An engineer is applying dimensional analysis to study the flow of air through this horizontal sudden contraction for the purpose of characterizing the pressure drop. The flow is being modeled as constant density and steady. What is the functional relationship of the variables that characterize this situation

Answers

Answer 1

Answer:

The answer is " [tex]\Delta p = f(V1, p, V2, d, D, L)[/tex]"

Explanation:

Please find the complete question in the attached file.

Its change in temperature in pipes depends on rate heads and loss in pipes owing to pipe flow, contractual loss, etc.

The temperature change thus relies on V1 v2 p d D L.

An Engineer Is Applying Dimensional Analysis To Study The Flow Of Air Through This Horizontal Sudden

Related Questions

Vince is trying to figure out the volume of two mystery matters. The volume of one of the substances needs to be measured by submerging it in water and the other needs to be measured using a graduated cylinder. Based on the properties of two mystery matters, what are they? (2 points)

Group of answer choices

A rock and orange juice

Helium and a golf ball

Lemonade and milk

Orange juice and helium

Answers

Answer:

Rock and orange juice

Explanation:

The mystery matter to be submerged in water must be a solid, therefore we can eliminate the Lemonade and Milk, and Orange juice and Helium, as these pairs do not contain solids. The graduated cylinder is used to measure the volume of a liquid, therefore the only remaining option is Rock and Orange Juice.

Engineers design products or processes to meet desired needs. Your desired need or goal (hopefully) is to graduate with your Bachelor of Science degree in engineering. But what is the process you need to apply to be successful in achieving this goal?

Answers

Components of a Success Civil Engineering Career: Skills, Tools, and Technology.

A cylindrical buoy is 2m in diameter and 2.5m long and weight 22kN . The specific weight of sea water is 10.25kN/m^3 . (I) Show that buoy does not float with its axis vertical. (II). What minimum pull should be applied to a chain attached to the center of the base to keep the buoy vertical?

Answers

Answer:

[tex]GM<0[/tex]

So the bouy does not float with its axis vertical

Explanation:

From the question we are told that:

Diameter [tex]d=2m[/tex]

Length [tex]l=2.5m[/tex]

Weight [tex]W=22kN[/tex]

Specific weight of sea water [tex]\mu= 10.25kN/m^3[/tex]

Generally the equation for weight of cylinder is mathematically given by

Weight of cylinder = buoyancy Force

[tex]W=(pwg)Vd[/tex]

Where

[tex]V_d=\pi/4(d)^2y[/tex]

Therefore

[tex]22*10^3=10.25*10^3 *\pi/4(2)^2y\\\\\22*10^3=32201.3247y\\\\\y=1.5m[/tex]

Therefore

Center of Bouyance B

[tex]B=\frac{y}{2}=0.26m\\\\B=0.75[/tex]

Center of Gravity

[tex]G=\frac{I.B}{2}=2.6m[/tex]

Generally the equation for\BM is mathematically given by

[tex]BM=\frac{I}{vd}\\\\BM=\frac{3.142/64*2^4}{3.142/4*2^2*0.5215}\\\\BM=0.479m\\\\[/tex]

Therefore

[tex]BG=2.6-0.476\\\\BG=0.64m[/tex]

Therefore

[tex]GM=BM-BG\\\\GM=0.479m-0.64m\\\\GM=-0.161m\\\\[/tex]

Therefore

[tex]GM<0[/tex]

So the bouy does not float with its axis vertical

Hi, can anyone draw me an isometric image of this shape?​

Answers

I can give me like 10 minutes I gotta find my book
I have 2 accounts here’s the answer

explain all the characteristics of computer

Answers

They are as follows-

Speed
Accuracy
Storage
Versatility
Diligence
Automation
Reliability
Power of Remembering

Let us understand each characteristic in brief:-

Speed – Speed of a computer means the time it takes to complete any given task. The computer works at a very lightning speed. For example, a computer takes a second to calculate 3 million calculations rather than a human which takes years. Hence nowadays the speed of the computer is measured in terms of microseconds, Nanoseconds, and even in Pico seconds instead of seconds or milliseconds.


Accuracy – The computers are programmed and designed in such a manner that their results are almost 100% accurate. It performs all the tasks with the same accuracy. There are very few chances of uncertainty in results and even though an error occurs, it can happen either due to wrong input data or unreliable programs by a programmer. Such errors are referred to as Garbage In Garbage Out (GIGO) which means, if you provide wrong instructions to the computer then you get wrong results.


Versatility – Along with being accurate and diligent a computer is also a versatile device. It can perform several types of tasks at a time if they are reduced to a certain set of logical steps. A computer can be used for many purposes at different places such as booking air and rail tickets, weather forecasting, listening to music, and playing games. Also at a time, one can pay his utility bills and can make a monthly budget too. It can prepare documents, data sheets and also can make models of houses, dams, etc.
Diligence – The ability of a computer to perform tasks without getting tired is known as diligence. Computers are highly reliable, they do not get fed up, exhausted, or lack concentration. They can work for hours and hours unlike humans and can give accurate or error-free results. For example, humans will start feeling tired after 2 -3 hours and will lack concentration whereas a computer will keep on working until the results are achieved.
Automation – Automation means working automatically. A computer can work on its own without the intervention of the person using it. Programs can be made for the computer to perform the task and based on the sequence it executes the tasks and gives accurate results. In case an error occurs, it gives error messages too and registers the logs.
Reliability – High reliability of a computer depends on low failure rate and easy maintenance. The results given out by the computer are reliable as the accuracy is almost 100%.
Power of Remembering – The computer has the power of storing data or information for several years. It cannot lose the data on its own. A person can retrieve the data whenever required and the data remains the same after a number of years also. It gives the freedom to the user to decide on how much data to store and how much to remove.

Water enters and leaves a pump in pipelines of the same diameter and approximately the same elevation. If the pressure on the inlet side of the pump is 30 kPa and a pressure of 500 kPa is desired for the water leaving the pump, what is the head that must be added by the pump

Answers

Answer:

The head added by the pump is approximately 51.8 meters

Explanation:

The given parameters of the water are;

The initial diameter of the pump ≈ The final diameter of the pump

The inlet side pressure, p₁ = 30 kPa

The intended outlet side pressure, p₂ = 500 kPa

The power of the pump, P = ρ·g·Q·H

Where, the pressure added by the pump, Δp = p₂ - p₁ = ρ·g·H

ρ = The density of the water ≈ 997 kg/m³

g = The acceleration due to gravity ≈ 9.81 m/s²

H = The head added by the pump

Therefore, we have;

500 kPa - 30 kPa = 997 kg/m³ × 9.81 m/s² × H

H = (500 kPa - 30 kPa)/(997 kg/m³ × 9.1 m/s²) ≈ 51.8 m

The head added by the pump, H ≈ 51.8 meters.

Which of the following is NOT part of a car's drive train?
A axle
B rotor
C differential
D transmission

Answers

Answer:

B. rotor

Explanation:

The correct answer Is rotor because the others are part of a cars drivetrain

The drive train system exists as a critical element of a vehicle and the transmission exists as an integral part of the drive train. B rotors NOT part of a car's drive train.

Which is not part of the drive train?

A drive train exists not really a single part of your car – it's a set of drive train components that interact with the engine to drive the wheels and different regions of the vehicle to thrust it into motion. These components often contain the transmission, differential, driveshaft, axles, CV joints, and wheels.

Therefore, the correct answer is option B rotors.

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State two factors that shows that light travels in a straight line​

Answers

Explanation:

Light travels in straight lines

Once light has been produced, it will keep travelling in a straight line until it hits something else. Shadows are evidence of light travelling in straight lines. An object blocks light so that it can't reach the surface where we see the shadow.

Answer:

The two factors are Air and Object

You are the public relations director of a nonprofit hospital in a competitive market in a midsized city located in a metro area of 350,000 people. It is sweeps week for broadcast media. One of the stations is running a series on HIV/AIDS in the community. Recent segments have included those listed below.
The need for a confidential clinic
Homelessness related to HIV/AIDS
How persons living with HIV/AIDS suffer from being outcasts
How understanding has increased in some circles but prejudice remains in many.
An appealing case of a hemophiliac who acquired HIV/AIDS through transfusion at the university hospital has been reported in the series. The university and its teaching hospital are located elsewhere in the state.
At a staff meeting this morning, you learn that petitions are circulating in the community to request your hospital to convert its former nurses’ residence into a clinic and residential shelter for HIV/AIDS patients.
The hospital no longer maintains a school of nursing. The three-story brick building has been used for miscellaneous administrative purposes since nurses’ training was phased out. The residence is connected to the hospital by an elevated corridor, similar to a skywalk. It does not have facilities for food service or laundry. Nurses always ate at the hospital and the hospital handled their laundry. The residence and hospital are served by common systems for hot water, steam heat, ventilating and sewer. The building predates central air conditioning.
The human resources director reports that the business agent for kitchen and laundry workers, who are represented by a union, has already made informal contacts about this proposal, suggesting that grievances will result, at the very least, and a strike could ensue.
Your director of volunteers expresses concern about reaction of volunteers who now handle many peripheral duties.
Your physical plant supervisor, who lives in the neighborhood, says neighbors are already anxious over the possibility of HIV/AIDS patients in their vicinity.
Your hospital’s five-year Strategic Plan, which was recently updated, has no mention of developing an HIV/AIDS specialty.
Individual Assignment
For this assignment, you are to write a letter (using your own name) to the hospital CEO, John Dolman and the Board of Governors outlining your plan to resolve this issue.
Remember, that your letter will be made public to the other audiences and publics. In your recommendations, you should provide both long and short-term strategies that would solve this problem. To solve this problem you should note if additional resources or expenditures would be need to achieve the goals that you define.
When writing the letter you should provide a brief description of the problems, you have found. What are the facts about major issues? Identify facts about key players in the case, the business problem(s) and then rank order the critical issues. Consider relevant information and underlying assumptions. Finally provide your recommendations.
As you write your recommendations, think about the following;
How do the cultural values at the hospital relate to communication, technology, information flow and openness?
As the hospital goes forward, should it stick to the espoused culture or should it change? How would you recommend that they change?
How would you suggest that they resolve this disparity? In other words what should they do?
Provide specific suggestions that will help the organization as they go forward.
In the closing, highlight benefits of your recommendations. As a PR director, you need to be honest but tactful in your recommendations.
Remember
Carefully read the "case study" and type a letter that details your specific analysis and recommendations about how problem presented in case might be approached and solved.
This document should be formatted for reading ease, not a page of text. Make sure you use address it correctly, provide a date, headings, and bullet points as needed to make it easy to read.

Answers

Answer:

Following are the application to the given question:

Explanation:

To,

          The Chief Operating Officer,

           Maidan Hospitals, USA

02.10.2020

Subject: HIV/AIDS disease spreading control

Respected Mr Dolman,

The media as well as the individuals living in the area have indeed been notified again that the spread of Hiv / Aids must be regulated and managed immediately. A proper environment must be created artificially to heal this sickness and help stop it from spreading.

Its fight for the sickness ought to be a forward end to bring it through to the high levels instead of being fearful of disease. The disease also is seen in the hospital as it has grown via infusion so that the nursing staff must keep a check mostly on the issue frequently.

This position taken through distributing petitions in the community proposes that a small number of clinics must be established, as this could help to stop the disease from becoming spread. They have also seen that hospital nurses eat, sleep, washing dishes, etc. in such a single place.

To stop this same nursing staff that lives in the health facilities shortly, I suggest that perhaps it should be broken into combinations of 4 individuals and relocated to newly built hospitals, in which they can stay individually and retain hygiene, preserve the atmosphere, help educate, etc. Those who should be accountable. Each clinic and physicians visit every day to examine their clients.

Many patients might well be healed without great faith using these specific HIV/AIDS measures because all norms and laws are observed and mainly social distance is maintained of each patient. Its clinics, as well as the environment, must be sanitized but kept from outside so that the community members recover the confidence and trust of the health departments beforehand. More importantly, a regulatory body should be established that can monitor the operations properly, handle cash, etc. to run smoothly.

Here are a few of my suggestions and promise that it could be successful if it is kept & rigorously implemented.

Thank you and regards,

Joy Roy.

(PR. Director)

A square plate of titanium is 12cm along the top, 12cm on the right side, and 5mm thick. A normal tensile force of 15kN is applied to the top side of the plate. A normal tensile force of 20kN is applied to the right side of the plate. The elastic modulus, E, is 115 GPa for titanium.If the left and bottom edges of the plate are fixed, calculate the normal strain and elongation of both the TOP and RIGHT side of the plate.

Answers

Answer:

[tex]X_t=2.17391304*10^{-4}[/tex]

[tex]X_r=2.89855072*10^{-4}[/tex]

[tex]e_t=0.0026[/tex]

[tex]e_r=0.0035[/tex]

Explanation:

From the question we are told that:

Dimension [tex]12*12[/tex]

Thickness [tex]l_t=5mm=5*10^-3[/tex]

Normal tensile force on top side [tex]F_t= 15kN[/tex]

Normal tensile force on right side  [tex]F_r= 20kN[/tex]

Elastic modulus, [tex]E=115Gpap=>115*10^9[/tex]

Generally the equation for Normal Strain X is mathematically given by

 [tex]X=\frac{Force}{Area*E}[/tex]

Therefore

For Top

 [tex]X_t=\frac{Force_t}{Area*E}[/tex]

Where

 [tex]Area=L*B*T[/tex]

 [tex]Area=12*10^{-2}*5*10^{-3}[/tex]

 [tex]Area=6*10^{-4}[/tex]  

 [tex]X_t=\frac{15*10^3}{6*10^{-4}*115*10^9}[/tex]

 [tex]X_t=2.17391304*10^{-4}[/tex]

For Right side[tex]X_r=\frac{Force_r}{Area*E}[/tex]

Where

Area=L*B*T

 [tex]Area=12*10^{-2}*5*10^{-3}[/tex]

 [tex]Area=6*10^{-4}[/tex]  

 [tex]X_r=2.89855072*10^{-4}[/tex]

 [tex]X_r=2.89855072*10^{-4}[/tex]

Generally the equation for elongation is mathematically given by

 [tex]e=strain *12[/tex]

For top

 [tex]e_t=2.17391304*10^{-4}*12[/tex]

 [tex]e_t=0.0026[/tex]

For Right

 [tex]e_r=2.89855072*10^{-4} *12[/tex]

 [tex]e_r=0.0035[/tex]

Water flows through a converging pipe at a mass flow rate of 25 kg/s. If the inside diameter of the pipes sections are 7.0 cm and 5.0 cm, find the volume flow rate and the average velocity in each pipe section.

Answers

Answer:

volumetric flow rate = [tex]0.0251 m^3/s[/tex]

Velocity in pipe section 1 = [tex]6.513m/s[/tex]

velocity in pipe section 2 = 12.79 m/s

Explanation:

We can obtain the volume flow rate from the mass flow rate by utilizing the fact that the fluid has the same density when measuring the mass flow rate and the volumetric flow rates.

The density of water is = 997 kg/m³

density = mass/ volume

since we are given the mass, therefore, the  volume will be mass/density

25/997 = [tex]0.0251 m^3/s[/tex]

volumetric flow rate = [tex]0.0251 m^3/s[/tex]

Average velocity calculations:

Pipe section A:

cross-sectional area =

[tex]\pi \times d^2\\=\pi \times 0.07^2 = 3.85\times10^{-3}m^2[/tex]

mass flow rate = density X cross-sectional area X velocity

velocity = mass flow rate /(density X cross-sectional area)

[tex]velocity = 25/(997 \times 3.85\times10^{-3}) = 6.513m/s[/tex]

Pipe section B:

cross-sectional area =

[tex]\pi \times d^2\\=\pi \times 0.05^2= 1.96\times10^{-3}m^2[/tex]

mass flow rate = density X cross-sectional area X velocity

velocity = mass flow rate /(density X cross-sectional area)

[tex]velocity = 25/(997 \times 1.96\times10^{-3}) = 12.79m/s[/tex]

An aggregate blend consists of 65% of aggregate A and 35% of aggregate B. The bulk specific gravities of aggregate A and B are 2.45 and 3.25, respectively. What is the bulk specific gravity of the blend?
a) 2.45
b) 2.68
c) 2.73
d) 2.92

Answers

Answer:

2.68

Explanation:

Percentage by Mass of each Aggregate :

Pa = 65% ; Pb = 35%;

Bulk Specific gravity of each aggregate :

Ga = 2.45 ; Gb = 3.25

Gsb = (Pa + Pb) / (Pa/Ga + Pb/Gb)

Gsb = (65 + 35) / (65/2.45 + 35/3.25)

Gsb = (65 + 35) / 37.299843

Gsb = 100 / 37.299843

Gsb = 2.68

The purpose of the international residential code is to

Answers

Answer:

The International Building Code (IBC) is a model code that provides minimum requirements to safeguard the public health, safety and general welfare of the occupants of new and existing buildings and structures.

Explanation:

What possible scenarios may happen if you do the task without using PPE?

Answers

Without PPE, employees are at risk of Cuts and punctures. Chemical burns. Electric shocks. Exposure to excessive noise or vibration.

A brittle material is subjected to a tensile stress of 1.65 MPa. If the specific surface energy and modulus of elasticity for this material are 0.60 J/m2 and 2.0 GPa, respectively. What is the maximum length of a surface flaw that is possible without fracture

Answers

Answer:

The maximum length of a surface flaw that is possible without fracture is

[tex]2.806 \times 10^{-4} m[/tex]

Explanation:

The given values are,

σ=1.65 MPa

γs=0.60 J/m2

E= 2.0 GPa

The maximum possible length is calculated as:

[tex]\begin{gathered}a=\frac{2 E \gamma_{s}}{\pi \sigma^{2}}=\frac{(2)\left(2 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}\right)(0.60 \mathrm{~N} / \mathrm{m})}{\pi\left(1.65\times 10^{6} \mathrm{~N} / \mathrm{m}^{2}\right)^{2}} \\=2.806 \times 10^{-4} \mathrm{~m}\end{gathered}[/tex]

The maximum length of a surface flaw that is possible without fracture is

[tex]2.806 \times 10^{-4} m[/tex]

Determine the horsepower required to compress 1 lbm/min of ethylene oxide from 70 oF and 1 atm to 250 psia. The compressor has an efficiency of 75%. The molar heat capacity of ethylene oxide is given by Cp

Answers

Complete Question:

Problem 8 Determine the horsepower required to compress 1 lbm/min of ethylene oxide from 70 °F and 1 atm to 250 psia. The compressor has an efficiency of 75%. The molar heat capacity of ethylene oxide is given by

C_p=10.03+0.0184T  C_p[=]Btu/lbmole- "F ; T[=] °F C,

Answer:

[tex]P'=0.377hp[/tex]

Explanation:

From the question we are told that:

Initial Temperature T_1=70 F

Final Temperature [tex]T_2=250pisa =114.94F[/tex]

Efficiency [tex]E=75\%=0.75[/tex]

Generally the equation for Work-done  is mathematically given by

 [tex]W=\int C_pT[/tex]

 [tex]W=10.03(114.94-70 )+0.0184((114.94)^2-70^2 )[/tex]

 [tex]W=527.21btu/ibmole[/tex]

 [tex]W=11.982btu/ibm[/tex]

Generally the equation for Efficiency  is mathematically given by

 [tex]E=\frac{isotropic Power}{Actual P'}[/tex]

 [tex]E=\frac{P}{P'}[/tex]

Since

Isotropic Power

  [tex]P=0.0167*11.982btu/ibm[/tex]

 [tex]P=0.2btu/s[/tex]

Therefore

 [tex]P'=\frac{0.2}{0.75}[/tex]

 [tex]P'=0266btu/s[/tex]

Since

 [tex]1btu/s=1.4148hp[/tex]

Therefore

 [tex]P'=0.377hp[/tex]

The allowable tensile stress for a 6.25 mm diameter bolt with a thread length of 5.5 mm is 207 MPa. The allowable shear stress of the material is 103 MPa. Where and how will such a bolt be most likely to fail if placed in tension

Answers

Answer:

At the threads due to shear.

Explanation:

Given :

The allowable tensile stress = 207 MPa

The allowable shear stress = 103 MPa

If a tensile force is applied, the maximum shear stress occurs at the threads of  the bolt. The bolt is most likely to fail at the critical section. The critical cross section is the section having the minimum cross sectional area.

The portion of the bolt having threads has the minimum cross sectional area.

So when the bolt is applied with a tensile force, failure is most likely to take place at the threads due to the shearing force.

Okay bro let’s go man yes yes

Answers

Answer:do me ti

Why not me

Why not me

do me ti

Why not me

Why not me

Do me ti

Why not me

Why not me

Explanation:

mitski

Things to be done before isolation

Answers

As in a lockdown? Or quarantine? Gets lots of canned food, toilet paper, water and clothing for the future.

A cylindrical block of wood 1 m in diameter and 1 m long has a specific weight of 7500 N/m^3. Will it float in water with its axis vertical?

Answers

Answer:

The block will float with its axis vertical.

Explanation:

For it to float, the upward force on the cylindrical block must be equal to the weight of an equal volume of water. Also, this upward force must be greater than or equal to the weight of the cylindrical block for it to float.

So, weight of cylindrical block, W = specific weight × volume

specific weight = 7500 N/m³

volume = πd²h/4 where d = diameter of block and h = height of block

volume = π(1 m)² × 1 m/4 = π/4 m³ = 0.7854 m³

W = 7500 N/m³ × 0.7854 m³ = 5890.5 N

Since the density of water = 1000 kg/m³, its specific weight W' = 1000 kg/m³ × 9.8 m/s² = 9800 N/m³

Since the volume of the cylinder = volume of water displaced, the weight of water displaced W' = upward force = specific weight of water × volume of water displaced =  9800 N/m³ × 0.7854 m³ = 7696.92 N

Since W' = 7696.92 N > W = 5890.5 N, the block will float with its axis vertical since the upward force is greater than the weight of the cylindrical block.

A 2.0-in-thick slab is 10.0 in wide and 12.0 ft long. Thickness is to be reduced in three steps in a hot rolling operation. Each step will reduce the slab to 75% of its previous thickness. It is expected that for this metal and reduction, the slab will widen by 3% in each step. If the entry speed of the slab in the first step is 40 ft/min, and roll speed is the same for the three steps, determine: (a) length and (b) exit velocity of the slab after the final reduction

Answers

Answer:

26.02 ft

86.7690 ft/min

Explanation:

After 3 steps

0.75³(2.0 thickness)

T = 0.84375

W = (1+0.03)³10

= 10.92727 inches

A To get length

2.0 x 10 x 12 x12 = 0.84375 x 10.92727x lf

= 2880 = 9.21988Lf

Lf = 2880/9.21988

= 312.368 inches

Convert to feet

322.368 x 0.0833

= 26.02 ft

B.

= 2 x 10 x 40 = 0.84375 x 10.92727 x vf

800 = 9.21988vf

Vf = 800/9.21988

Vf = 86.7690 ft/min

The statement that is correct about the relation between the velocity boundary layer and heat transfer for flow over a flat plate that is uniform in temperature is

Answers

Answer: the heat flux increases as the velocity boundary layer transitions to laminar to turbulent.

Explanation:

The correct statement about the relation between the velocity boundary layer and heat transfer for flow over a flat plate that is uniform in temperature is that the heat flux increases as the velocity boundary layer transitions to laminar to turbulent.

It should be noted that the heat goes in a streamline direction in a laminar flow, thereby the molecules less collide with each other. On the other hand, the direction is zig zag in a turbulent heat flux and this will bring about more collision of the molecules which leads to a rise in the heat flux.

What is the per capita GDP of China? Be sure to indicate the calendar year that this information represents.

Answers

10,261.68 USD (2019)

The per capita GDP of China in the Calendar year 2021 was found to be around 12,359 U.S. dollars.

What is GDP?  

GDP termed Gross Domestic Product, has been evaluated with the value producing the economy of the region with the values added with the used products formed to be the less of the economy produced. It has been termed as the measure of the income of a region and not the wealth.

The per capita GDP has been the total income earned by a person in a region during a specified period of time. The calculation has been made by dividing the total gross income of the region by the total population.

China has been the world's most populous country in the East Asian region. It has been found that the per capita GDP of China is low because of its large population. In the calendar year 2021, the per capita GDP of China was 12,359 U.S. dollars.

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Why does the ceramic made from Thorium and Oxygen have the chemical ratio of 2 oxygen atoms to every thorium atom (ThO2)

Answers

Gf so 467 gah can-go FTC 346

If you deposit $ 1000 per month into an investment account that pays interest at a rate of 9% per year compounded quarterly.how much will be in your account at the end of 5 years ?assume no interpèriod compounding

Answers

Answer:

5,465.4165939453

Explanation:

formula

A=P(1+r/n)^n(t)

p=1000

r=0.09

n=4

t=5

can help me with this circuit question? ​
the last word is (cutoff)

Answers

Answer:

The answer is "[tex]25\times 10^{-9}[/tex]".

Explanation:

Using formula:

[tex]f_c=\frac{1}{2\pi RC}\\\\w_c= 4 \frac{krad}{sec}\\\\w_c=2\pi fc\\\\R=w\\\\c=\frac{1}{w_c\ R}\\\\[/tex]

  [tex]=\frac{1}{4 \times 10^3 \times 10\times 10^3}\\\\=\frac{1}{40 \times 10^6 }\\\\=0.025 \times 10^{-6 }\\\\=25\times 10^{-9}[/tex]

Resistance depends on which three properties of a wire?

Color and texture are not directly related to a wire’s resistance.

1. color, thickness, texture
2. thickness, length, temperature
3. length, texture, temperature
4. temperature, color, texture

Answers

Answer:

2

Explanation:

From the formula R=(ro)A/l resistance depends on the length of the wire, the area of the wire(thickness) and the resistivity(ro) which depends on the material and temperature.

The number of pulses per second from IGBTs is referred to as

Answers

Referred to as Carrier Frequency

A particle which moves in two-dimensional curvilinear motion has coordinates in millimeters which vary with time t in seconds according to X=2t^2 +3t–1 and y = 5t - 2. Determine the coordinates of the center of curvature C at time t = 1s.

Answers

Answer:

The answer is "22.501,-22.899"

Explanation:

Just as in the previous problems find the angle the velocity makes with the  x-axis and radius of curvature.

[tex]x= 2t^2 + 3t — 1\\\\y=5t-2\\\\x=4t+3\\\\y=5\\\\\tan \alpha (t = 1) =\frac{y}{x}=\frac{5}{4+3}=\frac{5}{7} \to alpha=35.54^{\circ}\\\\[/tex]

For the radius of curvature, we can use the expression from the last two  problems, but first express the position and derivatives as y(x).

[tex]y(x)=2(\frac{y+2}{5})^2+3(\frac{y+2}{5})-1=\frac{1}{25}(2y^2+23y+13)\\\\y'(x)=\frac{1}{25}(4y+23)\\\\y''(x)=\frac{4}{25}\\\\\rho(t=1)=\frac{[1+(\frac{dy}{dx})^2]^{\frac{3}{2}}}{\frac{d^2y}{dx^2}}=\frac{(1+(\frac{35}{25})^2)^{\frac{3}{2}}}{4}25=31.828[/tex]

The position for the center of the radius of curvature [tex]\vec{r}[/tex], (finding this expression is easy and is left as an exercise for the reader.)

[tex]\to \vec{r} = \hat{x}(x + \rho \sin \alpha) + \hat{y}(y- \rho \cos \alpha)\\\\= (4 + 18.501, 3-25.899)\\\\=(22.501, -22.899)[/tex]

For a pipe system with a pump (pumping uphill), the change in elevation is 400 feet and the total head loss is 408.5 feet. Assuming gage pressure at the entrance and exit and no difference in velocity between the entrance and exit, determine the total energy transferred to the water. Estimate the required power input if the pump efficie

Answers

Answer:

Explanation:

From the given information;

There is no change or any difference in velocity in between the inlet and the outlet.

Therefore by using Bernoulli's equation, we have:

[tex]\dfrac{V_1^2}{2g}+ \dfrac{P_1}{\gamma}+ z_1 + Epump= \dfrac{V_2^2}{2g}+ \dfrac{P_2}{\gamma}+ z_2+ H_L[/tex]

By dividing like terms on both sides, the equation is reduced to:

[tex]z_1 + E_{pump} = z_2+H_L \\ \\ E_{pump} =(z_2-z_1)+H_L[/tex]

where;

[tex]\Delta z = 400[/tex]

[tex]\Delta z = z_2-z_1[/tex]

[tex]\text{total head loss}= 408.5[/tex]

[tex]E_{pump} =(400)+408.5[/tex]

[tex]E_{pump} = 808.5 \ ft[/tex]

The required power input can be determined by using the formula:

[tex]P= \dfrac{\gamma_wQH_{pump}}{\eta}[/tex]

Assuming the missing pump efficiency = 70% and the flow rate Q= 1.34

Then:

[tex]P= \dfrac{62.40\times 1.34 \times 808.5}{0.7}[/tex]

[tex]P = \dfrac{96576.48 \ ft.lb/s}{550\dfrac{ ft*lb/s}{hp}}[/tex]

P = 175.594 hp

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