part 2..number 2...evaluate the expressions using numbers and evaluate the expression for the numbers provided...please read the direction to make sure I'm understanding what's asked of me..I'm a 7th grader can u please help me with my math summer package and explain it in a way that a 7th grader can understand it
Answers
Given:
Each story is 13ft tall.
Explanation:
a) To find: The height of the skyscraper if it has 55 stories.
Since the number of stories increases the height of the skyscraper also increases.
That is,
[tex]\begin{gathered} h=Number\text{ of stories}\times Height\text{ of each story} \\ h=55\times13 \\ =715ft \end{gathered}[/tex]b) To find: The height of the skyscraper if it has 65 stories.
The height of the skyscraper would be,
[tex]\begin{gathered} h=Number\text{ of stories}\times Height\text{ of each story} \\ h=65\times13 \\ =845ft \end{gathered}[/tex]c) To find: The height of the skyscraper if it has 75 stories.
The height of the skyscraper would be,
[tex]\begin{gathered} h=Number\text{ of stories}\times Height\text{ of each story} \\ h=75\times13 \\ =975ft \end{gathered}[/tex]d) To find: The equation of the height if it has f stories
The height of the skyscraper would be,
[tex]\begin{gathered} h=Number\text{ of stories}\times Height\text{ of each story} \\ h=f\times13 \\ h=13f \end{gathered}[/tex]Final answer:
a) The height of the skyscraper if it has 55 stories is 715ft.
b) The height of the skyscraper if it has 65 stories is 845ft.
c) The height of the skyscraper if it has 75 stories is 975ft.
d) The expression that represents the height of f stories is h = 13f.
Related Questions
Starting at sea level, a submarine descended at a constant rate to a depth of −34 mile relative to sea level in 5 minutes.
What was the submarine's depth relative to sea level after the first minute?
Enter your answer as a fraction in simplest form.
Answers
Based on the fact that the submarine's depth was descended to at a constant rate, the submarine's depth relative to sea level with the passing of the first minute was -6⁴/₅ miles
How to find the submarine depth?The submarine descended at a constant rate to the current depth of -34 miles in 5 minutes. This means that the rate can be found by the formula:
= Current depth / Time
= -34 / 5
= -6.8 miles per minute
After the first minute, the depth is:
= -6.8 x 1
= -6.8 miles
This number in fractions is:
= -6 + 8/10
= -6 + 4 / 5
= -6⁴/₅ miles
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6. The equations of two lines are 6x - y = 2 and 4x - y = -8. What is thevalue of y in the solution for this system of equations?Your answer
Answers
The given system of equations : 6x - y = 2 and 4x - y = -8.
6x - y = 2 ( 1 )
4x - y = -8 ( 2 )
for the value of y, use substitution method:
Solve the equation (1) for y :
6x - y = 2
y = 6x - 2
Susbtitute the value of y in the equation ( 2 )
4x - y = - 8
4x - (6x - 2) = - 8
4x - 6x + 2 = - 8
4x -6x = - 8 - 2
-2x = -10
Divide both side by ( -2)
-2x/(-2) = -10/(-2)
x = 5
Substitute x = 5 in the equation ( 1 )
6x - y = 2
6( 5 ) - y = 2
30 - y = 2
y = 30 - 2
y = 28
So, the value of y is 28
Answer : y = 28
√X²+5x+4/X²+8x+16 - X²-3x-4/X²-16
Answers
The expression given as [x²+ 5x + 4]/[x² + 8x + 16] - [x² - 3x - 4]/[x²-16] simplifies to 0
What are expressions?Expressions are mathematical statements that are represented by variables, coefficients and operators
How to evaluate the expression?The expression is given as
[x²+ 5x + 4]/[x² + 8x + 16] - [x² - 3x - 4]/[x²-16]
Factorize the expression
So, we have
[x²+ 5x + 4]/[x² + 8x + 16] - [x² - 3x - 4]/[x²-16] = [(x + 4)(x + 1)]/[(x + 4)(x + 4)] - [(x - 4)(x + 1)]/[(x + 4)(x - 4)]
Simplify the common factors
So, we have
[x²+ 5x + 4]/[x² + 8x + 16] - [x² - 3x - 4]/[x²-16] = [(x + 1)]/[(x + 4)] - [(x + 1)]/[(x + 4)]
The terms of the above equation are the same
So, the result of subtracting one from the other is 0
This gives
[x²+ 5x + 4]/[x² + 8x + 16] - [x² - 3x - 4]/[x²-16] = 0
Hence, the value of the expression is 0
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The half life of radium -226 is 1640 years. If a sample contains 200 mg, how many mg will remain after 4000 years?
Answers
Find solutions to the linear equation y=12x+24
Answers
Te solutions to the linear equation given as y = 12x + 24 are (0, 24), (1, 36) and (2, 48)
How to determine the solutions to the linear equation?From the question, the linear equation is given as
y = 12x + 24
To determine the solutions, we assume values for the variable x and then calculate the y values
Having said that, we have
y = 12x + 24
Set x = 0
So, we have
y = 12 x 0 + 24 = 24
Set x = 1
So, we have
y = 12 x 1 + 24 = 36
Set x = 2
So, we have
y = 12 x 2 + 24 = 48
So, the ordered pairs of the solutions are (0, 24), (1, 36) and (2, 48)
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In a triple batch of a spice mix, there are 6 teaspoons of garlic powder and 15
teaspoons of salt. Answer the following questions about the mix.
2. How much salt is used with 8 teaspoons of garlic powder
3. If there are 14 teaspoons of spice mix, how much salt is in it.
4. How much More salt is there than garlic powder if 6 teaspoons of garlic powder are use
Answers
The answers of the given questions are:
8 teaspoons of garlic powder are combined with 20 tablespoons of salt.10 teaspoons of salt are included in every 14 teaspoons of spice mixture.If 6 teaspoons of garlic powder are used, there are 15 teaspoons more salt than garlic powder.What exactly are ratio and proportion?A ratio is an ordered pair of numbers a and b, denoted by the symbol a / b, where b does not equal zero. A proportion is an equation that sets two ratios equal to each other. For example, if there is one boy and three girls, the ratio could be written as: 1: 3 (for every one boy, there are three girls).Given: There are 6 teaspoons of garlic powder and 15 teaspoons of salt in a triple batch of spice mix.
Let x be the teaspoons of salt.
Salt used with 8 teaspoons of garlic powder:
6/15 = 8/x
x = 20
Therefore, 20 teaspoons of salt is used with 8 teaspoons of garlic powder.
6 + 15 = 21 teaspoons of spice mix
Salt used in 14 teaspoons of spice mix:
21/15 = 14/x
x = 10 teaspoons of salt.
Therefore, if there are 14 teaspoons of spice mix, 10 teaspoons of salt is there in it.
If 6 teaspoons of garlic powder are used then,
21-6 = 15 teaspoons of more salt is used
Therefore, 15 teaspoons of more salt is there than garlic powder if 6 teaspoons of garlic powder are used.
The answers of the given questions are:
20 teaspoons of salt is used with 8 teaspoons of garlic powder.If there are 14 teaspoons of spice mix, 10 teaspoons of salt is there in it. 15 teaspoons of more salt is there than garlic powder if 6 teaspoons of garlic powder are used.Learn more about ratio and proportion here:
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Find the midpoint of the segment with the following endpoints.
(4, 2) and (7, 6)
Answers
The midpoint of the segment with the following endpoints, (4, 2) and
(7, 6) is (5.5, 4).
How to determine the midpoint of a given segment?
The center point of a straight line can be located using the midpoint formula. We can use this midpoint formula to determine the coordinates of the supplied line's midpoint in order to discover its location on a graph. Assuming that the line's endpoints are (x₁, y₁) and (x₂, y₂), the midpoint (a, b) is determined using the following formula:
(a , b) ≡ (((x₁ + x₂)/2), ((y₁ + y₂)/2))
Let the line segment be AB having endpoints as A(4, 2) and B(7, 6);
also let the co-ordinates of midpoint be C = (a, b)
Using the given formula in the available literature,
(a, b) = ((4 + 7)/2, (2 + 6)/2)
Equating parts of the previous equation, we get,
a = (4 + 7)/2 = 11/2 = 5.5
b = (2 + 6)/2 = 4
Thus, the midpoint of the segment is (5.5, 4).
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A set of data has a mean of 9.6 and a standard deviation of 0.8. What number in the data set would have a z-score of -1.5?
Answers
A set of data has a mean of 9.6 and a standard deviation of 0.8. The number in the data set that would have a z-score of -1.5 is
x =8.4
This is further explained below.
What is the z-score?The number of normal deviations within which the value of a raw score is either above or below the average value of what is observed or measured is the number that is referred to as the standard score in the field of statistics.
Raw scores that are greater than the mean are assigned positive standard scores, and raw scores that are equal to or lower than the mean are assigned negative standard scores.
Generally, the parameters of the solutionare
[tex]\mu &=9.6 \quad \sigma=0.8 \quad z=-1.5 \\\\z &=\frac{x-\mu}{\sigma} \\\\-1.5 &=\frac{x-9.6}{0.8} \\[/tex]
Where
z=distribution
x=mean
[tex]\sigma[/tex]=standard deviation
u=population mean
Hence, solve for x
x =-1.2+9.6
x =8.4
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To the nearest tenth of pound Does has need to buy?
Answers
Answer: She needs approximately 142.5 pounds
Explanation:
From the information given,
A pound of fertilizer covers 39 square feet of lawn.
If the lawn measures 5557.4 square feet, then
the number of pounds of fertilizer that she needs to buy = 5557.4/39 = 142.4975
Rounding to the nearest tenth,
She needs approximately 142.5 pounds
[tex] \sqrt{25} [/tex]what's the square root
Answers
[tex] \sqrt{25} [/tex] ()
what's the square root ?
√25 = 5
because 5*5= 25
[tex]\sqrt[]{5\cdot5}=\sqrt[]{5^2}=\text{ 5}[/tex]________________________
Answer
√25 = 5
Hey can someone please help me with this drag and drop? I’ll give brainliest :)
Answers
Lengths of similar triangles and similar polygons are proportional to each other so, answer to the question in image are-
a. ZY=20
b. X=20.8
c. 9miles
What are similar polygons?
similar polygons are the polygons in which all the corresponding angles are same. Hence, they have same shape. The ratio of sides in any two similar polygons are same. This concept of constant ratio of sides is useful in evaluating the length of sides.
a. A/a=B/b=C/c = D/d
WX/HI=ZY/JK
ZY=20
b. X=(2.4×39)/4.5
X= 20.8
c. If 5cm represents 2miles it implies 1cm represents
1cm=2/5
So, 22.5cm will represent
22.5cm=2/5×22.5
22.5cm=9miles
This means that 22.5cm track represents the distance of 9 miles on map
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Ava can run 4/5 of a mile in 4/3 of an hour. How far can she run in 1 hour? *
Answers
Answer:
She can run 3/5 miles in 1 hour
Explanation:
Given that Ava can run 4/5 of a mile in 4/3 of an hour, we want to find how far she can run in 1 hour.
Let x represent the number of miles she can run in one hour.
The statement can be represented in the pair of equations:
[tex]\begin{gathered} \frac{4}{5}miles=\frac{4}{3}\text{hours} \\ \\ x\text{ hour }=1\text{hour} \end{gathered}[/tex]Using these equations, we have:
[tex]\begin{gathered} \frac{4}{5}=\frac{4}{3}x \\ \\ x=\frac{\frac{4}{5}}{\frac{4}{3}} \\ \\ x=\frac{4}{5}\times\frac{3}{4} \\ \\ =\frac{3}{5} \end{gathered}[/tex]That is, she can run 3/5 miles in 1 hour
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Solve the inequality n minus three fifths is less than or equal to negative four sevenths for n.
n is greater than or equal to negative forty one over thirty five
n is less than or equal to negative one over thirty five
n is less than or equal to one over thirty five
n is greater than or equal to forty one over thirty five
Answers
The solution to the given inequality would be n ≤ 1/35 which is the correct answer would be an option (C).
What is inequality?Inequality is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are not equal.
We have to determine the solution of the inequality n minus three-fifths is less than or equal to negative four sevenths for n.
As per the given condition, translate the phrase into an algebraic inequality as :
⇒ n - 3/5 ≤ - (4/7)
⇒ n ≤ 3/5 - (4/7)
⇒ n ≤ (21 - 20)/35
⇒ n ≤ 1/35
Therefore, the solution to the given inequality would be n ≤ 1/35.
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4) The measure of one of two supplementary angles is 8 degrees more than three times the other. Find the measure of the larger of the two angles.
Answers
Supplementary angles add 180 degrees.
One of the two angles is 8 degrees more than 3 times the other.
If one of the angles is A and the other is B, then:
[tex]A=8+3B[/tex]As they are supplementary, they add 180 degrees:
[tex]A+B=180[/tex]We replace the information of the second equation in the first one and solve:
[tex]\begin{gathered} A=180-B \\ A=8+3B=180-B \\ 8+3B=180-B \\ 4B+B=180-8 \\ 5B=172 \\ B=\frac{172}{5} \\ B=34.4 \end{gathered}[/tex]Now we can solve for the other angle:
[tex]A=8+3B=8+3(34.4)=8+103.2=111.2[/tex]The measure of the angles is 34.4 degrees and 111.2 degrees.
Marsha thinks that because 123 is greater than 68, 0.123 must be greater than 0.68. Show and explain why Marsha is incorrect.
Answers
Let's begin by listing out the information given to us:
[tex]\begin{gathered} 123=1\text{0}0 \\ \text{ 20} \\ \text{ 3} \\ 123=1\text{ hundred + 2 tens + 3 units} \\ 68\text{ = 6 (10)} \\ \text{ 8} \\ 68\text{ = 6 tens + 8 units} \end{gathered}[/tex]To know which is greater between 0.123 To know which i3& 0.68, let's express it in tenth, hundredth & thousandth
[tex]\begin{gathered} 0.123=3\text{ thousandth + 2 hundredth + 1 tenth + 0 unit} \\ 0.123=0.003+0.02+0.1+0 \\ 0.68=\text{ 6 hundredth + 8 tenth + 0 unit} \\ 0.68=0.60+0.08+0 \end{gathered}[/tex]0.123 has 3 decimal places, which means it is 123/1000
0.68 has 2 decimal places, which means it is 68/100
When you multiply by 100, we have:
0.123 * 100 = 12.3
0.68 * 100 = 68
It becomes very evident that 0.68 is greater than 0.123
A marathon is 46,145 yards (about 26 miles) long. If Terrence has run 23,561 yards, estimate by rounding to thousands the number of yards he needs to run to complete the marathon.Terrence needs to run about ______ yards.
Answers
Given:
The length of the marathon is L= 46,145 yards.
The length covered by terrence is d = 23,561 yrads.
The objective is to find the remaining distance need to cover by terrence.
To calculate the remaining distance, we will use the relation,
[tex]x=L-d[/tex]On plugging the values in the above relation, we get,
[tex]\begin{gathered} x=46145-23561 \\ =22584\text{ yards} \\ \approx23000\text{ yards} \end{gathered}[/tex]Hence, Terrence needs to run about 23000 yards.
Find an angle θ with 0∘<θ<360∘ that has the same:
Sine function value as 210∘
θ = _____ degrees
Cosine function value as 210∘
θ = ______ degrees
Answers
sin theta = -0.5 degrees
cos theta=-0.86 degrees
hope it helped
HI there. I need some help with this question. I cannot figure out what the answer is.
Answers
From the question we were given the following:
Area of the square is 19 square units
Area of the circle is 30 square units
Area of intersection is 3 square units.
We are asked to find the area in square units of the entire coloured region.
So,
Are of Square = 19 square units
Are of Circle = 30 square units
Area of Intersection = 3 square units
Area of coloured region = Area of Square + Area of Circle - Area of Intersection
Therefore, Area of coloured region = 19 + 30 - 3
= 46 saqure units.
The volume for a rectangular prism is given by the formula V = l · w · h, where l is the length of the prism, w is the width of the prism, and h is the height of the prism.
If the volume of a rectangular prism with a height of 8 inches is 200 cubic inches and the base of the prism is a square, then what is the width of the rectangular prism?
A.
5 inches
B.
12.5 inches
C.
25 inches
D.
40 inches
Answers
If the volume of a rectangular prism with a height of 8 inches is 200 cubic inches and the base of the prism is a square, then the width of the rectangular prism is 5 inches
The volume of the rectangular prism = 200 cubic inches
The height of the rectangular prism = 8 inches
We know the volume of the rectangular prism = l×w×h
Where ls if the length of the base
w is the width of the base
h is the height of the rectangular prism
Given that the base of the prism is a square, then the length of the base is equal to width of the base
Consider
l = w = x
Substitute the values in the equation of volume
x × x × 8 = 200
[tex]x^{2}[/tex] × 8 = 200
[tex]x^{2}[/tex] = 25
x = 5 inches
Hence, if the volume of a rectangular prism with a height of 8 inches is 200 cubic inches and the base of the prism is a square, then the width of the rectangular prism is 5 inches
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What’s 2,0000000 +3000,00000
Answers
In order to add these two numbers, we need to add the algarisms that are in the same position.
Since the first number has 7 zeros and the second one has 8 zeros, the numbers 2 and 3 will not be added, since they are in different positions (the number 3 has more "value", since it's in a higher position).
So, adding these two numbers, we have:
Therefore the result of this sum is 320,000,000 (three hundred and twenty million).
An arrow is launched upward with a velocity of 320 feet per second from the top of a 30-foot building. What is the maximum height
attained by the arrow?
Answers
Answer: Maximum height reached is 804.88 m
Step-by-step explanation:
At maximum height velocity is zero
We have equation of motion v² = u² + 2as
Initial velocity, u = 320 ft/s = 97.536 m/s
Final velocity, v = 0 m/s
Acceleration, a = -9.81 m/s²
Substituting
v² = u² + 2as
0² = 97.536² + 2 x -9.81 x s
s = 484.88 m
So the arrow further a height of 484.88 m
Total height = 320 + 484.88 = 804.88 m
Simplify the expression √(112x^10 y^13 ). Show your work. please help
Answers
To create the abbreviated expression, combine similar terms by adding them all together. If the expression be [tex]$\sqrt{112 x^{10} y^{13}}$[/tex] then expression exists [tex]$4 \sqrt{7} x^5 y^6 \sqrt{y}$[/tex].
What is meant by an expression?Solving a math problem is the same thing as simplifying an expression. You basically strive to write an expression as simply as you can when you simplify it. In the conclusion, there shouldn't be any more multiplying, dividing, adding, or removing to do.
Start by recognizing the like terms, or terms with the same variables and exponents, in algebraic formulas. Then, to create the abbreviated expression, combine similar terms by adding them all together.
Let the expression be [tex]$\sqrt{112 x^{10} y^{13}}$[/tex]
separating the roots of the expression, we get
[tex]$\sqrt{112 x^{10} y^{13}}=\sqrt{112} \sqrt{x^{10}} \sqrt{y^{13}}$[/tex]
simplifying the above equation, we get
[tex]$=\sqrt{112} \sqrt{x^{10}} \sqrt{y^{13}}$[/tex]
Simplify [tex]$\sqrt{x^{10}}= x^5$[/tex]
[tex]$=\sqrt{112} x^5 \sqrt{y^{13}}$[/tex]
Simplify [tex]$\sqrt{y^{13}}=y^6 \sqrt{y}$[/tex]
[tex]$=\sqrt{112} x^5 y^6 \sqrt{y}$[/tex]
[tex]$=\sqrt{112}=4 \sqrt{7}$[/tex]
[tex]$=4 \sqrt{7} x^5 y^6 \sqrt{y}$[/tex]
Therefore, the correct answer is [tex]$4 \sqrt{7} x^5 y^6 \sqrt{y}$[/tex].
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Given H(t)=10-2t^2 , find h^-1 (t), is h (t) one to one ? What does this imply about h^-1(t)
Answers
We have the function:
[tex]H(t)=10-5t^2[/tex]And we have to find the inverse function.
We can write this as:
[tex]H(H^{-1}(t))=t[/tex]We can solve this as:
[tex]\begin{gathered} H(H^{-1}(t))=10-2(H^{-1})^3=t \\ 10-2(H^{-1})^3=t \\ 2(H^{-1})^3=10-t \\ (H^{-1})^3=\frac{10-t}{2} \\ H^{-1}=\sqrt[3]{\frac{10-t}{2}}^{} \end{gathered}[/tex]The inverse function is:
[tex]H^{-1}=\sqrt[3]{\frac{10-t}{2}}^{}[/tex]The domain of H is all the real numbers, as the domain of H^-1.
Find the coefficient of third term of (x + 2)³. A. 40 OB. 10 OC. 20 D. 80 Reset Selection A
Answers
Given:
The expression given is,
[tex]\left(x+2\right)^5[/tex]Required:
To find the coefficient of the third term.
Explanation:
Let us expand the expression to find the coefficient.
[tex]\begin{gathered} \left(x+2\right)^5 \\ =\frac{5!}{5!}x^52^0+\frac{5!}{4!}x^42^1+\frac{5!}{2!3!}x^32^2+\frac{5!}{3!2!}x^22^3+\frac{5!}{4!1!}x^12^4+\frac{5!}{5!0!}x^02^5 \\ =x^5+10x^4+40x^3+80x^2+80x+32 \end{gathered}[/tex]Hence, the coefficient of the third term is 40.
Final Answer:
The coefficient of the third term is 40.
Option A is correct.
Round to the answer to the nearest tenth.18. A 24-foot ladder leaning against a building forms an 18° angle with the side of the building,How far is the base of the ladder from the base of the building?
Answers
In order to solve this problem, first let's draw the corresponding image to the problem:
Then, to calculate the distance x, we can use the sine relation of the angle of 18°.
The sine relation is the length of the opposite side to the angle over the length of the hypotenuse.
So we have:
[tex]\begin{gathered} \sin (18\degree)=\frac{x}{24} \\ \text{0}.309=\frac{x}{24} \\ x=24\cdot0.309 \\ x=7.42 \end{gathered}[/tex]So the distance wanted is 7.42 ft.
Use Heron's Area Formula to find the area of the triangle. (Round your answer to two decimal places.) A = 81°, b = 76, c = 39
Answers
First, let's find the measure of the third side, using the law of cosine:
[tex]\begin{gathered} a^2=b^2+c^2-2bc\cdot\cos(A)\\ \\ a^2=76^2+39^2-2\cdot76\cdot39\cdot\cos81°\\ \\ a^2=5776+1521-927.34\\ \\ a^2=6.369.66\\ \\ a=79.81 \end{gathered}[/tex]Now, let's use Heron's formula to calculate the area:
[tex]\begin{gathered} p=\frac{a+b+c}{2}=97.405\\ \\ A=\sqrt{p(p-a)(p-b)(p-c)}\\ \\ A=1463.75 \end{gathered}[/tex]if a student scored a 52 on his first test ,make a prediction for his score on the second test .Assume the regression equation is appropriate for the prediction. Round the answer to 2 decimal places.
Answers
Solution
We have the following info given:
x: 75,76, 91, 65,48,75,85,62,51,80,94,43
y: 69, 88, 101, 63, 59, 82, 86, 67, 56, 84, 105, 44
After apply OLS (Ordinary LEast Squares) we got the following regression line:
y= 1.0607x + 0.6442
We want to find the best prediction for a student who scored 52 in the first test so we have this:
y= 1.0607* 52 + 0.6442 = 55.80
Then the best prediction for this case is 55.80
Help Please!
A.
[tex] \frac{3}{4} [/tex]
B.
[tex] \frac{5}{4} [/tex]
C.
[tex] \frac{3}{5} [/tex]
D.
[tex] \frac{4}{5} [/tex]
Answers
Answer:
Step-by-step explanation:
Soh Cah Toa
S stand for sine, C stand for Cosine and the T stand for Tangent
'o' is the opposite, 'a' stand for adjacent (next to) and h stand for hypotenuse (the longest length of the triangle)
[tex]sin(\theta)=\frac{opposite}{hypotenuse}[/tex]
[tex]cos(\theta)=\frac{adjacent}{hypotenuse}[/tex]
[tex]tan(\theta)=\frac{opposite}{adjacent}[/tex]
We care about angle A and we want sine. So we will use the first equation.
The opposite from A is 3 and the hypotenuse is 5.
[tex]sin(A)=\frac{3}{5}[/tex]
I need help with this question but no one is helping me! Can someone please help me
Answers
Answer:
Step-by-step explanation:
Number of yellow marbles =13
Number of teal marbles = 13
Two marbles are drawn randomly
Probability that both marbles are teal
Hence the probability that both marbles are teal is 0.026
If E is the midpoint of DF
with DE = 9x + 24 and
EF = 18x - 39, then find x
and DF.
Answers
Answer:
x=7, DF = 174
Step-by-step explanation:
18x-39=9x+24
9x=63
x=7
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