Given,
length of object, [tex]h_o = 3 cm[/tex]
We know, for flat refracting surface,
Image distance = object distance
So,
magnification is = [tex]-1[/tex]
length of the image,
[tex]h_i = magnification * h_o\\\\h_i = -1 * 3 \\\\h_i = -3cm[/tex]
Here, negative sign means inverted image.
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On average, how many stars would we have to search before we would expect to hear a signal? assume there are 500 billion stars in the galaxy.
We would have to search at least 5,000,000,000 (5 billion) stars before we would expect to hear a signal.
To find out the number of stars that we will need to search to find a signal, we need to use the following formula:
total of stars/civilizations500,000,000,000 (500 billion) stars / 100 civilization = 5,000,000,000 (5 billion)
This shows it is expected to find a civilization every 5 billion stars, and therefore it is necessary to search at least 5 billion stars before hearing a signal from any civilization.
Note: This question is incomplete; here is the complete question.
On average, how many stars would we have to search before we would expect to hear a signal? Assume there are 500 billion stars in the galaxy.
Assuming 100 civilizations existed.
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A furniture crate of mass 60 kg is at rest a loading ramp that makes an angle of 25° with the horizontal
The coefficient of kinetic friction between the crate and the ramp is 0.2. What force, applied parallel to the incline, is required to push the crate up the incline at a constant speed?
Answer:
furniture crate of mass 60 kg is at rest a loading ramp that makes an angle of 25° with the horizontal
The coefficient of kinetic friction between the crate and the ramp is 0.2. What force, applied parallel to the incline, is required to push the crate up the incline at a constant speed?
Explanation:
furniture crate of mass 60 kg is at rest a loading ramp that makes an angle of 25° with the horizontal
The coefficient of kinetic friction between the crate and the ramp is 0.2. What force, applied parallel to the incline, is required to push the crate up the incline at a constant speed?
[tex] \huge \boxed{ \sf lol}[/tex]
A new moon is discovered orbiting Neptune with an orbital speed of 9.3 x103 m/s. Neptune's mass is 1.0 x1026 kg. A) What is the radius of the new moon's orbit? B) What is the orbital period? Assume that the orbit is circular. (G = 6.673 x10-11 N-m²/kg?
12/3/21 A wave in the ocean has a wavelength of 24 m and a frequency of 8 Hz,What is the wave's speed?
Answer:
192 m/sExplanation:
The speed of the wave given only it's frequency and wavelength can be found by using the formula
[tex]c = f \times \lambda[/tex]
where
c is the velocity of the wave in m/s
[tex] \lambda[/tex] is the wavelength in m
f is the frequency in Hz
From the question we have
c = 8 × 24 = 192
We have the final answer as
192 m/sHope this helps you
A car travels 120 miles in 12 hours. What is
the car's speed?
Select one:
O a. 10 m/s
b. 10 mph
c. 1200 mph
O d. 0.1 m/s
Answer:
I hope it will help you...
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Why are movie scenes in outer space often unrealistic?
Answer:
see explanation
Explanation:
by my calculations, i believe it may be because they have to pretend to be in space.
one of them is Space & Interstellar Travel
You slide towards the window when a car makes a sudden turn
Answer:
thats ummm
Explanation:
law of inertia
Newton’s 1 law
Draw a diagram that represents how a mechanical wave interacts with a particular material.
Create a diagram and include reflection, absorption, and transmission.
Write a brief description (3+ sentences) of the interaction of the mechanical waves and the material. Include an explanation of how the amplitude and frequency of the wave are affected.
85 POINTS!!
When mechanical waves interact with material, it transfer its energy to the material.
What are mechanical waves?Mechanical waves are the type of waves that require a medium for transporting their energy from one region to another. Mechanical waves depend on particle interaction in order to transport their energy.
The amplitude and frequency of the wave are negatively affected due to the striking of mechanical waves with the material.
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Answer:
i have a screenshot just use mine https:/ss27
Explanation:
what class of motion did aristotle attribute to the moon?
free tingsssssssssss
Explanation:
yayyy thx u soo muchihuhuhu
Answer:
thx
Explanation:
A 50 kg swimmer goes off end of water slide at 10 m/s- what is swimmers momentum ?
Answer:
The swimmer's momentum is 500 Kg m/s.
Hope you could get an idea from here.
Doubt clarification - use comment section.
If the half-life of iodine-131 is 8 days, how much of a 5.00 sample is left after 32 days?
A) 0.31
B) 2.5
C) 1.25
D) 0.62
Answer:
Option A, 0.31
Explanation:
n = Time taken / half life
n = 32/ 8
= 4
Remaining fraction = 1/2^n
= 1/2⁴
= 1/16
Amount of iodine-131 left = 1/16 × 5
= 0.3125
Express the sum of 2.52 kg + 131 g in kilograms with the correct number of significant
figures.
Convert second term into kg
131 = 0.131
Term has become:
2.52 + 0.131
The total is:
2.651 kg
will mark brainliest if answer
I won't touch the object because there is a warning sign and that means you stay out if it because it is a danger sign that High Resistance Material that means it is dangerous.
Where in an equation for photosynthesis does glucose belong? on the left, because it is a product on the left, because it is a reactant on the right, because it is a product on the right, because it is a reactant
Answer: The answer is on the right, because it is a product.
Explanation: During photosynthesis, light energy converts carbon dioxide and water (the reactants) into glucose and oxygen (the products).
Glucose belongs to the right side in photosynthesis equation because it is a product on the right.
What is Photosynthesis?Photosynthesis is the conversion of light energy into chemical energy by green plants and other organisms. Light energy is collected and utilized by green plants during photosynthesis to transform water, carbon dioxide, and minerals into oxygen and energy-rich organic molecules Glucose.photosynthesis equation can be written as6CO2 + 6H2O → C6H12O6 + 6O2.
Carbon dioxide + Water → Glucose + oxygen
Hence, the correct option is C.
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If you were to mix 10 grams of salt into 100 grams of water, how much will the total mass of the solution be?
Group of answer choices
90 grams
100 grams
110 grams
10 grams
110 grams
mass of salt + mass of water
10 + 100
110g
Answer:
110 grams
Explanation:
If you were to mix 7 grams of sugar into 100 grams of water, how much will the total mass of the solution be?
No mass was gained or lost, so the mass would be 107 grams.
100 grams
107 grams
93 grams
95 grams
No mass was gained or lost, so the mass would be 107 grams.
(For your problem it would be 10+ 100= 110g)
What is the equivalent resistance of a 12-ohm resistor wired in parallel with a 4-ohm resistor?
А
0.06 ohms
B
0.33 ohms
С
3.0 ohms
D
16.0 ohms
[tex]R=\frac{R1.R2}{R1+R2} = \frac{12.4}{12+4}=\frac{48}{16}=3<ohms>[/tex]
The answer is : C. 3.0 ohms
Ok done. Thank to me :>
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Suppose two objects are gravitationally attracted to each other with some force F. If the mass of object 1 is multiplied by a factor of five and the mass of object 2 is multiplied by a factor of two, what will the new gravitational force be between the objects?
A. F2
B. 1/2F
C. 0.1F
D. 2F/5
E. 5F
J. 10F
Please help will mark brainliest
If F = Gm₁m₂/d², and we change m₁ to 5m₁ and m₂ to 2m₂, then the new magnitude of the gravitational force is
F' = G (5m₁) (2m₂) / d²
F' = 10 Gm₁m₂ / d²
but this is really just F' = 10F. So J is the correct choice.
Hi there!
Using Newton's Law of Universal Gravitation:
[tex]\large\boxed{F_g = G\frac{m_1m_2}{d^2}}[/tex]
Fg = Force of gravity (N)
G = Gravitational Constant
m₁ = mass of object 1 (kg)
m₂ = mass of object 2 (kg)
d = distance between the objects (m)
There is a direct relationship between the masses of the objects and the resulting force of gravity, so we can plug new values in:
[tex]F_g = G\frac{5m_12m_2}{d^2}} = 10G\frac{m_1m_2}{d^2}} = 10F_g[/tex]
Thus, the correct answer is J. 10Fg.
A kilowatt-hour is a unit of
1. force
2. power
3. work
4. voltage
5. current
6. None of these
7. torque
(I tried 2 and 6, but they were both wrong :( )
Answer:
option 4 is the correct answer
3. Suppose Earth orbited a star whose mass was double the mass of the sun. If the radius of Earth's orbit remained
the same as it is now, then compared with gravitational force between Earth and the sun, the gravitational force
between Earth and the star would be -
A. half as much
B. the same
C. two times as much
D. four times as much
Answer:
F1 = G M m / R^2 current force on earth
F2 = G M * 2 m / R^2 force if mass were doubled
F2 / F1 = 2 the force would be twice as large
The gravitational force between two objects not only depends on the mass but also the distance between them. If the distance to the star is same as to sun, then by doubling mass force also doubles. Thus option C is correct.
What is universal law of gravitation?Gravitational force is the attractive force by which an object attracts other objects into its centre of mass. We are all standing in the ground because of the gravitational pull by earth.
The gravitational force between two objects of mass M1 and M2 at a distance r is written as follows:
g = G M1 M2/ r ² . where, G is gravitational constant.
As per this relation, gravitational force is directly proportional to the mass and inversely proportional to the square of the distance.
If the star has a distance from earth equal to the distance between sun and earth, but its mass is double the mass of sun, then the gravitational force will be two times compared with the sun.
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(50 POINTS) please answer each question:
what is the Distance from Earth (light years)
what is the Visual Luminosity in comparison to Sun
what is the Surface Temperature (Kelvin)
stars:
Sun
Alpha Centauri A
Sirius B
Barnard’s Star
Vega
Proxima Centauri
Answer:
i know the first one.
Explanation:
the distance from earth in light years is 6 trillion miles.
A 50.0 kg crate is pulled 375 N of force applied to a rope. The crate slides without friction.
After being pulled 3.07 meters the crate has a velocity of 5.61 m/s. What is the angle (degrees) made by the rope with the horizontal?
Hi there!
We can use the work-energy theorem to solve.
Recall that:
[tex]\large\boxed{W = \Delta KE = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2}[/tex]
The initial kinetic energy is 0 J because the crate begins from rest, so we can plug in the given values for mass and final velocity:
[tex]W = \frac{1}{2}(50)(5.61^2) = 786.8025 J[/tex]
Now, we can define work:
[tex]\large\boxed{W = Fdcos\theta}}[/tex]
Now, plug in the values:
[tex]786.8025 = Fdcos\theta\\\\786.8025 = (375)(3.07)cos\theta[/tex]
Solve for theta:
[tex]cos\theta = .6834\\\theta = cos^{-1}(.6834) = \boxed{46.887^o}[/tex]
This is not meant to be a long, mathematically-intensive problem. If you find yourself going down that road, you might want to rethink your approach.
Answer:
rethink your approach to what?
Explanation:
The density of air is 1.3 kg/m'. Calculate the mass of air in the room.
Answer:
The density of air is 1.3 kg/m'. Calculate the mass of air in the room.
If the 0.10 kg baseball on the right has a
kinetic energy of 5 J, what is its velocity?
Answer:
10 m/sExplanation:
The kinetic energy of an object can be found by using the formula
[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]
m is the mass
v is the velocity
Since we're finding the velocity we make v the subject
That's
[tex]v = \sqrt{ \frac{2k}{m} } \\ [/tex]
From the question
k = 5 J
m = 0.1 kg
We have
[tex]v = \sqrt{ \frac{2 \times 5}{0.1} } = \sqrt{ \frac{10}{0.1} } = \sqrt{100} \\ = 10[/tex]
We have the final answer as
10 m/sHope this helps you
A wave traveling at 230 m/sec has a wavelength of 2.1 meters. What is the frequency of this wave?
Answer:
109.52 HzExplanation:
The frequency of the wave when given it's velocity and wavelength only can be found by using the formula
[tex]f = \frac{c}{ \lambda} \\ [/tex]
where
c is the velocity of the wave in m/s
[tex] \lambda[/tex] is the wavelength in meters
From the question we have
c = 230 m/s
[tex] \lambda[/tex] = 2.1 m
[tex]f = \frac{230}{2.1} = 109.523809... \\ [/tex]
We have the final answer as
109.52 HzHope this helps you
where in space did the expansion of the universe begin?
Answer:
The big bang
Explanation:
It is theorized the expansion of the universe began with the big bang, the universes expansion therefore did not begin in a spot of the universe rather the universe expanded from the big bang.
1 kg ball has eight joules of kinetic energy. what is its speed?
[tex]\\ \sf\Rrightarrow KE=\dfrac{1}{2}mv^2[/tex]
[tex]\\ \sf\Rrightarrow 8=\dfrac{1}{2}v^2[/tex]
[tex]\\ \sf\Rrightarrow v^2=16[/tex]
[tex]\\ \sf\Rrightarrow v=√16[/tex]
[tex]\\ \sf\Rrightarrow v=4m/s[/tex]
Answer:
the answer is 4m/s
If a 75 kg box collides with a stationary 35 kg box with a force of 110 N, what must be true of the magnitude of the reaction force?
According to Newton third law of motion, what must be true of the magnitude of the reaction force is that the reaction force will be equal and opposite to the action force of 110 newtons
From Newton third law of motion which state that in every action of force, there will be equal and opposite reaction.
If a 75 kg box collides with a stationary 35 kg box with a force of 110 N, the mass 35 kg will produce a reaction force which is equal and opposite to the action force 110 newton received from mass 75 kg.
Therefore, what must be true of the magnitude of the reaction force from mass 35 kg is that the mass will produce an equal and opposite force equal to 110 Newtons.
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