Calculate the energy used by a radio of power 30W in 1 minute.

Answers

Answer 1

Answer:

1.8kJ

Explanation:

Formula :

Energy used = Power x time

===============================================================

Given :

⇒ Power = 30 W

⇒ Time = 1 minute = 60 seconds

=============================================================

Solving :

⇒ Energy used = 30 W × 60 s

⇒ Energy used = 1,800 J

⇒ Energy used = 1.8kJ

Answer 2

Answer:

1800 joule (1.8kJ)

Explanation:

Formula:

Power = Work / Time

30 = Work / 60

Work = 1800 joule

Work = 1.8kJ

Energy = Work done = 1.8kJ

Hence, Energy used is 1.8kJ.


Related Questions

Question 7 of 10
which type of insurance policy covers liability that exceeds the coverage of a
regular insurance policy?
o a. health insurance
o b. disability insurance

Answers

Answer: it’s actually umbrella

Explanation: because

Norma kicks a soccer ball with an initial velocity of 10.0 meters per second at an angle of 30.0°.

If the ball moves through the air for 3.2 seconds, what is the horizontal distance traveled by the ball? Round your answer to the nearest tenth.

Answers

Answer: 30

Explanation:

How are distance and displacement related?​

Answers

Answer: They both give us a notion about the position of an object

Explanation:

When the defibrillator is in use, a potential difference of 4800 V is applied across the
person's chest.
A charge of 0.16 coulombs passes through the person's chest in 4.0 ms
Calculate the resistance of the person's chest.

Answers

If a defibrillator is in use with the given potential difference and charge in the given time, the resistance of the person's chest is 120 Ohms.

What is the resistance of the person's chest?

From Ohm’s law;

V = I × R

Where V is the voltage or potential difference, potential difference, I is the current and R is the resistance.

Given that;

Potential difference v = 4800VCharge Q = 0.16CTime elapsed t = 4.0ms = ( 4/1000 )s = 0.004sResistance R = ?

First, we calculate the current I.

Since current is the electric charge transferred per unit time.

I = Q/t

I = 0.16C / 0.004s

I = 40A

Now, the resistance of the person's chest will be;

V = I × R

R = V / I

R = 4800V / 40A

R = 120Ω

Therefore, If a defibrillator is in use with the given potential difference and charge in the given time, the resistance of the person's chest is 120 Ohms.

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If the _ of the proteins changes, this is called a mutation

Answers

Answer:

If the DNA of the proteins changes, this is called a mutation.

Explanation: Hope it helps you :))))

Have a good day

Please select the word from the list that best fits the definition
the resistance of an object to moving or to stopping
a. gravity
b. inertia
c. gravitational force

Answers

Answer:

inertia

Explanation:

the resistance of an object to moving or to stopping

a. gravity

b. inertia

c. gravitational force

Why is a Magnetar extremely magnetic?

Answers

Answer:

The dominant theory of the strong fields of magnetars is that it results from a magnetohydrodynamic dynamo process in the turbulent, extremely dense conducting fluid that exists before the neutron star settles into its equilibrium configuration.

How strong is a magnetar magnetic field?

It can generate the most intense magnetic field observed in the Universe. The field strength of a magnetar is one thousand trillion times stronger than Earth's and is so intense that it heats the surface to 18 million degrees Fahrenheit. We only know of about 10 magnetars in the Milky Way galaxy.

There are uniform cubes in a toy box, a child makes a pillar using these cubes on a rough plane which is inclined to the horizontal at angle theta. The cubes do not slide on each other. If tan theta = 1/8, the max no. of cubes that can be stacked is,
A. 4
B. 5
C. 8
D. 16

Please explain the methods of obtaining the ans . Will mark the brainliest for the best ans

Answers

The maximum number of cubes that can be stacked on the inclined plane without sliding is determined as 8.

Net force on the box

The net force on the box can be used to determine the maximum number of cubes that can be stacked without sliding.

The stack cubes must be at equilibrium.

∑Fx = 0

nW - μFₙ = 0

where;

n is number of the cubesFₙ is the normal force of the cubesW is the weight of the cubes acting parallel to the plane

n(mg)sinθ - μmgcosθ = 0

n(mg)sinθ  = μmgcosθ

nsinθ  = μcosθ

let the coefficient of friction = 1

nsinθ  = cosθ

n = cosθ/sinθ

n = 1/tanθ

n = (1)/(1/8)

n = 8

Thus, the maximum number of cubes that can be stacked on the inclined plane without sliding is determined as 8.

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the yacht shown below has a mass of 8300kg. determine its weight in air [ Acceleration due to gravity, g = 10 N kg¹
[tex]w = mg [/tex]

Answers

Answer:

83000kg

Explanation:

mass=8300kg

g=10

w=mg

8300×10=83000kg

The water in this pot is in the process of changing from a liquid to a gas. Thermal energy is still being added to the water as it vaporizes, but its temperature and the motion of its particles are not increasing. What do you think is happening to the extra energy?

Answers

The extra energy allows the molecules to convert states of molecules.

What is heating?

When the temperature is increased , the body or particle is said to be heating.

The water in this pot is in the process of changing from a liquid to a gas. Thermal energy is still being added to the water as it vaporizes, but its temperature and the motion of its particles are not increasing.

When the liquid is converted to gas, the temperature reaches the boiling point of water. After boiling, the heat added up will only make the particles to convert its phase and go away in then atmosphere.

Thus, extra energy added helps molecules of water to change its state from liquid to solid.

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The next closest star to Earth, Proxima Centuri, is 4.25 lightyears away. How far is that in meters?

Answers

Answer:

4.0208 x 10^16 meters

Explanation:

speed of light in m/s   *      # seconds in a year      * 4.25 years =

2.99792 x 10^8   *        3600*24*365.25  *     4.25 = 4.0208 x 10^16 m

Click this link to view O*NET’s Work Styles section for Postal Service Mail Carriers. (Common work styles are listed near the top and less-common work styles are near the bottom.) According to O*NET, which common work styles do Postal Service Mail Carriers need? Select four options.

dependability
creativity
leadership
integrity
self-control
attention to detail

Answers

The common work styles do Postal Service Mail Carriers need creativity, integrity, self-control and attention to detail.


What is postal mail service carriers?

They commonly sort mail and orchestrate it arranged by their conveyance course. They convey the mail by walking or any vehicle. They also gather mail and convey it to the post office. Mail transporters answer clients inquiries, provide forms, and look out for surprising conditions on their course.

Thus, the common workstyles they should need to have are creativity, integrity, self-control and attention to detail.

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Answer:

1456

Explanation:

This diagram shows half of the magnetic field of a bar magnet. Carefully draw in the other
half of the field.
Which way does the magnetic field go? Tick the correct box.
From the north pole to the south pole of the magnet. From the south pole to the north pole of the magnet..

Answers

Answer:

Explanation:

A bungee jumper jumps off a bridge and bounces up and down several times.
She finally comes to rest 16 m below the bridge from which she just jumped.
If her mass is 50 kg and the spring constant of the bungee cord is 35 N/m,
how much energy was lost due to air resistance while she was bouncing?
(Recall that g = 9.8 m/s²)
OA. 5420 N
OB. 3360 N
OC. 4280 N
O D. 6550 N

Answers

The energy that was lost due to air resistance while she was bouncing is determined as 3,360 J.

Conservation of energy

The amount of energy lost due to  air resistance while she was bouncing is determined from the principle of conservation of energy.

ΔE = P.E - Ux

ΔE = mgh - ¹/₂kx²

ΔE = (50)(9.8)(16) - ¹/₂(35)(16)²

ΔE = 3,360 J

Thus, the energy that was lost due to air resistance while she was bouncing is determined as 3,360 J.

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Read the scenario below and answer the question that follows.

Jean has been increasingly hyperactive, staying up all night, and finishing her work assignments in record time during the past few weeks. She feels it is a big improvement from how she felt before, when she was worried about losing her job, had trouble concentrating, and felt extremely irritable.

Jean is most likely suffering from __________ disorder.
A.
major depressive
B.
bipolar
C.
phobic
D.
generalized anxiety

Answers

the answer you are looking for is D most of those are signs of anxiety

1. Find the force if the mass is 6 kg and the acceleration is 12 m/s/s ​

Answers

Answer:

The answer to the question is 72N

The formular for calculating force is;

Force = Mass× acceleration due to gravity

therefore 6kg×12m/s/s = 72N

If a rock is thrown downward with an initial speed 6ms then what is the rocks velocity after 4 sec

Answers

Answer:

[tex]\huge\boxed{\sf V_f=45.2 \ m/s}[/tex]

Explanation:

Given Data:

Initial velocity = [tex]V_i[/tex] = 6 m/s

Time = t = 4 sec

Acceleration due to gravity = g = 9.8 m/s²

Required:

Final velocity = [tex]V_f[/tex] = ?

Formula:

[tex]v_f=v_i+gt[/tex]

Solution:

Put the givens in the formula

[tex]V_f=6 +(9.8)(4)\\\\V_f=6+39.2\\\\V_f=45.2 \ m/s\\\\\rule[225]{225}{2}[/tex]

A woman launches a boat from one shore of a straight river and wants to land at the point directly on the opposite shore. If the speed of the boat is 10 mph and the river is flowing east at 5mph, in what direction should she head the boat in order to arrive at the desired landing point

Answers

Answer:

If she stands on the North side of a river flowing to the East at 5 mph,

she must head towards the SouthWest to arrive on the South side of the river directly across from her starting point and we have

x^2 + 5^2 = 10^2 where x is her speed directly across the river

x = (75)^1/2 = 8.66 mph towards the South

sin theta = 5 / 10 = 1/2

She must angle the boat at 30 deg from straight South

HURRY A spring with a spring constant of 350 N/m pulls a door closed. How much work is done as the spring pulls the door at a constant velocity from an 85.0-cam stretch to a 5.0-cm stretch?

Answers

In stretching or compressing the spring by a distance of x (in meters), one performs 1/2 (350 N/m) x² of work on the spring, or equivalently the spring performs -1/2 (350 N/m) x² of work on the door. This work is negative since the restoring force of the spring opposes the force used to stretch or compress the spring.

Then when the spring is allowed to relax, it performs 1/2 (350 N/m) x² of work to return it to equilibrium position. The force from the spring acts in the direction of the door's motion, so the work done is positive once more.

Now, the work done on the door …

• … to return it from 85.0 cm = 0.850 m to equilibrium is

1/2 (350 N/m) (0.850 m)² = 126.4375 J

• … to return it from 5.0 cm = 0.050 m to equilibrium is

1/2 (350 N/m) (0.050 m)² = 0.4375 J

• … to relax from 85.0 cm to 5.0 cm from equilibrium is

126.4375 J - 0.4375 J = 126 J

Suppose a 2662 kg giant seal is placed on a scale and produces a 20.0 cm compres- sion. If the seal and spring system are set into simple harmonic motion, what is the period of the oscillations

Answers

Answer:

  0.8976 seconds

Explanation:

The period of oscillation for the simple harmonic motion can be found using the formula ...

  T = 2π√(d/g)

where d is the displacement of the spring due to the attached weight, and g is the acceleration due to gravity.

__

For d = 0.20 meters, the period is ...

  T = 2π√(0.20/9.8) ≈ 0.8976 . . . . seconds

_____

Additional comment

The formula for the oscillator period is usually seen as ...

  T = 2π√(m/k)

where m is the mass in the system and k is the spring constant. The value of the spring constant is calculated from ...

  k = mg/d

Using that in the formula, we find it simplifies to ...

  [tex]T=2\pi\sqrt{\dfrac{m}{k}}=2\pi\sqrt{\dfrac{m}{\left(\dfrac{mg}{d}\right)}}=2\pi\sqrt{\dfrac{d}{g}}[/tex]

The 85-lb force P is applied to the 200-lb crate, which is stationary before the force is applied. Determine the magnitude and direction of the friction force F exerted by the horizontal surface on the crate.

Answers

The direction of the friction force F exerted by the horizontal surface on the crate will be in the left direction.

How to depict the force?

From the information given, the 85-lb force P is applied to the 200-lb crate, which is stationary before the force is applied.

mg = 200 ×  0.2248 × 9.8 = 440.608

The static friction force will be:

= 0.5 × 440.608

= 220.304N

Therefore, the static friction is greater than the force applied. Therefore, there'll be a static friction acting on the box on the left direction.

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8. A round tube weighs 30 kg. If the tube is stood on end, it pushes down on the floor with a pressure of 20 N/m². How many square inches is the end of the tube​

Answers

Answer:

22785 square inches

Explanation:

As the mass of the tube is 30kg, therefore it is exerting a force of 30g N(30g = 30 × 9.8 = 294)So the force is 294 N.Pressure is 20 N/m², as given.As we know Pressure is equal to the force exerted per unit area (P=F/A).Therefore, A=F/P

        A = 294 ÷ 20 = 14.7 m²

As 1 m² = 1550 square inches. Therefore, 14.7 m² = 14.7 × 1550 square inches = 22785 square inches

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Every summer I drive to Pennsylvania. It is 895 km to get there. If I average 100 km/hr, how much time will I spend driving?

Answers

Answer the time you bee spending driving iss 795 because 895-795=100

Explanation:

A car started its journey at point A. After 30 seconds, the car had reached point B. The car stops at point B for 10 seconds. Then, the car turned around and arrived at point A after 15 seconds. The car stopped at point A for 20 seconds. The car then went on his way and get to the point C after 10 seconds. Find the velocity from 30 to 40s

Answers

Since the displacement is equal to zero, the velocity from 30 to 40s will also be zero.

Velocity

Velocity is the distance travelled by a body in a specific direction per time taken. It is measured in meter per second. That is, m/s

Given that a car started its journey at point A. After 30 seconds, the car had reached point B. The car stops at point B for 10 seconds. Then, the car turned around and arrived at point A after 15 seconds. The car stopped at point A for 20 seconds. The car then went on his way and get to the point C after 10 seconds.

To find the velocity from 30 to 40s, we must realize that velocity can also be defined as;

Velocity = displacement / time

The displacement from point A to B and back to A is equal to zero.

Therefore, The velocity from 30 to 40s is also zero.

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If a 0.08 kg cell phone falls off a table at 15 m/s, then what is its kinetic energy right before it hits the ground?

Answers

The kinetic energy of the phone right before it hits the ground is 9J.

Kinetic energy of the phone

The kinetic energy of the phone right before it hits the ground is calculated as follows;

K.E = ¹/₂mv²

where;

m is mass of the phonev is velocity of the phone

K.E = ¹/₂(0.08)(15)²

K.E = 9 J

Thus, the kinetic energy of the phone right before it hits the ground is 9J.

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Determine the force p required to (a) raise and (b) lower the 40-kg cylinder at a slow, steady speed. the coefficient of friction between the cord and its supporting surface is 0.30.

Answers

Answer:

T - M g - Ff = M a     describes the acceleration of the object

T = M g + Ff      if the object moves at constant speed  (a = zero)

Ff = μ M g = .3 * 40 * 9.8 = 118 N     the force of friction

Ff will be in a direction opposite to the motion

M g = 40 kg * 9.8 m/s = 392 N

a) T = M g + Ff   for an object moving upwards

T = 392 + 118 = 510 N

b) T = M g - Ff     for an object moving downwards

T = 392 - 118 = 274 N

Which best explains why the receiver of a signal must understand the code or language being used

Answers

The receiver of a signal must understand the code or language being used to avoid confusion and losses.

What is a Signal?

This is usually in the form of a sound or body movement and is involved in conveying messages to people.

The receiver must understand the code or language in order to prevent confusion or loss of lives and properties.

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When the switch is closed electrons will flow from.

Answers

The statement is true, when the switch is closed electrons will flow.

What is current?

Current can be defined as the rate of flow of charges or electrons in a given circuit.

Q = It

I = Q/t

where

Q is charget is timeI is currentWhat is a Closed circuit?

A closed circuit is a type of circuit in which the wire connection of the circuit is complete and in which current flows.

Switch can be used close or open a circuit.

Thus, the statement is true, when the switch is closed electrons will flow.

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A scientist claims that a certain type of fabric is better able to repel water than another. Which option describes an experiment that will produce evidence that will support or refute her claim?
A. Test groups of each kind of fabric by exposing them to the same amount of water for the same amount of time.
B. Test groups of each kind of fabric by exposing them to the same amount of water for different amounts of time?
C. Test a group of one kind of fabric by spraying water on it, and a group of the other fabric by submerging it.
D. Test a group of one fabric by spraying it with distilled water, and a group of the other fabric by spraying it with salt water.

Answers

The best way would be to test groups of each kind of fabric by exposing them to the same amount of water for the same amount of time. The correct option is A.

Scientific experiments

In conducting scientific experiments to compare test subjects such as the fabrics mentioned in the illustration, the test subjects must be subjected to the same conditions.

The outcome of the experiment will no longer be scientifically valid if the test subjects are not exposed to the same condition.

Thus, the two fabrics must be exposed to the same amount of water for the same amount of time in order to come to a valid conclusion about which is a better water repeller among the two.

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Does paint and cardboard have joints in it

Answers

Noooo it doesn’t because it’s not apart of the body
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