cells in animals and plants use the ___ that plants put in the air

Answer:

What is the new volume if the temperature is constant? V=2.50L. P = lookPa. P2=40k Pa. V2 = x. PV = P2 ... If a sample of gas occupies 6.8 L at 327°C

To determine the volume of N_{2} gas produced when 42.7 g of CO is reacted completely at STP (Standard Temperature and Pressure), we need to use the concept of molar ratios and the ideal gas law. By calculating the number of moles of CO and using the balanced equation, we can find the number of moles of [tex]N_{2}[/tex]. Then, using the ideal gas law, we can convert the moles of N_{2} to volume at STP.

First, we need to determine the number of moles of CO using its molar mass. The molar mass of CO is approximately 28.01 g/mol. By dividing the given mass (42.7 g) by the molar mass, we can calculate the number of moles of CO. Next, using the balanced equation, we see that the stoichiometric ratio between CO and N2 is 2:1. This means that for every 2 moles of CO, 1 mole of N_{2}is produced. By applying the stoichiometric ratio, we can determine the number of moles of N_{2}produced.

Finally, to find the volume of N2 gas at STP, we can use the ideal gas law. At STP, the pressure is 1 atmosphere (atm) and the temperature is 273.15 K. The ideal gas law equation, PV = nRT, can be rearranged to V = (nRT)/P, where V is the volume, n is the number of moles, R is the ideal gas constant, T is the temperature in Kelvin, and P is the pressure. By substituting the calculated number of moles of N_{2}, the ideal gas constant, the temperature at STP, and the pressure at STP into the ideal gas law equation, we can determine the volume of N_{2} gas produced.

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Ozone was created millions of years ago from a natural process frozen in ice during the ice age, the gases that make up the ozone layer were formed naturally from oxygen atoms accompanied by a reaction of ultraviolet radiation and molecular oxygen which was frozen in the ice during the time of the ice age was released over years as the ice melted.

An atom is defined as the smallest unit of matter which forms an element. Every form of matter whether solid,liquid , gas consists of atoms . Each atom has a nucleus which is composed of protons and neutrons and shells in which the electrons revolve.

The protons are positively charged and neutrons are neutral and hence the nucleus is positively charged. The electrons which revolve around the nucleus are negatively charged and hence the atom as a whole is neutral and stable due to presence of oppositely charged particles.

Atoms of the same element are similar as they have number of sub- atomic particles which on combination do not alter the chemical properties of the substances.

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Answer: The molarity of solution is 0.08 M

Explanation:

pH is the negative logarithm of hydrogen ion concentration. It tells abpout the acidity or basicity of a solution.

[tex]pH=-log[H^+][/tex]

also pH+pOH=14

given : pH of NaOH = 12.9

Thus pOH = (14-12.9) = 1.1

Thus [tex][OH^-]=10^{-1.1}=0.08M[/tex]

As [tex]NaOH\rightarrow Na^++OH^-[/tex]

As 1 mole of [tex]OH^-[/tex] is produced by = 1 mole of NaOH

Thus 0.08 moles of [tex]OH^-[/tex] are produced by = [tex]\frac{1}{1}\times 0.08=0.08[/tex] moles of NaOH

The molarity of solution is 0.08 M

The statement is True. In an aqueous and diethyl ether extraction, the aqueous layer will be the top layer. This is due to the difference in density between water and diethyl ether.

Water has a higher density compared to diethyl ether, which causes it to settle at the bottom layer. Diethyl ether, being less dense, will form the top layer. During the extraction process, immiscible solvents like water and diethyl ether are used. Since these solvents do not mix together, they form separate layers based on their densities. Water, being denser, will settle at the bottom while diethyl ether, being lighter, will float on top. This allows for the separation of compounds or substances that are preferentially soluble in either of the solvents. By carefully extracting the top or bottom layer, depending on the desired component, one can isolate specific compounds from a mixture.

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Answer:

bacteria

Explanation:

answer: yes I believe so

explain: I just think it is I have done this before

1 2 3 4 5 and how the question ask

a. True. Due to the differences in composition between serous fluid and serum, the normal values for chemistry tests can vary.

Serum refers to the liquid component of blood that remains after the blood has clotted and the clot has been removed.

On the other hand, serous fluid is a clear, watery fluid that is similar to serum and is found in body cavities such as the pleural, peritoneal, and pericardial cavities.

The composition of serous fluid can differ from serum due to various factors. When testing serous fluid, the values for chemistry tests such as electrolytes, proteins, enzymes, and other analytes may have different reference ranges compared to those obtained from serum testing. This is because the cellular and protein content of serous fluid is different from that of blood serum.

For example, the normal range for protein concentration in serum is generally higher compared to serous fluid due to the presence of fibrinogen and other proteins involved in clotting that are not present in serous fluid.

Due to the differences in composition between serous fluid and serum, the normal values for chemistry tests can vary. Therefore, it is important to use appropriate reference ranges specific to serous fluid when interpreting the results of chemistry tests on serous fluid samples.

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The element with the following electron configuration [Kr] 4d105s25p2 belongs to transition element.

The given electron configuration belongs to an element with atomic number 52. It can be written as 1s22s22p63s23p63d104s24p64d105s25p2. It belongs to the transition element as the electrons are filled in d orbital. KNO3 dissolves in water is a physical change.A physical change refers to a change in the state or properties of matter without any modification in its composition. The given options that are physical change and rest is a chemical change.KNO3 dissolves in water is a physical change as the salt is still KNO3 and has not been modified into something else. It simply separated into smaller particles to mix uniformly with the solvent, which in this case is water.A firecracker explodes, when popcorn pops when placed in a microwave and a piece of wood is burned are all examples of chemical change.A nail rusts is also a chemical change.

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Phospholipids with tails of 18 carbon atoms and two double bonds would   produce the most fluid lipid bilayer

Option (D) is correct.

The fluidity of a lipid bilayer is influenced by the composition of the phospholipids that make up the membrane. The presence of unsaturated fatty acid tails, indicated by the presence of double bonds, increases the fluidity of the lipid bilayer.

phospholipids with tails of 18 carbon atoms and two double bonds, would produce the most fluid lipid bilayer among the given choices. The presence of double bonds in the fatty acid tails introduces kinks in the hydrocarbon chains, which prevent them from packing tightly together. This increases the fluidity of the lipid bilayer by allowing the phospholipids to move more easily.

Therefore, the correct option is (D).

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Answer: 65 cal

Explanation: they have to find the weight of the peanuts on a scale and per grams. Then put them in water . You should be able to get the calories

Answer:

0

Explanation:

A voltage makes the electric charges to move.

When we install a D - cell batteries in the flashlight with their positive ends facing each other, as compared to the batteries installed with their positive and negative terminals facing each other, the flashlight will not work as the total voltage across the two batteries will be zero.

The equilibrium constant expression for the given reaction is:

[tex]K = ([HCl]^2 * [Br_2]) / ([HBr]^2 * [Cl_2])[/tex]

To calculate the value of the equilibrium constant for the reaction [tex]2HBr(g) + Cl_2(g)[/tex] ⇌ [tex]2HCl(g) + Br_2(g),[/tex] you need the concentrations (or pressures) of the reactants and products at equilibrium.

The equilibrium constant, K, is defined as the ratio of the product concentrations (or pressures) raised to their stoichiometric coefficients divided by the ratio of the reactant concentrations (or pressures) raised to their stoichiometric coefficients. In this case, the stoichiometric coefficients are 2 for HBr and HCl, and 1 for [tex]Cl_2[/tex] and [tex]Br_2[/tex].

The equilibrium constant expression for the given reaction is:

[tex]K = ([HCl]^2 * [Br_2]) / ([HBr]^2 * [Cl_2])[/tex]

Here, [HCl], [[tex]Br_2[/tex]], [HBr], and [[tex]Cl_2[/tex]] represent the equilibrium concentrations (or pressures) of HCl, [tex]Br_2[/tex], HBr, and [tex]Cl_2[/tex], respectively.

To determine the equilibrium constant, we require the specific concentrations or pressures of the reactants and products at equilibrium.

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Approximately 100.916 kJ of energy is required to form 140.0 g of NO2 from its respective elements.

The energy required to form 140.0 g of NO2 from its respective elements can be calculated using the standard heat of formation and stoichiometry. First, we need to determine the number of moles of NO2 in 140.0 g. The molar mass of NO2 is 46.01 g/mol, so the number of moles is calculated as:

moles of NO2 = mass of NO2 / molar mass of NO2 = 140.0 g / 46.01 g/mol ≈ 3.043 mol

Next, we multiply the number of moles by the standard heat of formation, which is given as 33.2 kJ/mol:

energy required = moles of NO2 × standard heat of formation

= 3.043 mol × 33.2 kJ/mol

≈ 100.916 kJ

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Answer:

1) 5.0 mL, 4.0 mL, 3.0 mL and 2.0 mL respectively.

2) 3.0 mL

Explanation:

Hello there!

1) In this case, by considering that the equation we use for dilutions contain the initial and final concentrations and volumes:

[tex]C_1V_1=C_2V_2[/tex]

For the first four solutions, we compute the volume of the stock one (V1) as shown below:

[tex]V_1=\frac{C_2V_2}{C_1}[/tex]

Thus, we obtain:

[tex]V_1^1=\frac{3.5x10^{-5}M*10.00mL}{7.0x10^{-5}M} =5.0mL\\\\V_1^2=\frac{2.8x10^{-5}M*10.00mL}{7.0x10^{-5}M} =4.0mL\\\\V_1^3=\frac{2.1x10^{-5}M*10.00mL}{7.0x10^{-5}M} =3.0mL\\\\V_1^4=\frac{1.4x10^{-5}M*10.00mL}{7.0x10^{-5}M} =2.0mL[/tex]

2) In this case, for a final concentration of 2.1x10-5 M and a volume of 10.00 mL, the volume of the stock solution would be:

[tex]V_1=\frac{2.1x10^{-5}M*10.00mL}{7.0x10^{-5}M} =3.0mL[/tex]

Best regards!

Explanation:

Indoors, you can change the size of a shadow by moving your body or the object closer to or farther from the light.

Shadows grow bigger and fuzzier as the object moves closer to the light source, and smaller and sharper as the object moves farther away.

Answer:

C) Na2HAsO4 and Na2SO4

Explanation:

Got it right on Edg

Answer:

The answer is C 65 g/100 mL of water

Explanation:

Answer:

Define Transportation in plants: Transportation in plants is when the plant transports water and other mineral throughout the whole plant from the roots to the stem and finally specific parts of a plant.

Define Respiration In Plants: Is when plants use photosynthesis to make their own food to make energy for the plant's growth

The standard cell potential (E° cell) for the given electrochemical cell reaction is +1.103 V. (B)

Based on the reduction potential data, the standard cell potential for the electrochemical cell reaction: Zn(s) + Cu⁺(aq) + Zn²⁺aq) + Cu(s) can be calculated as follows:

Reaction: Zn(s) + Cu²⁺(aq) → Zn²⁺(aq) + Cu(s)

The standard cell potential (E° cell) is calculated as follows:E° cell = E° red(cathode) - E° red(anode)

We have, E° red(Zn²⁺) = -0.763 VE° red(Cu²⁺) = +0.340 V

Therefore,E° cell = E° red(Cu²⁺) - E° red(Zn²⁺) = 0.340 V - (-0.763 V) = +1.103 V

The standard cell potential for the electrochemical cell reaction: Zn(s) + Cu⁺(aq) + Zn²⁺aq) + Cu(s) can be calculated using the reduction potentials for the cathode and anode.

The cathode has a reduction potential of +0.340 V for Cu²⁺(aq) + 2e⁻ Cu(s) and the anode has a reduction potential of -0.763 V for Zn²⁺ (aq) + 2e⁻Zn(s).

Using the formula,E° cell = E° red(cathode) - E° red(anode)we get,E° cell = E° red(Cu²⁺) - E° red(Zn²⁺) = 0.340 V - (-0.763 V) = +1.103 V.(B)

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Answer:

2059.645g Cl

Explanation:

A mole of any element contains 6.022e23 molecules, so we will divide the given amount of molecules by 6.022e23.

3.5e25 / 6.022e23 = 5.81e1

5.81e1 = 58.1 mol Cl

Now that we have found the amount of moles of Chlorine, we will multiply the number of moles by the molar mass of Chlorine, which is 35.45g/mol.

35.45(58.1) = 2059.645g Cl

Answer:

please give me brainlist and follow

Explanation:

In this type of neutralization reaction, the acids and bases are the reactants, since they are the materials that will react to form a new solution. ... For instance, in the equation HCl + NaOH → NaCL + H2O, the HCl (hydrochloric acid, a strong acid) and NaOH (sodium hydroxide, a strong base) are the reactants.

Answer:

The hydrogen reacts with oxygen across an electrochemical cell

Explanation:

Answer:

See explanation

Explanation:

In ClNO , nitrogen is the central atom here. The central atom has a tetrahedral electron pair geometry and a lone pair on the nitrogen atom. Due to the lone pair, the electron pair geometry is now trigonal pyramidal.

The molecule CS2 has a linear molecular geometry. There are four electron groups around the central atom hence the electron pair geometry is tetrahedral but the molecular geometry results from the repulsion of the two double bonds.

The electron domain geometry for Cl2CO  is tetrahedral since there are four electron pairs around the central atom. However, the molecular geometry is trigonal planar due to the sp2 hybridization of the central carbon atom.

The electron domain geometry of Cl2SO  is tetrahedral due to the four electron pairs around the central atom. However, due to the lone pair on sulphur, the molecular geometry is  triagonal pyramidal.

In SO2F2, sulphur the central atom is surrounded by four electron pairs which are all bonding groups hence both the molecular geometry and the electron pair geometry is tetrahedral.

In XeO2F2, the central atom is Xe. There are five electron pairs around the Xe central atom four of which are bonding groups. The electron domain geometry and molecular geometry is trigonal bipyramidal.

For ClOF2 , the central atom Cl is surrounded by four electron pairs hence the electron pair geometry is tetrahedral but it is an AX3E(three bonding groups and one lone pair are present in the structure) specie hence it is trigonal pyramidal.

Answer:

One of the most common methods used today to determine the composition of stars is spectroscopy.

Explanation:

Spectroscopy is the study of the interaction between matter and electromagnetic radiation as a function of the wavelength or frequency of the radiation.