Find the area of the figure below, formed from a triangle and a parallelogram. A figure is formed from a triangle and a parallelogram. The base of the triangle is 8 millimeters and the height is 2 millimeters. The bottom and top of the parallelogram are 6 millimeters and the height is 4 millimeters.

Answer:

Y=3/4x-2

Step-by-step explanation:

Atleast I think so

Answer:

y=3/4x-2

Step-by-step explanation:

y=mx+b

Y= 3/4x-2 because you rise 3 run 4 and the line crosses the y-axis at the point (0, -2)

C that's because the angles are vertically opposite

Answer:

y=-1/3x+5

Step-by-step explanation:

Use rise/run

The bracelet price on which company get its maximum profit  is 8 thousand dollar

A rule or law that define an relationship between one variable to another variable

The company's annual profit (in thousands of dollars) as a function of the price of a bracelet (in dollars) is modeled by: P(x)=-2x^2+16x-24

To find maximum profit , we need to find out the vertex

x coordinate of vertex formula is -b/2a

P(x)= -2x^2 +16 x-24

a=-2  and b = 16

x= -b/2a= -16/2 x -2 = 4

Now we plug in 4 for x  and find out P(4)

P (x) = -2 x (4)^2 + 16 x 4 - 24 = 8

So the maximum profit the company can earn is 8 thousand dollars when price = $4

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Answer:

i cant really see the words

Step-by-step explanation:

Answer:

92F

Step-by-step explanation:

the record high January temperature in Austin, Texas, is 90F. the record low January temperature is -2F. Find the difference between the high and low temperatures.

= 90 - (-2)

= 90 + 2

= 92F

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \: 8i[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad\displaystyle \tt \rightarrow \: 2 {x}^{2} = - 128[/tex]

[tex]\qquad\displaystyle \tt \rightarrow \: {x}^{2} = - \frac{ 128}{2} [/tex]

[tex]\qquad\displaystyle \tt \rightarrow \: {x}^{2} = - 64[/tex]

[tex]\qquad\displaystyle \tt \rightarrow \: x = \sqrt{ - 64} [/tex]

[tex]\qquad\displaystyle \tt \rightarrow \: x = \sqrt{( - 1) \sdot(64)} [/tex]

[tex]\qquad\displaystyle \tt \rightarrow \: x = \sqrt{ 64} \sdot \sqrt{ - 1} [/tex]

[tex]\qquad\displaystyle \tt \rightarrow \: x = 8 \sdot i[/tex]

[tex]\qquad\displaystyle \tt \rightarrow \: x = 8i[/tex]

[ i = iota, and i² = -1 ; (complex number) ]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

[tex]x=8i[/tex]

Step-by-step explanation:

Given equation:

[tex]2x^2=-128[/tex]

Divide both sides of the equation by 2:

[tex]\implies \dfrac{2x^2}{2}=\dfrac{-128}{2}[/tex]

[tex]\implies x^2=-64[/tex]

Square root both sides:

[tex]\implies \sqrt{x^2}=\sqrt{-64}[/tex]

[tex]\implies x^2=\sqrt{-64}[/tex]

Rewrite -64 as 8² · -1:

[tex]\implies x=\sqrt{8^2 \cdot-1}[/tex]

[tex]\textsf{Apply radical rule} \quad \sqrt{ab}=\sqrt{a}\sqrt{b}:[/tex]

[tex]\implies x=\sqrt{8^2}\sqrt{-1}[/tex]

[tex]\textsf{Apply radical rule} \quad \sqrt{a^2}=a, \quad a \geq 0:[/tex]

[tex]\implies x=8\sqrt{-1}[/tex]

[tex]\textsf{Since $\sqrt{-1}=i$}[/tex]

[tex]\implies x=8i[/tex]

Imaginary numbers

Since there is no real number that squares to produce -1, the number [tex]\sqrt{-1}[/tex] is called an imaginary number, and is represented using the letter i.

An imaginary number is written in the form [tex]bi[/tex], where [tex]b \in \mathbb{R}[/tex].

Answer:[tex]75m^{2}[/tex]

Step-by-step explanation: Just have to square root 5625m2 to get each side length

commutative property is an example of the blank property.

What in mathematics is a commutative property?

What is a commutative property example?

2(x+3) = 2x+6

Commutative Property used in this function.

4x-3

put x=2

4(2)-3 =  Commutative Property used in this function.

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According to the given problem,

(i) It is given that,

The cost price of 1000 packets of peanuts = Rs. 50

We need to find the cost price of 1 packet of peanut = [tex]\frac{50}{1000}[/tex] = Rs. 0.05

(ii) Selling price at which Sipho continues to sell 1 packet = Rs. 1

Then Selling price of 1000 packets = 1000 x 1 = Rs. 1000

Then Profit made by sipho = Selling Price - Cost Price

= 1000 - 50

= Rs.950

Profit percentage gained by Sipho = [tex]\frac{Profit}{Cost Price}[/tex] x 1000

= [tex]\frac{950}{50}[/tex] x 1000

= 1900 %

(iii) The profit earned by sipho remains same, we nee to find the cost price at which Sipho should sell 100gm of her peanuts is Rs. 1

(iv) I would advice Sipho to sell peanuts at a selling price more than the cost price in order to gain profit

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f(x) is maximum at x=3 and the maximum value of f(x) = 5.

The highest and smallest values of a function, respectively, can either be found inside a specific range or across the entire domain. They are sometimes referred to collectively as the function's extrema. The plural forms of the maximum and minimum functions are maxima and minima, respectively.

The given quadratic function is [tex]f(x) = -2 (x-3)^{2} +5[/tex]

Comparing it with [tex]f(x) = a (x-h)^{2} +k[/tex]

Here, a= -2, h =3 and k = 5.

Since a is negative, so parabola is open downward.

Therefore, the quadratic function has a maximum value.

Here, the vertex is (h,k) =(3,5)

Therefore, f(x) is maximum at x=3 and the maximum value of f(x) = 5.

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Answer:

Step-by-step explanation:

Jan 15, 2020 — this line also pass through 0,8 and 2,2. slope is -3. the equation is y-2= -3(x-2). heart outlined. Thanks 10.

2 answers

·

10 votes:

Answer:this line also pass through 0,8 and 2,2. slope is -3. the equation is y-2= -3(x-2)

Missing: OY ‎| Must include: OY

Answer:

23

Step-by-step explanation:

3-(-20)

The allegation that the proportion has increased from that of earlier studies is not supported by enough data.

Hypothesis test: A statistical hypothesis test is a method of statistical inference used to decide whether the data at hand sufficiently support a particular hypothesis. Hypothesis testing allows us to make probabilistic statements about population parameters

Let p represent the population percentage.

Then, Null hypothesis  : H₀:p=0.79

Alternative hypothesis : H₀:p>0.79

The hypothesis test is a right-tailed test because the alternative hypothesis is right-tailed.

Out of 200 high school seniors in this city, 162 intend to enroll in college, according to a random sampling.

Because n = 200 > 30 we must employ the z-test (otherwise we use t-test.)

p`=162/200=0.81

Population percentage test statistic:

[tex]z=(p`-p)/[/tex][tex]\sqrt{p`(1-p)/n[/tex]

[tex]z=(0.81-0.79)/\sqrt{0.81(1-0.81)/200}[/tex] =0.720984093915≈0.72

Consequently, the sample test statistic's z-value is 0.72.

Right-tailed test P-value:

[tex]p(z > 0.72)=1-p(\leq 0.72)[/tex]

≈[tex]1-0.7642375[/tex]

≈[tex]0.2357625[/tex]

≈[tex]0.2358[/tex]

We are unable to reject the null hypothesis since the p-value is higher than the threshold for significance (0.05).

Therefore, we draw the conclusion that the allegation that the proportion has increased from that of earlier studies is not supported by enough data.

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The value of x is 4

The value of m ∠VUR = 126°

From the image shown, we have that;

Note that all the sides of a equilateral triangle are equal.

Then, we have;

Now, equate the side lengths of the inscribed triangle, we have;

3x + 8 = 6x - 4

collect like terms

3x - 6x = -4 - 8

subtract the like terms

-3x = -12

Make 'x' the subject of formula

x = -12/-3

Find the quotient

x = 4

Note that m ∠VRS and m ∠VUR are on a straight line, we have;

m ∠VRS +  m ∠VUR = 180

substitute the values

54° +  m ∠VUR = 180

m ∠VUR = 180 - 54

m ∠VUR = 126°

Hence, the values are 4 and 126°

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The solution to the expression | a − 5 | − 1 is 2

Expressions are mathematical statements that are represented by variables, coefficients and operators

The expression is given as

| a − 5 | − 1

Also, we have the values to be

a = 2 , b = − 3 , c = − 4 , h = 6 , y = 4 , and z = − 1

Substitute these values in the given equation

So, we have the following equation

| a − 5 | − 1 = | 2 − 5 | − 1

Evaluate the difference

So, we have the following equation

| a − 5 | − 1 = | −3 | − 1

This gives

| a − 5 | − 1 = 3 − 1

Evaluate the difference

| a − 5 | − 1 = 2

Hence, the value is 2

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If Amy, Ravi, and Bob have a total of $127 in their wallets. Bob has 4 times what Ravi has. Ravi has $7 less than Amy. The amount they have  have in their wallets is : Army has $22.33, Ravi $89.33, Henry $15.33.

Let Army represent x dollars

Let Ravi represent   4x

Let Bob represent  x - 7

Hence,

x + x - 7 + 4x = 127

Simplify by combining like terms

6x - 7 = 127

Add 7 to both sides of the equation leaving 6x

6x = 127+7

6x = 134

x =134/6

x = 22.33

x = Army has $22.33

Ravi

4x  where x = 22.33

4(22.33) = 89.33

Bob

x - 7 where x = 22.33

22.33 -7 = 15.33

Prove :

Ravi + Bob + Henry = 127

= 22.33 +89.33 + 15.33 = 126.99 ≅127 (Approximately)

Therefore the have $22.23, $89.33 and 15.33 respectively.

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2+2 a very complicated math question 2+2 = 6 because there's two 2's so that gives us an extra 2 so the actual question is "what is 2 + 2 + 2"

so the answer to your question is 6

The missing lengths of the sides of the congruent triangles described are:

AC = 25 units.

PQ = 3 units.

The corresponding side lengths of any two or more triangles that are congruent to each other are always equal in measure. That is, the three sides of one triangle have lengths that are equal to the corresponding three sides of the other triangle, if both triangles are congruent triangles.

We are told that triangles ABC and LMN are congruent to each other, therefore:

AB = LM = 41 units [corresponding sides]

AC = LN = 25 units [corresponding sides]

BC = MN = 38 units [corresponding sides].

Therefore, the length of AC is 25 units.

Also, it is assumed that triangles FGH and PQR are congruent triangles, therefore:

FG = PQ = 3 units [corresponding sides]

GH = QR = 4.5 units [corresponding sides]

Therefore, the length of PQ is 3 units.

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Answer:

[tex] \frac{54}{n {}^{11} } [/tex]

Step-by-step explanation:

[tex](3n {}^{ - 3} ) \times (3 {n}^{ - 3} )[/tex]

[tex]6 {n}^{ - 5} \times 9n {}^{ - 6} [/tex]

[tex]54 {n}^{ - 11} [/tex]

[tex] \frac{54}{n {}^{11} } [/tex]

Helena came to the right conclusion because the transition of quadrilaterals is accurately depicted.

Given,

Two quadrilaterals = QRST and XYZW

Helena came to the right conclusion because the transition of quadrilaterals is accurately depicted.

How should the facts be explained?

According to the information provided, Helena was interested to know whether the quadrilaterals were congruent.

The quadrilaterals in this instance cannot be mapped into one another via a series of stiff transformations, hence they are not congruent.

As a result, no mistakes are made.

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Answer:

3(h + 6)

Step-by-step explanation:

Since we are starting with

h•3 + 6•3, try to see that there are two terms here h•3 and 6•3. In both of these terms is the factor 3. We can factor out the 3. This leaves behind (h + 6).

h•3 + 6•3

= 3(h + 6)

Its like "un-distributive" property. (this is not a technical term)

Volume of boxes as per condition given:

a. Volume of fish food cube=(1/64) ft³

b. Volume of big box=(1/32)ft³

c. Volume of shipping box=(585/16) ft³

As given,

Dimensions of fish food cubes:

Length=1/4 ft

Width=1/4 ft

Height=1/4ft

a. Volume of fishing food cube=Length ×width ×height

                                                     =(1/4)×(1/4)×(1/4)

                                                     =(1/64)ft³

b. Volume of big box

=(Number of boxes) ×(volume of fishing food cubes)

=2×(1/64)

=(1/32)ft³

c. Dimensions of shipping box

Length=3ft

Width=3 3/4 ft

         =15/4 ft

height=3 1/4 ft

          =13/4 ft

Volume of shipping box=3 × (15/4) ×(13/4)

                                              =(585/16) ft³

Therefore, volume of boxes as per condition given:

a. Volume of fish food cube=(1/64) ft³

b. Volume of big box=(1/32)ft³

c. Volume of shipping box=(585/16) ft³

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Answer:

y<4

Steps:

18 + 6y < 42

6y < 42 - 18

y < 24/6

y < 4

Answer:

y<4

Step-by-step explanation:

18+6y<42

Subtract 18 from both sides.

6y<42−18

Subtract 18 from 42 to get 24.

6y<24

Divide both sides by 6. Since 6 is positive, the inequality direction remains the same.

[tex]y < \frac{24}{6} [/tex]

Divide 24 by 6 to get 4.

y<4

The graph on the right to locate points D, E, and G is, 5.D(0, 3), 6.  E(0, 2),  7. G(0, -3).

What is graph?
In mathematics, a graph is a visual representation or diagram that shows facts or values in an ordered way.

Here, for instance, we can plot a graph showing the type and quantity of school supplies used by pupils in a class based on the data provided below.

Rectangle: Rectangles have parallel opposite sides; therefore, D must be positioned such that CD is parallel to AB and AD is parallel to BC. This necessitates that point D be.
D(0, 3)

Trapezoid: A trapezoid has one set of parallel opposed sides. As a result, we must select point E such that either AE or CD are parallel to AB.
We have picked point E in the accompanying picture so that AE and BC are parallel.
E(0, 2)

Keep in mind that point E might be somewhere left of point C on line y=3 or above point A on line x=0. Point D and point E cannot be in the same place.
E(0, p) or E(q, 3) where p > 0, q < 8, and p≠3, q≠0

Parallelogram: The middle of each parallelogram is where its diagonals connect. As a result, the midway of AB and CG must coincide. We need to have... in order for that to occur.
A + B = C + G
G = A + B - C = (0, 0) +(8, 0) -(8, 3) = (0+8-8, 0+0-3) = (0, -3) (0, -3)
Point G is located where...
G(0, -3)

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7.031 is greater than 7.03.

The given value is having a 2-digit decimal place.

The options which are provided are:

1)7.031

2)7.030

3)7.003

4)7.0

Comparing the first decimal placeholder of each option with the question, all options have the same digit which is zero.

Comparing the second decimal placeholder of each option with the question, only option 1)7.031 and option 2)7.030 is having .03 the rest of the options, option 3)7.0003 and 4)7.0 have .00 has their second digit hence both option 7.0003 and 7.0 are smaller than 7.03.

Out of the remaining options, when options 1)7.03 and 2)7.031 are compared it can be seen that 7.031 is greater because the third decimal placeholder of 7.031 is 1 and 7.03 is 0 hence 7.031 is greater than 7.03.

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