Suitable average for averaging the shoe sizes of children is


Select one:
a. Mean
b. Harmonic Mean
c. Geometric Mean
d. Percentile
e. Mode

Answer:

52500

Step-by-step explanation:

Let there be x employees in the previous year

Now, the company has 32% more employees whis is 69300

i.e.

[tex]x + \frac{32}{100} x = 69300\\\\ \implies\frac{132x}{100} = 69300 \\\\\implies 132x = 6930000\\\\\implies x = \frac{6930000}{132}\\[/tex]

⇒ x = 52500

There were 52500 employees in the previous year

Answer:

Step-by-step explanation:

To find the density of the wooden board, we need to divide the mass of the board by its volume. The volume of a rectangular prism is calculated by multiplying its length, width, and height.

Given:

Length (l) = 0.3 m

Width (w) = 2.1 m

Height (h) = 0.1 m

Mass (m) = 0.17 kg

Volume (V) = l × w × h

V = 0.3 m × 2.1 m × 0.1 m

V = 0.063 m³

Density (ρ) = mass / volume

ρ = 0.17 kg / 0.063 m³

ρ ≈ 2.7 kg/m³

The density of the wooden board is approximately 2.7 kg/m³.

Answer:

az

Step-by-step explanation:

After 8 visits: General Admission: Each person would pay $200. Annual Public Session Pass: Each person would pay $299.

After 10 visits: General Admission: Each person would pay $250. Annual Public Session Pass: Each person would still pay $299.

To determine when it is better to have a session pass versus just paying general admission, we need to compare the costs for each option.

General Admission with skate rental: $25

Annual Public Session Pass with skate rental: $299

After 8 visits:

For General Admission, the cost per visit would be $25 per visit.

Total cost for 8 visits: $25 x 8 = $200

For the Annual Public Session Pass, the cost is a one-time payment of $299, regardless of the number of visits. Therefore, after 8 visits, the cost remains the same at $299.

Therefore, after 8 visits, it would be more cost-effective to have the Annual Public Session Pass as the cost per person would be $299.

After 10 visits:

For General Admission, the cost per visit remains at $25 per visit.

Total cost for 10 visits: $25 x 10 = $250

For the Annual Public Session Pass, the cost remains the same at $299, regardless of the number of visits.

Therefore, after 10 visits, it would still be more cost-effective to have the Annual Public Session Pass as the cost per person would still be $299.

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The following question may be like this:

When is it better to have a session pass versus just paying general admission? After 8 visits: How much would each person pay? Show your work for calculations. Session Pass______? General Admission______?After 10 visits: How much would each person pay? Show your work for calculations.Session pass _____? General Admission_____?

GENERAL ADMISSION WITH SKATE RENTAL  $25

ANNUAL PUBLIC SESSION PASS WITH SKATE RENTAL $299

LOCKER RENTAL-ONE TIME USE  $5

HELMET RENTAL  $5

SKATE HELPER-PER HOUR $15

Answer:

5n - 8 = 37

5n = 45

n = 9

The number is 9.

Answer:

$3.3

Step-by-step explanation:

4x = 1.32

x = 0.33$ / ft

10x = 10 * 0.33 = 3.3$

Answer:

Step-by-step explanation:

0

Answer:

0

Step-by-step explanation:

25 ÷ 5+7-(4 x 3)

25 ÷ 5+7-(4 x 3)

5+7-(4 x 3)

5+7-(4 x 3)

5+7-12

12-12

0

I wrote in bold the steps you need to follow using PEMDAS (Parentheses, Exponents, Multiplication and Divison left to right, and Addition and Subtraction left to right).

The row operation on the matrix [tex]\left[\begin{array}{ccc|c}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right][/tex] is [tex]\left[\begin{array}{ccc|c}1&0&0&8\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]

From the question, we have the following parameters that can be used in our computation:

[tex]\left[\begin{array}{ccc|c}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]

The row operation is given as

1/2R₁

This means that we divide the entries on the first row by 2

Using the above as a guide, we have the following:

[tex]\left[\begin{array}{ccc|c}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right] = \left[\begin{array}{ccc|c}1&0&0&8\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]

Hence, the row operation on the matrix is [tex]\left[\begin{array}{ccc|c}2&0&0&16\\0&8&0&3\\0&0&5&6\end{array}\right] = \left[\begin{array}{ccc|c}1&0&0&8\\0&8&0&3\\0&0&5&6\end{array}\right][/tex]

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The equivalent expressions for this problem are given as follows:

Equivalent expressions are the expressions that have the same result, hence we must simplify each expression.

The first expression is given as follows:

(4x³ + 7x - 4) - (2x³ - x - 8).

Simplifying the like terms, we have that:

Hence it is equivalent to expression B.

The second expression is simplified as follows:

[tex](x^4 - 3x^2 + x) + (2x^4 + 4x - 7) = 3x^4 - 3x^2 + 5x - 7[/tex]

The third expression is simplified as follows:

(x² - 2x)(2x + 3) = 2x³ + 3x² - 4x² - 6x = 2x³ - x² - 6x.

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The measure of the indicated angle formed by a secant and tangent line is 61 degrees.

The outside or external angles theorem states that "the measure of an angle formed by two secant lines, two tangent lines, or a secant line and a tangent line from a point outside the circle is half the difference of the measures of the intercepted arcs.

It is expressed as;

External angle = 1/2 × ( x - y )

From the diagram:

Intercepted arc GE = y = 73°

Intercepted arc HE = x = 195°

External angle GFE = ?

Plug the given values into the above formula and solve for the indicated angle:

External angle = 1/2 × ( x - y )

External angle GFE = 1/2 × ( 195 - 73 )

External angle GFE = 1/2 × 122

External angle GFE = 61°

Therefore, the outside angle is 61 degrees.

Option C) 61° is the correct answer.

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A rotation is a geometric transformation that preserves the shape and size of a figure while changing its orientation in space. It is a fundamental concept in geometry and is used in various fields, including art, design, and engineering.

A rotation of a figure can be considered as a transformation that rotates the figure around a fixed point, known as the center of rotation. During the rotation, each point of the figure moves along an arc around the center, maintaining the same distance from the center.

To perform a rotation, we specify the angle of rotation and the direction (clockwise or counterclockwise). The center of rotation remains fixed while the rest of the figure rotates around it. The resulting figure is congruent to the original figure, meaning they have the same shape and size but may be in different orientations.

Rotations are commonly described using positive angles for counterclockwise rotations and negative angles for clockwise rotations. The magnitude of the angle determines the amount of rotation. For example, a 90-degree rotation would result in the figure being turned a quarter turn counterclockwise.

In general, a rotation is a geometric transformation that keeps a figure's size and shape while reorienting it in space. It is a fundamental idea in geometry that is applied in a number of disciplines, including as engineering, design, and the arts.

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The calculated vertex of the function y = 2(x + 4)(x - 2) is (-1, -18)

From the question, we have the following parameters that can be used in our computation:

y = 2(x + 4)(x - 2)

Expand the equation

So, we have

y = 2x² + 4x - 16

Differentiate the function and set to 0

So, we have

4x + 4 = 0

So, we have

4x = -4

Evaluate

x = -1

Next, we have

y = 2(-1 + 4)(-1 - 2)

Evaluate

y = -18

This means that the vertex is (-1, -18)

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Given the information in the diagram, the theorem that best justifies why lines j and k must be parallel include the following: D. converse alternate exterior angles theorem.

In Mathematics and Geometry, parallel lines are two (2) lines that are always the same (equal) distance apart and never meet or intersect.

In Mathematics and Geometry, the alternate exterior angle theorem states that when two (2) parallel lines are cut through by a transversal, the alternate exterior angles that are formed lie outside the two (2) parallel lines, are located on opposite sides of the transversal, and are congruent angles.

Since the alternate exterior angles are congruent, we can logically deduce the following based on the converse alternate exterior angles theorem;

93° ≅ 93° (lines j and k are parallel lines).

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Complete Question:

Given the information in the diagram, which theorem best justifies why lines j and k must be parallel?

alternate interior angles theorem

alternate exterior angles theorem

converse alternate interior angles theorem

converse alternate exterior angles theorem

Answer:

a) x² - x - 12 = 0

Step-by-step explanation:

We have equation A = equation B

⇒ x² - 9 = x + 3

⇒ x² - 9 - x - 3 = 0

⇒ x² - x - 12 = 0

The value of m<RQS as required to be determined in the task content is; 70°.

It follows from the task content that the measure of angle RQS is to be determined as required.

Recall, the measure of the central angle subtended by an arc is twice that which it subtends at any point on the circumference.

Therefore, m<RPS = 2 • m<RQS.

m<RQS = 140°/2

m<RQS = 70°.

Ultimately, the measure of angle RQS are; 70°.

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One of the transformations undergone by Triangle 1 is a rotation, which involves turning the triangle around a fixed point while preserving its shape and size.

A rotation is a transformation that turns an object around a fixed point, known as the center of rotation. In the given results, if the triangle appears in a different orientation but retains its shape and size, it indicates a rotation.

During a rotation, each point of the triangle is moved along a circular path around the center of rotation. The distance from the center of rotation remains constant, and the angle between any two corresponding points on the original and rotated triangles is preserved. The direction of rotation can be clockwise or counterclockwise, depending on the given results.

To describe a rotation, we need to specify the angle of rotation and the direction. For example, "Triangle 1 underwent a counterclockwise rotation of 90 degrees" would indicate that the triangle was rotated by 90 degrees in the counterclockwise direction.

The specific rotation can be described by stating the angle of rotation and the direction.

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Both Roger and Jeff will have run a distance of 1/3 mile when Jeff catches up to Roger after 2 minutes.

To solve this problem, we can determine the relative speeds of Roger and Jeff.

Since Roger runs one mile in 9 minutes, his speed is 1/9 miles per minute.

Similarly, Jeff runs one mile in 6 minutes, so his speed is 1/6 miles per minutes.

Let's assume that Jeff catches up to Roger after t minutes.

In that time, Roger would have run (1/9) [tex]\times[/tex] t miles, and Jeff would have run (1/6) [tex]\times[/tex] t miles.

Since Jeff gives Roger a 1-minute head start, we can express their distances covered as:

Distance covered by Roger = (1/9) [tex]\times[/tex] (t+1) miles

Distance covered by Jeff = (1/6) [tex]\times[/tex] t miles

For Jeff to catch up to Roger, their distances covered must be equal. So we can set up the equation:

(1/9) [tex]\times[/tex] (t+1) = (1/6) [tex]\times[/tex] t

To solve for t, we can cross-multiply and simplify:

6(t+1) = 9t

6t + 6 = 9t

6 = 9t - 6t

6 = 3t

t = 2

Therefore, it will take 2 minutes for Jeff to catch up to Roger.

Substituting t = 2 back into the equations, we can find the distances covered by each:

Distance covered by Roger = (1/9) [tex]\times[/tex] (2+1) = 1/3 mile

Distance covered by Jeff = (1/6) [tex]\times[/tex] 2 = 1/3 mile

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The probability that the next spin will land on red is 7%

To express the probability that the next spin will land on red as a percent to the nearest whole number. We need to consider the number of red as proportion of the total.

From the table:

number of red = 4

total = 4 + 18 + 10 + 18 + 11 = 61

Probability that the next spin will land on red = 4/61

As percent to the nearest whole number:

Probability that the next spin will land on red = (4/61) * 100

Probability that the next spin will land on red = 7%

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Complete Question

Check attached image

Answer:

See below

Step-by-step explanation:

To solve for "a", you would first isolate ab on the right-hand side by adding "c" on both sides:

[tex]ab-c=d\\ab-c+c=d+c\\ab=d+c[/tex]

Next, you would divide both sides by "b" to isolate "a":

[tex]ab=d+c\\ab\div b=(d+c)\div b\\a = \frac{d+c}{b}[/tex]

The solution is:

Work/explanation:

To solve the given expression for a, we should isolate it by using basic algebraic operations.

The first step is to add c to each side:

[tex]\sf{ab-c=d}[/tex]

[tex]\sf{ab=d+c}[/tex]

Now, divide each side by b:

[tex]\sf{a=\dfrac{d+c}{b}}[/tex]

I have solved the equation for a.

The speed of Jake's initial trip is x = 24 kilometers per hour, and the speed of the return trip is x + 6 = 30 kilometers per hour.

Let's assume that Jake's speed during the initial trip is represented by "x" kilometers per hour.

On the return trip, he drives 6 kilometers per hour faster, so his speed can be represented as "x + 6" kilometers per hour.

To find the time taken for each trip, we can use the formula Time = Distance / Speed.

For the initial trip, the time taken is 120 kilometers divided by x kilometers per hour, which gives us 120/x hours.

On the return trip, the time taken is 120 kilometers divided by (x + 6) kilometers per hour, which gives us 120/(x + 6) hours.

According to the problem, the return trip takes 1 hour less than the initial trip. So we can set up the equation:

120/x - 1 = 120/(x + 6)

To solve this equation, we can multiply both sides by x(x + 6) to eliminate the denominators:

120(x + 6) - x(x + 6) = 120x

Simplifying this equation:

120x + 720 - x² - 6x = 120x

Combining like terms:

x² + 6x - 720 = 0

Now we can solve this quadratic equation by factoring or using the quadratic formula. By factoring, we find:

(x + 30)(x - 24) = 0

This gives us two potential solutions: x = -30 or x = 24.

Since speed cannot be negative, we discard the solution x = -30.

Therefore, the speed of Jake's initial trip is x = 24 kilometers per hour, and the speed of the return trip is x + 6 = 30 kilometers per hour.

So, Jake drives at a speed of 24 kilometers per hour on the initial trip and 30 kilometers per hour on the return trip.

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The predicted sales in month 5 is -2778.

Obtaining the linear equation which models the data :

b = slope = (y2-y1)/(x2-x1)

b = (926-7408)/(4-1)

b = -2160.67

c = intercept ;

taking the points (x = 2 and y = 3704)

Inserting into the general equation:

3704 = -2160.67(2) + c

3704 = -4321.33 + c

c = 3704 + 4321.33

c = 8025.33

General equation becomes : y = -2160.67x + 8025.33

To obtain sales in month 5:

y = -2160.67(5) + 8025.33

y = -2778

Hence, the predicted sales in month 5 is -2778.

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Answer:

Using the sine function, we have:

sin(angle) = opposite / hypotenuse

sin(22 degrees) = opposite / 18 feet

We can rearrange this equation to solve for the opposite side (height of the building):

opposite = sin(22 degrees) * 18 feet

Calculating this:

opposite ≈ 6.24 feet

Therefore, the base of the ladder from the base of the building is approximately 6.24 feet.

By using the change of base formula: The solution to the equation log(base y) (X-2) = 5 is [tex]X = y^5 + 2.[/tex]

To solve the equation log(base y) (X-2) = 5 using the change of base formula, we can rewrite the equation as log(base b) (X-2) / log(base b) y = 5.

Using the change of base formula, we can choose any base for b.

Let's choose base 10 for simplicity.

So the equation becomes log(base 10) (X-2) / log(base 10) y = 5.

We know that log(base 10) (X-2) represents the logarithm of (X-2) to the base 10, and log(base 10) y represents the logarithm of y to the base 10.

Now, to solve for X, we can isolate it by multiplying both sides of the equation by log(base 10) y:

log(base 10) (X-2) = 5 [tex]\times[/tex] log(base 10) y.

This simplifies to:

log(base 10) (X-2) [tex]= log(base 10) y^5.[/tex]

Since the logarithms on both sides have the same base, we can remove the logarithm and equate the arguments:

[tex]X - 2 = y^5.[/tex]

Now we can solve for X by adding 2 to both sides:

[tex]X = y^5 + 2.[/tex]

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Answer:

Step-by-step explanation:

1. The system of inequalities that models this scenario can be represented as:

Let x be the number of servings of dry food.

Let y be the number of servings of wet food.

The cost constraint:

1x + 5y ≤ 15

The minimum number of dogs constraint:

x + y ≥ 4

2. The graph of the system of inequalities would be a shaded region in the coordinate plane.

To graph the inequality 1x + 5y ≤ 15, we can first graph the equation 1x + 5y = 15 (the corresponding boundary line) by finding two points on the line and connecting them. For example, when x = 0, y = 3, and when y = 0, x = 15. Plotting these points and drawing a line through them will represent the equation 1x + 5y = 15.

Next, we need to shade the region below the line because the inequality is less than or equal to (≤). This shaded region represents the solutions that satisfy the cost constraint.

To graph the inequality x + y ≥ 4, we can again find two points on the line x + y = 4 (the corresponding boundary line). For example, when x = 0, y = 4, and when y = 0, x = 4. Plotting these points and drawing a line through them will represent the equation x + y = 4.

Lastly, we shade the region above the line x + y = 4 because the inequality is greater than or equal to (≥). This shaded region represents the solutions that satisfy the minimum number of dogs constraint.

The solution set is the overlapping region where the shaded areas of both inequalities intersect. This region represents the combination of servings of dry food and wet food that Michelle can purchase within her budget ($15) to feed at least four dogs at the animal shelter.

The inequalities D + W > 4 and D + 5W ≤ 15 model the problem. The graph represents these inequalities, with the overlap of shaded regions showing possible food serving combinations.

Let's define D as the number of servings of dry food and W as the number of servings of wet food. The system of inequalities that models this scenario is:

The graph will show the solution sets to the inequalities. D and W must both be non-negative, hence the graphed area is in the first quadrant. The first inequality requires shading above a line that connects (0,4) and (4,0). This line is solid since numbers equal to 4 are included. The second inequality requires shading below a line that connects (0,3) and (15,0). This is also a solid line because Michelle can spend exactly $15. The overlapping region of the graph is the solution set, quantifying the combinations of dry and wet food servings that Michelle can buy.

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Answer:

c) 54 feet

Step-by-step explanation:

Let the  side of the square be x

perimeter = 4x

⇒ 36 = 4x

⇒ x = 36/4 = 9 feet

Each side is 9 feet

When we join the two squares, it becomes a rectangle with

b = 9

l = 9 + 9 = 18

The perimeter of a rectangle is 2(l + b)

perimeter = 2(18 + 9)

= 2(27)

= 54 feet

Answer:

Option (c) 54 feet

Step-by-step explanation:

Perimeter of one square is 36 feet.

Side of square = 36 / 4 = 9 feet

When combined together one side of each square merged.

So, the perimeter of rectangular shape will be;

(9+9+9) + (9+9+9)

27 + 27

54 feet.

The initial stress is 1.273 × [tex]10^9[/tex] N/[tex]m^2[/tex], the resultant stress is 1.273 × [tex]10^9[/tex] N/[tex]m^2[/tex] and the induced force in the bar when the temperature reaches 50°C is 100.03 kN.

To calculate the initial stress in the tie bar, we can use the formula:

Stress = Load/Area

The area of the tie bar can be calculated using the formula for the area of a circle:

Area = π * [tex](diameter/2)^2[/tex]

Plugging in the values, we get:

Area = π * [tex]10 mm^{2}[/tex] = π *[tex](5 mm)^2[/tex] = 78.54 [tex]mm^2[/tex]

Converting the area to square meters, we have:

Area = 78.54 [tex]mm^2[/tex]* (1 m^2 / 1,000,000 [tex]mm^2[/tex]) = 7.854 × 1[tex]0^-5 m^2[/tex]

Now we can calculate the initial stress:

Initial Stress = 100 kN / 7.854 ×[tex]10^-5 m^2[/tex] = 1.273 × [tex]10^9 N/m^2[/tex]To calculate the resultant stress when the temperature rises to 50°C, we need to consider the thermal expansion of the tie bar. The change in length can be calculated using the formula:

ΔL = α * L0 * ΔT

Where ΔL is the change in length, α is the coefficient of linear expansion, L0 is the initial length, and ΔT is the change in temperature.

The induced force in the bar can be calculated using the formula:

Induced Force = Initial Stress * Area + E * α * ΔT * Area

Plugging in the values, we get:

Induced Force = (1.273 × 10^9 N[tex]m^2[/tex] * 7.854 × [tex]10^-5 m^2[/tex]) + (200 × [tex]10^9[/tex] N/[tex]m^2[/tex] * 14 × [tex]10^-6[/tex] /K * (50 - 15) K * 7.854 × [tex]10^-5 m^2[/tex])

Simplifying the equation, we find:

Induced Force = 100.03 kN

Therefore, the initial stress is 1.273 × [tex]10^9[/tex] N/[tex]m^2[/tex], the resultant stress is 1.273 × [tex]10^9[/tex] N/[tex]m^2[/tex], and the induced force in the bar when the temperature reaches 50°C is 100.03 kN.

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The probable question may be:

A rigidly held tie bar in a heating chamber has a diameter of 10 mm and is tensioned to a load of 100 kN at a temperature of 15°C. What is the initial stress, the resultant stress and what will be the induced force in the bar when the temperature in the chamber has risen to 50°C? E= 200 GN/ m2 and the coefficient of linear expansion of the material for tie bar = 14 × 10−6 /K.

a. The t-value is 1.895.

b. The t-value is 1.734.

c. The t-value is 2.898.

To calculate the t-statistic for a confidence interval, we first need to determine the degrees of freedom (df), which depends on the sample size minus one. We can then use a t-distribution table, software, or calculator to find the t-value at the desired confidence level and degrees of freedom.

a. For a 90% confidence interval with 8 observations, the degrees of freedom is 7. Using the t-distribution table or calculator,

b. For a 90% confidence interval with 18 observations, the degrees of freedom is 17. Using the t-distribution table or calculator,

c. For a 99% confidence interval with 18 observations, the degrees of freedom is 17. Using the t-distribution table, software, or calculator,

Note that as the sample size increases, the degrees of freedom increase and the t-value approaches the value of the standard normal distribution for large sample sizes. This means that for large sample sizes, we can use the z-value instead of the t-value in confidence interval calculations.

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