Assume that the amounts of weight that male college students gain during their freshman year are normally distributed with a mean of μ = 1.1 kg and a standard deviation of o= 4.6 kg.
Complete parts (a) through (c) below.

b. If 25 male college students are randomly selected, find the probability that their mean weight gain during freshman year is between 0 kg and 3 kg.
The probability is
(Round to four decimal places as needed.)

Answer:

Median: 5.5

Mean: 5.1

The gradient will only be equal to 3 if the value of d is 7.

If we have two points (a, b) and (c, d), the gradient of the segment with these endpoints is:

G = (d - b)/(c - a)

Here the endpoints are (5, 9) and (d, 15), and the gradient is 3, so we can write the equation:

3 = (15 - 9)/(d - 5)

3*(d - 5) = 6

3d - 15 = 6

3d = 15 + 6 = 21

d = 21/3

d = 7

The value of d is 7.

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If one card is drawn randomly from a deck, then the probability that it is not a face card is 76.9%

Probability

Probability refers the possible way of getting the required event.

Given,

A standard deck of cards has 52 cards of four different suits (diamonds, spades, hearts, clubs). Each suit consists of numbered cards 1 (Ace) to 10, followed by Jack, Queen and King (face cards).

Here we need to find the probability of getting not a face card and we have to round off the resulting value to the tenth percent.

We know that,

Total number of cards = 52

Number of suits = 4

Number of cards in each suit = 13

Number of face cards in each suit = 3

Therefore, the total number of face cards in the deck is calculated s,

=> 3 x 4

=> 12

Therefore, the probability of getting not a face card is

=> (52 - 12)/52

=> 40/52

When we simplify this one then we get,

=> 0.7692

When we convert this into percent and round of to the nearest tenth then we get the probability of getting not a face card is

=> 76.9%.

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Between the previous balance method and the daily balance method, the method of calculating Yvonne's June finance charge that will result in a greater finance charge is:

Using the previous balance method to compute the finance charge, the beginning balance is added to purchases minus payments.  Then the APR is applied to the sum.

The daily balance method ensures that an average daily balance is computed for the billing cycle and then the APR is applied to the average to compute the finance charge.

Date   Transaction             Amount ($)   Balance     Daily Balance

6/1      Beginning balance    925.43      $925.43  $5,552.58 ($925.43 x 6)

6/7     Payment                       62.74      $862.69     3,450.76 ($862.69 x 4)

6/11    Purchase                      28.27      $890.96     8,909.60 ($890.96 x 10)

6/21   Purchase                      50.00      $940.96    9,409.60 ($940.96 x 10)

Total                                                        $27,322.54

Average daily balance = $910.75 ($27,322.54)

APR = 17.79%

MPR = 1.4825% (17.79%/12)

Previous balance method = $13.95 ($940.96 x 1.4825%)

Average daily balance = $13.50 ($910.75 x 1.4825%)

Difference = $0.45 ($13.95 - $13.50)

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The following table details her credit card transactions in the month of June.

Date   Transaction             Amount ($)

6/1      Beginning balance    925.43

6/7     Payment                       62.74

6/11    Purchase                      28.27

6/21   Purchase                      50.00

Between the previous balance method and the daily balance method, which method of calculating Yvonne's June finance charge will result in a greater finance charge, and how much greater will it be?

a. The daily balance method will have a finance charge $0.21 greater than the previous balance method.

b. The daily balance method will have a finance charge $0.53 greater than the previous balance method.

c. The previous balance method will have a finance charge $0.45 greater than the daily balance method.

d. The previous balance method will have a finance charge $0.40 greater than the daily balance method.

[tex] \bold{1: 3a + 2a \: = 5a}[/tex]

[tex]\bold{2: - 5b - 7b = - 12b}[/tex]

[tex]\bold{3: - a {}^{2} - 9 a{}^{2} = - 10a {}^{2}}[/tex]

[tex]\bold{4: 3a {}^{x - 2} + 5a {}^{x - 2} = 8a {}^{x - 2}}[/tex]

[tex] \bold{5: 18x - 11x = 7x}[/tex]

[tex]\bold{6: 5a - 8a + a - 6a + 21a = 13}[/tex]

The reduction of similar terms is an operation that aims to convert two or more similar terms into a single term.

In these cases you must add or subtract either addition, subtraction or subtraction and addition, using the law of signs.

[tex]\begin{gathered} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: {\bold{Law \: of \: signs: }} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: + \times + = + \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - \times + = - \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: + \times - = - \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: - \times - = + \end{gathered} [/tex]

The shape of the sampling distribution of the daily proportions of overripe oranges is approximately normal.

The correct answer option is option C

Sampling distribution refers to a probability distribution in which samples are drawn from a population which is taken from a larger population.

Types of sampling

Shapes of sampling distribution:

Number of oranges Toni's restaurant receives everyday = 200

Population of overripe oranges = approximately 11%

Therefore, it the supplier's claim is true of overripe oranges is true, shape of the sampling distribution is approximately normal.

Complete question:

Toni runs a restaurant that receives a shipment of 200 oranges every day. According to the supplier, approximately 11% of the population of these oranges is overripe. Suppose that Toni calculates the daily proportion of overripe oranges in her sample of 200. We can assume the supplier's claim is true, and that the oranges each day represent a random sample. What will be the shape of the sampling distribution of the daily proportions of overripe oranges?

Choose 1 answer:

Skewed to the left

Skewed to the right

Approximately normal

Uniform

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Answer:

0.000348 (rounded)

Step-by-step explanation:

Please tell me if this is wrong.

Answer: 250000

Step-by-step explanation:

multiple 10 4 times then multiply 25 at the end

Answer:

ubtract

36

from both sides of the equation.

x

2

+

14

x

=

−

36

To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of

b

.

(

b

2

)

2

=

(

7

)

2

Add the term to each side of the equation.

x

2

+

14

x

+

(

7

)

2

=

−

36

+

(

7

)

2

Simplify the equation.

Tap for more steps...

x

2

+

14

x

+

49

=

13

Factor the perfect trinomial square into

(

x

+

7

)

2

.

(

x

+

7

)

2

=

13

Solve the equation for

x

.

Tap for more steps...

x

=

±

√

13

−

7

The result can be shown in multiple forms.

Exact Form:

x

=

±

√

13

−

7

Decimal Form:

x

=

−

3.39444872

…

,

−

10.60555127

…

Step-by-step explanation:

Answer:

Generally, more selective schools may require or recommend a writing score, while less selective ones may not (though there certainly are exceptions). It's worth noting that most schools no longer require the ACT with Writing, though many schools recommend it.

Step-by-step explanation:

To find the distance between the points shown we subtract each point and the x-axis

Distance between two points is the length of the line segment that connects the two points in a plane. The formula to find the distance between the two points is usually given by d=√((x2– x1)² + (y2 – y1)²). This formula is used to find the distance between any two points on a coordinate plane or x-y plane.

Since the two points are on the same coordinate on the x -axis

To find the distance between the two points we subtract the y coordinates of the two points and the x axis.

In conclusion the distance between the two points is found by subtracting the two points and the x -axis

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Answer:

----------------------------------

Answer:

$1580.69

Step-by-step explanation:

Monthly Payment Formula

[tex]\sf PMT=\dfrac{Pi\left(1+i\right)^n}{\left(1+i\right)^n-1}[/tex]

where:

Given:

Substitute the values into the formula to calculate the monthly payment:

[tex]\implies \sf PMT=\dfrac{12000(0.00415)\left(1+0.00415\right)^{60}}{\left(1+0.00415\right)^{60}-1}[/tex]

[tex]\implies \sf PMT=\dfrac{49.8\left(1.00415\right)^{60}}{\left(1.00415\right)^{60}-1}[/tex]

[tex]\implies \sf PMT=\dfrac{63.84764727}{0.2820812705}[/tex]

[tex]\implies \sf PMT=226.3448656[/tex]

Therefore, the total payments over the life of the loan is the monthly payment multiplied by the total number of months:

[tex]\implies \sf 226.3448656 \times 60=\$13580.69[/tex]

To calculate how much interest Jessie pays over the life of the loan, subtract the original loan amount from the total payments amount:

[tex]\implies 13580.69-12000=\$1580.69[/tex]

Therefore, the interest Jessie will pay over the life of the loan is $1580.69.

According to the given depression angle, ship is 4.4 miles apart from ship B.

Depression angle:

Depression angle refer an angle that is formed with the horizontal line if the line of sight is downward from the horizontal line.

Given,

A pilot is flying over the ocean. She determines that the angles of depression to two ships are 74° and 48°, as shown in the figure below. The plane is 5 miles from the ship located at point A.

Here we need to find the distance between the two ships.

Here we know the following,

Distance between plane and Ship A = 5 miles.

And the depression angle = 74°, 48°

Let us consider the following, that they sit on a line,

So under this situations,

=> 80 - 48 - 74 = 58 degrees.

The next thing we have to do is bring this 74 degree angle inside the diagram. Because it is congruent to this interior angle because they are alternate.

Then it can be written as,

=> x = sin 74°/5

=> x = 4.4

Therefore, the two ships are 4.4 miles apart from each other.

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The Linear inequality holds true for 21 ≥ x;

What is Linear Inequality?

The mathematical expression with unequal sides is known as inequality in mathematics. Inequality is referred to in mathematics when a relationship results in a non-equal comparison between two expressions or two numbers. In this instance, any of the inequality symbols, such as greater than symbol (>), less than symbol (), greater than or equal to a symbol (), less than or equal to a symbol (), or not equal to a symbol (), is used in place of the equal sign "=" in the expression. Polynomial inequality, rational inequality, and absolute value inequality are the various types of inequalities that can exist in mathematics. The symbols "" and ">" signify tight inequalities, while "" and "" signify slack inequalities.

In the given question, the given inequality given is:

-3(2x-11) ≥ 8x-9;

Solving the Inequality:

⇒-6x + 33 ≥ 8x - 9;

⇒33 + 9 ≥ 8x - 6x;

⇒ 42 ≥ 2x;

⇒ 21 ≥ x;

Hence,

The Linear inequality holds true for 21 ≥ x;

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1. The unpaid balance after 12 months of paying $546.61 for borrowing $81,000 for 27 years at 6.8% is $79,915.29.

2. During this period, the interest she paid was $5,474.61.

The total payment made, including interest and principal, for 12 months is the product of the monthly payments and 12 months.

From the amortization schedule from an online finance calculator at month 12, we can deduce that the loan balance is $79,915.29.

When this balance is subtracted from the loan, the difference is the principal repayment so far.

N (# of periods) = 324 months (27 years x 12)

I/Y (Interest per year) = 6.8%

PV (Present Value) = $81,000

PMT (Periodic Payment) = $-546.61

Results:

Sum of all periodic payments = $-6,559.32 ($546.61 x 12)

Total Interest for six months = $5,474.61

1 $81,000.00 $-546.61 $459.00 $-80,912.39

2 $80,912.39 $-546.61 $458.50 $-80,824.28

3 $80,824.28 $-546.61 $458.00 $-80,735.68

4 $80,735.68 $-546.61 $457.50 $-80,646.57

5 $80,646.57 $-546.61 $457.00 $-80,556.96

6 $80,556.96 $-546.61 $456.49 $-80,466.84

7 $80,466.84 $-546.61 $455.98 $-80,376.21

8 $80,376.21 $-546.61 $455.47 $-80,285.06

9 $80,285.06 $-546.61 $454.95 $-80,193.40

10 $80,193.40 $-546.61 $454.43 $-80,101.22

11 $80,101.22 $-546.61 $453.91 $-80,008.52

12 $80,008.52 $-546.61 $453.38 $-79,915.29

Total payment at $546.61 x 12 months = $6,559.32

Principal repayment for 12 months = $1,084.71 ($81,000 - $79,915.29)

Interest paid for 12 months = $5,474.61 ($6,559.32 - $1,084.71)

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The kite's elevation relative to the ground is 6.45 feet.

Elevation simply means the height above sea level.

In this case, Jose flies a kite 17 1/2 ft above the ground and he increases its elevation by 4 3/4 ft by letting out some strung. and then changes its elevation by - 15.8 ft.

This will be illustrated as:

= 17.5 + 4.75 - 15.8

= 6.45 ft

The elevation is 6.45 feet.

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The time period of the given waveform is 2 units time

From the waveform,

Each units represent one units

The time period is the time taken for waveform to complete one cycle.

Here we have to find the time taken for the given wave to complete one cycle.

Here at t = 0 the wave reaches its positive peak point

At t = 1, the wave reaches its negative peak point

At t = 2, the wave reaches its positive peak point again

Therefore, in this waveform, the wave took 2 units time to complete one cycle

The time period = 2 units time

Hence, the time period of the given waveform is 2 units time

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The estimated sum of the given numbers using the range method is 20.1.

We are given three numbers. The numbers are 8.94, 2.16, and 9.02. All the given numbers are decimal numbers. We need to estimate the sum of all the numbers. The approximate value of each number is calculated below.

8.94 ≈ 8.9

2.16 ≈ 2.2

9.02 ≈ 9.0

Let the estimated sum of the given number be represented by the variable "E".

E = 8.9 + 2.2 + 9.0

E = 20.1

The actual sum of the given numbers is given below.

A = 8.94 + 2.16 + 9.02

A = 20.12

We can see that the estimated sum is very accurate as compared to the actual sum.

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When the radius is 9cm, it increases at a rate of 0.06 cm per second.

We assume the ballon is a perfect sphere. Remember that the volume of a sphere as a function of the radius is given by:

V = (4/3)*3.14*(R)³

When the radius is R = 9cm, the volume is:

V =  (4/3)*3.14*(9cm)³ = 3,052.08 cm³

Isolating the radius as a function of the volume, we get:

R = ∛((3/4*3.14)*V)

And we know that the volume increases at a constant rate of 6cm³/s, if we assume that the initial volume is 3,052.08 cm³ then we can write the radius as a function of time as:

R(t) = ∛((3/4*3.14)*(3,052.08 cm³ + 6cm³/s*t))

Where t is the time in seconds.

Now we need to differentiate this and evaluate in t = 0.

R'(t) = (1/3)*(3/4*3.14)*(3,052.08 cm³ + 6cm³/s*t)^(-2/3)* (6cm³/s*3/4*3.14)

Evaluating in t = 0 we get:

R'(0) = (1/3)*(3/4*3.14)*(3,052.08 cm³ + 6cm³/s*0)^(-2/3)* (6cm³/s*3/4*3.14)

       =  (1/3)*(3/4*3.14)*(3,052.08 cm³)^(-2/3)* (6cm³/s*3/4*3.14) = 0.06 cm/s

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The car was sold for 3429.5 cents and the percent discount from the original price is 14.265%.

According to the question,

We have the following information:

Beginning on day one, the owner discounts the price by 5% each day until it sells. On the third day the car sells. And the original price of the model car was $40.

The first day:

40*5/100

200/100

2

The price on the first day = $38

The second day:

38*5/100

190/100

1.9

The price on the second day = 38-1.9

The price on second day = 36.1

The third day:

36.1*5/100

180.5/100

1.805

The price on third day = $34.295 (36.1-1.805)

1 dollar = 100 cents

Price of car in cents = 3429.5 cents

B) Percent discount from the original price:

Let's take it to be x.

40 - (40x/100) = 34.295

-40x/100 = 34.295-40

-40x/100 = -5.705

40x = 570.5

x = 570.5/40

x = 14.265%

Hence, the car was sold for 3429.5 cents and the percent discount from the original price is 14.265%.

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The length of side CA is right triangle ABC, 8.86 centimeters

In this question, we have been given triangle ABC has a right angle at C.

This means, AB is the hypotenuse of right triangle ABC.

measure of angle A = 41 degrees

and the length of side BC = 7.7 centimeters

We need to find length of CA

Consider sine of angle A.

sin(A) = opposite side/hypotenuse

sin(41°) = BC/AB

0.6561 = 7.7 / AB

AB = 7.7/0.6561

AB = 11.74

Applying Pythagoras theorem,

AB² = BC² + AC²

11.74² = 7.7² + AC²

AC² = 11.74² - 7.7²

AC = √(78.53)

AC = 8.86 centimeters

Therefore, the length of side CA is right triangle ABC, 8.86 centimeters

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Answer:

x < - 4 or x > 4

Step-by-step explanation:

given an inequality of the type| x | > a , then the solution is in the form

x < - a or x > a

thus

- 2x < - 8

divide both sides by - 2, reversing the symbol as a result of dividing by a negative quantity.

x > 4

OR

- 2x > 8

divide both sides by - 2, reversing the symbol

x < - 4

solution is x < - 4 or x > 4

Answer:

The answer can be expressed in two types of forms.

INEQUALITY FORM:  x < -4  or  x > 4

INTERVAL NOTATION:  ( –∞, –4) (4, ∞ )

Step-by-step explanation:

1. Isolate the variable "x" by dividing each side by factors that do not contain the variable "x."

2. Write |-2x|>8 as a piece:

TOP: {-2x > 8    x ≤ 0  / BOTTOM: {2x > 8   x > 0}

3. Divide each term by -2, then simplify.

x < -4

4. Divide each term by 2, then simplify.

x > 4

5. Find the union of the solutions.

The amounts drained by each pipe, considering a system of equations, are given as follows:

The variables to the system of equations are presented as follows:

A water tank holds a total of 5,600 gallons, hence:

x + y + z = 5600.

Pipe B drains twice as much as pipe A, hence:

y = 2x.

Pipe C drains 65 gallons more than pipe B, hence:

z = 65 + y = 65 + 2x.

Replacing the last two equations into the first, the amount drained by Pipe A is obtained as follows:

x + y + z = 5600.

x + 2x + 65 + 2x = 5600

5x = 5535

x = 5535/5

x = 1107 gallons.

Hence the remaining amounts are given as follows:

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256 805 - 136.667 ≈ 256 668.333

The difference is approximately 256 668.333

The additional number of days that is required to complete the rest of the work in mixed fraction is equal to 4 4/11 days.

First of all, we would determine the number of work left for Ann after two (2) working days:

In one (1) day, the amount of work that would be done by Ann alone is given by 1/10 days. Therefore, the amount of work that would be done by Ann alone in two (2) days is given by 2/10 or 1/5 days.

For the number of work left, we have:

Work left = 1 - 1/5

Work left = 4/5 days.

Similarly, the amount of work that would be done by Ben alone in one (1) day is given by 1/12 days.

Therefore, the combined work rate of both Ann and Ben is given by:

Combined work rate = 4/5 + 1/12

Combined work rate = 11/60

For the additional number of days required to complete the rest of the work, we have:

Additional days = 4/5 ÷ 11/60

Additional days = 4/5 × 60/11

Additional days = 4 × 12/11

Additional days = 48/11

Additional days = 4 4/11 days.

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This question requires you to find simple interest. Total money in the account after 10 years is $189,000

The total money can be calculated as follows:

Given,

=Deposit×Interest×Year

=18,000×8.5%×10

=18,000×[tex]85/100[/tex]×10

=$171,000

=$171.000+$18.000

=$189,000

Hence, the simple interest or total money in the account after 10 years without any withdrawals of additional deposits is $189,000.

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The amount of money in the account after 10 years will be $42113.64.

Compound interest is applicable when there will be a change in the principle amount after the given time period.

For example, if you give anyone $500 at the rate of 10% annually then $500 is your principle amount. After 1 year the interest will be $50 and hence principle amount will become $550 now for the next year the interest will be $550, not $500.

As per the given,

Principle amount P = $18000

Rate of interest r = 8.5% = 0.085

Time t = 10

By continuous compounding interest formula,

P = (18000)[tex]e^{0.085\times10}[/tex]

P = $42113.64

Hence "The amount of money in the account after 10 years will be $42113.64".

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The equation (in slope-intercept form) of the line passing through the points with the given coordinates (−2,3) , (−3,2) is y = x + 5

The equation of a line in slope intercept form can be represented as follows:

y = mx + b

where

Hence, let's find the slope of the line using the coordinates (-2, 3) and (-3, 2).

Therefore,

m = 2 - 3 / -3 + 2

m = - 1 / -1

m = 1

Therefore, lets find the y-intercept using (-2, 3)

y = x + b

3 = -2 + b

b = 3 + 2

b = 5

Hence, the equation of the line in slope intercept form is y = x + 5

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Answer:

350 in. squared

Step-by-step explanation:

Deondra read at rate 40 pages per hour.

What is the meaning of the rate?

The rate at which something occurs or changes, as well as the quantity or frequency with which it does so over a period of time.

What is the unitary method?

The unitary approach is a strategy for problem-solving that involves first determining the value of a single unit, then multiplying that value to determine the required value.

Given that, Deondra read 18 pages in 2/5 of an hour.

Use unitary method to calculate the required value:

In 2/5 hour, she read 18 pages.

In 1 hour, she read 18/(2/5) pages.

In 1 hour, she read 18 × (5/2) pages = 40 pages.

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The equation for the nth term of the arithmetic sequences are:

a_n = -11 + 4n and a_n = -10 + 2n where n is an positive integer.

What is the arithmetic sequence?

A series of numbers called an arithmetic progression or arithmetic sequence has a constant difference between the terms.

The formula of nth term of an arithmetic sequence is a_n = a + (n-1) d

The arithmetic sequence is -7, -3, 1, ....

The first term is a = -7.

The common difference is d = (-3)-(-7) = 1 - (-3) = 4.

The nth term of an arithmetic sequence is

a_n = -7 + (n-1) 4

a_n = -7 + 4n -4

a_n = -11 + 4n

The arithmetic sequence is -8, -6, -4, ....

The first term is a = -8.

The common difference is d = (-6)-(-8) = -4 - (-6) = 2.

The nth term of an arithmetic sequence is

a_n = -8 + (n-1) 2

a_n = -8 + 2n - 2

a_n = -10 + 2n

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