Declination. As you can see, the position has a significant impact on the compass's direction. Declination, which is measured in degrees on your map and represents the angle between magnetic north and true north.
The compass does not always point precisely toward geographic north on the surface of the Earth. An angle known as "declination" describes the compass's departure from true north (or "magnetic declination"). If you were to stand at the north geomagnetic pole, your compass would be held horizontally as usual and would not have a preference to point in any specific direction. The same would be true if you were to stand at the south geomagnetic pole. The north-pointing end of your compass would point up at the south geomagnetic pole if you were to hold it on its side, and it would point down at the north geomagnetic pole.
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An object starts at rest and experiences a constant acceleration of 4 m/s² for 3 seconds.
Sketch the acceleration-time graph for this object.
1. What was the initial velocity of the object?
2. What was the velocity of the object after 1 second?
3.What was the velocity of the object after 2 seconds?
4.What was the velocity of the object after 3 seconds?
5. Sketch the velocity-time graph for this object.
6. What was the average velocity of the 1st second?
7.What distance did the object travel in the 1st second?
8. What was the average velocity of the 2nd second?
9. What distance did the object travel in the 2nd second?
10.What was the average velocity of the 3rd second?
11. What distance did the object travel in the 3rd second?
12.Sketch the position-time graph for this object.
13.What was the displacement of the object?
14.What was the distance travelled by the object?
For the given acceleration and time, following are the different velocities.
Given:
acceleration a = 4 m/s²
time t = 3 sec
initial velocity u = 0 [ starts from rest ]
let final velocity be = v
Therefore according to the question,
velocity after 1 sec :
v = u + at
v = 0 + 4 x 1
v = 4m/s ( after 1 sec)
Velocity after 2 secs
v = 0 + 4 x 2
v= 8m/s (after 2 sec)
Velocity after 3 secs
v = 0 + 4 x 3
v = 12m/sec
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Help me as pleasessss help with 1,2 and 3
galaxy fragments in the early universe formed before the first stars. in dark matter mini-halos. due to gravity from large dark matter halos. in places where the universe was slightly less dense than average.
Galaxy fragments originated in the early world due to the gravity of massive amounts of dark matter.
Dark matter is any substance that primarily interacts with visible matter through gravity (e.g., stars and planets). Therefore, in theory, it need not be made up of a brand-new form of fundamental particle but rather may be built up, at least in part, of typical baryonic matter, such as protons or neutrons.
The concept of dark matter, the invisible substance whose gravitational pull is assumed to hold galaxies together, may not be the most pleasing one in physics. According to a recent study, however, if you want to get rid of it, you'll need to switch it out for something more stranger: a gravitational force that at some distances pushes large objects apart and at others draws them together. The analysis highlights how difficult it is to rationalize away dark matter.
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A 8.0-kg chunk of putty moving at 4m / s collides with and sticks to a 7.0-kg 1 bowling ball that is initially at rest. The bowling ball with its putty passenger will then be set in motion with a velocity of (round to the hundredths)
The velocity of the bowling ball with its putty passenger will be 2.28 m/s.
Velocity of the moving chunk = [tex]V_{c}[/tex] = 4 m/s
Mass of the chunk = [tex]M_{c}[/tex] = 8 kg
Mass of the bowling ball = [tex]M_{b}[/tex] = 7 kg
Velocity of the bowling ball = [tex]V_{b}[/tex] = 0
Since this is the perfect inelastic collision, so according to the law of conservation of momentum
Conservation of momentum is a fundamental law of physics that states that the total momentum of an isolated system is conserved in the absence of an external force.
Mathematically, it is p = m*v[tex]p_{initial} = p_{final}[/tex]
[tex]p_{initial}[/tex] = [tex]V_{c}[/tex] * [tex]M_{c}[/tex] + [tex]M_{b}[/tex] * [tex]V_{b}[/tex]
[tex]p_{initial}[/tex] = 8*4 + 7*0
[tex]p_{initial}[/tex] = 32 + 0
[tex]p_{initial}[/tex] = 32 kg.m/s
[tex]p_{final}[/tex] = ( [tex]M_{c}[/tex] + [tex]M_{b}[/tex] ) [tex]V_{final}[/tex]
[tex]p_{final}[/tex] = ( 8 + 7 ) [tex]V_{final}[/tex]
[tex]p_{final}[/tex] = 14 [tex]V_{final}[/tex] kg.m/s
[tex]p_{initial} = p_{final}[/tex]
32 = 14 [tex]V_{final}[/tex]
[tex]V_{final}[/tex] = [tex]\frac{32}{14}[/tex]
[tex]V_{final}[/tex] = 2.28 m/s
The bowling ball with its putty passenger will then be set in motion with a velocity of 2.28 m/s.
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What is the mass of an object that has a weight of 69.3 N?
Answer:
7.06663336 kg
Explanation
to get the mass of an object divide the force of gravity(9.8) from the weight (in this case, 69.3 N) to get 7.06663336 kg. Or round it (if it's okay with your teacher) and get 7.07 or 7.1 kg
what is the maximum speed with which a 1100 kg rubber-tired car can take this curve without sliding? (take the static coefficient of friction of rubber on concrete to be 1.0.)
The question is incomplete, however, 39.2 velocity is the maximum speed with which a 1100 kg rubber-tired car can take this curve without sliding
Consider the net force acting horizontal component of friction [tex](\mu _sN \cos \theta)[/tex] and normal force Acting in horizontal component of friction [tex](N sin \theta)[/tex] , So the sum of force is
[tex]mv_max^2/r=N sin \theta+\mu _sN cos \theta[/tex]
Consider the net force acting vertical component of friction [tex](N cos \theta)[/tex] and normal force acting in Vertical component of friction [tex](\mu _sN sin \theta)[/tex] the wight of car is perpendicular to the force (-mg)
[tex]mg=N cos \theta-\mu _sN sin \theta[/tex]
[tex]v_max^2/rg=sin \theta+\mu _scos \theta/cos \theta-\mu _ssin \theta[/tex]
[tex]\nu_max=\sqrtrgsin \theta+\mu _scos \theta/cos \theta-\mu _ssin \theta[/tex]
[tex]" Substitute, "80" "m" for ' "r,,9.81" for ' "g" ', "18.0" for "\theta" and "1.0" for\mu_s[/tex]
after solving
[tex]v_max=39.2 m/s[/tex]
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What is the acceleration?
Answer:
3m/s²
Explanation:
From 60 to 70 s the velocity increases from 50 to 80 m/s
Acceleration is defined as a = Δv/Δt
where Δv = change in velocity
and Δt = change in time
Δv = 80 - 50 = 30 m/s
Δt = 70 - 60 = 10 s
Acceleration = 30/10 = 3m/s²
help please i have a 17 as a grade :)
Given
A 50kg boy
A 100 kg father
Speed (both) 5 m/s
Procedure
Kinetic energy is a form of energy that an object or a particle has by reason of its motion
For the boy
[tex]\begin{gathered} K_b=\frac{1}{2}mv^2 \\ K_b=\frac{1}{2}\cdot50\operatorname{kg}\cdot(5m/s)^2 \\ K_b=625J \end{gathered}[/tex]For the father
[tex]\begin{gathered} K_f=\frac{1}{2}mv^2 \\ K_f=\frac{1}{2}\cdot100\operatorname{kg}\cdot(5m/s)^2 \\ K_f=1250J \end{gathered}[/tex]Now, let's compare the kinetic energy between father and boy
[tex]\begin{gathered} \frac{father^{\prime}s\text{ KE}}{boy^{\prime}s\text{ KE}} \\ \frac{1250J}{625J} \\ \frac{father^{\prime}s\text{ KE}}{boy^{\prime}s\text{ KE}}=2 \end{gathered}[/tex]The father's KE is twice the boy's kinetic energy
Screenshot:
Part 2:
Part 1:
the timing device in an automobile’s intermittent wiper system is based on rc an time constant and utilizes 0.500 μf a capacitor and a variable resistor. determine the time constant if the resistance is 30 mω.
Our resistance is four mega houses at two seconds. Simply enter 15 seconds as R times 150.50 times 10 to the negative six digits for the calculation. We therefore have 30 Mega Ohms.
It is required to wipe the screen of an automobile on a regular basis when there is a light drizzle, when it is dirty, or when any of these conditions exist. There is a switch that uses an electrical circuit to wipe the screen. A main-wiper control circuit system and a relay control circuit are components of an intermittent wiper system. The relay control circuit uses a transistor and diode combination in an RC circuit.
According to what we've been told, our RC circuit's capacitance is 0.5 micro Farads, or 0.5 times ten to the minus six Farads. The resistance times the capacitance produces the time constant. And by multiplying both sides by C, we may find R's value. And when the time constant is divided by the capacitance, which is equal to 0.5 times ten to the minus six Farads, we have the minimum resistance, which is equal to 4.00 Mega Ohms.
The maximum time constant divided by capacitance occurs when the resistance is at its maximum. As a result, when we replace tau with 15 seconds, we obtain 30.0 Mega Ohms. To modify the frequency of the wiper blades' oscillation, the resistance must be able to shift between four and thirty megaohms.
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What is the weight of a 179 kg football player?
A person pushes a crate using 412 N. What is the mass of the crate if it accelerates at 1.1 m/s2?
Answer:
m=374.5kg
Explanation:
force=mass × acceleration
F=m × a
a=1.1m/s²
f=412N
412=m × 1.1
412=1.1m
m=412/1.1
m=374.5kg
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The gas pressure in an oxygen tank is 3.90 atm at a temperature of 298 K. If the pressure decreases to 3.20 atm, what is the temperature of the gas in kelvin? it need to be rounded by three significant figures to
The temperature of the gas rounded to three significant figures would be 244 Kelvin.
What is an ideal gas?
It is an imaginary gas for which the volume occupies by it is negligible, this gas does not exist in a practical situation and the concept of an ideal gas is only the theoretical one.
As given in the problem, the gas pressure in an oxygen tank is 3.90 atm at a temperature of 298 K. If the pressure decreases to 3.20 atm,
By using the constant volume for the ideal gas,
P₁/P₂ = T₁/T₂
3.90 /3.20 = 298 / T₂
T₂ = 244 Kelvin
Thus, the temperature of the gas rounded to three significant figures would be 244 Kelvin.
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An iguana crawls from a position of 5.0m to a position of -18m. If it completes this in 9.0s, what was its average velocity?
The average velocity of Iguana is -2.55m/s when it crawls from 5m to -18m in 9 seconds.
Average velocity of a body is defined as the total displacement divided by the total time taken by the body.
Here, initial position of iguana is 5m and the final position of the iguana is -18m.
Total displacement D is,
D = final position - initial position.
D = -18-5
D = -23m
Total time taken by the iguana is 9.0 seconds.
Average velocity(V) = total displacement/total time taken.
Putting values,
V = -23/9
V = -2.55m/s.
So, the average velocity of the iguana is -2.55m/s.
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What do all living things constantly engage in
All living things are constantly engaged in Homeostasis.
Homeostasis is the capacity to sustain a comparatively constant internal condition that endures despite changes in the external environment. To consume energy and eventually live, all living things—from plants to puppies to people—must control their interior environments. For numerous reasons, the body sustains homeostasis. Body temperature, blood sugar levels, and varying pH levels are a few of them. Not merely at the level of the entire body as it is for temperature, homeostasis is maintained at several levels.
Homeostasis is a state that can be preserved by all living things. They have systems in place to regulate things like their internal temperature, water balance, and acidity. Normal cell functions that take place inside of them depend on homeostasis. Normal life processes are interfered with if an organism can't sustain equilibrium. Ailment or even death might follow.
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A student made the electromagnet shown and used it to pick up one sewing pin. Which change to the electromagnet would most likely allow it to pick up two sewing pins?A. Double the length of the wires that connect it to the battery.B. Replace the nail with a thick roll if paper.C. Double the number of coils of wires around the nail.D. Replace the nail with a large bolt.
ANSWER:
C. Double the number of coils of wires around the nail.
STEP-BY-STEP EXPLANATION:
In order to collect two sewing pins, the student must double the number of coils around the nail.
Answer: Double the number of coils of wires around the nail.
Explanation: Just did this on apex, mostly for their benefit.
A humming bird flies 1.m along a straight path at a height of 5.9 m above the ground. Upon spotting a flower below, the hummingbird drops directly downward 1.8 m to hover in front of a flower.
What is the magnitude of the hummingbird’s total displacement?
The hummingbird's total displacement is 6.168m, 16.96⁰ Southwest.
Construct a right-angled triangle from the bird's displacement
⇒From the diagram uploaded; we calculate the resultant/total displacement (R) of the bird using Pythagoras theorem,
R² = 5.9² + 1.8²
R² = 38.05
R = √38.05
R = 6.168 m
calculate the direction of the bird's displacement
From the vector diagram head-to-tail rule, we determine the cardinal direction;[tex]tan\alpha = \frac{1.8}{5.9}[/tex]
From the diagram; [tex]tan\alpha = 0.3050[/tex]
[tex]\alpha = tan^{-1} 0.3050[/tex]
[tex]\alpha = 16.96^{o}[/tex]
Therefore the hummingbird's total displacement is 6.168m, 16.96⁰ Southwest.
What is displacement?Displacement is defined as a change in the location of an object. It is a vector quantity and has direction and magnitude. It is represented as an arrow pointing from the starting position to the final position. For example - when an object moves from point A to point B, the position of the object changes.
Displacement (symbolized d or s ), also called length or distance, is a one-dimensional quantity representing the difference between two specified points. The standard SI unit of displacement is the meter (m).
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please answer questions 15, 16, and 17 below for a 2m long steel coil spring with a diameter of 2cm in a passenger vehicle is exposed to a force of 2,000 n. if the length of the coil extends elastically to 2.2m upon this force, please calculate
The question is incomplete, however 7.1 X 10^6 N/m^2 is Young's Modulus of 2m long steel coil spring with a diameter of 2cm in a passenger vehicle is exposed to a force of 2,000 N. If the length of the coil extends elastically to 2.2m upon this force.
[tex][Y=Fl\pir^2e],[Y=4000 \cdot2/\pi0.1884/2\pi^2\cdot0.4)][/tex]
Y = 7.1 X 10^6 N/m^2
Young's modulus is a metric for determining how elastic a substance is. The ability of a body to resist attempts to deform it using an external shearing stress is referred to as its elastic property.
The internal force of a material that attempts to return the body to its former shape is known as a restoration force. Young's modulus of elasticity is the proportion of restorative stress generated and strain (deformations such an increase in length per unit length).
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an automobile of mass m is proceeding around a highway curve of 40-meter radius. the surface of the roadway is horizontal, and the coefficient of friction between the tires and the roadway is 0.50. the maximum speed with which the car can round the curve without slipping is...
The maximum speed with which the car can round the curve without slipping is 14m/s
Given the following:
The radius, r=40m
The coefficient of friction μ=0.5
Then from Newton's law:
μmg=mv^2/r
From the above equation, the speed, v of the car is:
v=√μrg, where μ=0.5, r=40m, and g=9.8m/s^2
v=√(0.5)(40m)(9.8m/s^2)
v=√196
v=14m/s
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what is the angular momentum of a 0.310 kg uniform ball revolving on the end of a thin string in a circle of radius 1.50 m at an angular speed of 12.5 rad/s? ignore the mass of the string.
The angular momentum of revolving ball is 8.72 kg.m²/s.
We need to know about the angular momentum to solve this problem. An angular momentum is a unit that measures the difficulty of stopping rotating objects. The angular momentum depends on the inertia and angular speed. It can be written as
L = I . ώ
where L is angular momentum, I is inertia and ώ is angular speed.
From the question above, the given parameters are
m = 0.31 kg
r = 1.5 m
ώ = 12.5 rad/s
Find the inertia of the revolving ball
I = m . r²
I = 0.31 . 1.5²
I = 0.6975 kgm
By substituting the given parameters, we can calculate the angular momentum
L = I . ώ
L = 0.6975 . 12.5
L = 8.72 kg.m²/s
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Based on this law, if a collapsing cloud is isolated in space with no external forces, what must happen to it as its size decreases?.
Based on law of conservation of angular momentum if a collapsing cloud is isolated in space with no external forces, the cloud will spin faster, the size will go on decreasing and the angular momentum will go on increasing that is reduction in radius and it will start spinning faster.
What is Nebular Theory?According to the nebular theory, a cloud of gas and dust must gravitationally collapse into a disk in order for planets to form inside. The disk must flatten out to fit observations. what causes this flattening to happen? Take the law of conservation of angular momentum, which states that an amount related to an object's size(its moment of inertia) times the rate at which rotates (angular speed) must always remain constant if no external forces are acting on the object.
Therefore, if a collapsing cloud is isolated in space with no external forces, the cloud will spin faster the size will go on decreasing and the angular momentum will go on increasing that is reduction in radius and it will start spinning faster.
What is law of conservation of angular momentum?Principle of conservation of angular momentum states that, if no external torque acts on a system, the total angular momentum of the system remains constant. If I be the momentum of inertia of a body about a given axis of rotation and w be its angular velocity, then I w= constant
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Question 10
5 pts
Jet fighter planes have ejector seats for rapid escapes from
unresolvable mechanical failures during flight. The typical
mass of a jet fighter seat is 200lbs, while the typical mass
of a jet fighter pilot is 155lbs. For the pilot to safely escape
their crashing plane, they must get at least 100 feet away
from the plane within 2 seconds of ejecting. What force
must the ejector seat launch with to meet these
Requirements
Answer:
See below
Explanation:
d istance = 1/2 a t ^2
100 = 1/2 (a) 2^2 solves for a = 50 ft/s^2
F = ma
= (200+ 155) ( 50) = 17750 lb ft/ s^2 ( this is 2454 N )
The force must the ejector seat launch with to meet these requirements is 17750 lb ft/ s².
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
Given that distance = 1/2 a t²
100 = 1/2 (a) 2² solves for a = 50 ft/s²
F = ma
F = (200+ 155) ( 50) = 17750 lb ft/ s² ( this is 2454 N )
The force must the ejector seat launch with to meet these requirements is 17750 lb ft/ s².
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When do trilobites disappear from the rock sequence?
Answer:
252 million years ago
Explanation:
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suppose you were hired to build a dam. what features would you look for in a site? be sure to consider the impact on living things as well as the physical characteristics of the site.
The fact that the water is surrounded by sturdy rock, soil, and sand has some aspects that are highly advantageous if I were in charge of assessing a site for a hydraulic dam to generate electricity.
A hydraulic dam is a barrier constructed through a river or lake to redirect or hold back water. The Engolasters dam, for example, uses its related infrastructure to generate energy, create a vertical drop, and retain water from the rivers.At 1,616 meters above sea level, Lake Engolasters is an oblong lake located in Andorra's Encamp parish (5,302 ft). created in a depression left by a glacier.Therefore we know that, a hydraulic dam is where power is generated.
Electricity is produced at the dam and distributed throughout the entire nation. A dam is formed by six main elements.
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shows a two-ended "rocket" that is initially stationary on a frictionless floor, with its center at the origin of an x axis. the rocket consists of a central block c (of mass m
What is the velocity of block C at t = 2.80 s is v₁=0.6 m/s and v₂= -0.15 m/s b. d=0.18m is the position of block C's center at that time.
The term "rate at which an object changes its position" is used to describe velocity, a vector quantity. Imagine someone moving quickly, taking one stride ahead, one step back, and constantly returning to their starting place. While there might be a frenzy of activity as a result, the velocity would be nil. The motion would never produce a change in position because the subject always returns to their starting place. Since the rate at which a position changes determines velocity, this motion has zero velocity. A person in motion must exert every effort to move farther from their starting location than necessary in order to increase their velocity.
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A particle that has zero momentum must also have zero kinetic energy.Select one:O TrueO False
The kinetic energy of an object is the energy possessed by the object due to its motion. That is when the velocity of the object is zero, i.e., when the object is at rest, the kinetic energy of the object will be zero.
The linear momentum is the product of the mass and the velocity of an object. When the momentum of the object is zero, the velocity of the object is also zer.
Thus whenever a particle has a zero momentum, its velocity and hence its kinetic energy will also be equal to zero.
Therefore, the given statement is true.
A torpedo fired from a submerged submarine is propelled through the waterwith a speed of 20.00 m/s and explodes upon impact with a target 2000.0 maway. If the sound of the impact is heard 101.4 s after the torpedo was fired,what is the speed of sound in water? (Because the torpedo is held at a constantspeed by its propeller, the effect of water resistance can be neglected.)
Given,
The initial speed, u=20.00 m/s
The distance between the submerine and the target is d=2000.0m
The sound of impact is heard after T=101.4 s.
To find
The speed of sound in water.
Explanation
Here the total time taken to reach the submarine is the sum of thetime taken by the torpedo to reach the target and the time taken for it to come back.
Let the speed be v.
Thus,
[tex]\begin{gathered} T=\frac{d}{u}+\frac{d}{v} \\ \Rightarrow101.4=\frac{2000}{20}+\frac{2000}{v} \\ \Rightarrow v=1428.6\text{ m/s} \\ \end{gathered}[/tex]Conclusion
Speed of the sound in water is 1428.6 m/s
If u drop a ball from a tower 6 miles up where will it land
A- Alongside the tower
B-Fall upward into space
C-Downward into space
D- It will circle around the earth
The ball will land alongside the tower due to the gravitational pull of the earth. Therefore, option (A) is correct.
What is gravity?Gravity is a force that attracts any physical body which has mass towards the center of the earth. Everybody having mass exerts a force or gravitational pull on every other object with mass. Gravity is the reason the planets orbit the sun as well as the moon orbits the earth.
Every particle of matter in the universe attracts every other particle with a specific force, and that force is directly proportional to the product of the masses of those particles.
Mathematical expression for gravity can be written as:
[tex]F= G\frac{mM}{r^2}[/tex]
Where F is the force between objects, m and M are masses of objects interacting, the distance between the center of the masses is equal to 'r' and, G is the gravitational constant.
When you drop a ball from a tower 6 miles up it will land back on the surface of the earth alongside the tower due to the gravitational pull of the earth.
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What would your weight on the moon be if you weighed 120 pounds on Earth?
(50 POINTS !!)
Answer:
Explanation:
Given:
m = 120 pounds = 120·0,454 = 54.48 kg
g = 1.625 m/s² - Acceleration of free fall on the Moon
_______________________________
F - ?
F = m·g = 54.48·1.625 ≈ 88.5 N
Answer:
about 20 pounds
If you weigh 120 pounds on Earth, you will weigh about 20 pounds on the moon.
Explanation:
Dont ask for an explanation ok buddy?
The left hand 'hill' is 15 m high. The right hand 'hill' is 26 m high. How fast must a 525kg cart have to go (at the top of the left hill) in order to get over the right hand hill?
Answer
A 51.7-kg hiker ascends a 43.2-meter high hill at a constant speed of 1.20 m/s. ... The initial kinetic energy can be found using the work-energy theorem.
Missing: 525kg | Must include: 525kg
You place a box weighing 299.7 n on an inclined plane that makes a 43.5 angle with the horizontal. compute the component of the gravitational force acting down the inclined plane. answer in units of n.
The gravitational force acting down the inclined plane is 206.19N
The force acting along the inclined plane is opposite the frictional force and the formula to express it is:
[tex]F_{m}[/tex]= F sinФ
It is given that
F = 299.7N
Ф = 43.5 degree
Putting the value we have:
[tex]F_{m}[/tex] = 299.7 sin 43.5°
= 299.7 (0.688)
= 206.19N
Therefore the gravitational force acting down the inclined plane is 206.19N.
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