4. What are these parts commonly called?
Select all that apply:
Carburetor venturi tubes
Carburetor emulsion tubes
Carburetor air bleed tubes
O Carburetor stand-off tubes

Answer:

Full wave rectification flips the negative half cycle of the sine wave to positive so the result is two positive half cycles.

Explanation:

hope it helps a lil

The code to

were written in JavaScript and are found in the attached images

The first code declares a variable called num and gives it an initial value of 0. It then enters a while loop that lauches a message box (using window.alert) to print the message "Keep going" as long as num remains less than 5.

If nothing is done within the loop to increment num towards the value 5, the loop will go on endlessly notifying the user to "Keep going".

So, an increment of 1 was added to the loop body to increment the variable num. This makes sure the loop terminates.

Here, a function was created that receives two arguments (n1  and n2), then returns the product (n1 * n2)

This last code segment creates an array using the new keyword. The new keyword is generally used in constructing objects.

In this case the object constructed is an array having three strings;

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Answer:

The OR gate is a digital logic gate that implements logical disjunction (∨) from mathematical logic – it behaves according to the truth table above. A HIGH output (1) results if one or both the inputs to the gate are HIGH (1). If neither input is high, a LOW output (0) results.

Answer:

0.2 x 100

Explanation:

Engineering strain is the original crossection/original crossection

cold work percentage is

original crossection/original crossection x 100

Answer:

They are configured this way to avoid overlap issues.

Explanation:

The separation and purification process is used for DEVELOPING VACCINES. The development of vaccines must follow strict guidelines.

A vaccine is a biological preparation used to protect against harmful diseases (e.g., viruses) in a simple and safe manner.

Vaccine purification is a strict process consisting of clarification, concentration and chromatography in order to separate the extract that contains the active principle of the vaccine.

The techniques used for vaccine filtration include membrane filtration, depth filtration and centrifugation.

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Neither technician Technician or  B is correct in the statement above.

Vibration is a factor that is said to be caused by one or more other factors that occur together at any given time.

This can be due to actors such as imbalance, misalignment, wear and looseness and others. An imbalance  occurs due to  a "heavy spot" that is found inside a rotating component and it will lead to vibration when the unbalanced weight is said to rotates in circles round the machine's axis.

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Answer:

It's because to increase efficiency.

Explanation:

As electricity is transmitted over long distances, there are inherent energy losses along the way.

(I hope this will help)

Answer:

  $681.29

Explanation:

The amortization formula seems to apply. The monthly payment on a loan of P at rate r for t years is ...

  A = P(r/10)/(1 -(1 +r/12)^(-12t))

For the given loan parameters, the monthly payment is ...

  A = $60,000(0.065/12)/(1 -(1 +0.065/12)^(-12·10)) ≈ $681.29

The monthly payment is $681.29.

The expression of V(m³)=e^(t(s)) to make V in in³ and t in minutes is;

V(in³) = (¹/₆₁₀₂₄)a[tex]e^{\frac{1}{60}bt(h)[/tex]

We are given that;

Volume of microbial culture is observed to increase according to the formula;

V = e^(t)

where;

t is in seconds

V is in m³

We want to now express V in in³ and t in minutes.

Now, from conversions;

1 m³ = 61024 in³

Also; 1 second = 1/60 minutes

according to formula for exponential decay, we know that;

V = ae^(bt)

Thus, we have;

61024V = ae^(¹/₆₀b(t(h))

V(in³) = (¹/₆₁₀₂₄)a[tex]e^{\frac{1}{60}bt(h)[/tex]

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Answer:

You forgot the image and or example. I mean the answer could be anything right now.

Answer:

Known: Form of the velocity and temperature profiles at a particular axial location for flow in a circular tube. Find: Nusselt number at the prescribed.

Explanation:

Answer:

  5

Explanation:

One pulse is required for each bit to be moved.

5 pulses are required.

Answer:

the answer is Letter C

Explanation:

DON'T TRULY TRUST ME PLEASE..

Answer:

Explanation:

The largest positive number that can be represented in 13 bits for the two cases are

A) Unsigned number

[tex](2)^n - 1 = (2)^{13} - 1 = 8191[/tex]

In Binary - [tex](1111111111111)_2[/tex]

In decimal - [tex](8191)_{10}[/tex]

In hexadecimal - [tex](1FFF)_{16[/tex]

B) Signed number

[tex]2^n = 2^{13} = 8192[/tex]

The range is from [tex](2^n-1)[/tex]

therefore, the maximum value is [tex](4096)_{10}[/tex]

In binary - [tex](1000000000000)_2[/tex]

In hexadecimal - [tex](1000)_{16}[/tex]

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Answer:

The ratio of water to flour needed to make tortillas, which is 3 : 4

Explanation:

100 w = 75 f

w/f = 75/100 = 3/4

The value of Vz at point z from the generator  = 17.748 ∠ -107.62°  V

Given data :

Internal resistance = 50 ohms

Vg = 10 ∠ 0° v

length of air line = 3.6 m

Terminating resistance = 25 + j25 Ω

First step : Determine the Total impedance

Total Impedance ( z ) = Rin + Rline + Rl + jXl

                                   = 50 + 50 + 25 + j25  

                                   = 125 + j25  ≈ 127.47 ∠ 11.3°

Next step : Determine the current in the circuit

current ( I ) = Vg / z

                  =  ( 10∠0° v ) / ( 127.47 ∠ 11.3° )

                 = 0.0784 ∠ -11.3  amp

Final step : Determine the value of Vz at point z from the generator

Vz = ( Vg + I * Ri ) - ( RI * I + Rline * I )

    = ( 10∠0° + 0.0784 ∠ -11.3  * 50 ) - ( 25 + j25  + 50 * 0.0784 ∠ -11.3 )

    = -5.37 - j16.91  ≈  17.748 ∠ -107.62°  V

Hence we can conclude that the value of Vz at point z form the generator 17.748 ∠ -107.62°  V

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Hello your question is incomplete below is the complete question

A 100 MHz generator with Vg =10< 0 degree (v) and internal resistance 50-ohm is connected to a lossless 50-ohm air line that is 3.6m long and terminated in a 25+j25 (ohm) load.

Find (a) V(z) at a location z from the generate.

Answer:

C

Explanation:

they are flat black

Answer:

Vehicle Dynamics for use with MATLAB/Simulink (VDMS) is a lumped-parameter, 15 degrees-of-freedom vehicle simulation program that reads input files containing chassis, suspension kinematics and compliances, tire, driveline, and aerodynamic inputs.

Explanation:

hope it helps you

Answer:

Do you mean 4m^3 and 3.0 tones?

Explanation:

solution:

Mass = m = 3.0 tones

- 1 ton = 1,000 kg

= 3.0 × 1,000

= 3,000 kg

volume = v = 4m^3

Required:

Mass density of oil = p = ?

We know that;

[tex]p = \frac{mass}{volume} = \frac{m}{v} = \frac{3000}{4} = 750kg |m^{3} ans [/tex]

The answer is:

750kg / m^3

Answer:

  three-phase

Explanation:

2-phase, 3-phase, and 6-phase systems are in use. The most common of these is 3-phase.

A modern industrial plant most likely uses a 3-phase system.

__

Additional comment

Serious research began on 6-phase power transmission systems in 1973. They have been shown to increase power transfer, and to reduce corona, magnetic fields, and audio noise compared to 3-phase systems. However, they are not in widespread industrial use.

The friction loss in the system is 3.480 kilowatts.

Let suppose that the pump within a distribution system is an open system at steady state, whose mass and energy balances are shown below:

[tex]\dot m_{in}-\dot m_{out} = 0[/tex] (1)

[tex]\dot m_{in} = \frac{\dot V_{in}}{\nu_{in}}[/tex] (2)

[tex]\dot m_{out} = \frac{\dot V_{out}}{\nu_{out}}[/tex] (3)

[tex]\eta \cdot \dot W_{el} + \dot m_{in}\cdot (h_{in}-h_{out}) - \dot W_{f} = 0[/tex] (4)

Where:

From steam tables we get the following water properties at inlet and outlet:

Inlet

[tex]p = 100\,kPa[/tex], [tex]T = 25\,^{\circ}C[/tex], [tex]\nu = 0.001003\,\frac{kJ}{kg}[/tex], [tex]h = 104.927\,\frac{kJ}{kg}[/tex], Subcooled liquid

Outlet

[tex]p = 300\,kPa[/tex], [tex]T = 25\,^{\circ}C[/tex], [tex]\nu = 0.001003\,\frac{kJ}{kg}[/tex], [tex]h = 105.128\,\frac{kJ}{kg}[/tex], Subcooled liquid

If we know that [tex]\dot V_{in} = 0.05\,\frac{m^{3}}{s}[/tex], [tex]\nu_{in} = 0.001003\,\frac{m^{3}}{kg}[/tex], [tex]h_{in} = 104.927\,\frac{kJ}{kg}[/tex], [tex]h_{out} = 105.128\,\frac{kJ}{kg}[/tex], [tex]\eta = 0.90[/tex] and [tex]\dot W_{el} = 15\,kW[/tex], then the friction loss in the system is:

[tex]\dot W_{f} = \frac{\dot V_{in}}{\nu_{in}}\cdot (h_{in} - h_{out}) + \eta \cdot \dot W_{el}[/tex]

[tex]\dot W_{f} = \left(\frac{0.05\,\frac{m^{3}}{s} }{0.001003\,\frac{m^{3}}{kg} } \right)\cdot \left(104.927\,\frac{kJ}{kg}-105.128\,\frac{kJ}{kg}\right) + (0.90)\cdot (15\,kW)[/tex]

[tex]\dot W_{f} = 3.480\,kW[/tex]

The friction loss in the system is 3.480 kilowatts. [tex]\blacksquare[/tex]

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Explanation:

I think is SAE standard J2810