I’m having trouble with this question I need some help please

Answers:

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Explanation:

For equation A, I'll transform the right hand side into a similar form as the left side. Throughout the steps below, the left hand side stays the same.

[tex]\sqrt{448x^c} = 8x^3\sqrt{7x}\\\\\sqrt{448x^c} = \sqrt{(8x^3)^2}\sqrt{7x}\\\\\sqrt{448x^c} = \sqrt{64x^{3*2}}\sqrt{7x}\\\\\sqrt{448x^c} = \sqrt{64x^{6}}\sqrt{7x}\\\\\sqrt{448x^c} = \sqrt{64x^{6}*7x}\\\\\sqrt{448x^c} = \sqrt{64*7x^{6+1}}\\\\\sqrt{448x^c} = \sqrt{448x^{7}}\\\\[/tex]

Therefore, c = 7

Notice that 7/2 = 3 remainder 1. The quotient 3 is the exponent for the term outside the root for [tex]8x^3\sqrt{7x}[/tex] while the remainder 1 is the exponent for the x term inside the root.

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We do the same idea for equation B.

[tex]\sqrt[3]{576x^{d}} = 4x\sqrt[3]{9x^{2}}\\\\\sqrt[3]{576x^{d}} = \sqrt[3]{(4x)^3}\sqrt[3]{9x^{2}}\\\\\sqrt[3]{576x^{d}} = \sqrt[3]{64x^3}\sqrt[3]{9x^{2}}\\\\\sqrt[3]{576x^{d}} = \sqrt[3]{64x^3*9x^{2}}\\\\\sqrt[3]{576x^{d}} = \sqrt[3]{64*9x^{3+2}}\\\\\sqrt[3]{576x^{d}} = \sqrt[3]{576x^{5}}\\\\[/tex]

This must mean d = 5

Note: 5/3 = 1 remainder 2, which means [tex]\sqrt[3]{x^5} = x^1\sqrt[3]{x^2} = x\sqrt[3]{x^2}[/tex]

Answer:

32 and 37

Step-by-step explanation:

Because the difference between the values is 5.

Answer: 4oz

Step-by-step explanation:

Answer:

10 quarters, 9 dimes, and 20 nickels.

Step-by-step explanation:

q - 1 = d, 2q = n or q = 1/2n

.25q + .10(q - 1) + .05(2q) = 4.40

.25q + .10q - .10 + .10q = 4.40

.45q - .10 = 4.40

.45q = 4.50

4.5/.45 = 10

He has 10 quarters, 9 dimes, and 20 nickels.

Answer:

constant over time

Step-by-step explanation: for every 3 cookies the cost goes up 2 dollars

well, a WHOLE is 1, which we can split in many fractions, say 5/5, 10/10 or 999/999 and so on.

we know 1/5 of the jar is chocolate chip, and there's the rest, well, the Whole jar in 5ths have to be 5/5, if we take away 1/5 from 5/5, the "rest" is 5/5 - 1/5 = 4/5.

now, we also know that 1/2 of the "rest" is peanut butter, or namely that 1/2 of 4/5 is peanut butter, how much will that be?  let's divide 4/5 by 2

[tex]\cfrac{4}{5}\div 2\implies \cfrac{4}{5}\div \cfrac{2}{1}\implies \cfrac{4}{5}\cdot \cfrac{1}{2}\implies \cfrac{4}{10}\implies \cfrac{2}{5}[/tex]

Answer:

2/5

Step-by-step explanation:

0.4 x 10/10

= 4/10 divide by 2

=2/5

Answer:

-15

Step-by-step explanation:

-16 -|-6| +7

-16 - 6 + 7

= - 15

Absolute value is just taking the positive value of a number.

Step-by-step explanation:

-16-(-2-4)+7=

-16-(-6)+7=

-16+6+7=

-16+13=

-3

The value of f(15), to the nearest hundredth is 253.88

The standard exponential equation is given as:

If f(4.5) = 16, then;

16 = ab^4.5 ..............1

Similarly, if f(9.5) = 60, then:

60 = ab^9.5 ........................... 2

Dividing both equations will give:

60/16 = ab^9.5/ab^4.5

60/16 = b^9.5-4.5

60/16 = b^5

3.75 = b^5

b = 1.3

Get the value of a. Recall that;

60 = ab^9.5

60 = a(1.3)^9.5

60 = 12.09a

a = 60/12.09

a = 4.96

Get the value of f(15)

f()15 = 4.96(1.3)^15

f(15) = 4.96(51.18)

f(15) = 253.88

Hence the value of f(15), to the nearest hundredth is 253.88

Learn more on exponential functions here: https://brainly.com/question/12940982

Answer:

3b

Step-by-step explanation:

Answer:

144

Step-by-step explanation:

divide 50 by 3 and then multiply by 9

[tex]\begin{cases} f(x) = x^4+14x\\ g(x) = 6-x \end{cases}\qquad \qquad h(x) = f(x) + g(x) \\\\\\ h(x) = (x^4+14x)+(6-x)\implies h(x) = x^4+14x-x+6 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill h(x) = x^4+13x+6~\hfill[/tex]

now, if we graph h(x), Check the picture below, we can see that horizontally the line keeps on moving towards the left, going going and going towards -infinity, and it also keeps on moving towards the right, going going and going towards +infinity, and since the horizontal area used by the function is the domain of it, the domain for h(x) will be (-∞ , +∞).

The degree of a vertex is defined as the number of edges that touch the vertex. The (i, j)-th entry of the adjacency matrix tells you whether vertex i touches vertex j (1 if yes, 0 if no). Then the degree of vertex i is equal to the sum of the i-th row in the adjacency matrix.

• vertex 1 : degree = 0 + 1 + 0 + 0 + 1 = 2

• vertex 2 : degree = 1 + 0 + 1 + 1 + 1 = 4

• vertex 3 : degree = 0 + 1 + 0 + 1 + 0 = 2

• vertex 4 : degree = 0 + 1 + 1 + 0 + 1 = 3

• vertex 5 : degree = 1 + 1 + 0 + 1 + 0 = 3

So, the correct answer is A. 2.

Answer:

No

Step-by-step explanation:

These are the artists of each subject, not the general function of each genre.

Brainliest for

Answer:

300

Step-by-step explanation:

[(-4 2/7) x (-18)] x (-3 8/9) x (-1)

= [-30/7 x -18] x -35/9 x -1

= 540/7 x -35/9 x -1

= -300 x -1

= 300

Answer:

check if the question I used is right or not

A

Step-by-step explanation:

the origin, (0, 0)

For center of dilation Q, the image of a point A after dilation by a factor of k is ...   A' = kA + (k-1)Q Then for points A, A', and dilation factor k, the center of dilation can be found to be ...   (A' -kA)/(k-1) = Q

Here, that is ...   Q = ((-2, -2) -(1/2)(-4, -4))/(1/2 -1) = (0, 0)/(-1/2)  

Q = (0, 0) 

Answer:

x = 4

Step-by-step explanation:

17x+2 = 18x-2

4 = x

good luck

Answer:

x = 4

Hope you could understand.

If you have any query, feel free to ask.

for the answer I think it is 2 cm

the answer : 10 cm :>

Answer:

A-4.51

Step-by-step explanation:

I was going to ask to what place but then I saw all the others wouldn't make sense.

The percentage of motorists falling in each category, in the long term, are as follows:

High-risk category = 70%

Low-risk category = 30%

Data and Calculations:

Risk Profile Categories of Motorists

                                                       High Risk      Low Risk

Probability of remaining

 in the same category                      50%              10%

Probability of moving to another

 category                                          50%              90%

Probability a motorist falling in the high-risk category = (50% x 50%) + (50% x 90%)

= 25% + 45%

= 70%

Probability a motorist falling in the low-risk category = (50% x 50%) + (50% x 10%)

= 25% + 5%

= 30%

Thus, the probability of a motorist falling in the high-risk category is 70%, while the probability of a motorist falling in the low-risk category is 30%.

Learn more about probability here: https://brainly.com/question/24756209

Answer:

1st one:5≥x>-infinity

2nd one :5<x<+infinity

3rd one :5>x>- infinity

Answer:

C. Multiply the first equation by -4

Step-by-step explanation:

Hi there!

In order to eliminate the y values, we would have to find a number in which the sum of the top y value and the bottom y value would equal 0. In this case, the bottom y value is equal to +4 (the +4y), so we would have to find the number that would add to make that 0, which is -4. Since the y value for the top equation is 1, all we have to do is multiply the equation by -4 so that our y value is equal to -4y and the y can be eliminated.

I hope this helps!!

Step-by-step explanation:

Q3

25 - (x-8)²/4 = [100 - (x-8)²]/4

[100 - (x²- 16x + 64)]/4

(100 - x² + 16x - 64)/4 = (-x² + 16x + 36)/4

(36 + 16x - x²)/4 = (36 - 2x + 18x - x²)/4

[2(18 - x) + x(18 - x)]/4 = [(2 + x)(18 - x)]/4

....proved

Q4

3(ax + 7) - 2(x + b) = 4x + 29

expanding,

3ax + 21 - 2x - 2b = 4x + 29

3ax - 2x + 21 - 2b = 4x + 29

Comparing terms; x terms,

3ax - 2x = 4x

3a - 2 = 4

3a = 6

a = 6/3

a = 2

constant terms,

21 - 2b = 29

21 - 29 = 2b

2b = -8

b = -8/2

b = -4

.... proved

Answer:

i think its a and d

Step-by-step explanation:

[tex] \huge \bf \: Question : [/tex]

[tex]3 = 2x[/tex]

This is an equation. We need to find the value of X and verify it.

[tex] \huge \bf \: Solution : [/tex]

Let's find out the value of X :-

[tex] \sf \implies \: 3 = 2x[/tex]

Firstly, over turn the equation :-

[tex]\sf \implies2x = 3[/tex]

Then, Divide both sides of this equation by 2 :-

[tex]\sf \implies \: \dfrac{2x}{2} = \dfrac{3}{2} [/tex]

Cancel 2/2 on this equation and Leave x :-

3/2 can't be cancelled.

[tex]\sf \implies \: \dfrac{ \cancel2x}{ \cancel2} = \dfrac{3}{2} [/tex]

[tex]\sf \implies \: x = \dfrac{3}{2} [/tex]

Hence the value of x is 3/2.

________________________________

[tex] \bf \huge \: Verification : [/tex]

Put the value of x on this equation :-

[tex]\sf \implies \: 3 = 2x[/tex]

On Putting 3/2 instead of x :-

As we know that x is multiplied with 2 so,

[tex]\sf \implies \: 3 = 2 \times \dfrac{3}{2} [/tex]

Simplify this equation(Cancel 2 and 2) :-

[tex]\sf \implies \: 3 = \cancel2 \times \dfrac{3}{ \cancel2} [/tex]

[tex]\sf \implies \: 3 = 3[/tex]

[tex]\sf \implies \bf \: L HS = RHS[/tex]

[tex] \boxed {\bf\huge Hence, verified.}[/tex]

______________________________________

I hope this helps!

Please let me know if you have any questions.

~MisterBrian

Answer:

Step-by-step explanation:

Is this the entire question? Some of it makes no sense without a diagram or something.

To get rid of A you actually have to solve the equation.

7h – 5(3h – 8) = –72        Remove the brackets

7h - 15h + 40 = - 72          Combine the like terms

- 8h + 40 = - 72                Subtract 40 from both sides

- 8h = -112                        Divide by -8

    h = 14

Well the depth is a whole number so A is true.

We don't know anything about time. But the answer is positive.

C is false because B is true.

We don't know exactly what the depth of the well is.

I would pick A, but you need the entire question.