5) A 20.0 kg cart with no friction wheels sits on a table. A light string is attached to it and runs over a low friction pulley to a 0.0150 kg mass.
Draw a free body diagram showing all the forces acting on each object
Calculate the acceleration of the masses
Calculate the tension force in the cord
How long will it take the block to get to go 1.2 m to the edge of the table.
What will the velocity be as soon as it gets to the edge?
Answers
Answer:
1) Please find attached, created with Microsoft Visio
2) The acceleration of the masses connected by the light string is 0.00735 m/s²
3) The tension in the cord is 0.147 N
4) The time it would take the block to go 1.2 m to the edge of the table is approximately 18.07 s
5) The velocity of the cart as soon as it gets to the edge of the table is 0.042 m/s
Explanation:
1) Please find attached, the required free body diagram, showing the tension, weight and frictional (zero friction) forces acting on the cart and the mass created with Microsoft Visio
2) The acceleration of the masses connected by the light string is given as follows;
F = Mass, m × Acceleration, a
The mass of the truck, M = 20.0 kg
The mass attached to the string, hanging rom the pulley, m = 0.0150 kg
The force, F acting on the system = The pulling force on the cart = The tension on the cable = The weight of the hanging mass = 0.0150 × 9.8 = 0.147 N
The pulling force acting on the cart, F = M × a
∴ F = 0.147 N = 20.0 kg × a
a = 0.147 N/(20.0 kg) = 0.00735 m/s²
The acceleration of the truck = a = 0.00735 m/s²
3) The tension in the cord = F = 0.147 N
4) The time, t, it would take the block to go 1.2 m to the edge of the table is given by the kinematic equation, s = u·t + 1/2·a·t²
Where;
s = The distance to the edge of the table = 1.2 m
u = The initial velocity = 0 m/s (The cart is assumed to be initially at rest)
a = The acceleration of the cart = 0.00735 m/s²
t = The time taken
Substituting the known values, gives;
s = u·t + 1/2·a·t²
1.2 = 0 × t + 1/2 ×0.00735 × t²
1.2 = 1/2 ×0.00735 × t²
t² = 1.2/(1/2 ×0.00735) ≈ 326.5306
t = √(1.2/(1/2 ×0.00735)) ≈ 18.07
The time it would take the block to go 1.2 m to the edge of the table = t ≈ 18.07 s
5) The velocity, v, of the cart as soon as it gets to the edge of the table is given by the kinematic equation, v² = u² + 2·a·s as follows;
v² = u² + 2·a·s
u = 0 m/s
v² = 0² + 2 × 0.00735 × 1.2 = 0.001764
v = √(0.001764) = 0.042
The velocity of the cart as soon as it gets to the edge of the table = v = 0.042 m/s.
Answer:
There's no answer I'm just taking points like you did me, so thank you for your points I'll put them to good use ;)
Related Questions
How do photons help explain the photoelectric effect?
A. Changing light frequencies create opposing electric fields that affect electrons.
B. "Packets" of electromagnetic energy eject electrons.
C. Particles with positive charge attract negative electrons.
D. Single particles of light take the place of electrons that have similar mass and energy.
Answers
Answer:
Option B
"Packets" of electromagnetic energy eject electrons.
Explanation:
A photon is a tiny packet of light. Light as we know is a form of electromagnetic energy. Whenever light is incident on a photoelectric surface, the energy of the light wave gets transferred to the electron, causing it to have enough energy to eject electrons from its surface. The electrons, once ejected, are now free to move about, thus, resulting in the flow of electrical current.
This makes option B the correct answer
If y is inversely proportional to x and y = 4 and x=10, find y when x = 20
Answers
Answer:
Y=8
Explanation:
Y=4
X=10
if x is 20 it means it is doubled frm the previous therefore it means even y has to be doubled
first. now
x=10. x=20
y=4. y=8
Which electron dot diagram shows the bonding between 2 chlorine atoms?2 dots then C l with 2 dots above and 1 dot below then 2 dots then 2 dots then C l with 2 dots above and 1 dot below then 2 dots.2 dots then C l with 2 dots above and 2 dots below then 2 dots then C l with 2 dots above and 2 dot below then 2 dots.2 dots then C l with 2 dots above and 2 dots below then 1 dot then C l with 2 dots above and 2 dots below then 2 dots.2 dots then C l with 2 dots above and 1 dot below then 3 dots then 3 dots then C l with 2 dots above and 1 dot below then 2 dots.
Answers
Answer:
It is B
Explanation:
Answer: 2nd answer
Explanation: took exam
Fill in the blank.
_______________, not velocity, is used to calculate the average acceleration.
Answers
Answer:
speed
Explanation:
Change in velocity, not velocity, is used to calculate the average acceleration. Velocity is displacement over time.
Acceleration:
It is defined as the ratio of change in velocity to time. It is given by:
Acceleration= Change in velocity / time
a= u-v / t
where,
u= initial velocity
v= final velocity
t= time
Thus, we can conclude that a change in velocity is used to calculate average acceleration.
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You serve a volleyball with a mass of 2.1 kg. The ball leaves your hand with a speed of 35 m/s. The ball has __________________ energy. Calculate it.
Answers
Answer:
The ball has kinetic energy
the kinetic energy is 945 J
Explanation:
Answer:
The ball has 1286.25 J of energy
Explanation:
Kinetic Energy
Is the type of energy of an object due to its state of motion. It's proportional to the square of the speed.
The equation for the kinetic energy is:
[tex]\displaystyle K=\frac{1}{2}mv^2[/tex]
Where:
m = mass of the object
v = speed at which the object moves
The kinetic energy is often expressed in Joules (J).
The volleyball of a mass m=2.1 Kg is served at v=35 m/s, calculating its kinetic energy:
[tex]\displaystyle K=\frac{1}{2}\cdot 2.1\cdot 35^2[/tex]
[tex]\displaystyle K=\frac{1}{2}\cdot2.1\cdot 1225[/tex]
K = 1286.25 Joule
The ball has 1286.25 J of energy
A light, flexible rope is wrapped several times around a hollow cylinder with a weight of 40 N and a radius of 0.25m that rotates without friction about a fixed horizontal axis. The cylinder is attached to the axle by spokes of a negligible moment of inertia. The cylinder is initially at rest. The free end of the rope is pulled with a constant force P for a distance of 5 m, at which point the end of the rope is moving 6 m/s. If the rope does not slip on the cylinder, what is the value of P
Answers
Answer:
The value is [tex]P = 14.7 \ N[/tex]
Explanation:
From the question we are told that
The weight of the hollow cylinder is [tex]W = 40 \ N[/tex]
The radius of the hollow cylinder is [tex]r = 0.25 \ m[/tex]
The distance which it is pulled is [tex]d = 5 \ m[/tex]
The velocity of the end of the rope is [tex]v = 6 \ m/s[/tex]
Gnerally the mass of the hollow cylinder is
[tex]m = \frac{W}{g }[/tex]
=> [tex]m = \frac{ 40 }{ 9.8 }[/tex]
=> [tex]m = 4.081 \ kg[/tex]
Generally angular displacement for the distance covered is mathematically represented as
[tex]\theta = 2 \pi * \frac{ d } {2\pi r }[/tex]
=> [tex]\theta = 2 \pi * \frac{ 5 } {2\pi r }[/tex]
=> [tex]\theta = \frac{ 5 } { 0.25}[/tex]
=> [tex]\theta =20[/tex]
Generally the torque experienced by the hollow cylinder is mathematically represented as
[tex]P * r = I * \alpha[/tex]
Here I is the moment of inertia
=> [tex]P * r = m r^2 * \alpha[/tex]
=> [tex]\alpha = \frac{P }{ mr }[/tex]
Generally from kinematic equation
[tex]w_f ^2 = w_i ^2 + 2\alpha \theta[/tex]
=> [tex]w_f ^2 = w_i ^2 + 2\alpha \theta[/tex]
Generally the final angular velocity is mathematically
[tex]w_f = \frac{v}{r}[/tex]
=> [tex]w_f = \frac{ 6 }{ 0.25 }[/tex]
=> [tex]w_f = 24 \ m/s[/tex]
Generally the initial angular velocity is Zero given that the hollow cylinder was at rest before rolling
[tex]24^2 = 0^2 + 2* \frac{P}{4.081 *0.25 } * 20[/tex]
=> [tex]24^2 = 0^2 + 2* \frac{P}{mr} * 20[/tex]
=> [tex]P = 14.7 \ N[/tex]
Imagine that you fill a balloon at sea level (1.0 atm) with 18 L of air. You are taking the balloon to Denver, Colorado, for a birthday party. Colorado is the “Mile High State,” and Denver has an air pressure of 0.85 atm. When you get to the party, what will the volume of the balloon be?
Answers
Answer:
21.18 L
Explanation:
From the question given above, the following data were obtained:
Initial pressure (P₁) = 1 atm
Initial volume (V₁) = 18 L
Final pressure (P₂) = 0.85 atm
Final Volume (V₂) =?
With the application of the Boyle's law equation, we can obtain the final volume (i.e the new volume) of the gas as follow:
P₁V₁ = P₂V₂
1 × 18 = 0.85 × V₂
18 = 0.85 × V₂
Divide both side by 0.85
V₂ = 18 / 0.85
V₂ = 21.18 L
Therefore, the new volume of the gas will be 21.18 L
PLEASE HELP! FOR BRAINLIEST!
Answers
Answer:
i read the whole thing the answer that matches the most is C
hope this helped :D
Explanation:
A ball of mass 0.0887 kg is dropped from a height 1.76 m above the ground. The acceleration of gravity is 9.8 m/s 2 . Neglecting air resistance, determine the
Answers
Answer:
determine the.........
A ball is thrown straight upward with a velocity of 14 m/s. What is the maximum height
reached by the ball?
(1 Point)
10 m
20 m
14 m
32 m
Answers
Hello!
[tex]\large\boxed{d = 10 m}[/tex]
When the ball reaches its maximum height, the velocity equals 0. We can use the kinematic equation:
vf = vi + at, where:
vf = final velocity (0)
vi = initial velocity (14 m/s)
a = acceleration due to gravity, or 9.8 m/s (downwards)
t = time, which will be solved for.
Plug in the given values:
0 = 14 - 9.8(t)
-14 = -9.8(t)
t ≈ 1.429 sec
Solve for the distance traveled using the kinematic equation:
d = 1/2(vf + vi)t
Plug in the values:
d = 1/2(14 + 0)(1.429)
d = 1/2(14 · 1.429)
d ≈ 10 m
plzzzzzzzzz help me will mark u brainest
Answers
Answer:
B
Explanation:
acceleration = change in speed / change in time
for 1, speed increases over time, so positive acceleration
for 3, speed decreases over time, so negative acceleration (or deceleration)
An explosion occurs at the end of a pier. The sound reaches the other end of the pier by traveling through three media: air, fresh water, and a slender metal handrail. The speeds of sound in air, water, and the handrail are 355, 1480, and 5490 m/s, respectively. The sound travels a distance of 117 m in each medium. (a) After the first sound arrives, how much later does the second sound arrive
Answers
Answer:
0.05773 sec
Explanation:
We know that
time = distance/speed = d/V
for air
t1 = 117/355 = 0.3295 sec
for fresh water
t_2 = 117/1480 = 0.07905 sec
for metal
t_3 = 117/5490 = 0.02131 sec
So as we can see sound will reach through metal hand rail 1st, then through fresh water and then through air
1st = metal hand rail
2nd = fresh water
3rd = air
time difference between 1st and 2nd sound = t_2 - t_3 = 0.07905 - 0.02131 = 0.05773 sec
As you travel downhill, your vehicle needs less power to reach the bottom and your stopping _________ increases.
Answers
Answer: Distance
Explanation:
When driving, it is important for one to always use safety belt and obey traffic rules.
During a collision, it is vital to always adhere to safety belts and also use occupant protection systems in order to help reduce the impact that an be felt during a collision. As you travel downhill, your vehicle needs less power to reach the bottom and your stopping distance increase.
A 75kg bicyclist (including the bicycle), initially at rest at the top of a hill, coasts down the hill, reaching a speed of 14.6m/s at the bottom of the hill. The distance and height of the hill are shown. Neglect any friction impeding the motion and the rotational energy of the wheels. List the energy types at the initial and final time and whether work and loss (due to non-conservative forces) occur as well as the corresponding amounts of energy.
Answers
The energy type at the initial time is potential energy and the energy at the final time or position is kinetic energy.
What is the law of conservation of energy?The law of conservation of energy states that energy can neither be created nor destroyed but can be transformed from one form to another.
Based on the law of conservation of mechanical energy, the formula for the change in the kinetic energy and the potential energy of the bicyclist is given as;
K.Ei + P.Ei = K.Ef + P.Ef
where;
K.Ei is the initial kinetic energy of the bicyclistK.Ef is the final kinetic energy of the bicyclistP.Ei is the initial potential energy of the bicyclistP.Ef is the final potential energy of the bicyclistThe kinetic energy of the bicyclist increases with increase in the velocity of the bicyclist while the potential energy increases with increase in the height of the bicyclist.
At the initial position when the bicyclist is at rest, the kinetic energy is zero, so the only energy at the initial position is potential energy because the height is maximum.
In addition, at the final position, the velocity of the bicyclist is maximum and the height is zero, so the only energy at the final position is kinetic energy.
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The development of current atomic theory has changed over time as result of different proposed models and experiments. Place these in chronological order.
Answers
Answer:
b????
Explanation:
hope its right
The development of the current atomic theory has changed over time as a result of different proposed models and experiments as per the chronological order of the development of the atomic models, the correct answer is option B
What are atomic models?There are some models that are used to explain the arrangements of subatomic particles inside the atom based on the atomic theory of atom are known as the atomic models.
As given in the problem statement The development of the current atomic theory has changed over time as a result of different proposed models and experiments. The chronological order of the atomic model is given as follows
John Dalton's atomic model
The Plum Pudding Model, developed by J.J. Thomson,
Using the alpha particle bombardment experiment on a thin sheet of gold, Rutherford's model
Niels Bohr's model explained the revolving nature of the electrons in the different shells around the nucleus of the atom.
Erwin Schrodinger's model explains the arrangement of the subatomic particles as the electron Cloud Model
Thus, the correct answer is option B.
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calculate the kinetic energy of running kitten that has a mass of 4 kg and velocities of 2 m/s
Answers
Un automóvil se mueve a velocidad constante v = 60 [km/h]. Si el tiempo de reacción del conductor al ver la luz roja de una intersección es de 0.5 [s], y ´este desacelera a razón de 40 [m/s2 ] ¿Qué distancia recorre el automóvil desde el instante en que el conductor nota la se˜nal hasta detenerse por completo? Entiéndase por tiempo de reacción, el intervalo de tiempo transcurrido entre el instante en que se percibe la señal y el instante en que se lleva a cabo la acción (instante en que el conductor activa el sistema de frenado).
Answers
Answer:
El automóvil recorre una distancia de 11.806 metros antes de deternerse por completo.
Explanation:
De acuerdo con el enunciado, el conductor nota la luz roja, empieza a decelerar 0.5 segundos después y decelera hasta detenerse. La distancia total recorrida por el automóvil desde el instante en que el conductor nota la luz roja ([tex]\Delta s_{T}[/tex]), medida en metros:
[tex]\Delta s_{T} = \Delta s_{1}+\Delta s_{2}[/tex] (1)
Donde:
[tex]\Delta s_{1}[/tex] - Distancia recorrida a velocidad constante, medida en metros.
[tex]\Delta s_{2}[/tex] - Distancia recorrida hasta alcanzar el reposo, medida en metros.
Si suponemos que la segunda etapa describe un movimiento uniformemente acelerado, entonces la distancia recorrida total que representada por la siguiente fórmula:
[tex]\Delta s_{T} = v_{o}\cdot \Delta t_{o} + \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot a}[/tex] (2)
Donde:
[tex]v_{o}[/tex] - Velocidad inicial del automóvil, medida en metros por segundo.
[tex]v_{f}[/tex] - Velocidad final del automóvil, medida en metros por segundo.
[tex]\Delta t_{o}[/tex] - Tiempo de reacción del conductor, medido en segundo.
[tex]a[/tex] - Aceleración, medida en metros por segundo al cuadrado.
Si conocemos que [tex]v_{o} = 16.667\,\frac{m}{s}[/tex], [tex]v_{f} = 0\,\frac{m}{s}[/tex], [tex]\Delta t_{o} = 0.5\,s[/tex] y [tex]a = -40\,\frac{m}{s^{2}}[/tex], entonces la distancia recorrida total es:
[tex]\Delta s_{T} = \left(16.667\,\frac{m}{s} \right)\cdot (0.5\,s)+\frac{\left(0\,\frac{m}{s} \right)^{2}-\left(16.667\,\frac{m}{s}\right)^{2}}{2\cdot \left(-40\,\frac{m}{s^{2}} \right)}[/tex]
[tex]\Delta s_{T} = 11.806\,m[/tex]
El automóvil recorre una distancia de 11.806 metros antes de deternerse por completo.
3. Jackie tells Mike she can't go swimming, she is allergic to the chlorine. This is an example of ______.
A. self-concept
B. self-talk
C. self-disclosure
D. self-perception
Answers
Answer:
self perception
Explanation:
i think its self perception because he tells to others
what is a good college i can attend if i have Low B's and high C's as grades
Answers
Answer:
search easy colleges to get into ig
Explanation:
The law of __________________________ says that people think of similar objects as belonging together.
Answers
Answer:
Explanation:is the law means that the police are the law
A space probe recovered an 8.5-kg sample of rocks from the surface of Mars. The acceleration due to gravity on Mars is 3.7 meters per second squared. What is the weight of the sample of rocks on the surface of the earth?
Answers
Answer: 31N
Explanation:F = m x a
F = 8.5 x 3.7
F = 31.45
F = 31 (rounded)
F = 31 N
Incident ray X passes parallel to the principal axis of a concave lens. Incident ray Y passes parallel to the principal axis of a convex lens.
How do the rays behave differently after passing through each lens?
Ray X continues moving in the same direction, and ray Y refracts and passes through the focal point located behind the lens.
Both rays refract and move as though they passed through the focal point.
Ray X appears as though it passed through the focal point in front of the lens, and ray Y passes through the focal point on the other side of the lens.
Both rays continue moving in the same direction.
Answers
Answer:
Explanation:
It would be option C. Ray x appears as though it passed through the focal point in front of the lens, and ray Y passes through the focal point on the other side of the lens.
Answer:
c. Ray X appears as though it passed through the focal point in front of the lens, and ray Y passes through the focal point on the other side of the lens.
Explanation:
PLZ HELP MEEEEEEE,;-;
Answers
Answer:
thxs for the points
Explanation:
because just started
help please asap due 20 minutes please help me
Answers
Hiaaa I need help pwease" concerning the planetary orbits why was Copernicus somewhat inaccurate?"
Answers
I make you a brainlist helppp
Calculate the
combined mass
of this go kart
and its rider if
the cart exerts a force of 800
N and the car accelerates at
7 m/s2??
Answers
Answer:
114.29 kgExplanation:
The mass of the car can be found by using the formula
[tex]m = \frac{f}{a} \\ [/tex]
f is the force
a is the acceleration
From the question we have
[tex]m = \frac{800}{7} \\ = 114.285714...[/tex]
We have the final answer as
114.29 kgHope this helps you
TNT is an example of a high explosive. True False
Answers
The statement "TNT is an example of a high explosive." is true.
What is TNT?TNT, short for trinitrotoluene, is a highly explosive chemical compound that is widely used in military and industrial applications. It is a pale yellow crystalline solid that is highly sensitive to heat, shock, and friction. TNT is made by the nitration of toluene, a colorless liquid hydrocarbon that is derived from petroleum.
TNT is known for its high explosive power, which makes it a popular choice for use in bombs, missiles, and other weapons. When TNT is detonated, it releases a large amount of energy in the form of a shock wave and high-temperature gases. This explosive power is due to the presence of three nitro groups (-NO2) in the TNT molecule, which makes it highly unstable and reactive.
Despite its explosive properties, TNT is relatively stable under normal conditions and can be stored and transported safely. It is also relatively easy to manufacture, which has made it a popular choice for military applications since World War I. Today, TNT is still used in a variety of military and industrial applications, although it has been largely replaced by more powerful explosives in some applications.
Therefore, The correct answer is True. TNT (trinitrotoluene) is a high explosive that is commonly used in military and industrial applications. It is highly sensitive to heat, shock, and friction and can release a large amount of energy when it detonates.
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The air is an example of a gas in a gas solution. True or false
Answers
Hope this helped!
at constant pressure by what fraction of its volume will aquantity of gas change if the temperature changes from -173degree C to 27degree C
Answers
Answer:
The volume of the gas becomes three times the initial volume.
Explanation:
Given that the pressure is constant, and temperature changes from -173degree C to 27degree C.
So, the initial temperature, [tex]T_1[/tex] = -173 degree C = -173+273 = 100 K.
The final temperature, [tex]T_2[/tex]= 27 degree C = 27+273=300 K.
As the pressure is constant, so [tex]P_1=P_2[/tex].
Let V_1 and V_2 be the initial and final volume respectively.
Assuming that the given gas is ideal gas.
So, applying the ideal gas equation
PV=nRT
where n is the number of moles of the gas and R is the universal gas constant.
For the initial state, [tex]P_1V_1=n_1RT_1\cdots(i)[/tex]
and for the final state, [tex]P_2V_2=n_2RT_2 \cdots(ii)[/tex]
Dividing the equation (i) by (ii), we have
[tex]\frac {P_1V_1}{P_2V_2}=\frac {n_1RT_1}{n_2RT_2} \\\\\frac {P_1V_1}{P_2V_2}=\frac {n_1T_1}{n_2T_2}[/tex]
As the mass of the gas is not changing, so [tex]n_1=n_2[/tex], then
[tex]\frac {P_1V_1}{P_2V_2}=\frac {T_1}{T_2}[/tex]
As the pressure is not changing, so [tex]P_1=P_2[/tex], then
[tex]\frac {V_1}{V_2}=\frac {100}{300}[/tex]
[tex]V_2=3V_1[/tex]
So, the volume of the gas becomes three times the initial volume.
11 A car is driven on a long journey along a flat, horizontal road. The car stops several times on the
journey and its engine becomes hot.
Which type of energy does not change during the journey?
A the chemical energy in the fuel tank
the gravitational energy of the car
c the internal (thermal) energy of the engine
B
D the kinetic energy of the car
Answers
Answer:
A
Explanation:
Because the gravity is the one pulling the car to the ground so it doesnot change
The same same thing happens to the chemical energy in the engine it doesnot change as it is the one that makes the car to move from one place to another
Option B is correct that is the gravitational energy of the car does not change.
(A) The chemical energy in the fuel tank gets converted into thermal energy heating up the engine and mechanical energy which helps moving the car.
(B) Gravitational energy is due to the force of gravitation between the car and the earth and depends on their respective masses which does not change as the car moves.
(C) The internal energy is proportional to thermal energy. the thermal energy of the engine increases which means its internal energy also increases.
(D) The kinetic energy of the car changes as it moves and stops.
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