Pls help I need a good grade
Hello~
I used Cymath for this!
https://www.cymath.com/answer?q=(0.4%20*10%5E-6)%20(0.7%20*%2010%5E-2)
In short the answer is B.
The link has the step by step answers!
I highly recommend this sight by the way, its always correct!
Ary~
Please help.
60
41
49
30
Answer: [tex]30^{\circ}[/tex]
Step-by-step explanation:
[tex]\cos x=\frac{13}{15}\\\\x=\cos^{-1} \left(\frac{13}{15} \right)\\\\x \approx 30^{\circ}[/tex]
2x -20 = -30
What is x?
NO LINKS!!!
What is the volume of this solid?
220 cubic units.
Answer:
Solution given:
for small cylinder
r=1
and for large cylinder
R=5+1=6
height for both [h]=2
Now
Volume of solid=πR²h-πr²h=πh(R²-r²)
=3.14*2(6²-1²)=219.8 =220 units ³.
Small cylinder is r=1
Large cylinder is R= 5+1 =6
Height (h) =2
Volume of solid,
→ πR²h-πr²h
→ πh(R²-r²)
→ 3.14 × 2(6²-1²)
→ 219.8
→ 220 cubic units
96 sq meters
144 sq meters
84 sq meters
102 sq meters
Pls show work I get different answers from people every time
Answer:
84 sq meters
Step-by-step explanation:
1. Approach
In order to solve this problem, one will have to divide the figure up into simple shapes. A picture is attached showing how the shape is divided up for this answer. Find the area of each region, then add up the results to find the total area.
2. Area of Region 1
As one can see, the length of (Region 1), as given is (6), the width is (3). To find the area multiply the length by the width.
Length * width
6 * 3
= 18
3. Area of Region 2
In (Region 2), the length is given, (12). However, one must find the width, this would be the size of the total side, minus the width of (Region 1). Multiply the length by the side to find the area.
Length * width
= 12 * (8 - 3)
= 12 * 5
= 60
4. Area of Region 3
In (Region 3), the length of the figure is (2), the width is (3). To find the area, multiply the length by the width.
Length * width
= 2 * 3
= 6
5. Total area
Now add up the area of each region to find the total rea,
(Region 1) + (Region 2) + ( Region 3)
= 18 + 60 + 6
= 84
Help me plsssssssssss
Find the distance between the points (6,5) and (4,-2). use of the graph is optional
Answer ? Anyone
Answer:
√53
Step-by-step explanation:
Distance between two points =
√(4−6)^2+(−2−5)^2
√(−2)^2+(−7)^2
= √4+49
=√53
= 7.2801
Hope this helps uwu
9514 1404 393
Answer:
option 2: √53
Step-by-step explanation:
The distance formula is useful for this:
d = √((x2 -x1)² +(y2 -y1)²)
d = √((4-6)² +(-2-5)²) = √((-2)² +(-7)²) = √(4+49)
d = √53
The distance between the given points is √53.
r − ns × 12
for n = 2, r = 9, and s = 3.
Answer:
-63
Step-by-step explanation:
9 - (2×3) × 12
9 - (6 × 12)
9 - 72
= -63
Answer:
-63
Step-by-step explanation:
r − ns × 12
Let n = 2, r = 9, and s = 3
9 - (2)*3 * 12
Multiply first
9 - 72
-63
Please help it’s a riddle can you find the correct answer
NEED HELP ON THIS ASAP PLZ!!
Answer:
x = 9.7
Step-by-step explanation:
tan θ = opposite side / adjacent side
tan 37° = x / 13
multiply 13 on each side
13 × tan 37° = 13 × x /13
13 × tan 37° = x
Rewrite
x = 13 × tan 37°
multiply, we get
x = 13 × 0.75355..
x = 9.79620265
Round nearest tenth = 9.7
a farmer employs 12 men to harvest his crops.they take 9 boys to do the job.if he had employed 8 men,how ling would it have taken.
Answer:
it needs more information
What is the distance between 3x - 5y + 3 =0 and 6x - 10y -12 =0
9514 1404 393
Answer:
(9/34)√34 ≈ 1.543
Step-by-step explanation:
The second equation can be rewritten as ...
6x -10y -12 = 0
3x -5y -6 = 0
3x -5y = 6
__
The formula for the distance from point (x, y) to line ax+by+c=0 is ...
d = |ax+by+c|/√(a²+b²)
Then the distance from a point to the first line is ...
d = |3x -5y +3|/√(3² +(-5)²)
We know from the rearrangement of the second equation that points on its line satisfy (3x-5y) = 6. Substituting this value for (3x -5y) in the distance formula gives ...
d = |6 +3|/√34
Simplifying and rationalizing the denominator gives a distance of ...
d = (9/34)√34 ≈ 1.543
Amie collects data on the fuel efficiency, in miles per gallon, and the mass, in kilograms, of
several different cars. She creates a scatter plot and determines that the line of the best fit for
the scatter plot has the equation y = 43.28 -0.011x, where y is the fuel efficiency, in miles per
gallon, and x is the mass, in kilograms. Based on this model, which of the following statements
is true?
O For every 100-kilogram increase in mass, the fuel efficiency of car decreases by about 0.4 miles
per gallon
O For every 100-kilogram increase in mass, the fuel efficiency of car increases by about 1.1 miles
per gallon
O For every 100-kilogram increase in mass, the fuel efficiency of car decreases by about 1.1 miles
per gallon
O For every 100-kilogram increase in mass, the fuel efficiency of car increases by about 0.4 miles
per gallon
Answer:
For every 100-kilogram increase in mass, the fuel efficiency of car decreases by about 1.1 miles per gallon.
Step-by-step explanation:
Fuel efficiency after x kg in mass:
y = 43.28 -0.011x
Thus, the slope is of -0.011 per x kg.
Increase of 100:
When x = 100, as the slope is negative, the efficiency will decay by:
-0.011*100 = -1.1
Decay of 1.1 miles per gallon, so the answer is:
For every 100-kilogram increase in mass, the fuel efficiency of car decreases by about 1.1 miles per gallon.
Can someone help me find the equivalent expressions to the picture below? I’m having trouble
Answer:
Options (1), (2), (3) and (7)
Step-by-step explanation:
Given expression is [tex]\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}[/tex].
Now we will solve this expression with the help of law of exponents.
[tex]\frac{\sqrt[3]{8^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}=\frac{\sqrt[3]{(2^3)^{\frac{1}{3}}\times 3} }{3\times2^{\frac{1}{9}}}[/tex]
[tex]=\frac{\sqrt[3]{2\times 3} }{3\times2^{\frac{1}{9}}}[/tex]
[tex]=\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3\times 2^{\frac{1}{9}}}[/tex]
[tex]=2^{\frac{1}{3}}\times 3^{\frac{1}{3}}\times 2^{-\frac{1}{9}}\times 3^{-1}[/tex]
[tex]=2^{\frac{1}{3}-\frac{1}{9}}\times 3^{\frac{1}{3}-1}[/tex]
[tex]=2^{\frac{3-1}{9}}\times 3^{\frac{1-3}{3}}[/tex]
[tex]=2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }[/tex] [Option 2]
[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2[/tex] [Option 1]
[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(\sqrt[9]{2})^2\times (\sqrt[3]{\frac{1}{3} } )^2[/tex]
[tex]=(2^2)^{\frac{1}{9}}\times (3^2)^{-\frac{1}{3} }[/tex]
[tex]=\sqrt[9]{4}\times \sqrt[3]{\frac{1}{9} }[/tex] [Option 3]
[tex]2^{\frac{2}{9}}\times 3^{-\frac{2}{3} }=(2^2)^{\frac{1}{9}}\times (3^{-2})^{\frac{1}{3} }[/tex]
[tex]=\sqrt[9]{2^2}\times \sqrt[3]{3^{-2}}[/tex] [Option 7]
Therefore, Options (1), (2), (3) and (7) are the correct options.
Assume the sample is a random sample from a distribution that is reasonably normally distributed and we are doing inference for a sample mean. Find endpoints of a t-distribution with 0.005 beyond them in each tail if the sample has size n
Answer:
The correct answer is "2.660".
Step-by-step explanation:
Given that,
Sample size,
n = 61
t-distribution with,
t = 0.005
Now,
The degree of freedom will be:
= [tex]n-1[/tex]
= [tex]61-1[/tex]
= [tex]60[/tex]
hence,
⇒ [tex]t,df=t_{0.005}, 60[/tex]
[tex]=2.660[/tex]
I am trying to graph y=2x-7
Step-by-step explanation:
The given equation is :
y = 2x-7
We will first find the points,
x 0 , , 3.5, 1 , 2 , 3
y -7 , 0, -5, -3, -1
The graph of the above equation is as follows :
It is a linear equation.
Describe the shape that would result from a horizontal slice of the figure below.
PLEASE ANSWER FAST ILL MARK BRAINLEIST.!!!
Answer:
A triangular prism and a trapezoidal prism, if I understand the question
Step-by-step explanation:
There wound be a trapezoid and a triangle if you cut it horizontally. If you mean vertically, it would be a right triangular prism
An item was marked down 64% from its original price, x. The amount discounted was $30. Which equation can be
used to find the original price?
0.64(x) = 30
0.64(30) = x
30 +0.64 = x
x + 0.064 = 30
Answer:
0.64(x) = 30
Step-by-step explanation:
Hope that's correct.
Simplify the following expression.
29.718 - 29.63
Answer:
0.088 is the answer...
help me :) which this question plzzzz !!
I believe its <ABF =<EDJ
Can someone please help ASAP!!
Step-by-step explanation:
you need to find:
uw:
uv:
vw= 8(already known)
Measure of W= 35
Measure of u= 90
measure of v= 180-90+35= 55
finding uv:
sin(35)= uv/8
0.57=uv/8
4.56=uv
finding uw:
sin(55)= uw/8
0.82= uw/8
6.56= uw
Find the center and foci of the ellipse:
16x2 + 25y2 – 64x – 50y - 311 = 0
Answer:
You should first make sure you explain what exactly is the question, before delete others answers.♀️♀️
Step-by-step explanation:
Ryder is building a workbench.
The top of the workbench is a rectangular piece of plywood that is 6.25 feet long and 1.83 feet wide.
Part A
Round the length and width to the nearest whole number.
Then estimate the perimeter of the workbench.
Which of the following equations models this estimate of the perimeter?
A. 6 + 6 + 2 + 2 = 16
B. 6 × 2 = 12
C. 7 + 7 + 2 + 2 = 18
D. 7 × 2 = 14
Part B
Round the length and width to the nearest tenth.
Then estimate the perimeter of the workbench.
Which of the following equations models this estimate of the perimeter?
A. 6.2 + 6.2 + 1.8 + 1.8 = 16
B. 6.2 × 1.8 = 11.16
C. 6.3 + 6.3 + 1.8 + 1.8 = 16.2
D. 6.3 × 1.8 = 11.34
i need help. Also need the answer in step by step form
Answer: GIVEN : f(x)= -3x+1
f(x)= -5
REQUIRE: x=?
CALCULATION:
f(x)= -3x+1
As, given f(x)= -5.
Hence,
-5= -3x+1
OR
-3x+1= -5
-3x= -5-1
-3x=-6
x= -6/-3
x= 2
A farmer finds there is a linear relationship between the number of bean stalks, n, she plants and the yield, y, each plant produces. When she plants 30 stalks, each plant yields 31 oz of beans. When she plants 36 stalks, each plant produces 29 oz of beans. Find a linear relationship in the form y=mn+b that gives the yield when n stalks are planted.
Answer:
[tex]y = -\frac{1}{3}m + 41[/tex]
Step-by-step explanation:
Linear equation:
A linear function has the following format:
[tex]y = mn + b[/tex]
In which m is the slope and b is the y-intercept.
When she plants 30 stalks, each plant yields 31 oz of beans. When she plants 36 stalks, each plant produces 29 oz of beans.
This means that these two points belong to the line: (30,31), (36,29).
Finding the slope:
When we have two points, the slope is given by the change in the output divided by the change in the input.
Change in the output: 29 - 31 = -2
Change in the input: 36 - 30 = 6
Slope:
[tex]m = \frac{-2}{6} = -\frac{1}{3}[/tex]
Thus
[tex]y = -\frac{1}{3}m + b[/tex]
Finding b:
We take one of the points and replace on the equation.
(30,31) means that [tex]m = 30, y = 31[/tex]. Thus
[tex]y = -\frac{1}{3}m + b[/tex]
[tex]31 = -\frac{1}{3}(30) + b[/tex]
[tex]31 = -10 + b[/tex]
[tex]b = 41[/tex]
Thus
[tex]y = -\frac{1}{3}m + 41[/tex]
Solve the system of equations Y=-2x+5 and y=x^2+3x+9
I think
x= -4, -1 and y=13, 8
(-4, 13) and (-1, 8)
If x = 35°, which two lines can be proven parallel?
a)n and o
b)l and m
c)n and l
d)m and o
Answer:
a) n and o
Step-by-step explanation:
by the concept of corresponding angles, angles that are equal when a line intersects 2 parallel lines .
l is the line that intersects n and o, and since x = 35, theyre corresponding angles resulting in n and o being parallel
Answer:
a) n and o
Step-by-step explanation:
Corresponding angles
a musician believes that listening to classical music affects mood determine if two-tailed or one-tailed
Answer:
I think one tailed correct me if im wrong
6h+(−8.1d)−14+5d−2.5h
Answer:
3.5h-3.1d-14
Step-by-step explanation:
6h+(−8.1d)−14+5d−2.5h
Combine like terms
6h -2.5h -8.1d +5d -14
3.5h-3.1d-14
Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side of the equation.
cot x sec4x = cot x + 2 tan x + tan3x
(sin x)(tan x cos x - cot x cos x) = 1 - 2 cos2x
1 + sec2x sin2x = sec2x
sine of x divided by one minus cosine of x + sine of x divided by one minus cosine of x = 2 csc x
- tan2x + sec2x = 1
Answer:
Step-by-step explanation:
1)
[tex]cot x sec^4 x = cotx + 2tanx + tan^3 x[/tex]
[tex]RHS =[/tex]
[tex]=\frac{cosx}{sinx} + 2 \frac{sinx }{cosx} + \frac{sin^3x }{cos^3x}\\\\[/tex]
[tex]= \frac{cosx(cos^3x) + 2sinx(sinx \ cos^2x ) + sin^3x(sinx)}{sinx \ cos^3x}\\\\[/tex] [tex][\ taking LCM \ ][/tex]
[tex]=\frac{cos^4x + 2sin^2xcos^2x +sin^4x }{sinx cos^3x}[/tex]
[tex]= \frac{(sin^2 x + cos^2x)^2 }{sin x \ cos^3 x}[/tex] [tex][ \ a^4 + 2a^2b^2 + b^4 = (a^2 + b^2 ) ^2 \ ][/tex]
[tex]= \frac{1}{sinx \ cos^3 x}\\\\= \frac{1 \times cosx}{sinx \times cos^3x \times cosx}[/tex] [tex][ \ multiplying\ and \ dividing \ by \ cosx \ ][/tex]
[tex]= \frac{cosx}{sinx} \times \frac{1}{cos^4x}\\\\=cot x \ sec^4 x[/tex]
[tex]= LHS[/tex]
2)
[tex]sin x \ ( tanx \ cosx - cotx \ cosx) = 1 - 2cos^2x[/tex]
[tex]LHS =[/tex]
[tex]=sinx( [ \frac{sinx}{cosx} \times cosx)] - [ \frac{cosx}{sinx}\times cosx] )\\\\= sinx (sinx - \frac{cos^2x}{sinx})\\\\=sin^2x - cos^2 x\\\\=(1 - cos^2x ) -cos^2 x[/tex] [tex][ \ sin^2x = 1 -cos^2 x \ ][/tex]
[tex]= 1 -cos^2x - cos^2 x \\\\= 1 - 2cos^2x \\\\=RHS[/tex]
3)
[tex]1 + sec^2x \ sin^2x = sec^2 x[/tex]
[tex]LHS =[/tex]
[tex]= 1 +sec^2x \sin^2x \\\\= 1 + (\frac{1}{cos^2x} \times sin^2x )\\\\= 1 + \frac{sin^2 x}{cos^2x}\\\\= 1 + tan^2x \\\\= sec^2 x\\\\=RHS[/tex]
4)
[tex]\frac{sinx}{1 -cosx} + \frac{sinx}{1+cosx} = 2 \ cosec x[/tex]
[tex]LHS =[/tex]
[tex]=\frac{sinx}{1 -cosx} + \frac{sinx}{1+cosx} \\\\= \frac{sinx(1 +cosx)}{(1-cosx)(1+cosx)} + \frac{sinx(1-cox)}{(1+cosx)(1-cosx)}\\\\= \frac{sinx +sinx\ cosx}{(1 - cos^2x)} + \frac{sinx - sinx \ cosx}{1 - cos^2x}\\\\=\frac{sinx + sinx \ cosx + sinx - sinx \ cosx}{1 - cos^2x}\\\\=\frac{2sinx}{sin^2x}\\\\=\frac{2}{sinx}\\\\=2 cosec\ x\\\\=RHS[/tex]
5)
[tex]- tan^2 + sec^2 x = 1\\\\[/tex]
[tex]sin^2 x + cos^2 x = 1\\\\\frac{sin^2x }{cos^2x} + \frac{cos^2x}{cos^x} = \frac{1}{cos^2x}\\\\tan^2x + 1 = sec^2x \\\\1 = sec^2 - tan^2x \\\\-tan^2x + sec^2 x = 1[/tex]