find the distance and displacement for the following figures :

Answer:

90π in²

Step-by-step explanation:

  r = 3 in

  h = 10 in

     [tex]\sf \boxed{\text{\bf Surface area of cylinder =$\pi r^2h$}}[/tex]

                                                   [tex]= \pi 3*3*10\\\\= 90 \pi \ in^2[/tex]

In this question it is given that the radius of a cylinder is 3 inches. The height of the cylinder is 10 inches. We are asked to calculate the surface area of the cylinder in terms of π .

Radius = 3 inches

Height = 10 inches

We know,

[tex] \star \: \small \boxed{\rm{ Surface \: area \: of \: a \: cylinder = πr²h}}[/tex]

Substituting the values we get

[tex] \small\sf{ Surface \: area \: of \: a \: cylinder = π × 3² × 10}[/tex]

[tex] \small\rm{ Surface \: area \: of \: a \: cylinder = π × 3 \times 3 × 10}[/tex]

[tex] \small\rm Surface \: area \: of \: a \: cylinder = π × 90[/tex]

[tex] \small\sf{ Surface \: area \: of \: a \: cylinder = \bf{90 π \: inches²}}[/tex]

Answer + Step By Step Explanation:

There is no single value for y as the input could differ (x)

y = -3/4x

if x = 0, y = -3/4(0) than y = 0

if x = 1, y = -3/4(1) than y = -3/4

...

if x = 5, y = -3/4(5) than y = -15/4

Answer:

[tex]slo pe \: = \frac{2}{7} [/tex]

Step-by-step explanation:

[tex]y1 = 3\\ x1 = - 8 \\ y2 = 7 \\ x2 = 6[/tex]

[tex]slope = \frac{y2 - y1}{x2 - x1} [/tex]

[tex]sope = \frac{7 - 3}{6 - ( - 8)} [/tex]

[tex]slope = \frac{4}{6 + 8} [/tex]

[tex]slope = \frac{4}{14} [/tex]

[tex] = \frac{2}{7} [/tex]

Answer:

[tex]\textsf{slope}=\dfrac{2}{7}[/tex]

Step-by-step explanation:

[tex]\textsf{let}\:(x_1,y_1)=(-8,3)[/tex]

[tex]\textsf{let}\:(x_2,y_2)=(6,7)[/tex]

Using the slope formula:

[tex]\textsf{slope}=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{7-3}{6-(-8)}=\dfrac{4}{14}=\dfrac{2}{7}[/tex]

Therefore, the slope between the two points (-8, 3) and (6, 7) is 2/7

Answer:

122.5 squared

Step-by-step explanation:

bahh have have aheve shaved she sbdnabd sjsbd akdbd

The box-and-whisker plot that illustrates the given data set is shown in the image below (see attachment).

A box-and-whisker plot consists of the following values of a data set: min, max, lower quartile, median, and upper quartile.

Here, Given the data set,

30, 22, 22, 27, 28, 23, 24, 25, 26, 23

the five-number summary for the box-and-whisker plot would be:

Minimum: 22

Quartile Q1: 22.75

Median: 24.5

Quartile Q3: 27.25

Maximum: 30

Thus, the box-and-whisker plot that illustrates the given data set is shown in the image below (see attachment).

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Answer:

See below ~

Step-by-step explanation:

Q1

⇒ Remember that sides opposing larger angles are greater in size

⇒ 75° > 54° > 51°

⇒ AC > BC > AB

Q2

⇒ The exterior angles lie outside the triangle

⇒ ∠1 + ∠2 = ∠6 (Exterior Angle Property)

⇒ ∠1 + ∠2 = ∠P (Exterior Angle Property)

⇒ ∠3 = ∠5 (Vertical Angles)

Answer:

78

Step-by-step explanation:

= 12 x^2 - 30         put in ' - 3 ' for  'x'

= 12 ( -3 )^2 - 30

 = 12 (9) - 30 = 78

Answer:

78

Step-by-step explanation:

Expression:

Evaluate x = 3 according to the question:

[tex]6 \{2 (- 3) {}^{2} - 5) \}[/tex]

Solve this problem, applying PEMDAS.

Hence,the answer to the given expression is 78.

-Regards,Hannah :)

The polynomial function represented by the data is equal to D. f(x) = −x² + 10.

In order to determine the polynomial function represented by the data, we would substitute the value of x (-3) into the given set of functions as follows:

For option A, we have:

f(x) = 6x + 15

f(-3) = 6(-3) + 15

f(-5) = -18 + 15

f(-5) = -3 (False).

For option B, we have:

f(x) = -6x - 45

f(x) = -6(-3) - 45

f(x) = 18 - 45

f(x) = -27 (False).

For option C, we have:

f(x) = x² - 40

f(x) = -3² - 40

f(x) = 9 - 40

f(x) = -31 (False).

For option D, we have:

f(x) = −x² + 10

f(x) = −(-2)² + 10

f(x) = −9 + 10

f(x) = 1 (True).

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Complete Question:

A polynomial function is represented by the data in the table.

x = -5, -4, -3, -2, -1

f(x) = -15, -6, 1, 6, 9

Choose the function represented by the data.

A. f(x) = 6x + 15

B. f(x) = −6x − 45

C. f(x) = x² − 40

D. f(x) = −x² + 10

Answer:

Exact Area =

16pi - 32 square meters

Decimal Approx:

A = 18.3 sq m

Step-by-step explanation:

In degrees, it's 360° all the way around a circle. The 270° in the image is to show you that the small piece (the triangle and yellow segment) are in a 90° part of the circle. That is 1/4 of the circle, this helps with area two ways. We'll find 1/4 of the circle area and also, that makes the triangle base 8 and height 8. This helps us find triangle area. See image.

Answer:

πr²h= 1696

⇒r²=1696/3.14×15

⇒r²=36.009

⇒r=√36.009

∴r=6.0008=z

If the  -8 is under the square root, then...

[tex]\displaystyle L = \lim_{x\to -3} \sqrt{x^2-8}\\\\L = \sqrt{(-3)^2-8}\\\\L = \sqrt{9-8}\\\\L = \sqrt{1}\\\\L = 1\\\\[/tex]

OR

If the -8 is not under the square root, then...

[tex]\displaystyle L = \lim_{x\to -3} \sqrt{x^2}-8\\\\L = \sqrt{(-3)^2}-8\\\\L = \sqrt{9}-8\\\\L = 3-8\\\\L = -5[/tex]

Either way, we replace x with -3 and simplify.

For more information, refer to the direct substitution rule for limits.

The limit of   [tex]\lim_{x \to \-(-3)} \sqrt{x^{2} -8}[/tex] is one.

A limit is the value that a function approaches as the input approaches some value. Limits are essential to calculus and mathematical analysis, and are used to define continuity.

The given limit is [tex]\lim_{x \to \-(-3)} \sqrt{x^{2} -8}[/tex]

Now replace x with -3 as limit value is -3

√(-3)²-8

Square root over minus three square minus eight

The three square is nine

√9-8

When eight is subtracted from nine we get one.

√1

The square root of one is always one

[tex]\lim_{x \to \-(-3)} \sqrt{x^{2} -8}[/tex]=1

Hence, [tex]\lim_{x \to \-(-3)} \sqrt{x^{2} -8}[/tex] is one.

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Answer:

13.2 units

Step-by-step explanation:

12 is to 7.2 as   (12+10) is to x

12/7.2   =  (12+10)/x

x = 22 * 7.2/12 = 13.2 units

Answer:

x = -75

Step-by-step explanation:

[tex]\frac{3}{5}[/tex] x = - 45 ( multiply both sides by 5 to clear the fraction )

3x = - 225 ( divide both sides by 3 )

x = - 75

Answer:

A

Step-by-step explanation:

The correct first step in solving the inequality –4(3 – 5x)≥ –6x + 9 is,

⇒ - 12 + 20x ≥ - 6x + 9

A relation by which we can compare two or more mathematical expression is called an inequality.

We have to given that;

The inequality is,

⇒ - 4(3 - 5x) ≥ - 6x + 9

Now, We can simplify as;

⇒ - 4(3 - 5x) ≥ - 6x + 9

⇒ - 12 + 20x ≥ - 6x + 9

⇒ 20x + 6x ≥ 12 + 9

⇒ 26x ≥ 21

⇒ x ≥ 21/26

Thus, The correct first step in solving the inequality –4(3 – 5x)≥ –6x + 9 is,

⇒ - 12 + 20x ≥ - 6x + 9

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The graph state that the initial point is (6.9), and the terminal point is (2,1). The vertex of the parabola is  (3,0). Arrows along the parabola to indicate motion right to left.

Let take x = 4 - t    =t  =  4 - x       as equation  (1)

And y = (t - 1)^2       as equation (2)

Then input equation  (1)  into equation   (2)

y  = ( 4 - x - 1)^2

y = ( 3 - x)^2

y = ( x - 3)^2

So therefore, y = a ( x -3)^2  +  0

It can be written as y  = a(x - h)^2  + k      

Where, a = 1    

The vertex  known to be (h, k)  will be = (3,0).

The starting point is  if t = -2

Therefore, x  = (4 - -2)   = 6      

  y =  (-2 - 1)^2  = (-3)^2    = 9  

So x, y =  (6,9).

Note that if t  = 2

Then x = (4 - 2) =  2      

  y  =  (2 - 1)^2   = 1^2  

=  1    

Therefore, x, y =(2, 1).

Therefore, The graph of the parametric equations  state that the initial point is (6.9), and the terminal point is (2,1). The vertex of the parabola is  (3,0). Arrows along the parabola to indicate motion right to left.

See full question below

What does the graph of the parametric equations x(t)=4−t and y(t)=(t−1)^2, where t is on the interval [−2,2], look like?

The parametric equations graph as a portion of a parabola. The initial point is _____, and the terminal point is _____. The vertex of the parabola is ____. Arrows are drawn along the parabola to indicate motion ____.

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The area of the circle grows by a factor of 9, and the actual area is 360

The given parameters are:

Old area = 40

Scale factor = 3

When the circle is dilated, the new area becomes

New area = Old * (Scale factor)^2

Substitute 3 for scale factor

New area = Old * 3^2

Evaluate the exponent

New area = Old * 9

This means that the area of the circle grows by a factor of 9, and the actual area is:

New area = 40 * 9 = 360

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Answer:

25 degrees

Step-by-step explanation:

arc divided by 2 = angle

50/2=25

The area of this hub cap is about  510.44625 cm².

The area of circle is pi times the square of the radius.

Area of circle =π r²

Circumference (C) = 2π r

80.07 = 2 (3.14) r

76.87/ (2x 3.14) =r

r = 12.75 cm

now, Area be

=π r²

= 3.14*12.5*12.75

=510.44625 cm²

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Answer:

0.1

Step-by-step explanation:

You are adding on 0.1 for each line and since G is the first line after 0, it is 0.1.

The functions have complex roots from the image are

Functions (b) and (d). This is further explained below.

Generally, Function is simply defined as a connection between two or more variables that may be expressed mathematically.

In conclusion,  Functions with graphs that never touch or cross the x-axis are said to have complicated roots, not real ones.

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Answer:

≈0.71 or [tex]\frac{\sqrt{2}}{2}[/tex].

sin(45°) =  approximately 0.71. The value is also equal to [tex]\frac{\sqrt{2}}{2}[/tex].

Hope this helps!!!

Please mark me as brainliest!!!

Answer:

11,000

Step-by-step explanation:

10% of 10,000 is 1,000 so 5% is 500 and add 2 of 5% you get 1,000 and add it to the old price thus you get 11,000.

The percentage of the original block cookie that is packaged and ready to be distributed to stores is: 12.6%.

To calculate the percentage of the original 100lb cookie that is packaged and ready to be distributed, we must perform the following operations:

We must calculate how much each package of 5 cookies weighs, for this we multiply the weight of each cookie (3 ounces) 0.18 pounds by the number of cookies in each package (5).

Next, we need to calculate how much the box containing 14 packages of cookies weighs by multiplying the weight of each package (0.9 lb) by the number of packages in each box (14).

Lastly, we need to calculate how much percentage the weight of each box is equal to the weight of the original 100 lb cookie that Latonya made. For that we divide 100 lbs. by 100 and multiply the result by the final weight of the box (12.6lbs).

Based on the above, each box contains 12.6% of the first 100-lb cookie Latonya made.

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Using it's concept, it is found that the probability of being a girl and choosing lemonade is given by:

b. 0.2.

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, out of 130 people, 26 are girls who choose lemonade, hence the probability is given by:

p = 26/130 = 0.2, which means that option b is correct.

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Answer:

[tex]5.6 \times 10^{-8}~ m[/tex]

Step-by-step explanation:

[tex]0.000000056\\\\=\dfrac{56}{1000000000}\\\\\\=\dfrac{56}{10^9}\\\\\\=56 \times 10^{-9}\\\\\\=56 \times 10^{-1} \times 10^{-8}\\\\\\=5.6 \times 10^{-8}~[/tex]

Answer:  [tex]\frac{n!}{(n-r)!}[/tex]

The exclamation marks indicate factorial.

For instance, 4! = 4*3*2*1 = 24. You start with the given number and multiply your way down to 1.

For more information, check out the nPr permutation formula.

Answer:

13.) 314.2 in²

15.) 181.5 ft²

Step-by-step explanation:

The area of a circle is found using the equation:

A = πr²

In this equation, "π" represents the number pi (3.14....) and "r" represents the radius (half the diameter).

For 13.), you have been given the radius. Thus, you can substitute it into the equation and solve for "A".

A = πr²

A = π(10)²

A = π x (100)

A = 314.2 in²

For 15.), you have been given the diameter. To find the radius, you need to divide this value by 2. Once you find the radius, you can plug it into the equation and simplify like above.

diameter = 15.2 ft
radius = 7.6 ft

A = πr²

A = π(7.6)²

A = π x (57.76)

A = 181.5 ft²

Answer: decrease the resources invested

Step-by-step explanation:

Answer:

[tex] {x}^{ - 2} = \frac{1}{ {x}^{2} } \: \: –> {7}^{ - 2} = \frac{1}{ {7}^{2} } = \frac{ 1}{49} \\ \\ {x}^{ - 1} = \frac{1}{ {x}^{1} } \: –> {7}^{ - 1} = \frac{1}{ {7}^{1} } = \frac{1}{7} \\ \\ {x}^{0} –> {7}^{0} = 1 \\ \\ {x}^{1} –> {7}^{1} = 7 \\ \\ {x}^{2} –> {7}^{2} = 49[/tex]