PLEASE NEED HELP ASAP IM GIVING ALL MY POINTS THIS SHOULD BE A EASY QUESTION.​

Answer:

Step-by-step explanation:

In math, every function has a domain and a range.

Therefore, with this information given to us, we need to also know about coordinate pairs. Coordinate pairs are written in (x, y) form.

Functions are classified in four ways:

Finally, the domain and range should be written in ascending order. Therefore, the lowest number should be written first in the domain and the highest number should be written last.

Function 1

We are given the function: [tex]\text{ \{(-3, 3)}, (1, 1), (0, -2), (1, -4), (5, -1) \} }[/tex].

Using the information above, we can pick out our x and y-values from the function.

Values of Domain: -3, 1, 0, 1, 5

Values of Range: 3, 1, -2, -4, -1

Now, we need to arrange these in ascending order.

Domain Rearranged: -3, 0, 1, 1, 5

Range Rearranged: -4, -2, -1, 1, 3

Using these values, we can see what values we have.

For x-values:

x = -3: 1 value

x = 0: 1 value

x = 1: 2 values

x = 5: 1 value

For y-values:

y = -4: 1 value

y = -2: 1 value

y = -1: 1 value

y = 1: 1 value

y = 3: 1 value

Therefore, we can begin classifying this function. Because we have all separate y-values, we have a function. However, we have two of the same x-value, so we have an onto function.

Now, we can create our domain and range in the set. We use the same formatting given for the first function. We list the values in ascending order and list them in brackets to show that they are apart of a set.

The domain values are the x-values, so they are [tex]\text{ \{-3, 0, 1, 5\}}[/tex].

The range values are the y-values, so they are [tex]\text{ \{-4, -2, -1, 1, 3\}}[/tex].

Therefore, the domain and range for function one are defined, but this is not a function. Because the x-values repeat, it cannot be a function.

Function 2

We are given a table of values that needs to be translated into the set notation. This makes it easier to identify the values. We are given x-coordinates in the top row and y-coordinates in the bottom row. And, the table is set up to where the x-value directly above the y-value makes a coordinate pair. Using this, we can create the set function.

The set function is [tex]\text{ \{(-2, -7), (-1, -2), (0, 1), (1, -2), (2, -7)\}}[/tex].

Now, we can use the same method as above to pick out the x and y-values and reorder them to be from least to greatest.

Values of Domain: -2, -1, 0, 1, 2

Values of Range: -7, -2, 1, -2, -7

Now, we rearrange these.

Domain Rearranged: -2, -1, 0, 1, 2

Range Rearranged: -7, -7, -2, -2, 1

Now, we can check how many times the function presents each coordinate.

For x-values:

x = -2: 1 value

x = -1: 1 value

x = 0: 1 value

x = 1: 1 value

x = 2: 1 value

For y-values:

y = -7: 2 values

y = -2: 2 values

y = 1: 1 value

Now, we can classify the function. The x-values are unique, but the y-values are repeated. Therefore, because the x-values are assigned to one y-coordinate and they are unique, this is not an one-to-one function. Additionally, it cannot be an onto function because the y-values are not unique - they are repeated. Therefore, it is neither an one-to-one function or an onto function. If this function were graphed, it would actually reveal a parabola. However, it is still a function.

The domain values are the x-values, so they are [tex]\text{ \{-2, -1, 0, 1, 2\}}[/tex].

The range values are the x-values, so they are [tex]\text{ \{-7, -2, 1\}}[/tex].

Find the values of X and Y

please help!! i don’t understand.

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Cube root of x^3


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