The sheet of metal has dimensions 56 cm by 33 cm. It sis melted down
and recast into discs of the same thickness and radius 7 cm. How many
disces will be cast ?

(i) The uniform and normal distribution for chromium is 2.4927 and 16.5762. (ii) The uniform and normal distribution for Barium is 0.0031 and 0.3323. (iii) The uniform and normal distribution for Fluoride is 0.0289 and 0.0167

For each substance, the standard deviation o is estimated by assuming uniform distribution and normal distribution. The uniform distribution standard deviation is computed using the formula as follows:

o = (b-a) / √12

where

a is the minimum value,

b is the maximum value.

The normal distribution standard deviation is calculated using the formula as follows:

o = (b - a) / 6.

Estimate the standard deviation o for each substance. Round your answers to 4 decimal places. Substance Chromium Barium Fluoride Uniform Distribution. The range of contaminant levels for chromium is from 0.45 to 8.61. The minimum value is 0.45 and the maximum value is 8.61.

(i) Chromium

Uniform distribution

o = (b-a) / √12

  = (8.61 - 0.45) / √12

  = 2.4927

  ≈ 2.4927 (rounded to 4 decimal places)

Normal Distribution

The maximum value for chromium is 100 and the minimum value is 0.45. Thus, the standard deviation o for chromium using normal distribution is:

o = (b-a) / 6

  = (100 - 0.45) / 6

  = 16.5762

  ≈ 16.5762 (rounded to 4 decimal places)

(ii) Barium

Uniform Distribution

The range of contaminant levels for barium is from 0.006 to 0.018. The minimum value is 0.006 and the maximum value is 0.018.

Thus, the standard deviation o for barium using uniform distribution is:

o = (b-a) / √12

  = (0.018 - 0.006) / √12

  = 0.0031

  ≈ 0.0031 (rounded to 4 decimal places)

Normal Distribution

The maximum value for barium is 2 and the minimum value is 0.006. Thus, the standard deviation o for barium using normal distribution is:

o = (b-a) / 6

  = (2 - 0.006) / 6

  = 0.3323

  ≈ 0.3323 (rounded to 4 decimal places)

(iii) Fluoride

Uniform Distribution  

The range of contaminant levels for fluoride is from 1.04 to 1.14. The minimum value is 1.04 and the maximum value is 1.14. Thus, the standard deviation o for fluoride using uniform distribution is:

o = (b-a) / √12

  = (1.14 - 1.04) / √12

  = 0.0289

  ≈ 0.0289 (rounded to 4 decimal places)

Normal Distribution

The maximum value for fluoride is 1.14 and the minimum value is 1.04. Thus, the standard deviation o for fluoride using normal distribution is:

o = (b-a) / 6

  = (1.14 - 1.04) / 6

  = 0.0167

  ≈ 0.0167 (rounded to 4 decimal places).

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Complete Question:

The Environmental Protection Agency (EPA) requires that cities monitor over 80 contaminants in their drinking water. Samples from the Lake Huron Water Treatment Plant gave the results shown here. Only the range is reported, not the mean.

For each substance, estimate the standard deviation σ by using one of the methods shown in Table 8.11 in section 8.8. (Round your answers to 4 decimal places.)

(i) The uniform and normal distribution is Chromium.  

(ii) The uniform and normal distribution is Barium.  

(iii) The uniform and normal distribution is Fluoride.

Relation of each of these are:

(a) Reflexive: NO

(b) Symmetric: YES

(a) Reflexive: No.

The relation R is not reflexive because there exist elements x in set A for which x is not related to itself. For example, if we take x = 0, then 0 is not less than or equal to 0, so xRx does not hold.

(b) Symmetric: Yes.

The relation R is symmetric because for any x and y in set A, if xRy holds, then yRx also holds. This is because if x is less than or equal to y, then y is greater than or equal to x, satisfying the symmetry property of the relation.

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Answer:

0.333333

Step-by-step explanation:

0.333 yards are in one foot

16^1/5 = 2^4/5 .. & .. 8^3/4 = 2^9/4

____________

2^4/5 × 2^x = 2^9/4

2^16/20 × 2^x = 2^45/20

2^[ ( 16/20 ) + x ] = 2^45/20

16/20 + x = 45/20

x = 45/20 - 16/20

x = 29/20

Answer:

[tex]x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}[/tex]

Step-by-step explanation:

Quadratic formula: [tex]x=\frac{-b\±\sqrt{b^2-4ac} }{2a}[/tex] when the equation is [tex]0=ax^2+bx+c[/tex]

The given equation is [tex]1=-2x+3x^2+1[/tex]. Let's first arrange this so its format looks like [tex]y=ax^2+bx+c[/tex]:

[tex]1=-2x+3x^2+1[/tex]

[tex]1=3x^2-2x+1[/tex]

Subtract 1 from both sides of the equation

[tex]1-1=3x^2-2x+1-1\\0=3x^2-2x+0[/tex]

Now, we can easily identify 3 as a, -2 as b and 0 as c. Plug these into the quadratic formula:

[tex]x=\frac{-b\±\sqrt{b^2-4ac} }{2a}\\x=\frac{-(-2)\±\sqrt{(-2)^2-4(3)(0)} }{2(3)}[/tex]

I hope this helps!  

In a survey project, an outcome variable refers to the variable that represents the main focus or result of interest in the study.

In a survey project, the outcome variable, otherwise known as the dependent variable, represents the main focus or result of interest.

It is the variable researchers seek to measure or predict based on the collected data. The purpose of an outcome variable is to provide insights into the specific aspect being studied, enabling researchers to understand relationships between independent variables and the outcome.

Analyzing the outcome variable allows for drawing conclusions, identifying patterns, and determining the impact of various factors. It serves as a crucial metric for evaluating success, making informed decisions, and drawing meaningful conclusions from the survey findings.

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There are 40,320 different ways the race with 8 runners can be completed.

To determine the number of different ways a race with 8 runners can be completed, we can use the concept of permutations.

In a race with no tie, the order in which the runners finish matters. We want to find the number of permutations of 8 runners.

The formula to calculate permutations is given by n!, where n represents the number of items being permuted.

In this case, there are 8 runners, so the number of different ways the race can be completed is:

8! = 8 x 7 x 6 x 5 x 4 x 3 x 2 x 1 = 40,320.

Each permutation represents a unique arrangement of the runners crossing the finish line. By considering the order of finish for each runner, we account for all possible outcomes in the race.

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Answer:

I think the awnser is 27.9

Step-by-step explanation:

4.5*6.2=27.9

Answer:  Gradpoint answer

C.

7

Step-by-step explanation:  Math.way answer

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

Exact Form:

z = 0 ,  7/ 4

Decimal Form:

z = 0 ,  1.75

Mixed Number Form:

z = 0 ,  1  3/ 4

Answer:

7

Step-by-step explanation:

(z – 4)(2z + 1) = z(2z + 1) – 4(2z + 1) = 2z2 + z – 8z – 4 = 2z2 – 7z – 4

The second term is –7z, so 7 fills in the blank.

Answer:

Step-by-step explanation:

99(v + 9) is all you need here.

The proportion of the low-income group who are social networking users is approximately 0.6928, and the proportion of the high-income group who are social networking users is approximately 0.6464.

a) To find the proportions, we divide the number of social networking users in each income group by the total number of respondents in that group. For the low-income group, the proportion is 300/433 ≈ 0.6928. For the high-income group, the proportion is 353/546 ≈ 0.6464.

b) The difference in proportions is obtained by subtracting the proportion of the high-income group from the proportion of the low-income group. The difference is approximately 0.6928 - 0.6464 = 0.0464.

c) The standard error of the difference can be calculated using the formula SE = √[(p1(1-p1)/n1) + (p2(1-p2)/n2)], where p1 and p2 are the proportions of social networking users in each group, and n1 and n2 are the sample sizes of each group. Plugging in the values, we get SE ≈ √[(0.6928(1-0.6928)/433) + (0.6464(1-0.6464)/546)] ≈ 0.0348.

d) To construct a confidence interval for the difference between the proportions, we can use the formula CI = (difference ± critical value × SE). For a 99% confidence level, the critical value can be found using a standard normal distribution table, which is approximately 2.576. Plugging in the values, we get the 99% confidence interval ≈ (0.0464 ± 2.576 × 0.0348) ≈ (0.0464 ± 0.0685).

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The standardized test statistic is 12.961

To test the claim that σ = 2.38.7 with n - 12, a = -0.05 and 52-32.4,

we need to calculate the standardized test statistic.

The appropriate response is 12.961.

So, the standardized test statistic is calculated as follows:

`x = (n - 1)s² / σ²`

Where `n` is the sample size, `s` is the sample standard deviation, and `σ` is the population standard deviation.

`n = 12, s = 52 - 32.4 = 19.6, and σ = 2.38.7`

Then, `x² = (12 - 1)(19.6)² / (2.38.7)² = 12.961`

Therefore, the appropriate response is 12.961`.

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Answer:

Step-by-step explanation:

Answer: 14

Step-by-step explanation:

to find the answer we must figure out what half of 35 points is because Andrew scored 2/5 of 35.

we can write the equation like this:

2/5 of 35 = Andrew's points

2/5 of 35 = 14

therefore 2/5 of 35 is 14

therefore Andrew scored 14 points.

Answer:

x = 19.5   or 19 1/2

Step-by-step explanation:

cos 41 = 14.7/x

x = 19.5

Answer:    0.185

Step-by-step explanation:

Divide 120.99 and 654:

120.99÷654=0.185

So the final answer is 0.185 units.

A better approximation of f'(0) using Richardson's extrapolation is -6.91412.

To find a better approximation of f'(0) using Richardson's extrapolation, we can apply the formula:

[tex]R(1,1) = f'(h) + (f'(h) - f'(2h))/((1/2)^1 - 1)[/tex], where h is the step size.

Given the values:

f'(1) = -4.50557 (for h = 1)

f'(0.5) = -2.09702 (for h = 0.5)

Let's calculate R(1,1):

[tex]R(1,1) = f'(1) + (f'(1) - f'(0.5))/((1/2)^1 - 1)\\ = -4.50557 + (-4.50557 - (-2.09702))/(2 - 1)\\ = -4.50557 + (-2.40855)/1\\ = -4.50557 - 2.40855\\ = -6.91412.[/tex]

Therefore, a better approximation of f'(0) using Richardson's extrapolation is -6.91412.

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One dimension, called "media richness," is used to classify social media and is shown on the x-axis of Figure 20-1. It ranges from "words" to "animation" and represents the level of interactivity and information.

In the context of social media, the concept of media richness refers to the degree of richness or complexity in the communication channel. It is a measure of the ability of a medium to convey information effectively, facilitate understanding, and support interaction between users.

Media richness is influenced by factors such as the presence of nonverbal cues, immediate feedback, personalization, and the capacity for multiple communication channels. Figure 20-1 likely represents a graphical representation or classification of social media based on their media richness.

The x-axis of the figure represents the continuum of media richness, ranging from "words" to "animation." At one end of the spectrum, "words" represent text-based communication platforms that primarily rely on written content. As we move towards the other end, "animation" represents media that incorporate rich visual and interactive elements such as videos, graphics, and multimedia features.

By placing different social media platforms along this dimension, Figure 20-1 provides a visual representation of their relative media richness levels. It helps in understanding the varying capabilities and characteristics of different social media platforms and their potential for communication, engagement, and information sharing.

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Let us check the given polynomials for point polynomial time as follows:

(a)  Justynach an! (points ==-+ 2022 in Riel) This polynomial is not in point polynomial time because there is no condition on the polynomial and points.

(b)  3 points / 20021011.101 +2022 in C[x] This polynomial is not in point polynomial time because the given points are not on the polynomial.

(c)  /= x+ 2022 in F7649[*] This polynomial is in point polynomial time because it is a monic polynomial and the given point is on the polynomial.

(d) pon-2 +3 This polynomial is not in point polynomial time because it is a constant polynomial and there are no points to verify.

(e)  [4 points] / -6° - 21x + 700 in Q[*] This polynomial is in point polynomial time because all the points are on the polynomial.

(f)  f = 625x3 - 6633r2 + 86- 8855 in Qlur. This polynomial is in point polynomial time because all the points are on the polynomial.

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(a)  Explanation:  In order to prove that X and Y are dependent random variables, we need to show that: pX,Y(x,y)≠pX(x)pY(y) when (x,y) ∈ T which means the joint probability of X and Y is not equal to the product of the marginal probability of X and Y.

For (x,y) ∈ T, pX,Y(x,y) = P (X=1, Y=y) = 1+y

But pX(x) = P(X=1) = Σ pX,Y(1, y) = Σ (1+y)

where the summation is taken over all y for which (1, y) ∈ T. For (1,1) ∈ T,

we get pX,Y(1,1) = 2 and pX(1) = Σ pX,Y(1,y) = 2 + 3 = 5. So, pX,Y(1,1) ≠ pX(1)pY(1) which implies that X and Y are dependent random variables.

(b) E[XY] = Σ Σ xy pX,Y(x,y) where the summation is taken over all x and y for which pX,Y(x,y) > 0.

Substituting the values, we get, E[XY] = Σ Σ xy (1+y) where the summation is taken over all (x,y) ∈ T.

So, E[XY] = (1+1) (1+1) + (1+2) (1+2) + (1+3) (1+3) = 2*2 + 3*4 + 4*6 = 2 + 12 + 24 = 38.

(c) Covariance of X and Y can be determined as follows: Cov(X,Y) = E(XY) - E(X)E(Y)Now, E(X) = Σ x pX(x) and E(Y) = Σ y pY(y)

Substituting the values, we get E(X) = 5/9 and E(Y) = 20/9

Therefore, Cov(X, Y) = E(XY) - E(X)E(Y) = 38 - (5/9) (20/9) = 38 - 100/81 = 998/81.

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Answer:

the answer. is 60 because you round of 64

Answer:

Ты русский? на этом сайте только американцы они тебе не помогут ни чем

Step-by-step explanation:

Answer:

x < -2 ?

Step-by-step explanation:

Answer:

C. 672

Step-by-step explanation:

Answer:

C) 672

Step-by-step explanation:

Answer:

how many brain cells do you have compared to the average person?

Step-by-step explanation: