Answer:
2.08 hpExplanation:
The power of the crane can be found by using the formula
[tex]p = \frac{f \times d}{t} \\ [/tex]
f is the Force
d is the distance
t is the time taken
From the question we have
[tex]p = \frac{2400 \times 10}{15} = \frac{24000}{15} \\ [/tex]
We have
power = 1600 W
But 1 W = 0.0013 hp
So 1600 = 2.08 hp
We have the final answer as
2.08 hpHope this helps you
Lucia kicks a ball on a level playing field with an initial velocity of 11.3 m/s at an angle of 35° above the horizontal. Find: Time of flight? Horizontal distance traveled? Maximum height?
Explanation:
Given that,
Initial velocity, u = 11.3 m/s
Angle above the horizontal, [tex]\theta=35^{\circ}[/tex]
Time of flight :
[tex]t=\dfrac{2u\sin\theta}{g}\\\\t=\dfrac{2\times 11.3\times \sin(35)}{9.8}\\\\t=1.32\ s[/tex]
Horizontal distance traveled is given by :
x = ut
x = 11.3 m/s × 1.32 s
x = 14.916 m
Maximum height is given by :
[tex]H=\dfrac{u^2\sin^2\theta}{2g}\\\\H=\dfrac{(11.3)^2\times \sin^2(35)}{2\times 9.8}\\\\H=2.14\ m[/tex]
Hence, time of flight is 1.32 s, horizontal distance is 14.916 m and maximum height is 2.14 m.
Part 2: Identify the independent, dependent, and constant variables
Experiment 1: A soap manufacturer runs an experiment to compare the foaming action of different dish detergents. Equal
amounts of each brand of detergent are placed in identical containers half-filled with water. The water and dish detergent are at
a temperature of 20°Celsius. Each container is agitated for 30 seconds, and then the height of the foam is measured.
a. independent variable:
b. dependent variable:
C. constant variable(s):
For a substance to change phases, the amount of Internal energy must change. Water exists in three phases: liquid, solid (ce), and gas (water vapor). Which of the following lists the
phases in order of increasing total energy?
O
gas, liquid, solid
solid, gas, liquid
solid, liquid, gas
oliquid, gas, solld
Which example illustrates Newton's second law?
A. A wheelbarrow remains stationary when no one pushes on it.
B. More mass is added to a wheelbarrow, and a larger force is
required to move it.
C. A person pushes a wheelbarrow, causing it to move forward.
D. The force of a wheelbarrow on the ground is equal to the force of
the ground on the wheelbarrow.
Answer:B
Explanation:
Mass
More mass is added to a wheelbarrow, and a larger force is required to move it - illustrates Newton's second law.
What is force?An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.
The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
Newton’s second law of motion states that “Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration."
Hence more mass is added to a wheelbarrow, and a larger force is required to accelerate, i.e., move it.
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Find the range of a projectile launched at an angle of 30° with an initial velocity of 20m/s.
Answer:
The range is 35.35 m
Explanation:
Projectile Motion
It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.
Being vo the initial speed of the object, θ the initial launch angle, and [tex]g=9.8m/s^2[/tex] the acceleration of gravity, then the maximum horizontal distance traveled by the object (also called Range) is:
[tex]\displaystyle d={\frac {v_o^{2}\sin(2\theta )}{g}}[/tex]
The projectile was launched at an angle of θ=30° with an initial speed vo=20 m/s. Calculating the range:
[tex]\displaystyle d={\frac {20^{2}\sin(2\cdot 30^\circ )}{9.8}}[/tex]
[tex]\displaystyle d={\frac {400\sin(60^\circ )}{9.8}}[/tex]
[tex]d=35.35\ m[/tex]
The range is 35.35 m
in a free body diagram the weight is
Answer:
Explanation:
a. WEIGHT: As we have seen, weight is the gravitational force exerted on an object by the Earth (or any other celestial body). If an object is near the Earth's surface and has mass, then the object has a weight. The magnitude of its weight is w = mg and its direction is toward the center of the Earth.
!!please help !!!!! I’ll give brainliest
Answer:
45 degrees
Explanation:
a projectile travels the farthest when it is launches at the angle of 45 degree.
describe where the information and communication technology can be used it different section?
guys help me i will make you brainliest <3
Answer:
See below
Explanation:
ICT " Information and the communication technology" can be used in sectors like Telecommunications. ADB support for telecommunications and ICT is changing lives across the region. ...
ICT in Education. ICT can improve the efficiency and quality of education at all levels. ...
ICT in Public Sector Management. ...
ICT in Health. ...
ICT in Agriculture and Food Security.
( hope it helped <3 )
The
of an object shows how fast the object is moving at a specific
Answer:
Speed is a description of how fast an object moves; velocity is how fast and in what direction it moves. In physics, velocity is speed in a given direction. When we say a car travels at 60 km/h, we are specifying its speed.
At a local swimming pool, the diving board is elevated h = 9.5 m above the pool's surface and overhangs the pool edge by L = 2 m. A diver runs horizontally along the diving board with a speed of v0 = 2.7 m/s and then falls into the pool. Neglect air resistance. Use a coordinate system with the horizontal x-axis pointing in the direction of the diver’s initial motion, and the vertical y-axis pointing up. Let the y-axis be directed vertically down. Express the time t_w it takes the diver to move off the end of the diving board to the pool surface in terms of v_0, h, L, and g. Calculate the time, t_w in seconds, it takes the diver to move off the end of the diving board to the pool surface. Determine the horizontal distance, d_w in meters, from the edge of the pool to where the diver enters the water.
Answer:
1) The time it takes the diver to move off the end of the diving board to the pool surface, [tex]t_w[/tex], is approximately 1.392 seconds
2) The horizontal distance from the edge of the pool to where the diver enters the water, [tex]d_w[/tex], is approximately 5.76 meters
Explanation:
1) The given parameters are;
The height of the diving board above the pool's surface, h = 9.5 m
The length by which the diving board over hangs the pool L = 2 m
The speed with which the diver runs horizontally along the diving board, v₀ = 2.7 m/s
Taking [tex]t_w[/tex] = The time it takes the diver to move off the end of the diving board to the pool surface
Therefore, we have from the equation of free fall;
h = 1/2 × g × [tex]t_w[/tex]²
Where;
g = The acceleration due to gravity = 9.81 m/s²
Substituting the values, gives;
9.5 = 1/2 × 9.81 × [tex]t_w[/tex]²
[tex]t_w[/tex] = √(9.5/(1/2 × 9.81)) ≈ 1.392 s
The time it takes the diver to move off the end of the diving board to the pool surface = [tex]t_w[/tex] ≈ 1.392 s
2) The horizontal distance, [tex]d_w[/tex], in meters from the edge of the pool to where the diver enters the water is given as follows;
[tex]d_w[/tex] = L + v₀ × [tex]t_w[/tex] = 2 + 2.7× 1.392 ≈ 5.76 m
∴ The horizontal distance from the edge of the pool to where the diver enters the water ≈ 5.76 meters.
What happens to the minerals as gneiss forms from schist?
Answer:
Explanation:
Gneiss is a high grade metamorphic rock, meaning that it has been subjected to higher temperatures and pressures than schist. However, unlike slate and schist, gneiss does not preferentially break along planes of foliation because less than 50% of the minerals formed during the metamorphism are aligned in thin layers.
A vector is expressed in polar notation as A⃗ = ( 35.0 N, 37 ∘) Calculate the components of the vector, and enter them (separated by a comma) in the answer box to express the vector in rectangular notation.
Answer:
A = (27.95 N, 21 N)
Explanation:
The polar co-ordinates are given as:
(r,θ) = (35 N, 37°)
Now, to convert this into polar co-ordinates (x, y), we will use following relations:
r² = x² + y²
(35)² = x² + y²
1225 = x² + y² ----------- equation (1)
and
tan θ = y/x
tan 37° = y/x
y = 0.753 x ------------------- equation (2)
Substituting this value in equation (1):
1225 = x² + (0.753 x)²
1225 = 1.567 x²
x² = 1225/1.567
x = √781.32
x = 27.95 N
using this value in equation (2)
y = (0.753)(27.95 N)
y = 21 N
Therefore, the vector can be represented in polar co-ordinates as:
A = (27.95 N, 21 N)
HELP! NEED THE ANSWER IN 6 MINS!!!!!!!!!!!!!!!
Answer:
C
Explanation:
Which option is the smallest particle that represents the compound carbon
dioxide?
A. A carbon dioxide molecule B. A carbon dioxide atom
C. A carbon atom and an oxygen atom
D. A carbon ion and an oxygen ion
HELPPPPP
PLEASE I NEED THIS ANSWER FASTTTT
Answer:The answer is A
Explanation: You can instantly eliminate b and d because an ion isn't mentioned, and it is impossible to have a carbon dioxide atom. C is incorrect because there has to be two oxygen's to create a carbon dioxide molecule.
Answer:
D. A carbon dioxide molecule
Explanation:
The force that causes an object to follow a
circular path is
tion:
at o
1. an inertiali force.
2. a centripetal force.
3. a gravitational force.
CI
nents
stant
4. a fluid force.
Answer:
2.a centripetal force.
Convert 318 meters per second to kilometers per hour
Answer:
1144.8
Explanation:
1 meter per second is equal to 3.6 kilometers per hour
An eagle is flying horizontally 16.4 meters above a lake at a speed of 9.3 m/s, carrying a small pumpkin in its talons. The pumpkin slips free. How far horizontally will the pumpkin travel after it slips from the eagle until it hits the ground?
Answer:
The horizontal distance the pumpkin will travel after it slips from the eagle is 17.02 m
Explanation:
Given;
height above the ground, h = 16.4 m
speed of the eagle, v = 9.3 m/s
The time it will take the pumpkin to fall at the given height is calculated as;
[tex]t = \sqrt{\frac{2h}{g} }\\\\t = \sqrt{\frac{2*16.4}{9.8} }\\\\t = 1.83 \ s[/tex]
The horizontal distance traveled at this time is given by;
x = vt
x = (9.3)(1.83)
x = 17.02 m
Therefore, the horizontal distance the pumpkin will travel after it slips from the eagle is 17.02 m
How is energy stored in food? Is the form of energy stored in food different from the form stored in gasoline? Explain.
Answer:
There are little tiny batteries that are contained within the molecules of the food. The sun charges these batteries, and when the food is eaten, the energy from the batteries flows through the acids in the stomach, which gives the person or animal energy. In gasoline, the energy is created when the gasoline is set on fire and burned, there is no energy within it already. So they are different forms of energy. Hope this helps!
You throw an orange out a window at a height of 12.00 meters
upwards at an angle of 32° to the horizontal at a velocity of 3.5
m/s. What is the maximum height that the orange will reach?
Answer:
12.18
Explanation:
The maximum height that the orange will reach is 12.18 m.
What is projectile?When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion.
You throw an orange out a window at a height of 12.00 meters upwards at an angle of 32° to the horizontal at a velocity of 3.5 m/s.
If u is the initial speed, the maximum height of the ball from the point of throwing is
H = u² sin²θ / 2g
Put the values, we get
H = 3.5² sin²32° / (2x9.81)
H = 0.1753 m
So, the maximum height calculated from the ground is
12 + 0.18 = 12.18 m
Thus ,the maximum height that the orange will reach is 12.18 m.
Learn more about projectile.
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A 7.40-kg object initially has 347 J of gravitational potential energy. Then an elevator lifts the object a distance of 20.6 m above its previous position. How much work did the elevator perform on the object?
Answer:
W = 1493.9 J = 1.49 KJ
Explanation:
The work done by the elevator on the object will be equal to the gain in is potential energy:
W = ΔP.E
W = mgΔh
where,
W = Work = ?
m = mass of object = 7.4 kg
g = 9.8 m/s²
Δh = gain in height = 20.6 m
Therefore,
W = (7.4 kg)(9.8 m/s²)(20.6 m)
W = 1493.9 J = 1.49 KJ
El cloro (Z igual a 17) es un elemento utilizado generalmente en la desinfección de piscinas en la naturaleza hay 2 isótopos del cloro: el Cl-35, con una abundancia del 75% y el Cl-37 con una abudancia del 25%. Determina : a)los protones y los neutrones que hay en el nucleo de cada uno de estos isotopos b) la masa atomica media del cloro expresada en u c) el numero de atomos de cloro que hay en 15g de cloro
Answer:
a) El número de neutrones de Cl-35 es 18 y del Cl-37 es 20.
b) La masa atómica media del cloro es 35.5 uma.
c) En 15 g de cloro hay 2.55x10²³ átomos.
Explanation:
a) Para calcular los protones y neutrones de los isótopos Cl-35 y Cl-37 debemos usar la siguiente fórmula:
[tex] A = Z + N [/tex]
En donde:
Z: es el número de protones = 17
N: es el número de neutrones
A: es la masa atómica
Los isótopos de un elemento dado tienen el mismo número de protones (número atómico) y en ellos sólo varia la la masa atómica (y por ende el número de neutrones); por lo que el Cl-35 y Cl-37 tienen igual Z (17).
Para el Cl-35 tenemos:
[tex] N = A - Z = 35 - 17 = 18 [/tex]
Y para el Cl-37 tenemos:
[tex]N = 37 - 17 = 20[/tex]
Por lo tanto, el número de neutrones de Cl-35 es 18 y del Cl-37 es 20.
b) La masa atómica media del cloro está dada por:
[tex]M_{Cl} = A_{Cl-35}*\%_{Cl-35} + A_{Cl-37}*\%_{Cl-37} = 35 u*\frac{75}{100} + 37 u*\frac{25}{100} = 35.5 u[/tex]
Entonces, la masa atómica media del cloro es 35.5 uma.
c) Para encontrar el número de átomos de Cl que hay en 15 g debemos usar el número de Avogadro (6.022x10²³ átomos/mol):
[tex] N = \frac{1 mol}{35.5 g}*15 g*\frac{6.022 \cdot 10^{23} atomos}{1 mol} = 2.55 \cdot 10^{23} atomos [/tex]
Finalmente, en 15 g de cloro hay 2.55x10²³ átomos.
Espero que te sea de utilidad!
PLEASE HELP ASAP...TIMED TEST. PLEASE ANSWER WITH AT LEAST A PARAGRAPH!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
A scientist wants to analyze signals from outer space. Her lab has sensors to detect sound waves, radio waves, and seismic waves. Which of these sensors will provide the best information? Explain your reasoning.
Answer: I am pretty sure that you should pick radio waves.
Explanation: The scientist should use radio waves. I think this because you can use the radio waves to analyze the signals from outer space. This will work much better than anything there, to analyze it the best possible.
The best I could do.
A positive ion is called a ____________ and a negative ion is called an
Answer:
Cation
Explanation:
Best way to remember this one is a CATion is PAWS-itive!
The U-tube contains a coloured liquid of density 9.6 x102 kg/m3. If the difference in height between the liquid levels in the two arms of the U-tube is 0.16m, calculate the excess pressure (above air pressure) in the cylinder. (Take g = 10 N/kg)
Explanation:
P = ρgh
P = (9.6×10² kg/m³) (10 N/kg) (0.16 m)
P = 1536 Pa
Rounded to two significant figures, the pressure is 1500 Pa, or 1.5 kPa.
Help on this pls. !!!!!
Answer:
C
Explanation:
Select the correct answer.
Which statement about pneumatic systems is true?
A.
Pneumatic systems generate greater force than hydraulic systems.
B.
Pneumatic systems are safe to use at any level of pressure.
C.
Pneumatic systems are more expensive than hydraulic systems.
D.
Pneumatic systems are cleaner than hydraulic systems.
Statement D about pneumatic systems is true. Pneumatic systems are cleaner than hydraulic systems.
What is the pneumatic system?Pneumatic systems are employed in a wide range of manufacturing and assembly applications. They can be used to transport objects on production lines as well as in maintenance facilities.
In hydraulic systems liquid is used as fluid for the force transmission. While in the pneumatic system air is used causing more cleanliness in the system.
The pneumatic systems are cleaner than hydraulic systems.
Hence, a statement D about pneumatic systems is true.
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What is electronegativity
A. An atoms ability to attract other electrons and form a chemical bond
Explanation:
Electronegativity is a measure of an atom's ability to attract shared electrons to itself. On the periodic table, electronegativity generally increases as you move from left to right across a period and decreases as you move down a group.
Answer:
A)
Explanation:
I took the test and got it right. Flvs
Which car is accelerating?
A) a car that is unmoving
B) a car that rounds a curve at a constant speed
C) a car travels in a straight line at a constant speed
D) a car is set to a constant speed of 60 miles per hour
Answer:
The car that is accelerating is B a car that rounds a curve at a constant speed
Explanation:
Although all of the cars are at a constant speed or not moving acceleration is the change in speed or the change of directions therefore making the only car changing directions your answer.
Answer:
its B (:
Explanation:
i took the test :)
A car of mass 1167 kg accelerates on a flat highway from 10 m/s to 28.0 m/s. How much work does the car's engine do on the car?
Answer:
Workdone = 465766038 Joules.
Explanation:
Given the following data;
Mass = 1167
Initial velocity = 10m/s
Final velocity =28m/s
To find the workdone;
We know that from the workdone theorem, the workdone by an object or a body is directly proportional to the kinetic energy possessed by the object due to its motion.
Mathematically, it is given by the equation;
W = Kf - Ki
W = ½MVf² - ½MVi²
Substituting into the equation
W = ½(1167)*28² - ½(1167)*10²
W = ½ * 1361889* 784 - ½ * 1361889 * 100
W = 533860488 - 68094450
Workdone = 465766038 Joules.
The planes LA534 and LA639 are coming in for a landing on the same runway which means they are each lowering their altitude. Note that LA534 is traveling at twice the speed of LA 639. What must they do to keep from crashing into each other on the runway
Answer:
plane LA534 will have to decrease it speed by twice that of plane LA639.
Explanation:
Since both planes want to land there must be a decrease in speed.
We are told that plane LA534 velocity is twice that of plane LA639.
Now for the two planes to land without a crash. the opposite or reverse will be the case in terms of deceleration, that is
Plane LA639 will have to decrease its speed by twice the decrease in speed of plane LA534