Explain the effect of changing the temperature on pressure in terms of velocity and force of particles

Answer:

The correct option is;

75 N

Explanation:

The given parameters are;

The angle of inclination of the ramp, θ = 42°

The gravitational force of the box = m × g = 112.1 N

Let [tex]F_f[/tex] represent the force of static friction acting on the box

Given that the box is at rest, we have

The component of the gravitational force acting along the inclined plane = The force of static friction acting on the box, [tex]F_f[/tex]

We have that the component of the gravitational force acting along the inclined plane = m × g × sin (θ) = [tex]F_f[/tex]

[tex]F_f[/tex] = m × g × sin (θ)

Substituting the values, gives;

[tex]F_f[/tex] = 112.1 × sin (42°) ≈ 75.0095409728

∴ The force of static friction acting on the box = [tex]F_f[/tex] ≈ 75 N

Answer:

C: 75N

Explanation:

Answer: green car and red car

Explanation:

Answer:

it is white car for the first question and for the second it goes green slowest and white fastest red is in the middle

Answer:

a) El trabajo realizado por esta fuerza mientras el bloque se mueve desde la posición x = + 10 m hasta la posición x = + 20 m es 900 joules.

b) La rapidez del bloque en la posición x = + 20 metros es aproximadamente 5.701 metros por segundo.

Explanation:

a) El trabajo expermentado por el bloque ([tex]W[/tex]), medido en joules, es definida por la siguiente ecuación integral:

[tex]W = \int\limits^{x_{max}}_ {x_{min}} F(x) \, dx[/tex] (1)

Donde:

[tex]x_{min}[/tex], [tex]x_{max}[/tex] - Posiciones mínima y máxima del bloque, medidos en metros.

[tex]F(x)[/tex] - Fuerza horizontal aplicada al bloque, medida en newtons.

Si conocemos que [tex]F(x) = 6\cdot x[/tex], [tex]x_{min} = 10\,m[/tex] y [tex]x_{max} = 20\,m[/tex], entonces el trabajo realizado por esta fuerza es:

[tex]W = \int\limits^{20\,m}_{10\,m} {6\cdot x} \, dx[/tex] (2)

[tex]W = 6\int\limits^{20\,m}_{10\,m} x\, dx[/tex]

[tex]W = 3\cdot x^{2}\left|\limits_{10\,m}^{20\,m}[/tex]

[tex]W = 3\cdot [(20\,m)^{2}-(10\,m)^{2}][/tex]

[tex]W = 900\,J[/tex]

El trabajo realizado por esta fuerza mientras el bloque se mueve desde la posición x = + 10 m hasta la posición x = + 20 m es 900 joules.

b) La rapidez final del bloque se determina mediante de Teorema del Trabajo y la Energía, es decir:

[tex]W = K_{f}-K_{o}[/tex] (3)

Donde son [tex]K_{o}[/tex], [tex]K_{f}[/tex] las energías cinéticas traslacionales inicial y final, medidos en joules.

Al aplicar la definición de energía cinética traslacional, expandimos y simplificamos la ecuación como sigue:

[tex]W = \frac{1}{2}\cdot m \cdot (v_{f}^{2}-v_{o}^{2})[/tex] (4)

Donde:

[tex]m[/tex] - Masa del bloque, medido en kilogramos.

[tex]v_{o}[/tex], [tex]v_{f}[/tex] - Rapideces inicial y final del bloque, medidos en metros por segundo.

[tex]\frac{2\cdot W}{m} = v_{f}^{2}-v_{o}^{2}[/tex]

[tex]v_{f} = \sqrt{\frac{2\cdot W}{m}+v_{o}^{2}}[/tex]

Si conocemos que [tex]W = 900\,J[/tex], [tex]m = 20\,kg[/tex] y [tex]v_{o} = \sqrt{10}\,\frac{m}{s}[/tex], entonces la rapidez final del bloque es:

[tex]v_{f} = \sqrt{\frac{900\,J}{2\cdot (20\,kg)}+10\,\frac{m^{2}}{s^{2}} }[/tex]

[tex]v_{f} \approx 5.701\,\frac{m}{s}[/tex]

La rapidez del bloque en la posición x = + 20 metros es aproximadamente 5.701 metros por segundo.

Explanation:

Given parameters:

Energy input  = 130000J

Energy output = 53000J

Unknown:

Efficiency of the conversion = ?

Solution:

Efficiency is the percentage of work output to work input;

  Mathematically;

 Efficiency  = Energy output/ Energy input x 100

 Efficiency  = 53000/130000 x 100 = 40.8%

Answer:

Explanation:

Given

final speed v = 3015ft/s

initial speed = 0m/s

Distance S = 4146m/s

Required

Time

Using the equation of motion to get the time;

S = (v+u)/2 * t

since 1m = 3.28084ft'

4146m = 3.28084 * 4146 = 13,602.36264feet

13,602.36264 = 3015+0/2 * t

13,602.36264 = 1,507.5t

t = 13,602.36264/ 1,507.5

t = 9.023 secs

Hence it will take 9.023 seconds the rescuer die the biller to strike a target

Answer:

Gravity always pulls the ball toward the center of earth (the ground).

Explanation:

Answer:

0 I think

Explanation:

Answer:

32 m/s².

Explanation:

From the question given above, the following data were obtained:

Mass (m) of cart = 120 Kg

Radius (r) = 15 m

Velocity (v) = 22 m/s

Centripetal acceleration (a) =?

The centripetal acceleration experienced by the cart can be obtained as illustrated below:

a = v²/r

a = 22² / 15

a = 484 / 15

a = 32.27 ≈ 32 m/s²

Thus, the centripetal acceleration experienced by the cart is approximately 32 m/s².

Answer:

so first is the clouds is presipitision then its  the ocean one and then dirt and then the mud then the gray part

Explanation:

Answer:

the answer might be A and D if not sorry

Explanation:

Answer:

Explanation:

A ) Total energy of spring block system at height = kinetic energy at the bottom

= 1/2 m V²

= .5 x 2 x 2²

= 4 J

B )

height of ramp be h

mgh = 1/2 m ( v₂² - v₁² )

2 x 9.8 x h = 2² - 1.2²

19.6 h = 4 - 1.44

h = .1306 m

13.06 cm

C ) If distance between B and C be x₁

work done by friction = reduction in kinetic energy

= μ mg x₁ = 1/2 m ( 2² - 1.4² )

.3 x 9.8 x₁ = 1.02

x₁ = 34.7 cm

D )

If distance between C and D be x₂

work done by friction = reduction in kinetic energy

= μ mg x₂ = 1/2 m ( 1.4² - 0 )

.3 x 9.8 x₂ = .98  

x₂ = 33.33 cm

E )

Total work done by friction

= 1/2 m v² - 0 , v = 2 m /s

= .5 x 2 x 2²

= 4 J .

F )

Mechanical energy of the system at E = 0

G ) 1/2 k x² = 1/2 m v²

kx = 50 N , where x is compression and k is spring constant

k²x² / 2k = 1/2 m v²

50² / k = 2 x 1.2²

k = 868.05 N / m

H ) kx = 50

x = 50 / k

= 50 / 868.05

= 5.76 cm .

Answer:  

t=2.59s

Explanation:

v=23.5m/s u=15.2m/s a=3.2m/s^2 t=?

using equation v=u+at t=(v-u)/a t= (23.5-15.2)/3.2=8.3/3.2=2.59s

Answer:

part a: 4.25s

part b: 180.625m

Explanation:

part a:

what we know: vi=42.5m/s

                          t=?

                          vf=0

                          g= -10m/s^2

----------------------------------------------------------

equation: vf-vi/g=t

plug in: -42.5m/s/ - 10m/s^2 = 4.25s

-----------------------------------------------------------

part b: 42.5m/s x(times) 4.25s = 180.625m

Answer:

59.51 mph.

Explanation:

The following data were obtained from the question:

Distance (d) = 147 miles

Time (t) = 2.47 hours.

Speed (S) =?

Speed is defined as the distance travelled per unit time. Mathematically, it is expressed as:

Speed (S) = Distance (d) / time (t)

S = d/t

With the above formula, we can obtain the speed of the girl as illustrated below:

Distance (d) = 147 miles

Time (t) = 2.47 hours.

Speed (S) =?

S = d/t

S = 147 miles / 2.47 hours.

S = 59.51 miles per hour (mph)

Thus, the speed of the girl is 59.51 mph.

Answer:

deposition, sublimation

Explanation:

The changes of state occur between solids and gases during deposition and sublimation. The second and fifth option are correct.

The conversion of solid to gas and gas to solid directly, as in case of solid ice made of carbon di oxide.

The change of state means changing the phase of the matter with the change in temperature and pressure of the surrounding.

The vaporization change liquid to gas or solid to liquid and vice versa. Freezing is converting liquid to solid. Melting is converting from solid to liquid.

The rest phenomenon are deposition and sublimation in which phase change between solid and gas.

Thus,  second and fifth option are correct.

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Answer: an steppe climate

Explanation:

Answer:

C-objects with balanced forces remain un changed

Explanation:

because the forces that act on the body cancel each other and the net force=0

Answer:

v =  44,3 m/s

Explanation:

La velocidad la podemos hallar usando la siguiente expresión:

[tex] v_{f}^{2} = v_{0}^{2} - 2gh [/tex]

En donde:

h: es la máxima altura = 100 m

[tex]v_{f}[/tex]: es la velocidad final = 0 (en la altura máxima)

[tex]v_{0}[/tex]: es la velocidad inicial =?

g: es la gravedad = 9,81 m/s²

Resolviendo la ecuación anterior para v₀, tenemos:

[tex] v_{0} = \sqrt{2gh} = \sqrt{2*9,81 m/s^{2}*100 m} = 44,3 m/s [/tex]

Entonces, el proyectil fue lanzado hacia arriba con una velocidad de 44,3 m/s.

Espero que te sea de utilidad!                      

Answer:

Vy = 4.65 m/s

Explanation:

Since, the airplane is descending at a rate of 480 km/h at an angle of 2° from horizontal. Therefore, its vertical component of velocity shall be given as follows:

Vy = V Sin θ

where,

Vy = Vertical Component of Velocity = ?

V = Velocity of Plane = (480 km/h)(1000 m/1 km)(1 h/3600 s) = 133.33 m/s

θ = Angle = 2°

Therefore,

Vy = (133.33 m/s)(Sin 2°)

Vy = 4.65 m/s

Knowing the force and the duration, we can simply multiply them to get the "impulse".  This is really convenient for this question, because the impulse is also the change in momentum.  So let's do it:

Change in momentum =  (force) x (duration)

Change in momentum = (1 x 10² Newtons) x (1 x 10⁴ seconds)

Change in momentum = (100 N) x (10,000 seconds)

Change in momentum = 1,000,000 Newton-seconds

Change in momentum = 1,000,000 kg-m/s .

That sunawfulada momentum !  It's the same change in momentum as if you stopped a 4,000-kg truck that was going 550 mph, in 1 second !

There's gotta be something wrong here.

Notice the duration of the impact in the question: 1 x 10⁴ seconds.

That's 2 hours and 47 minutes !  Collisions don't normally take that long.

Call me batty, but I've got a hunch that the duration actually is supposed to be 1.0 x 10 to the NEGATIVE fourth power. Then, the change in momentum is

(100 N) x (0.0001 s)  =  0.01 kg-m/s

That's still a slightly uncomfortable result, but it's definitely more realistic ... it could be the act of batting a fly or a mosquito out of the air.

I like that a lot better than a collision that takes almost 3 hours.

Density is the mass per unit volume of any object. It is calculated by dividing the mass of an object by its volume. This is:

ρ = m/V

ρ = 4.05 g  / 12 mL

ρ = 0.3375 g/mL

OPTION A

Answer:

I think that Mars would be the easiest planet for humans to colonize because they have already begun working on colonizing Mars and have made a ton of progress.

Answer:

The force of gravity, g = 9.8 m/s2

Gravity accelerates you at 9.8 meters per second per second. After one second, you're falling 9.8 m/s. After two seconds, you're falling 19.6 m/s, and so on.

Time to splat: sqrt ( 2 * height / 9.8 )

It's the square root because you fall faster the longer you fall.

The more interesting question is why it's times two: If you accelerate for 1 second, your average speed over that time is increased by only 9.8 / 2 m/s.

Velocity at splat time: sqrt( 2 * g * height )

This is why falling from a higher height hurts more.

Energy at splat time: 1/2 * mass * velocity2 = mass * g * height

Explanation:

The time taken by the rock to fall will be 3 seconds.

Velocity is defined as the ratio of the distance moved by the object at a particular time. The velocity is a vector quantity so it needs both the magnitude and the direction.

The time taken for the freely falling body is calculated by the equations of motion. That is v² = u² + 2gs. By using the equation we can calculate the velocity and the time period.

The force of gravity, g = 9.8 m/s²

Gravity accelerates you at 9.8 meters per second per second. After one second, you're falling 9.8 m/s. After two seconds, you're falling 19.6 m/s, and so on.

Time to splat  = √( 2 x height) / 9.8

Time to splat  =  √( 2 x 50 ) / 9.8

Time to splat  =  3 seconds

Therefore, the time taken for the rock to fall will be 3 seconds.

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Answer:

vf=79.38 m/s

y= 321.5 m

Explanation:

Free Fall Motion

A free-falling object falls under the exclusive influence of gravity. Free-falling objects do not encounter air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is [tex]g = 9.8 m/s^2[/tex].

The final velocity of a free-falling object after a time t is given by:

vf=g.t

The distance traveled by a dropped object is:

[tex]\displaystyle y=\frac{gt^2}{2}[/tex]

1.

The penny will fall for t=8.1 s before hitting the ground, thus the height from which it was dropped is:

[tex]\displaystyle y=\frac{9.8\cdot 8.1^2}{2}[/tex]

y= 321.5 m

2.

The final velocity is:

[tex]vf=9.8\cdot 8.1[/tex]

vf=79.38 m/s

Answer:

102564.103 C

Explanation:

From the question given above, the following data were obtained:

Energy (E) = 4000 J

Potential difference (V) = 0.078 V

Charge (Q) =?

Thus, we can obtain the charge as illustrated below:

E = ½QV

4000 = ½ × Q × 0.078

4000 = Q × 0.039

Divide both side by 4000

Q = 4000 / 0.039

Q = 102564.103 C

Thus, the charge is 102564.103 C.

Answer:How far is the distance?

Explanation: