Answer:
The final components of velocity of the composite object is 3.33 m/s.
Explanation:
Given;
mass of the first object, m₁ = 3.35 kg
initial velocity of the first object, u₁ = 4.90 m/s in positive x-direction
mass of the second object, m₂ = 1.88 kg
initial velocity of the second object, u₂ = 3.12 m/s in negative y-direction
initial momentum of the first object, P₁ = 3.35 x 4.9 = 16.415 kgm/s
initial momentum of the second object, P₂ = 1.88 x 3.12 = 5.8656 kgm/s
The resultant velocity of the two objects is given by;
R² = 16.415² + 5.8656²
R² = 303.858
R = √303.858
R = 17.432 kgm/s
Apply the principle of conservation of linear momentum for inelastic collision;
total initial momentum before = total final momentum after collision
P₁(x) + P₂(y) = Pf
R = Pf
R = v(m₁ + m₂)
17.432 = v(m₁ + m₂)
where;
v is the final components of velocity of the composite object
[tex]v = \frac{17.432}{m_1 + m_2} \\\\v = \frac{17.432}{3.35+1.88} \\\\v = 3.33 \ m/s[/tex]
Therefore, the final components of velocity of the composite object is 3.33 m/s.
Which condition must be met in order for an equation to be balanced? The elements in the reactants are the same as the elements in the products. There are fewer elements in the reactants than there are in the products. The number of atoms in the reactants is greater than the number of atoms in the products. The number of atoms in the reactants equals the number of atoms in the products
Answer:
The elements in the reactants are the same as the elements in the products
Explanation:
The condition for a balanced equation is as follows :
The number of atoms for each element in reactant = Number of atoms for each element in product.
Total charge on reactant and product must be same.
The example of a balanced equation is:
Reaction of carbon and hydrogen :
[tex]C+2H_2\rightarrow CH_4[/tex]
No. of carbon atom on Carbon on LHS = 1
No. of carbon atom on Hydrogen on LHS = 4
No. of carbon atom on Carbon on RHS = 1
No. of carbon atom on Hydrogen on RHS = 4
So, for a balanced equation, The elements in the reactants are the same as the elements in the products. Hence, the correct option (a).
Answer:
The answer is A
Explanation:
A car traveling 13 m/s to the north collides with a car traveling 19 m/s to the
south. Each car has a mass of 1250 kg. If the system is defined as the two
cars, what is the change in momentum of the system due to the collision?
O A. 16,250 kg-m/s
O B. 0 kg•m/s
O C. 40,000 kg•m/s
D. 23,750 kg•m/s
Answer: B. 0 kg*m/s
Explanation:
Parallel circuits:
O A. provide more than one path for current flow.
O B. will have positive charges flowing in one branch, negative charges
in the other.
C. always need more voltage than series circuits.
O D. are rarely used in the wiring in homes.
Answer:
Provide more than one path for current flow. (answer option A)
Explanation:
When one connects resistors in parallel, one provides more than a single path for the current to flow. The current separates on each branch according to the resistance it experiences.
A positively charged atom has? 1. gained protons. 2. gained electrons. 3. lost electrons. 4. lost protons.
Answer:
3. lost electrons.
Explanation:
An atom that has lost an electron is positively charged because the number of protons is now greater than the number of electrons in the atom.
Protons are positively charged particles in an atom. Electrons are negatively charged particles. Neutrons do not carry any charges.If the number of protons and electrons are the same, the atom has no charge
If the protons > electrons, the atom becomes positively charged
If electrons > protons, the atom becomes negatively charged.
Atoms becomes charged by losing or gaining electrons.
Which type of star cluster is shown?
Answer:
♡ madeline here ♡
you forgot the attachment, luv ☆
have a great day!
- madeline/madi ✧･ﾟ: *✧･ﾟ:･ﾟ✧*:･ﾟ✧･ﾟ
Explanation:
OPENNNN
I AM CORRECT AND DATS MY NAMEEE OO I BE LIKE 2POC CHAINS:);)
There is more than one answer
Explanation:
the answers are the first 3.
Answer:
4.6
Explanation:
Ans is 4.6 b coz the difference b/w 4.6 and the other values is comparitively the largest.
Suppose someone travels 50 mi at 50 mi/h, then travels 50 mi at 25 mi/h, then travels 50 mi at 10 mi/h.
a). My estimate is 18.75 mph.
b). The average speed is 18.75 mph.
I nailed it.
Oil with a density of 890 kg/m3 moves through a constricted pipe in steady, ideal flow. At the lower point shown in the figure below, the pressure is
P1 = 2.00 ✕ 104 Pa,
and the pipe diameter is 7.00 cm. At another point
y = 0.30 m
higher, the pressure is
P2 = 1.25 ✕ 104 Pa
and the pipe diameter is 3.50 cm.
A tube is open at both its left and right ends. The tube starts at the left end, extends horizontally to the right, curves up and to the right, and extends horizontally to the right again. The right end is higher than its left end, and the change in height is labeled y. The pressure at the left end is labeled P1, and the pressure at the right end is labeled P2.
a- find the speed of the flow in the lower section (m/s)
b- find the speed of the flow in the higher section (m/s)
c- find the volume flow rate in the pipe (m^3/s)
Answer:
(a) V₁ = 1.06 m/s
(b) V₂ = 4.24 m/s
(c) Q = 4.08 x 10⁻³ m³/s
Explanation:
(b)
The formula derived for Venturi tube can be used here:
P₁ - P₂ = (ρ/2)(V₂² - V₁²)
where,
P₁ - P₂ = Difference in Pressure = (2x 10⁴ Pa) - (1.25 x 10⁴ Pa) = 0.75 x 10⁴ Pa
ρ = Density of Oil = 890 kg/m³
V₂ = Velocity at Higher End = ?
V₁ = Velocity at Lower End = ?
Therefore,
0.75 x 10⁴ Pa = [(890kg/m³)/2](V₂² - V₁²)
V₂² - V₁² = (0.75 x 10⁴ Pa)/(445 kg/m³)
V₂² - V₁² = 16.85 m²/s² ------------------- equation (1)
Now, we will use continuity equation:
A₁V₁ = A₂V₂
where,
A₁ = Lower End Area = πd₁²/4 = π(0.07 m)²/4 = 3.848 x 10⁻³ m²
A₂ = Higher End Area = πd₂²/4 = π(0.035 m)²/4 = 9.621 x 10⁻⁴ m²
Therefore,
(3.848 x 10⁻³ m²)V₁ = (9.621 x 10⁻⁴ m²)V₂
V₁ = (9.621 x 10⁻⁴ m²)V₂/(3.848 x 10⁻³ m²)
V₁ = 0.25 V₂ -------------------- equation (2)
using this value in equation (1):
V₂² - (0.25 V₂)² = 16.85 m²/s²
0.9375 V₂² = 16.85 m²/s²
V₂² = (16.85 m²/s²)/0.9375
V₂ = √(17.97 m²/s²)
V₂ = 4.24 m/s
(a)
using the value of V₂ in equation (2):
V₁ = 0.25(4.24 m/s)
V₁ = 1.06 m/s
(c)
For fluid flow rate we use the following equation:
Flow Rate = Q = A₂V₂ = (9.621 x 10⁻⁴ m²)(4.24 m/s)
Q = 4.08 x 10⁻³ m³/s
The speed if the fluid increases as pressure decreases.
(a) The speed of the flow in the lower section is 1.06 m/s
(b) The speed of the flow in the higher section is 4.24 m/s
(c) The volume flow rate in the pipe [tex]\bold {4.08 x 10^-^3m^3/s}[/tex].
The relation pressure and volume in constricted pipe can be derived by the formula formula ,
[tex]\bold {P_1 - P_2 = (\rho /2)(V_2^2 - V_1^2)}[/tex]
Where,
P₁ - P₂ -Difference in Pressure = [tex]\bold { 0.75 x 10^4}[/tex]
[tex]\rho[/tex] - Density of Oil = 890 kg/m³
V₂ - Velocity at Higher End = ?
V₁ - Velocity at Lower End = ?
put the values in the formula,
[tex]\bold {0.75 x 10^4 Pa = \dfrac{(890kg/m^3)}{2(V_2^2 - V_1^2)}}\\\\\bold {V_2^2 - V_1^2 = \dfrac {0.75 x 10^4 Pa}{445 kg/m^3}}\\\\\bold {V_2^2 - V_1^2 = 16.85 m^2/s^2}[/tex]
The continuity equation,
[tex]\bold {A_1V_1 = A_2V_2}[/tex]
Where,
[tex]\bold {A_1 }[/tex] - Area of lower end = [tex]\bold {3.848 x 10^-^3m^2}[/tex]
[tex]\bold {A_2 }[/tex] - Area of higher end = [tex]\bold {9.621 x 10^-^4m^2}[/tex]
Put the value in the formula above,
[tex]\bold {(3.848 x 10^-^3m^2)V_1= (9.621 x 10^-^4m^2)V^2}\\\\\bold {V_1 = \dfrac {(9.621 x 10^-^4 m^2)V_2}{(3.848 x 10^-^3 m^2)}}\\\\\bold {V_1 = 0.25 \times V_2}[/tex]
Put the value of [tex]\bold {V_1}[/tex], we get
[tex]\bold {V_2= 4.24 m/s}[/tex]
Therefore,
[tex]\bold {V1 = 0.25 (4.24 m/s)}\\\\\bold {V_1 = 1.06 m/s}[/tex]
The flow rate
[tex]\bold {Q = A_2V_2}[/tex]
[tex]\bold {Q = (9.621 x 10^-^4 m^2)(4.24 m/s)}\\\\\bold {Q = 4.08 x 10^-^3m^3/s}[/tex]
Therefore, the flow rate of the oil in the pipe is [tex]\bold {4.08 x 10^-^3m^3/s}[/tex].
To know more about Bernoulli's equation, refer to the link:
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A wave with a frequency of 230 Hz has a wavelength of 0.25 meters. At what speed will this wave travel?
Identify the wavelength of this wave.
Answer:
A
Explanation:
The line(A) goes throughout the entire picture. So therefore choice A would be it's length.
a mule pulls a cart of milk 10 meters, with a force of 50 newtons calculate the work done by the mule
Answer:
500 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 50 × 10
We have the final answer as
500 JHope this helps you
can someone help me???
Answer:
The correct answer is A. 8.0. In 2011, no fertiziler was added to the soil so the pH was not affected.
Aria is riding her bike. She is bent slightly over, holding onto her handlebars. She wants to go faster. Which best explains what she should do? She should bend her hips so her head is closer to the handlebars. She should sit straight up on the bike, keeping her arms tight to her body. She should spread her arms wide while sitting straight in her seat. She should flap her arms up and down like a bird.
Answer:
She should bend her hips so her head is closer to the handlebars
Explanation:
Answer:
Yea its A
Explanation:
Two lenses with focal lengths 10cm and 20cm and made of same material are placed coaxially
separated by distance d. The value of d such that the system is achromatic is
A) 20 om
) 30cm
C) 10 cm
D) 15 cm
in the space below derive two equations one in the y direction and one in the x direction expressing newton’s second law using symbols
Answer:
Fₓ = maₓ
Fy = may
Explanation:
The Newton's Second Law tells us about the force. It says whenever an unbalanced force is applied to a body, an acceleration is produced in that body. The direction of this acceleration is in the direction of the force itself. Hence, the law can be written as:
F = ma
where,
F = Unbalanced force
m = mass of body
a = acceleration magnitude
We, can write two equations separately for x-direction and y-direction as follows:
Fₓ = maₓ
Fy = may
where,
Fₓ = x-component of unbalanced force
aₓ = x-component of acceleration
Fy = y-component of unbalanced force
ay = y-component of acceleration
(20 points) An engineer is tasked with developing a model to study a cylindrical heat exchanger in a steam system. The prototype cylinder is 2.54 cm in diameter and the steam properties are: velocity
This question is incomplete, the complete question is;
An engineer is tasked with developing a model to study a cylindrical heat exchanger in a steam system. The prototype cylinder is 2.54 cm in diameter and the steam properties are: velocity = 30 m/s; density = 0.6 kg/m³; and absolute viscosity = 1.197 X 10⁻⁵ N-s/m², respectively. The model is going to be tested in a water tunnel where the water temperature is 20°C and the velocity is 3 m/s
a) what is the prototype Reynolds number, based on using the cylinder diameter as the characteristic length?
b) what should be the diameter of the model be to ensure dynamic similitude?
Answer:
a) the prototype Reynolds number is 38195.488
b) 0.01278 m or 1.278 cm should be the diameter of the model be to ensure dynamic similitude
Explanation:
Given that;
1 prototype ; d = 2.54 cm = 0.0254 m, Vp = 30 m/s, Sp = 0.6 kg/m³, Up = 1.197 × 10⁻⁵ N-s/m²
Model{ water at 20°C}; dm = ?, Vm = 3 m/s, Pm = 998.23 kg/m³, Um = 1.002 × 10⁻³ N-s/m²
a) what is the prototype Reynolds number,
to calculate prototype Reynolds number we use the expression;
(Re)p = SpVpdP / Up
we substitute our value
(Re)p = (0.6 × 30 × 0.0254) / 1.197 × 10⁻⁵
(Re)p = 38195.488
Therefore the prototype Reynolds number is 38195.488
b)
what should be the diameter of the model be to ensure dynamic similitude?
i.e dm = ?
so dynamic similarity [ viscous flow]
(Re)m = (Re)p
[PmVmdm / Um] = [SpVpdP / Up]
we substitute
[998.23 × 3 × dm / 1.002 × 10⁻³] = (0.6 × 30 × 0.0254) / 1.197 × 10⁻⁵
2994.69dm / 1.002 × 10⁻³ = 38195.488
2994.69dm = 38.2718
dm = 38.2718 / 2994.69
dm = 0.01278 m or 1.278 cm
Therefore 0.01278 m or 1.278 cm should be the diameter of the model be to ensure dynamic similitude
there are approximately 19 billion chickens in the world. If one third of them like to cross the road, how many chickens have gone to the other side?
Answer:
57,000,000,000(fifty-seven billion)
Explanation:
19000000000/ 1/3 = 57000000000
What is conflict resolution?
if something is shot straight up in the air at a speed of 17 m/s, how much time before I it will hit the ground
A skier leaves the horizontal end of a ramp with a velocity of 25.0 m/s and lands 70.0 m from the base of the ramp. How high is the end of the ramp from the ground? m
Answer:
The end of the ramp is 38.416 m high
Explanation:
Horizontal Motion
When an object is thrown horizontally with an initial speed v and from a height h, it follows a curved path ruled by gravity.
The maximum horizontal distance traveled by the object can be calculated as follows:
[tex]\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}[/tex]
If the maximum horizontal distance is known, we can solve the above equation for h:
[tex]\displaystyle h=\frac {d^2g}{2v^2}[/tex]
The skier initiates the horizontal motion at v=25 m/s and lands at a distance d=70 m from the base of the ramp. The height is now calculated:
[tex]\displaystyle h=\frac {70^2\cdot 9.8}{2\cdot 25^2}[/tex]
[tex]\displaystyle h=\frac {4900\cdot 9.8}{2\cdot 625}[/tex]
h= 38.416 m
The end of the ramp is 38.416 m high
A force of 1.50 N acts on a 0.20kg trolley so as to accelerate it along an air track
The track and force are horizontal and in line . How fast is the trolley going after acceleration from rest through 30cm , if friction is negligible
Answer:
2.12m/s
Explanation:
Given parameters:
Force on trolley = 1.5N
Mass of trolley = 0.2kg
Unknown:
Velocity of the trolley = ?
Solution:
To solve this problem, we first find the acceleration of the trolley;
Force = mass x acceleration
Acceleration = [tex]\frac{Force }{mass}[/tex]
Insert the parameters and solve;
Acceleration = [tex]\frac{1.5}{0.2}[/tex] = 7.5m/s²
Now to find the acceleration;
Initial velocity = 0m/s
v² = u² + 2aS
v is the final velocity
u is the initial velocity
a is the acceleration
S is the distance
Distance = 30cm and this is 0.3m
v² = 0² + 2(7.5)0.3 = 4.5
v = √4.5 = 2.12m/s
Open with
Part 2. Problem Solving
Directions: Follow the GUESS Method of solving problem to get full credit for your works
1. A kid throws a rock off the edge of a cliff 60.0 m high. When he drops the rock, it takes 5,0
sec for it to reach the ground below.
a.) Determine the time it takes to reach the ground below, and
b.) How long would it take the rock to hit the ground if he threw it down with a speed of 15
m/sec?
is hit stmight upward and reach a maximum height of 80.0 m.
Answer:
A.) 5s
B.) 2.29s
C.) 39.6 m/s
Explanation:
Given that a kid throws a rock off the edge of a cliff 60.0 m high. When he drops the rock, it takes 5,0sec for it to reach the ground below.
a.) Determine the time it takes to reach the ground below,
The time is 5s
b.) How long would it take the rock to hit the ground if he threw it down with a speed of 15m/sec?
Using the second equation of motion:
H = Ut + 1/2gt^2
Substitute all the parameters into the formula
60 = 15t + 1/2 × 9.8 × t^2
60 = 15t + 4.9t^2
Multiply all by 10
49t^2 + 150t - 600
t^2 + 3.06t = 12.24
( t + 1.53)^2 = 12.24 + 2.3409
t + 1.53 = sqrt ( 14.5809)
t = 3.82 - 1.53
t = 2.29s
is hit stmight upward and reach a maximum height of 80.0 m.
Using the third equation of motion
V^2 = U^2 - 2gH
At maximum height, V = 0
0 = U^2 - 2 × 9.8 × 80
U^2 = 1568
U = sqrt ( 1568)
U = 39.6 m/s
An ultrasound machine is being used to try to identify potential kidney stones. The machine is working properly and no kidney stones are found. Which statement best describes this situation? The generated sound wave will not be able to reflect off of the object. The sound wave will not be generated, so there will be no echoes received. The echoes will be made but will not be able to be received by the machine. The machine will not be able to process the received echoes into images.
Answer:
The generated sound wave will not be able to reflect off of the object.
Explanation:
The statement that best describes this situation is: The generated sound wave will not be able to reflect off of the object.
What is an Ultrasound Machine?An ultrasound machine is a device that is used to capture images in the human body for review by a medical examiner. The machine gives off sound waves that are reflected off body structures.
So, for the ultrasound machine being described, the absence of kidney stones will cause a non-reflection of the object to be captured.
Since the machine is in good working condition, the sound wave will be generated.
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A small child has a wagon with a mass of 10 kilograms. The child pulls on the wagon with a force of 2 Newton’s. What is the acceleration of the wagon?
PHYSICS
Mass = 10 kg
Force = 2 N
Acceleration = ____?
Answers :
[tex]f \: = m \times a[/tex]
2 = 10 × a
2 / 10 = a
0,2 m/s² = a ✅
A 0.964 kg radio-controlled car is driving 4.38 m/s. What is its momentum?
Unit: kg*m/s
A ray diagram shows that an object is placed in front of a plane mirror. What are the characteristics of the image produced by the object? inverted, larger than object, real upright, smaller than object, virtual inverted, same size as object, real upright, same size as object, virtual
Answer:
D. upright, same size as object, virtual
Explanation:
it is a plane mirror, it has no changes
The characteristics of the image produced by the object placed in front of a plane mirror will be upright, the same size as the object, and virtual.
What is the law of reflection?The law of reflection states that when a ray of light reflects back from a surface the angle of incidence of light on a surface is equal to the angle of reflection.
The image produced by an object in front of a plane mirror will be upright, the same size as the object, and virtual.
learn more about the law of reflection
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Gertrude writes a short story in which the main character must enter a nuclear-powered spaceship’s engine room that has lost its shielding in order to prevent the engine from flooding the rest of the ship with radiation. The main character is not wearing protective gear.
What effects are best for Gertrude to consider when planning what may happen to the character?
non-stochastic effects such as possible DNA mutations later in life resulting from the short-term, high-level exposure
non-stochastic effects such as severe burns and radiation sickness resulting from the short-term, high-level exposure
stochastic effects such as possible DNA mutations that are unlikely to occur from the single, low-level exposure
stochastic effects such as severe burns and radiation sickness resulting from the long-term, low-level exposure
Answer: (B) non-stochastic effects such as severe burns and radiation sickness resulting from the short-term, high-level exposure
Explanation: edgeunity
The impact of best for Gertrude to consider when planning what may happen to the character is non-stochastic effects.
What are non-stochastic effects?
It is that impact where incidence and severity based on dose.
Since as per the given situation, Gertrude writes a short story so here the character should be considered as the non-stochastic effects like burning and the radiation sickness that leads from the short term and high level of exposure.
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Adam takes a bus on a school field trip. The bus route is split into the five legs listed in the table. Find the average velocity for each leg of the trip. Then arrange the legs of the trip from highest velocity to lowest. Leg Distance (km) Time (min) A 18 9 B 25 15 C 24 8 D 48 12 E 15 7 leg A leg B leg C leg D leg E
Answer:
The answer is:
VA= 33 m/S
VB= 27.8 m/s
VC= 50 m/s
VD=66.7 m/s
VE=35.7 m/s
So, the Legs from the highest velocity to the lower are:
D - C - E - A - B
The explanation:
we are going to use the velocity formula:
Velocity = distance (m) / time (s)
So,
A) when D = 18 Km = 18000 m
and t = 9 min = 9*60 =540 s
So V = 18000m/ 540 S
= 33 m/S
B) when D = 25 Km = 25000 m
and t = 15 min = 15 * 60 = 900 S
So V = 25000m / 900S
= 27.8 m/s
C) when D = 24 Km = 24000 m
and t = 8 min = 8 * 60 = 480 s
So V = 24000m / 480s
= 50 m/s
D) when D = 48 Km = 48000 m
and t = 12 min = 12 * 60 = 720 s
So V = 48000 m / 720s
=66.7 m/s
E) when D = 15 km = 15000m
and t = 7 min = 7 * 60 = 420 s
So V = 15000m / 420s
= 35.7 m/s
wave length of sodium light is 5893A express in nanometre
Answer:
589.3 nm
Explanation:
The wavelength of a sodium light is 5893 A.
We need to find the wavelength in nm.
[tex]5893\ A=5893\times 10^{-10}\ m[/tex]
Also, [tex]1\ nm=10^{-9}\ m[/tex]
[tex]5893\ A=5893\times 10^{-9}\times 10^{-1}\ m\\\\=5893\times 10^{-1}\ nm\\\\=589.3\ nm[/tex]
So, the wavelength of sodium light is 589.3 nm.
jose has a mass of 70 kg, what is his weight