leave it as an improper fraction)

3) The volume of the bin is also given by the formula Volume = Area of Base × Height. Plus we know the volume is 126/27 cubic feet and the height is 2 1/3 = 7/3 of a foot, so:

Step-by-step explanation: Volume = Area of Base × Height

126/27 = Area of Base × 7/3

126/27 × 3/7 = Area of Base

The  area of the base of bin is 2 feet².

What is Volume of Cube?

The formula of volume of the cube is given by: Volume = a³, where a is the length of its sides or edges.

Given:

Edge = 1/3 feet

Volume of 1 cube= l³= (1/3)³ = 1/27

Totals cubes= 126

So, Volume of 126 cube= 126 x 1/27 = 126/ 27

Then, Volume of Plastic Bin= Area of base x height

126 / 27 =  Area of base x 7/3

Area of base = 126 /27 x 3 /7

Area of base = 2 ft²

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Gravel is being dumped from a conveyor belt at a rate of 30 ft^3/min, and its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal. How fast is the height of the pile increasing when the pile is 10 ft high?

Answers

The height of the pile increasing at the rate of  4.56 inches per minute when the pile is 10 ft high.

In given situation, the rate of change of height is equal to the rate of change of volume, divided by the base area.

First we find the base area.

base area = (π/4)d²

base area = (π/4)10²

base area = 25π ft²

base area ≈ 78.5 ft²

Then the rate of change of height would be,

(30 ft³/min)/(78.5 ft²)

≈ 0.38 ft/min

= 4.56 inches / minute

Therefore, the height of the pile increasing at the rate of  4.56 inches per minute when the pile is 10 ft high.

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Given that f(x) = x sqaured - 10x + 16 and g(x) = x - 8, find f (x) · g(x) andexpress the result in standard form.

Answers

Given the functions

[tex]f(x)=x^2-10x+16[/tex][tex]g(x)=x-8[/tex]

You have to calculate

[tex]f(x)\cdot g(x)[/tex][tex](x^2-10x+16)\cdot(x-8)[/tex]

To solve this you have to apply the distributive property of multiplications, that is, you have to multiply each term of the first parenthesis with each term of the second parenthesis.

As follows:

[tex]\begin{gathered} (x^2-10x+16)\cdot(x-8) \\ (x^2\cdot x)+(x^2)\cdot(-8)+(-10x\cdot x)+(-10x)\cdot(-8)+(16\cdot x)+(16\cdot(-8)) \\ x^3-8x^2-10x^2+80x+16x-128 \end{gathered}[/tex]

Now simplify the like terms

[tex]\begin{gathered} x^3+(-8x^2-10x^2)+(80x+16x)-128 \\ x^3-18x^2+96x-128 \end{gathered}[/tex]

The result in standard form is

[tex]f(x)\cdot g(x)=x^3-18x^2+96x-128[/tex]

Find a_10 5, 12, 19, 26, 33...

Answers

Given,

The progression is 5, 12, 19, 26, 33...​

The first term of the series is, a = 5.

The common difference of the series is,

d = 12 - 5 = 7

The 10th term of the series is,

[tex]\begin{gathered} a_{10}=a+(10-1)\times d \\ =5+9\times7 \\ =5+63 \\ =68 \end{gathered}[/tex]

Hence, the 10th term of the series is 68.

find the value of x and y that make the quadrilateral

Answers

The quadrilateral have equal opposite sides, for example:

Then, (4x + 6) must be equal to (7x - 3), and (4y - 3) is equal to (3y + 1), therefore

[tex]4x+6=7x-3[/tex]

We can solve that equation for x

[tex]\begin{gathered} 4x+6=7x-3 \\ \\ 3x=9 \\ \\ x=\frac{9}{3}=3 \end{gathered}[/tex]

Hence, x = 3. Now let's solve the other equation

[tex]\begin{gathered} 4y-3=3y+1 \\ \\ y=4 \end{gathered}[/tex]

Then the value of y is 4.

Final answers:

x = 3

y = 4

Melissa brought 6 apples for $1.20 .if each apple cost the same amount, how much would 20 apples cost

Answers

The cost of 20 apples is such that the ratio of apples to cost maintained or each apple costs the same amount is $4.

What are the ratio and proportion?

The ratio is the division of the two numbers.

For example, a/b, where a will be the numerator and b will be the denominator.

As per the given,

Melissa brought 6 apples for $1.20.

The ratio of cost to apple ⇒

1.20/6

Now let's suppose the cost of 20 apples is x dollars.

The ratio of cost to apple ⇒

x/20

Since the cost of each apple is the same, therefore, both ratios must be the same.

x/20 = 1.20/6

x = 20(1.20/6)

x = 4

Hence "The cost of 20 apples is such that the ratio of apples to cost maintained or each apple costs the same amount is $4".

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find the lateral area and surface area the lateral area of the prism is __in squared. the surface area of the prism is __ in squared

Answers

Answer

The lateral area of the prism is 900 in squared

The surface area of the prism is 960 in squared

Explanation

Given:

The first side of the triangular base, a = 12 in

The second side of the triangular base, b = 13 in

The height of the prism, h = 30 in

What to find:

The lateral area and surface area of the prism.

Step-by-step solution:

The first step is to find the third side, c of the triangular base using Pythagoras rule.

[tex]\begin{gathered} b^2=c^2+a^2 \\ \\ 13^2=c^2+12^2 \\ \\ c^2=13^2-12^2 \\ \\ c^2=169-144 \\ \\ c^2=25 \\ \\ c=\sqrt{25} \\ \\ c=5\text{ }in \end{gathered}[/tex]

Now, the next step is to calculate the lateral area of the prism using the formula below.

[tex]\begin{gathered} L.A=ha+hb+hc \\ \\ L.A=30\times12+30\times13+30\times5 \\ \\ L.A=360+390+150 \\ \\ L.A=900\text{ }in^2 \end{gathered}[/tex]

The lateral area of the prism is 900 in squared

The final step is to calculate the surface area of the prism using the formula below.

[tex]S.A=Lateral\text{ }Area+Base\text{ }Area[/tex]

The base area is

[tex]=2(\frac{1}{2}cb)=2(\frac{1}{2}\times5\times12)=2(\frac{60}{2})=60\text{ }in^2[/tex]

Therefore, the Surface Area = (900 + 60) = 960 in squared

IXL Transversals of parallel lines: prove angle relationships 6QF for geometry, please help

Answers

4) [tex]m\angle XWY=m\angle HGY[/tex] (definition of congruent angles)

5) [tex]\angle HGY \cong \angle GTU[/tex] (corresponding angles theorem)

6) [tex]m\angle HGY=m\angle GTU[/tex] (definition of congruent angles)

7) [tex]\angle GTU[/tex] and [tex]\angle UTR[/tex] are supplementary (linear pair)

8) [tex]m\angle GTU+m\angle UTR=180^{\circ}[/tex] (definition of supplementary angles)

9) [tex]m\angle HGY+m\angle UTR=180^{\circ}[/tex] (substitution)

10) [tex]m\angle RTU+m\angle XWY=180^{\circ}[/tex] (substitution)

Question: how do I figure out if a number is rational or irrational

Answers

A number is said to be rational if it can be written or transformed into the p/q form, where p and q are integers and q is a non-zero number; if it cannot be written in this form, it is said to be irrational.

Any number that can be written or stated in the p/q form, where p and q are integers and q is a non-zero number, is said to be rational.

A number that is irrational, on the other hand, cannot be stated in p/q form, and its decimal expansion is non-repeating and non-terminating.

Example: √2, √7, √11

Hence we get the required answer.

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Which of the following equations represents a line that is perpendicular toy=-3x+6 and passes through the point, (3, 2)?A. y=-3x+1B. y=(1/3x)+3C. y=(-1/3x)+1OD. y=(1/3x)+1

Answers

Step 1

For perpendicular lines

[tex]m_1=-\frac{1}{m_2}[/tex][tex]m_1=-3[/tex][tex]\begin{gathered} -3=-\frac{1}{m_2} \\ m_2=-\frac{1}{-3} \\ m_2=\frac{1}{3} \end{gathered}[/tex]

Step 2

[tex]\begin{gathered} Given\text{ points \lparen3,2\rparen} \\ y=mx+b---\text{ Standard equation of a line} \\ y=\frac{1}{3}x+b \end{gathered}[/tex][tex]2=\frac{1}{3}(3)+b[/tex]

Find b, the y-intercept

[tex]\begin{gathered} 2=1+b \\ b=2-1=1 \end{gathered}[/tex]

Answer; Option D

[tex]y=\frac{1}{3}x+1[/tex]

22. A 250W carrier is to be modulated at an 85% modulation level. What is the total transmitted power? a. 340.3 W b. 25.32 dB c. 0.340 kW d. 55.32 dBm e. All of the above.

Answers

The total transmitted power is a. 340.3 W.

The transmitted and carrier power is related with modulation through the formula -

[tex] P_{t} = P_{c}(1 + \frac{ {m}^{2} }{2} )[/tex]

where [tex]P_{t}[/tex] is transmitted power, [tex]P_{t}[/tex] is carrier power and m is modulation.

Keep the values in formula to find the value of total transmitted power.

[tex]P_{t}[/tex] = 250 (1 + 85%²/2)

Taking square of percentage

[tex]P_{t}[/tex] = 250 (1 + 0.7225/2)

Performing division in the bracket

[tex]P_{t}[/tex] = 250 (1 + 0.36125)

Performing addition in the bracket

[tex]P_{t}[/tex] = 250×1.36125

Performing multiplication

[tex]P_{t}[/tex] = 340.3125

Thus, the total transmitted power when carrier power is 250 W and modulation is 85% is a. 340.3 W.

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Does the graph represent a function? 4 5 6 7 -3+ no O yes

Answers

To prove:

The given graph is a function.

The given graph is a function if and only if no x value has more than one value of y, or we can say that a graph is a function iff no vertical line intersects the graph in more than one point.

Thus, by the given graph it is clear that for x = 7 their are two values for y that is y = -6 , -7

So, the given graph is not a function

Factories 6ax2-3ay-8bx2+4by

Answers

=[2[tex]x^{2}[/tex]-y][3a-4b] This is the factorized form of 6a[tex]x^{2}[/tex]-3ay - 8 b[tex]x^{2}[/tex] + 4by

What is factorization ?

To factorize a number, use the factorization formula. Factorization is the process of dividing a whole into components that, when multiplied together, equal the original number. The factorization approach simplifies any algebraic or quadratic equation by using the basic factorization formula, which represents the equations as the product of factors rather than expanding the brackets. Any equation may have an integer, a variable, or the algebraic expression itself as a factor.

6a[tex]x^{2}[/tex]-3ay - 8 b[tex]x^{2}[/tex] + 4by

Rearrange the expression

6a[tex]x^{2}[/tex] -8bx² -3ay +4by

2[tex]x^{2}[/tex][3a-4b] - y[3a-4b]

=[2[tex]x^{2}[/tex]-y][3a-4b]

This is the factorized form of 6a[tex]x^{2}[/tex]-3ay - 8 b[tex]x^{2}[/tex] + 4by

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You are about to enter an elevator with a weight capacity of 500 pounds. There are three people already in the elevator. The weights of the passengers are 107 pounds, 172 pounds and 129 pounds. Assuming that you weigh 136 pounds, is it safe for you to enter the elevator?

Answers

Given

capacity of 500 pounds.

weights of the passengers are 107 pounds, 172 pounds and 129 pounds.

you weigh 136 pounds

Find

is it safe for you to enter the elevator?

Explanation

as total pounds in the elevator = 107 + 172 + 129 = 408 pounds

total pounds included my weight = 408 + 136 = 544 pounds

capacity = 500 pounds

so , extra pounds = 544 - 500 = 44 pounds

so , no it is not safe for you to enter the elevator.

Final Answer

Therefore , No the weigh capacity would be exceeded by 44 pounds

6.4 The ratio of length and breadth of a rectagular field is 4:3. If perimeter of the field is 700m, find (i) length and breadth of the field (ii) area of the field.

Answers

Hope it helped !! :)

.........

If P is the centroid of the triangle JKL, JK = 22, KN = 13, and OL = 18, find each measure.

Answers

Given

JK = 22

KN = 13

OL = 18

Procedure

Centroid formulation

KM = JK/2 = 22/2 = 11

KM = 11

NL = KN

NL = 13

KL = 2KN = 2(13) = 26

KL = 26

JO = OL = 18

JO = 18

JL = 2OL = 2(18)

JL = 36

Other Questions
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