Determine the period, amplitude, and phase shift of[tex]f(x)=3cos2\left \{ x-\frac{\pi }{4}]+1[/tex]

b) List the five critical points for the first cycle. (3 marks)

Use this information to sketch the graph off(x) for two

complete cycles. Determine [tex]\frac{1}{4}[/tex] wave and starting point.

Clearly label the scale on both axes. (3 marks)

Answer:

g(x) = (x + 2)² + 1

Explanation:

Given parent function: f(x) = x²

If the function translates two units right

If the function translates one units up

Green's theorem in vector calculus connects a line integral around a simple closed curve C to a double integral over the plane area D limited by C.

Green's theorem in vector calculus connects a line integral around a simple closed curve C to a double integral over the plane area D limited by C. It is a two-dimensional variant of Stokes' theorem.

The path of the particle is positively oriented so we can use Green's theorem to find the work done in moving particle along C.

The work done is given by [tex]\oint_{c}\vec F \cdot \vec{dr}[/tex]

Here, [tex]\vec F[/tex](x,y)=<x+y, y²-x>

Then [tex]\oint_{c}\vec F \cdot \vec{dr} = \oint_{c}(x+y)dx+(y^2-x)dy[/tex]

In comparison with [tex]\oint_{c}Pdx+Qdy[/tex] what we have,

P= x+y and Q=y²-x

Then [tex]\dfrac{\partial P}{\partial y} = 1[/tex] and [tex]\dfrac{\partial Q}{\partial x} =-1[/tex]

Using the Green's Theorem,

[tex]\oint_{c}Pdx+Qdy = \iint_{D} \left ( \dfrac{\partial Q}{\partial x}-\dfrac{\partial P}{\partial y}\right )dA[/tex]

Here D in polar Co-ordinates is given by,

D={(r,θ) : 0 ≤ r ≤ 7, 0 ≤ θ ≤ π}

Then

[tex]\oint_{c}(x+y)dx+(y^2-x)dy\\\\=-\iint_D 2dA\\\\=-\int_{\pi}^{0}\int_{0}^7 2r drd\theta\\\\=-49\pi[/tex]

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Answer:

3/20

Step-by-step explanation:

0.15 = 15/100

This is not simplified though :

15/100 ÷ 5/5 = 3/20

This is simplified

Hope this helped and brainliest please.

The correct answer is option c. Which is the function is increasing when x is greater than zero.

A function in mathematics set up a relationship between the dependent variable and independent variable. on changing the value of the independent variable the value of the dependent variable also changes.

In the graph, we can see that at the origin the graph becomes zero. When the graph proceeds rightwards the value of the function is increasing as the value of x is increasing.

Therefore the correct answer is option c. Which is the function is increasing when x is greater than zero.

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Answer:

Behold! Try using Desmos or something

#PlatoAccuracyMatters

#WhaddyaMeanPlatoLives?

Step-by-step explanation:

The functions and their matching properties are:

To do this, we start by plotting the graphs of the functions h(x), j(x) and g(x)

Next, we list out the properties from the graphs

From the graphs of the functions (see attachment), we have the following highlights:

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Answer:

8/3

Divide both sides by the GCF, 4.

32 ÷ 4 = 8

12 ÷ 4 = 3

Step-by-step explanation:

6x² - 24x - 3x + 2

6x² - 27x + 2

Answer:

C 17.25

Step-by-step explanation:

i think aanswer its c

Answer:

12.04

Step-by-step explanation:

add 8 and 9 by the power of two: 8^2+9^2

that equals to 145

find the square root of 145 and that equals to 12.04

Answer:

  0.8

Step-by-step explanation:

The change of base formula for logarithms can be used to find this value exactly. (Your calculator can also tell you.)

  [tex]\log_b(a)=\dfrac{\log(a)}{\log(b)}[/tex]

__

Using this relation with the given numbers, we have ...

  [tex]\dfrac{\log(256)}{\log(1024)}=\dfrac{\log(2^8)}{\log(2^{10})}=\dfrac{8\cdot\log(2)}{10\cdot\log(2)}=\dfrac{8}{10}\\\\\boxed{\dfrac{\log(256)}{\log(1024)}=0.8}[/tex]

The inequality sign can be used when referring to two quantities that are not the same size.

An inequality is used to express a condition whereby the two quantities are not the same.

For instance, if we have the same number of students inside and outside a classroom, we can use the equality sign. In a case where we do not have the same number of students inside and outside the classroom, we can use the inequality sign.

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Answer:

see explanation

Step-by-step explanation:

the set of x- values ( the input ) are called the domain

Answer:

domain

Step-by-step explanation:

as the y values is the range

The test statistic is -0.46 and the p-value is gotten as 0.3340

The question is not complete because the data from the sample is 105, 107, 117, 106, 110.

Mean of sample is;

Mean = (105 + 107 + 117 + 106 + 110)/5

Mean; x' = 109

From online standard deviation calculator, the standard deviation of the sample is; S = 4.848

Now, the claim is that your team scored an average significantly less than 110 points. Thus, let's define the hypothesis as;

Null Hypothesis; μ = 110

Alternative Hypothesis; μ < 110

standard error of the mean; S_m = S/√n

S_m = 4.848/5

S_m = 2.17

Thus, the t-statistic is;

t = (x' - μ)/S_m

t = (109 - 110)/2.17

t = -0.46

Degree of freedom for this sample size is;

D.F = N - 1 =5 - 1 = 4

From online p-value from t-score calculator, we have;

p-value = 0.3340

The p-value is greater than the significance value and as such we fail to reject the null hypothesis and conclude that there is not enough evidence to support the claim that your team scored an average significantly less than 110 points.

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Step-by-step explanation:

p = 2r + pi×r

p = r(2 + pi)

r = p/(2 + pi)

Answer:

r = [tex]\frac{p}{2+\pi }[/tex]

Step-by-step explanation:

p = 2r + πr ← factor out r from each term

p = r(2 + π) ← divide both sides by (2 + π )

[tex]\frac{p}{2+\pi }[/tex] = r

Answer:

y=3 x=4

Step-by-step explanation:

4x - 2y = 10

4x + y = 19

    -3y=-9

the 4x canceled out.

y=3

plug in y into one of the equations

4x + 3 = 19

4x=16

x=4

Hope this helps!

If not, I am sorry.

Answer:

(4, 3 )

Step-by-step explanation:

4x - 2y = 10 → (1)

4x + y = 19 → (2)

subtract (1) from (2) term by term

(4x - 4x) +y - (- 2y) = 19 - 10

0 + y + 2y = 9

3y = 9 ( divide both sides by 3 )

y = 3

substitute y = 3 into either of the 2 equations and solve for x

substituting into (2)

4x + 3 = 19 ( subtract 3 from both sides )

4x = 16 ( divide both sides by 4 )

x = 4

solution is (4, 3 )

[tex]\qquad\qquad\huge\underline{{\sf Answer}}[/tex]

Let's evaluate ~

The given expression is :

[tex]\qquad \sf  \dashrightarrow \:4x + 8[/tex]

plug the value of x as 3

[tex]\qquad \sf  \dashrightarrow \:4(3) + 8[/tex]

[tex]\qquad \sf  \dashrightarrow \:12 + 8[/tex]

[tex]\qquad \sf  \dashrightarrow \:20[/tex]

Therefore, the required value is 20

Answer:

a. equation

Step-by-step explanation:

The LHS is equal to the RHS

Two or more expressions with an Equal sign is called as Equation. Hence Equation is the relationship of 5x+3=7.

Two or more expressions with an Equal sign is called as Equation.

The given is 5x+3=7

It is a equation because the left hand side is equal to the RHS side

It has a equal sign.

Where as in expressions there will be no equal sign.

Expression has only numbers, operators and variables.

5x+3=7 is not a function as it has no y variable or other variable.

Hence equation is the relationship of 5x+3=7.

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Answer:

72

Step-by-step explanation:

54/2(3)−3^2

= 54/2(3)−3^2

=72

Answer:

[tex]x = -3~\text{and}~ x = -\dfrac 35[/tex]

Step-by-step explanation:

[tex]~~~~~~5x^2 +18x +9=0\\\\\implies 5x^2 +15x +3x +9 = 0\\\\\implies 5x(x+3) +3(x+3) = 0\\\\\implies (x+3)(5x+3) = 0\\\\\implies x = -3,~ x = -\dfrac 35[/tex]

Answer:

x = -3

OR

x = -(3/5)

Step by step explanation:

Given:

To Find:

Soln:

Use quadratic formulae:

[tex] \rm x=\cfrac{-b\pm\sqrt{b^2-4ac}}{2}[/tex]

According to the question,on the formula,

So substitute them on the formula:

THEN solve for x.

[tex] \rm \implies \: x = \cfrac{-1 8 \pm \sqrt{18 {}^{2} - 4(5 \times 9) }}{2 \times 5} [/tex]

[tex] \rm \implies \: x = \cfrac{-1 8 \pm \sqrt{324- 20 \times 9) }}{10} [/tex]

[tex]\rm \implies \: x = \cfrac{-1 8 \pm \sqrt{324- 180}}{10} [/tex]

[tex] \rm \implies \: x = \cfrac{ - 18 \pm \sqrt{144} }{10} [/tex]

[tex] \rm \implies \: x = \cfrac{ - 18 \pm12}{10}[/tex]

[tex] \rm \implies \: x = \cfrac{9 \pm 6}{5} [/tex]

Final solution will after adding first(9+6),then secondly subtracting both 9-6

[tex] \rm \implies \boxed{x = - \cfrac{3 }{5} }[/tex]

[tex] \implies \boxed{\rm x = - 3}[/tex]

So there'll be two possible answers.

Explanation:

Jamie has 7 choices for the first slot, then 6 choices for the next, and 5 choices for the final slot. Order matters. He has 7*6*5 = 210 permutations.

Alternatively you can use the nPr permutation formula with n = 7 and r = 3.

That formula is

[tex]nPr = \frac{n!}{(n-r)!}[/tex]

The exclamation marks indicate factorials. For instance, 4! = 4*3*2*1 = 24.

Answer:

B. 210 is correct!

Step-by-step explanation:

I got it correct on the quiz.

im not sure I'd need to see the figure

The area of the shaded region = area of semicircle - area of triangle ACB = 11.32 cm².

Area of a triangle = 1/2(base)(height).

Area of a semi-circle = 1/2(πr²).

m∠ACB is a right triangle based on the central angle theorem. Therefore, ΔACB is a right triangle.

Radius of circle = OC = 4 cm

CB = 4 cm

Diameter AB = 2(4) = 8 cm

Using the Pythagorean theorem, find AC in ΔACB:

AC = √(AB² - CB²)

AC = √(8² - 4²)

AC ≈ 6.9 cm

Area of ΔACB = 1/2(CB)(AC)

Area of ΔACB = 1/2(4)(6.9)

Area of ΔACB ≈ 13.8 cm²

Area of semicircle = 1/2(πr²) = 1/2(π)(4²)

Area of semicircle ≈ 25.12 cm²

Area of the shaded region = area of semicircle - area of triangle ACB = 25.12 - 13.8

Area of the shaded region = 11.32 cm²

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The probability of a flowering plant bearing flowers in January if it is a tulip is 68%.

From the attached table, we see the respective probabilities of each flower bearing flowers in January as;

Tulip = 68%

Anemon = 81%

Manzanita = 77%

Peony = 70%

Fuschia Flowering currant = 74%

Total = 76%

Thus, it is clear that the probability of a flowering plant bearing flowers in January if it is a tulip is 68%.

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Answer: insufficient data

Step-by-step explanation: Plato 100% right

Answer:

113.04m^2

Step-by-step explanation:

Surface area for Base and top

[tex]2*\pi d=2*3.14*4=25.12[/tex]

Surface area for the other part

[tex]\pi d*h = 12.56*7 = 87.92[/tex]

you will get

113.04m^2

The equation we can use to find the value of x in the diagram given is: B. (5x + 30) + 5x = 90.

Angles that give a sum of 90 degrees when added are referred to as complementary angles.

The angles, (5x + 30) and 5x are complementary angles, since the sum of both gives a right angle (90 degrees).

Therefore, the equation that we can use to find x in the diagram is: B. (5x + 30) + 5x = 90.

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Answer:

D

Step-by-step explanation:

A function input can only have ONE output value

so the number 5 can't output two different numbers

Answer:

15

Step-by-step explanation:

First lets simplify the left side :

5/12 + 5/12 + 5/12 = 15/12

15/12

To make the right side into 15/12 we must multiply it by 15:

15 × 1/12 = 15/12

So the blank is 15

Hope this helped and brainliest please.

Answer:

15/1

Step-by-step explanation:

you simply add the 5's only not the 12. when u multiply 1 and 12 u get 12 and when you multiply 15 and 1 you get 15

The what is the volume of a cube if the diagonal of one side is 5sqrt(2) is V = 125 cubic units

A square is a shape with 4 sides

Let the side of the square be x units. If the length of the diagonal is 5√2, the value of x can be expressed using the pythagoras theorem as shown;

x² + x² = (5√2)²

2x²  = 25(2)

x² = 25

x = 5 units

Determine the volume

V = x³

V = 5³

V = 125 cubic units

Hence the what is the volume of a cube if the diagonal of one side is 5sqrt(2) is V = 125 cubic units

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Answer:

It would take him 4 hrs.

Step-by-step explanation:

Hope this helps!

Time taken by mike alone to finish the Task is 12 hours.

steve can complete a task in 6 hours.
he and mike can complete the same task in 4 hours.

Rate of change is defined as the change in value with rest to the time is called rate of change.

Here,
Rate of steve finishing task per hour = 1/6
Rate at which both finishes the task per hour = 1/4
Rate at which mike finishes the task per hour = M
now

M = 1/4-1/6
M = 3-2/12
M = 1/12
here, mike finishes his task at 12 hours

Thus, Time taken by mike alone to finish the Task is 12 hours.

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