calculate the molar solubility of baso4 in a 0.250 m solution of nahso4? ka for hso4- = 1.2 x 10-2.

Answer:

See explanation below

Explanation:

1) Total Revenue:

Total revenue refers to the total amount of income that is generated when a company sells or offers their service.

It is usually calculated as the product of the product or services sold by the quantity.

It is calculated by ;

TR = Q * P

Where TR = Total Revenue

Q = Quantity

P = Price

2.) Average Revenue:

Average revenue is the revenue gotten by a company per unit of output sold. It is calculated by:

AR = TR / Q

Where AR = Average Revenue

TR = Total Revenue

Q. = Quantity

3.) Marginal Revenue:

This is the net revenue that is generated by selling an additional unit of commodity; which is the change in total revealer unit. It is calculated by:

MR = change in Total Revenue / change in Quantity

Where MR = Marginal Revenue

4.) Gross Profit:

Gross profit is the amount of revenue left after factoring out the cost of production and sales and servicing.

It is calculated by subtracting revenue from the cost of goods sold -

Gross Profit = Revenue - Cost of goods sold

Net Profit:

Net profit is the amount of money a company has left after subtracting all interests, tax expenses and cost.

It is calculated by;

Net Profit = Gross Profit - Expenses

CH4 + 2 O2 = CO2 + 2 H2O

i believe it's this :p

Answer:

Cinder cone

Explanation:

Answer:

[tex]\boxed {\boxed {\sf molarity = 0.17 \ M \ C_6H_12O_6}}[/tex]

Explanation:

Molarity is found by dividing the moles of solute by liters of solution.

[tex]molarity = \frac {moles}{liters}[/tex]

We are given grams of a compound and milliliters of solution, so we must make 2 conversions.

1. Gram to Moles

We must use the molar mass. First, use the Periodic Table to find the molar masses of the individual elements.

Next, look at the formula and note the subscripts. This tells us the number of atoms in 1 molecule. We multiply the molar mass of each element by its subscript.

6(12.011)+12(1.008)+6(15.999)=180.156 g/mol

Use this number as a ratio.

[tex]\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}[/tex]

Multiply by the given number of grams.

[tex]78 \ g \ C_6H_12O_6 *\frac {180.156 \ g\ C_6H_12 O_6}{ 1 \ mol \ C_6H_12O_6}[/tex]

Flip the fraction and divide.

[tex]78 \ g \ C_6H_12O_6 *\frac { 1 \ mol \ C_6H_12O_6}{180.156 \ g\ C_6H_12 O_6}[/tex]

[tex]\frac { 78 \ mol \ C_6H_12O_6}{180.156 }= 0.432958102977 \ mol \ C_6H_12O_6[/tex]

2. Milliliters to Liters

There are 1000 milliliters in 1 liter.

[tex]\frac {1 \ L }{ 1000 \ mL}[/tex]

Multiply by 2500 mL.

[tex]2500 \ mL* \frac {1 \ L }{ 1000 \ mL}[/tex]

[tex]2500 * \frac {1 \ L }{ 1000 }= 2.5 \ L[/tex]

3. Calculate Molarity

Finally, divide the moles by the liters.

[tex]molarity = \frac {0.432958102977 \ mol \ C_6H_12O_6}{ 2.5 \ L}[/tex]

[tex]molarity = 0.173183241191 \ mol \ C_6H_12O_6/L[/tex]

The original measurement has 2 significant figures, so our answer must have the same. That is the hundredth place and the 3 tells us to leave the 7.

[tex]molarity \approx 0.17 \ mol \ C_6H_12O_6 /L[/tex]

1 mole per liter is also equal to 1 M.

[tex]molarity = 0.17 \ M \ C_6H_12O_6[/tex]

Answer:

Gamma-rays are a form of electromagnetic radiation, as are radio waves, infrared radiation, ultraviolet radiation, X-rays and microwaves. Gamma-rays can be used to treat cancer, and gamma-ray bursts are studied by astronomers.

Explanation:

Hope this helped Mark BRAINLIEST!!!

Gamma Rays are ionizing Electromagnetic radiation, obtained by the decay of an atomic nucleus. Gamma rays are more penetrating, in matter, and can damage living cells to a great extent. Gamma rays are used in medicine (radiotherapy), industry ( Sterilization and disinfection) and the nuclear industry.

Molecular crystals are held together by the intermolecular forces of dispersion and dipole-dipole forces and by hydrogen bonding. The statement is True.

Molecular crystals are held together by the intermolecular forces of dispersion, dipole-dipole forces, and hydrogen bonding.

Dispersion forces are the weakest intermolecular forces and are present in all molecules. They are caused by the temporary uneven distribution of electrons in a molecule, which creates a temporary dipole.

The temporary dipole in one molecule can induce a dipole in another molecule, resulting in a weak attractive force.

Dipole-dipole forces are stronger than dispersion forces and are present in molecules that have a permanent dipole. The positive end of one dipole is attracted to the negative end of another dipole, resulting in a stronger attractive force.

Hydrogen bonding is the strongest intermolecular force and is present in molecules that contain a hydrogen atom bonded to a highly electronegative atom, such as oxygen, nitrogen, or fluorine.

The hydrogen atom is partially positive, while the electronegative atom is partially negative. This creates a strong attractive force between the hydrogen atom of one molecule and the electronegative atom of another molecule.

The type of intermolecular force that is most important in holding a molecular crystal together depends on the structure of the molecules in the crystal.

For example, a crystal of water is held together by hydrogen bonding, while a crystal of methane is held together by dispersion forces.

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The molarity of the 30% by mass hydrogen peroxide solution is 9.78 M, the mole fraction of H2O2 is 1.0, and the molar concentration is also 9.78 M.

To calculate the molarity, mole fraction, and molar concentration (molarity) of a 30% by mass hydrogen peroxide (H2O2) solution with a density of 1.11 g/ml, we need to follow these steps:

Step 1: Calculate the molarity (M):

The molarity is defined as the number of moles of solute per liter of solution. We need the molar mass of hydrogen peroxide to calculate the number of moles.

The molar mass of H2O2 = 2(1.01 g/mol) + 2(16.00 g/mol) = 34.02 g/mol

The mass of H2O2 in 100 g of the solution (30% by mass) = 30 g

Number of moles of H2O2 = mass / molar mass = 30 g / 34.02 g/mol = 0.882 mol

The volume of the solution can be calculated using the density:

Volume of solution = mass of solution / density = 100 g / 1.11 g/ml = 90.09 ml = 0.09009 L

Molarity (M) = moles / volume = 0.882 mol / 0.09009 L = 9.78 M

Step 2: Calculate the mole fraction (χ) of H2O2:

The mole fraction is the ratio of the moles of H2O2 to the total moles of all components in the solution.

Mole fraction (χ) = moles of H2O2 / total moles

Total moles = moles of H2O2 = 0.882 mol

Mole fraction (χ) = 0.882 mol / 0.882 mol = 1.0

Step 3: Calculate the molar concentration (molarity):

Molar concentration (molarity) is the number of moles of solute per liter of solution.

Molarity (M) = moles of H2O2 / volume of solution = 0.882 mol / 0.09009 L = 9.78 M

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Answer:  fuel and oxygen are reactants.

Explanation:

Answer:

fuel and oxygen

Explanation:

I take test

There are 356.2 mg of Cl in a 3.49 g sample of cleaning solution containing 21.5 wt% NaOCl (74.44 g/mol).

To calculate the milligrams of Cl (35.453 g/mol) in a 3.49 g sample of cleaning solution containing 21.5 wt% NaOCl (74.44 g/mol), first calculate the weight of NaOCl in the sample:3.49 g x 0.215 = 0.75 g NaOCl

Next, calculate the number of moles of NaOCl in the sample:0.75 g NaOCl ÷ 74.44 g/mol = 0.01006 mol NaOClSince NaOCl is the only source of Cl in the solution, this also represents the number of moles of Cl in the sample.

Finally, convert the number of moles of Cl to milligrams:0.01006 mol x 35.453 g/mol x 1000 mg/g = 356.2 mg Cl.

We have to calculate the milligrams of Cl in a cleaning solution sample.

The sample contains NaOCl, so we will first calculate the number of moles of NaOCl in the sample. This will also give us the number of moles of Cl in the sample because NaOCl is the only source of Cl in the solution.

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In the self-splicing of group 1 introns, the first transesterification reaction is initiated by the nucleophilic attack of the 3' hydroxyl group of the guanosine nucleotide within the intron on the 5' splice site.

This nucleophilic attack forms a 3' - 5' phosphodiester bond and releases the 5' exon. This process is facilitated by the catalytic properties of the intron RNA itself, without the involvement of any protein factors.

The self-splicing of group 1 introns involves two transesterification reactions that lead to the removal of the intron and the joining of the flanking exons.

The first transesterification reaction is the key step that initiates the splicing process. It is the attack of the guanosine nucleotide on the 5' splice site that triggers the subsequent splicing reactions.

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The type of radioactive decay that results in no change in mass number and atomic number for the starting nucleus is gamma decay. The correct answer is option D.

Gamma decay is a type of radioactive decay that involves the emission of gamma rays from an atomic nucleus. Gamma rays are high-energy photons that are emitted when the nucleus undergoes a transition from a higher energy state to a lower energy state. Gamma decay does not result in a change in the atomic number or mass number of the nucleus, as no particles are emitted from the nucleus. Instead, the nucleus simply releases energy in the form of a gamma ray. Therefore, option D) Gamma is the correct answer.

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Answer: I don’t know sorry

Explanation:

The  true statement is, the leaving group ability of the heteroatom group determines the reactivity towards nucleophilic acyl substitution.

Nucleophilic acyl substitution describes a class of substitution reactions involving nucleophiles and acyl compounds.

Also, nucleophilic acyl substitution is a type of substitution reaction involving an acyl group and a nucleophile.

Thus, the statement that is true regarding nucleophilic acyl substitution is, the leaving group ability of the heteroatom group determines the reactivity towards nucleophilic acyl substitution.

Thus, in nucleophilic acyl substitution, a nucleophile displaces the leaving group, resulting in a carbonyl compound.

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Hydrogen is the only exception, as it has only one valence electron.

The Lewis symbol for an atom includes its symbol and valence electrons represented as dots. The following are the Lewis symbols for neutral atoms with their electron dots and pairs of dots:- Hydrogen (H): 1 electron; Lewis symbol: H •- Helium (He): 2 electrons; Lewis symbol: He ••- Carbon (C): 4 electrons; Lewis symbol: C •• ••- Nitrogen (N): 5 electrons; Lewis symbol: N •• •• •••- Oxygen (O): 6 electrons; Lewis symbol: O •• •• ••••- Fluorine (F): 7 electrons; Lewis symbol: F •• •• ••• •••The number of valence electrons for each atom is determined by the group number on the periodic table. Hydrogen is the only exception, as it has only one valence electron.

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If this atom has one additional neutron but the other subatomic particles remained the same as shown, this slightly different atom would be called an isotope.

An isotope is a variant of an atom that has a different number of neutrons. Because isotopes of the same element have the same number of protons in the nucleus, they all have the same atomic number. However, they can differ in mass number, and therefore in atomic mass. In a neutral atom, the number of protons in the nucleus equals the number of electrons that orbit the nucleus, giving the atom a net electrical charge of zero.

However, the number of neutrons in the nucleus can differ, implying that isotopes of the same element may have different atomic masses.

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Answer: the density is 997 kg

Explanation:

Answer: The standard emf for each of the following reactions are:

1. 2.87V    2. 3.21V   3. -3.91V.

Explanation: The standard emf of the given reaction is given by the formula:EMF= E°(reduced) - E°(oxidized)

1. H2(g) + F2(g) → 2H+(aq) + 2F-(aq).The balanced equation is:H2(g) + F2(g) → 2H+(aq) + 2F-(aq)The standard reduction potentials are given by:E°(H+(aq)/H2(g)) = 0V and E°(F-(aq)/F2(g)) = +2.87V.The standard emf can be calculated using the given formula:EMF = E°(reduced) - E°(oxidized)= 2.87 - 0= 2.87V

2. Cu2+(aq) + Ca(s) → Cu(s) + Ca2+(aq).The balanced equation is:Cu2+(aq) + Ca(s) → Cu(s) + Ca2+(aq)The standard reduction potentials are given by:E°(Cu2+(aq)/Cu(s)) = 0.34V and E°(Ca2+(aq)/Ca(s)) = -2.87V.The standard emf can be calculated using the given formula:EMF = E°(reduced) - E°(oxidized)= 0.34 - (-2.87)= 3.21V

3. 2ClO-3(aq) + 10Br-(aq) + 12H+(aq) → Cl2(g) + 5Br2(l) + 6H2O(l)The balanced equation is:2ClO-3(aq) + 10Br-(aq) + 12H+(aq) → Cl2(g) + 5Br2(l) + 6H2O(l)The standard reduction potentials are given by:E°(Cl2(g)/2Cl-(aq)) = +1.36V and E°(Br2(l)/2Br-(aq)) = +1.09V.The standard emf can be calculated using the given formula:EMF = E°(reduced) - E°(oxidized)= 1.36 - (5*1.09)= -3.91V.

Hence,The standard emf for each of the following reactions are:1. 2.87V2. 3.21V3. -3.91V.

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Answer:

Explanation:

The first thing that you need to do here is to calculate the theoretical yield of the reaction, i.e. what you get if the reaction has a

100

%

yield.

The balanced chemical equation

N

2

(

g

)

+

3

H

2

(

g

)

→

2

NH

3

(

g

)

tells you that every

1

mole of nitrogen gas that takes part in the reaction will consume

3

moles of hydrogen gas and produce

1

mole of ammonia.

In your case, you know that

1

mole of nitrogen gas reacts with

1

mole of hydrogen gas. Since you don't have enough hydrogen gas to ensure that all the moles of nitrogen gas can react

what you need



3 moles H

2

>

what you have



1 mole H

2

you can say that hydrogen gas will act as a limiting reagent, i.e. it will be completely consumed before all the moles of nitrogen gas will get the chance to take part in the reaction.

So, the reaction will consume

1

mole of hydrogen gas and produce

1

mole H

2

⋅

2 moles NH

3

3

moles H

2

=

0.667 moles NH

3

at

100

%

yield. This represents the reaction's theoretical yield.

Now, you know that the reaction produced

0.50

moles of ammonia. This represents the reaction's actual yield.

In order to find the percent yield, you need to figure out how many moles of ammonia are actually produced for every

100

moles of ammonia that could theoretically be produced.

You know that

0.667

moles will produce

0.50

moles, so you can say that

100

moles NH

3

.

in theory

⋅

0.50 moles NH

3

.

actual

0.667

moles NH

3

.

in theory

=

75 moles NH

3

.

actual

Therefore, you can say that the reaction has a percent yield equal to

% yield = 75%

−−−−−−−−−−−−−

Consider if the reaction is conducted with 3 moles of hydrogen and 2 moles of nitrogen as it in the balanced reaction, and if only 4.1 g of ammonia is produced, then the percent yield will be 12%.

The ratio of  the actual yield to the theoretical yield multiplied by 100 is the percent yield. No simple reactions can achieve a 100 % yield.

As per the given reaction, 3 moles of hydrogen reacts with 2 moles of nitrogen and produce 2 moles of ammonia. Molar mass of ammonia is 17 g/mol. Thus, 2 moles are 34 g/mol.

Assume that if the theoretical yield is 34 g, then the percent yield for actual yield of  4.1 g is,

4.1 /34 ×100 = 12.1 %.

Now lets assume that only one mole of hydrogen is reacted here, number of moles of ammonia produced by one mole of hydrogen is :

=  1 mole × 2 mol / 3 moles

= 0.66 moles.

0.66 moles = 0.66 × 17 g/mol = 11.22 g.

For a theoretical yield of 11.22 g, the percent yield will be

= 4.1 /11.22

= 36.6 %.

Therefore, by assuming if 3 moles of hydrogen are reacted then percent yield will be 12% for 4.1 g of actual yield and 36 % if only one mole of hydrogen is reacted.

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Answer:

High pressure.

Explanation:

The weather should have clear skies, if it is a Large "L" it would be could be stormy.

Hope this helps! have a great day!

Answer:

ok i dont get your question fully but i'll answer

When copper sulfate is dissolved in water in a beaker, a bright blue liquid or solution is formed. If copper sulfate is added until no more will dissolve, a saturated solution is formed. And some blue crystals will remain at the bottom of the beaker due to crystallization reaction. It is the process by which a solid form, where the atoms or molecules are highly organized into a structure known as a crystal.

To calculate the number of grams of nickel (II) nitrate hexahydrate required, we need to use the formula:

moles = concentration (M) x volume (L)

First, let's convert the volume from milliliters (mL) to liters (L):

25 mL = 25/1000 L = 0.025 L

The molar mass of nickel (II) nitrate hexahydrate can be calculated as follows:

Nickel (Ni) atomic mass = 58.69 g/mol

Nitrogen (N) atomic mass = 14.01 g/mol

Oxygen (O) atomic mass = 16.00 g/mol

Molar mass of nickel (II) nitrate = (1 * Ni) + (2 * N) + (6 * O)

= (1 * 58.69) + (2 * 14.01) + (6 * 16.00)

= 58.69 + 28.02 + 96.00

= 182.71 g/mol

Now, we can calculate the number of moles:

moles = 0.034 M x 0.025 L

= 0.00085 moles

Finally, we can calculate the mass of nickel (II) nitrate hexahydrate:

mass = moles x molar mass

= 0.00085 moles x 182.71 g/mol

≈ 0.155 grams

Therefore, approximately 0.155 grams of nickel (II) nitrate hexahydrate are required to prepare a 25 mL solution with a concentration of 0.034 M.

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The solubility of compounds such as sucrose, histidine, gelatin, and vegetable oil is biologically relevant due to various reasons. Solubility affects nutrient absorption, cellular processes, transport and distribution of molecules, structural and functional roles of biomolecules, and biological interactions.

Solubility facilitates the digestion and absorption of nutrients, enables cellular reactions and enzymatic processes, influences nutrient transport and distribution within organisms, contributes to the structural and functional properties of biomolecules, and impacts molecular interactions within biological systems. Understanding the solubility of these compounds enhances our understanding of biological mechanisms and aids in the development of therapeutic and nutritional approaches.

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Answer:

It is an Ionic bond

The counter ion in the coordination compound [Co(NH3)4Cl2]NO3 is NO3-.

In a coordination compound, there is a central metal ion or atom that is surrounded by ligands. The ligands coordinate to the metal ion through donation of electron pairs. In this compound, the central metal ion is cobalt (Co), which is coordinated to four ammonia (NH3) ligands and two chloride (Cl) ligands.

The counter ion is the ion that balances the charge of the entire coordination compound. In this case, the coordination compound carries a net charge of 0 because the total charges of the ligands (4NH3 with no charge and 2Cl- with a -1 charge each) sum up to 0. Therefore, to balance the charge, a counter ion is required.

The counter ion in this compound is NO3-, which is a nitrate ion. The nitrate ion carries a -1 charge, which balances the overall charge of the coordination compound.

The counter ion in the coordination compound [Co(NH3)4Cl2]NO3 is NO3-. It serves to balance the charge of the coordination compound, which has a net charge of 0 due to the coordination of the ligands.

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Out of the given options, CH3COOH is the strongest acid.

The strength of an acid is determined by its ability to donate protons. The more the acid donates protons, the stronger it is.Acid strength increases with decreasing pKa value. The pKa value of CH3COOH is 4.76. The lower the pKa value, the stronger the acid. CH3OCH3 is a weakly acidic compound with a pKa value of 15.5, whereas CH3CH2OH is a slightly acidic compound with a pKa value of 16. CH3NHCH3 is a non-acidic compound because it lacks an acidic hydrogen atom. CH3CH=CH2 is an alkene and is not an acidic compound.To summarize, CH3COOH is the strongest acid among the given options with a pKa value of 4.76.

So, option c is the correct answer.

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For the following aqueous equilibria;

a. NH₃(aq) + H₂O(l) ⇌ NH₄⁺(aq) + OH⁻(aq)

The Brønsted-Lowry conjugate acid-base pairs in this equilibrium are:

NH₃ (conjugate base) and NH₄⁺ (conjugate acid)

H₂O (conjugate acid) and OH⁻ (conjugate base)

To determine the weaker side, compare the strengths of the conjugate acid-base pairs. In this case, NH₃ is a weaker base than H₂O, and NH4+ is a stronger acid than OH-. Therefore, the weaker side is the left side of the equation: NH₃(aq) + H₂O(l).

b. HCN(aq) + H₂O(l) ⇌ H₃O⁺(aq) + CN⁻(aq)

The Brønsted-Lowry conjugate acid-base pairs in this equilibrium are:

HCN (conjugate base) and H₃O⁺ (conjugate acid)

H₂O (conjugate acid) and CN⁻ (conjugate base)

To determine the weaker side, compare the strengths of the conjugate acid-base pairs. In this case, HCN is a weaker base than H₂O, and H₃O⁺ is a stronger acid than CN-. Therefore, the weaker side is the left side of the equation: HCN(aq) + H₂O(l).

c. NH₄⁺(aq) + CO₃²⁻(aq) ⇌ NH₃(aq) + HCO₃⁻(aq)

The Brønsted-Lowry conjugate acid-base pairs in this equilibrium are:

NH₄⁺ (conjugate acid) and NH₃ (conjugate base)

CO₃²⁻ (conjugate base) and HCO₃⁻ (conjugate acid)

To determine the weaker side, compare the strengths of the conjugate acid-base pairs. In this case, NH₃ is a weaker base than NH₄⁺, and HCO₃⁻ is a stronger acid than CO₃²⁻. Therefore, the weaker side is the right side of the equation: NH₃(aq) + HCO₃⁻(aq).

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Answer:

C. one star

Explanation:

Of course our solar system has one unique star which is the sun while others have atleast two which are called binary solar

Answer:

There are needed 375mL of the 2.0M BaCl₂ solution completing to 500mL with water.

Explanation:

We can find with the volume and concentration of the barium chloride the moles of BaCl₂ required. With the moles and the concentration of our stock solution we can know the volume of the 2.0M BaCl₂ solution required as follows:

Moles required:

0.500L * (1.50mol / L) = 0.750 moles BaCl₂

Volume stock solution:

0.750 moles BaCl₂ * (1L / 2.0mol) = 0.375L

Answer:

What is this?

Explanation: