Answer:
actually you can't find it without acceleration.
you need to use one of these three equations
1- Vf = Vi + at
2- 2ad = Vf^2 - Vi^2
3- d = Vit + 1/2 at^2
A 100 g mass of tungsten at 100.0°C is placed in 200 g of water at 20.0°C. The
mixture reaches equilibrium at 21.6°C. Calculate the specific heat of tungsten
The specific heat capacity of tungsten given the data from the question is 0.17 J/gºC
Data obtained from the questionMass of tungsten (M) = 100 g
Temperature of tungsten (T) = 100 °C
Mass of water (Mᵥᵥ) = 200 g
Temperature warm water (Tᵥᵥ) = 20 °C
Specific heat capacity of the water (Cᵥᵥ) = 4.184 J/gºC
Equilibrium temperature (Tₑ) = 21.6 °C
Specific heat capacity of tungsten (C) = ?
How to determine the specific heat capacity of tungstenHeat loss = Heat gain
MC(T – Tₑ) = MᵥᵥCᵥᵥ(Tₑ – Tᵥᵥ)
100 × C × (100 – 21.6) = 200 × 4.184(21.6 – 20)
100 × C × 78.4 = 1338.88
Divide both sides by 100 × 78.4
C = 1338.88 / (100 × 78.4 )
C = 0.17 J/gºC
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The definition of energy is the ability to ___________.
(Hint: one word)
nitrogen dioxide is a major component of smog which type of chemical reaction creates this product?
a. synthesis reaction
b. replacement reactions
c. combustion reactions
d. decomposition reaction
Answer:
A.synrhesis reaction
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Both igneous and sedimentary rock can become metamorphic rock if enough ________________ are applied.
Your mother asks you to carry a load of wood to the fireplace and lower it to the hearth. In doing this you have used your arms as levers. Which statement describes this as a class three lever?
Question 13 options:
The wood in your hands was the fulcrum, the load your elbow, and the effort (input force) was supplied by your arm muscles.
The wood was the load in your hands, the fulcrum was your elbow and the effort (input force was supplied by your arm muscles.
The fulcrum was the muscles in your arms, the load was the wood in your hands and the effort (input force) was the elbow.
Answer: The correct answer is the weight of the wood.
Explanation:
Hope this helps
A 3.1 kg carton's GPE was increasing by 7.8 J as it was lifted above the ground. How high was it lifted?
Answer:it was lifted
Explanation:
by me lifting it because i can life it very high
How to do this question plz
Answer:
Let L be the length of the wire.
N λ = M L where N is the number of wavelengths λ. Also, M and are integers and L is the length of the wire
There must be nodes at the ends of the wire and anti-nodes at the points of zero displacement - λ/2, λ, 3λ/ 2, etc.
The simplest would be 2 λ = L or L = λ / 2
In such a situation one would have
N-A-N or node-antinode-node
There is a 180 degree phase change upon reflection of the wave creating the standing wave
The distance between nodes or anti-nodes must be λ/2 and there must be nodes at the ends of the wire
The smallest possible particle of complete matter is the atom. True or false?
true
false
Answer:
TRUE !!
Explanation:
An atom is the smallest particle of an element
18 through 22 multiple choice please help
Answer:
18:equilibrium
19:10.8
20:separating the surfaces with a layer of air
21:it remains motionless
22:cm/s
Objects 1 and 2 attract each other with a gravitational force
of 18.0 units. If the mass of Object 1 is doubled mass of object 2 is tripled AND the
distance separating Objects 1 and 2 is halved, then the gravitational force will be
new gravitational force will be
units.
The new gravitational force of the two objects will be 432 N.
The given parameters:
Force between object 1 and object 2, F = 18 NLet the mass of object 1 = m1Let the mass of object 2 = m2Let the distance between the two object = rThe gravitational force between the two objects is calculated by applying Newton's law of universal gravitation;
[tex]F = \frac{Gm_1m_2}{r^2} \\\\G = \frac{Fr^2}{m_1m_2}\\\\G = \frac{Gm_1m_2}{r^2} \\\\G = \frac{18r^2}{m_1m_2}[/tex]
when the mass of the object 1 = 2m1mass of the object 2 = 3m2distance between the two object = ¹/₂r[tex]\frac{18r^2}{m_1 m_2 } = \frac{F_2(\frac{1}{2}r)^2 }{2m_1 \times 3m_2} \\\\\frac{18r^2}{m_1 m_2 } = \frac{F_2 \times r^2}{4 \times 2m_1 \times 3m_2} \\\\\frac{18r^2\times 4 \times 2m_1 \times 3m_2}{m_1 m_2\times r^2 } = F_2\\\\432 \ N = F_2[/tex]
Thus, the new gravitational force of the two objects will be 432 N.
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The Sun has a mass of 1.99 x 10^30kg [^30 is an exponent] and is 1.5 x 10^11m [^11 is an exponent] from the earth. The planet Earth is 5.98 x 10^24kg [^24 is an exponent]. What is the gravitational attraction between the sun and the earth? G=6.67×10^-11 (-11 is an exponent)
We are given –
Mass of earth,m = 5.98×10²⁴ kgMass of sun, M= 1.99×10³⁰ kgDistance between Earth andSun, r= 1.5×10¹¹ m
G = 6.67×10⁻¹¹ Nm²/kg²We are asked to find the gravitational attraction between the sun and the earth.
By Universal Law of Gravitation, we know that –[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\sf F = \dfrac{GMm}{r²}}[/tex]
Substituting values, we get –
[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf F = \dfrac{6.67×10^{-11}\times 5.98×10^{24}\times 1.99×10^{30}}{(1.5×10^{11})^2}[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf F = \dfrac{6.67×10^{-11}×5.98×10^{24}×1.99×10^{30}}{2.25×10^{22}}[/tex]
[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf F = 35.27×10^{21}[/tex]
[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf F = 3.53×10^{22} N}[/tex]
Henceforth ,gravitational attraction between the sun and the earth. is 3.53×10²²N .______________________________________________
Classify the statement below as either Speed or Velocity?
A jeep was driving 40 mph
heading to the grocery store.
Answer:
Hello There!
It is Speed.
[tex]\Large\bold\red{Reason}[/tex]
Because in the question it is said that at which speed car is travelling.
Speed is a scalar quantity.
If it is velocity then first know this that it is a vector quantity.
It must include both magnitude and direction.
If it is velocity then it would be 40 mph east or west or north or south.
I hope it is helpful to you...Cheers!_____________[URGENT] A swimmer wants to end up at a dock due north of her starting position on the south shore of a river. In still water her maximum speed is 1.25m/s. The river has a current flowing 0.35m/s [E].
a.) calculate the direction that she must aim herself through the water to arrive at the dock.
b.) how long will it take for the swimmer to cross the river, if the distance from the starting point to the dock is 300 m?
Please show all your work, thanks
Explanation:
As you can see in the picture, we want the swimmer to go on a straight line, so the speed of the water must be equal to the speed of the swimmer along the x-axis. We also know the value of v, so we can calculate the of the cosine of the angle (alpha) between Vx and V. Thanks to the fundamental relation of gioniometry (cos^2(x) + sin^2(x) = 1) we can find the sine of alpha and calculate Vy. With Vy we can calculate the time that the swimmer will use for reaching the dock: s = Vy * t => t = s/(Vy).
I'll let you do all the calculations, you just have to plug in values.
a)The direction that she must aim herself through the water to arrive at the dock will be 73.7°.
b)The time it takes for the swimmer to cross the river will be 240 seconds.
What is speed?Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while v for the final speed. its si unit is m/sec.
Given data;
The maximum speed of the swimmer In still water,v=1.25m/s.
Speed of river = 0.35m/s [E]
α is the direction that she must aim herself through the water to arrive at the dock.
t is the time it takes for the swimmer to cross the river
The distance from the starting point to the dock is,s = 300 m
If the swimmer were to swim straight, the water's speed along the x-axis would have to match that of the swimmer.
[tex]\rm v_w = v_x = 0.35 \ m/sec[/tex]
α is the angle between vx and v
The value of the
[tex]\rm cos \alpha = \frac{v_x}{v} \\\\ \alpha = cos ^{-1}(\frac{0.35}{1.25} )\\\\ \alpha = 73.7 ^0[/tex]
The time that the swimmer will use for reaching the dock;
s = V×t
t = s/(v)
t=300 m / 1.25 m/sec
t = 240 seconds
Hence, the direction that she must aim herself through the water to arrive at the dock. and it takes for the swimmer to cross the river will be 73.7° and 240 seconds respectively.
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Two forces that act on very small distances (smaller than you can see ) are
if the speed of a car is increased by 50%, bywhat factor will its minimum braking distance be increased, assuming all else is the same?
When the speed of a car increases by a factor of 50%, the minimum braking distance will also be increased by a factor.
Braking distance will increase by a factor 2.25
Solution
From Newton's equation of motion, we can say that;
v² = u² + 2as
Where initial velocity is zero, we have;
v² = 2as
s = v²/2a
s is the distance and v is the final speed.
50% increase in speed means it has increased by a factor of 1.50
Hence we have
1.50²v² is directly proportional to the 1.50²d
Distance = 1.50²v² = 2.25d
Hence, breaking distance will increase by a factor 3.0625
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How do you un rewrap something?
what is q if 28.6 g of water is heated from 22.0°c to 78.3°c? the specific heat of water is 4.184 j/g·°c.
Answer:
6736 J
Explanation:
Knowing that Q = cmΔT:
Q = 4.184 J/(g·°C) · 28.6g · (78.3 °C - 22.0 °C) = 6736 J.
Pravat exerts a force of 30 N to lift a bag of groceries 0. 5 m. How much work did Pravat do on the bag? Note : Work = Force x Distance 0 J 15 J 30 J 60 J.
Answer:
15 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 30 × 0.5 = 15
We have the final answer as
15 JHope this helps you
The amount of work done by Pravat if he exerts a force of 30 N to lift a bag of groceries 0.5m is 15J.
WORK DONE:The work done by a body can be calculated by multiplying the force exerted by the distance moved. That is;
Work done = force (F) × distance (m)
According to this question, Pravat exerts a force of 30N to lift a bag of groceries 0.5 m. The work done is calculated as follows:
Work done = 30N × 0.5m
Work done = 15J
Therefore, the amount of work done by Pravat if he exerts a force of 30 N to lift a bag of groceries 0.5m is 15J.
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1. A ball rolls off a desk at a speed of 3.0 m/s, lands 0.40 seconds later, and lands 1.2 m away from the desk
b) how high is the desk
Answer:
0.784m
Explanation:
This is a projectile motion problem so we analyze the horizontal and vertical motions separately. Since the question is asking for the height of the desk, it shows we need to analyze the vertical motion.
Define the following:
Variable
Data
Control
Technology
Hypothesis
Physical Science
Experiments
Answer:
Variable- not consistent or having a fixed pattern; liable to change
Data- facts and statistics collected together for reference or analysis
Control- a group or individual used as a standard of comparison for checking the results of a survey or experiment
Technology- the application of scientific knowledge for practical purposes, especially in industry
Hypothesis- a supposition or proposed explanation made on the basis of limited evidence as a starting point for further investigation
Physical Science- the sciences concerned with the study of inanimate natural objects, including physics, chemistry, astronomy, and related subjects
Experiments- a scientific procedure to make a discovery, test a hypothesis, or demonstrate a known fact
Explanation:
the breaks on a 15,680 N car exert a stopping force of 640 N.
what is the potential energy of a 2kg plant that is on a windowsill 1.3 m high?
what is the kinetic energy of a 7.26 kg bowling ball that is rolling at a speed of 2 m/s
an apple as 6 J of energy. the apple sits on a counter 3 m high. what is the mass of the apple/
Answer:
25.48
Explanation:
What are the rest of the blanks?
Use the drop-down menus to complete each statement. Is the process of charging an object without touching it. Is the process of charging a sphere by touching it with a charged rod.
The process of charging an object without touching it is called induction charging.
The process of charging a sphere by touching it with a charged rod is called charging by conduction..
When an uncharged object brings into the contact of the charged object but not touching the object directly, the uncharged object gets charged. This process of charging is called Induction Charging.
When an uncharged object brings in to the contact of the charged object by touching it directly, the uncharged object gets charged, This process of charging is called Conduction Charging.
When a charged rod touches the metal sphere, sphere gets same charged as the rod. The process of charging a sphere by touching it with a charged rod. is called conduction charging.
For more details about the conduction and induction charging, follow the link given below.
https://brainly.com/question/13599143.
Answer:
induction and conduction or 3,2 or c and b
Explanation:
edge 2022
45. What is the wovelength of a 30. Hertz periodic
wave moving ol 60. meters per second?
a. 0.50m
c. m
b 20m
d 1800 m
The wavelength is 2m.
Hence, Option c) 2m is the correct answer
Given that;
Frequency; [tex]f = 30Hz[/tex]
Speed; [tex]v = 60m/s[/tex]
Wavelength; [tex]\lambda =\ ?[/tex]
using the expression for the relations between wavelength, frequency and speed of wave:
[tex]\lambda = \frac{v}{f}[/tex]
Where [tex]\lambda[/tex] is wavelength, f is frequency and v is speed.
We substitute our given values into the equation
[tex]\lambda = \frac{60m/s}{30Hz}\\\\\lambda = \frac{60m/s}{30s^{-1}}\\\\\lambda = 2m[/tex]
The wavelength is 2m.
Hence, Option c) 2m is the correct answer.
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The frequency of the moving wave is 30 Hz and if it is moving at the speed of 60 m/s then the wavelength will be equal to 2 m.
What is Wavelength?The distance between two identical locations (adjacent crests) in successive cycles is known as the wavelength, and it is used to describe waveform signals that are transmitted over wires or into space. Typically, in wireless systems, this length is specified in meters (m), centimeters (cm), or millimeters (mm).
The wavelength is more frequently described in nanometers (nm), which are units of 10⁻⁹ m, or angstroms, which are units of 10⁻¹⁰ m, for infrared (IR), visible light (UV), and gamma radiation.
As per the provided given data in the question,
Frequency, f = 30 Hz
Speed, v = 60 m/s
Then, the wavelength of the moving wave will be,
λ = v/f
= 60/30
λ = 2 meters.
Therefore, the wavelength will be 2 meters.
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What force is responsible for how magma flows and rocks stack up on top of one another?
Question 6 options:
Electroweak and Strong
Nuclear
Electromagnetic
Gravitational
Gravitational force is responsible for how magma flows and rocks stack up on top of one another.
Gravitational force is the force hat attracts all objects to the center of the earth. The force of gravity accounts for the fact that when an object is thrown up, it falls back to the earth.The force that is responsible for how magma flows and rocks stack up on top of one another is the gravitational force.Hence, it is the gravitational force that is responsible for how magma flows and rocks stack up on top of one another.
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a 25 kg cart has 125 kg*m/s of momentum, how fast is the car going
Answer:
5m/s
Explanation:
equation for momentum is mass times velocity
25 x 5 = 125
Please please help
Matter is made up of particles which
are too small to see without the aid of
a microscope. What do scientists call
these particles?
A.bonds
B.mixtures
C.energy
D.atoms
Answer:
D
Explanation:
an airplane flies with a constant speed of 620 miles per hour. how far can it travel in 3 1/2 hours?
Answer:
hi there !
1 hour -------> 620 miles
3 1/2 ---------> ?
the number of miles the airplane travels in 3 1/2 hours
= 3 1/2 × 620 = "2170" miles
A 0.15 kg baseball moving at 20 m/s is stopped by a player in 0.010 s. What is the average force of the ball?
Answer: 300N
Explanation:
Impulse= Mass * Velocity
F.T = M * V
F= MV/T
F= (0.15*20)/ 0.01
F= 300N