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Solve the equation -3x^2+2x+4= -x-3 by writing a linear-quadratic system and solving using the intersection feature of a graphing calculator. Round to the nearest hundredth
A. x= -2.44 and x=3.12
B. x=-1.63 and x=4.44
C. x=-1.11 and x=2.11
D. x=-2.61 and x=0.42

Answer: i did c when i had the same question but it was just a guess

Step-by-step explanation:

The solution of an equation is x= -1.11 and x = 2.11.

A polynomial equation of the second degree is quadratic, which means that at least one of its terms must be squared. Quadratic equations are another name for it. The quadratic equation generally looks like this:

ax² + bx + c = 0, where x is a numerical coefficient and a, b, and c are unknown variables.

Given equation -3x² + 2x + 4 = -x - 3

simplify the equation we get

3x² - 2x - 4 -x -3 = 0

3x² - 3x - 7 = 0

The equation is solved by the Quadratic formula

x =  (-b ± [tex]\sqrt{b^{2} - 4ac }[/tex])/2a

a = 3, b = -3, c = -7

x = [-(-3) ± [tex]\sqrt{(-3)^{2} - 4(3)(-7)}[/tex]]/2(3)

x = (3 ± 9.643)/6

taking positive sign

x = 12.643/6 = 2.1072 = 2.11

taking negative sign

x = -6.643/6 = -1.1072 = -1.11

Hence the values of x are -1.11 and 2.11

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