In one to two sentences, explain how this reaction demonstrates that matter is neither created nor destroyed in a chemical reaction.

Considering the definition of percent yield, the percentage yield of the reaction is 68.18%.

To determine the efficiency of a reaction, the percent yield is used, which describes the ratio of the actual yield to the theoretical yield.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

percent yield= (actual yield÷ theoretical yield)× 100%

where:

In this case, you know:

Replacing in the definition of percent yield:

percent yield= (15 g÷ 22 g)× 100%

Solving:

percent yield= 68.18%

Finally, the percentage yield is 68.18%.

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The new concentration (molarity) of the solution is 0.5M.

According to this question, Sam pipettes dilutes 10ml of a 1.5 M AgNO3 solution with water until the final volume is 30 ml.

Formula =

C1V1 = C2V2

Where;

1.5 × 10 = 30 × C2

15 = 30C2

C2 = 15/30 = 0.5M

Therefore, the new molarity of the solution is 0.5M.

What is concentration in chemistry?

A measure of the concentration of a chemical variants, in peculiar of a solute in a solution, in terms of amount of object per unit volume of solution is called concentration. Its also called molarity, amount concentration or substance concentration.

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A net ionic equation for the reaction is :

Cu(s)  + 2H⁺(aq) ---->  Cu²⁺(aq)  + H₂(g)

The reaction of Cu with HBr is given as :

Cu(s) + HBr(aq) --->  CuBr₂(aq)   +  H₂(g)

to balance the equation multiple 2 in HBr , we get the balance equation :

Cu(s) + 2HBr(aq) --->  CuBr₂(aq)   +  H₂(g)

write the complete ionic equation :

Cu(s)  + 2H⁺(aq)  +  2Br⁻(aq) ----->  Cu²⁺(aq)  + 2Br⁻(aq) + H₂(g)

now, cancel out the spectator ion from the equation, spectator ions are the same ion in the reactants and product side, we get :

Cu(s)  + 2H⁺(aq) ---->  Cu²⁺(aq)  + H₂(g)

Thus, this is the net ionic equation of the reaction.

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The importance of knowing chemical reactions to engineers is this information can be utilized to improve reactor design or operating circumstances such as feed flow rate and feed mix.

Breaking carbon-carbon bonds between the reactant molecules (particles) and creating new bonds between atoms in product particles are examples of chemical reactions (molecules). The number of atoms is the same before and after the chemical transition, but the number of molecules changes.

Therefore, chemical reactions are important to engineers because they can be used to improve reactor design or operating conditions such as feed flow rate and feed mix.

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Answer:

Oxidation is the loss of electrons or an increase in the oxidation state of a chemical or atoms within it.

Iron is oxidized to form the iron oxide known as rust.

Answer:

Explanation:

Name the metal by its elemental name.

Name the nonmetal by its elemental name and an -ide ending.

Name polyatomic ions by their names.

The answer to this question= 3 rules that ionic compounds must follow are-

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Vaporization totally overcomes intermolecular attractions. Water has an enthalpy of vaporization (energy required to boil) of 40.7 kJ/mol.

A is the ideal answer.

Which of the following best exemplifies how the positive value of H° for CaF2 dissolving in water is explained? In the crystal lattice, Ca2+ ions and F- ions have very potent ion-ion interactions.

Due of its greater effective nuclear charge, Ar. The atomic radius and initial ionization energy of several elements are displayed in the table above.

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The state symbols for the reactants, products, and addition are as follows: Mg(s) + H2SO4 (aq) MgSO4 (aq) + H2 (g), where the sole reactants are H+(aq) and Fe (s). H2 is the offered product (g).

Energy is released and the molecules of hydrogen and oxygen can join to generate either water or hydrogen peroxide when the molecules of H2 and O2 are mixed and allowed to react.

The substance or substances to the left of the arrow in a chemical equation are the reactants. Reactants are substances that are present at the beginning of a chemical reaction. The substance or substances to the right of the arrow are products.

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Strong nucleophile Sodiumbutyne reacts with 4-bromobutanol to produce a nucleophilic substitution reaction.

Nucleophilic substitution reaction is defined as a series of reactions where a positively charged electrophile is attacked by an electron-rich nucleophile to remove a leaving group.

This causes the mass of the product to increase with the addition of more carbon atoms. The strong base sodiumbutyne reacts with the alcohol's hydrogen to produce an acid-base reaction. Consequently, lower mass product alkyne is formed.

Thus, strong nucleophile Sodiumbutyne reacts with 4-bromobutanol to produce a nucleophilic substitution reaction.

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A carbohydrate with two sugar units would be a(n) oligosaccharide. Correct answer: letter D.

This is because an oligosaccharide is a carbohydrate that contains two to ten sugar molecules, making it a carbohydrate with two sugar units.

Are a type of organic compound found in living things. They are composed of carbon, hydrogen and oxygen in the ratio of C:H:O = 1:2:1. Carbohydrates are the main source of energy for the body and are found in many foods, such as:

They can be further divided into simple carbohydrates, such as sugar, and complex carbohydrates, such as starch.

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The important technique not for experiment is performing a flame test.

One of the most frequently employed analytical techniques in chemistry is the flame test. It is primarily used to observe and examine the presence of specific elements in the given compound or salt.

The flame test typically looks for the presence of metal ions in a compound.

Every element has a different flame test because each element's ions have unique characteristics depending on their emission spectrum.

This distinction can be seen in the color of the flames that are produced when burning salt that contains metal ions.

It should be noted that atoms, not ions, are present in the emission spectrum of each element that determines the flame color in this case.

The visible color lines that are seen in flame tests are frequently the result of the electrons in the ions undergoing a transformation.

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The zinc coating makes the coin appear to have a new silver covering. Brass is created when a coin is heated in a Bunsen flame due to the migration of zinc into the copper's surface layer. This gives the coin a gold appearance.

The following describes how zinc and sodium hydroxide react to generate sodium zincate:

Na2[Zn(OH)4](aq) + H2 = Zn(s) + 2NaOH(aq) + 2H2O(l) (g)

A wire or direct contact between the copper and the zinc, as in this case, is required for the plating reaction to occur in an electrochemical cell.

The following electrode reactions:

Zn(s) Zn2+(aq) + 2e- at the zinc electrode, then the zinc ions complex as [Zn(OH)4].

2–(aq)

Zn(s) + 4OH- at the copper electrode: [Zn(OH)4]2-(aq) + 2e- (aq)

The zinc coating gives the coin the appearance of having a silver coating.

To determine the amount of zinc added, weigh the coins both before and after plating.

Brass is created when the coin is heated under a Bunsen flame because the zinc migrates into

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The limiting reagent is O₂.

Reagents are substances used to facilitate or accelerate chemical reactions. They can be either synthesized in the laboratory or found naturally. Reagents can also serve as catalysts, solvents, buffers, surfactants, and/or scavengers. They are essential components of most chemical processes, enabling scientists and engineers to control and manipulate reactants and products. Reagents are also used to detect, measure, and identify substances in a variety of analytical procedures.

a. The limiting reagent is O₂. This is because there is less moles of O₂ than P4, so O₂ will be used up faster and will be the first reactant to be completely used up.
b. 24.2 mol of O₂ will react with 8.24 mol of P4, producing 16.16 mol of P₂O5 (s).
c. 16.16 mol of P₂O5 (s) will produce 143.1 g of P₂O5 (s). This is calculated by using the molar mass of P₂O5 (s): 143.1 g/mol.

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There are several factors that can contribute to the speed of an object, including its mass, shape, and the surface it is moving on. In general, slimmer objects tend to go faster than objects with more structure because they offer less resistance to movement, which allows them to accelerate more quickly and reach higher speeds.

One factor that can affect the speed of an object is its mass, or the amount of matter it contains. All other things being equal, an object with a lower mass will tend to be faster than an object with a higher mass, because it has less matter to move and therefore requires less energy to accelerate.

Another factor that can affect the speed of an object is its shape, or the way it is structured. Slimmer objects tend to be more streamlined, meaning they have a shape that allows them to move through the air or water with less resistance. This can allow them to go faster than more structured objects, which may have a shape that creates more drag or resistance to movement.

Finally, the surface an object is moving on can also affect its speed. For example, an object moving on a smooth, flat surface may be able to go faster than an object moving on a rough or uneven surface, because the smooth surface offers less resistance to movement.

Overall, the speed of an object is determined by a combination of these and other factors, including the force applied to the object and the level of resistance it encounters. Slimmer objects tend to go faster than objects with more structure because they offer less resistance to movement, which allows them to accelerate more quickly and reach higher speeds.

The acidic hydrogen atom in any carboxylic acid is attached to oxygen atom in the cooh group.

Carboxylic acids are organic compounds containing a carboxyl group, which is a functional group consisting of a carbonyl group (C=O) bonded to a hydroxyl group (–OH). They are found in nature in the form of fatty acids, amino acids, and carbohydrates. Carboxylic acids are often used in the production of polymers, fabrics, solvents, and surfactants. They have a wide range of applications, from pharmaceuticals to food additives. Carboxylic acids are also used in the production of chemical intermediates and as precursors to other compounds. Carboxylic acids are distinguished from other acids by the presence of a carbon atom bonded to an oxygen atom and a hydroxyl group. The acidic properties of carboxylic acids are due to the presence of the carboxyl group, which is highly polar and can form hydrogen bonds with other molecules.

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Polar molecules would move further in a liquid solution than in a non-polar solvent because they are more closely bound to polar solvents.

The precursor 9-fluorenone has been used in the synthesis of a wide range of organic the electronic devices. Here are a few the typical instances: creation of the host for the blue and green organic light-emitting diodes (PHOLEDs).

As the second most common PAH, fluorene is often present as a gas from a number of the sources, including tobacco smoke, resinous pitch, petroleum refining, exhaust fumes gases, and gasoline.

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A stimulus has opened the voltage-gated sodium channel in an area of a neuron's plasma membrane. As a result, sodium rushes into the neuron and diffuses to adjacent areas; this in turn results in the opening of voltage-gated sodium channels in the adjacent areas. Thus, option "c" is correct.

When the potential in the membrane rises above the threshold energy, the natrium voltage-gated sodium channels will be opened. The opening of the natrium voltage-gated sodium channels will allow the movement of sodium to the cells. This happens because the concentration of sodium outside the cell is much higher than inside the cells, the sodium will flow into the cells.

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[tex]\frac{1}{6}L[/tex] or 166.667 ml of water must be evaporated in order to make this solution 3M.

When the problem states "250ml of 1M Ca(OH)₂", it means that you have 250ml of a solution that contains 1 mole of solute (Ca(OH)₂) for each liter of the solution.

In order to make a 1M solution be a 3M solution, we'll have to remove some of the solvent liquid, in order to make it more concentrated.

The original molarity is: M= Moles of solute (n) / Liters of solution (v).

Since the problem states that the original molarity is 1M, we have 1 mole of solute per liter of solution in the original solution. Therefore, initial molarity is: [tex]M=\frac{1mol}{1liters}=\frac{0.250mol}{0.250L}[/tex]

250ml= 0.250 L.

As you may see, in order to make the molarity fraction equal 3M, we'll have to multiply the numerator by 3 or divide the denominator by the same number:

[tex]M=\frac{0.250mol}{0.250L/3}=\frac{0.250mol}{\frac{1}{12} L}[/tex]

The amount of solution evaporated is given by the difference between the denominator of the molarity of the original expression and the new expression:

[tex](0.250-\frac{1}{12})\\ \\(\frac{3}{12}-\frac{1}{12})L\\ \\\frac{2}{12} L\\ \\\frac{1}{6} L[/tex]

[tex]\frac{1}{6}L[/tex] or 166.667 ml of water must be evaporated in order to make this solution 3M. The ending product will have the following molarity:

[tex]M=\frac{0.250moles}{\frac{1}{12} L} =3M[/tex].

The number of moles of gas in the given sample is equal to 3.324 mol.

The ideal gas law can be demonstrated as an equation representing the behavior of a perfect gas. The product of the volume and pressure (P) is equal to the multiplication of the gas constant (R), moles of gas, and absolute temperature.

The ideal gas equation for a gas can be written as shown below:

PV = nRT

Where n is the moles, P is the pressure,  V is the volume of the gas,  T is temperature and R is the gas constant.

Given, the volume of gas, V = 76.87 L

The temperature of the gas, T = 40.04°C =  40.04 + 273 = 313.04 K

The pressure of the gas, P = 1.11 atm

Substituting the values T, V, R, and P in the gas equation, we will get:

The number of moles of the given gas sample, n = PV/RT

n = 1.11 ×76.87/(0.082 × 313.04)

n =3.324 mol

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Planar trigonal C, The triangular planar molecules have a center atom that is linked to three other atoms and is sp2 hybridized. if the structure consists of just two bonds and one pair of electrons.

The electrons of sp3 hybridized species are held farther away from the nucleus than those of sp2 (33% s-character) and sp (50% s-character) hybridized species because the s orbital is retained farther away from the nucleus and has a lower energy than the p orbital. The more stable the electrons are, the nearer to the nucleus they are.

A relationship gets stronger and lasts shorter as its s-character increases. the strongest bond is a sp–sp bond, and sp3−sp3 bond is weakest.

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The result in a linear plot when the natural logarithm of the species concentration (Al) is plotted against time will be (A) A reaction rate is dependent on the concentration of only one reactant.

The linear plot between ln([A]) and time will follow the First-order reaction kinetics, that is as follows;

    ln[A] = -kt + ln[A]0

In the above-mentioned equation;

    k = rate constant

    [A]0 = initial concentration of the reactant.

By the equation, it is confirmed that it is a linear plot between ln([A]) and t.

Therefore, A reaction rate is dependent on the concentration of only one reactant.

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Sodium bicarbonate and citric acid are used in this activity's interaction to create water and carbon dioxide.

HCO3- (aq) + H+ (aq) H2O (l) + CO2  (g)

Hence, Sodium bicarbonate and citric acid are used in this activity's interaction to create water and carbon dioxide.

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The pair of elements most likely to combine in order to form a salt would be Mg and Br. Option 3.

Salts are chemical compounds formed by the combination of positive ions, usually from bases, and negative ions, usually from acids. In other words, salt cannot be formed from two positive or two negative ions.

Going by this definition:

On the other hand, Mg forms a positive ion, [tex]Mg^{2+[/tex], and Br forms a negative ion, [tex]Br^-[/tex]. Thus both can form a salt, unlike other options.

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The light -dependent stage of photosynthesis contain the absorption of light via  pigments consisting chlorophyll and the switch of electrons from water to generate ATP and NADPH. These reactions arise in the  thylakoid membranes of the chloroplasts and also are referred to as the Hill response or the electron transport chain. Key phrases related to the light dependent stage are:

The light-independent reactions of photosynthesis, additionally referred to as the Calvin cycle or the carbon fixation cycle, contain the conversion of carbon dioxide into glucose and different natural compounds by the usage of the energy saved in ATP and NADPH. These reactions arise in the stroma of the chloroplasts. Key phrases related to the mild-unbiased reactions include:

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The following correctly identify the main types of oxidizing agents used in organic oxidation reactions :

D) Reagents containing an oxygen-oxygen bond

E) Reagents containing an oxygen-metal bond

The oxidation reaction are the reaction is the removal of the hydrogen is called as the oxidation reaction . the increases in the oxidation number or we can say that the loss of the electron are called as the oxidation reaction. The removal of the oxygen is called as the reduction reaction . the decreases in the oxidation number or the gain of the electron is the reduction reaction.

Thus, the Reagents containing an oxygen-oxygen bond and Reagents containing an oxygen-metal bond are main types of the oxidizing agents used in oxidation reaction.

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The new pressure is 1.78 atm.

What Are The Gas Laws

The gas laws were developed in the early 17th century to help scientists determine volumes, amounts, pressures, and temperatures when it comes to gas-related issues. Three fundamental laws—Charles' Law, Boyle's Law, and Avogadro's Law—make up the gas laws (all of which will later combine into the General Gas Equation and Ideal Gas Law). The relationship between pressure, temperature, volume, and amount of gas is found using the three basic gas laws.

At initial, the pressure (Pi) is 0.80 atm.
At initial, the temperature (Ti) is (20+273)K that, is 293 K
The final temperature (T2) is (380+273)K that, is 653 K
Then, at constant volume:

P1/T1 = P1/T2
0.80/293 = P2/653
P2= 1.78

Therefore, the new pressure (P2) is 1.78 atm

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Melting, sublimation, and vaporizations are endothermic. Freezing, deposition, and condensation are exothermic.

What are endothermic and exothermic reactions?

Hence, all about exothermic and endothermic process.

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