30/5.472 i need to use dividing decimals

Answer:

11 cm

Step-by-step explanation:

add whole numbers

1 + 4 + 2 = 7

add decimal numbers

1.5 + 2.5 = 4

add the answers

7 + 4 = 11

have a splendid day <3

Answer:

11cm

Step-by-step explanation:

To find perimeter, you simply just add each of the side lengths.

To make this easier to read, lest group some of the terms

1cm + 4cm = 5cm

2cm + 1.5cm = 3.5cm

5cm + 3.5cm = 8.5cm

8.5cm + 2.5cm = 11cm

The five terms are bolded to make sure that we added each term in the sum.

Answer:

0.00706666666

Step-by-step explanation:

Answer:

The answer has no solution because it is infinite and that's your vairiable

Answer:

-15 and 1

Step-by-step explanation:

Answer:

a) -0.25

b) 1

c)0

Step-by-step explanation:

a) 0.25 + (-0.25)=0

b) -5*1=-5

c) 0*(-6)=0

Answer:

The first answer

Step-by-step explanation:

Answer:

Correct answer is {6,10,12,14}

Step-by-step explanation:

Answer:

Step-by-step explanation:

45

Answer:

x=44°

Step-by-step explanation:

It's an Isosceles triangle, it has two equal sides (DC=CE) so also its two equal angles of 44 degrees

Hope this helps

Answer:

its the first one

Step-by-step explanation:

Answer:

the inputs are: 0,1,2,8,12

the outputs are: 19,9,7,16,17

(Put them in order if needed)

**inputs are x values and outputs are the y values**

Answer:

62.3538290725

Step-by-step explanation:

Sorry That All I Could Get For You

Answer:

gimme money

Step-by-step explanation:

Answer:

23518

Step-by-step explanation:

1) the total volume can be calculated as the sum of two volumes (for more info see the picture): V=V₁+V₂, where V₁ belongs to the prisma and V₂ - to the cylinder;

2) V₁=a*b*h; V₁=20*20*37=14800 (m³);

V₂=3/4*(π*r²*h); V₂=3/4*3.1415*100*37≈8717,6625 (m³), note the full volume of the cylinder cannot be included into the result, but 3/4 of its volume;

3) finally, V=14800+8717.6625=23517,6625≈23518 (m³).

Answer:

V = 23518 m3

Step-by-step explanation:

The volume of the cube part of building

(20)(20)(37)=14800 cm3

Each cylinder:

h=37/12=3.083 m

r=10 m

[tex]v=\pi (10)^{2} (3.083)=968.66m^{3}[/tex]

all the cylinders:

[tex]v=(12)(968.66)=11,623.89cm^{3}[/tex]

Total volume.

[tex]V=14800+\frac{3}{4} (11,623.89)[/tex]

[tex]V=14800+8717.92=23,517.92[/tex]

nearest m3:

[tex]V=23518m^{3}[/tex]

I hope this help you

Answer:

x=112, y=28, z=22

Step-by-step explanation:

68°+4y°=180° (adj angles on a str line)

4y=180-68

=112

y=112÷4

=28

x°+68°=180° (int angles)

x=180-68

=112

(5z+2)°=x° (corr angles)

5z+2=x

5z+2=112

5z=112-2

=110

z=110÷5

=22

Answer:

5^6

Step-by-step explanation:

5 was multiplied repeatedly 6 times, so it's 5 to the power of 6

Answer:

5 to the power of 6 or 5^6

Step-by-step explanation:

Answer:

Option A.

Step-by-step explanation:

Try To Cross Check It 1st

Answer:

x = 1/3

Step-by-step explanation:

assuming this is saying (8^2)^x = 4

2^6x = 4

2^6x = 2^2

6x = 2

x = 1/3

Step-by-step explanation:

,

[tex] \frac{7}{8} = \frac{49}{x} \\ 7x = 392 \\ x = \frac{392}{7} \\ x = 56[/tex]

Answer:

x = 56

Step-by-step explanation:

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    7/8-(49/x)=0

Step by Step solution:

Step 1:

Simplify 49/x

Equation at the end of step 1:

7/8 - 49/x = 0

Step 2:

Simplify 7/8

Equation at the end of step 2:

7/8 - 49/x = 0

Step 3:

Calculating the Least Common Multiple :

Find the Least Common Multiple

     The left denominator is :       8  

     The right denominator is :       x  

       Number of times each prime factor

       appears in the factorization of:

Prime  

Factor   Left  

Denominator   Right  

Denominator   L.C.M = Max  

{Left,Right}  

2 3 0 3

Product of all  

Prime Factors  8 1 8

                 Number of times each Algebraic Factor

           appears in the factorization of:

   Algebraic    

   Factor      Left  

Denominator   Right  

Denominator   L.C.M = Max  

{Left,Right}  

x  0 1 1

     Least Common Multiple:

     8x  

Calculating Multipliers :

3.2    Calculate multipliers for the two fractions

    Denote the Least Common Multiple by  L.C.M  

   Denote the Left Multiplier by  Left_M  

   Denote the Right Multiplier by  Right_M  

   Denote the Left Deniminator by  L_Deno  

   Denote the Right Multiplier by  R_Deno  

Left_M = L.C.M / L_Deno = x

 Right_M = L.C.M / R_Deno = 8

Making Equivalent Fractions :

3.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      7 • x

  ——————————————————  =   —————

        L.C.M              8x  

  R. Mult. • R. Num.      49 • 8

  ——————————————————  =   ——————

        L.C.M               8x  

Adding fractions that have a common denominator :

3.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

7 • x - (49 • 8)     7x - 392

————————————————  =  ————————

       8x               8x    

STEP

4

:

Pulling out like terms :

4.1     Pull out like factors :

  7x - 392  =   7 • (x - 56)  

Equation at the end of step

4

:

 7 • (x - 56)

 ————————————  = 0  

      8x      

STEP

5

:

When a fraction equals zero :

5.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 7•(x-56)

 ———————— • 8x = 0 • 8x

    8x    

Now, on the left hand side, the  8x  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  7  •  (x-56)  = 0

Equations which are never true:

5.2      Solve :    7   =  0

This equation has no solution.

A a non-zero constant never equals zero.

Solving a Single Variable Equation:

5.3      Solve  :    x-56 = 0  

Add  56  to both sides of the equation :  

                     x = 56

One solution was found :

x = 56

Answer:

ok so first lets look for the highest y value which is 4

the lowest one is -4

so -4<x>4

The answer is c

Hope This Helps!!!

Answer:

  18 cm

Step-by-step explanation:

The perimeter is the sum of the side lengths:

  3 cm + 4 cm + 5 cm + 6 cm = 18 cm

_____

Additional comment

If these are the side lengths in order around the figure, it cannot exist. (It will be a line segment 9 units long.)

Answer:

68 degrees

Step-by-step explanation:

Supplementary angles have sum 180°

<A=

Answer:

It's not a function

Because it's not a function, you don't have to answer b and c

Answer:

142 watermelon

Step-by-step explanation:

10/71 = 20 / w

w = 20(71/10) = 142

[tex]-2 \dfrac 5{12} - \left( - 10 \dfrac 89 \right)\\\\\\=- \left(2 + \dfrac 5{12} \right) + \left(10 + \dfrac 89 \right) \\\\\\=8 + \dfrac 89 - \dfrac 5{12}\\\\\\=8+ \dfrac{32}{36} - \dfrac{15}{36}\\\\\\= 8 + \dfrac{17}{36}\\\\\\= 8 \dfrac{17}{36}[/tex]

Only two real numbers satisfy x² = 23, so A is the set {-√23, √23}. B is the set of all non-negative real numbers. Then you can write the intersection in various ways, like

(i) A ∩ B = {√23} = {x ∈ R | x = √23} = {x ∈ R | x² = 23 and x > 0}

√23 is positive and so is already contained in B, so the union with A adds -√23 to the set B. Then

(ii) A U B = {-√23} U B = {x ∈ R | (x² = 23 and x < 0) or x ≥ 0}

A - B is the complement of B in A; that is, all elements of A not belonging to B. This means we remove √23 from A, so that

(iii) A - B = {-√23} = {x ∈ R | x² = 23 and x < 0}

I'm not entirely sure what you mean by "for µ = R" - possibly µ is used to mean "universal set"? If so, then

(iv.a) Aᶜ = {x ∈ R | x² ≠ 23} and Bᶜ = {x ∈ R | x < 0}.

N is a subset of B, so

(iv.b) N - B = N = {1, 2, 3, ...}

Answer:

Step-by-step explanation:

the answer is 1.1324

Answer:

Step-by-step explanation:

( [tex]x_{1}[/tex] , [tex]y_{1}[/tex] ) and ( [tex]x_{2}[/tex] , [tex]y_{2}[/tex] )

midpoint is ( [tex]\frac{x_{1} +x_{2} }{2}[/tex] , [tex]\frac{y_{1} +y_{2} }{2}[/tex] )

~~~~~~~~~~~~~

( p , p + q )

( p + 4 , 3q + 6 )

( p + p + 4 ) ÷ 2 = - 2

p = - 4

( - 4 + q + 3q + 6 ) ÷ 2 = 5

2q = 4

q = 2

Answer:

1 7/8 (1, 2)

Step-by-step explanation:

60/5=12 so dwayne reads 3/8 chapter per 12 minutes

12/3=4 so dwayne reads 1/8 chapter per 4 minutes

4x8=32 dwayne reads a chapter per 32 minutes.

2x32=64 and got 4 minute extra which is the time for dwayne to read 1/8 chapter

So Dwayne can read 1 7/8 chapter in 1 hour, if rounding off then 2 chapters, if only an entire chapter counts then 1

Answer:

Step-by-step explanation:

Using the binomial distribution, it is found that there is a 0.81 = 81% probability that NEITHER customer is selected to receive a coupon.

For each customer, there are only two possible outcomes, either they receive the coupon, or they do not. The probability of a customer receiving the coupon is independent of any other customer, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

0.81 = 81% probability that NEITHER customer is selected to receive a coupon.

Answer:

B=30

Step-by-step explanation:

Like and give 5 star rating

Answer:

b = 30

Step-by-step explanation:

all terms in the first equation will be three times the related terms in the second equation.

Then the two equation describe the same infinite line and any x,y pair that fits on one line will also fit on the other.

The car will travel a distance of 52.08 seconds will the brakes applied before it stops

The acceleration of the car after t seconds that the brake was applied is given as:

[tex]a=-0.08t m/s^2[/tex]

The speed of the car after  3 seconds that the brake was applied, u = 5 m/s

The speed of the car when it eventually stops, v = 0m/s

3 seconds after the brake was applied:

The time, t = 3 seconds

substitute t = 3 into the acceleration  [tex]a=-0.08t m/s^2[/tex]

[tex]a=-0.08(3)m/s^2\\\\a = -0.24m/s^2[/tex]

To calculate the distance traveled by the car after the brakes are applied, use the equation below

[tex]v^2=u^2+2as[/tex]

Substitute u = 5, a = -0.24, and v = 0 into the equation above in order to calculate the distance

[tex]0^2=5^2+2(-0.24)s\\\\0=25-0.48s\\\\0.48s = 25\\\\s = \frac{25}{0.48}\\\\s = 52.08 m[/tex]

The car will travel a distance of 52.08 seconds will the brakes applied before it stops

Learn more here: https://brainly.com/question/25597363

Answer:

x = -47/6

Step-by-step explanation:

Simplify both sides of the equation : 13x + 20 = 7x - 27

Subtract 7x from both sides : 6x + 20 = -27

Subtract 20 from both sides : 6x = -47

Divide both sides by 6 : 6x/6 = -47/6

Answer : x = -47/6