Answer:
98N
Explanation:
Given parameters:
Mass of the bowling ball = 10kg
Mass of the softball = 1kg
Unknown:
Force of gravity on the bowling ball = ?
Solution:
The force of gravity on an object is the same as the weight of the body;
Weight = m x g
m is the mass
g is the acceleration due to gravity = 9.8m/s²
Weight of bowling ball = 10kg x 9.8m/s² = 98N
A spring compresses 0.8 m when the 800 kg crate of llamas slides down and hits it. Ignore friction and find the spring constant of the spring. The ramp is at a 47° angle.
Answer:
7167.27N/m
Explanation:
To get the force constant k, we will use the formula;
F = kx where
F is the force acting on the object down the plane
k is the spring constant
x is the extension
The force acting down the ramp us F = Wsintheta. The formula will become;
Wsintheta = kx
mgsintheta = kx
K = mgsintheta/x
K = (800)(9.8)sin47°/0.8
K= 7840sin47°/0.8
K = 5733.81/0.8
K = 7167.27N/m
Hence the spring constant of the spring is 7167.27N/m
The ball is displaced to the left and then oscillates backwards and forwards between the two plates. The ball touches a plate once every 0.05 s. Every time it touches a plate, a charge of 2.8 × 10−8 C (0.000 000 028 C) is transferred. Calculate the average current produced by the repeated transfer of charge.
Answer:
Average current produced by the repeated transfer of charge is 5.6 × 10⁻⁷ ampere
Explanation:
The formula to be used here is
Q = It
where Q is the quantity of electricity and it is measured coulombs (C); 2.8 × 10⁻⁸ C or 0.000000028 C
I is current and it is measured in ampere (amps or A); unknown
t is time and it is measured in seconds (s); 0.05 s
Since, average current is what is unknown
I =Q/t
I = 0.000000028/0.05
I = 5.6 × 10⁻⁷ A
Average current produced by the repeated transfer of charge is 5.6 × 10⁻⁷ ampere
Which change to an object would double its kinetic energy?
A. Increasing its mass to twice its original value
B. Increasing its mass to four times its original value
C. Increasing its velocity to four times its original value
D. Increasing its velocity to twice its original value
Describe an experiment to show that the force pulling an object increase
with the increase in the mass of the object.
Answer:
"Acceleration due to gravity" whereby Force and Mass are directly proportional
Explanation:
F=ma
Answer:
just use the magnet experience
Explanation:
it shows how force pulling an object increase
with the increase in the mass of the object.
A parallel circuit containing two bulbs and a bell has three paths for the current flow. If the first bulb in the circuit burns out, what effect will it have on the other loads in the circuit?
A. The other bulb will go out, but the bell will continue to work.
B. The other bulb will remain lit, but the bell will no longer work.
C. The other loads will not be affected.
D. All the other devices will stop working.
Answer:
C
Explanation:
Since the circuit is in parallel there will be no effect on the other loads.
Which of the following statements is true of inertia?
(1 Point)
Inertia is a force
Inertia is a force which keeps stationary objects at rest and moving objects in motion at constant velocity.
Inertia is a force which brings all objects to a rest position.
A more massive object has more inertia than a less massive object.
Options A, B & D are true.
We are dealing with the concept of inertia.
From Newton's first law of motion which is referred to as law of inertia, we are told that; An object will remain at rest or continue in constant motion unless it is acted upon by an external force.This means that inertia is the force that keeps an object at rest or in constant motion.
Furthermore, it means that the bigger the object, the more the inertia because a bigger object will require more force to make it move from rest.Looking at the options, the only option that doesn't correspond with definition of Inertia is Option C. Options A, B and D are true based on our explanation above.Read more at; brainly.com/question/13656225
An 1850 kg car is moving to the right at a constant speed of 1.44 m/s.
a. What is the net force on the car?
b. What would be the net force on the car if it were moving to the left?
Answer:
Read explanation and see if that helps
Explanation:
Newton's second law of motion states that the force on an object is given by f = ma. since the car is moving to the right at a constant speed of 1.44 m/s the acceleration a = 0. this means that there is no net force driving the car.
direction doesnt matter as long as the car is moving in a straight line at a constant speed the force will always be zero
The acceleration of the car in both directions (right and left) is zero.
The given parameters;
mass of the car, m = 1850 kgspeed of the car, v = 1.44 m/sThe net force on the car is calculated by applying Newton's second law of motion as shown below;
F = ma
where;
a is the acceleration of the carAt constant speed, the acceleration of the car will be zero
F = m(a)
F m(0)
F = 0
When the car is moving left, the net force is also zero since the acceleration is zero.
Thus, the acceleration of the car in both directions (right and left) is zero.
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A baseball is thrown towards home plate. It takes 3.4 seconds for the ball to reach the catcher's glove from the pitcher's glove and reaches a maximum velocity of 90m/s. What is the ball's acceleration?
Answer:
57
Explanation:
You launch a model rocket that has a mass of 1.5 kg. At a height of 300 m, it is traveling at 125 m/s. What is it's kinetic energy at this point
Answer:
KE = 11,719 J
Explanation:
KE = ½ mv²
KE = ½ (1.5 kg) (125 m/s)²
KE = 11,719 J
Answer: 11,719 J
Explanation:
just did it on a.p.e.x
Which of the following diagrams best represents the gravitational force W. the frictional force f, and the normal force N that act on the block?
It's D.
Weight always points downward.
The normal force always points perpendicular to the surface.
Friction opposes motion, so it points in the direction opposite the direction in which the block is moving.
what does acromyn BMI stand for
Answer:
Body Mass Index
Explanation:
Mechanical weathering does not change a rock's
Answer:
composition
Explanation:
With mechanical weathering, the composition of the rocks does not change. ... This process can cause the rock to again break down into smaller pieces.
Answer:
composition
Explanation:
1. What does a negative value mean? Can distance be negative? Explain.
Answer: A negative value is values and frequency for the data you are analyzing had enough negative values. Sometimes distance can be negative. For example, when you are in the pool, underwater, or standing left from the middle of origin.
Explanation:
Clouds are forming along the front because the rising air is
A) contracting and warming, causing
evaporation
B) contracting and cooling, causing evaporation
C) expanding and warming, causing condensation
D) expanding and cooling, causing condensation
Answer:
D
Explanation:
The water vapor rises in the air. It starts to expand while cooling the higher it gets in the atmosphere. This causes condensation.
Clouds are forming along the front because the rising air is expanding and cooling, causing condensation (Option D).
Cloud formation occurs when water vapor cools and condenses to form liquid water droplets or solid ice crystals.In a cloud, liquid water droplets are formed at temperatures higher than 0 Celsius degrees, while solid ice crystals are formed at temperatures lesser than 0 Celsius degrees.In consequence, during cloud formation, the excess amount changes from water vapor (gas) into a liquid (water droplets) or solid (ice).In conclusion, clouds are forming along the front because the rising air is expanding and cooling, causing condensation (Option D).
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Jacki evaluated the expression below. 2 cubed (3 minus 1) + 4 (8 minus 12) = 2 cubed (2) + 4 (4) = 8 (2) + 16 = 16 + 16 = 32. What was Jacki’s error? Jacki should have simplified the exponent first. Jacki should have multiplied 4 and 8 first. Jacki did not subtract 12 from 8 correctly. Jacki should not have multiplied 8 and 2.
Answer:
Her error was that she did not subtract 12 from 8 correctly
Explanation:
Jackie did 8-12 instead of 12-8
Plss help
The above person is in an elevator as it accelerates
upward. What do they feel?
a. Heavier than normal. c. The same weight as
normal.
b. Lighter than normal. d. Scared to be in an elevator
with no door.
Answer:
b
Explanation:
imagine urself on an elevator dont you feel lighter
At which position is the roller coaster car's amount of potential energy about equal to the amount of kinetic energy?
Answer:
The mass of the cars and people and the height of the track where the cars are located determine the potential energy in the system. Potential energy depends on an object’s mass and height and the gravitational pull on the object. A change in gravity would result in a change in potential energy. For example, if the track were located on the Moon instead of Earth, the potential energy would be different.
Explanation:
A 100 kg cart on a roller coaster has 1800J of kinetic energy. How fast is it going?
KE= 1/2mv2
Answer:
the speed is equal to 6 m/s
Explanation:
How is fishpond raising affected by global climate change?
Answer:
It creates bad air so that’s like air pollution I guess
Explanation:
Definition: This is a drawing showing the direction and magnitude of all forces acting on a body.
Answer:
Free body diagram
During a lab you combined 5g of sodium bicarbonate and 10g of vinegar to produce sodium acetate, water, and carbon dioxide. After the reaction the contents of the beaker only weighed 14.5g. How much of the reactants were converted into carbon dioxide?
Answer:
Explanation:
Na₂CO₃ + CH₃COOH = CH₃COONa + CO₂ + H₂O .
1 mole 1 mole
mol weight of sodium carbonate = 106
mol weight of acetic acid = 60
5 g of sodium carbonate = 5 / 106 = .047 moles
10 g of acetic acid = 10 / 60 = .167 moles
sodium carbonate is the limiting reagent
.047 moles will react with .047 moles of acetic acid to give products .
grams of acetic acid reacted = .047 x 60 = 2.82 gram
grams of sodium carbonate reacted = 5 grams .
A sled slides down a snow-covered hill at constant speed. If the hillside is 10° above the horizontal, what is the coefficient of kinetic friction between the runners of the sled and the snow?
Answer:
The kinetic coefficient of friction between the runners of the sled and the snow is approximately 0.176.
Explanation:
At first we present a free body diagram of the sled as an image attached below. From 1st and 2nd Newton's Laws we know that an object is at equilibrium when it is either at rest or moving at constant velocity. The equations of equilibrium associated with the sled is:
[tex]\Sigma F_{x'} = f-W\cdot \sin \theta = 0[/tex] (1)
[tex]\Sigma F_{y'} = N-W\cdot \cos \theta = 0[/tex] (2)
Where:
[tex]\theta[/tex] - Inclination of the hillside, measured in sexagesimal degrees.
[tex]N[/tex] - Normal force from ground to sled, measured in newtons.
[tex]W[/tex] - Weight of the sled, measured in newtons.
[tex]f[/tex] - Kinetic friction between sled and ground, measured in newtons.
The definitions of kinetic friction and weight are, respectively:
[tex]f=\mu_{k}\cdot N[/tex] (3)
[tex]W = m\cdot g[/tex] (4)
Where:
[tex]\mu_{k}[/tex] - Kinetic coefficient of friction, dimensionless.
[tex]m[/tex] - Mass of the sled, measured in kilograms.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
By applying (3) and (4) in (1) and (2), we have the following system of equations:
[tex]\mu_{k}\cdot N-m\cdot g\cdot \sin \theta = 0[/tex] (1b)
[tex]N -m\cdot g \cdot \cos \theta = 0[/tex] (2b)
And by applying (1b) in (2b), we have the following expression for the kinetic coefficient of friction:
[tex]\mu_{k}\cdot m\cdot g \cdot \cos \theta -m\cdot g \cdot \sin \theta = 0[/tex]
[tex]\mu_{k} = \tan \theta[/tex] (5)
If we know that [tex]\theta = 10^{\circ}[/tex], then the kinetic coefficient of friction between the runners of the sled and the snow is:
[tex]\mu_{k} = \tan 10^{\circ}[/tex]
[tex]\mu_{k}\approx 0.176[/tex]
The kinetic coefficient of friction between the runners of the sled and the snow is approximately 0.176.
PLEASE HELP , THOSE ARE ALL THE ANSWERS!
Answer:
I don't understand
Explanation:
Una esfera de radio 0.4m tiene una masa de 300kg, se desea sumergir en agua para saber si flota o no. En este ejercicio use la densidad del agua en kg/m^3.
Answer:
La esfera no flotará pero se hundirá cuando se coloque en el agua porque su densidad es mayor que la del agua.
Explanation:
De la pregunta anterior, se obtuvieron los siguientes datos:
Radio (r) de la esfera = 0,4 m
Masa de esfera = 300 Kg
Densidad del agua = 1000 Kg / m³
A continuación, determinaremos el volumen de la esfera. Esto se puede obtener de la siguiente manera:
Radio (r) de la esfera = 0,4 m
Pi (π) = 3,14
Volumen (V) de la esfera =?
V = 4/3 πr³
V = 4/3 × 3,14 × 0,4³
V = 12,56 / 3 × 0,064
V = 0,27 m³
A continuación, determinaremos la densidad de la esfera. Esto se puede obtener como se ilustra a continuación:
Masa de esfera = 300 Kg
Volumen de esfera = 0,27 m³
Densidad de esfera =?
Densidad = masa / volumen
Densidad de la esfera = 300 / 0,27
Densidad de la esfera = 1111,11 Kg / m³
Comparando la densidad del agua y la de la esfera.
Sustancia >>>>>>> Densidad
Agua >>>>>>>>>>> 1000 Kg / m³
Esfera >>>>>>>>>> 1111,11 Kg / m³
De la ilustración anterior, podemos ver que la densidad de la esfera es mayor que la del agua.
Por lo tanto, la esfera no flotará sino que se hundirá cuando se coloque en el agua porque su densidad es mayor que la del agua.
what disadvantages does a conveyor belt have?
Answer:
Some of the disadvantages are: The normal design of a belt conveyor is opened. If your product needs to be contained, covers and or drip pans can become expensive and cumbersome. If the material is sticky, belt cleaning can be difficult and generally not very successful.
Explanation:
A hockey puck with a mass of 0.18 kg is at rest on the horizontal frictionless surface of the rink. A
player applies a horizontal force of 0.5 N to the puck. Find the speed and the traveled distance 5s
later.
Given :
A hockey puck with a mass of 0.18 kg is at rest on the horizontal frictionless surface of the rink.
A player applies a horizontal force of 0.5 N to the puck.
To Find :
The speed and the traveled distance 5s later.
Solution :
Acceleration is :
a = F/m
a = 0.5/0.18 = 2.78 m/s² .
Now, velocity after 5 seconds is given by :
v = 0 + 2.78×5 m/s
v = 13.9 m/s
Also, distance travelled :
[tex]d = \dfrac{v^2-u^2}{2a}\\\\d = \dfrac{13.9^2-0^2}{2\times 2.78}\\\\d = 34.75 \ m[/tex]
Therefore, speed and the traveled distance 5 s later is 13.9 m/s and 34.75 m.
A firefighter of mass 75 kg slides down a pole. The force of friction is 400N. What is the firefighter's acceleration as they slide down the pole?
Answer:
a = 5.33 [m/s²]
Explanation:
To solve this problem we must use Newton's second law which tells us that the sum of the forces acting on a body is equal to the product of mass by acceleration.
ΣF = m*a
where:
F = force = 400 [N]
m = mass = 75 [kg]
a = F/m
a = 400/75
a = 5.33 [m/s²]
Isaac Newton's first law of motion states?
Answer:
His first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. In other words its inertia.
Explanation:
Newtons first law of motion states that"A body will continue to its state of rest or motion unless external force acted upon it.
A wave had a frequency of 5 hertz and a speed of 25 m/s. What is the wavelength of the wave
Heya!!
For calculate wavelength, lets applicate formula:
[tex]\boxed{\lambda = V/f}[/tex]
Δ Being Δ
f = Frequency = 5 Hz
v = Velocity = 25 m/s
[tex]\lambda[/tex] = Wavelenght = ?
⇒ Let's replace according the formula:
[tex]\boxed{\lambda = 25\ m/s / 5\ Hz }[/tex]
⇒ Resolving
[tex]\boxed{\lambda = 5\ m}[/tex]
Result:
The wavelength is 5 meters.
Good Luck!!
The wavelength of the wave is 5 meters.
Given the following data:
Frequency = 25 HertzSpeed = 25 m/s.To find the wavelength of the wave:
Mathematically, the wavelength of a waveform is calculated by using the formula;
[tex]Wavelength = \frac{Speed}{Frequency}[/tex]
Substituting the given parameters into the formula, we have;
[tex]Wavelength = \frac{25}{5}[/tex]
Wavelength = 5 meters.
Therefore, the wavelength of the wave is 5 meters.
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A thin hoop with a mass of 5.0 kg rotates about a perpendicular axis through its center. A force F is exerted tangentially to the hoop. If the hoop’s radius is 2.0 m and it is rotating with an angular acceleration of 2.5 rad/s2, calculate the magnitude of F.
a. 35 N
a. 20 N
c. 25 N
d. 8 N
Given :
Thin hoop with a mass of 5.0 kg rotates about a perpendicular axis through its center.
A force F is exerted tangentially to the hoop. If the hoop’s radius is 2.0 m and it is rotating with an angular acceleration of 2.5 rad/s².
To Find :
The magnitude of F.
Solution :
Torque on hoop is given by :
[tex]\tau =F\times R\\\\I\alpha = FR\\\\MR^2\alpha = FR\\\\F = MR\alpha[/tex]( Moment of Inertia of hoop is MR² )
Putting value of M, R and α in above equation, we get :
[tex]F=5\times 2\times 2.5\ N\\\\F = 25 \ N[/tex]
Therefore, the magnitude of force F is 25 N.
Hence, this is the required solution.