I NEED HELP WITH MATH PLEASEEE??!

Answer:

x = -3

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Equality Properties

Distributive Property

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify.

3x + 2 = x + 4(x + 2)

Step 2: Solve for x

Answer:

x=-3

Step-by-step explanation:

3x+2=x+4(x+2)

3x+2=x+4x+8

3x=5x+6

3x-6=5x

-6=2x

x=-3

Answer: x = -3, 5, 4

Step-by-step explanation:

Don't have time for it

Answer:

-3; (8, -20)

Step-by-step explanation:

to find the rate of change we do (y2 - y1) / (x2 - x1)

basically we choose 2 points on y and subtract them while using the 2 points on x and subtracting them

after subtracting them we divide change of y by change of x

for this one i chose (3, -5) and (6, -14)

-14 - (-5) = -9

6 - 3 = 3

-9 / 3 = -3

the rate of change is three

to find the y intercept we can use this equation

y = -3x + b

and then plug in things

ill plug in the first set of coordinates

-5 = -3(3) + b

-5 = -9 + b

b = 4

so the y intercept is b

using this equation

y = -3x + 4

we can find out what value y is when the x value is 8

-3(8) + 4 = -20

Answer:

A: 150+(45•p)

B: 125+(50•p)

Step-by-step explanation:

You multiply the monthly fee by a letter representing an unknown number because we dont know how many months you are staying with each company and we add the one time fee because you are only paying once, so in conclusion you add the one time fee to the result of  the monthly fee by how many months.

a. If G(t) = a (1 + r)ᵗ, then G(0) = a corresponds to the starting area of the glacier, which is given to be 142 acres. So a = 142.

The area of the glacier shrinks by 4.4% each year. This means that after 1 year, the area is reduced to

142 - (4.4% of 142) = 142 (1 - 0.044) ≈ 135.75 acres

After another year,

135.75 - (4.4% of 135.75) = 135.75 (1 - 0.044) ≈ 129.78 acres

or equivalently, 142 (1 - 0.044)² acres.

And so on. After t years, the glacier would have an area of

G(t) = 142 (1 - 0.044)ᵗ   ⇒   G(t) = 142 × 0.956ᵗ

b. If the year 2007 corresponds to t = 0, then 2012 refers to t = 5. Then the area of the glacier is

G(5) = 142 × 0.956⁵   ⇒   G(5) ≈ 113.39 acres

c. Simply take the difference between G(5) and G(0) :

G(5) - G(0) ≈ 142 - 113.39 ≈ 28.61 acres

d. The average rate of change of G(t) from 2007 to 2012 is given by the difference quotient of G(t) over the interval 0 ≤ t ≤ 5 :

[tex]ARC_{[2007,2012]} = \dfrac{G(5) - G(0)}{5 - 0} \approx \dfrac{113.39 - 142}5[/tex]

so that ARC ≈ -5.72 acres/year. This rate tells us that a little less than 6 acres of glacial ice is lost each year, based on the reduction over the first 5 years.

e. The year 2017 refers to t = 10, so now we compute

[tex]ARC_{[2012,2017]} = \dfrac{G(10) - G(5)}{10 - 5} \approx \dfrac{90.55-113.39}5[/tex]

which comes out to about ARC ≈ -4.57 acres/year. Since this rate is smaller than the ARC between 2007 and 2012, this means that the glacial ice is disappearing at a slower rate in later years.

See below

[tex]\\ \sf\Rrightarrow y=-x+2[/tex]--(1)

[tex]\\ \sf\Rrightarrow y=x+1[/tex]--(2)

Now

[tex]\\ \sf\Rrightarrow -x+2=x+1[/tex]

[tex]\\ \sf\Rrightarrow -2x=-1[/tex]

[tex]\\ \sf\Rrightarrow x=0.5[/tex]

Put in eq(2)

[tex]\\ \sf\Rrightarrow y=0.5+1[/tex]

[tex]\\ \sf\Rrightarrow y=1.5[/tex]

Answer:

Step-by-step explanation:

#a

[tex]\\ \sf{:}\dashrightarrow -2(-4.5)=9.0[/tex]

#b

[tex]\\ \sf{:}\dashrightarrow (-8.7)(-10)=8.7[/tex]

#c

[tex]\\ \sf{:}\dashrightarrow (-7)(-2)=14[/tex]

#d

[tex]\\ \sf{:}\dashrightarrow (-9)(-10)=90[/tex]

Answer:

First what does x represent. For example x could equal 5 so (5)2 +2 simplified is 10 +2 which is 12 :)

Step-by-step explanation:

[tex]5y+2x = -7~~~~~......(i)\\\\y = -2x +5 ~~~~~~.....(ii)\\\\(i) -(ii):\\\\5y+2x -y = -7-(-2x+5)\\\\\implies 4y +2x = -7 +2x -5\\\\\implies 4y +2x -2x = -12\\\\\implies 4y = -12\\\\\implies y = - \dfrac{12}4 = -3\\\\\\\text{Substitute}~ y=-3~ \text{in equation (ii):}\\\\\\-3 = -2x +5\\\\\implies 2x = 5 +3 \\\\\implies 2x = 8\\\\\implies x = \dfrac 82 =4\\\\\text{Hence,}~ x = 4[/tex]

Answer:

to confusing

Step-by-step explanation:

Answer:

The nightly rate at Stargazer Suites is $25 more than the nightly rate at Retro Retreat.

Step-by-step explanation:

Answer:

Step-by-step explanation:

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

[tex]\\ \sf\Rrightarrow 0.02349[/tex]

[tex]\\ \sf\Rrightarrow 0.0235\times 10^{-1}[/tex]

[tex]\\ \sf\Rrightarrow 2.35\times 10^{-3}[/tex]

Option C is correct

[tex]0.002349 \\ estimate \: \: \: it \\ = 0.00235 \\ = 0.00235 \times 1000 \\ = 2.35 \\ therefore \\ 0.00235 \\ = 2.35 \times \frac{1}{1000} \\ = 2.35 \times {10}^{ - 3} [/tex]

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

Step-by-step explanation:

Given:

Find the number of Science Society members:

Find the total number of group members:

Find the number of Mathematics Society members:

[tex]32^{-\tfrac 25}\\\\=(2^5)^{-\tfrac 25}\\\\=2^{-2}\\\\=\dfrac 1{2^2}\\\\=\dfrac 14[/tex]

Answer:

B)

Step-by-step explanation:

10/5 + 4(72 - 6)

10/5 + 288 - 24          Distribute the 4 to 72 and 6

2 + 288 - 24               Divide

2 + 264                       Combine the like terms

262                        

Answer:

y = 4 (-3) - 2

y = -12 - 2

y = -14

Step-by-step explanation:

I suppose you mean to convert 58₁₀ to base 2, and not 5810₁₀ to base 2.

Write 58 as the sum of the largest powers of 2 that you can:

58 = 32 + 26

58 = 32 + 16 + 10

58 = 32 + 16 + 8 + 2

58 = 2⁵ + 2⁴ + 2³ + 2¹

58 = 1×2⁵ + 1×2⁴ + 1×2³ + 0×2² + 1×2¹ + 0×2⁰

⇒   58₁₀ = 111010₂

To convert from base 2 to base 10, write out and simplify the decimal expansion as in the last line of the previous example.

10111₂ = 1×2⁴ + 0×2³ + 1×2² + 1×2¹ + 1×2⁰

10111₂ = 16 + 0 + 4 + 2 + 1

⇒   10111₂ = 23₁₀

#a

[tex]\\ \sf\Rrightarrow (58)_{10}[/tex]

[tex]\\ \sf\Rrightarrow (2+8+16+32)_{10}[/tex]

[tex]\\ \sf\Rrightarrow (2^1+2^3+2^4+2^5)_{10}[/tex]

[tex]\\ \sf\Rrightarrow 0(2^0) 1(2^1)+0(2^2)+1(2^3)+1(2^4)+1(2^5)[/tex]

[tex]\\ \sf\Rrightarrow (111010)_2[/tex]

#b

[tex]\\ \sf\Rrightarrow (10111)_2[/tex]

[tex]\\ \sf\Rrightarrow 1\times 2^0+1\times 2^1+1\times 2^2+0\times 2^3+1\times 2^4[/tex]

[tex]\\ \sf\Rrightarrow 1+2+4+16[/tex]

[tex]\\ \sf\Rrightarrow (23)_{10}[/tex]

Here is my answer. I hope it is helpful.

Answer:

[tex]f(x)\div g(x)=x-10[/tex]

Step-by-step explanation:

[tex]\frac{x^2-19x+90}{x-9}[/tex]

[tex]\frac{(x-10)(x-9)}{x-9}[/tex]

[tex]x-10[/tex]

Answer:

[tex]f(x)\div g(x)=-10[/tex]

Step-by-step explanation:

Solve [tex]f(x)[/tex]

[tex]f(x)=x^2-19x+90[/tex]

[tex]x^2-19x+90[/tex]

[tex]\mathrm{Break\:the\:expression\:into\:groups}[/tex]

[tex]\left(x^2-9x\right)+\left(-10x+90\right)[/tex]

[tex]\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2-9x[/tex]

[tex]=x(x-9)[/tex]

[tex]\mathrm{Factor\:out\:-10\;from}\:\:-10x+90[/tex]

[tex]=-10(x-9)[/tex]

[tex]=x\left(x-9\right)-10\left(x-9\right)[/tex]

[tex]\mathrm{Factor\:out\:common\:term\:}x-9[/tex]

[tex]\bold{\left(x-9\right)\left(x-10\right)}[/tex]

Solve [tex]g(x)[/tex]

[tex]g(x)=x-9[/tex]

[tex]\bold{x-9}[/tex]

[tex](x-9\right)\left(x-10)}\div \:x-9[/tex]

Now, solve:

[tex](x-9\right)\left(x-10)}\div \:x-9[/tex]

[tex]=\frac{(x-9)\left(x-10)}{:x-9}[/tex]

[tex]= -10[/tex]

Therefore, [tex]f(x)\div g(x)=-10[/tex]

a) Write an expression to describe the journey of the yellow submarine.

-> ((0 - 40) + 30) - 25

[] Sea level = 0

[] The descend 40 meters = -40

[] After examining the sea, they rose 30 meters = + 30

[] They dove 25 meters to look at an octopus = -25

b) At what depth did they stop to look at the octopus?

-> -35 meters

[] The started at 0 (0), descended 40 (-40), rose 30 (-10), and then sove 25 (-35) to see the octopus

[] Another way to think of this is to simplify our previous expression completely

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Answer:

8/7A - C = B

Step-by-step explanation:

A= 7/8(B+C)

Multiply both sides by 8/7

8/7A = B + C

Subtract C

8/7A - C = B

Answer:

There’s a subtle, but important difference between these 2 methods of handling events. If you’ll use the first method, event handlers, the difference is that if you add two event handlers for the same button click, the second event handler will overwrite the first and only that event will trigger

Step-by-step explanation:

i hope this answer your questions

Answer:

  y = 18

Step-by-step explanation:

Direct variation means y will change by the same factor x does. When x changes by a factor of 15/10 = 1.5, the value of y will change by that same factor

  x = 10, y = 12

  x= 15, y = 1.5×12 = 18

The new value of y is y = 18.

_____

Written as a proportion, you have ...

  y/15 = 12/10

  y = 15×12/10 = 18

__

Written as a direct variation equation, you have ...

  y = kx

  12 = k·10   ⇒   k = 1.2

  y = 1.2·15 = 18 . . . . for x=15

Answer: C. Distributive Property

Step-by-step explanation: To simplify this expression, you would multiply 6 by y and 2.

Answer:

the start numbew woould be 26

Step-by-step explanation:

6 less than 26 is 20

Answer:

n=26

Step-by-step explanation:

Answer:

yes they form a proportion

Answer:

1. if x + 5 = 12, then x = 7

:Subtraction property of equality

2. If x + y = 20, and y = 5, then x + 5 = 20.

:Substitution property of equality

3. If 2x3 = 11, then 11 = 2x - 3.

:Symmetric property of equality

The angles, 60°, [tex]\displaystyle \frac{\pi}{4}[/tex] and [tex]\displaystyle \frac{\pi}{6}[/tex] are special angles that have known trigonometric ratio values.

First part;

Second part;

Third part;

Reasons:

First Part;

Considering a unit circle with the center at the origin of the graph, we have;

The sine of the angle, θ, rotated by the radius is the vertical distance of a point P on the circle which is the location of the radius, from the horizontal axis.

The cosine of the angle, θ, is the horizontal distance of P from the vertical axis, such that we have;

The coordinates of point P = (cos(θ), sin(θ))

In the four quadrant, we have;

First Quadrant; All trigonometric ratios are positive

Second Quadrant; sine is positive

Third Quadrant; Tan is positive

Fourth Quadrant; Cosine is positive

Second part;

We have; At 120°, the point P is the same elevation from the horizontal axis, therefore;

sin(60°) = sin(120°) = 0.5·√3

However, the x-coordinate of the point P is in the negative direction, therefore, we get;

cos(120°) = -cos(60°) = -0.5

Similarly from the quadrant relationship, we have;

240° is in the third quadrant, and it is 60° below the negative horizontal line, therefore;

sin(240°) = -sin(60°) = -0.5·√3

cos(240°) = -cos(60°) = -0.5

300° is in the fourth quadrant, and it is 60° below the positive x-axis, therefore;

sin(300°) is negative and cos(300°) is positive

Which gives;

sin(300°) = -sin(60°) =  -0.5·√3

cos(300°) =  cos(60°) = 0.5

Third part;

[tex]\displaystyle \frac{\pi}{4} =45^{\circ}[/tex]

[tex]\displaystyle \frac{\pi}{6} =30^{\circ}[/tex]

The sine and cosine of 45° can be used to find the sine and cosine of (180° + 45°) = 225°, (360° - 45°) = 315°

Also, due to the mid location of the angle 45° on the quadrant, we have;

Another angles is the sines and cosine of (90° + 45°) = 135°

Therefore, [tex]\displaystyle \frac{\pi}{4}[/tex], can be used to find the sine and cosine of 135°, 225°, and 315°

[tex]\displaystyle 135^{\circ} = \mathbf{\frac{3 \cdot \pi}{4}}[/tex], [tex]\displaystyle 225^{\circ} = \frac{5 \cdot \pi}{4}[/tex], [tex]\displaystyle 315^{\circ} = \frac{7 \cdot \pi}{4}[/tex]

Therefore,

[tex]\displaystyle \frac{\pi}{4}[/tex] can be used to find the sine and cosine of [tex]\displaystyle \mathbf{\frac{3 \cdot \pi}{4}}[/tex], [tex]\displaystyle \mathbf{\frac{5 \cdot \pi}{4}}[/tex], and [tex]\displaystyle \mathbf{ \frac{7 \cdot \pi}{4}}[/tex]

Similarly, the sine and cosine of, [tex]\displaystyle \frac{\pi}{6}[/tex]  = 30° can be used to find the sine and cosine of 150°,  210°, and 330°.

[tex]\displaystyle 150^{\circ} = \frac{5 \cdot \pi}{6}[/tex], [tex]\displaystyle 210^{\circ} = \frac{7 \cdot \pi}{6}[/tex], and [tex]\displaystyle 330^{\circ} = \frac{11 \cdot \pi}{6}[/tex]

[tex]\displaystyle \frac{\pi}{6}[/tex], can be used to find the sine and cosine of [tex]\displaystyle \mathbf{ \frac{5 \cdot \pi}{6}}[/tex], [tex]\displaystyle \mathbf{ \frac{7 \cdot \pi}{6}}[/tex], and [tex]\displaystyle \mathbf{\frac{11 \cdot \pi}{6}}[/tex]

Learn more about the sine and cosine of angles here:

https://brainly.com/question/4372174

Answer:

Step-by-step explanation:

The cosine value of an angle is the x coordinate of the point the angle corresponds to on the unit circle, and the sine value of an angle is the y coordinate of that point. 120, 240, and 300 all form 60 degree reference angles which in turn forms 30-60-90 triangles which help to find the sine and cosine of these corresponding angles. Pi/4 radians converts to 45 degrees which forms a 45-45-90 special triangle on the unit circle which has its own known trigonometric ratio. Pi/6 radians converts to 30 degrees which forms a 30-60-90 triangle on the unit circle which also has a known trigonometric ratio. These ratios help find the sine and cosine of the angles on the unit circle which corresponds to a point on the coordinate plane.