Answer:
the lens you must select has an angle of 143º measured with respect to the horizontal, this angle is 53º with respect to the vertical.
Explanation:
The glare is caused by the reflection of light in the water, the polarization of the reflected light is polarized in a direction parallel to the surface of the water, the polarization is total for the angles
n = tan [tex]\theta_{p}[/tex]
\theta_{p} = tan⁻¹ n
the refractive index for seawater is 1.33
\theta_{p}= tan⁻¹ 1.33
\theta_{p} = 53º
for this angle the light is totally polarized, for the other angles the polarization is partial.
Based on this, the lenses must eliminate this polarization, so its polarization direction must have 90º with respect to this polarization,
\theta_{lens} = 53 +90
\theta_{lens}= 143º
Therefore, the lens you must select has an angle of 143º measured with respect to the horizontal, this angle is 53º with respect to the vertical.
A lens that could work is one that is polarized 45º with respect to the vertical.
The glass that is worn to eliminate glare must be able to remove glare away from the user.
What are sunglasses?The term sunglasses refers to the kind of glasses that are worn to prevent glare from the sun. This is because the glasses are made of polaroid materials that eliminate glare.
The question is incomplete as the sunglasses are not shown. However, the glass that is worn to eliminate glare must be able to remove glare away from the user.
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Science questions!! Please help!!
Post Assessment on Investigating the Immune System
please help!! Please choose the right answers!! Dont guess if you dont know the answers!!
arcsin 0.9331 in degrees
Answer:
68.9233231661
Explanation:
Just put it into your calculator, shift sin should do it but it will come up like this: [tex]sin^{-1}[/tex] which is the same as arcsin
NO LINKS PLEASE; On the calendar, the full moon is shown happening on the eleventh of the month. What moon would you see around the date shown with the question mark?
First Quarter
New Moon
Waxing Crescent
Waning Gibbous
Wanning gibbous
hope it helps u
Plz mrk me brainlest
Please please help me please please help please please help me please
Answer:
Electromagnetic waves do not require any medium to travel whereas mechanical waves must have a medium to propagate.
So, Basically, it is B I believe.
Hope It Helps!
A box proceeds along the x-axis and the figure below shows a record of its velocity as a function of time. Every grid line along the vertical axis corresponds to 2.00 m/s and each gridline along the horizontal axis corresponds to 0.500 s. (Enter your answer in m/s^2. Indicate the direction with signs of your answers. Note that t=0 at the intersection of the axes.) a) Determine the average acceleration of the box in the time interval t=0 to t=2.50 s. b) Determine the average acceleration of the box in the time interval t=2.50 s to t=7.50 s. c) Determine the average acceleration of the box in the time interval t=0 to t=10.0 s
Answer:
The answer is "[tex]\bold{0, 12.8 \ \frac{m}{s^2}, and \ 6.4 \ \frac{m}{s^2}}[/tex]"
Explanation:
For point a:
The average time interval acceleration for the box [tex]t = 0\ to\ t = 250 \ s:[/tex]
[tex]\to \alpha_{0 \ to \ 2.50}=\frac{v_f - v_i}{t_f-t_i}=\frac{0-0}{2.50-0}=0[/tex]
For point b:
The average time interval acceleration for the box
[tex]t = 250 \ s\ to\ t = 750 \ s :[/tex]
[tex]\to \alpha_{2.50 \ to \ 7.50}=\frac{v_f - v_i}{t_f-t_i}=\frac{32-(-32)}{7.50-2.50}=12.8 \ \frac{m}{s^2}[/tex]
For point c:
The average time interval acceleration for the box [tex]t = 0\ to \ t = 10 \ s :[/tex]
[tex]\to \alpha_{2.50 \ to \ 7.50}=\frac{v_f - v_i}{t_f-t_i}=\frac{32-(-32)}{10-0}=6.4 \ \frac{m}{s^2}[/tex]
What unit is current measured in?
When silver nitrate and beryllium chloride react, silver chloride and beryllium nitrate form. What are the coefficients in this equation? (Note: Be sure to keep the reactants and products in the same order that they appear in the question.)
A. 2,1,1,2
B. 1,2,2,1
C. 1,2,1,2
D. 2,1,2,1
Answer:
D. 2,1,2,1
Explanation:
The equation of the reaction is; 2AgNO3 + BeCl2 + ---------》2AgCl + Be(NO3)2
The rule applied in balancing chemical reaction equation is that the number of atoms of each element on the reactants side must be the same as the number of atoms of the same element on the products sides.
If this rule is properly applied to the reaction between silver nitrate and beryllium chloride to form silver chloride and beryllium nitrate , the coefficients in the equation are; 2,1,2,1
If two speeds are in exact opposite directions, the combined speed is the difference in the speeds.
A. True
B. False
How many tons and pounds (like together, not two different numbers) is 9,920 pounds? Please help,
Answer:
About 5 tons (4.96)
Philosophy:The Big Picture Unit 7
Why does Marx’s workers’ paradise resolve the problems of capitalism?
I KNOW C IS INCORRECT SO CHOOSE OUT OF A,B OR D
A. Everything is free, and no one has to work.
B. Workers are divided into three classes, much like in Plato’s ideas.
C. There is no currency in the paradise so no economic problems.
D. People work for their own good instead of a factory owner’s.
Answer:
B
Explanation:
If you cross of what you don't think are the answers then it makes it easier to narrow it down to what the answers are.
Hope this helps!
When an object is fully converted into energy the amount of energy liberated is
3.6×1017 J, what is the mass of the substance?
Answer:
Mass, m = 4 kg
Explanation:
Given the following data;
Energy = 3.6 * 10^17 Joules
We know that the speed of light is equal to 3 * 10⁸ m/s.
To find the mass of the substance;
The theory of special relativity by Albert Einstein gave birth to one of the most famous equation in science.
The equation illustrates, energy equals mass multiplied by the square of the speed of light.
Mathematically, the theory of special relativity is given by the formula;
[tex] E = mc^{2} [/tex]
Where;
E is the energy possessed by a substance.m is the mass.c is the speed of light.Substituting into the formula, we have;
[tex] 3.6 * 10^{17} = m * 300000000^{2} [/tex]
[tex] 3.6 * 10^{17} = m * 9*10^{16} [/tex]
[tex] m = \frac {3.6 * 10^{17}}{9*10^{16}} [/tex]
Mass, m = 4 kg
a solid cubic centimeter of platinum weighs 21.5 N. if this cube of platinum is placed under water, what volume of water is displaced? what weight of water is displaced? (Hints: 1 cm3 of water has a mass of 1 gram; 1 gram weighs 0.0098 N; density of platinum = 21.5 g/cm3.)
Answer:
Mp =Pp g where p = density of solid Platinum
Wp = Mp Pp g weight of mass M
Volume displaced is 1 cm^3
Weight of water = .0098 N since 1 cm^3 displaced
Or Ww = 1 cm^3 * .001 kg / cm^3 * 9.8 N/kg = .0098 N
What does Binding Energy in the nucleus represent?
Answer:
Nuclear binding energy is the energy required to split a nucleus of an atom into its component parts: protons and neutrons, or, collectively, the nucleons. The binding energy of nuclei is always a positive number, since all nuclei require net energy to separate them into individual protons and neutrons.
I hope you find this helpful.
Biodiversity decline poses a problem in an ecosystem because
Answer:
Biodiversity decline continues due to a rapidly expanding human population. Habitat is damaged in order to meet growing needs for agriculture, urban development, water and materials. Fish, wildlife and plants are overharvested, despite mounting evidence that many harvesting practices are unsustainable.
What is the centripetal force for a roller coaster if the mass is 10 kg and the normal force is 25 N?
Answer:
Fc = 123 Newton
Explanation:
Net force can be defined as the vector sum of all the forces acting on a body or an object i.e the sum of all forces acting simultaneously on a body or an object.
Mathematically, net force is given by the formula;
[tex] Fnet = Fapp + Fg[/tex]
Where;
Fnet is the net force.
Fapp is the applied force.
Fg is the force due to gravitation.
Given the following data;
Normal force = 25N
Mass = 10kg
To find the centripetal force;
From the net force, we have the following formula;
Fc = N + mg
Where;
Fc is the centripetal force.
N is the normal force.
mg is the the weight of the object.
Substituting into the formula, we have;
Fc = 25 + 10(9.8)
Fc = 25 + 98
Fc = 123 Newton
In a Young's double-slit experiment the separation distance y between the second-order bright fringe and the central bright fringe on a flat screen is 0.0176 m, when the light has a wavelength of 425 nm. Assume that the angles are small enough so that is approximately equal to . Find the separation y when the light has a wavelength of 614 nm.
Answer:
Y = 0.0254 m = 25.4 mm
Explanation:
The formula for the fringe spacing in Young's Double-slit experiment is given by the following formula:
[tex]Y = \frac{\lambda L}{d}[/tex]
where,
Y = fringe spacing = 0.0176 m
λ = wavelength = 425 nm = 4.25 x 10⁻⁷ m
L = Distance between screen and slits
d = slit separation
Therefore,
[tex]\frac{0.0176\ m}{4.25\ x\ 10^{-7}\ m} = \frac{L}{d}\\\\\frac{L}{d} = 41411.76[/tex]
Now, for:
λ = 614 nm = 6.14 x 10⁻⁷ m
[tex]Y = (6.14\ x\ 10^{-7}\ m)(41411.76)\\[/tex]
Y = 0.0254 m = 25.4 mm
An inventor claims to have developed a power cycle capable of delivering a net work output of 400 kJ for an energy input by heat transfer of 1200 kJ. The system undergoing the cycle receives heat from a source of 550K and rejects heat to a sink of 350K. Determine if this is a valid claim.
Answer: Valid claim
Explanation:
Given
Work output is [tex]W=400\ kJ[/tex]
Work input is [tex]Q=1200\ kJ[/tex]
The temperature of the source [tex]T_h=550\ K[/tex]
The temperature of the sink is [tex]T_l=350\ K[/tex]
Efficiency is given by
[tex]\eta =\dfrac{\text{W}}{\text{Q}}\times 100[/tex]
Insert the values
[tex]\Rightarrow \eta=\dfrac{400}{1200}\times 100\\\\\Rightarrow \eta=\dfrac{100}{3}\\\\\Rightarrow \eta=33.3\%[/tex]
For ideal cycle it is
[tex]\Rightarrow \eta=\dfrac{T_h-T_l}{T_l}\times 100\\\\\Rightarrow \eta=\dfrac{550-350}{550}\times 100\\\\\Rightarrow \eta=36.36\%[/tex]
The efficiency of the cycle is less than the ideal situation, therefore, it is valid claim.
Please help, confused on this whole lesson
Answer:
1,4,3and 2 would happen hope this helps
A film of oil lies on wet pavement. The refractive index of the oil exceeds that of the water. The film has the minimum nonzero thickness such that it appears dark due to destructive interference when viewed in visible light with wavelength 678 nm in vacuum. Assuming that the visible spectrum extends from 380 to 750 nm, what is the longest visible wavelength (in vacuum) for which the film will appear bright due to constructive interference
Answer:
Explanation:
For destructive interference , the condition is
2μt = nλ
2μt = n x 678
For constructive interference , the condition is
2μt = (2n+1)λ₁ /2
n x 678 = (2n+1)λ₁ /2
λ₁ = 1356 n / ( 2n + 1 )
λ₁ = 1356 / ( 2 + 1/n )
For longest wavelength , denominator should be smallest or n should be largest . The longest value of n is infinity so
λ₁ = 1356 / 2
= 678 nm .
Learning Goal: To understand the concept of moment of inertia and how it depends on mass, radius, and mass distribution.
In rigid-body rotational dynamics, the role analogous to the mass of a body (when one is considering translational motion) is played by the body's moment of inertia. For this reason, conceptual understanding of the motion of a rigid body requires some understanding of moments of inertia. This problem should help you develop such an understanding.
The moment of inertia of a body about some specified axis is I = cmr^2, where c is a dimensionless constant, m is the mass of the body, and r is the perpendicular distance from the axis of rotation. Therefore, if you have two similarly shaped objects of the same size but with one twice as massive as the other, the more massive object should have a moment of inertia twice that of the less massive one. Furthermore, if you have two similarly shaped objects of the same mass, but one has twice the size of the other, the larger object should have a moment of inertia that is four times that of the smaller one.
Two spherical shells have their mass uniformly distrubuted over the spherical surface. One of the shells has a diameter of 2 meters and a mass of 1 kilogram. The other shell has a diameter of 1 meter. What must the mass m of the 1-meter shell be for both shells to have the same moment of inertia about their centers of mass?
Answer:
m₂ = 4 kg
Explanation:
The moment of inertia is defined by
I = ∫ r² dm
for bodies with high symmetry it is tabulated, for a spherical shell
I = 2/3 m r²
in this case the first sphere has a radius of r₁ = 2m and a mass of m₁ = 1 kg, the second sphere has a radius r₂ = 1m.
They ask what is the masses of the second spherical shell so that the moment of inertia of the two is the same.
I₁ = ⅔ m₁ r₁²
I₂ = ⅔ m₂ r₂²
They ask that the two moments have been equal
I₁ = I₂
⅔ m₁ r₁² = ⅔ m₂ r₂²
m₂ = (r₁ / r₂) ² m₁
let's calculate
m₂ = (2/1) ² 1
m₂ = 4 kg
Match these items.
1. effect observed when light from an object in cool air passes through warm air
2. line perpendicular to a surface
3. splitting of light into its component colors angle of incidence
4. alignment of light into a single vibrational direction
5. larger angle as light passes from air to water
6. cause of the sky's color
7. bouncing of light rays reflection
8. bending of light between media
9. ratio of speeds of light
10. inability of light to escape a low-velocity medium due to a large angle of approach refraction
a. scattering
b.dispersion
c.angle of incidence
d.index of refraction
e.mirage
f.reflection
g.normal
h.total inertial reflection
i.polarization
j.refraction
Answer:
1. effect observed when light from an object in cool air passes through warm air
→ h. total internal reflection
2. line perpendicular to a surface
→ g. normal.
3. splitting of light into its component colors angle of incidence
→ b. dispersion.
4. alignment of light into a single vibrational direction
→ i. polarization
5. larger angle as light passes from air to water
→ c. angle of incidence
6. cause of the sky's color
→ f. reflection
7. bouncing of light rays reflection
→ f. reflection
8. bending of light between media
→ j. refraction.
9. ratio of speeds of light
→ d. index of refraction.
10. inability of light to escape a low-velocity medium due to a large angle of approach refraction
→ scattering.
A cargo spacecraft was orbiting the earth. It is equipped with rocket and has an initial mass of 30 metric ton. It wants to catch up with the international space station to deliver the cargo. So its rocket engine was fired for 1 minute. The engine ejects mass at a rate of 30 kg/s with an exhaust velocity of 3.1 km/s. The pressure at the nozzle exit is 5 kPa and the diameter of exit area is 94.4 cm. What is the thrust of the engine in a vacuum
Answer:
Explanation:
A cargo spacecraft was orbiting the earth. It is equipped with rocket and has an initial mass of 30 metric ton. It wants to catch up with the international space station to deliver the cargo. So its rocket engine was fired for 1 minute. The engine ejects mass at a rate of 30 kg/s with an exhaust velocity of 3.1 km/s. The pressure at the nozzle exit is 5 kPa and the diameter of exit area is 94.4 cm. What is the thrust of the eng
4. When Tina went for a walk, she covered the first 300 m in 100 s and the next 200 m in 150
s. What was Tina's average speed?
A 1 m/s
B 2 m/s
C 3 m/s
D 5 m/s
2m/s
300m+200m=500m
100s+150s=250s
500m/250s= 2m/s
The average speed of tina will be 2m/s.
We have Tina who went for a walk.
We have to determine her average speed.
What is Average Speed ?Average speed is the rate of change of displacement with respect to time.
v(avg) = Δx/Δt
According to the question -
Total Distance covered = d = 500 m
Total time taken = t = 250 s
Average speed = 500/250 = 2 m/s
Hence, the average speed of tina will be 2m/s.
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Directions: Fill in the blank with the correct word. Choose from the list of possible answers in the word bank below:
atoms
compound
element
heterogeneous
homogeneous
mixture
molecule
particles
solution
suspension
1. An _______________ is made up of just one kind of atom.
2. Matter is made up of tiny _______________.
3. In a mixture called a ________________ the particles are larger and can settle out.
4. A _______________ of water is made up of two hydrogen atoms and one oxygen atom.
5. Two or more elements chemically combined form a _______________.
6. _______________ are the building blocks of matter.
7. Seawater is an example of a _______________ mixture because it is the same throughout.
8. Vegetable soup is an example of a _______________.
9. In a _______________ one substance is dissolved in another.
10. A mixture that is not the same throughout is called a _______________ mixture.
Answer:
1).atoms (3). mixture. (5). Element
2). particles (4). molecules (6). suspension
Explanation:
(7). Homogeneous (8). Heterogeneous
(9). compound (10). solutions
The volume of a piece of rock was 18.0 cm^3. The student measured the mass of the piece of rock as 48.6 g. Calculate the density of the rock in g/cm^3.
Answer:
Density of rock piece = 2.7 g/cm³
Explanation:
Given:
Volume of rock piece = 18 cm³
Mass of rock piece = 48.6 gram
Find:
Density of rock piece
Computation:
We know relation between density, mass and volume,
Density = Mass / Volume
Density of rock piece = Mass of rock / Volume of rock
Density of rock piece = 48.6 / 18
Density of rock piece = 2.7 g/cm³
g 2. In a laboratory experiment on standing waves a string 3.0 ft long is attached to the prong of an electrically driven tuning fork which vibrates perpendicular to the length of the string at a frequency of 60 Hz. The weight (not mass) of the string is 0.096 lb. a) [5 pts] What tension must the string be under (weights are attached to the other end) if it is to vibrate in four loops
Answer:
The tension in string will be "3.62 N".
Explanation:
The given values are:
Length of string:
l = 3 ft
or,
= 0.9144 m
frequency,
f = 60 Hz
Weight,
= 0.096 lb
or,
= 0.0435 kgm/s²
Now,
The mass will be:
= [tex]\frac{0.0435}{9.8}[/tex]
= [tex]0.0044 \ kg[/tex]
As we know,
⇒ [tex]\lambda=\frac{2L}{n}[/tex]
On substituting the values, we get
⇒ [tex]=\frac{2\times 0.9144}{4}[/tex]
⇒ [tex]=0.4572 \ m[/tex]
or,
⇒ [tex]v=f \lambda[/tex]
⇒ [tex]=0.4572\times 60[/tex]
⇒ [tex]=27.432 \ m/s[/tex]
Now,
⇒ [tex]v=\sqrt{\frac{T}{\mu} }[/tex]
or,
⇒ [tex]T=\frac{m}{l}\times v^2[/tex]
On putting the above given values, we get
⇒ [tex]=\frac{0.0044}{0.9144}\times (27.432)^2[/tex]
⇒ [tex]=\frac{752.51\times 0.0044}{0.9144}[/tex]
⇒ [tex]=3.62 \ N[/tex]
When monochromatic light of an unknown wavelength falls on a sample of aluminum, a minimum potential of 2.27 V is required to stop all of the ejected photoelectrons. (The work function for aluminum is 4.08 eV.) HINT (a) Determine the maximum kinetic energy (in eV) of the ejected photoelectrons. eV (b) Determine the maximum speed (in m/s) of the ejected photoelectrons. m/s (c) Determine the wavelength in nm of the incident light. nm
Answer:
a) KE max = 3.632 * 10^{-19}
b) v = 6.31 * 10^5 m/s
c) Lambda = 195 nm
Explanation:
a) Work done is given by equation
W = V * q = change in kinetic energy = Final KE – Initial KE
Substituting the given values, we get –
V * 1.6*10^{-19} =0 - Initial KE
KE max = 2.27 * 1.6*10^{-19} = 3.632 * 10^{-19}
b) As we know KE = 0.5 mv^{2}
Substituting the given values, we get –
3.632 * 10^{-19} = 0.5 * (9.11 * 10^{-31}) v^2
v = 6.31 * 10^5 m/s
c) Incident energy = W + K max
Substituting the given values we get
hc/lambda = 4.08 * 1.6 * 10^{-19} J + 3.632 * 10^{-19} J
6.626 *10^{-34} * 3*10^8/lambda = 4.08 * 1.6 * 10^{-19} J + 3.632 * 10^{-19} J
Lambda = 1.95 * 10^7
Lambda = 195 nm
Two creatures sit on a horizontal frictional rotating platform. The platform rotates at a constant speed. The creatures do not slip off as it rotates.
ASSUME:
Red has a mass of 5 kg
Red is 1.5 m from the center
Red has a speed of 9 m/s
Blue has a mass of 25 kg
Blue has a speed of 1.8 m/s
The force of friction on Red is EQUAL to the force of friction on Blue
DETERMINE:
How far from the center is Blue
Answer:
M v^2 / R = centripetal force
For Red: M v^2 / R = 5 * 9^2 / 1.5 = 270
For Blue M v^2 / R = 270 = 25 * 1.8^2 / Rb
So Rb = 25 * 1.8^2 / 270 = .3 m
A weight lifter lifts a 1470N barbell above his head from the floor the a height of 2m. he holds the barbell there for 5 sec. how much work does he do?
Answer:
Workdone = 2940 Nm
Explanation:
Given the following data;
Force = 1470 N
Distance = 2m
Time = 5 seconds
To find the work done;
Mathematically, workdone is given by the formula;
Workdone = force * distance
Substituting into the formula, we have;
Workdone = 1470 * 2
Workdone = 2940 Nm
The ratio of carbon-14 to nitrogen-14 in an artifact is 1:7. Given that the half-
life of carbon-14 is 5730 years, how old is the artifact?
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Answer:
17,190 years old
Explanation:
A p e x