Let's begin by listing out the information given to us:
[tex]\begin{gathered} 123=1\text{0}0 \\ \text{ 20} \\ \text{ 3} \\ 123=1\text{ hundred + 2 tens + 3 units} \\ 68\text{ = 6 (10)} \\ \text{ 8} \\ 68\text{ = 6 tens + 8 units} \end{gathered}[/tex]To know which is greater between 0.123 To know which i3& 0.68, let's express it in tenth, hundredth & thousandth
[tex]\begin{gathered} 0.123=3\text{ thousandth + 2 hundredth + 1 tenth + 0 unit} \\ 0.123=0.003+0.02+0.1+0 \\ 0.68=\text{ 6 hundredth + 8 tenth + 0 unit} \\ 0.68=0.60+0.08+0 \end{gathered}[/tex]0.123 has 3 decimal places, which means it is 123/1000
0.68 has 2 decimal places, which means it is 68/100
When you multiply by 100, we have:
0.123 * 100 = 12.3
0.68 * 100 = 68
It becomes very evident that 0.68 is greater than 0.123
12Solve using the Quadratic Formula for 2x2 + 5x – 3 = 0x = -5, 7b. X = -12,2X = -3,42
2x² + 5x - 3 = 0
Multiply the coeeficient of x² and the constant (-3)
That is 2 ( - 3) = -6
Find the numbers whose sum is 5 and whose product is -6
The number is 6 and -1
Replace 5x by the numbers
2x² + 6x - x - 3 = 0
2x( x + 3) - 1 ( x + 3) = 0
(2x - 1 ) ( x + 3) = 0
Either 2x -1 = 0 or x + 3 = 0
2x = 1
x = 1/2 or x = -3
You have one box that is 2 and 5 11 feet tall and a second box that is 2.45 feet tall. Write the decimal expansion for 2 and 5 11. If you stack the boxes, about how tall will the stack be
You have one box that is 2 and 5/11
feet tall and a second box that is 2.45 feet tall. Write the decimal expansion for
2 and 5/11. If you stack the boxes, about how tall will the stack be
we have that
[tex]2\frac{5}{11}=2+\frac{5}{11}=\frac{22+5}{11}=\frac{27}{11}=2.454545\ldots[/tex]If you stack the boxes,
we have
2.45+2.45=4.90 ft
Maya has 846 beads. She is making bracelets with 18 beads on each. How many bracelets is she able to make?
Answer:
maya is able to make 47 bracelets
Step-by-step explanation:
(x ^ 2 + 11x + 18) / (x + 3) =
Answer:
x+8 - 6/x+3
Step-by-step explanation:
ANSWER ONLY A-Ca. what is the students speed from the 3rd to 5th minute?b. at what times during the bike ride did the student come to a stop?c. During what time intervals did the students speed increase?
SOLUTION:
Case: Distance time graph
Method:
a) the students speed from the 3rd to 5th minute
[tex]\begin{gathered} Speed,s \\ s=\frac{4-2.25}{5-3} \\ s=\frac{1.75}{2} \\ s=0.875miles\text{ }per\text{ }minute \end{gathered}[/tex]b) the times during the bike ride did the student come to a stop
d and h
8 minutes and 23 minutes
c) the students speed increase during.
b to c. 1 and 3 minutes
e to f. 11 and 15 minutes
f to g. 15 and 17 minutes
The list price of a DVD player is $129. Sam found the player on sale for $90.30. What was the percent discount?
A percent discount of 30%
Explanation:
Since $129 represent 100% of the price, then the new price $90.30 represent 70 %
129 * 100 / 90.30 = 70 %
Since from the 100% of the price, it went to 70% of it, there was a discount of 30%
100 - 70 = 30%
Given the function: f(x) = (x − 3)(x + 7)(x − 1)its f-intercept is:its x-intercepts are:
Given: Given the function: f(x) = (x − 3)(x + 7)(x − 1)
Required: its f-intercept and its x-intercepts.
Explanation:
[tex]f(x)=(x-3)(x+7)(x-1)[/tex]For f-intercept, put x = 0
[tex]\begin{gathered} f(0)=(0-3)(0+7)(0-1) \\ f(0)=21 \end{gathered}[/tex]So the f-intercept is (0,21).
For x-intercepts, put f(x) = 0
[tex]\begin{gathered} 0=(x-3)(x+7)(x-1) \\ x=3,-7,1 \end{gathered}[/tex]So x-intercepts are (3,0),(-7,0) and (1,0).
Final Answer:
f-intercept: (0,21)
x-intercept: (3,0),(-7,0),(1,0).
Graph the equation using the slope and the y-interceptY=-8/5x-4
We got the linear equation:
[tex]y=\frac{-8}{5}x-4[/tex]The slope of this line will be -8/5 and the y-intercept will be -4.
To graph it, first find the intercept with x - axis.
We can find it if we equal the equation to zero.
[tex]\begin{gathered} \frac{-8}{5}x-4=0 \\ \\ -\frac{8}{5}x=4 \\ \\ x=-\frac{20}{8}=-\frac{10}{4}=-\frac{5}{2} \end{gathered}[/tex]Now, we got two points:
[tex](-\frac{5}{2},0),(0,-4)[/tex]To graph the function, we only join these points:
So that's the graph for the function.
can you help please this is really important
The value of x is 10 and the length of SU is 50.
Here SU is the line and T is the mid-point of the line
So from this we have
SU = ST + TU
ST = TU
SU = 2ST = 2TU
ST = 3x - 5 and TU = 2x + 5
As ST = TU
3x - 5 = 2x + 5
x = 10
SU = 2ST
= 2( 3x - 5)
= 2( 3 × 10 - 5)
= 2( 30 - 5)
= 2× 25
= 50
Therefore the value of x is 10 and the length of SU is 50.
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A print shop borrows $4200 from a credit union for 178 days. The credit union charges simple interest at an annual rate of 6.5% for this loan. Assume each day is 1/365 of a year.
round your final answers to the nearest cent.
A) Find the interest that will be owed after 178 days.
B) Assuming the print shop doesn't make any payments, find the amount owed after 178 days.
Using percentages, the answer to both the subparts are:
(A) Interest that will be owed after 178 days: $4,336.5(B) Interest after 178 days if sop doesn't repay: $4,473What is the percentage?A percentage is a figure or ratio stated as a fraction of 100 in mathematics. Although the abbreviations "pct.", "pct.", and occasionally "pc" is also used, the percent symbol, "%," is frequently used to indicate it. A % is a number without dimensions and without a standard measurement.So, since the interest is annual 6.5%:
(A) Interest that will be owed after 178 days:
Interest/2 ⇒ 6.5/2 ⇒ 3.25%Now, 3.25% of 4200:
4200/100 × 3.25 = 136.5$4,336.5(B) Interest after 178 days if sop doesn't repay:
Interest ⇒ 6.5%Now, 6.5% of 4200:
4200/100 × 6.5 = 273$4,473Therefore, using percentages, the answer to both the subparts are:
(A) Interest that will be owed after 178 days: $4,336.5(B) Interest after 178 days if sop doesn't repay: $4,473Know more about percentages here:
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harry and marie despoit $800.00 into a savings account which earns 9% interest compounded monthly they want to use the money in the account to go on a trip in 3 years how much will they be able to spend
harry and marie despoit $800.00 into a savings account which earns 9% interest compounded monthly they want to use the money in the account to go on a trip in 2 years how much will they be able to spend
we know that
The compound interest formula is equal to
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]where
A is the Final Investment Value
P is the Principal amount of money to be invested
r is the rate of interest in decimal
t is Number of Time Periods
n is the number of times interest is compounded per year
in this problem we have
P=$800
r=9%=9/100=0.09
n=12
t=2 years
substitute in the expression above
[tex]\begin{gathered} A=800(1+\frac{0.09}{12})^{12\cdot2} \\ \\ A=800(\frac{12.09}{12})^{(24)} \\ A=\$957.13 \end{gathered}[/tex]the answer is $957.13The length of the smaller rectangle is 12 inches and the width is x inches. The length of the larger rectangle is 20 inches and the width is 15 inches. What is the area of the smaller rectangle?
The area of the smaller rectangle is 108 inches².
What is the Area of a Rectangle?The area of a rectangle is calculated to determine the area occupied by the rectangle within its boundary. A rectangle's area (A) is the product of its length 'a' and width or breadth 'b'. As a result, the Area of the Rectangle = (a × b) square units.
Given the dimensions of the smaller rectangle:
Length = 12 inches
Width = x inches
Given the dimensions of the larger rectangle:
Length = 20 inches
Width = 15 inches
To find the value of x we use proportion,
[tex]\frac{12}{x} = \frac{20}{15}[/tex]
Cross-multiplying, we get
12 × 15 = 20x
x = 180/20 = 9
Hence, the width of the smaller rectangle is 9 inches.
Area of the smaller rectangle = length × width
= 12 × 9
= 108 inches²
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Jordan wants to use the Starz princess hall, the Dynamic DJ's as his music And Roscoe's for his equipment. If Jordan has a total of $800 and wants the music to play for 4 hours, how many people can Jordan party?
The number of people that can attend Jordan's party is 50 people.
How many people can attend Jordan's party?The equation that represents the total amount that would be spent at the party would be a linear equation. A linear equation increases at a constant rate.
The form of the linear equation would be:
Total amount = rental fee + (charge per hour of the Dynamic DJ x number of hours he plays) + (cost per person of Roscoe's rentals x number of people)
$800 = $400 + ($50 x 4) + ($4 x p)
$800 = $400 + $200 + $4p
$800 = $600 + $4p
$800 - $600 = $4p
$200 = $4p
p = $200 / $4
p = 50 people
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4505 x 219 standard algorithm
After throughfall calculating the multiplication 4505 x 219 in standard algorithm, we have come to find that product is 986595
What is standard algorithm?In elementary math, a standard algorithm or method is a particular computation technique that is typically taught for resolving particular mathematical issues. In general, these techniques include exchanging, regrouping, long division, long multiplication using a standard notation, and standard formulas for average, area, and volume.
These techniques can vary somewhat by country and time, but they typically include these techniques. Similar techniques are also available for more complex functions like square roots, but they are no longer taught in general mathematics classes because calculators are more convenient.
4505 x 219 in standard algorithm is as follows:
⇒ 4 5 0 5
× 2 1 9
4 0 5 4 5
+ 4 5 0 5
+ 9 0 1 0
9 8 6 5 9 5
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A parking garage charges a flat fee of $3 to enter the garage and then an additional hourly
charge to park. The cost to park in the garage can be modeled by the equation: P = 3+c.h
where c is the hourly rate to park and h is the number of hours parked in the garage.
a) Write an equation to find the number of hours a person parked if we know P and c.
b) If c=$2.25, find P if the person parks for 6 hours.
c) If P=$25.50, find how many hours the person parked if the cost per hour is $2.25.
If the cost to park in garage can be modeled by the equation P = 3+ch
Part A
The equation to find the number of hours a person parked h = (P-3) / c
Part B
If c = $2.25 and number of hours h =6 hours, then the cost to park in garage is $16.5
Part C
If P = $25.50, the person parked 10 hours if the cost per hour is $2.25
The flat fee of parking = $3
The cost to park in garage can be modeled by the equation
P = 3+ch
Where c is the hourly rate to park
h is the number of hours parked in the garage
Part A
The equation to find the number of hours a person parked is
P = 3+ch
c × h = P-3
h = (P-3) / c
Part B
c = $2.25
h = 6 hours
P = 3 + 2.25×6
= 3 + 13.5
= $16.5
Part C
P = $25.50
c = 2.25
h = (P-3)/c
= (25.50-3)/2.25
= 10 hours
Hence, if the cost to park in garage can be modeled by the equation P = 3+ch
Part A
The equation to find the number of hours a person parked h = (P-3) / c
Part B
If c = $2.25 and number of hours h =6 hours, then the cost to park in garage is $16.5
Part C
If P = $25.50, the person parked 10 hours if the cost per hour is $2.25
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What is the slope of the line that contains these points? 9 X 17 13 21 -24 -21 -18 Y - -15 slope:
We have to use the slope formula
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Let's replace the points (9,-24) and (13,-21). Where
[tex]\begin{gathered} x_1=9 \\ x_2=13 \\ y_1=-24 \\ y_2=-21 \end{gathered}[/tex][tex]m=\frac{-21-(-24)}{13-9}=\frac{-21+24}{4}=\frac{3}{4}[/tex]Hence, the slope is 3/4.however, she is not quite sure where to start. Using complete sentences, describe to Erika how to solve this equation
Explanation:
For the given equation
[tex]50^x=17[/tex]For Erika to resolve the question
Step 1: We will take the logarithm of both sides
[tex]\log (50^x)=\log (17)[/tex]Step 2: Simplify the expression
Thus
[tex]x\log 50=\log 17[/tex]Step 3: Solve for x
[tex]x=\frac{\log 17}{\log 50}[/tex][tex]x=0.724[/tex]Identify the domain and range of the function. y=x−−√−1
The domain of the function is [1, ∞) and the range of the function is [0,∞).
Domain and range:
The domain and range of a function are refers the set of all the inputs and outputs a function can give respectively.
Basically, domain takes all the possible input values from the set of real numbers whereas the range takes all the output values of the function.
Given,
Here we have the function
y = √x - 1
Now, here we need to find the domain and range of the function.
The given function is rewritten as,
√x - 1 > 0
Square both sides then we get,
x - 1 > 0
Add 1 on both sides then we get,
x > 1
Therefore, the domain is [1, ∞).
Similarly, let us consider, y ≥ 0
Therefore, the range is [0,∞).
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Divide 6.1 x 10^20 by 3.2 x 10^5. Express your answer in scientific notation.
PLEASE HELP!!!!
The division of the two numbers in scientific notation is equal to 1.91*10^15
Division of NumbersTo solve this problem, we have to divide the two numbers in scientific notation and to do this, we can simply apply division law of indices here;
We can first divide 6.1 by 3.2.
This will give us 1.90625 which is approximately 1.91.
Then applying the law of indices and subtract the power from one another. This becomes 20 - 5 = 15
The final value will be 1.91 * 10^15
The division of 6.1*10^20 by 3.2*10^5 is equal 1.91 *10^15
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At 30 mph a trip from Town A to Town B takes 6 hours. If the speed were doubled, how many hours would the trip take?
The time taken by Town A to Town B will be 3 hours.
What is speed?Speed is defined as the ratio of the time distance traveled by the body to the time taken by the body to cover the distance. Speed is the ratio of the distance traveled by time. The unit of speed in miles per hour.
Given that at 30 mph a trip from Town A to Town B takes 6 hours.
The time taken will be calculated as,
Total distance = 30 x 6 = 180 meters
Speed = 30 x 2 = 60 mph
The time,
T = 180 / 60= 3 hours
Therefore, the time taken by Town A to Town B will be 3 hours.
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Choose all equivalent expression ( s). (4) ^ (3z ^ 2); (4) ^ (- 3x ^ 2); (1/4) ^ (3z ^ 2); (pi/4) ^ (3x)
Answer:
B, C
Step-by-step explanation:
You want to find the equivalent expressions among ...
4^(3x^2)4^(-3x^2)(1/4)^(3x^2)(x/4)^(3x)Rules of exponentsThe relevant rule of exponents is ...
a^b = (1/a)^-b
Equivalent expressionsExpressions with the same base and different exponents will not be equivalent. (A≠B).
Expressions with different bases and the same exponent will not be equivalent. (A≠C).
A variable in the base cannot replace a variable in the exponent. (A≠D).
The rule of exponents tells us replacing the base by its reciprocal and negating the exponent will result in an equivalent expression. (B=C).
The equivalent expressions are 4^(-3x^2) and (1/4)^(3x^2).
What is the polynomial function of lowest degree with rational real coefficients and roots 2 and squared root 5?
The polynomial having the above quantities is expressed as x³ - 2x² - 5x + 10 = 0
The above situations will form a Cubic polynomial. A Cubic polynomial function may be defined as an expression which can be written in the form of ax³ + bx² + cx + d = 0 where a, b, c and d are coefficients and x is the independent variable. Since, the polynomial should have real coefficients so its multiplicity will be equal to 1. Now, the roots of the polynomial are given as 2 and √5. Since, square roots always occur in pair so the polynomial will have -√5 as its root. Now, the polynomial formed will be
(x - 2) (x - √5) (x + √5) = 0
(x - 2) (x² - 5) = 0
x³ - 5x - 2x² + 10 = 0
=> x³ - 2x² - 5x + 10 = 0 which is the required polynomial.
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The admission fee to an amusement park is $18. It costs an additional "c" dollars to rent a locker to hold your belongings. The total cost for 9 people to
enter the amusement park and each rent a locker is $252. How much does it cost for one person to rent a
A local farm raises horses and goats. • Let x represent the number of horses on the farm. • The number of goats is 3 times the number of horses. • The total number of horses and goats on the farm is 96. What is x, the number of horses on the farm?
The number of horses on the harm will be 24.
What is an expression?
Expression in math is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
Given that;
A local farm raises horses and goats.
The total number of horses and goats on the farm is 96.
Let number of horses = x
Since, The number of goats is 3 times the number of horses.
Then, Number of goats = 3x
The total number of horses and goats on the farm is 96.
Hence, we can formulate;
x + 3x = 96
4x = 96
x = 24
Thus, The number of horses on the harm will be 24.
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Are the triangles congruent using AAS?
True
False
Given lines l, m and n are all parallel and cut by two transversal lines, find the value of 2. 2 12 6. т х 33 n
Answer:
66
Explanation:
By the Thales theorem, if we have the following figure:
Then, the following equation applies:
[tex]\frac{a}{c}=\frac{b}{d}[/tex]So, in this case, we can formulate the following equation:
[tex]\frac{6}{12}=\frac{33}{x}[/tex]Then, solving for x, we get:
[tex]\begin{gathered} 6\cdot x=33\cdot12 \\ 6x=396 \\ \frac{6x}{6}=\frac{396}{6} \\ x=66 \end{gathered}[/tex]Therefore, the value of x is 66.
Identify the segments that are skew to line EF. There are four answers.
The lines that are not intersecting and perpendicular to each other, are not parallel to each other, and are not coplanar are called skew lines.
The four lines that are skew to line EF are AB, GB, CH, and DC.
What are skew lines?The lines that are not intersecting and perpendicular to each other, are not parallel to each other, and are not coplanar are called skew lines.
We have,
A line EF on the given square figure.
We have the following lines on the given figure.
DG, CB, HA, FA, FG, GB, AB, EH, ED, DC,CH,
We see that,
FG, FA, EH, and ED are perpendicular and intersecting to line EF.
DG, CB, and HA are parallel to line EF.
So the remaining lines will be skew to line EF
i.e AB, GB, CH, and DC
Thus,
The four lines that are skew to line EF are AB, GB, CH, and DC.
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BE is the diameter of circle A. What's the measure of ∠BCE?Question 12 options:1) 90°2) 88°3) 180°4) 93°
Since BCE is an inscribed angle, it measures half the measure of the inscribed arc.
Angle BCE inscribes the arc BE of 180°, we have:
[tex]\begin{gathered} \text{BCE}=\frac{BE}{2} \\ BCE=\frac{180}{2} \\ \text{BCE}=90\degree \end{gathered}[/tex]Therefore the correct option is 1)
please help me brainliest?
Answer:
See below.
Step-by-step explanation:
Given multiplication:
[tex]3 \dfrac{1}{5} \times 2 \dfrac{5}{8}[/tex]
Convert the mixed numbers into improper fractions by multiplying the whole number by the denominator of the fraction, adding this to the numerator of the fraction, and placing the answer over the denominator:
[tex]\implies \dfrac{3 \times 5+1}{5} \times \dfrac{2 \times 8+5}{8}[/tex]
[tex]\implies \dfrac{15+1}{5} \times \dfrac{16+5}{8}[/tex]
[tex]\implies \dfrac{16}{5} \times \dfrac{21}{8}[/tex]
[tex]\textsf{Apply\;the\;fraction\;rule} \quad \dfrac{a}{b} \times \dfrac{c}{d}=\dfrac{ac}{bd}:[/tex]
[tex]\implies \dfrac{16 \times 21}{5 \times 8}[/tex]
[tex]\implies \dfrac{336}{40}[/tex]
Reduce the fraction by dividing the numerator and denominator by the common factor of 8:
[tex]\implies \dfrac{336 \div 8}{40 \div 8}[/tex]
[tex]\implies \dfrac{42}{5}[/tex]
Divide the numerator by the denominator:
[tex]\implies 42 \div 5=8\;\textsf{remainder}\;2[/tex]
The mixed number answer is the whole number and the remainder divided by the denominator:
[tex]\implies 8 \dfrac{2}{5}[/tex]
Step-by-step explanation:
when you want to start solving it you will do 16 over 5 * 21/8equals 8 whole number 2/5
it will give you 336 all over 40 if you divide by 8 you will get 42/5 which is 8 whole number 2/5
Question #36 Multiple-Choice Reduce -2 + b2 by 7 + b2. C5 0 2b2-7 C9
Answer:
[tex]-2+b^2-7-b^2=-9[/tex]Step-by-step explanation:
Reduce the following expressions:
[tex]-2+b^2-(7+b^2)[/tex]Operate like terms:
[tex]-2+b^2-7-b^2=-9[/tex]