Answer:
5.65mg of the isotope remains
Explanation:
The radioactive decay follows the equation:
Ln[A] = -kt + ln[A]₀
Where [A] is amount of the isotope after time t, k is decay constant, and [A]₀ is initial amount of the isotope.
k = ln 2 / Half-life
k = ln 2 / 3.82 days
k = 0.18145days⁻¹
Replacing:
Ln[A] = -0.18145days⁻¹*10.1days + ln[35.3mg]
ln[A] = 1.7312
[A] = 5.65mg of the isotope remains
Collision theory states that as molecules or ions bump into each other, a reaction will only occur if the collision has the correct amount of energy and impact is at the right angle and location. Describe how collision theory helps predict how temperature, pressure, and concentration impact reaction rates. Question 5 of 11 Collision theory states that as molecules or ions bump into each other, a reaction will only occur if the collision has the correct amount of energy and impact is at the right angle and location. Describe how collision theory helps predict how temperature, pressure, and concentration impact reaction rates. As temperature increases, the number of collisions _______ and the energy of the collisions _______.
Answer: As temperature increases, the number of collisions increases and the energy of the collisions increases.
Explanation:
According to collision theory, for a reaction to take place it is necessary to have collisions between the reacting species or atoms.
A collision will only be effective if species coming together have a certain minimum value of internal energy equal to the activation energy of the reaction.
More is the number of collisions taking place in a chemical reaction more will be the kinetic energy of its molecules. As kinetic energy is the energy acquired due to motion of atoms or a substance.
Also, collisions increases with increase in temperature as:
[tex]K.E = \frac{3}{2}kT[/tex]
Kinetic energy is directly proportional to temperature. So, more is the temperature more will be energy of molecules.
Thus, we can conclude that as temperature increases, the number of collisions increases and the energy of the collisions increases.
HELPPP
After 25.3 seconds, the concentration of a starting material
was measured to decrease from 2.00 M to 1.17 M.
Answer:
Rate = 0.83M/s
Explanation:
Rate of a chemical reaction is the 'absolute value' of change in concentration per unit time. That is ...
Rate = |Change in concentration / unit time|
= |Δ[Conc]/Δtime|
= |(1.17M -2.00M) / 25.3s|
= |- 0.83M/s|
= 0.83M/s*
------------
*Note: Some scholars define rate of reaction as a 'scaler' quantity having only magnitude as rate of reaction in a physical sense (up, down, right, left) is not definitive. In physical mechanics, rate is assigned a direction and magnitude of action and becomes a 'vector' quantity.
The speed at which the reaction occurs is called the rate of reaction. The rate of reaction for the decreased concentration is 0.83 M/s.
What is the reaction rate?The reaction rate is the increase or decrease in the concentration of the products per unit of time. The formula for a reaction rate is given as,
[tex]\rm Rate = \rm \dfrac {\text{Change in concentration}} {Unit \; time}[/tex]
Given,
Initial concentration = 1.17 m
Final concentration = 2.00 M
Time = 25.3 sec
Substituting values in the above equation:
[tex]\begin{aligned} &= \dfrac{1.17 - 2.0} {25.3}\\\\&= -0.83\\\\&= 0.83 \;\rm M/s\end{aligned}[/tex]
Therefore, 0.83 M/s is the reaction rate.
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Aerobic respiration is the cellular process in which
A)
oxygen is added to citric acid, providing energy to the cell.
B)
oxygen is added to NAD+ to form NADH.
C)
oxygen is added to an organic fuel, providing energy to the cell.
D)
oxygen is added to ATP, providing energy to the cell.
Answer:
oxygen is add to ATP providing energy to the cell
I NEED THIS NOW AND NO LINKS OR ILL REPORT
Which material creates the most waste and pollutants when creating one
ton of bottles? *
aluminum
glass
plastic
Answer:
plastic
........................
Please answer before 3PM C June 7th, 2021. Which statement about the cell theory is correct?
Answer:
Hi, there the answer is D.
Explanation:
Use the Hertzsprung-Russell diagram and temperature and luminosity data to identify each star
Answer:
Q:Use the Hertzsprung-Russell diagram and temperature and luminosity data to identify each star
Explanation:
Take it as u please
Answer:
white dwarf- star C
main sequence- star A
giant- Star B
Explanation:
Got it right
what is work and state the law of conservation mass?
Answer:
Work is a force causing the movement or displacement of an object
law of conservation mass:
1. Atoms cannot be created or destroyed in a chemical reaction.
2. Molecules cannot be created or destroyed in a chemical reaction.
3. Compounds cannot be created or destroyed in a chemical reaction.
4. Heat cannot be created or destroyed in a chemical reaction.
The reaction of iron (III) oxide with carbon monoxide produces iron and carbon dioxide.
Fe,O3(s) + 3CO(g) - 2Fe(s) + 3C0 (9)
If you have 39.5g of Fe2O3, how many grams of CO are required for a complete reaction?
Answer:
21g
Explanation:
no.ofmol fe2o3=39.5/(56×2+16×3)=0.25mol
from equation 1mole fe2o3 react with 3mole co
so,0.25mol fe2o3 react with 0.75mol co
mass of co=0.75×(12+16)=21g
Answer:
Approximately [tex]20.8\; \rm g[/tex].
Explanation:
[tex]\rm Fe_2O_3 \, (s) + 3\; CO\, (g) \to 2\; Fe\, (s) + 3\; CO_2\, (g)[/tex].
Relative atomic mass:
[tex]\rm Fe[/tex]: [tex]55.845[/tex].[tex]\rm C[/tex]: [tex]12.011[/tex].[tex]\rm O[/tex]: [tex]15.999[/tex].Formula mass:
[tex]\begin{aligned}M({\rm Fe_2O_3}) &= 2 \times 55.845 + 3 \times 15.999\\ &= 159.687\; \rm g \cdot mol^{-1}\end{aligned}[/tex].
[tex]\begin{aligned}M({\rm CO}) &= 12.011 + 15.999\\ &= 28.010\; \rm g \cdot mol^{-1}\end{aligned}[/tex].
Number of moles of [tex]\rm Fe_2O_3[/tex] formula units in [tex]39.5\; \rm g[/tex] of this compound:
[tex]\begin{aligned}&n({\rm Fe_2O_3}) \\ &= \frac{m({\rm Fe_2O_3})}{M({\rm Fe_2O_3})} \\ &= \frac{39.5\; \rm g}{159.687\; \rm g \cdot mol^{-1}}\approx 0.247\; \rm mol\end{aligned}[/tex].
Refer to the balanced equation for this reaction.
Coefficient of [tex]\rm Fe_2O_3[/tex]: [tex]1[/tex].Coefficient of [tex]\rm CO[/tex]: [tex]3[/tex].Hence, for every formula unit of [tex]\rm Fe_2O_3[/tex] that this reaction consumes, [tex]3\; \rm mol[/tex] of [tex]\rm CO[/tex] molecules would also need to be consumed. Therefore, if neither reactant is in excess:
[tex]\displaystyle \frac{n({\rm CO})}{n({\rm Fe_2O_3})} = \frac{3}{1} = 3[/tex].
Calculate the number of moles of [tex]\rm CO[/tex] required to react with that [tex]39.5\; \rm g[/tex] of [tex]\rm Fe_2O_3[/tex]:
[tex]\begin{aligned}&n({\rm CO}) \\ &= n({\rm Fe_2O_3}) \cdot \frac{n({\rm CO})}{n({\rm Fe_2O_3})} \\[0.5em] &\approx 0.247\; \rm mol \times 3 \approx 0.742\; \rm mol\end{aligned}[/tex].
Make use of the formula mass of [tex]\!\rm CO[/tex] to find the mass of that [tex]0.742\; \rm mol[/tex] of [tex]\rm CO[/tex] molecules:
[tex]\begin{aligned} m({\rm CO}) &= n({\rm CO}) \cdot M({\rm CO}) \\ &\approx 0.742\; \rm mol \times 28.010\; \rm g \cdot mol^{-1} \\ &\approx 20.8\; \rm g\end{aligned}[/tex].
A sample of propane, C3Hg, contains 14.4 moles of carbon atoms. How many total moles of atoms does
the sample contain?
Express the total number of moles of carbon and hydrogen numerically.
Answer:
43.2 mol C
115 mol H
158 mol of atoms
Explanation:
Step 1: Given data
Moles of C₃H₈: 14.4 mol
Step 2: Calculate the number of moles of C
The molar ratio of C₃H₈ to C is 1:3. The moles of C are 3/1 × 14.4 mol = 43.2 mol.
Step 3: Calculate the number of moles of H
The molar ratio of C₃H₈ to H is 1:(. The moles of H are 8/1 × 14.4 mol = 115 mol.
Step 4: Calculate the total number of moles of atoms
n = nC + nH = 43.2 mol + 115 mol = 158 mol
Please help!!! I"m on a plato mastery test. If you give me an actual answer i will give you brainliest!!!
Identify an element on the periodic table that is chemically similar to boron (B).
The ones that are in red are the possible answers
Answer:
SI
Explanation:
I would say silicon because it is also another metalloid. Boron is a metalloid.
How many molecules are in 0.5 grams of ammonia, NH3?
Answer:
I dont no ma men
Explanation:
Sorry cause a dont no
CH3CH2CH2CH2CH2NH2 (organic molecule name)
Explanation:
Heterocyclic aromatic amine: The amine nitrogen is part of an aromatic ring. ... Use a number to locate the amino group on the parent chain. The IUPAC name of CH3CH2CH2CH2CH2NH2 is 1-pentylamine.
The name of the compound CH₃CH₂CH₂CH₂CH₂NH₂ is 1-pentylamine.
How are organic compounds named?Organic compounds are named according to the set of rules provided by the international union of pure and applied chemistry (IUPAC). According to it,1) the chain of carbon atoms having highest number of carbon atoms is selected.
2)according to the number of carbon atoms in chain, parent chain is named.
3) Numbering is done in such a way that substituent if present the carbon on which it is present gets the lowest number.
4) The functional group which is present is mentioned as a suffix along with the carbon position on which it is present.
For example,CH₃CH₂CH₂CH₂CH₂NH₂ is named as follows :
1) As there is only one chain present, amine functional group being present it is numbered from the left hand side as the amine group will get the lowest number.
2) The name is given by writing the parent name that is pentane along with the position of amine group which is carbon-1.
Thus, it is named as 1-pentylamine.
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A sample of oxygen is subjected to an absolute pressure of 2.4 atm. If the specific internal energy of the sample at 310 K is 5700 J/mol relative to a known reference state, what is the specific enthalpy of the oxygen relative to that same reference state?
Answer:
The required specific enthalpy for oxygen = 8277.34 J/mol
Explanation:
Given that :
Pressure = 2.4 atm
Temperature = 310 K
specific internal energy U = 5700 J/mol
To find the specific enthalpy using the formula:
H = U + PV
where;
H is known as the specific enthalpy
Recall that from ideal gas equation
PV = nRT
For specific enthalpy, it is constant that n = 1
Thus;
PV = RT
replacing that into the equation (H = U + PV), we have:
here;
R = 8.314 J/mol K (constant)
H = U + RT
H = 5700 J/mol +( 8.314 J/mol K × 310 K)
H = 5700 J/mol + ( 2577.34 J/mol)
H = 8277.34 J/mol
Caustic soda, NaOH, can be prepared commercially by the reaction of Na2CO3 with slaked lime, Ca(OH)2. How many grams of NaOH can be obtained by treating 1.350 kg of Na2CO3 with Ca(OH)2
Caustic soda, NaOH, can be prepared commercially by the reaction of Na2CO3 with slaked lime, Ca(OH)2. 1.509 kg of NaOH can be obtained by treating 1.350 kg of Na2CO3 with Ca(OH)2.
what is the function of caustic soda ?Caustic soda means an alkali salt or Lye, which is the common name of sodium hydroxide due corrosive nature of this salt on animal and plant tissues.
It is used in a wide range of applications and the chemical formula of sodium hydroxide is NaOH, used as cleansing agent and also in manufacturing of washing soda.
sodium hydroxide cam also applied as the reagent in the laboratories, preparation of soda lime, used in extraction of aluminum by purifying bauxite.
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Ethylene produced by fermentation has a specific gravity of 0.787 at 25 degree Celsius. What is the volume of 125g of ethanol at this temperature? (The density of water at 25 degree Celsius is 0.997 g/mL)
Answer: The volume of given amount of ethanol at this temperature is 159.44 mL
Explanation:
Specific gravity is given by the formula:
[tex]\text{Specific gravity}=\frac{\text{Density of a substance}}{\text{Density of water}}[/tex]
We are given:
Density of water = 0.997 g/mL
Specific gravity of ethanol = 0.787
Putting values in above equation, we get:
[tex]0.787=\frac{\text{Density of a substance}}{0.997g/mL}\\\\\text{Density of a substance}=(0.787\times 0.997g/mL)=0.784g/mL[/tex]
Density is defined as the ratio of mass and volume of a substance.
[tex]\text{Density}=\frac{\text{Mass}}{\text{Volume}} [/tex] ......(1)
Given values:
Mass of ethanol = 125 g
Density of ethanol = 0.784 g/mL
Putting values in equation 1, we get:
[tex]\text{Volume of ethanol}=\frac{125g}{0.784g/mL}=159.44mL[/tex]
Hence, the volume of given amount of ethanol at this temperature is 159.44 mL
Having enough folic acid in your system by the early weeks of pregnancy is critical to prevent spina bifida.
Answer:
Yes.
Explanation:
Yes, enough folic acid in the body by the early weeks of pregnancy helps to prevent spina bifida. The body of woman uses folate during the pregnancy which produces red and white blood cells that help your baby to grow. Folate also lowers the risk of neural tube defect (NTD) in the unborn baby. Neural tube defect (NTDs) are the serious birth defects that greatly affect the spinal cord, brain and skull of the baby.
Reaction Progression
Which statement best describes the diagram?
The pathway A-B-D involves a catalyst and is slower than A-C-D.
The pathway A-B-D involves a catalyst and is faster than A-C-D.
The pathway A-C-D involves a catalyst and is slower than A-B-D.
The pathway A-C-D involves a catalyst and is faster than A-B-D
Obtain 2 test tubes. 2. Add 2 mL of animal blood plasma into the first test tube a. Use a pH test strip to measure the pH of the blood plasma. ______
Answer:
7.4
Explanation:
Plasma proteins are part of the buffer systems of blood plasma. Plasma contains both positively and negatively charged amino and carboxyl groups. These compounds' charged portions can attract and link hydrogen(H) and hydroxyl ions(OH-), therefore act as buffers.
Plasma serves as a weak and ineffective buffer. The pH of a buffer should always be around 7.4 which is nearly neutral. As such we may deduce from the first experimental observation that there is no change in pH.
Calculate the pH of a 0.35 mol/L solution of butanoic acid
Answer:
2.6
Explanation:
Step 1: Given and required data
Concentration of butanoic acid (Ca): 0.35 MpKa of butanoic acid: 4.82Step 2: Calculate the acid dissociation constant (Ka) of butanoic acid
We will use the following expression.
pKa = -log Ka
Ka = antilog - pKa
Ka = antilog -4.82 = 1.51 × 10⁻⁵
Step 3: Calculate [H⁺] of the solution
For a weak acid, we can use the following expression.
[H⁺] = √(Ca × Ka)
[H⁺] = √(0.35 × 1.51 × 10⁻⁵) = 2.3 × 10⁻³ M
Step 4: Calculate the pH of the solution
pH = -log [H⁺] = -log 2.3 × 10⁻³ = 2.6
which type of chemical bond would be formed between two elements having electron configuration of 1s2 2s2 2p6 3s2 and 1s2 2s2 2p4
Which of the following compounds is SOLUBLE?
A. SrSO4
B. CaCO3
C. BaS
D. CaCl2
Answer:
A).
Strontium Sulphate is soluble
Once the race had been completed, the students opened their canisters to see if anything remained inside. They wanted to decide if they should modify their techniques for another race. Designs 1, 2, and 3 all still had some solid Alka-Selzter residue in the canister. Design 4 did not. The teacher asked the students to analyze their results as an engineer would. What worked well in the design? What could be improved? Predict what Design Team 3 decided to change.
A)Use hot water
B)Use more water
C)Not to crush the tablet and to use hot water
D)Not to crush the tablet and to use more water
HURRY! GIVING BRAINLY
Answer:
a
Explanation:because i did the test
Question 26 (1 point)
What is the number of electrons shared between the atoms
in an 12 molecule?
Оа
7
Ob
2.
Ос
8
Od
4
Question 27 1 point)
Answer:
obviously 2 is the answer
4-A major textile dye manufacturer developed a new yellow dye. The dye has a percent composition of 75.95% X, 17.72% N, and 6.33% H by mass with a molar mass of about 240 g/mol. Determine the molecular formula of the dye.
Answer:
C₁₅N₃H₅
Explanation:
Let's assume we have 240 g of the dye (1 mol), in that case we'd have:
240 g * 75.95/100 = 182.28 g of C240 g * 17.72/100 = 42.53 g of N240 g * 6.33/100 = 15.19 g of HNow we convert the masses of each element into moles, using their respective molar masses:
182.28 g C ÷ 12 g/mol = 15.19 mol C ≅ 1542.53 g N ÷ 14 g/mol = 3.04 mol N ≅ 3 15.19 g C ÷ 1 g/mol = 15.19 mol H ≅ 15Thus the molecular formula is C₁₅N₃H₅.
2) Calculate the density of a rod of metal (in g/cm) with a mass of 196.41g, a diameter of 3.10
cm and a height of 7.55 cm. Volume cylinder = rh. Remember the radius is half the length
of the diameter.
Volume =
Density
Answer:56.98496
Explanation:
half if diameter is radius or 1.55 and double the radius is 3.10 or the length of the diameter. you have a height given, so use the radius and heaight to plug it in the circular cylinder calculator and you get 56.98496
Calcium has 6 different isotopic forms, listed with their fractional composition values, 40Ca-0.96941; 42Ca-0.00647; 43Ca-0.00135; 44Ca-0.2086 ; 46Ca-0.00004; and 48Ca-0.00187. Identify the most and least abundant isotopes of calcium.
Answer:
The most abundant isotope is ⁴⁰Ca and the least abundant is ⁴⁶Ca
Explanation:
The mass, in percentage, of eah isotope of Calcium is their fractional composition multiplied by 100:
40Ca-0.96941*100 = 96.941% of ⁴⁰Ca
42Ca-0.00647*100 = 0.647% of ⁴²Ca
43Ca-0.0013*100 = 0.13% of ⁴³Ca
44Ca-0.02086*100 = 2.086% ⁴⁴Ca
46Ca-0.00004*100 = 0.004% ⁴⁶Ca
48Ca-0.00187*100 = 0.187% of ⁴⁸Ca
That means the most abundant isotope is ⁴⁰Ca and the least abundant is ⁴⁶Ca
Common decay process definition in your own words
Answer:
Your welcome! :)
Explanation:
THE PROCESS IS: Radioactive decay involves the emission of a particle and/or energy as one atom changes into another. In most instances, the atom changes its identity to become a new element.
THE DEFINITION IS: Decay, decompose, rot, putrefy, spoil mean to undergo destructive dissolution. decay implies a slow change from a state of soundness or perfection. a decaying mansion decompose stresses a breaking down by chemical change and when applied to organic matter a corruption.
How does glue, borax, and water turn into slime, scientifically?
How does glue, borax, and water turn into slime, scientifically?
AnswerIt is the matter of time and WeatherA certain liquid has a normal freezing point of and a freezing point depression constant . A solution is prepared by dissolving some glycine () in of . This solution freezes at . Calculate the mass of that was dissolved.
The question is incomplete, the complete question is:
A certain substance X has a normal freezing point of [tex]-6.4^oC[/tex] and a molal freezing point depression constant [tex]K_f= 3.96^oC.kg/mol[/tex]. A solution is prepared by dissolving some glycine in 950. g of X. This solution freezes at [tex]-13.6^oC[/tex]. Calculate the mass of urea that was dissolved. Round your answer to 2 significant digits.
Answer: 129.66 g of glycine will be dissolved.
Explanation:
Depression in the freezing point is the difference between the freezing point of the pure solvent and the freezing point of the solution.
The expression for the calculation of depression in freezing point is:
[tex]\text{Freezing point of pure solvent}-\text{freezing point of solution}=i\times K_f\times m[/tex]
OR
[tex]\text{Freezing point of pure solvent}-\text{freezing point of solution}=i\times K_f\times \frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Mass of solvent (g)}}[/tex] ....(1)
where,
i = Van't Hoff factor = 1 (for non-electrolytes)
Freezing point of pure solvent = [tex]-6.4^oC[/tex]
Freezing point of solution = [tex]-13.6^oC[/tex]
[tex]K_f[/tex] = freezing point depression constant = [tex]3.96^oC/m[/tex]
[tex]M_{solute}[/tex] = Molar mass of solute (glycine) = 75.07 g/mol
[tex]w_{solvent}[/tex] = Mass of solvent = 950 g
Plugging values in equation 1:
[tex]-6.4-(-13.6)=1\times 3.96\times \frac{\text{Given mass of glycine}\times 1000}{75.07\times 950}\\\\\text{Given mass of glycine}=\frac{7.2\times 75.07\times 950}{1\times 3.96\times 1000}\\\\\text{Given mass of glycine}=129.66g[/tex]
Hence, 129.66 g of glycine will be dissolved.
Define how a parasitic relationship between a host and a parasite works.
Answer:
A parasitic relationship is one in which one organism, the parasite, lives off of another organism, the host, harming it and possibly causing death. The parasite lives on or in the body of the host.