The radius of the satellite's motion is 2.49 × 10⁷ m
Since the centripetal force, F = mv²/r equals the gravitational force, F' = GMm/r² on the satellite,
F = F'
mv²/r = GMm/r²
v² = GM/r
Making r subject of the formula, we have
r = GM/v² where r = radius of satellite's motion, G = universal gravitational constant = 6.67 × 10⁻¹¹ Nm²/kg², M = mass of earth = 5.972 × 10²⁴ kg and v = speed of satellite = 4,000 m/s.
Substituting the values of the variables into the equation, we have
r = GM/v²
r = 6.67 × 10⁻¹¹ Nm²/kg² × 5.972 × 10²⁴ kg/(4,000 m/s)²
r = 39.83324 × 10¹³ Nm²/kg ÷ 16 × 10⁶ m²/s²
r = 2.4895775 × 10⁷ m
r ≅ 2.49 × 10⁷ m
So, the radius of the satellite's motion is 2.49 × 10⁷ m.
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Answer:
25.0 million meters
Explanation:
Which of the followng is Newton's Second Law?
a. An object in motion will stay in motion unless acted upon by an unbalanced outside force
b .Force = mass times acceleration
c.When one object puts a force on the another object, the second object puts a force back on the first, equal in magnitude and opposite in direction
Answer:
A
Explanation:
2. In a race, if a runner starts and stops at the same position, what is their
displacement? *
Answer:
It is the same
Explanation:
I Jsut know
how much does it cost to charge an electric car at a public charging station
Answer:
Rs 16.5 lakh is a charge of an electric car at a public charging station
Which factor is not a type of spectra?
A.
emission
B.
absorption
C.
continuous
D.
discontinuous
A stone is dropped off a tall building. It takes 4.5 s to hit the ground Determine the height of the building.
Explanation:
time =4.5sec
gravity =9.8m/s square
so to determime the height we can use the formula
1/2 of gravity times time square
which results in 99.25
Please find attached photograph for your answer.
Hope it helps.
Do comment if you have any query.
un cuerpo suspendido en el aire es capaz de:
a) liberar energía al caer
b) puede ejecutar un trabajo
c) posee energía antes de caer
d) todas son correctas
Answer:
Explanation:
d
A 22 kg body is moving through space in the positive direction of an x axis with a speed of 190 m/s when, due to an internal explosion, it breaks into three parts. One part, with a mass of 13 kg, moves away from the point of explosion with a speed of 130 m/s in the positive y direction. A second part, with a mass of 2.2 kg, moves in the negative x direction with a speed of 460 m/s. What are the (a) x-component and (b) y-component of the velocity of the third part
Answer: Our notation is as follows : the mass of the original body is M=20.0kg ; its initial velocity is
ν
0
=(200m/s)
i
^
; the mass of one fragment is m
1
=10.0kg ; its velocity is
ν
1
=(100m/s)
j
^
; the mass of the second fragment is m
2
=4.0kg ; its velocity is
ν
2
=(−500m/s)
i
^
; and , the mass of the third fragment is m
3
=6.00kg . Conservation of linear momentum requires
M
ν
0
=m
1
ν
1
m
2
ν
2
+m
3
ν
3
.
The energy released in the explosion is equal to ΔK , the change in kinetic energy .
(a) Using the above momentum -conservation equation leads to
ν
3
=
m
3
M
ν
0
−m
1
ν
1
−m
2
ν
2
=
6.00kg
(20.0kg)(200m/s)
i
^
−(10.0kg)(100m/s)
j
^
−(4.0kg)(−500m/s)
i
^
=(1.00×10
3
m/s)
i
^
−(0.167×10
3
m/s)
j
^
.
The magnitude of
ν
3
is
ν
3
=
(1000m/s)
2
+(−167m/s)
2
=1.01×10
3
m/s
It points at θ=tan
−1
(−167/1000)=−9.48
∘
(that is at 9.5
∘
measured clockwise from the +x axis) .
(b) The energy released is ΔK :
ΔK=K
f
−K
i
=(
2
1
m
1
ν
1
2
+
2
1
m
2
ν
2
2
+
2
1
m
3
ν
3
2
)−
2
1
Mν
0
2
=3.23×10
6
J
Explanation:
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ali starts moving his car from rest and accelerates it at 5 m/s^2 over 8 seconds. what is the velocity of ali's car reached by the end of these 8 seconds ?
Explanation:
u=0, v=?, a=5m/s², t=8sec
So, by the formula,
v=u+at
v=0+5×8
v=40m/s.
hope this helps you .
part 2 of 2
With what speed does the stone strike the
water?
Answer in units of m/s.
Hi there!
We can begin by finding the final VERTICAL velocity of the ball.
Use the following kinematic equation: vf² = vi² + 2ad
The ball does not have any initial velocity in the vertical direction so:
vf² = 2ad
Plug in given values:
vf² = 2(9.81)(44) = 29.38 m/s
Find the TOTAL speed using the pythagorean theorem (involving both the horizontal velocity which remains the same and vertical velocity)
v = √(21²) + (29.38²) = 36.115 m/s
exoplanets are difficult to detect because they are:
Explanation:
Exoplanets are very hard to see directly with telescopes. They are hidden by the bright glare of the stars they orbit. So, astronomers use other ways to detect and study these distant planets.
Exoplanets are difficult to detect because they are a star 'wobbles' as it orbits the center of mass, changing the wavelength of light it emits.
why is clay soil chosen for earthenware? Explain it.
There are many reasons actually...
◇ Clayey soil is easy to mould than the other soils.
The other soils (like sandy soil & loamy soil) are grainy or dry in nature & cannot be moulded. In the ancient times, when technology & the know-hows were still not introduced, people used clayey soul to make earthern pots to store stuff. This practice still continues even today.
◇ It keeps water cool.
Ever wondered why water stored in the earthenware remains cool even on a sunny day? It's because the heat required for evaporation is taken from water inside the pot & thus it cools the water stored inside.
◇ Clayey soil is also moist, durable, more plastic like & easy to retain making it ideal for potters to make earthenware.
__________
Clay soil is used to make earthenwares because, clay can be easily molded to desired sizes and shapes. Clay absorbs water moiety and make the pot very cool inside.
What is clay?Clay is a type of soil made by the sedimentation process near water resources. They are rich in minerals. Clay is rich in silicates and intermolecular force in the soil is comparatively less and can be easily molded any shape and size.
When clay is fired to a high enough temperature, the glass-forming materials in the ceramic form a liquid glass. This glass bridges the gaps between the clay particles. As the pottery cools at the end of the firing process, the glass between the clay particles solidifies again.
Clay pots make the water cooler inside. Hence, clay is used to make earthen wares.
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if the amplitude of a sound wave is tripled, the intensity will:
Answer:
Increase 9 times
Explanation:
the schwarzschild radius of a black hole depends on
Answer:
The mass of the object.
Explanation:
Happy Thanksgiving!
The Schwarzschild radius of a black hole depends solely on its mass. The Schwarzschild radius is a concept in general relativity that defines the boundary known as the event horizon.
The formula for the Schwarzschild radius is given by:
r_s = 2GM / c²
Where: r_s is the Schwarzschild radius
As the mass of the black hole increases, its Schwarzschild radius also increases. This means that a more massive black hole has a larger event horizon and a stronger gravitational pull.
The mass of the black hole is the primary factor determining the size of the Schwarzschild radius, while other properties, such as spin or charge, can also affect the structure and behavior of the black hole but do not directly impact the Schwarzschild radius.
Therefore,The Schwarzschild radius of a black hole depends solely on its mass.
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what is the fate of the energy in ultraviolet light that is incident upon glass?
Answer:
we can say when UV light is incident. Essentially, when it strikes glass or incident upon gloss, it will be absorbed. The energy has to go somewhere. Um, and in this case, this radiation is then converted to thermal energy and the glass raises and temperature.
Explanation:
Got the information from the internet
A young woman walks up 55 steps to the top of a water slide. She slides
down, feet first, all the way to the bottom gaining speed as she goes. If each
step of the slide is.10m tall, how fast will she be going at the bottom?
Answer:
potential energy PE = M g h
KE at bottom = 1/2 M V^2
Regardless of the slope of the slide the change in energy is the same
1/2 V^2 = g h
V = (2 g h)^1/2 = (2 * 9.8 m/s^2 * 10 m)^1/2 = 14 m / s
Perhaps the question says that h = 55 * .1 = 5.5 m
Then V = (2 * 9.8 * 5.5) = 10.4 m/s
Which will be different on the moon than it is on Earth?
weight
mass
Answer:
Below
Explanation:
On the moon, an objects weight will be different than it is on earth. This is because we cannot change the mass of an object, the mass of an object is the measure of matter an object has. However the weight is depended on the gravitational pull of whatever planet you are on. In this case, weight will be lighter on the moon than it is on earth because the moon's gravitational pull is 1.62 m/s^2 while earths is around 9.8 m/s^2.
Hope that helps!
A quantity that has its own unit and is not derived from another is called a .
Answer:
Derived quantities are derived from the Fundamental quantities and so the answer is Fundamental Quantity.
A quantity that has its own unit and is not derived from another is called a Fundamental quantity.
The given problem is based on the concept of Fundamental quantities. A fundamental quantity is a physical quantity which does not depends on any other quantities.
For example - Kilogram (kg) is a fundamental quantity, that is unique and it is used to determine the mass of any object.Meter (m) is the fundamental quantity that determines the length of dimensions. Second (s) is the fundamental quantity, that determines the time.Fundamental quantities are the independent quantities which are utilized for the derivation of another type of physical quantities, known as derived quantities.
Thus, we can conclude that a quantity that has its own unit and is not derived from another is called a Fundamental quantity.
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If the mass of the Earth is doubled, how will the moon’s orbit be affected?
What Would Happen to the Orbit of the Moon if it Were Twice as Massive? ... The orbit would not change.
HOPE IT HELPS:)
PLS FOLLOW:)
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A car accelerates from 20m/s to 25m/s in 4s as it passes a truck. What is the distance travelled?
Answer:
afcorse 1 miles
Explanation:
yep plz make me the brainliest
The distance travelled by car is displacement which is
What is displacement?Displacement is defined to be the change in position of an object.
[tex]s=\frac{1}{2} (v+u)t[/tex]
[tex]s=\frac{1}{2} (25+20)4\\s= 90 m[/tex]
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SOMEONE PLEASE HELP ME IM GOING INSANE 4 Select the correct answer. A satellite completes one revolution of a planet in almost exactly one hour. At the end of one hour, the satellite has traveled 2.0 x 107 meters and is only 10 meters away from its starting point. What is the numerical value of the satellite's average velocity after that one hour? O A. -3.77 x 10-2 meters/second OB. -2.77 x 10-3 meters/second OC. -2.62 x 10-2 meters/second D. -5.55 x 103 meters/second
Hi there!
Since we are dealing with such large distances, we can approximate.
Recall that the equation for speed is:
displacement / time = velocity
OR:
d/t = v
Begin by converting one hour to seconds:
1 hr = 3600 sec
Now, we can solve for velocity:
(-2.0 × 10⁷) / 3600 = -5555.6 m/s ⇒ D: -5.55 × 10³ m/s
The temperature of a body is measured using the resistance of a wire. To calibrate the device the following measurements were taken (ohms is the unit of electrical resistance).
Resistance in melting ice 240 ohms.
Resistance in boiling water 250 ohms.
a. What is the change in resistance for a change in temperature of 1 Degree Celcius?
b. The wire is placed into some hot water and the resistance is mesured to be 246 ohms. What is the temperature of the water?
Answer:
A)250-240
=10+960
=970
What is a lever?....
Answer:
A lever is a simple machine in the subject "S.T.E.M"
Explanation:
Levers use the following forces in order to be used: push or pull.
examples are crow bars,shovels, brooms and ect.
a. A pure sample was analysed and was found to contain 6.25 g of lithium, 5.40 g of carbon, & 21.60
g of oxygen. Calculate the empirical formula. Show your work out. If you do not show any work out,
marks will not be given. [3]
b. The molar mass of the compound is 116 g/mol, what is its molecular formula?
PLS URGENTLY ANS
The empirical formula of the compound is Li₂CO₃
First, we will determine the respective number of moles of each element present in the compound by dividing by their atomic masses
Lithium Carbon Oxygen
6.25÷6.94 5.40÷12.01 21.60÷16.00
0.9006 0.4496 1.35
Now, divide through by the smallest number of moles, that is, 0.4496
Lithium Carbon Oxygen
0.9006÷0.4496 0.4496÷0.4496 1.35÷0.4496
2 1 3
Hence, the empirical formula of the compound is Li₂CO₃
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Which sense is used to determine whether an object is something you might want to eat?
smell
sight
taste
all of the above
Answer: D, All of the above!
Explanation:
I just helped my daughter with this test and it was correct!! Good luck !!
1 point
A roller coaster is 20 m high and traveling 11 m/s. If the roller coaster has a
mass of 150 kg, what is its total energy? (only put the number, no units or
commas)
Answer:
ETotal=38505J
Explanation:
Known values:
m=150kg
h=20m
v=11m/s
KE=mv^2/2
PE=mgh
ETotal=PE+KE
KE=(150(11^2))/2
KE=9075
PE=150(9.81)(20)
PE=29430
ETotal=9075+29430
ETotal=38505J
eleven wa=eighs 47 kg. her height is 1.63 m. what is her bmi
Answer:
17.7kg/[tex]m^{2}[/tex]
Explanation:
BMI =
= [tex]\frac{weight (kg)}{height (m) . height (m)}[/tex]
= 47kg/(1.63m×1.63m)
= 17.689kg/[tex]m^{2}[/tex]
≈ 17.7kg/[tex]m^{2}[/tex]
this planet has a very toxic atmosphere that traps heat, making it the hottest planet in the solar system.
Answer:
Venus
Explanation:
basic 2nd grade smarts "no offense"
A kitchen has a water supply, an electricity supply and electric lighting there are several electrical appliances in the kitchen including a toaster, akettle a clothes iron, a microwave oven and a dishwasher discuss three hazards of using electricity in this kitchen ?
The hazards of using electricity in this kitchen include the following below:
Risk of electric shocks: These electrical appliances use an electric source for their various functions in which electric current flows through them when
turned on. Exposure and contact of the naked wire with individuals will bring
about shock.
Risk of burns: The kitchen has various heating appliances such as toaster,
kettle,iron and oven which may result in burns if not carefully handled.
Risks of fire : The heat and electric current from these appliances can trigger a spark and fire which may raze down the building is also another hazard.
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Explain how potential and kinetic energy are at play when we talk about Newton’s second law of motion?
Answer:
represents the energy the object possesses by virtue of its motion. ... This type of energy is generally known as kinetic energy. Thus, Equation (16) states that any work done on point object by an external force goes to increase the object's kinetic energy.
Explanation:
The relation between some bodies are involved by Object's position and motion, i.e., through potential and kinetic energy in which it actually explained by Newton's second law of motion.
What is Newton's second law of motion?
Definition:
Newton's second law states that force is equal to the rate of change of momentum, i.e., the mass and velocity.
It can be written as F = mv where m is mass and v is velocity. Potential energy can be described by a body's position while kinetic energy is possessed by a body's motion. Both forms of energy are influenced by forces and are equal to the total momentum. Momentum can be described by explaining the mass and velocity of the object.Learn more about Newton's second law of motion,
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How do you find the magnitude of the air inside a balloon?
Answer:
This demonstration is often done following a discussion of the ideal gas equation of state, PV=nRT.
We begin by weighing a balloon, then blowing it up and weighing it again. In the photo shown on right, the mass indication increased from 3.4 to 3.5 grams. At this point, it is important to note that the scale measures force, even though it reports a conclusion about mass based on the force measurement.
One assumption made in reaching the conclusion is that the buoyant force on the object being weighed is negligible. In the case of the balloon, this is incorrect. The buoyant force on this balloon is equal to the weight of the air displaced.
Since the volume of air inside the balloon is essentially the same as the volume of air displaced, we should expect that the buoyant force would support the weight of the air inside the balloon: The reported mass should not go up at all, because the force required of the scale should not change.
The increase in reported mass of .1 gram is attributed to the higher density of the air inside the balloon: The tension in the balloon compresses the air inside, as attested by the pressure required to blow the balloon up. Evidently, for this experiment, the pressure inside is greater than atmospheric by about 2%.
In the picture at right, the balloon is being pressed into a pan of liquid nitrogen. (The pan is the styrofoam lid of a small lunch box.) The balloon floats lightly on the liquid nitrogen unless pressed down. Pressing down places more surface area in contact with the cold nitrogen and speeds the demonstration. It is interesting to note the buoyant force by this liquified constituent of air.
The balloon shrinks dramatically, as indicated below. When left in contact with the liquid nitrogen long enough (perhaps 5 minutes) the oxygen inside the balloon liquifies, and then the nitrogen liquefies also. Close observation of the photo at the upper left corner of the pan shows some liquid nitrogen bubbles may forming above the dark spot in the center of the pan. One can also make out a faint line at the upper left corner of the pan which is the liquid nitrogen surface. The balloon still floats, riding rather high on that surface. Evidently, some of the balloon contents remain in the gas phase, making the mass of the balloon less than the mass of the displaced liquid nitrogen.
Next, we take the shrunken balloon and place it back on the scale, as above. In this instance, the reported mass is 8.7 grams, an increase of 5.2 grams.
A look at the figure on the right shows a faint line near the bottom of the cold balloon. Above that line, the balloon contains gas; below the liquid. That line represents the top surface of the liquid air inside the balloon. With this evidence, the easy thing to say would be, "Of course, liquids are heavier than gases," but that would be incorrect. We assert that the amount of air inside the balloon has not changed and that the mass of that air is not dependent on temperature.
If these assertions are true, then the force of gravity on the balloon has not changed. The scale reading is determined by the force which it must exert on the balloon in order to keep it stationary. Evidently, the required force is larger when the balloon is shrunken. The reason is that the buoyant force (upward) has decreased to practically zero, leaving the scale alone to balance the downward force by gravity.
From the data, we can say that the change in the buoyant force is equal to the weight associated with the apparent change in mass. The weight of 5.2 grams is about .052 newtons. The buoyant force is less now because the balloon displaces less air. If we could measure the change in volume of the balloon as DV, then the buoyant force would be (r g DV) upwards, where r is the density of air that was displaced by the balloon, and g is the gravitational field strength, 9.8 Newton/kg.
Note that the .052 newton force is not the weight of the air inside the balloon. Rather, it is the weight of the air that was displaced by the balloon. If we ignore the compression of air inside the balloon, the two numbers are the same. However, the two samples are completely different.
We can estimate the volume of the balloon by assuming that the hand in the photograph is about .1meters across. For purposes of estimation, we say that the volume shrank to almost zero when the balloon was cold so that the change in volume was nearly equal to the original volume. Plugging in numbers gives fair agreement with the book value of 1kg/cubic meter for the density of air.
The value for the density of air is secondary to two main features of this demonstration:
Large changes in temperature produce the large changes in volume that are indicated by the ideal gas equation.
The mass of air in a volume equal to the volume of a balloon can be determined provided that the buoyant force is understood.