i need help especially for #4

Forever c x stays in the set but x+y may be out side the set.

What is set?

A set comprises elements or members that can be mathematical objects of any sort, including numbers, symbols, points in space, lines, other geometric forms, variables, or even other sets. A set is the mathematical model for a collection of various things.

a consider the set of vectors in [tex]$\mathbb{R}^2$[/tex]

[tex]A=\left\{\left(x_1, x_2\right) \in \mathbb{R}^2 \mid x_2 \geqslant 2\right\} .$$[/tex]

where[tex]$x=\left(x_1, x_2\right)$[/tex]

Then for any [tex]$x=\left(x_1, x_2\right), y=\left(y_1, y_2\right) \in A$[/tex]

ere that[tex]$x+y=\left(x_1+y_1, x_2+y_2\right) \in A\left(\right.$ Since $x_2+y_2 \geqslant 2+2$[/tex]

But take [tex](4,2) \in A$.[/tex]

Then [tex]\frac{1}{2}(4,2)=(2,1) \notin A$.[/tex]

ce. [tex]$\frac{1}{2}(4,2)$[/tex] belongs outside the set

i.. I some vectors in A such that[tex]\frac{1}{2} x \notin A$[/tex].

b Consider the set of vectors in [tex]$\mathbb{R}^2$[/tex]

[tex]A=\left\{\left(x_1, x_2\right) \in \mathbb{R}^2 \mid \begin{array}{ll}\frac{1}{2} x_1 \leq x_2 \leq \frac{3}{2} x_1 & \text { if } x_1 \geqslant 0 \\\frac{3}{2} x_1 \leq x_2 \leq \frac{1}{2} x_1 & \text { if } x_1 < 0\end{array}\right\}$$[/tex]

The geometrical representation of this set is

see that for any scalar [tex]$c, \quad c x=e\left(x_1, x_2\right) \in A$[/tex]. But if we take [tex](3,2) *(-2,3-3) \in A$ but $(3,2)+(-2,-3)=(1,-1) \& A$[/tex].

Thus forever c x stays in the set but x+y may be out side the set.

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Answer:

x = 3

Step-by-step explanation:

You want to solve for x, so you want to get x on one side of the equation. To do this, you can add the -12.18 to both sides of the equation (you add since it's negative).

2.14x - 12.18 = -5.76

2.14x = 6.42

Then you want to get x by itself, without the 2.14 in front of it. To do this, you can divide both sides of the equation by 2.14.

This will give you,

x = 3

The customer who purchases 10 Microsoft 365 Business Premium licenses at $22 each per month, for a full year, then 6 months later decides they only need 5 licenses for the remainder of the year, would pay a total charge of $1,980 with a credit of $660 for the year.

The total charge the customer will pay is based on the difference between the total charge for the year and the prorated charge of credit for non-usage.

The charge per month for Microsoft 365 =  $22

The charge per month for 10 Microsoft 365 = $220 ($22 x 10)

The charge for 1 year for one Microsoft 365 = $264 (22 x 12)

The charge for 6 months for 10 Microsoft 365 = $1,320 ($220 x 6)

The charge for 12 months for 10 Microsoft 365 = $2,640 (220 x 12)

The prorated charge for 6 months for 5 Microsoft 365 returned = $660 ($2,640 x 5/10 x 6/12)

The initial total charge for the year = $2,640

The total credit for the year = $660

The total charge for the year = $1,980 ($2,640 - $660)

Thus, the customer will pay $1,980 after receiving a prorated credit for 5 returned licenses worth $660.

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Answer: 13h

Step-by-step explanation:

126 + 20 = 146
250 - 146 = 104
104 : 8 = 13

He will need 13h

Answer:

13.5

126 plus 20 is $146

250 minus 146 is 108

108 divided by 8 is 13.5

Answer: Choice A, Choice B, Choice C

In other words, it's nearly everything but choice D.

====================================================

Explanation:

Let's say we select "2" as the thing to fill the blank.

2x+3 = -4x+17

2x+4x = 17-3

6x = 14

x = 14/6

x = 7/3

We get one solution in this case.

The same applies for the values 5 and 7. I'll let you do those steps.

In contrast, if we filled the blank with -4, then,

-4x+3 = -4x+17

-4x+4x = 17-3

0x = 14

0 = 14

We get a contradiction which leads to "no solutions".

Visually, the equations y = -4x+3 and y = -4x+17 are parallel lines that never intersect. We need them to intersect if we want a solution. Recall that parallel lines have equal slopes but different y-intercepts. Both sides have a slope of -4 in this case.

Therefore, the quick rule of thumb is this: if the slopes are not equal, then the linear equation has exactly one solution.

(i) At a total of 100 Songs the Charges for Company A and Company B will be Equal.

(ii) I would rather suggest to select Company A as the Total Charges to download 150 Songs is $127.5

What is Linear Equation in One Variable?

A linear equation is a one-variable equation of a straight line. The variable's only power is 1. Linear equations in one variable have the form ax + b = 0 and are solved using simple algebraic techniques.

Solution:

Let, Songs Downloaded be x

Total Charges of Company A = 15 + 0.75*x

Total Charges of Company B = 0.9*x

(i) Total Charges by Company A = Total Charges by Company B

15 + 0.75*x = 0.9*x

15 = 0.15*x

x = 100 songs

(ii) Charges by Company A to Download 150 Songs = 15 + 0.75 * 150

= 15 + 112.5 = $127.5

Charges by Company B to Download 150 Somgs = 0.9 * 150 = $135

I would rather suggest to select Company A as the Total Charges to download 150 Songs is $127.5

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The value of y varies directly with x, and the constant of variation is 3, and function rule y = 3x.

When one value is dependent on another i.e if one value increases with respect to another or if one value decreases with respect to another then we can say that the two quantities are in direct variation.

In simple words,  It is the relationship between two variables where one of the variables is a constant multiple of the other.

When two values a and b are varies directly then the relation between them can be shown as given below

=> a ∝ b

=> a = kb  here 'k' constant of variation

Here we have

x values    57   63   66  

y values    19    21    22  

Let's assume that y varies directly with x  

=>  y ∝ x

=>  y = kx ---- (1)  

Where k is the proportionality constant    

From (1)

We can write k = x/y

From the above calculations, if y varies directly with x then x/y must be a constant.

Now check whether the given value can give a constant

At  x = 57 and y = 19

[tex]= > \frac{x}{y} = \frac{57}{19} = 3[/tex]  

At  x = 63 and y = 21

[tex]= > \frac{x}{y} = \frac{63}{21} = 3[/tex]  

At  x = 66 and y = 22

[tex]= > \frac{x}{y} = \frac{66}{22} = 3[/tex]    

From the above calculation,

For given x and y values, x/y is always constant

Therefore,  

It is true that y varies directly with x, and the constant of variation is 3    

Here the function rule will be  y = x × constant of variation

=> y = 3x

Therefore,

The value of y varies directly with x, and the constant of variation is 3, and function rule y = 3x

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The correct option is the value of the digit 1 in the actual measurement is 110 the value of the digit 1 in the original measurement. (option C)

Here is the place value of each of the digits in the wrong table length :

1 = thousand

6 = hundred

0 = tens

2 = units

5 = tenth

Here is the place value of each of the digits in the actual table length :

1 = hundred

6 = tens

2 = units

5 = tenth

5 has the same value in both the wrong length and the right length.

The value of 6 in the actual measurement is ten times that of the wrong measurement .

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The ratio of 27 feet to 8 yards is 9/8 while converting feet to yards and the ratio is also 9/8 while converting yards to feet.

Yards and feet are units use to measure the length of geometrical shapes.

1 foot equal to 0.333 yards and similarly 1 yard equal to 3 feet. There is proportional relationship between them.

We got the same fraction value from the ratio of two units which implies that the two units are proportional.

1 foot =0.333 yard so

27 feet = 9 yards

similarly, 1 yard = 3 feet

so, 8 yard = 24 feet

hence, the ratio is 9/8

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Answer:

Imma write it in the explanation

Step-by-step explanation:

6. interior angles, alternate angles

for c to be parallel with d, we need 2 and 7 to be interior angles (a+b=180°, u/c shaped), and 3 and 5 to be alternate angles (a=b, z shaped).

7. 1+3=180°, 2+4=180°

there were 2 parallel lines in a trapezium, so for the c shape on 1 and 3 they add up to 180°, and same thing to 2 and 4.

Option D is the correct answer. Paired samples t-test is the same as the dependent t-test, but different from one sample z-test.

The dependent t-test also called the paired t-test or paired-samples t-test compares which means the two related groups to determine whether there is a statistically significant difference between these means.

The T-test is defined as a univariate hypothesis test that is based on a t-statistic, On the other side, Z-test is also a univariate test that is based on a standard normal distribution.

There is a small comparison between the t-test and z-test:

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Answer: $11.94

Step-by-step explanation: 4 x 0.99 = $3.96 and then 2 x $3.99 = $7.98 now $7.98 + $3.96 = $11.94

Answer:

x = -3

Step-by-step explanation:

0.2x + 2 = 0.2(4 - x)

0.2x + 2 = 0.8 - 0.2x

0.4x = -1.2

x = -1.2/0.4

x = -3

To find the slope of a line that passes through two points, you can use the formula:

slope = (y2 - y1)/(x2 - x1)

In this case, the two points are (0,0) and (1/3, 7/3). Substituting these values into the formula, we get:

slope = (7/3 - 0)/(1/3 - 0)

slope = 7/3

Therefore, the slope of the line that passes through (0,0) and (1/3, 7/3) is 7/3.

is that even a question bro?

The sample size needed is at least 311.17.

We have that to find our α level, that is the subtraction of 1 by the confidence interval divided by 2. So:

α = [tex]\frac{1-0.95}{2} = 0.025[/tex]

Now, we have to find z in the Z-table as such z has a p-value of 1-α

So it is z with a p-value of , so

1-0.025 = 0.975, so z = 1.96

Now, find the margin of error M as such

[tex]M = z*\frac{sd}{\sqrt{n} }[/tex]

where sd = σ = standard deviation

At least n, in which N is found when M= 0.06 and σ = 0.54. So

 [tex]M = z*\frac{sd}{\sqrt{n} } \\0.06 = 1.96 * \frac{0.54}{\sqrt{n}} \\\sqrt{n} = \frac{1.96*0.54}{0.06} \\\sqrt{n} = 17.64\\n = 311.1696\\[/tex]

Rounding off to the nearest integer, we get n = 311.17.

Thus, the sample size needed is at least 311.17.

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The true or false values of the statements are:

From the question, we have the following parameters that can be used in our computation:

C(m) = 4.50m + 7

The smallest number of mugs she can sell is 0

So, we have the following equation

C(0) = 4.50 * 0 + 7

Evaluate

C(0) = 0

This means that the range is y ≥ 0

Next, the domain cannot be all real numbers

This is because real numbers include negative and decimal numbers

For the y-intercept, we have

C(m) = 4.50m + 7

Set m to 0

y-intercept = 4.5 * 0 + 7

Evaluate

y-intercept = 7

For the y-intercept, we have

C(m) = 4.50m + 7

Set C(m) to 0

4.5 * x-intercept  + 7 = 0

Evaluate

x-intercept = -7/4.5 -- this cannot be taken as the x-intercept  because it is a negative number

Also, we have the slope to be 4.5

So, the rate of change is $4.5 per mug

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The expected value is 160 and SE for the number of students in the sample is 9.78

a)Given: students of which 25000 of which 10000 are older than 25 and 25000-10000=15000 are not older than 25.

we represent 400 students by drawing 400 tickets from a box that contains 15000 tickets labeled 0 and 10000 tickets labeled 1

Expected value and standard deviation of a box:

First, we determine the expected value of the box, which is the sum of all values on the tickets by the number of tickets.

[tex]expected value box=\frac{15000*0+10000*1}{25000}\\\\ =\frac{10000}{25000} =\frac{2}{5}[/tex]

expected value box=0.4

let us next determine the standard deviation using the shortcut formula:

SD=(big number-small number)*√fraction with small number*fraction with a small number.

[tex]SD=(1-0)*\sqrt{\frac{10000}{25000} *\frac{15000}{25000} \\\\SD=1*\sqrt{\frac{2}{5} *\frac{3}{5} } \\SD=1*\sqrt{\frac{6}{25} } =\frac{\sqrt{6} }{5}[/tex]

SD=0.4899.

Expected value sum=Number of draws*expected value box

                                  =400*0.4

Expected value sum=160

standard error of the sum is the product of the square root of the number of draws and the standard deviation of the box.

SE Sum=√number of draws*SD box

SE Sum=√400*0.4899

             =20*0.4899

 SE Sum=9.78

b)EXpected value and standard error:

The expected value of the percentage is the expected value of the sum divided by the number of draws.

Expected value percentage=Expected value sum/Number of draws*100%

                                               160/400*100

                                              =0.4*100%

Expected value percentage=400%

The standard error of the percentage is the standard error for the sum divided by the sample size:

SE%=SE for number/Number of draws*100%

         =9.798/400*100%

          =0.0245*100%

  SE% =2.45%

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(a) For positive Linear Regression , Y score will be above mean .

(b) For negative Linear Regression , Y score will be below the mean .

What is Linear Regression ?

The term Linear regression analysis is used to predict the value of one  variable based on the value of another variable.

Part(a)

when the relationship of regression between two variables is positive then if one variable increase the other variable also increases ,

So , if the the x score is above the mean then the Y score will be also above the mean .

Part(b)

when the relationship of regression between two variables is negative then if one variable increase the other variable decreases ,

So , if the the x score is above the mean then the Y score will be below the mean .

Therefore , (a) Y score will be above the mean .

(b) the Y score will be below the mean .

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With the mid segment of the triangle MNP as M (-1, 3), N (4, 0), P (-2, -2) the coordinates of the triangle are

The coordinates is calculated from the midsegment using the formula

X= (x₂ + x₁)/2

Y = (y₂ + y₁)/2

Vertex 1 and 2: point  M  (-1, 3),  

X

-1 = (x₂ + x₁)/2

-2 = x₂ + x₁

Y

3 = (y₂ + y₁)/2

6 = y₂ + y₁

Vertex 2 and 3:  point N (4, 0)

X

4 = (x₂ + x₃)/2

8 = x₂ + x₃

Y

0 = (y₂ + y₃)/2

0 = y₂ + y₃

Vertex 1 and 3:  point P(-2, -2)

X

-2 = (x₃ + x₁)/2

-4 = x₃ + x₁

Y

-2 = (y₃ + y₁)/2

-4 = y₃ + y₁

The equations

X

-2 = x₂ + x₁

8 = x₂ + x₃

-4 = x₃ + x₁

Y

6 = y₂ + y₁

0 = y₂ + y₃

-4 = y₃ + y₁

from -2 = x₂ + x₁, we find x₁ = -2 - x₂

plugging in x₁ = -2 - x₂ to -4 = x₃ + x₁ gives

-4 = x₃ + -2 - x₂

-2 = x₃ - x₂

then we have

8 = x₂ + x₃

-2 = x₃ - x₂

solving simultaneously

x₃ = 3, x₂ = 5 then x₁ = -2 - x₂ = -7

from 0 = y₂ + y₃, we find that y₂ = -y₃

plugging in y₂ = -y₃ into 6 = y₂ + y₁ gives

6 = -y₃ + y₁

then we have

-4 = y₃ + y₁

6 = -y₃ + y₁

solving simultaneously gives

y₁ = 1, y₃ = -5, then y₂ = -y₃ = -(-4) = 5

The vertex of the triangle are

(-7, 1), (5, 5), and (3, -5)

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Answer:

Pie heysgeusuwhueywgyssyywyw

y = p x is Proportional relationship.

What is proportional relationship?

Proportional relationships are relationships between two variables where their ratios are equivalent. Another way to think about them is that, in a proportional relationship, one variable is always a constant value times the other. That constant is know as the "constant of proportionality".

The answer depends on the equation given.

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Answer:

b

Step-by-step explanation:

a variable is an unknown number normally represented by a letter and in this case the variable is b

hopes this helps please mark brainliest

The equation of the ellipse is x²/8² + y²/(2√15)² = 1.

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

Example:

2x + 4 = 9 is an equation.

We have,

Foci: (-2, 0) and (2, 0)

Length of major axis: 8

The equation of an ellipse.

x²/a² + y²/b² = 1

Where a is the major axis and b is the minor axis.

Now,

b² + c² = a²

c = 2

a = 8

b² = a² - c²

b² = 64 - 4

b² = 60

b = √60

b = √(4 x 15)

b = 2√15

Now,

x²/a² + y²/b² = 1

x²/8² + y²/(2√15)² = 1

Thus,

The ellipse equation is x²/8² + y²/(2√15)² = 1.

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Answer:

D

Step-by-step explanation:

3x - 2y = 10 → (1)

2y = 3x - 16 → (2)

substitute 2y = 3x - 16 into (1)

3x - (3x - 16) = 10

3x - 3x + 16 = 10

16 = 10 ← not possible

this indicates the system has no solution.

There is no solution to this system. Therefore, option D is the correct answer.

A system of linear equations consists of two or more equations made up of two or more variables such that all equations in the system are considered simultaneously. The solution to a system of linear equations in two variables is any ordered pair that satisfies each equation independently.

The given that the system of linear equations are

3x - 2y = 10 -------(i)

2y = 3x - 16

3x-2y=16 -------(ii)

Subtract equation (ii) from equation (i), we get

3x-2y-(3x-2y)=10-16

0≠4

Therefore, option D is the correct answer.

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Answer:Żeby obliczyć ilu rodziców wolontariuszy potrzeba, najpierw trzeba obliczyć ile uczniów będzie brało udział w wycieczce. W klasie piątej jest 20 uczniów, z czego 90% ma pozwolenie na wyjazd, czyli 20 x 0,9 = 18 uczniów z piątej klasy pojedzie na wycieczkę. W klasie szóstej jest też 20 uczniów, z czego 90% ma pozwolenie na wyjazd, czyli 20 x 0,9 = 18 uczniów z szóstej klasy pojedzie na wycieczkę. Razem będzie 18 + 18 = 36 uczniów.

Szkoła wymaga 1 rodzica wolontariusza na każdych 8 uczniów, więc na 36 uczniów potrzeba 36/8 = <<36/8=4.5>>4,5 rodziców wolontariuszy. Ponieważ rodzice wolontariuszy trzeba wybrać całymi osobami, to potrzeba ich 5.

Odpowiedź: Potrzeba 5 rodziców wolontariuszy.

Step-by-step explanation:

a) A minimum number of dogs that could have a mass of more than 24 kg is 6.

b) The maximum number of dogs that could have a mass of more than 18 kg is 20.

We will rearrange the function using fundamental algebraic concepts to process the value of x when the derivative equals 0. This response gives  us the x-coordinate of the function's vertex, which is the point that  the maximum or minimum will occur. To find the minimum or maximum, we will start by rewriting the solution into the original function.

From the given parameters, we can see that the minimum of the values present in the interval 20 to 40 is 6

From the given parameters, we can see that the maximum of the values present in the interval 20 to 40 is;

(12 + 6) = 18

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