-2+2-0-2=?
can someone explain the answer for this​

Answer:

5 percent.

Step-by-step explanation:

Divide tax by the cost to see the percentage of the tax.

750/37.50=0.05

5 percent.

Answer:

y intercept is 2 x =-3

Step-by-step explanation:

2x-3y=-6

subtract 2

-3y=-2×-6

divide by -3

y=2/3+2

×

0=2/3x+2

-2=2/3×

-3=x

Answer:

yes, it is

Step-by-step explanation:

plug in the point (1, -1) (x,y) into the equation y = 9x - 10

-1 = 9(1)-10

-1 = 9-10

-1=-1

Answer:

line dancing, square dancing, etc

Step-by-step explanation:

Answer: square dancing, circle dancing, line dancing.

Hope this helps... Stay safe and have a great day/night!!! :D

Answer:

Tell whether the following equations represent a linear function.

10x + 2y = 4--linear equation✓

−x² + 3y = 19--quadratic equation

6x + 1/2y = 3--linear equation✓

Answer:

35.015

Step-by-step explanation:

see attached image

Answer: For my opinion, I think it's either A or B.

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

$500 + $100x > 1200

x represents the months

Answer:

This graph has a slop of 0

Step-by-step explanation

see the included picture of the graph

Answer:

I got (4x+3)(3x+1)

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Step-by-step explanation:

1 pound = 16 ounces

1 week = 7 days

0.1 x 7 = 0.7 pounds per week

0.7 x 16 = 11.2 ounces

0.1 lb/ day converts to 11.2 ounces / week

Answer:

The correct answer would be D. It would not be a linear function because the rate of change is not constant.

Step-by-step explanation:

The rate of change is not constant since it is not adding by a same number each time.

Answer:

x = 13

y = 8

Step-by-step explanation:

Answer:

m=-2

Step-by-step explanation:

Answer:

Shirley would have $115 and Joshua ends up with 152.5

Step-by-step explanation:

85+15+15=115

212.50-20-20-20-152.5

it's probably 17424 feet

The solution is $ 16.11

The total amount of money spend by Mrs.Hopkins on seeds and plants is given by the equation A = $ 16.11

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Let the cost of each tomato plant be = $ 2.59

The number of tomato plant = 4

The cost of 4 tomato plant = 4 x 2.59

The cost of 4 tomato plant = $ 10.36

Now ,

The cost of watermelon seeds = $ 1.87

The cost of adapeno plant = $ 3.88

So , the equation will be

The total amount of money A = cost of 4 tomato plant + cost of watermelon seeds + cost of adapeno plant

Substituting the values in the equation , we get

The total amount of money A = 10.36 + 1.87 + 3.88

The total amount of money A = $ 16.11

Therefore , the value of A is $ 16.11

Hence , the total amount of money is $ 16.11

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Answer:

b

Step-by-step explanation:

Answer:

No

Step-by-step explanation:

This relation is not a function. This line has repeating x-values, it only has one so each y-value cannot have a unique x-value. For this reason, no vertical line will ever be a function.  

The required terms are 7, 3 and 0. The correct option is (c).

What is an arithmetic sequence?

An arithmetic sequence is a kind of sequence of numbers where the difference of any two consecutive terms are the same.

This difference is known as the common difference of the sequence.

The given sequence is as below,

33, 25, 18, 12, …….

The difference between the consecutive terms is given as,

D₁ = 25 - 33

    = -8

D₂ = 18 - 25

     = -7

D₃ = 12 - 18

    = -6

It is clear that the difference between the consecutive terms are in arithmetic progression.

Thus, the next differences can be found as,

D₄ = -6 + 1

     = -5

D₅ = -5 + 1

    = -4  

And, D₆ = -4 + 1

             = -3

The next three terms of the sequence can be written as,

12 - 5 =7, 7 - 4 = 3, 3 - 3 = 0.

Hence, the next three terms of the given sequence are 7, 3 and 0.

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Answer: In three days

Step-by-step explanation:

Answer:

Domain=(-infinity,0)

Range: (-infinity,-1)

Step-by-step explanation:

Find the domain by finding where the equation is defined. The range is the set of values that correspond with the domain.

answer:

y=(x+7/2)^2-73/4

Answer:

im 90% sure its A

Step-by-step explanation:

Answer:

125.3 yards

Step-by-step explanation:

He wants them to run the  so 110^2+60^2 =which is 125.3.

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Answer:

70.9,109.1,204.0,336.0

Step-by-step explanation:

The solution set for the equation 6sin² θ - 7 sinθ - 5 = 0 in the interval [0,360)is {θ∈ [0,360)∣θ = 230.48 ,309.521}

Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.

The given equation is 6sin² θ - 7 sinθ = 5

Lets arrange in an order

6sin² θ - 7 sinθ - 5 = 0

a=6, b=-7 and c = -5

sinθ = 7±√49+120/12

Simplifying under the square root:

sinθ =7±17/12

Taking the positive solution first

sinθ =24/12

sinθ =2 (Not valid)

Now let's try the negative solution:

sinθ =7-17/12

sinθ =-10/12

sinθ =-5/6

θ= sin⁻¹(-5/6)

θ= −50.48⁰ ,−129.52⁰

we need to restrict our solution to the given interval [0,360), so we add 360 degrees to the negative angle:

θ=360−50.48 = 309.52 and 360 −129.52 =230.48

Therefore, the solution set for the equation 6sin² θ - 7 sinθ - 5 = 0 in the interval [0,360)is {θ∈ [0,360)∣θ = 230.48 ,309.521}

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Answer:

a) The horizontal asymptote of [tex]C(t)[/tex] is [tex]c = 0[/tex].

b) When t increases, both the numerator and denominator increases, but given that the grade of the polynomial of the denominator is greater than the grade of the polynomial of the numerator, then the concentration of the drug converges to zero when time diverges to the infinity. There is a monotonous decrease behavior.  

c) The time at which the concentration is highest is approximately 1.291 hours after injection.

Step-by-step explanation:

a) The horizontal asymptote of [tex]C(t)[/tex] is the horizontal line, to which the function converges when [tex]t[/tex] diverges to the infinity. That is:

[tex]c = \lim _{t\to +\infty} \frac{t}{3\cdot t^{2}+5}[/tex] (1)

[tex]c = \lim_{t\to +\infty}\left(\frac{t}{3\cdot t^{2}+5} \right)\cdot \left(\frac{t^{2}}{t^{2}} \right)[/tex]

[tex]c = \lim_{t\to +\infty}\frac{\frac{t}{t^{2}} }{\frac{3\cdot t^{2}+5}{t^{2}} }[/tex]

[tex]c = \lim_{t\to +\infty} \frac{\frac{1}{t} }{3+\frac{5}{t^{2}} }[/tex]

[tex]c = \frac{\lim_{t\to +\infty}\frac{1}{t} }{\lim_{t\to +\infty}3+\lim_{t\to +\infty}\frac{5}{t^{2}} }[/tex]

[tex]c = \frac{0}{3+0}[/tex]

[tex]c = 0[/tex]

The horizontal asymptote of [tex]C(t)[/tex] is [tex]c = 0[/tex].

b) When t increases, both the numerator and denominator increases, but given that the grade of the polynomial of the denominator is greater than the grade of the polynomial of the numerator, then the concentration of the drug converges to zero when time diverges to the infinity. There is a monotonous decrease behavior.  

c) From Calculus we understand that maximum concentration can be found by means of the First and Second Derivative Tests.

First Derivative Test

The first derivative of the function is:

[tex]C'(t) = \frac{(3\cdot t^{2}+5)-t\cdot (6\cdot t)}{(3\cdot t^{2}+5)^{2}}[/tex]

[tex]C'(t) = \frac{1}{3\cdot t^{2}+5}-\frac{6\cdot t^{2}}{(3\cdot t^{2}+5)^{2}}[/tex]

[tex]C'(t) = \frac{1}{3\cdot t^{2}+5}\cdot \left(1-\frac{6\cdot t^{2}}{3\cdot t^{2}+5} \right)[/tex]

Now we equalize the expression to zero:

[tex]\frac{1}{3\cdot t^{2}+5}\cdot \left(1-\frac{6\cdot t^{2}}{3\cdot t^{2}+5} \right) = 0[/tex]

[tex]1-\frac{6\cdot t^{2}}{3\cdot t^{2}+5} = 0[/tex]

[tex]\frac{3\cdot t^{2}+5-6\cdot t^{2}}{3\cdot t^{2}+5} = 0[/tex]

[tex]5-3\cdot t^{2} = 0[/tex]

[tex]t = \sqrt{\frac{5}{3} }\,h[/tex]

[tex]t \approx 1.291\,h[/tex]

The critical point occurs approximately at 1.291 hours after injection.

Second Derivative Test

The second derivative of the function is:

[tex]C''(t) = -\frac{6\cdot t}{(3\cdot t^{2}+5)^{2}}-\frac{(12\cdot t)\cdot (3\cdot t^{2}+5)^{2}-2\cdot (3\cdot t^{2}+5)\cdot (6\cdot t)\cdot (6\cdot t^{2})}{(3\cdot t^{2}+5)^{4}}[/tex]

[tex]C''(t) = -\frac{6\cdot t}{(3\cdot t^{2}+5)^{2}}- \frac{12\cdot t}{(3\cdot t^{2}+5)^{2}}+\frac{72\cdot t^{3}}{(3\cdot t^{2}+5)^{3}}[/tex]

[tex]C''(t) = -\frac{18\cdot t}{(3\cdot t^{2}+5)^{2}}+\frac{72\cdot t^{3}}{(3\cdot t^{2}+5)^{3}}[/tex]

If we know that [tex]t \approx 1.291\,h[/tex], then the value of the second derivative is:

[tex]C''(1.291\,h) = -0.077[/tex]

Which means that the critical point is an absolute maximum.

The time at which the concentration is highest is approximately 1.291 hours after injection.