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A 4.0 L sample of gas has a pressure of 300 kPa at 250K. What will the volume be if the pressure is increased to 500 kPa and the temperature is decreased to 200 K?

The solubility of nitrogen gas in water is 1.90 mL/dL at 1.00 atm and 13.3 mL/dL at 7.00 atm.

We want to relate the solubility of a gas with its partial pressure.

We can do so using Henry's law.

Henry's law states that the amount of dissolved gas in a liquid is proportional to its partial pressure above the liquid.

C = k × P

where,

The solubility of nitrogen gas is 1.90 mL/dL of blood at 1.00 atm.

Since the solvent is basically water, we can understand that the concentration of nitrogen gas is 1.90 mL/dL at 1.00 atm.

We can use this information to calculate Henry's Law constant.

k = C/P = (1.90 mL/dL)/1.00 atm = 1.90 mL/dL.atm

We want to calculate the solubility of nitrogen gas at a pressure of 7.00 atm.

We will use Henry's law.

C = k × P = (1.90 mL/dL.atm) × 7.00 atm = 13.3 mL/dL

The solubility of nitrogen gas in water is 1.90 mL/dL at 1.00 atm and 13.3 mL/dL at 7.00 atm.

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The freezing point of the solution is - 0.12 oC.

We know that;

ΔT = K m i

ΔT = Freezing point depression

K = Freezing constant

m = molality

i = Van't Hoff factor

Number of moles of sucrose= 2.23g/342 g/mol = 0.0065 moles

Mass of solvent in Kg = 0.1 Kg

Molality of the solution = 0.0065 moles/ 0.1 Kg = 0.065 m

Now;

ΔT = 1.86 oC/m × 0.065 m × 1

ΔT = 0.12 oC

Freezing point of pure water = 0 oC

Freezing point of solution =  0 oC -  0.12 oC = - 0.12 oC

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The chemical transformation of a carbon-carbon double bond is by addition reaction. The statement best describes the driving force is that the reaction is favorable because the total bond strength in the products is greater than in the reactants.

The bond energies of a molecule is simply known as the energies needed to break all the covalent bonds in the molecule.

When the bond energies of the product molecules is known to be greater than the bond energies of the reactants, the reaction is regarded as exothermic.

The full question is below

Which statement best describes the driving force behind the electrophilic addition of strong acid to an alkene?

The reaction is favorable because the pi bond is stronger than a sigma bond and it takes more energy to break it.

The reaction is favorable because a less stable, high-energy intermediate is formed.

The reaction is favorable because the first step is the rate-determining step.

The reaction is favorable because the total bond strength in the products is greater than in the reactants.

The reaction is favorable because the overall reaction is endothermic.

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Answer:

First, both ingredients are excellent at dissolving tough grime. However, vinegar alone will simply run off of most surfaces, while dish soap is too thick to use as a spray. But when you mix them together, you get an effective, sprayable cleaner that sticks to any surface!

Answer:

HowHow many moles of KOH are in 21.0g of KOH?

Answer:

0.374 moles

Explanation:

I have included the dimensional analysis below, and by MM I mean Molar Mass of the atom.

Hope this helps!

Answer:315 - 282 = 173?

Explanation:

Answer:

The partial pressure of water is much less than 1atm, so the free energy change for the process must be negative with ΔGrxn<0.

Explanation:

Water vapor will condense into liquid water when the water vapor is in its standard state, with a pressure of 1atm. Under normal circumstances, the partial pressure of water vapor is much less that 1atm. It is in a nonstandard state. The free energy change of this reaction has to be negative in order to make the reaction spontaneous.

The criteria of the spontaneous process are the change in the Gibbs free energy should be negative. Above the normal boiling point, the TΔS will be greater than ΔH and ΔG<0.

Gibbs free energy can be described as a state function therefore it doesn’t depend on the path. The change in free energy is equal to the change in enthalpy minus the product of entropy change and temperature of the system.

ΔG = ΔH - Δ (TS)

If the process is carried out at constant temperature, ΔT = 0:

ΔG = ΔH – TΔS

ΔG > 0 for the reaction is non-spontaneous, ΔG < 0 for the reaction is spontaneous, exergonic and ΔG = 0 for the reaction is at equilibrium.

Spontaneous can be described as a reaction that occurs by itself without any external action towards it. The non-spontaneous process needs constant external energy applied to continue and as the external action, the process will cease.

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A) The moles of NaOH are equal to moles of HCl.

Explanation:

NaOH + HCl ↦NaCl + H20

According to the equation given, we have N2 + 3H2 → 2NH3.

Therefore, to determine the moles of NH3 we have to do the following-

1.3 mol H2 × 2 mol NH3 / 3 mol H2 = 0.87 mol

Answer: .87 moles of NH3 are produced from 1.3 moles of H2.

I hope this helps!

Answer:i think its d not sure tho

Explanation:

Based on our knowledge of strong and weak acids, we can confirm that the Ka value for acetic acid will be relatively low since it is a weak acid.

Acids can be strong or weak. This is determined by its tendency to break apart into ions or stay together to form molecules. Although somewhat counter-intuitive, strong acids are those that are most likely to break apart and therefore contain a high number of ions within their solutions.

Weak acids, on the other hand, are those that tend to stay together in the form of molecules and therefore possess very low ion counts in their solutions. The acid dissociation constant, Kₐ, is used to measure whether an acid is weak or strong and how much so. In the case of Acetic acid, the ka measurement will offer a low value, indicating a weak acid.

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Answer:

the answer would be B

Explanation:

The power from the charger use electricity and the electricity transforms to energy that can be moved

Answer:

I am so sorry if I am wrong but my guess is no precipitate is formed.

Explanation:

If the following ions[tex]Mg^{+2}[/tex],[tex]Cl^{-}[/tex], [tex]Sr^{+2}[/tex], [tex]OH^{-}[/tex] are placed in a test tube, the precipitate formed is [tex]Mg(OH)_{2}[/tex]

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Answer:

It takes six molecules of carbon dioxide and six molecules of water to make one molecule of glucose.

Balanced:

2NaOH + CO2 → Na₂CO₃ + H₂O

Explanation:

To balance an equation, the amount of atoms on each side must be equal.

Atom Count on Reactant Side:

Atom Count On Product Side:

As you see, to simply balance the equation, put the 2 in order for the atom count on the reactant side to be equal to the product side. The 2 will add one more of each atom so that its the same as the product side.

Answer:

Ionization enthalpy

Explanation:

that should be right

Answer:The plates are not fixed but are constantly moving atop a layer of solid and molten rock called the mantle. The Ring of Fire is a string of volcanoes and sites of seismic activity, or earthquakes, around the edges of the Pacific Ocean. ... A hotspot is a place in the middle of a tectonic plate where hot magma rises.

Explanation:

Answer:

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9.false

10.true

Explanation:

I took the test

A cylindrical weight with a mass of 3 kg is dropped onto the piston from a height of 10 m. The entropy of the gas is 1.18 J/K and the change in the entropy of the environment is -1.18 J/K.

A cylindrical weight with a mass (m) of 3 kg is dropped, that is, its initial velocity (u) is 0 m/s and travels 10 m (s). Assuming the acceleration (a) is that of gravity (9.8 m/s²). We can calculate the velocity (v) of the weight in the instant prior to the collision with the piston using the following kinematic equation.

[tex]v^{2} = u^{2} + 2as = 2 (9.8 m/s^{2} ) (10m) \\\\v = 14 m/s[/tex]

The object with a mass of 3 kg collides with the piston at 14 m/s, The kinetic energy (K) of the object at that moment is:

[tex]K = \frac{1}{2} m v^{2} = \frac{1}{2} (3kg) (14m/s)^{2} = 294 J[/tex]

The kinetic energy of the weight is completely converted into heat transferred into the gas cylinder. Thus, Q = 294 J.

Given all the process is at 250 K (T), we can calculate the change of entropy of the gas using the following expression.

[tex]\Delta S_{gas} = \frac{Q}{T} = \frac{294 J}{250K} = 1.18 J/K[/tex]

The change in the entropy of the environment, has the same value but opposite sign than the change in the entropy of the gas. Thus, [tex]\Delta S_{env} = -1.18 J/K[/tex]

A cylindrical weight with a mass of 3 kg is dropped onto the piston from a height of 10 m. The entropy of the gas is 1.18 J/K and the change in the entropy of the environment is -1.18 J/K.

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Answer:

what's the question?

Explanation:

I'll help

Answer: .039L

Explanation:

Answer:

42.0g/mol

Explanation:

The steps for this question is to use the ideal gas law, and then use n=m/M to find molar mass.

PV = nRT

n= PV/RT

Change 23 degrees to 296.15 K and 684mmHg to kpa

n = (91.1925kpa)(2.00L)/(8.314Lkpa/mol K)(296.15K)

n= 0.074mol

n = m/M

M = m/n

M = 41.98489g/mol

Answer:

Forged parts are often tougher than cast parts. This can be determined by performing tensile tests on various areas on the parts. Additionally, the microstructures of forged and cast parts can be used to determine if a part was forged or cast. The microstructure of a cast part will have a more uniform grain structure.

Explanation:

Answer:

The bleaching action of sulphur di oxide is temporary because it involves the process of reduction. sulphur di oxide removes oxygen from the coloured substance and makes it colourless. Atmospheric oxygen slowly takes place of the removed oxygen and because of which the material regains the co

Answer:

c

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AMOUNG US AND THE ANSWER IS C

Explanation:

Answer:

its c

Explanation:

Answer:

The answer is option A

Explanation:

This is because the measure from crest to crest is also known as the wavelength, and the color of a wave always depends on its wavelength, if you see the electromagnetic spectrum

Hope this helps!

Answer:

d. 83 °c

Explanation:

Answer:

D. 83 c

Explanation:

took the test