hii i need these answers please!! as soon as possible and if you can’t see anything jus let me know and ill tell you what it says

Answer:

it forms another one

Explanation:

our solar system was formed by a nebula so that nebula is supposed to form another one

Explanation:

We need to find the index of refraction of a material for which the wavelength of light is 0.671 times its value in a vacuum.

The wavelength in any medium is given by :

[tex]\lambda_m=\dfrac{\lambda}{n}[/tex]

Where, [tex]\lambda[/tex] is wavelength in vacuum and n is refractive index of the medium.

[tex]n=\dfrac{\lambda}{\lambda_m}\\\\n=\dfrac{\lambda}{0.671\lambda}\\\\=\dfrac{1}{0.671}\\\\=1.49[/tex]

So, the medium can be PMMA (acrylic, plexiglas, lucite, perspex) which have a refractive index of 1.49.

The index of refraction of the material for which the wavelength of light is 0.671 times, the value of it in a vacuum is 1.49.

The index of refraction of a material is the ratio of wavelength of the wave in vacuum to the wavelength of the wave in the given medium.

The index of refraction is inversely proportional to the wavelength. It can be find out using the following formula.

[tex]n=\dfrac{\lambda}{\lambda_m}[/tex]

Here, (λ) is the wavelength in vacuum and (λm) is the wavelength in a medium.

The index of refraction of a material for which the wavelength of light is 0.671 times its value in a vacuum (0.671×λ).

Plug in the values in the above formula,

[tex]n=\dfrac{\lambda}{0.671\times\lambda}\\n=1.49[/tex]

Thus, the index of refraction of the material for which the wavelength of light is 0.671 times, the value of it in a vacuum is 1.49.

Learn more about the index of refraction here;

https://brainly.com/question/10729741

Answer:

I am a math genus and this one is hard 3142 i think you multiple

What is this?

Explanation:

Answer:

The distance between Jupiter and the Sun is 5.2 AU.

The answer would be A: 5.2 Au away from the sun (AU is the unit that is the same length as the distance between Earth and the Sun)

Answer:

T' = o.707T

Explanation:

[tex]T = 1/2\pi \sqrt{k/m} \\\\m'=2m then\\T' = 1/2\pi \sqrt{k/m'}\\ = 1/2\pi \sqrt{k/2m}\\T' = \frac{(1/2\pi \sqrt{k/m}\\)}{1.4} T' = \frac{T}{1.4}\\T' = 0.707T[/tex]

Explanation:

u = 0m/s

v = 30m/s

a = g = 10m/s²

s = H = ?

using the formula,

v² = u² + 2as

30² = 0² + 2(10)(H)

900 = 20H

H = 900/20

H = 45m

Answer:

the answer is

45m - height

Answer:

total sum of all numbers/ number of items in the set

Explanation:

Answer:

what are the choices

Explanation:

Answer:

Landforms are a result of a combination of constructive and destructive forces. Collection and analysis of data indicates that constructive forces include crustal deformation, faulting, volcanic eruption and deposition of sediment, while destructive forces include weathering and erosion.

Explanation:

Answer:

The correct option is  D

Explanation:

From the question we are told that

  The maximum electric field strength is  [tex]E = 1.0 *10^{11} \ V/m[/tex]

   The  area is  [tex]A = 5.0 \ mm^2 = 5.0 *10^{-6} \ m^2[/tex]

Generally the force the laser applies is mathematically represented as

       [tex]F = \epsilon_o * E ^2 * A[/tex]

Here  [tex]\epsilon_o = 8.85*10^{-12} C/(V \cdot m)[/tex]

      [tex]F = 8.85*10^{-12} * (1.0 *10^{11}) ^2 * 5.00*10^{-6 }[/tex]

=>   [tex]F = 4.43 *10^{5} \ N[/tex]

Answer:

61 degrees, I just did the test.

Explanation:

Answer: 61 degrees

Explanation:

I just did the question and got it right

Answer:

74 degrees

Explanation:

***************

Answer:

74 degrees on edge

Explanation:

Answer:

13.28m/s

Explanation:

Given

Distance covered by the ball S = 9m

initial velocity u = 0m/s

Required

velocity at the bottom of the hill (final velocity)

Using the equation of motion

v² = u²+2gS

v² = 0²+2(9.8)(9)

v² = 18(9.8)

v² = 176.4

v = √176.4

v = 13.28m/s

Hence the velocity at the bottom of the hill is 13.28m/s

Answer:

a

 [tex]y_1 = 0.004589 \ m[/tex]

b

 [tex]y_2 =0.009179 \ m[/tex]

Explanation:

From the question we are told that

   The wavelength of the red light is  [tex]\lambda _r = 633 \ nm = 633 *10^{-9} \ m[/tex]

    The width of the slit is  [tex]d = 0.40 mm = 0.40 *10^{-3} \ m[/tex]

    The distance of the screen from the point of diffraction is [tex]D = 2.9 \ m[/tex]

Generally the width of the central bright fringe is mathematically represented as

       [tex]y_1 = \frac{\lambda * D}{d}[/tex]

=>    [tex]y_1 = \frac{633 *10^{-9} * 2.90 }{0.40 *10^{-3}}[/tex]

=>    [tex]y_1 = 0.004589 \ m[/tex]

Generally the width of the first bright fringe on either side of the central one is mathematically represented as

     [tex]y_2 = 2 * y_1[/tex]

=>   [tex]y_2 = 2 * 0.004589[/tex]

=>   [tex]y_2 =0.009179 \ m[/tex]

Answer:

first thing first they really have to concern about this,

and second one is people should leave those hazardous places

Answer:

-Emergency evacuation roadways could be designed.

-An Evacuation plan could be organized.

-Warning Sirens could be designed.

Explanation:

Those 3 are the answer.

Answer:

2 m/s

Explanation:

The total time = 1 hour

The vertical displacement = 1 - 1

Vertical displacement = 0

Horizontal displacement = 4 - 2

Horizontal displacement = 2

Total displacement = sqrt (2^2 - 0^2)

Displacement - 2

Average velocity is displacement/time

= 2x1

=  2 m/s

The average velocity is 2 metres per second.

Answer:

Explanation:

KHAN ACADEMY

The free body diagram of the cheese block is attached with the answer.

A free body diagram consists of a diagrammatic representation of a single body or a subsystem of bodies isolated from its surroundings showing all the forces acting on it.

Given is a block of cheese is pulled on by a string and slides to the right along a rough surface.

The free body diagram of the cheese block is given with the image attached. The force applied for the forward motion of the block is greater in magnitude than the frictional force. The weight of the block is balanced by the normal reaction force. The following mathematical relations can be written -

F - F(f) = ma

and

mg = N

m = N/g

So -

F - F(f) = (N/g)a

Therefore, the free body diagram of the cheese block is attached with the answer.

To solve more questions on Free body diagram, visit the link below-

https://brainly.com/question/18936554

#SPJ2

Answer:

what i and confused

Explanation:

Answer:

nerd

Explanation:

I H4+3 U

Answer:

Answer for this question is 3590792.

56 Joules

We are given:

Mass of the Ball = 7 kg

Velocity of the Ball=  4 m/s

Kinetic Energy of the Ball:

We know that:

Kinetic Energy = 1/2 (Mass * Velocity²)

replacing the values

Kinetic Energy = 1/2(7 * (4)²)

Kinetic Energy = 1/2(7 * 16)

Kinetic Energy = 56 Joules

Answer:

i think its d

Explanation:

i took this quiz and got 100 percent

Answer:

(B)  1.23 x 10⁴ J

Explanation:

Given;

radius of the sphere, r = 7.0 m

diameter of the sphere, d = 2r = 14.0 m

mass of the person sitting on the sphere, m = 90.0 kg

The gravitational potential energy of the person is given by;

P.E = mgh

where;

g is acceleration due to gravity = 9.8 m/s²

h is the height above the ground level = d = 14.0 m

P.E = mgh

P.E = (90)(9.8)(14)

P.E = 12348 J

P.E = 1.2348 x 10⁴ J

Therefore, the gravitational potential energy of the person is 1.2348 x 10⁴ J

Answer:

solid, liquid, gas

Explanation:

The three phases of water are the three states of matter water can be found in, and that is:

solid (as in ice)

liquid (as in water)

gas (as in water vapor)

• initial speed: 48.0 m/s

The cannonball is shot horizontally, so

• initial horizontal speed: 48.0 m/s

• initial vertical speed: 0

Answer:

Y = 78.13 x 10⁹ Pa = 78.13 GPa

Explanation:

First we will find the centripetal force acting on the wire as follows:

F = mv²/r

where,

F = Force = ?

m = mass of rock = 0.34 kg

v = speed = 19 m/s

r = length of wire

Therefore,

F = (0.34)(19)²/r

F = 122.74/r  

now, we find cross-sectional area of wire:

A = πd²/4

where,

A = Area = ?

d = diameter of wire = 1 mm = 0.001 m

Therefore,

A = π(0.001)²/4

A = 7.85 x 10⁻⁷ m²

Now, we calculate the stress on wire:

Stress = F/A

Stress = (122.74/r)/(7.85 x 10⁻⁷)

Stress = 1.56 x 10⁸/r

Now, we calculate strain:

Strain = Δr/r

where,

Δr = stretch in length = 2 mm = 0.002 m

Therefore,

Strain = 0.002/r

now, for Young's modulus (Y):

Y = Stress/Strain

Y = (1.56 x 10⁸/r)/(0.002/r)

Y = 78.13 x 10⁹ Pa = 78.13 GPa

There are 4 forces acting on the block:

• its weight (magnitude w = m g = 98 N, where m = 10 kg and g = 9.80 m/s²), pointed downward

• the normal force (mag. n), pointed upward

• friction (mag. f = 15 N), pointing opposite the direction of motion

• the pulling force (mag. p = 75 N), pointing at a 20° angle with the positive horizontal direction

Let the direction in which the block is being pulled be the positive horizontal direction, and upward the positive vertical direction. Split up each force into their horizontal and vertical components, then apply Newton's second law. We have a net horizontal force of

∑ F = p cos(20°) - f = m a

where a is the acceleration of the block. The net vertical force is 0, since the block gets dragged along the surface and doesn't move up or down (presumably).

Solve for a :

(75 N) cos(20°) - 15 N = (10 kg) a

a ≈ 5.4 m/s²

Answer:

Potential energy

Explanation:

When the string is released, the potential energy is converted to kinetic energy in the movement of the arrow. The string pushes the arrow out and is the driving force behind the motion.